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  • JavaScript (jQuery) Regular Expression for searching through an array

    - by CoryDorning
    First and foremost, I do not know RegEx but am trying to piece something together to make this work. Just wanted you to be forewarned. ;) Anyways, I'm trying to create a regular expression to take a word from an array and see if it matches a word in another array. I only want the search to return true if the keyword array string contains the searchTerm word. (i.e. oneone would be false, so would ones). Any help is GREATLY appreciated. var searchTerm = ['one','two','three']; var keywords = ['String which contains one', 'This string is 2', 'Three is here']; var keywordIndex; // loop through each keyword array $.each(keywords, function(i) { $.each(searchTerm, function(j) { var rSearchTerm = new RegExp('\b' + searchTerm[j] + '\b',i); // if search term is found, swap accordion div content if (keywords[i].search(rSearchTerm) > -1) { keywordIndex = i; // grouping keyword is in } }); // end searchTerm loop }); // end keyword loop

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  • Global JavaScript Variable Scope: Why doesn't this work?

    - by CoryDorning
    So I'm playing around with JavaScript and came across what I think to be an oddity. Is anyone able to explain the following? (i've included the alerted values as comments) Why is the first alert(msg) inside foo() returning undefined and not outside? var msg = 'outside'; function foo() { alert(msg); // undefined var msg = 'inside'; alert(msg); // inside } foo(); alert(msg); // outside Considering these both work fine: var msg = 'outside'; function foo() { alert(msg); // outside } alert(msg); // outside and: var msg = 'outside'; function foo() { var msg = 'inside'; alert(msg); // inside } alert(msg); // outside

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