Search Results

Search found 38 results on 2 pages for 'jessy'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 1/2 | 1 2  | Next Page >

  • Multiple static WAN IP addresses to single LAN subnet

    - by Jessy Houle
    Below is my home network topology. I currently have 5 static IP addresses, 3 of which are in use by 3 routers. These routers in-turn subnet internal networks and port forward. I use my SSL VPN appliance to remote home from work or on the road. At this point I can remotely administer my Windows Server. I know the network is setup wrong, I was matching existing hardware the best I knew how. http://storage.jessyhoule.com.s3.amazonaws.com/network_topology.jpg Ok this said, here is the problem... One of my websites on my Windows Server now needs to be secure (SSL using port 443). However, I'm already port forwarding port 443 to my VPN appliance. Furthermore, if I'm going to have to reconfigure the network, I would really like to be able to use the SSL VPN to remotely administer all machines. I mentioned this to a friend of mine, who said that what I was looking for was a firewall. Explaining that a firewall would take in multiple static (WAN) IP addresses, and still allow all internal devices to be on the same network. So, basically, I could supply my SSL VPN appliance it's very own static (WAN) IP address routing, and yet have it on the same internal network (192.168.1.x) as all my other devices. The first question is... Does this sound right? Secondly, would you suggest anything different? And, finally, what is the cheapest way to do this? I am started down the road of downloading/installing untangle and smoothwall to see if they will do the job, hoping they take multiple static (WAN) IP addresses. Thank you in advance for your answers. -Jessy Houle

    Read the article

  • Apache local verses external (domain)

    - by Jessy Houle
    I have an Apache server running on Ubuntu server 10, using Passenger for Ruby on Rails. I have configured my site under the sites-enabled directory of Apache and can hit the server with an internal IP address (192.168.X.X) and the site comes back as expected. However, whenever I try to hit the site externally, either through the domain name or the IP address tied to the domain name, the site will not come back. I have a router in the middle with a static IP address, with Port Forwarding turned on (forwarding 80/443) to the server and I'm quite confident the issue isn't there. In fact, I even DMZed to the Ubuntu Server just to make sure. Also, all router firewall options have been turned off. So here is the question... Is there something else I have to do with Ubuntu server to allow externally requested port 80 traffic? Otherwise, is there some settings that need to be set in Apache to allow domain or external IP address port 80 traffic through? I'm pretty new to Apache, so, please take it a bit easy on me :-) Thank you for your responses. -Jessy Houle

    Read the article

  • Object Dump JavaScript

    - by Jessy Houle
    Is there a 3rd party add-on/application or some way to perform object map dumping in script debugger for a JavaScript object? Here is the situation... I have a method being called twice, and during each time something is different. I'm not sure what is different, but something is. So, if I could dump all the properties of window (or at least window.document) into a text editor, I could compare the state between the two calls with a simple file diff. Thoughts? Thank you in advance. -Jessy Houle

    Read the article

  • Updating Xml attributes with new values in a SQL Server 2008 table

    - by SMD
    I have a table in SQL Server 2008 that it has some columns. One of these columns is in Xml format and I want to update some attributes. For example my Xml column's name is XmlText and it's value in 5 first rows is such as: <Identification Name="John" Family="Brown" Age="30" /> <Identification Name="Smith" Family="Johnson" Age="35" /> <Identification Name="Jessy" Family="Albert" Age="60" /> <Identification Name="Mike" Family="Brown" Age="23" /> <Identification Name="Sarah" Family="Johnson" Age="30" /> and I want to change all Age attributes that are 30 to 40 such as below: <Identification Name="John" Family="Brown" Age="40" /> <Identification Name="Smith" Family="Johnson" Age="35" /> <Identification Name="Jessy" Family="Albert" Age="60" /> <Identification Name="Mike" Family="Brown" Age="23" /> <Identification Name="Sarah" Family="Johnson" Age="40" />

    Read the article

  • How to check and match the possible combinations of arraylist elements

    - by Jessy
    String [] A = {"High","Medium","Low"}; String [] B = {"High","Medium","Low"}; String [] C = {"High","Medium","Low"}; String [] D = {"High","Medium","Low"}; String [] E = {"High","Medium","Low"}; String [] F = {"High","Medium","Low"}; JComboBox Ai = new JComboBox(A); JComboBox Bi = new JComboBox(B); JComboBox Ci = new JComboBox(C); JComboBox Di = new JComboBox(C); JComboBox Ei = new JComboBox(E); JComboBox Fi = new JComboBox(F); .... //add the user choice in arrayList ArrayList<String> a = new ArrayList<String>(); a.add((String) Ai.getSelectedItem()); a.add((String) Bi.getSelectedItem()); a.add((String) Ci.getSelectedItem()); a.add((String) Di.getSelectedItem()); a.add((String) Ei.getSelectedItem()); a.add((String) Fi.getSelectedItem()); Scenario: On each comboBox, user need to choose one, which mean there are 6 choices at the end. There are 6*5*4*3*2*1 = 720 possible combinations of choices made by the user. What is the best way to check and match the user choice without writing the 720 else if ? e.g. if(Ai=="High" && Bi=="High" && Ci=="Low" && Di=="High" && Ei=="Low" && Fi=="Medium") { System.out.println("Good Choice"); } Thank you.

    Read the article

  • How to set arrayList size as null?

    - by Jessy
    String a []= {null,null,null,null,null}; //add array to arraylist ArrayList<Object> choice = new ArrayList<Object>(Arrays.asList(a)); System.out.println(choice.size()); Why the size of the arrayList choice is 5 when all the elements have been set to null

    Read the article

  • How to avoid null pointer error

    - by Jessy
    I trying to find whether the elements of 2 arrayLists are match or not. But this code give me error Exception in thread "AWT-EventQueue-0" java.lang.NullPointerException since some of the elements are null. How can I solved this problem? String level []={"High","High","High","High","High","High"}; ArrayList<Object> n = new ArrayList<Object>(Arrays.asList(level)); String choice []={null,"High","Low","High",null,"Medium"}; ArrayList<Object> m = new ArrayList<Object>(Arrays.asList(choice)); //Check if the two arrayList are identical for(int i=0; i<m.size(); i++){ if(!(m.get(i).equals(n.get(i)))){ result= true; break; } } return result; }

    Read the article

  • How to get image's coordinate on JPanel

    - by Jessy
    This question is related to my previous question http://stackoverflow.com/questions/2376027/how-to-generate-cartesian-coordinate-x-y-from-gridbaglayout I have successfully get the coordinate of each pictures, however when I checked the coordinate through (System.out.println) and the placement of the images on the screen, it seems to be wrong. e.g. if on the screen it was obvious that the x point of the first picture is on cell 2 which is on coordinate of 20, but the program shows x=1. Here is part of the code: public Grid (){ setPreferredSize(new Dimension(600,600)); .... setLayout(new GridBagLayout()); GridBagConstraints gc = new GridBagConstraints(); gc.weightx = 1d; gc.weighty = 1d; gc.insets = new Insets(0, 0, 0, 0);//top, left, bottom, and right gc.fill = GridBagConstraints.BOTH; JLabel[][] label = new JLabel[ROWS][COLS]; Random rand = new Random(); // fill the panel with labels for (int i=0;i<IMAGES;i++){ ImageIcon icon = createImageIcon("myPics.jpg"); int r, c; do{ //pick random cell which is empty r = (int)Math.floor(Math.random() * ROWS); c = (int)Math.floor(Math.random() * COLS); } while (label[r][c]!=null); //randomly scale the images int x = rand.nextInt(50)+30; int y = rand.nextInt(50)+30; Image image = icon.getImage().getScaledInstance(x,y, Image.SCALE_SMOOTH); icon.setImage(image); JLabel lbl = new JLabel(icon); // Instantiate GUI components gc.gridx = r; gc.gridy = c; add(lbl, gc); //add(component, constraintObj); label[r][c] = lbl; } I checked the coordinate through this code: Component[] components = getComponents(); for (Component component : components) { System.out.println(component.getBounds()); }

    Read the article

  • How to get the coordinate of Gridlayout

    - by Jessy
    Hi, I set my JPanel to GridLayout (6,6), with dimension (600,600) Each cell of the grid will display one pictures with different widths and heights. The picture first add to a JLabel, and the JLabel then added to the cells. How can retrieved the coordinate of the pictures in the cells and not the coordinate of cells? So far the out give these coordinate which equal height and width even on screen the pictures showed in different sizes. e.g. java.awt.Rectangle[x=100,y=100,width=100,height=100] java.awt.Rectangle[x=200,y=100,width=100,height=100] java.awt.Rectangle[x=300,y=100,width=100,height=100] The reason why I used GridLayout instead of gridBagLayout is that, I want each pictures to have boundary. If I use GridBagLayout, the grid will expand according to the picture size. I want grid size to be in fix size. JPanel pDraw = new JPanel(new GridLayout(6,6)); pDraw.setPreferredSize(new Dimension(600,600)); for (int i =0; i<(6*6); i++) { //get random number for height and width of the image int x = rand.nextInt(40)+(50); int y = rand.nextInt(40)+(50); ImageIcon icon = createImageIcon("bird.jpg"); //rescale the image according to the size selected Image img = icon.getImage().getScaledInstance(x,y,img.SCALE_SMOOTH); icon.setImage(img ); JLabel label = new JLabel(icon); pDraw.add(label); } for(Component component:components) { //retrieve the coordinate System.out.println(component.getBounds()); }

    Read the article

  • problem with sortrows MATLAB

    - by Jessy
    Hi, My question is related with the previous solved question in http://stackoverflow.com/questions/2925623/how-to-save-data-in-txt-file-in-matlab my problem is that, I decided to unsorted the output, however this error comes out when I removed the sortrows. And no error when I leave the sortrows I'm curious why.

    Read the article

  • How to display image within cell boundary

    - by Jessy
    How can I place an image within the cell boundary? I mean without taking the space of other cell? In the code below, random cells were selected to display images. One image in one cell. The problem is that, the image seems to take other cells as well. ... setPreferredSize(new Dimension(600,600)); final int ROWS = 6; final int COLS = 6; final int IMAGES = 10; setLayout(new GridBagLayout()); GridBagConstraints gc = new GridBagConstraints(); gc.weightx = 1d; gc.weighty = 1d; gc.insets = new Insets(0, 0, 0, 0);//top, left, bottom, and right gc.fill = GridBagConstraints.NONE; JLabel[][] label = new JLabel[ROWS][COLS]; Random rand = new Random(); // fill the panel with labels for (int i=0;i<IMAGES;i++){ ImageIcon icon = createImageIcon("myImage.jpg"); int r, c; do{ //pick random cell which is empty to avoid overlap image in the same cell r = (int)Math.floor(Math.random() * ROWS); c = (int)Math.floor(Math.random() * COLS); } while (label[r][c]!=null); //scale the image int x = rand.nextInt(20)+30; int y = rand.nextInt(20)+30; Image image = icon.getImage().getScaledInstance(x,y, Image.SCALE_SMOOTH); icon.setImage(image); JLabel lbl = new JLabel(icon); gc.gridx = r; gc.gridy = c; add(lbl, gc); //add image to the cell label[r][c] = lbl; }

    Read the article

  • How to display image within cell boundary

    - by Jessy
    How can I place an image within the cell boundary? I mean without taking the space of other cell? In the code below, random cells were selected to display images. One image in one cell. The problem is that, the image seems to take other cells as well. ... setPreferredSize(new Dimension(600,600)); final int ROWS = 6; final int COLS = 6; final int IMAGES = 10; setLayout(new GridBagLayout()); GridBagConstraints gc = new GridBagConstraints(); gc.weightx = 1d; gc.weighty = 1d; gc.insets = new Insets(0, 0, 0, 0);//top, left, bottom, and right gc.fill = GridBagConstraints.NONE; JLabel[][] label = new JLabel[ROWS][COLS]; Random rand = new Random(); // fill the panel with labels for (int i=0;i<IMAGES;i++){ ImageIcon icon = createImageIcon("myImage.jpg"); int r, c; do{ //pick random cell which is empty to avoid overlap image in the same cell r = (int)Math.floor(Math.random() * ROWS); c = (int)Math.floor(Math.random() * COLS); } while (label[r][c]!=null); //scale the image int x = rand.nextInt(20)+30; int y = rand.nextInt(20)+30; Image image = icon.getImage().getScaledInstance(x,y, Image.SCALE_SMOOTH); icon.setImage(image); JLabel lbl = new JLabel(icon); gc.gridx = r; gc.gridy = c; add(lbl, gc); //add image to the cell label[r][c] = lbl; }

    Read the article

  • How to store arrays in single array

    - by Jessy
    How can I store arrays in single array? e.g. I have four different arrays, I want to store it in single array int storeAllArray [] and when I call e.g. storeAllArray[1] , I will get this output [11,65,4,3,2,9,7]instead of single elements? int array1 [] = {1,2,3,4,5,100,200,400}; int array2 [] = {2,6,5,7,2,5,10}; int array3 [] = {11,65,4,3,2,9,7}; int array4 [] = {111,33,22,55,77}; int storeAllArray [] = {array1,array2,array3,array2} // I want store all array in on array for (int i=0; i<storeAllArray; i++){ System.out.println(storeAllArray.get[0]); // e.g. will produce --> 1,2,3,4,5,100,200,400 , how can I do this? }

    Read the article

  • im having problems accessing my core files/folders..

    - by Jessy Draves
    I'm wanting to build a video page that is similar to my product pages. But using different categories. I also put the videos on my product pages but I want to build a separate video page and link them all together.. I have almost 200 videos that i want my customers to be able to easily navigate through (like thumbnails). I also think that this will help my internal link structure. And my customers will be on my website longer.. Any suggestions??

    Read the article

  • activate and deactivate ComboBox

    - by Jessy
    How can I make the comboBox available when the checkBox was uncheck (vice versa) Why the comboBox is still disable after I unChecked the checkBox? choice [] = {"A","B","C"}; JComboBox a = new JComboBox(choice); JCheckBox chk = new JCheckBox("choice"); ... a.addActionListener(this); chk.addActionListener(this); ... public void actionPerformed(ActionEvent e) { //disable the a comboBox when the checkBox chk was checked if(e.getSource()==chk) a.setEnabled(false); //enable the a comboBox when the checkBox chk was unchecked else if(e.getSource()!=chk) a.setEnabled(true); }

    Read the article

  • How to change the cursor type

    - by Jessy
    This question is related to the previous post. http://stackoverflow.com/questions/2532936/how-to-save-file-and-read How can I change the cursor to "Hand" only when the mouse pointed on grid which is not Null (contained images)? So far the cursor turn to "Hand" all over the grids (null or not null). public GUI() { .... JPanel pDraw = new JPanel(); .... for(Component component: pDraw.getComponents()){ JLabel lbl = (JLabel)component; //add mouse listener to grid box which contained image if (lbl.getIcon() != null) lbl.addMouseListener(this); } public void mouseEntered(MouseEvent e) { Cursor cursor = Cursor.getDefaultCursor(); //change cursor appearance to HAND_CURSOR when the mouse pointed on images cursor = Cursor.getPredefinedCursor(Cursor.HAND_CURSOR); setCursor(cursor); }

    Read the article

  • MATLAB how to write header in text file

    - by Jessy
    How to write a text header in text file? for example in the example below, how to write the header code salay month just once? Code Salary Month 12 1000 12 14 1020 11 11 1212 9 fid = fopen('analysis1.txt','wt'); for i=1:10 array = []; % empty the array .... array = [code salary month]; format short g; fprintf(fid,'%g\t %g\t %g\n',array); % write to file end fclose(fid);

    Read the article

  • How to shuffle pairs

    - by Jessy
    How to shuffle the elements in the pairs? The program below, generate all possible pairs and later shuffle the pairs. e.g. possible pairs before shuffle is ab,ac,ae,af..etc shuffled to ac,ae,af,ab...etc How to make it not only shuffled in pairs but within the elements in the pair itself? e.g. instead of ab, ac, how can I make ba, ac ? String[] pictureFile = {"a.jpg","b.jpg","c.jpg","d.jpg","e.jpg","f.jpg","g.jpg"}; List <String> pic1= Arrays.asList(pictureFile); ... ListGenerator pic2= new ListGenerator(pic1); ArrayList<ArrayList<Integer>> pic2= new ArrayList<ArrayList<Integer>>(); public class ListGenerator { public ListGenerator(List<String> pic1) { int size = pic1.size(); // create a list of all possible combinations for(int i = 0 ; i < size ; i++) { for(int j = (i+1) ; j < size ; j++) { ArrayList<Integer> temp = new ArrayList<Integer>(); temp.add(i); temp.add(j); pic2.add(temp); } } Collections.shuffle(pic2); } //This method return the shuffled list public ArrayList<ArrayList<Integer>> getList() { return pic2; } }

    Read the article

  • How to save file and read

    - by Jessy
    Hello everyone, I create a program that place random image in grid layout format. The size of the grid layout is 6 x 6 = 36. Only 10 were filled with images (each image was different) and the rest were empty. freeimagehosting.net/uploads/bfb7e85f63.jpg How can I save it to a file and read it again, so it will display the same images with same placement on the grid? Here is the code that I used to save the images: //image file String []arrPic = {"pic1.jpg","pic2.jpg","pic3.jpg","pic4.jpg","pic5.jpg","pic6.jpg","pic7.jpg","pic8.jpg","pic9.jpg","pic10.jpg",,"pic11.jpg","pic12.jpg","pic13.jpg"}; ArrayList<String> pictures = new ArrayList<String>(Arrays.asList(arrPic)); ArrayList<String> file = new ArrayList<String>(); JPanel pDraw = new JPanel(new GridLayout(6,6,2,2)); ... //fill all grids with empty label for (int i =0; i<(6*6); i++){ JLabel lbl = new JLabel(""); pDraw.add(lbl); } ... //Choose random box to be filled with images for(int i=0; i<10; i++){ Boolean number = true; while(number){ int n = rand.nextInt(35); if(!(arraylist.contains(n))) number = false; arraylist.add(n); } //fill the grids with images for(int i=0; i<arraylist.size(); i++){ //select random image from arraylist int index = rand.nextInt (pictures.size()); String fileName = (String) pictures.get(index ); //find the image file icon = createImageIcon(fileName); //save the file in a new file file.add(fileName); //rescaled the image int x = rand.nextInt(50)+50; int y = rand.nextInt(50)+50; Image image = icon.getImage().getScaledInstance(x,y,Image.SCALE_SMOOTH); icon.setImage(image); //remove empty label and replace it with an image int one = (Integer) arraylist.get(i); pDraw.remove(one); final JLabel label; pDraw.add(label,one); }

    Read the article

  • How to add two label in one gridbox?

    - by Jessy
    Hello everyone, How can I add two label in the same grid box? e.g. in row 1, col 1 the will be 2 labels? The code below will add the label in two different grid. JPanel chckBox = new JPanel(new GridLayout(1,8,3,3)); JLabel label1 = new JLabel("A"); JLabel label2 = new JLabel("B"); ... chckBox.add(label1); chckBox.add(label2); ...

    Read the article

  • read ArrayList elements

    - by Jessy
    Why it print the wrong output? ArrayList<String> loc = new ArrayList<String>(); This arraylist stored the value of: [topLeft, topLeft, topLeft, bottomLeft, topLeft, bottomLeft, topLeft, topLeft, Left, topLeft] the firs index 0 is = topLeft if(loc.get(1)=="topLeft") System.out.println("same") else { System.out.println("not same") } This program print the wrong output not same instead of same

    Read the article

  • Problem with setVisible (true)

    - by Jessy
    The two examples shown below are same. Both are supposed to produce same result e.g. generate the coordinates of images displayed on JPanel. Example 1, works perfectly (print the coordinates of images), however example 2 returning 0 for the coordinate. I was wondering why because, I have put the setvisible (true) after adding the panel, in both examples. The only difference is that example 1 used extends JPanel and example 2 extends JFrame EXAMPLE 1: public class Grid extends JPanel{ public static void main(String[] args){ JFrame jf=new JFrame(); jf.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); final Grid grid = new Grid(); jf.add(grid); jf.pack(); Component[] components = grid.getComponents(); for (Component component : components) { System.out.println("Coordinate: "+ component.getBounds()); } jf.setVisible(true); } } EXAMPLE 2: public class Grid extends JFrame { public Grid () { setLayout(new GridBagLayout()); GridBagLayout m = new GridBagLayout(); Container c = getContentPane(); c.setLayout (m); GridBagConstraints con = new GridBagConstraints(); //construct the JPanel pDraw = new JPanel(); ... m.setConstraints(pDraw, con); pDraw.add (new GetCoordinate ()); // call new class to generate the coordinate c.add(pDraw); pack(); setVisible(true); } public static void main(String[] args) { new Grid(); } }

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

1 2  | Next Page >