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  • Getting AveragePower and PeakPower for a Channel in AVAudioRecorder

    - by Biranchi
    Hi all, I am annoyed with this piece of code. I am trying to get the averagePowerForChannel and peakPowerForChannel while recording Audio, but every time i am getting it as 0.0 Below is my code for recording audio : NSMutableDictionary *recordSetting =[[NSDictionary alloc] initWithObjectsAndKeys:[NSNumber numberWithFloat: 22050.0], AVSampleRateKey, [NSNumber numberWithInt: kAudioFormatLinearPCM], AVFormatIDKey, [NSNumber numberWithInt: 1], AVNumberOfChannelsKey, [NSNumber numberWithInt: AVAudioQualityMax], AVEncoderAudioQualityKey, [NSNumber numberWithInt:32],AVLinearPCMBitDepthKey, [NSNumber numberWithBool:NO],AVLinearPCMIsBigEndianKey, [NSNumber numberWithBool:NO],AVLinearPCMIsFloatKey, nil]; recorder1 = [[AVAudioRecorder alloc] initWithURL:[NSURL fileURLWithPath:audioFilePath] settings:recordSetting error:&err]; recorder1.meteringEnabled = YES; recorder1.delegate=self; [recorder1 prepareToRecord]; [recorder1 record]; levelTimer = [NSTimer scheduledTimerWithTimeInterval: 0.3f target: self selector: @selector(levelTimerCallback:) userInfo: nil repeats: YES]; - (void)levelTimerCallback:(NSTimer *)timer { [recorder1 updateMeters]; NSLog(@"Peak Power : %f , %f", [recorder1 peakPowerForChannel:0], [recorder1 peakPowerForChannel:1]); NSLog(@"Average Power : %f , %f", [recorder1 averagePowerForChannel:0], [recorder1 averagePowerForChannel:1]); } What is the error in the code ???

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  • "SpeakHere" iPhone Sample App

    - by Biranchi
    Hi All, Why does Apple has given such complex code in the documentation as Sample code for reference ??? I have wasted too much time in finding out how "averagePowerForChannel" works, but still no good. Where can i find good simple sample codes ??

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  • iPhone metering problems

    - by Eric Christensen
    When I'm recording an AVAudioRecorder object, I repeat a chunk of code via an NSTimer that includes: [soundrecording updateMeters]; NSLog(@"channel 0 average:%f, peak:%f",[soundrecording averagePowerForChannel:0],[soundrecording peakPowerForChannel:0]); NSLog(@"channel 1 average:%f, peak:%f",[soundrecording averagePowerForChannel:1],[soundrecording peakPowerForChannel:1]); When I'm recording a mono file, the peak power for channel 0 is just what you'd expect, a float from -160 to 0. But average power for channel 0 is always zero. (And, of course, the values for channel 1 are both zero.) When I'm recording a stereo file, both the average and peak values for both channels are as expected. Any thoughts on why, when recording a mono file, the average value for channel 0 isn't returning correctly, even though the peak is? Thanks!

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  • Conflit between AVAudioRecorder and AVAudioPlayer

    - by John
    Hi, here is my problem : The code (FooController) : NSString *path = [[NSBundle mainBundle] pathForResource:@"mySound" ofType:@"m4v"]; soundEffect = [[AVAudioPlayer alloc] initWithContentsOfURL:[NSURL fileURLWithPath:path] error:NULL]; [soundEffect play]; // MicBlow micBlow = [[MicBlowController alloc]init]; And MicBlowController contains : NSURL *url = [NSURL fileURLWithPath:@"/dev/null"]; NSDictionary *settings = [NSDictionary dictionaryWithObjectsAndKeys: [NSNumber numberWithFloat: 44100.0], AVSampleRateKey, [NSNumber numberWithInt: kAudioFormatAppleLossless], AVFormatIDKey, [NSNumber numberWithInt: 1], AVNumberOfChannelsKey, [NSNumber numberWithInt: AVAudioQualityMax], AVEncoderAudioQualityKey, nil]; and [recorder updateMeters]; const double ALPHA = 0.05; double peakPowerForChannel = pow(10,(0.05*[recorder peakPowerForChannel:0])); lowPassResults = ALPHA * peakPowerForChannel + (1.0 - ALPHA) * lowPassResults; NSLog(@"Average input: %f Peak input %f Low pass results: %f",[recorder averagePowerForChannel:0],[recorder peakPowerForChannel:0],lowPassResults); If I play the background sound and try to get the peak from the mic I get this log : Average input: 0.000000 Peak input -120.000000 Low pass results: 0.000001 But if I comment all parts about AVAudioPlayer it works. I think there is a problem of channel. Thanks

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