Is there a way to accept '%' as part of input that works both in python 2.6 & 3.0?
- by bug11
In 2.6, if I needed to accept input that allowed a percent sign (such as "foo % bar"), I used raw_input() which worked as expected.
In 3.0, input() accomplishes that same (with raw_input() having left the building).
As an exercise, I'm hoping that I can have a backward-compatible version that will work with both 2.6 and 3.0.
When I use input() in 2.6 and enter "foo % bar", the following error is returned:
File "<string>", line 1, in <module>
NameError: name "foo" is not defined
...which is expected.
Anyway to to accomplish acceptance of input containing a percent sign that works in both 2.6 and 3.0?
Thx.