Why does Java's hashCode() in String use 31 as a multiplier?
- by jacobko
In Java, the hash code for a String object is computed as
s[0]*31^(n-1) + s[1]*31^(n-2) + ... + s[n-1]
using int arithmetic, where s[i] is the ith character of the string, n is the length of the string, and ^ indicates exponentiation.
Why is 31 used as a multiplier?
I understand that the multiplier should be a relatively large prime number. So why not 29, or 37, or even 97?