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  • Java Simple WGS84 Lat Lon to Pixel X, Y

    - by Cnich
    I've read a multitude of information regarding map projection today. The amount of information available is overwhelming. I am attempting to simply convert lat, long values into a screen X, Y coordinate not using any map. I do not need the values projected onto any map, just on the window. The window itself is representing approx. a 1500x1500 meter location. Lat, Long accuracy needed is to a 1/10th of a second. What may be some simpler ways in converting lat/long representation to the screen? I've read several articles and post regarding translation onto images, but nothing related to the natural java coordinate system. Thanks for any insight.

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  • Mathematically Find Max Value without Conditional Comparison

    - by Cnich
    ----------Updated ------------ codymanix and moonshadow have been a big help thus far. I was able to solve my problem using the equations and instead of using right shift I divided by 29. Because with 32bits signed 2^31 = overflows to 29. Which works! Prototype in PHP $r = $x - (($x - $y) & (($x - $y) / (29))); Actual code for LEADS (you can only do one math function PER LINE!!! AHHHH!!!) DERIVDE1 = IMAGE1 - IMAGE2; DERIVED2 = DERIVED1 / 29; DERIVED3 = DERIVED1 AND DERIVED2; MAX = IMAGE1 - DERIVED3; ----------Original Question----------- I don't think this is quite possible with my application's limitations but I figured it's worth a shot to ask. I'll try to make this simple. I need to find the max values between two numbers without being able to use a IF or any conditional statement. In order to find the the MAX values I can only perform the following functions Divide, Multiply, Subtract, Add, NOT, AND ,OR Let's say I have two numbers A = 60; B = 50; Now if A is always greater than B it would be simple to find the max value MAX = (A - B) + B; ex. 10 = (60 - 50) 10 + 50 = 60 = MAX Problem is A is not always greater than B. I cannot perform ABS, MAX, MIN or conditional checks with the scripting applicaiton I am using. Is there any way possible using the limited operation above to find a value VERY close to the max?

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