Search Results

Search found 4 results on 1 pages for 'johnjohnga'.

Page 1/1 | 1 

• Is it possible to write a Shell script which is faster to the same script in perl?

  - by JohnJohnGa

  Hi, I wrote multiple scripts in perl & shell and I had compared the real execution time. In all the cases - Perl script is more than 10 times faster than shell script. So i wondered if it possible to write a Shell script which is faster to the same script in perl? and why perl faster than shell although I use the 'system' function in perl script. Thanks for your help, Regards, JohnJohnGa

  Read the article

• Display relative time in hour, day, month and year

  - by JohnJohnGa

  I wrote a function toBeautyString(epoch) : String which given a epoch, return a string which will display the relative time from now in hour and minute For instance: // epoch: 1346140800 -> Tue, 28 Aug 2012 05:00:00 GMT // and now: 1346313600 -> Thu, 30 Aug 2012 08:00:00 GMT toBeautyString(1346140800) -> "2 days and 3 hours ago" I want now to extend this function to month and year, so it will be able to print: 2 years, 1 month, 3 days and 1 hour ago Only with epoch without any external libraries. The purpose of this function is to give to the user a better way to visualize the time in the past. I found this: Calculating relative time but the granularity is not enough.

  Read the article

• What's behind the 'system' function in perl?

  - by JohnJohnGa

  i can thought that it will open a shell, execute the parameter (shell command) and return the result in a scalar. But, execute 'system' function in a perl script is faster than a shell command. It will call this command in C? If yes, what's the difference between rmdir foo and system('rmdir foo'); Thanks,

  Read the article

• Generics Type issue

  - by JohnJohnGa

  ArrayList<Integer> arrI = new ArrayList<Integer>(); ArrayList arrO = arrI; // Warning /* It is ok to add a String as it is an ArrayList of Objects but the JVM will know the real type, arrO is an arrayList of Integer... */ arrO.add("Hello"); /* How I can get a String in an ArrayList<Integer> ?? Even if the compiler told me that I will get an Integer! */ System.out.println(arrI.get(0)); Anybody can explain what's happening here?

  Read the article

1