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  • Get folders from my msn account onto outlook

    - by Cortopasta
    I have my msn email account setup with a bunch of folders to put all my different emails in. I don't use rules, just drag and drop sort. On my current computer, I have it go to outlook, and all the folders pop up fine. But I set that up 4 years ago, and now I'm setting up a new laptop and have no idea how to get it going again. Any ideas?

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  • Cheap web hosting that supports php/mysql

    - by Cortopasta
    Does anyone know where I can find web hosting that supports php/mysql? I'm just using it to practice updating/changing live web sites, and to run code in an environment other than my XAMP stack on my thumb drive. It doesn't need to be fast or able to use a lot of bandwith, just somewhere I can play with code to sharpen my skill set

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  • Unable to compare valuesfrom mysql in a prepared statement

    - by Cortopasta
    I can't seem to get this to connect to the database so that I can run my prepared statement. Does anybody have an idea what I've forgotten? private function check_credentials($plain_username, $password) { global $dbcon; $ac = new ac(); $ac->dbconnect(); $userid = $dbcon->prepare('SELECT id FROM users WHERE username = :username AND password = :password LIMIT 1'); $userid->bindParam(':username', $plain_username); $userid->bindParam(':password', $password); $userid->execute(); $id = $userid->fetch(); Return $id; } EDIT: I changed the SQL query from a SELECT FROM query, to an INSERT INTO query and it worked. WHat the heck is going on?

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  • PHP: Proper way of using a PDO database connection in a class

    - by Cortopasta
    Trying to organize all my code into classes, and I can't get the database queries to work inside a class. I tested it without the class wrapper, and it worked fine. Inside the class = no dice. What about my classes is messing this up? class ac { public function dbConnect() { global $dbcon; $dbInfo['server'] = "localhost"; $dbInfo['database'] = "sn"; $dbInfo['username'] = "sn"; $dbInfo['password'] = "password"; $con = "mysql:host=" . $dbInfo['server'] . "; dbname=" . $dbInfo['database']; $dbcon = new PDO($con, $dbInfo['username'], $dbInfo['password']); $dbcon->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); $error = $dbcon->errorInfo(); if($error[0] != "") { print "<p>DATABASE CONNECTION ERROR:</p>"; print_r($error); } } public function authentication() { global $dbcon; $plain_username = $_POST['username']; $md5_password = md5($_POST['password']); $ac = new ac(); if (is_int($ac->check_credentials($plain_username, $md5_password))) { ?> <p>Welcome!</p> <!--go to account manager here--> <?php } else { ?> <p>Not a valid username and/or password. Please try again.</p> <?php unset($_POST['username']); unset($_POST['password']); $ui = new ui(); $ui->start(); } } private function check_credentials($plain_username, $md5_password) { global $dbcon; $userid = $dbcon->prepare('SELECT id FROM users WHERE username = :username AND password = :password LIMIT 1'); $userid->bindParam(':username', $plain_username); $userid->bindParam(':password', $md5_password); $userid->execute(); print_r($dbcon->errorInfo()); $id = $userid->fetch(); Return $id; } } And if it's any help, here's the class that's calling it: require_once("ac/acclass.php"); $ac = new ac(); $ac->dbconnect(); class ui { public function start() { if ((!isset($_POST['username'])) && (!isset($_POST['password']))) { $ui = new ui(); $ui->loginform(); } else { $ac = new ac(); $ac->authentication(); } } private function loginform() { ?> <form id="userlogin" action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> User:<input type="text" name="username"/><br/> Password:<input type="password" name="password"/><br/> <input type="submit" value="submit"/> </form> <?php } }

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  • Why can't I get a TRUE return in this prepared statement?

    - by Cortopasta
    I can't seem to get this to do anything but return false. My best guess is that the prepared statement isn't executing, but I have no idea why. private function check_credentials($plain_username, $md5_password) { global $dbcon; $ac = new ac(); $ac->dbconnect(); $userid = $dbcon->prepare('SELECT id FROM users WHERE username = :username AND password = :password LIMIT 1'); $userid->bindParam(':username', $plain_username); $userid->bindParam(':password', $md5_password); $userid->execute(); $id = $userid->fetch(); Return $id; } *EDIT:*I've even tried hard coding the username and password into the function itself to try and isolate the problem like this: private function check_credentials($plain_username, $md5_password) { global $dbcon; $plain_username = "jim"; $md5_username = "waffles"; $ac = new ac(); $ac->dbconnect(); $userid = $dbcon->prepare('SELECT id FROM users WHERE username = :username AND password = :password LIMIT 1'); $userid->bindParam(':username', $plain_username); $userid->bindParam(':password', $md5_password); $userid->execute(); print_r($dbcon->errorInfo()); $id = $userid->fetch(); Return $id; } Still nothing :-/

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  • Why is htmlspecialchars adding slashes to my webpage?

    - by Cortopasta
    I have my input placed into mySQL through a PDO prepared statement, and have it placed in my website with PHP using htmlspecialchars() to protect against XSS. Only problem is now I get slashes, before any quotes, that are visible on the webpage to the user it only happens when I upload it to the server. Never happens on my localhost. Why is this happening?

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  • PDO prepared statement not working for login system

    - by Cortopasta
    Anybody no what I'm doing wrong here? I have a username and password hashed in my database, but i can't seem to get it to match the one I submit through the script. $res = $dbcon->prepare('SELECT id FROM users WHERE name = :name AND password = MD5(:password)'); $res->bindParam(':name', $user); $res->bindParam(':password', $password); $res->execute(); $row = $res->fetch(); for ($i=0; $i<7; $i++) { $row[$i]; }

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  • Error code while trying to use private variables in a function

    - by Cortopasta
    I get an error that says Parse error: syntax error, unexpected T_PRIVATE in E:\PortableApps\xampp\htdocs\SN\AC\ACclass.php on line 6 while trying to run my script. I'm new to classes in PHP and was wondering if someone could point out my error. Here's the code for that part. <?php class ac { public function authentication() { private $plain_username = $_POST['username']; private $md5_password = md5($_POST['password']); $ac = new ac();

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  • PHP: How do I have a variable hhtp-header value for my GET request?

    - by Cortopasta
    I want the user to submit an answer to a question, then upon submission be redirected back to the page where they asked the question and I can't seem to get this to work: if (!isset($_POST['answer']) && !isset($_POST['verse'])) { echo "Please fill out form."; } elseif (!isset($_POST['answer']) || !isset($_POST['verse'])) { echo "one field left blank"; } else { $user->submitAnswer($question_id); header("Location: welcome.php?question_id=$question_id"); exit; } What am I doing wrong? EDIT: Sorry, wasn't very clear. I'm trying to pass the variable $question_id to the header(location: part so that it will pull up the question they were just on and show the answer they posted

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  • jQuery: AJAX call isn't updating page

    - by Cortopasta
    Thought I had a simple AJAX call using $.POST(), but apparently my function isn't firing, and nothing is updating :-/ Here is the call: $(".answerVerse ul li").click(function(){ var rank = $(this).removeClass("star_empty star_full star_highlight").attr("class"); var verse_id = $(this).parent().parent().find(".verseId").html(); var answer_id = $(this).parent().parent().find(".answerId").html(); var place = this; $.post("rank.php", { rank: rank, verse_id: verse_id, answer_id: answer_id },function(data){ $(place).parent().removeClass().addClass(data.newVerseRank); for (i=0;i<=5;i++) { $(".answerVerse ul."+i).each(function(){ $(".answerVerse ul."+i+" li."+i).prevAll().andSelf().removeClass("star_empty").addClass("star_full"); }); } }, "json"); }); And here is the PHP (rank.php) that it calls: require_once("dbcon.php"); $user = new user(); $user->updateVerseRank($_POST['verse_id'], $_POST['rank']); $user->getVerse($_POST['verse_id']); $user->getAnswer($_POST['answer_id']; $arr = array ('newVerseRank'=>htmlspecialchars(round($user->verse[3])),'newVerseVotes'=>htmlspecialchars(round($user->verse[4])),'newAnswerRank'=>htmlspecialchars($user->answer[3])); echo json_encode($arr); Why am I not updating the page? I know it's something dumb I'm doing seeing as how this is my first attempt at AJAX and JSON :-/ Just trying to learn

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  • What's the PHP framework equivalent of jQuery?

    - by Cortopasta
    jQuery made javascript so easy for me, I was able to get up and running in a couple of hours doing most tasks. Which PHP framework has similar ease of use and rapid development/write less ability? Or am I stuck basically learning a new language no matter what framework I decide on?

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  • Using $.post for simple ajax test, what am I missing?

    - by Cortopasta
    Playing with jquery for the first time, and I'm trying to get a simple AJAX set up working so I can better understand how things work. Unfortunately, I don't know a whole lot. Here's the HTML with the script: <html> <head> <title>AJAX attempt with jQuery</title> <script type="text/javascript" src="jquery.js"></script> <script type="text/javascript"> function ajax(str){ $("document").ready(function(){ $.post("ajaxjquerytest.php",str,function(){ $("p").html(response); }); }); </script> </head> <body> <input type="text" onchange="ajax(this.value)"></input> <p>Age?</p> </body> </html> And here is the PHP it's talking to: <?php $age = $_POST['age']; if ($age < 30) { echo "Young"; } else if ($age > 30) { echo "Old"; } else { echo "you're 30"; } ?>

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  • jQuery works on local host, but not on website

    - by Cortopasta
    Using Notepad++ and XAMPP to test stuff, then I upload it to the website over FTP. In the head of my code, I have this to call jQuery and the script: <script type="text/javascript" src="/jquery.js"></script> <script type="text/javascript" src="/portfolio.js"></script> and it works fine locally on my XAMPP server. But as soon as it's uploaded onto the host, it throws this error: Resource interpreted as script but transferred with MIME type text/html. Not sure what's going on, or why it's having a hard time using jQuery. Any ideas?

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  • jQuery not selecting div class

    - by Cortopasta
    Trying to make a simple toggle menu, and I can't seem to hide/show the sub menu using this bit of jQuery: $(".topic news").mouseup(function(){ $(".feed groups").hide("fast", function(){ $(".feed messages").hide("fast"); $("ul.feed news").toggle("fast"); }); }); Here is the corresponding HTML: <div class="topic news"> <span>News Feed</span> </div> <ul class="feed news"> <li>News item #1</li> <li>News item #1</li> <li>News item #1</li> <li>News item #1</li> <li>News item #1</li> </ul> Any ideas?

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  • Learning OOP in PHP, trying to refactor my code. Can't connect to database anymore.

    - by Cortopasta
    Thought I understood how classes work, then I tried this code: class user { var $dbcon; var $dbinfo; var $con; var $error; function dbConnect() { $this->dbinfo['server'] = "localhost"; $this->dbinfo['database'] = "foolish_faith"; $this->dbinfo['user'] = "user"; $this->dbinfo['password'] = "password"; $this->con = "mysql:host=".$dbinfo['server']."; dbname=".$dbinfo['database']; $this->dbcon = new PDO($con, $dbinfo['user'], $dbinfo['password']); $this->dbcon->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION); $this->error = $this->dbcon->errorInfo(); if ($error[0] != "") { print "Error!"; print_r($error); } } } Now it just spits out this error: Fatal error: Uncaught exception 'PDOException' with message 'invalid data source name' in E:\PortableApps\xampp\htdocs\dbcon.php:24 Stack trace: #0 E:\PortableApps\xampp\htdocs\dbcon.php(24): PDO-__construct('', NULL, NULL) #1 E:\PortableApps\xampp\htdocs\login.php(4): user-dbConnect() #2 {main} thrown in E:\PortableApps\xampp\htdocs\dbcon.php on line 24 Can anybody see what I'm doing wrong, as I'm sure it has to do with my lack of knowledge when it comes to classes?

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  • Stop $_POST from having the same value when I refresh

    - by Cortopasta
    When a vote value is changed, the form POSTs the change, then refreshes the page. This is called on the top of the page upon load: if (isset($_POST['q'.$question_id])) { $user->updateQuestionVotes($question_id, $_POST['q'.$question_id]); } Why does it update every time I refresh after the first time? Do I need to unset it somehow?

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