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Search found 7 results on 1 pages for 'callcc'.

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  • How the yin-yang puzzle works?

    - by Hrundik
    I'm trying to grasp the semantics of call/cc in Scheme, and the Wikipedia page on continuations shows the yin-yang puzzle as an example: (let* ((yin ((lambda (cc) (display #\@) cc) (call-with-current-continuation (lambda (c) c)))) (yang ((lambda (cc) (display #\*) cc) (call-with-current-continuation (lambda (c) c)))) )

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  • call/cc in Lua - Possible?

    - by Pessimist
    The Wikipedia article on Continuation says: "In any language which supports closures, it is possible to write programs in continuation passing style and manually implement call/cc." Either that is true and I need to know how to do it or it is not true and that statement needs to be corrected. If this is true, please show me how to implement call/cc

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  • Continuation (call/cc) in Scheme

    - by darkie15
    Hi All, I need to understand Continuations in Scheme for my upcoming exams and I have no idea about continuations at all. Can anyone please suggest me sources of how to go about learning continuations? Regards, darkie

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  • Can continuations be used as a replacement for recursion?

    - by Sam
    The following function generates a 'stack level too deep (SystemStackError)' for n = 5,000 def factorial(n) n == 0 ? 1 : factorial(n -1) * n end Is there a way to avoid this error using continuations/callcc? Note: I know this can be implemented without recursion. e.g. def factorial2(n) (1..n).inject(1) {|result, n| result * n } end

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  • Continuation monad "interface"

    - by sdcvvc
    The state monad "interface" class MonadState s m where get :: m s put :: s -> m () (+ return and bind) allows to construct any possible computation with State monad without using State constructor. For example, State $ \s -> (s+1, s-1) can be written as do s <- get put (s-1) return (s+1) Similarily, I never have to

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