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• Using HTTPPOST with WebViewClient

  - by miannelle

  I am looking for an example of using a WebViewClient with shouldOverrideUrlLoading and using HttpPost. I need to display a web page, keep it within my layout boundaries so it can not launch a new browser and also use HttpPost to send data to the host.

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• Android: Cannot get the httpPost params but can get the httpGet from php

  - by jjLin

  Here is my android code to send request: // defaultHttpClient DefaultHttpClient httpClient = new DefaultHttpClient(); HttpPost httpPost = new HttpPost(serverUrl); List<NameValuePair> params = new ArrayList<NameValuePair>(); params.add(new BasicNameValuePair("abc", "abc2")); httpPost.setEntity(new UrlEncodedFormEntity(params)); HttpResponse httpResponse = httpClient.execute(httpPost); HttpEntity httpEntity = httpResponse.getEntity(); InputStream is = null; is = httpEntity.getContent(); BufferedReader reader = new BufferedReader(new InputStreamReader( is, "UTF-8"), 8); StringBuilder sb = new StringBuilder(); String line = null; while ((line = reader.readLine()) != null) { sb.append(line + "\n"); } is.close(); String json = ""; json = sb.toString(); Log.d("JSON", "JSON is:" + json); and here is my php code to get the request: <?php echo $_POST['abc']; ?> When I run the application, the string json is nothing. I expect to get JSON is:abc2 Then I change the some code, in android part: HttpPost httpPost = new HttpPost(serverUrl); change to: HttpPost httpPost = new HttpPost(serverUrl + "?abc=abc3"); in php part: <?php echo $_GET['abc']; ?> This time, the string json in logcat is JSON is:abc3. It is correct!! I have tried lots of time, but seems cannot send HttpPost request with params. Any one can help me to find out what wrongs with my code??

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• Update the model on HttpPost and render the changes in the View

  - by Etienne Giust

  With MVC3, I came over that problem where I was rendering a view with an updated model at the end of an HttpPost and the changes to the model were never applied to the rendered view :   NOT working as expected ! [HttpPost]         public ActionResult Edit(JobModel editedJobModel)         {             // Update some model property             editedJobModel.IsActive = true;                          // The view will NOT be updated as expected             return View(editedJobModel);         }   This is the standard behavior. In MVC3, POSTing the model does not render the Html helpers again. In my example, a HiddenFor bound to the IsActive value will not have its value set to true after the view is rendered.   Are you stuck, then ?   Well, for one, you’re not supposed to do that: in an ideal world you are supposed to apply the Post/Redirect/Get pattern. You would redirect to a new GET after your POST performed its actions. That’s what I usually do, but sometimes, when maintaining code and implementing slight changes to a pre-existing and tested logic, one prefers to keep structural changes to a minimum.   If you really have to (but my advice is to try to implement the PRG pattern whenever possible), here is a solution to alter values of the model on a POST and have the MVC engine render it correctly :   Solution [HttpPost] public ActionResult Edit(JobModel editedJobModel) {     // NOT WORKING : Update some model property     //editedJobModel.IsActive = true;     //Force ModelState value for IsActive property     ModelState["IsActive"].Value = new ValueProviderResult(true, "True", null);          // The view will be updated as expected     return View(editedJobModel); }   As you can see, it is a “dirty” solution, as the name (as a  string) of the updated property is used as a key of the ModelState dictionary. Also, the use of ValueProviderResult is not that straightforward.   But hey, it works.

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• Why my HttpPost can't receive all response data?

  - by Johnny

  I'm on Android 1.5, and my code is like this: HttpPost httpPost = new HttpPost(url); HttpEntity entity = new UrlEncodedFormEntity(params, HTTP.UTF_8); httpPost.setEntity(entity); HttpResponse response = httpClient.execute(httpPost); HttpEntity respEntity = response.getEntity(); String result = EntityUtils.toString(respEntity, DEFAULT_CHARSET); After successfully executed these codes, the result is a stripped string. I've tried using browser to test the url+param, it works fine and got all data. What's wrong with this code? Is there any parameters I need to specified?

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• Android HttpPost: how to get the result

  - by Sumit M Asok

  I have been trying long to send an HttpPost request and retrieve response but even though I was able to make a connection I don't yet get how to get the string message which is returned by the request-response HttpClient httpclient = new DefaultHttpClient(); HttpPost httppost = new HttpPost("http://www.myurl.com/app/page.php"); // Add your data List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(5); nameValuePairs.add(new BasicNameValuePair("type", "20")); nameValuePairs.add(new BasicNameValuePair("mob", "919895865899")); nameValuePairs.add(new BasicNameValuePair("pack", "0")); nameValuePairs.add(new BasicNameValuePair("exchk", "1")); try { httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs)); Log.d("myapp", "works till here. 2"); try { HttpResponse response = httpclient.execute(httppost); Log.d("myapp", "response " + response.getEntity()); } catch (ClientProtocolException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } } catch (UnsupportedEncodingException e) { e.printStackTrace(); } I'm sorry, I sound very naive because I'm new to java. Please help me.

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• HttpPost works in Java project, not in Android

  - by dave.c

  I've written some code for my Android device to login to a web site over https and parse some data out of the resulting pages. An HttpGet happens first to get some info needed for login, then an HttpPost to do the actual login process. The code below works great in a Java project within Eclipse which has the following Jar files on the build path: httpcore-4.1-beta2.jar, httpclient-4.1-alpha2.jar, httpmime-4.1-alpha2.jar, commons-logging-1.1.1.jar. public static MyBean gatherData(String username, String password) { MyBean myBean = new MyBean(); try { HttpResponse response = doHttpGet(URL_PAGE_LOGIN, null, null); System.out.println("Got login page"); String content = EntityUtils.toString(response.getEntity()); String token = ContentParser.getToken(content); String cookie = getCookie(response); System.out.println("Performing login"); System.out.println("token = "+token +" || cookie = "+cookie); response = doLoginPost(username,password,cookie, token); int respCode = response.getStatusLine().getStatusCode(); if (respCode != 302) { System.out.println("ERROR: not a 302 redirect!: code is \""+ respCode+"\""); if (respCode == 200) { System.out.println(getHeaders(response)); System.out.println(EntityUtils.toString(response.getEntity()).substring(0, 500)); } } else { System.out.println("Logged in OK, loading account home"); // redirect handler and rest of parse removed } }catch (Exception e) { System.out.println("ERROR in gatherdata: "+e.toString()); e.printStackTrace(); } return myBean; } private static HttpResponse doHttpGet(String url, String cookie, String referrer) { try { HttpClient client = new DefaultHttpClient(); client.getParams().setParameter(CoreProtocolPNames.PROTOCOL_VERSION, HttpVersion.HTTP_1_1); client.getParams().setParameter(CoreProtocolPNames.HTTP_CONTENT_CHARSET, "UTF-8"); HttpGet httpGet = new HttpGet(url); httpGet.getParams().setParameter(CoreProtocolPNames.PROTOCOL_VERSION, HttpVersion.HTTP_1_1); httpGet.setHeader(HEADER_USER_AGENT,HEADER_USER_AGENT_VALUE); if (referrer != null && !referrer.equals("")) httpGet.setHeader(HEADER_REFERER,referrer); if (cookie != null && !cookie.equals("")) httpGet.setHeader(HEADER_COOKIE,cookie); return client.execute(httpGet); } catch (Exception e) { e.printStackTrace(); throw new ConnectException("Failed to read content from response"); } } private static HttpResponse doLoginPost(String username, String password, String cookie, String token) throws ClientProtocolException, IOException { try { HttpClient client = new DefaultHttpClient(); client.getParams().setParameter(CoreProtocolPNames.PROTOCOL_VERSION, HttpVersion.HTTP_1_1); client.getParams().setParameter(CoreProtocolPNames.HTTP_CONTENT_CHARSET, "UTF-8"); HttpPost post = new HttpPost(URL_LOGIN_SUBMIT); post.getParams().setParameter(CoreProtocolPNames.PROTOCOL_VERSION, HttpVersion.HTTP_1_1); post.setHeader(HEADER_USER_AGENT,HEADER_USER_AGENT_VALUE); post.setHeader(HEADER_REFERER, URL_PAGE_LOGIN); post.setHeader(HEADER_COOKIE, cookie); post.setHeader("Content-Type","application/x-www-form-urlencoded"); List<NameValuePair> formParams = new ArrayList<NameValuePair>(); formParams.add(new BasicNameValuePair("org.apache.struts.taglib.html.TOKEN", token)); formParams.add(new BasicNameValuePair("showLogin", "true")); formParams.add(new BasicNameValuePair("upgrade", "")); formParams.add(new BasicNameValuePair("username", username)); formParams.add(new BasicNameValuePair("password", password)); formParams.add(new BasicNameValuePair("submit", "Secure+Log+in")); UrlEncodedFormEntity entity = new UrlEncodedFormEntity(formParams,HTTP.UTF_8); post.setEntity(entity); return client.execute(post); } catch (Exception e) { e.printStackTrace(); throw new ConnectException("ERROR in doLoginPost(): "+e.getMessage()); } } The server (which is not under my control) returns a 302 redirect when the login was successful, and 200 if it fails and re-loads the login page. When run with the above Jar files I get the 302 redirect, however if I run the exact same code from an Android project with the 1.6 Android Jar file on the build path I get the 200 response from the server. I get the same 200 response when running the code on my 2.2 device. My android application has internet permissions, and the HttpGet works fine. I'm assuming that the problem lies in the fact that HttpPost (or some other class) is different in some significant way between the Android Jar version and the newer Apache versions. I've tried adding the Apache libraries to the build path of the Android project, but due to the duplicate classes I get messages like: INFO/dalvikvm(390): DexOpt: not resolving ambiguous class 'Lorg/apache/http/impl/client/DefaultHttpClient;' in the log. I've also tried using a MultipartEntity instead of the UrlEncodedFormEntity but I get the same 200 result. So, I have a few questions: - Can I force the code running under android to use the newer Apache libraries in preference to the Android versions? - If not, does anyone have any ideas how can I alter my code so that it works with the Android Jar? - Are there any other, totally different approaches to doing an HttpPost in Android? - Any other ideas? I've read a lot of posts and code but I'm not getting anywhere. I've been stuck on this for a couple of days and I'm at a loss how to get the thing to work, so I'll try anything at this point. Thanks in advance.

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• is there a difference between HttpPost AcceptPost and PostOnly attributes from mvc2 and mvccontrib

  - by Omu

  is there a difference between HttpPost from mvc2 and AcceptPost, PostOnly attributes from mvccontrib ?

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• Android - How can I upload a txt file to a website?

  - by Donal Rafferty

  I want to upload a txt file to a website, I'll admit I haven't looked into it in any great detail but I have looked at a few examples and would like more experienced opinions on whether I'm going in the right direction. Here is what I have so far: DefaultHttpClient httpClient = new DefaultHttpClient(); HttpContext localContext = new BasicHttpContext(); private String ret; HttpResponse response = null; HttpPost httpPost = null; public String postPage(String url, String data, boolean returnAddr) { ret = null; httpClient.getParams().setParameter(ClientPNames.COOKIE_POLICY, CookiePolicy.RFC_2109); httpPost = new HttpPost(url); response = null; StringEntity tmp = null; try { tmp = new StringEntity(data,"UTF-8"); } catch (UnsupportedEncodingException e) { System.out.println("HTTPHelp : UnsupportedEncodingException : "+e); } httpPost.setEntity(tmp); try { response = httpClient.execute(httpPost,localContext); } catch (ClientProtocolException e) { System.out.println("HTTPHelp : ClientProtocolException : "+e); } catch (IOException e) { System.out.println("HTTPHelp : IOException : "+e); } ret = response.getStatusLine().toString(); return ret; } And I call it as follows: postPage("http://www.testwebsite.com", "data/data/com.testxmlpost.xml/files/logging.txt", true)); I want to be able to upload a file from the device to a website. But when trying this way I get the following response back. HTTP/1.1 405 Method Not Allowed Am I trying the correct way or should I be doing it another way?

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• HttpPost request unsuccessful

  - by The Thom

  I have written a web service and am now writing a tester to perform integration testing from the outside. I am writing my tester using apache httpclient 4.3. Based on the code here: http://hc.apache.org/httpcomponents-client-4.3.x/quickstart.html and here: http://hc.apache.org/httpcomponents-client-4.3.x/tutorial/html/fundamentals.html#d5e186 I have written the following code. Map<String, String> parms = new HashMap<>(); parms.put(AirController.KEY_VALUE, json); postUrl(SERVLET, parms); ... protected String postUrl(String servletName, Map<String, String> parms) throws AirException{ String url = rootUrl + servletName; HttpPost post = new HttpPost(url); List<NameValuePair> nvps = new ArrayList<NameValuePair>(); for(Map.Entry<String, String> entry:parms.entrySet()){ BasicNameValuePair parm = new BasicNameValuePair(entry.getKey(), entry.getValue()); nvps.add(parm); } try { post.setEntity(new UrlEncodedFormEntity(nvps)); } catch (UnsupportedEncodingException use) { String msg = "Invalid parameters:" + parms; throw new AirException(msg, use); } CloseableHttpResponse response; try { response = httpclient.execute(post); } catch (IOException ioe) { throw new AirException(ioe); } String result; if(HttpStatus.SC_OK == response.getStatusLine().getStatusCode()){ result = processResponse(response); } else{ String msg = MessageFormat.format("Invalid status code {0} received from query {1}.", new Object[]{response.getStatusLine().getStatusCode(), url}); throw new AirException(msg); } return result; } This code successfully reaches my servlet. In my servlet, I have (using Spring's AbstractController): protected ModelAndView post(HttpServletRequest request, HttpServletResponse response) { String json = String.valueOf(request.getParameter(KEY_VALUE)); if(json.equals("null")){ log.info("Received null value."); response.setStatus(406); return null; } And this code always falls into the null parameter code and returns a 406. I'm sure I'm missing something simple, but can't see what it is.

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• ASP.NET MVC - HttpPost to ReturnURL after redirect

  - by JP

  Hello, I am writing an ASP.NET MVC 2.0 application which requires users to log in before placing a bid on an item. I am using an actionfilter to ensure that the user is logged in and, if not, send them to a login page and set the return url. Below is the code i use in my action filter. if (!filterContext.HttpContext.User.Identity.IsAuthenticated) { filterContext.Result = new RedirectResult(String.Concat("~/Account/LogOn","?ReturnUrl=",filterContext.HttpContext.Request.RawUrl)); return; } In my logon controller I validate the users credentials then sign them in and redirect to the return url FormsAuth.SignIn(userName, rememberMe); if (!String.IsNullOrEmpty(returnUrl)) { return Redirect(returnUrl); } My problem is that this will always use a Get (HttpGet) request whereas my original submission was a post (HttpPost) and should always be a post. Can anyone suggest a way of passing this URL including the HttpMethod or any workaround to ensure that the correct HttpMethod is used? Thanks in advance, JP

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• MVC null model problem

  - by femi

  hello, i have created two create actions..one to call the create view and the other to process the create view using httppost. when i call the create view, it gets published correctly , dropdowns and all. the problem is that when i fill out the create form and click on the submit button, i get an error; Object reference not set to an instance of an object. My first thoughts are that i am passing a null model to the httppost create action.. How can i check to see if i am passing in a null model to the httppost create action? thanks

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• Using C# to HttpPost data to a web page

  - by druffmuff

  I want to log in into a website using C# code. Here's the html code of the example form: <form action="http://www.site.com/login.php" method="post" name="login" id="login"> <table border="0" cellpadding="2" cellspacing="0"> <tbody> <tr><td><b>User:</b></td><td colspan=\"2\"><b>Password:</b></td></tr> <tr> <td><input class="inputbg" name="user" type="text"></td> <td><input class="inputbg" name="password" type="password"></td> <td><input type="submit" name="user_control" value="Submit" class="buttonbg"></td> </tr> </tbody></table> </form> This is what I have tried so far with unsuccessful results: HttpWebRequest request = (HttpWebRequest)WebRequest.Create("http://www.site.com/login.php"); request.Method = "POST"; using (StreamWriter writer = new StreamWriter(request.GetRequestStream(), Encoding.ASCII)) { writer.Write("user=user&password=pass&user_control=Eingabe"); } HttpWebResponse response = (HttpWebResponse)request.GetResponse(); using (StreamReader reader = new StreamReader(response.GetResponseStream())) { stream = new StreamWriter("login.html"); stream.Write(reader.ReadToEnd()); stream.Close(); } Any Ideas, why this is failing?

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• Wrapper class for HttpGet / Post in Java?

  - by Tim Green

  Hi, Sorry, I'm quite new to Java. I've stumbled across HttpGet and HttpPost which seem to be perfect for my needs, but a little long winded. I have written a rather bad wrapper class, but does anyone know of where to get a better one? Ideally, I'd be able to do String response = fetchContent("http://url/", postdata); where postdata is optional. Thanks!

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• Problem simulating HTTP POST using HttpClient

  - by user560904

  I am trying to programatically send a HTTP Post request using HttpClient to http://ojp.nationalrail.co.uk/en/s/planjourney/query but it is not liking the request I send it. I copied the headers and body from what Chrome browser sends so it is identical but it doesn't like what I send as the HTML mentions there's an error. <div class="padding"> <h1 class="sifr"><strong>Sorry</strong>, something went wrong</h1> <div class="error-message"> <div class="error-message-padding"> <h2>There is a problem with the page you are trying to access.</h2> <p>It is possible that it was either moved, it doesn't exist or we are experiencing some technical difficulties.</p> <p>We are sorry for the inconvenience.</p> </div> </div> </div> Here is my Java program which uses HttpClient: package com.tixsnif; import org.apache.http.*; import org.apache.http.client.HttpClient; import org.apache.http.client.entity.UrlEncodedFormEntity; import org.apache.http.client.methods.HttpPost; import org.apache.http.impl.client.DefaultHttpClient; import org.apache.http.message.BasicNameValuePair; import org.apache.http.protocol.HTTP; import java.io.*; import java.util.*; import java.util.zip.GZIPInputStream; public class WebScrapingTesting { public static void main(String[] args) throws Exception { String target = "http://ojp.nationalrail.co.uk/en/s/planjourney/query"; HttpClient client = new DefaultHttpClient(); HttpPost httpPost = new HttpPost(target); BasicNameValuePair[] params = { new BasicNameValuePair("jpState", "single"), new BasicNameValuePair("commandName", "journeyPlannerCommand"), new BasicNameValuePair("from.searchTerm", "Basingstoke"), new BasicNameValuePair("to.searchTerm", "Reading"), new BasicNameValuePair("timeOfOutwardJourney.arrivalOrDeparture", "DEPART"), new BasicNameValuePair("timeOfOutwardJourney.monthDay", "Today"), new BasicNameValuePair("timeOfOutwardJourney.hour", "10"), new BasicNameValuePair("timeOfOutwardJourney.minute", "15"), new BasicNameValuePair("timeOfReturnJourney.arrivalOrDeparture", "DEPART"), new BasicNameValuePair("timeOfReturnJourney.monthDay", "Today"), new BasicNameValuePair("timeOfReturnJourney.hour", "18"), new BasicNameValuePair("timeOfReturnJourney.minute", "15"), new BasicNameValuePair("_includeOvertakenTrains", "on"), new BasicNameValuePair("viaMode", "VIA"), new BasicNameValuePair("via.searchTerm", "Station name / code"), new BasicNameValuePair("offSetOption", "0"), new BasicNameValuePair("_reduceTransfers", "on"), new BasicNameValuePair("operatorMode", "SHOW"), new BasicNameValuePair("operator.code", ""), new BasicNameValuePair("_lookForSleeper", "on"), new BasicNameValuePair("_directTrains", "on")}; httpPost.setHeader("Host", "ojp.nationalrail.co.uk"); httpPost.setHeader("User-Agent", "Mozilla/5.0 (Macintosh; U; Intel Mac OS X 10_6_4; en-US) AppleWebKit/534.10 (KHTML, like Gecko) Chrome/8.0.552.231 Safari/534.10"); httpPost.setHeader("Accept-Encoding", "gzip,deflate,sdch"); httpPost.setHeader("Accept", "text/html,application/xhtml+xml,application/xml;q=0.9,**/*//*;q=0.8"); httpPost.setHeader("Accept-Language", "en-us,en;q=0.8"); httpPost.setHeader("Accept-Charset", "ISO-8859-1,utf-8;q=0.7,*;q=0.7"); httpPost.setHeader("Origin", "http://www.nationalrail.co.uk/"); httpPost.setHeader("Referer", "http://www.nationalrail.co.uk/"); httpPost.setHeader("Content-Type", "application/x-www-form-urlencoded"); httpPost.setHeader("Cookie", "JSESSIONID=B2A3419B79C5D999CA4806B459675CCD.app201; Path=/"); UrlEncodedFormEntity urlEncodedFormEntity = new UrlEncodedFormEntity(Arrays.asList(params)); urlEncodedFormEntity.setContentEncoding(HTTP.UTF_8); httpPost.setEntity(urlEncodedFormEntity); HttpResponse response = client.execute(httpPost); InputStream input = response.getEntity().getContent(); GZIPInputStream gzip = new GZIPInputStream(input); InputStreamReader isr = new InputStreamReader(gzip); BufferedReader br = new BufferedReader(isr); String line = null; while((line = br.readLine()) != null) { System.out.printf("\n%s", line); } client.getConnectionManager().shutdown(); } } I keep the JSESSION ID updated if it expires but there seems to be another problem that I cannot see. Am I missing something rather obvious? He

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• How can I debug this web service http handler?

  - by baron

  Hello everyone, I am building a Httphandler following these instructions here It manipulates HTTP POST and HTTP GET. I have a client with two buttons two POST and GET. After i've tested and happy everythings working I move it from localhost to IIS. Now when I do this I get an exception in the POST handler code. How on earth can I debug this code line by line? I managed to do this awhile ago, I thought it was by attaching to process but I can't work it out. I can emulate GET just by typing address in browser, post im not sure about. I've tried telnetting and sending it from there but haven't had any luck.

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• ASP.Net MVC 2 is it possible to get the same instance of model(with slight changes) in HttpPost meth

  - by jjjjj

  Hi I have a complex entity User: public class User : BaseEntity { public virtual Taxi Taxi { get; set; } --> That is why i call it "complex" public virtual string Login { get; set; } public virtual string Password { get; set; } } where Taxi is a parent of User (Taxi has-many Users): public class Taxi : BaseEntity { public virtual string Name { get; set; } public virtual string ClientIp { get; set; } } BaseEntity consists of public virtual int Id { get; private set; } The problem occurs while trying to edit User [Authorize] public ActionResult ChangeAccountInfo() { var user = UserRepository.GetUser(User.Identity.Name); return View(user); } My ChangeAccountInfo.aspx <fieldset> <legend>Fields</legend> <% %> <div class="editor-label"> <%: Html.LabelFor(model => model.Login) %> </div> <div class="editor-field"> <%: Html.TextBoxFor(model => model.Login) %> <%: Html.ValidationMessageFor(model => model.Login) %> </div> <div class="editor-label"> <%: Html.LabelFor(model => model.Password) %> </div> <div class="editor-field"> <%: Html.TextBoxFor(model => model.Password) %> <%: Html.ValidationMessageFor(model => model.Password) %> </div> <div class="editor-field"> <%: Html.HiddenFor(model => model.Taxi.Name)%> </div> <p> <input type="submit" value="Save" /> </p> </fieldset> Post changes: [Authorize] [HttpPost] public ActionResult ChangeAccountInfo(User model) { if (ModelState.IsValid) { UserRepository.UpdateUser(model); return RedirectToAction("ChangeAccountInfoSuccess", "Account"); } return View(model); } But, the (User model) parameter has User.Id == 0 -- User entity had 5 before edit User.Login == "my new login" User.Password == "my new password" User.Taxi.Id == 0 -- User.Taxi entity had 3 before edit User.Taxi.Name == "old hidden name" User.Taxi.ClientIp == null -- User entity had 192.168.0.1 before edit Q: Is it possible not to mark all the fields of an entity (that should be in my UpdateUser) with tag "hidden" but still have them unchanged in my HttpPost method? e.g. not User.Taxi.ClientIp = null, but User.Taxi.ClientIp = 192.168.0.1 I'm using nhibernate, if it matters.

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• How do the httppost, httpput etc attributes in ASP.NET MVC 2 work?

  - by Tomas Lycken

  In ASP.NET MVC 2, a couple of new action filter attributes were introduced, as "shorthand" for attributes in ASP.NET MVC 1; for example, applying the HttpPostAttribute does the same thing as applying [AcceptVerbs(HttpVerbs.Post)] to an action method. In addition, with the more verbose syntax, it is possible to combine different methods, in order to allow for example both Post and Delete. Now I'm wondering: how do the new attributes work? If I apply both [HttpPost] and [HttpDelete], will ASP.NET MVC 2 allow both or require both (thus allowing nothing)?

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• Html.RenderAction Failed when Validation Failed

  - by Shaun

  RenderAction method had been introduced when ASP.NET MVC 1.0 released in its MvcFuture assembly and then final announced along with the ASP.NET MVC 2.0. Similar as RenderPartial, the RenderAction can display some HTML markups which defined in a partial view in any parent views. But the RenderAction gives us the ability to populate the data from an action which may different from the action which populating the main view. For example, in Home/Index.aspx we can invoke the Html.RenderPartial(“MyPartialView”) but the data of MyPartialView must be populated by the Index action of the Home controller. If we need the MyPartialView to be shown in Product/Create.aspx we have to copy (or invoke) the relevant code from the Index action in Home controller to the Create action in the Product controller which is painful. But if we are using Html.RenderAction we can tell the ASP.NET MVC from which action/controller the data should be populated. in that way in the Home/Index.aspx and Product/Create.aspx views we just need to call Html.RenderAction(“CreateMyPartialView”, “MyPartialView”) so it will invoke the CreateMyPartialView action in MyPartialView controller regardless from which main view. But in my current project we found a bug when I implement a RenderAction method in the master page to show something that need to connect to the backend data center when the validation logic was failed on some pages. I created a sample application below.   Demo application I created an ASP.NET MVC 2 application and here I need to display the current date and time on the master page. I created an action in the Home controller named TimeSlot and stored the current date into ViewDate. This method was marked as HttpGet as it just retrieves some data instead of changing anything. 1: [HttpGet] 2: public ActionResult TimeSlot() 3: { 4: ViewData["timeslot"] = DateTime.Now; 5: return View("TimeSlot"); 6: } Next, I created a partial view under the Shared folder to display the date and time string. 1: <%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<dynamic>" %> 2:  3: <span>Now: <% 1: : ViewData["timeslot"].ToString() %></span> Then at the master page I used Html.RenderAction to display it in front of the logon link. 1: <div id="logindisplay"> 2: <% 1: Html.RenderAction("TimeSlot", "Home"); %> 3:  4: <% 1: Html.RenderPartial("LogOnUserControl"); %> 5: </div> It’s fairly simple and works well when I navigated to any pages. But when I moved to the logon page and click the LogOn button without input anything in username and password the validation failed and my website crashed with the beautiful yellow page. (I really like its color style and fonts…)   How ASP.NET MVC executes Html.RenderAction In this example all other pages were rendered successful which means the ASP.NET MVC found the TimeSolt action under the Home controller except this situation. The only different is that when I clicked the LogOn button the browser send an HttpPost request to the server. Is that the reason of this bug? I created another action in Home controller with the same action name but for HttpPost. 1: [HttpPost] 2: [ActionName("TimeSlot")] 3: public ActionResult TimeSlot(object dummy) 4: { 5: return TimeSlot(); 6: } Or, I can use the AcceptVerbsAttribute on the TimeSlot action to let it allow both HttpGet and HttpPost. 1: [AcceptVerbs("GET", "POST")] 2: public ActionResult TimeSlot() 3: { 4: ViewData["timeslot"] = DateTime.Now; 5: return View("TimeSlot"); 6: } And then repeat what I did before and this time it worked well. Why we need the action for HttpPost here as it’s just data retrieving? That is because of how ASP.NET MVC executes the RenderAction method. In the source code of ASP.NET MVC we can see when proforming the RenderAction ASP.NET MVC creates a RequestContext instance from the current RequestContext and created a ChildActionMvcHandler instance which inherits from MvcHandler class. Then the ASP.NET MVC processes the handler through the HttpContext.Server.Execute method. That means it performs the action as a stand-alone request asynchronously and flush the result into the  TextWriter which is being used to render the current page. Since when I clicked the LogOn the request was in HttpPost so when ASP.NET MVC processed the ChildActionMvcHandler it would find the action which allow the current request method, which is HttpPost. Then our TimeSlot method in HttpGet would not be matched.   Summary In this post I introduced a bug in my currently developing project regards the new Html.RenderAction method provided within ASP.NET MVC 2 when processing a HttpPost request. In ASP.NET MVC world the underlying Http information became more important than in ASP.NET WebForm world. We need to pay more attention on which kind of request it currently created and how ASP.NET MVC processes.   Hope this helps, Shaun   All documents and related graphics, codes are provided "AS IS" without warranty of any kind. Copyright © Shaun Ziyan Xu. This work is licensed under the Creative Commons License.

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• Connecting to a web server over HTTP, code snippet

  - by Emanuil

  I'v got the following piece of code: try { HttpClient httpClient = new DefaultHttpClient(); HttpPost httpPost = new HttpPost("http://www.flashstall.com/json.txt"); HttpResponse httpResponse = httpClient.execute(httpPost); } catch (Exception e) { Log.e("m40", "Error in http connection " + e.toString()); } When I run it it logs "Error in http connection java.net.UnkownHostException: www.flashstall.com". What am I doing wrong?

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• Android Samsung S2 spannablestringbuilder error

  - by Bilal Akmal

  I'm working on an app which fetches data from server using JSON. It is working fine in emulator but in my phone, it is giving error and not getting data. The error comes at this point in JSON Parser.... HttpPost httpPost = new HttpPost(url); httpPost.setEntity(new UrlEncodedFormEntity(params)); HttpResponse httpResponse = httpClient.execute(httpPost);//Error Point httpEntity = httpResponse.getEntity(); On the third line logcat shows.... SPAN_EXCLUSIVE_EXCLUSIVE spans cannot have a zero length I have searched a lot but it doesn't help me.

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• Retrieve XML from URL

  - by Pl4za

  I am having some problems retrieving a xml from url with the following code: private static String getAlbumArt(String artistName, String albumName){ try{ XMLParser xml_parser = new XMLParser(); String xml = xml_parser.getXmlFromUrl(getAlbumURL(artistName, albumName)); Document doc = xml_parser.getDomElement(xml); NodeList N = doc.getElementsByTagName("album"); Node node = N.item(0); NodeList N2 = node.getChildNodes(); System.out.println("1------"); for (int i = 0; i < N2.getLength(); i++) { Node detailNode = N2.item(i); if (detailNode.getNodeType() == Node.ELEMENT_NODE) { System.out.println("2------"); if (detailNode.getNodeName().equalsIgnoreCase("image")) { String sizeVal = ((Element) detailNode).getAttribute("size"); String url = detailNode.getTextContent(); if (sizeVal.equalsIgnoreCase("large")) { return url; } } } } } catch (Exception e){ } return null; } The xml function which i call in the above code: public String getXmlFromUrl(String url) { String xml = null; try { DefaultHttpClient httpClient = new DefaultHttpClient(); HttpPost httpPost = new HttpPost(url); HttpResponse httpResponse = httpClient.execute(httpPost); HttpEntity httpEntity = httpResponse.getEntity(); xml = EntityUtils.toString(httpEntity); } catch (UnsupportedEncodingException e) { e.printStackTrace(); } catch (ClientProtocolException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } return xml; } getAlbumURL: public static String getAlbumURL(String artist, String album){ return URL_METHOD + METHOD_GETALBUM + AMPERSAND + API_KEY + AMPERSAND + PARAM_ARTIST + artist + AMPERSAND + PARAM_ALBUM + album; } XMLparser: public class XMLParser { // constructor public XMLParser() { } //Get XML from URL public String getXmlFromUrl(String url) { String xml = null; try { DefaultHttpClient httpClient = new DefaultHttpClient(); HttpPost httpPost = new HttpPost(url); HttpResponse httpResponse = httpClient.execute(httpPost); HttpEntity httpEntity = httpResponse.getEntity(); xml = EntityUtils.toString(httpEntity); } catch (UnsupportedEncodingException e) { e.printStackTrace(); } catch (ClientProtocolException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } return xml; } //Get dom element public Document getDomElement(String xml){ Document doc = null; DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); try { DocumentBuilder db = dbf.newDocumentBuilder(); InputSource is = new InputSource(); is.setCharacterStream(new StringReader(xml)); doc = db.parse(is); } catch (ParserConfigurationException e) { Log.e("Error: ", e.getMessage()); return null; } catch (SAXException e) { Log.e("Error: ", e.getMessage()); return null; } catch (IOException e) { Log.e("Error: ", e.getMessage()); return null; } return doc; } //Get nod element public final String getElementValue(Node elem ) { Node child; if( elem != null){ if (elem.hasChildNodes()){ for( child = elem.getFirstChild(); child != null; child = child.getNextSibling() ){ if( child.getNodeType() == Node.TEXT_NODE ){ return child.getNodeValue(); } } } } return ""; } //Get element value public String getValue(Element item, String str) { NodeList nlList = item.getElementsByTagName(str).item(0).getChildNodes(); Node nValue = (Node) nlList.item(0); return nValue.getNodeValue(); } } Any ideas ? I seriously don't know what is wrong.. I used this before and it worked.

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• ASP.NET. MVC2. Entity Framework. Cannot pass primary key value back from view to [HttpPost]

  - by Paul Connolly

  I pass a ViewModel (which contains a "Person" object) from the "EditPerson" controller action into the view. When posted back from the view, the ActionResult receives all of the Person properties except the ID (which it says is zero instead of say its real integer) Can anyone tell me why? The controllers look like this: public ActionResult EditPerson(int personID) { var personToEdit = repository.GetPerson(personID); FormationViewModel vm = new FormationViewModel(); vm.Person = personToEdit; return View(vm); } [HttpPost] public ActionResult EditPerson(FormationViewModel model) <<Passes in all properties except ID { // Persistence code } The View looks like this: <%@ Page Title="" Language="C#" MasterPageFile="~/Views/Shared/Site.Master" Inherits="System.Web.Mvc.ViewPage<Afp.Models.Formation.FormationViewModel>" %> <% using (Html.BeginForm()) {% <%= Html.ValidationSummary(true) % <fieldset> <legend>Fields</legend> <div class="editor-label"> <%= Html.LabelFor(model => model.Person.Title) %> </div> <div class="editor-field"> <%= Html.TextBoxFor(model => model.Person.Title) %> <%= Html.ValidationMessageFor(model => model.Person.Title) %> </div> <div class="editor-label"> <%= Html.LabelFor(model => model.Person.Forename)%> </div> <div class="editor-field"> <%= Html.TextBoxFor(model => model.Person.Forename)%> <%= Html.ValidationMessageFor(model => model.Person.Forename)%> </div> <div class="editor-label"> <%= Html.LabelFor(model => model.Person.Surname)%> </div> <div class="editor-field"> <%= Html.TextBoxFor(model => model.Person.Surname)%> <%= Html.ValidationMessageFor(model => model.Person.Surname)%> </div> <div class="editor-label"> <%= Html.LabelFor(model => model.DOB) %> </div> <div class="editor-field"> <%= Html.TextBoxFor(model => model.DOB, String.Format("{0:g}", Model.DOB)) <%= Html.ValidationMessageFor(model => model.DOB) %> </div>--%> <div class="editor-label"> <%= Html.LabelFor(model => model.Person.Nationality)%> </div> <div class="editor-field"> <%= Html.TextBoxFor(model => model.Person.Nationality)%> <%= Html.ValidationMessageFor(model => model.Person.Nationality)%> </div> <div class="editor-label"> <%= Html.LabelFor(model => model.Person.Occupation)%> </div> <div class="editor-field"> <%= Html.TextBoxFor(model => model.Person.Occupation)%> <%= Html.ValidationMessageFor(model => model.Person.Occupation)%> </div> <div class="editor-label"> <%= Html.LabelFor(model => model.Person.CountryOfResidence)%> </div> <div class="editor-field"> <%= Html.TextBoxFor(model => model.Person.CountryOfResidence)%> <%= Html.ValidationMessageFor(model => model.Person.CountryOfResidence)%> </div> <div class="editor-label"> <%= Html.LabelFor(model => model.Person.PreviousNameForename)%> </div> <div class="editor-field"> <%= Html.TextBoxFor(model => model.Person.PreviousNameForename)%> <%= Html.ValidationMessageFor(model => model.Person.PreviousNameForename)%> </div> <div class="editor-label"> <%= Html.LabelFor(model => model.Person.PreviousSurname)%> </div> <div class="editor-field"> <%= Html.TextBoxFor(model => model.Person.PreviousSurname)%> <%= Html.ValidationMessageFor(model => model.Person.PreviousSurname)%> </div> <div class="editor-label"> <%= Html.LabelFor(model => model.Person.Email)%> </div> <div class="editor-field"> <%= Html.TextBoxFor(model => model.Person.Email)%> <%= Html.ValidationMessageFor(model => model.Person.Email)%> </div> <p> <input type="submit" value="Save" /> </p> </fieldset> <% } % And the Person class looks like: [MetadataType(typeof(Person_Validation))] public partial class Person { public Person() { } } [Bind(Exclude = "ID")] public class Person_Validation { public int ID { get; private set; } public string Title { get; set; } public string Forename { get; set; } public string Surname { get; set; } public System.DateTime DOB { get; set; } public string Nationality { get; set; } public string Occupation { get; set; } public string CountryOfResidence { get; set; } public string PreviousNameForename { get; set; } public string PreviousSurname { get; set; } public string Email { get; set; } } And ViewModel: public class FormationViewModel { public Company Company { get; set; } public Address RegisteredAddress { get; set; } public Person Person { get; set; } public PersonType PersonType { get; set; } public int CurrentStep { get; set; } } }

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• Calling Web Services in classic ASP

  - by cabhilash

    Last day my colleague asked me the provide her a solution to call the Web service from classic ASP. (Yes Classic ASP. still people are using this :D ) We can call web service SOAP toolkit also. But invoking the service using the XMLHTTP object was more easier & fast. To create the Service I used the normal Web Service in .Net 2.0 with [Webmethod] public class WebService1 : System.Web.Services.WebService { [WebMethod] public string HelloWorld(string name){return name + " Pay my dues :) "; // a reminder to pay my consultation fee :D} } In Web.config add the following entry in System.web<webServices><protocols><add name="HttpGet"/><add name="HttpPost"/></protocols></webServices> Alternatively, you can enable these protocols for all Web services on the computer by editing the <protocols> section in Machine.config. The following example enables HTTP GET, HTTP POST, and also SOAP and HTTP POST from localhost: <protocols> <add name="HttpSoap"/> <add name="HttpPost"/> <add name="HttpGet"/> <add name="HttpPostLocalhost"/> <!-- Documentation enables the documentation/test pages --> <add name="Documentation"/> </protocols> By adding these entries I am enabling the HTTPGET & HTTPPOST (After .Net 1.1 by default HTTPGET & HTTPPOST is disabled because of security concerns)The .NET Framework 1.1 defines a new protocol that is named HttpPostLocalhost. By default, this new protocol is enabled. This protocol permits invoking Web services that use HTTP POST requests from applications on the same computer. This is true provided the POST URL uses http://localhost, not http://hostname. This permits Web service developers to use the HTML-based test form to invoke the Web service from the same computer where the Web service resides. Classic ASP Code to call Web service <%Option Explicit Dim objRequest, objXMLDoc, objXmlNode Dim strRet, strError, strNome Dim strName strName= "deepa" Set objRequest = Server.createobject("MSXML2.XMLHTTP") With objRequest .open "GET", "http://localhost:3106/WebService1.asmx/HelloWorld?name=" & strName, False .setRequestHeader "Content-Type", "text/xml" .setRequestHeader "SOAPAction", "http://localhost:3106/WebService1.asmx/HelloWorld" .send End With Set objXMLDoc = Server.createobject("MSXML2.DOMDocument") objXmlDoc.async = false Response.ContentType = "text/xml" Response.Write(objRequest.ResponseText) %> In Line 6 I created an MSXML XMLHTTP object. Line 9 Using the HTTPGET protocol I am openinig connection to WebService Line 10:11 – setting the Header for the service In line 15, I am getting the output from the webservice in XML Doc format & reading the responseText(line 18). In line 9 if you observe I am passing the parameter strName to the Webservice You can pass multiple parameters to the Web service by just like any other QueryString Parameters. In similar fashion you can invoke the Web service using HTTPPost. Only you have to ensure that the form contains all th required parameters for webmethod.  Happy coding !!!!!!!

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• MVC2: Validate PartialView before Form Submit of Page containing Partial View

  - by Pascal

  I am using asp.net mvc2 and having a basic Page that includes a Partial View within a form <% using (Html.BeginForm()) { %> <% Html.RenderAction("partialViewActionName", "Controllername"); %> <input type="submit" value="Weiter" /> <% } %> When I submit the form, the httpPost Action of my Page is called, and AFTER that the httpPost Action of my Partial View is called [HttpPost] public virtual ActionResult PagePostMethod(myModel model) { // here I should know about the validation of my partial View // If partialView.ModelState is valid then // return View("success"); // else return View(model) } [HttpPost] public virtual ActionResult partialViewActionName(myModel model) { ModelState.AddModelError("Error"); return View(model); } But as I am doing the Validation in the httpPost Method of my Partial View (because I want to use my Partial View in several Places) I cant decide if my hole page is valid or not. Has anyone an Idea how I could do this? Isn´t it a common task to have several partial Views in a page but have the information about validation in the page action methods? Thanks very much for your help!!

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• Android, sending XML via HTTP POST (SOAP)

  - by Intosia

  Hi, I would like to invoke a webservice via Android. I need to POST some XML to a URL via HTTP. I found this snipped for sending a POST, but i dont know how to include/add the XML data itself. public void postData() { // Create a new HttpClient and Post Header HttpClient httpclient = new DefaultHttpClient(); HttpPost httppost = new HttpPost("http://10.10.4.35:53011/"); try { // Add your data List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(2); nameValuePairs.add(new BasicNameValuePair("Content-Type", "application/soap+xml")); httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs)); // Where/how to add the XML data? // Execute HTTP Post Request HttpResponse response = httpclient.execute(httppost); } catch (ClientProtocolException e) { // TODO Auto-generated catch block } catch (IOException e) { // TODO Auto-generated catch block } } This is the complete POST message that i need to imitate: POST /a8103e90-f1e3-11dd-bfdb-8b1fcff1a110 HTTP/1.1 Host: 10.10.4.35:53011 Content-Type: application/soap+xml Content-Length: 602 <?xml version='1.0' encoding='UTF-8' ?> <s12:Envelope xmlns:s12="http://www.w3.org/2003/05/soap-envelope" xmlns:wsa="http://schemas.xmlsoap.org/ws/2004/08/addressing"> <s12:Header> <wsa:MessageID>urn:uuid:fc061d40-3d63-11df-bfba-62764ccc0e48</wsa:MessageID> <wsa:Action>http://schemas.xmlsoap.org/ws/2004/09/transfer/Get</wsa:Action> <wsa:To>urn:uuid:a8103e90-f1e3-11dd-bfdb-8b1fcff1a110</wsa:To> <wsa:ReplyTo> <wsa:Address>http://schemas.xmlsoap.org/ws/2004/08/addressing/role/anonymous</wsa:Address> </wsa:ReplyTo> </s12:Header> <s12:Body /> </s12:Envelope>

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