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  • How can I SELECT rows with MAX(Column value), DISTINCT by another column in SQL?

    - by Kaptah
    My table is: id home datetime player resource ---|-----|------------|--------|--------- 1 | 10 | 04/03/2009 | john | 399 2 | 11 | 04/03/2009 | juliet | 244 5 | 12 | 04/03/2009 | borat | 555 3 | 10 | 03/03/2009 | john | 300 4 | 11 | 03/03/2009 | juliet | 200 6 | 12 | 03/03/2009 | borat | 500 7 | 13 | 24/12/2008 | borat | 600 8 | 13 | 01/01/2009 | borat | 700 I need to select each distinct "home" holding the maximum value of "datetime". Result would be: id home datetime player resource ---|-----|------------|--------|--------- 1 | 10 | 04/03/2009 | john | 399 2 | 11 | 04/03/2009 | juliet | 244 5 | 12 | 04/03/2009 | borat | 555 7 | 13 | 24/12/2008 | borat | 600 8 | 13 | 01/01/2009 | borat | 700 I have tried: // 1 ..by the MySQL manual: SELECT DISTINCT home, id, datetime as dt, player, resource FROM topten t1 WHERE datetime = (SELECT MAX(t2.datetime) FROM topten t2 GROUP BY home ) GROUP BY daytime ORDER BY daytime DESC Doesn't work. Result-set has 130 rows although database holds 187. Result includes some dublicates of 'home'. // 2 ..join SELECT s1.id, s1.home, s1.datetime, s1.player, s1.resource FROM topten s1 JOIN (SELECT id, MAX(datetime) AS dt FROM topten GROUP BY id) AS s2 ON s1.id = s2.id ORDER BY daytime Nope. Gives all the records. // 3 ..something exotic: With various results.

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