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  • Perl passing argument into eval

    - by ehretf
    I'm facing an issue using eval function. Indeed I have some function name inside a SQL database, my goal is to execute those functions within perl (after retrieve in SQL). Here is what I'm doing, considering that $RssSource-{$k}{Proceed} contains "&test" as a string retrieved from SQL: my $str2 = "ABCD"; eval "$RssSource->{$k}{Proceed}";warn if $@; sub test { my $arg = shift; print "fct TEST -> ", $row, "\n"; } This is working correctly and display: fct TEST -> However I would like to be able to pass $str2 as an argument to $RssSource-{$k}{Proceed} but I don't know how, every syntax I tried return an error: eval "$RssSource->{$k}{Proceed}$str2" eval "$RssSource->{$k}{Proceed}($str2)" eval "$RssSource->{$k}{Proceed}"$str2 eval "$RssSource->{$k}{Proceed}"($str2) May someone tell me how to properly pass an argument to the evaluated function? Thanks a lot for your help Regards. Florent

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