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  • Vue d'ensemble de l'architecture modulaire de Qt 5, un billet de Guillaume Belz

    La sortie de Qt 5 se précise de jour en jour. L'une des principales évolutions de Qt 5 est la réorganisation des différents modules. Certaines fonctionnalités sont séparées dans des modules indépendants, comme le transfert des widgets depuis QtGui vers QtWidget, ou déplacées dans des modules existants, comme l'intégration des fonctionnalités d'OpenGL depuis QtOpenGL vers QtGui. Ce billet de blog présente l'ensemble des modules de Qt 5 et les principaux changement que l'on y trouvera. Les modules de Qt 5

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  • Qt Graphics et performances - le coût des commodités, un article de Gunnar traduit par Guillaume Belz

    Le 11 décembre 2009, la documentation de QPainter subissait un énorme ajout concernant l'optimisation de son utilisation. En effet, le bon usage de cet outil n'était pas accessible à tous, il n'était pas présenté dans la documentation. Ceci ne fut qu'un prétexte à une série d'articles sur l'optimisation de QPainter et de Qt Graphics en général. Voici donc le premier article de cette série, les autres sont en préparation : Qt Graphics et performances : ce qui est critique et ce qui ne l'est pas Pensez-vous que cet ajout à la documentation de QPainter sera utile ? Trouvez-vous les performances de vos applications trop faibles ?...

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  • La recherche Full Text avec Solr, par Guillaume Rossolini

    Bonsoir, Voici un article que je ne parviens pas à finaliser dans le détail, mais qui me semble suffisamment avancé pour vous le présenter sans trop rougir : Configurer un moteur de recherche performant à l'aide d'Apache Lucene/Solr et Apache Tomcat (ou tout autre conteneur de servlets) Citation: Apache Lucene est un moteur d'indexation de texte permettant d'effectuer des recherches en langage naturel à l'aide de diverses manipulations automatiques du ...

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  • Filtres d'écran en 2D avec OpenGL dans le Blender Game Engine, une traduction de Guillaume Belz

    Bonjour à tous Blender est à l'origine un logiciel libre de dessin 3D, mais propose de plus en plus de fonctionnalités avancées d'animation. En particulier, Blender intègre un moteur de jeux appelé Blender Game Engine (BGE), qui permet aux utilisateurs d'écrire leurs propres shaders en utilisant les langages Python et OpenGL Shading Language (GLSL). Dans cet article, l'auteur présente les bases pour écrire ses propres shaders et les paramétrer dans Blender à partir d'un exemple simple : un filtre de flou. Filtres d'écran en 2D avec OpenGL dans le Blender Game Engine A...

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  • Les accesseurs et les détails d'implémentation, un billet de Guillaume Belz

    C'est une discussion qui revient régulièrement sur le chat de Developpez.com. Une personne demande comment fait-on pour accéder aux variables membres privées d'une classe et on lui répond de créer des getter et setter. Viens alors un C++ien moyen (c'est-à-dire un casse-pied, en général moi) qui hurle au scandale et sort l'adage bien connu : "les accesseurs, c'est le mal". S'en suit une discussion sur pourquoi les accesseurs sont à éviter, quand j'ai le temps et l'humeur.

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  • Le C++ expressif n° 3 : pourquoi les erreurs de templates posent problèmes, un article d'Eric Niebler traduit par Guillaume Belz

    Bienvenue dans le troisième article de la série « le C++ expressif », une série d'articles consacrés aux Domain-Specific Embedded Language (DSEL) et à Boost.Proto, une bibliothèque pour les implémenter en C++. Dans cet article, Eric Niebler aborde le problème délicat des messages d'erreurs générés par les templates et surtout le fait que ce n'est pas une fatalité. Il insiste en particulier sur le fait qu'il est de la responsabilités des concepteurs de bibliothèques de faire en sorte que les messages d'erreurs soient compréhensibles par les utilisateurs. Le C++ expressif n° 3 : pourquoi les erreurs des templates posent des problèmes et qu'est-ce que vous pouvez faire pour ça ?

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  • OpenGL dans Qt5, tour d'horizon des nouveautés de l'intégration d'OpenGL dans Qt, un billet de Guillaume Belz

    Bonjour, En attendant un article plus détaillé sur Qt5, voici une présentation des classes et des modules utilisant OpenGL dans Qt5. Je rappelle également comment activer l'accélération matérielle dans Qt4 (QGLWidget, QGraphicsView, QDeclarativeView) et explique comment installer les binaires de Qt5 dans Ubuntu en utilisant les dépôts ppa. L'article du blog : OpenGL dans Qt5. Prochainement, j'aborderai en détail dans ce blog le nouveau module Qt3D de Qt5, avec des projets d'exemple. Que pensez-vous de cette réorgan...

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  • Qt Graphics et performance - la folie est de mettre en forme le même texte, un article de Eskil Abrahamsen Blomfeldt, traduit par Guillaume Belz

    Le 11 décembre 2009, la documentation de QPainter subissait un énorme ajout concernant l'optimisation de son utilisation. En effet, le bon usage de cet outil n'était pas accessible à tous, il n'était pas présenté dans la documentation. Ceci ne fut qu'un prétexte à une série d'articles sur l'optimisation de QPainter et de Qt Graphics en général. Voici donc le premier article de cette série, les autres sont en préparation : Qt Graphics et performances : ce qui est critique et ce qui ne l'est pas Pensez-vous que cet ajout à la documentation de QPainter sera utile ? Trouvez-vous les performances de vos applications trop faibles ?...

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  • Apple lance un tour de France de présentations Mac OS X Server

    Notre confrère Guillaume Gete nous fait part de sa participation au tour de France de présentation sur Mac OS X Server organiser par Apple pour tous le mois de Juin : Citation: Envoyé par Guillaume Gete Hop, c'est bientôt l'été, et on va faire chauffer les processeurs des serveurs. Si vous avez envie d'en savoir plus sur Mac OS X Server, je présenterai les solutions autour de Mac OS X Server et le Mac mini serveur durant les prochaines semaines, dans le cadre des sém...

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  • How to add dynamically a component in JSF2 during an Ajax request.

    - by Guillaume
    Hello, I am currently trying to dynamically add a new component to the JSF component tree during an ajax request. In fact I add a child to the UIViewRoot component in my AjaxBehaviorListener which is fired on server side during the ajax request process. The issue is that the new component is not rendered. It seems that this component is not taken into account in the render response phase. Could you help me on this issue ? Regards, Guillaume

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  • /dev/sda1 not a subset of /dev/sda?

    - by Guillaume Brunerie
    Hi, the first entry of my partition table is: $ sudo hexdump -Cv -n 16 -s 446 /dev/sda 000001be 80 01 01 00 83 fe ff ff 3f 00 00 00 81 1c 20 03 |........?..... .| (-Cv describe the output format, -n 16 asks for 16 bytes and -s 446 skips the first 446 bytes) You can see that my first partition is a primary Linux partition and that this partition begin at sector 63 (see for example here for the structure of the partition table). I would then expect that except for the first 63 sectors and the other partitions, /dev/sda1 and /dev/sda are exactly the same. But this is not the case, the sector #2 of /dev/sda1 is not exactly the same as the sector #65 of /dev/sda (but they are very similar, only 16 bytes are different): $ sudo hexdump -Cv -n 512 -s 65b /dev/sda 00008200 00 20 19 00 90 03 64 00 2d 00 05 00 5a 2f 56 00 |. ....d.-...Z/V.| 00008210 b6 b1 16 00 00 00 00 00 02 00 00 00 02 00 00 00 |................| 00008220 00 80 00 00 00 80 00 00 00 20 00 00 d8 38 ee 4c |......... ...8.L| 00008230 9a 01 ef 4c 05 00 24 00 53 ef 01 00 01 00 00 00 |...L..$.S.......| 00008240 59 23 e9 4c 00 4e ed 00 00 00 00 00 01 00 00 00 |Y#.L.N..........| 00008250 00 00 00 00 0b 00 00 00 00 01 00 00 3c 00 00 00 |............<...| 00008260 42 02 00 00 7b 00 00 00 85 23 eb f2 71 67 44 f5 |B...{....#..qgD.| 00008270 bb 8f 6f f2 3a 59 ff 4d 55 62 75 6e 74 75 00 00 |..o.:Y.MUbuntu..| 00008280 00 00 00 00 00 00 00 00 2f 75 62 75 6e 74 75 00 |......../ubuntu.| 00008290 d8 3c df 5d 00 88 ff ff 52 d0 ef 1d 00 00 00 00 |.<.]....R.......| 000082a0 c0 40 51 b6 00 88 ff ff 00 4e c8 bb 00 88 ff ff |[email protected]......| 000082b0 c0 f6 86 b8 00 88 ff ff 30 2e 0d a0 ff ff ff ff |........0.......| 000082c0 38 3d df 5d 00 88 ff ff 00 00 00 00 00 00 fe 03 |8=.]............| 000082d0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 |................| 000082e0 08 00 00 00 00 00 00 00 00 00 00 00 8a 53 d3 0e |.............S..| 000082f0 7c 7a 43 e4 8b fb ca e0 72 b7 fa c8 01 01 00 00 ||zC.....r.......| 00008300 00 00 00 00 00 00 00 00 16 4c 47 4b 0a f3 03 00 |.........LGK....| 00008310 04 00 00 00 00 00 00 00 00 00 00 00 fe 7f 00 00 |................| 00008320 24 b7 0c 00 fe 7f 00 00 01 00 00 00 22 37 0d 00 |$..........."7..| 00008330 ff 7f 00 00 01 00 00 00 23 37 0d 00 00 00 00 00 |........#7......| 00008340 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 08 |................| 00008350 00 00 00 00 00 00 00 00 00 00 00 00 1c 00 1c 00 |................| 00008360 01 00 00 00 e9 7f 00 00 00 00 00 00 00 00 00 00 |................| 00008370 00 00 00 00 04 00 00 00 9f 7d bb 00 00 00 00 00 |.........}......| 00008380 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 |................| 00008390 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 |................| 000083a0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 |................| 000083b0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 |................| 000083c0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 |................| 000083d0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 |................| 000083e0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 |................| 000083f0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 |................| versus $ sudo hexdump -Cv -n 512 -s 2b /dev/sda1 00000400 00 20 19 00 90 03 64 00 2d 00 05 00 5a 2f 56 00 |. ....d.-...Z/V.| 00000410 b6 b1 16 00 00 00 00 00 02 00 00 00 02 00 00 00 |................| 00000420 00 80 00 00 00 80 00 00 00 20 00 00 df 76 ef 4c |......... ...v.L| 00000430 df 76 ef 4c 06 00 24 00 53 ef 01 00 01 00 00 00 |.v.L..$.S.......| 00000440 59 23 e9 4c 00 4e ed 00 00 00 00 00 01 00 00 00 |Y#.L.N..........| 00000450 00 00 00 00 0b 00 00 00 00 01 00 00 3c 00 00 00 |............<...| 00000460 46 02 00 00 7b 00 00 00 85 23 eb f2 71 67 44 f5 |F...{....#..qgD.| 00000470 bb 8f 6f f2 3a 59 ff 4d 55 62 75 6e 74 75 00 00 |..o.:Y.MUbuntu..| 00000480 00 00 00 00 00 00 00 00 2f 75 62 75 6e 74 75 00 |......../ubuntu.| 00000490 d8 3c df 5d 00 88 ff ff 52 d0 ef 1d 00 00 00 00 |.<.]....R.......| 000004a0 c0 40 51 b6 00 88 ff ff 00 4e c8 bb 00 88 ff ff |[email protected]......| 000004b0 c0 f6 86 b8 00 88 ff ff 30 2e 0d a0 ff ff ff ff |........0.......| 000004c0 38 3d df 5d 00 88 ff ff 00 00 00 00 00 00 fe 03 |8=.]............| 000004d0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 |................| 000004e0 08 00 00 00 00 00 00 00 00 00 00 00 8a 53 d3 0e |.............S..| 000004f0 7c 7a 43 e4 8b fb ca e0 72 b7 fa c8 01 01 00 00 ||zC.....r.......| 00000500 00 00 00 00 00 00 00 00 16 4c 47 4b 0a f3 03 00 |.........LGK....| 00000510 04 00 00 00 00 00 00 00 00 00 00 00 fe 7f 00 00 |................| 00000520 24 b7 0c 00 fe 7f 00 00 01 00 00 00 22 37 0d 00 |$..........."7..| 00000530 ff 7f 00 00 01 00 00 00 23 37 0d 00 00 00 00 00 |........#7......| 00000540 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 08 |................| 00000550 00 00 00 00 00 00 00 00 00 00 00 00 1c 00 1c 00 |................| 00000560 01 00 00 00 e9 7f 00 00 00 00 00 00 00 00 00 00 |................| 00000570 00 00 00 00 04 00 00 00 a3 7d bb 00 00 00 00 00 |.........}......| 00000580 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 |................| 00000590 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 |................| 000005a0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 |................| 000005b0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 |................| 000005c0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 |................| 000005d0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 |................| 000005e0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 |................| 000005f0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 |................| For example in the third line, there is a 8.L in the first hexdump and v.L in the second. Why are there differences?

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  • Access a content control in C# when using Master Pages

    - by Guillaume Gervais
    Good day everyone, I am building a page in ASP.NET, and using Master Pages in the process. I have a Content Place Holder name "cphBody" in my Master Page, which will contain the body of each Page for which that Master Page is the Master Page. In the ASP.NET Web page, I have a Content tag (referencing "cphBody") which also contains some controls (buttons, Infragistics controls, etc.), and I want to access these controls in the CodeBehind file. However, I can't do that directly (this.myControl ...), since they are nested in the Content tag. I found a workaround with the FindControl method. ContentPlaceHolder contentPlaceHolder = (ContentPlaceHolder) Master.FindControl("cphBody"); ControlType myControl = (ControlType) contentPlaceHolder.FindControl("ControlName"); That works just fine. However, I am suspecting that it's not a very good design. Do you guys know a more elegant way to do so? Thank you! Guillaume Gervais.

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  • Which simple Java JPA ORM tool to use ?

    - by Guillaume
    What Java ORM library implementing JPA that match following criteria would you recommend and why ? free & open source alive (at least bug fixes and a mailing list) with good documentation simple not hibernate (this one is well-known :-) ) I need to select a simple ORM tool that can be set up in minutes without and easy to understand for setting simple CRUD daos. A query builder ill be an interesting plus. Later I can have to move to Hibernate, that's why being JPA compliant is a must. I have found some candidates on the web, but not so much feedback, so I will gladly take your advices on the topic. ----- EDIT --------- I have been successfully testing ebean/avaje with a small test cases. Any one has a feedback on using this tool in production ?

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  • How to assign foo.example.com to one IP address and example.com to a different one?

    - by Guillaume Pierre
    Say that I have a domain name called example.com and two server located at 2 different IP addresses: 1.2.3.4 and 6.7.8.9. How could I assign example.com to 1.2.3.4 and the subdomain foo.example.com to 6.7.8.9? [EDIT] I did try to put a A record linking from @ to the first IP address and from foo.example.com to the second IP address, as illustrated below: And I did configure a vhosts called foo.example.com on my server at IP address 2. The @ record works. But after 3 hours waiting for the result (DNS delay), nothing happened with foo.example.com, which link to nothing. Why?

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  • How to tell thunar to stop using my device?

    - by Guillaume Coté
    When I do sudo umount /media/KINGSTON I got umount: /media/KINGSTON: device is busy. By using fuser -c /media/KINGSTON And cat /proc/<pid>/cmdline I found that the process is thunar--deamon. I closed all file manager windows. When I try to umount it by right cliking on the desktop, it also gave an error : An application is preventing the volume "KINGSTON" from being unmounted I am affraid that killing Thunar is going to impact other process running in other terminal. How can I tell it that I don't need this usb key anymore so it stop using it?

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  • Code maintenance: keeping a bad pattern when extending new code for being consistent or not ?

    - by Guillaume
    I have to extend an existing module of a project. I don't like the way it has been done (lots of anti-pattern involved, like copy/pasted code). I don't want to perform a complete refactor. Should I: create new methods using existing convention, even if I feel it wrong, to avoid confusion for the next maintainer and being consistent with the code base? or try to use what I feel better even if it is introducing another pattern in the code ? Precison edited after first answers: The existing code is not a mess. It is easy to follow and understand. BUT it is introducing lots of boilerplate code that can be avoided with good design (resulting code might become harder to follow then). In my current case it's a good old JDBC (spring template inboard) DAO module, but I have already encounter this dilemma and I'm seeking for other dev feedback. I don't want to refactor because I don't have time. And even with time it will be hard to justify that a whole perfectly working module needs refactoring. Refactoring cost will be heavier than its benefits. Remember: code is not messy or over-complex. I can not extract few methods there and introduce an abstract class here. It is more a flaw in the design (result of extreme 'Keep It Stupid Simple' I think) So the question can also be asked like that: You, as developer, do you prefer to maintain easy stupid boring code OR to have some helpers that will do the stupid boring code at your place ? Downside of the last possibility being that you'll have to learn some stuff and maybe you will have to maintain the easy stupid boring code too until a full refactoring is done)

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  • What is a good support knowledge base tool?

    - by Guillaume
    I have been searching for a tool to help my team organize its knowledge for resolving recurring support cases. I know this question will probably be closed, but I'll try my change anyway because I know that I can have some good answers about that. Context: our team is developing and supporting an huge applications (lots of different screens and workflow processes. We already have a good tool for managing our documentation, but we are struggling with support cases. Support action involve often quite a lot of manual steps to fix stuff and the knowledge for these actions is more 'oral transmission' than modern tools. We need an efficient way to store them in a knowledge base to be able to retrieve similar cases based on patterns (a stacktrace, an error message, a component name, a workflow step, ...) and ranked by similarity. Our wiki search is not very powerful when it come to this kind of search and the team members don't want to 'waste' time writing a report that will never be found... Do you know efficient knowledge base tool for this kind of use case ?

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  • Why ubuntu does not use the kernels installed by automatic update?

    - by Guillaume Coté
    I used the script describe in this question to list the kernel installed on the computer : How do I to remove or hide old kernel versions, to clean up the boot menu? In the 3.2.0, I have 33, 34, 35, 36, 37, 38, 39, 41, 43, 44, 45 and 48. I would expect to be running 3.2.0-48 after a reboot, but I am still running 3.2.0-32. Why the kernels installed by auto update are not used? [I am running 12.04 LTS] /boot/grub/menu.lst was modified for the last time June 16 2013, it contains 3.2.0-32-generic 2.6.32-45-generic 2.6.32-44-generic 2.6.32-43-generic A recovery for each of those and a memtest. I would have expected the kernel between 3.2.0-33 to 3.2.0-48 to be in this file before 3.2.0-32.

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  • Which simple Java JPA ORM tool to use ?

    - by Guillaume
    What Java ORM library implementing JPA that match following criteria would you recommend and why ? free & open source alive (at least bug fixes and a mailing list) with good documentation simple (simpler than hibernate) I need to select a simple ORM tool that can be set up in minutes, without too much configuration and easy to understand, for setting simple CRUD DAOs. A query builder will be an interesting plus. Later I can have to move to Hibernate, that's why being JPA compliant is a must. I have found some candidates on the web, but not so much feedback, so I will gladly take your advices on the topic. ----- EDIT --------- I have been successfully testing ebean/avaje with a small test cases. Any one has a feedback on using these tools in production ?

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  • How can I keep directories in sync

    - by Guillaume Boudreau
    I have a directory, dirA, that users can work in: they can create, modify, rename and delete files & sub-directores in dirA. I want to keep another directory, dirB, in sync with dirA. What I'd like, is a discussion on finding a working algorithm that would achieve the above, with the limitations listed below. Requirements: 1. Something asynchronous - I don't want to stop file operations in dirA while I work in dirB. 2. I can't assume that I can just blindly rsync dirA to dirB on regular interval - dirA could contain millions of files & directories, and terrabytes of data. Completely walking the dirA tree could take hours. Those two requirements makes this really difficult. Having it asynchronous means that when I start working on a specific file from dirA, it might have moved a lot since it appeared. And the second limitation means that I really need to watch dirA, and work on atomic file operations that I notice. Current (broken) implementation: 1. Log all file & directory operations in dirA. 2. Using a separate process, read that log, and 'repeat' all the logged operations in dirB. Why is it broken: echo 1 > dirA/file1 # Allow the 'log reader' process to create dirB/file1: log = "write dirA/file1"; action = cp dirA/file1 dirB/file1; result = OK echo 1 > dirA/file2 mv dirA/file1 dirA/file3 mv dirA/file2 dirA/file1 rm dirA/file3 # End result: file1 contains '1' # 'log reader' process starts working on the 4 above file operations: log = "write file2"; action = cp dirA/file2 dirB/file2; result = failed: there is no dirA/file2 log = "rename file1 file3"; action = mv dirB/file1 dirB/file3; result = OK log = "rename file2 file1"; action = mv dirB/file2 dirB/file1; result = failed: there is no dirB/file2 log = "delete file3"; action = rm dirB/file3; result = OK # End result in dirB: no more files! Another broken example: echo 1 > dirA/dir1/file1 mv dirA/dir1 dirA/dir2 # 'log reader' process starts working on the 2 above file operations: log = "write file1"; action = cp dirA/dir1/file1 dirB/dir1/file1; result = failed: there is no dirA/dir1/file1 log = "rename dir1 dir2"; action = mv dirB/dir1 dirB/dir2; result = failed: there is no dirA/dir1 # End result if dirB: nothing!

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  • Why do I get a blank screen when starting Wubi?

    - by August Guillaume
    I used Wubi to download 12.04 on a new partition. When restarting, the computer (Levono windows 7 -64) froze with no signal on my screen. Turning the computer on and off I received the option to sign in on windows or ubuntu. Windows worked well, but Ubuntu seems to bomb again as before. I can look at the new partition where some Ubuntu files exist via Windows explorer. What am I to do? Is 12.04 compatible with windows 7?

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  • java: how to compress data into a String and uncompress data from the String

    - by Guillaume
    I want to put some compressed data into a remote repository. To put data on this repository I can only use a method that take the name of the resource and its content as a String. (like data.txt + "hello world"). The repository is moking a filesystem but is not, so I can not use File directly. I want to be able to do the following: client send to server a file 'data.txt' server compress 'data.txt' into data.zip server send to repository content of data.zip repository store data.zip client download from repository data.zip and his able to open it with its favorite zip tool I have tried a lots of compressing example found on the web but each time a send the data to the repository, my resulting zip file is corrupted. Here is a sample class, using the zip*stream and that emulate the repository showcasing my problem. The created zip file is working, but after its 'serialization' it's get corrupted. (the sample class use jakarta commons.io ) Many thanks for your help. package zip; import java.io.File; import java.io.FileInputStream; import java.io.FileOutputStream; import java.io.IOException; import java.io.InputStream; import java.util.zip.ZipEntry; import java.util.zip.ZipInputStream; import java.util.zip.ZipOutputStream; import org.apache.commons.io.FileUtils; /** * Date: May 19, 2010 - 6:13:07 PM * * @author Guillaume AME. */ public class ZipMe { public static void addOrUpdate(File zipFile, File ... files) throws IOException { File tempFile = File.createTempFile(zipFile.getName(), null); // delete it, otherwise you cannot rename your existing zip to it. tempFile.delete(); boolean renameOk = zipFile.renameTo(tempFile); if (!renameOk) { throw new RuntimeException("could not rename the file " + zipFile.getAbsolutePath() + " to " + tempFile.getAbsolutePath()); } byte[] buf = new byte[1024]; ZipInputStream zin = new ZipInputStream(new FileInputStream(tempFile)); ZipOutputStream out = new ZipOutputStream(new FileOutputStream(zipFile)); ZipEntry entry = zin.getNextEntry(); while (entry != null) { String name = entry.getName(); boolean notInFiles = true; for (File f : files) { if (f.getName().equals(name)) { notInFiles = false; break; } } if (notInFiles) { // Add ZIP entry to output stream. out.putNextEntry(new ZipEntry(name)); // Transfer bytes from the ZIP file to the output file int len; while ((len = zin.read(buf)) > 0) { out.write(buf, 0, len); } } entry = zin.getNextEntry(); } // Close the streams zin.close(); // Compress the files if (files != null) { for (File file : files) { InputStream in = new FileInputStream(file); // Add ZIP entry to output stream. out.putNextEntry(new ZipEntry(file.getName())); // Transfer bytes from the file to the ZIP file int len; while ((len = in.read(buf)) > 0) { out.write(buf, 0, len); } // Complete the entry out.closeEntry(); in.close(); } // Complete the ZIP file } tempFile.delete(); out.close(); } public static void main(String[] args) throws IOException { final String zipArchivePath = "c:/temp/archive.zip"; final String tempFilePath = "c:/temp/data.txt"; final String resultZipFile = "c:/temp/resultingArchive.zip"; File zipArchive = new File(zipArchivePath); FileUtils.touch(zipArchive); File tempFile = new File(tempFilePath); FileUtils.writeStringToFile(tempFile, "hello world"); addOrUpdate(zipArchive, tempFile); //archive.zip exists and contains a compressed data.txt that can be read using winrar //now simulate writing of the zip into a in memory cache String archiveText = FileUtils.readFileToString(zipArchive); FileUtils.writeStringToFile(new File(resultZipFile), archiveText); //resultingArchive.zip exists, contains a compressed data.txt, but it can not //be read using winrar: CRC failed in data.txt. The file is corrupt } }

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  • java: how to get a string representation of a compressed byte array ?

    - by Guillaume
    I want to put some compressed data into a remote repository. To put data on this repository I can only use a method that take the name of the resource and its content as a String. (like data.txt + "hello world"). The repository is moking a filesystem but is not, so I can not use File directly. I want to be able to do the following: client send to server a file 'data.txt' server compress 'data.txt' into a compressed file 'data.zip' server send a string representation of data.zip to the repository repository store data.zip client download from repository data.zip and his able to open it with its favorite zip tool The problem arise at step 3 when I try to get a string representation of my compressed file. Here is a sample class, using the zip*stream and that emulate the repository showcasing my problem. The created zip file is working, but after its 'serialization' it's get corrupted. (the sample class use jakarta commons.io ) Many thanks for your help. package zip; import java.io.File; import java.io.FileInputStream; import java.io.FileOutputStream; import java.io.IOException; import java.io.InputStream; import java.util.zip.ZipEntry; import java.util.zip.ZipInputStream; import java.util.zip.ZipOutputStream; import org.apache.commons.io.FileUtils; /** * Date: May 19, 2010 - 6:13:07 PM * * @author Guillaume AME. */ public class ZipMe { public static void addOrUpdate(File zipFile, File ... files) throws IOException { File tempFile = File.createTempFile(zipFile.getName(), null); // delete it, otherwise you cannot rename your existing zip to it. tempFile.delete(); boolean renameOk = zipFile.renameTo(tempFile); if (!renameOk) { throw new RuntimeException("could not rename the file " + zipFile.getAbsolutePath() + " to " + tempFile.getAbsolutePath()); } byte[] buf = new byte[1024]; ZipInputStream zin = new ZipInputStream(new FileInputStream(tempFile)); ZipOutputStream out = new ZipOutputStream(new FileOutputStream(zipFile)); ZipEntry entry = zin.getNextEntry(); while (entry != null) { String name = entry.getName(); boolean notInFiles = true; for (File f : files) { if (f.getName().equals(name)) { notInFiles = false; break; } } if (notInFiles) { // Add ZIP entry to output stream. out.putNextEntry(new ZipEntry(name)); // Transfer bytes from the ZIP file to the output file int len; while ((len = zin.read(buf)) > 0) { out.write(buf, 0, len); } } entry = zin.getNextEntry(); } // Close the streams zin.close(); // Compress the files if (files != null) { for (File file : files) { InputStream in = new FileInputStream(file); // Add ZIP entry to output stream. out.putNextEntry(new ZipEntry(file.getName())); // Transfer bytes from the file to the ZIP file int len; while ((len = in.read(buf)) > 0) { out.write(buf, 0, len); } // Complete the entry out.closeEntry(); in.close(); } // Complete the ZIP file } tempFile.delete(); out.close(); } public static void main(String[] args) throws IOException { final String zipArchivePath = "c:/temp/archive.zip"; final String tempFilePath = "c:/temp/data.txt"; final String resultZipFile = "c:/temp/resultingArchive.zip"; File zipArchive = new File(zipArchivePath); FileUtils.touch(zipArchive); File tempFile = new File(tempFilePath); FileUtils.writeStringToFile(tempFile, "hello world"); addOrUpdate(zipArchive, tempFile); //archive.zip exists and contains a compressed data.txt that can be read using winrar //now simulate writing of the zip into a in memory cache String archiveText = FileUtils.readFileToString(zipArchive); FileUtils.writeStringToFile(new File(resultZipFile), archiveText); //resultingArchive.zip exists, contains a compressed data.txt, but it can not //be read using winrar: CRC failed in data.txt. The file is corrupt } }

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  • Installing gitosis and closed port?

    - by Nicolas GUILLAUME
    I'm trying to install gitosis on a Server (hosted by OVH and running Ubuntu server 11.04). I've done it a few times and never had any problems. But this time I have something very wired when I simply try to clone gitosis. [root@ovks-1:~/]#git clone git://eagain.net/gitosis.git Cloning into gitosis... eagain.net[0: 208.78.102.120]: errno=Connection refused fatal: unable to connect a socket (Connection refused) zsh: exit 128 git clone git://eagain.net/gitosis.git Based on my searches it looks like the port 9418 is closed. But I don't understand, a server by definition shouldn't have any closed port and I can't find a way to see if they are. So how can I check is a port is open and how can I open it if closed? Thank you for your help. Requested by WesleyDavid: iptables -L result [root@odeoos-vks-1:~/]#iptables -L Chain INPUT (policy ACCEPT) target prot opt source destination Chain FORWARD (policy ACCEPT) target prot opt source destination Chain OUTPUT (policy ACCEPT) target prot opt source destination I have no idea what it means... Thanks :)

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