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  • How do I configure IIS to allow access to network resources for PHP scripts?

    - by Dereleased
    I am currently working on a PHP front-end that joins together a series of applications running on separate servers; many of these applications generate files that I need access to, but these files (for various reasons) reside on their parent servers. If I, from the command line, issue a bit of script such as: <?php var_dump(glob("\\\\machine-name\\some\\share\\*")); I will get the full contents of that directory, proving that there's no problem programmatically with PHP reading the contents of a UNC share. However, if I try to execute the same script from the web server, I get an empty array -- more specifically, if I use more explicitly functions designed to "open" a directory like it was a file, I get access errors. I believe this to be a permissions issue, but I am not a server/network administrator type, so I'm not sure what I need to do to correct this and get my script running, and the links I've checked out have not been a terrible amount of help, perhaps due to my background, or lack thereof as far as IIS is concerned, coupled with the fact that we are not actually using .NET for this. Relevant Stats: Windows Server 2008 Standard SP2 IIS 7.0 PHP 5.2.9 I will be connecting to two types of servers: a few other nearly-identical Server 2008 machines, and a machine running embedded XP. Links that have not been particularly helpful but maybe I am just misreading: http://support.microsoft.com/?id=306158 http://support.microsoft.com/kb/207671/EN-US/ http://support.microsoft.com/kb/280383/

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  • Clarification on ZVals

    - by Beachhouse
    I was reading this: http://www.dereleased.com/2011/04/27/the-importance-of-zvals-and-circular-references/ And there's an example that lost me a bit. $foo = &$bar; $bar = &$foo; $baz = 'baz'; $foo = &$baz; var_dump($foo, $bar); /* string(3) "baz" NULL */ If you’ve been following along, this should make perfect sense. $foo is created, and pointed at a ZVal location identified by $bar; when $bar is created, it points at the same place $foo was pointed. That location, of course, is null. When $foo is reassigned, the only thing that changes is to which ZVal $foo points; if we had assigned a different value to $foo first, then $bar would still retain that value. I learned to program in C. I understand that PHP is different and it uses ZVals instead of memory locations as references. But when you run this code: $foo = &$bar; $bar = &$foo; It seems to me that there would be two ZVals. In C there would be two memory locations (and the values would be of the opposite memory location). Can someone explain?

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