karem - Developer IT

PHP: form action on same page, still show same until refresh

- by Karem

Yes, Im having a little edit profile page, index.php?mode=profile. Lets take the username in the editprofile form as example. The username is already in the username-field. So i changed from "Peter" to "Tom" and press save. The action is ?mode=profile&edit=true. So now when i have pressed save it has updated the column in the db from Peter to Tom. But this field keeps having the value "Peter" until if i do press refresh (or f5), then "Tom" will appear. Like it hasnt updated in the database anything, although it did but it still shows Peter until next refresh.. like it caches, but it shouldnt cache nothing? Any help on this? Is it because its on the same "page" / file? what can i do

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css/html: white space break fix and now cant code fine?

- by Karem

Yes, so I got the problem that if you type a long sentence with no space e.g eeeeeeeeeeeeeeeeeeeeeeee, it will break itself, but then now I would need to start typing some ugly non-breaking coding. Example: http://jsfiddle.net/r3CFJ/ I need to have everything in one sentence in order not to make it break itself. Check here to see the result of not having everything in one sentence: http://jsfiddle.net/r3CFJ/1/ How can I fix this please any solutions?? as my further coding will get very ugly and not readable?

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PHP: codecomments inside functions prevents it work

- by Karem

$query = $connect->prepare("SELECT firstname, lastname FROM users WHERE id = '$id'"); $query->execute(); $row = $query->fetch(); // $full_name = $row["firstname"] . " ".$row["lastname"]; $full_name = $row["firstname"] . " ".substr($row["lastname"], 0, 1)."."; return $full_name; If i remove the line that is a comment ( // ), it will return $full_name, if its there then it wont work. I also tried commenting with #, but it still wont work(wont return anything) as soon as there is a codecomment weird issue

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PHP: Making my code simpler/shorter welcome message

- by Karem

Any suggestion to make this welcome message shorter: <?php if(isset($_SESSION['user_id'])) { if(isSet($_SESSION['1stTime'])){ ?> <strong id="welcome" style="font-size: 10px;"> <a href="logout.php"> Logga ut </a> </strong> <?php }else{ $_SESSION['1stTime'] = time(); ?> <script> $(document).ready(function() { $("#welcome").fadeIn("slow"); setTimeout(function(){ $("#welcome").fadeOut("slow"); setTimeout(function(){ $("#welcome").html("<a href='logout.php'>Logga ut</a>"); $("#welcome").fadeIn(); }, 800); }, 5000); }); </script> <strong id="welcome" style="display: none; color: #FFF; font-size: 10px;">Hej, <?php echo $FULL; ?>!</strong> <?php } } ?> First it checks if you are signed in. Next if 1stTime is set, if it is then show "Log out" in swedish, if it isnt, then introduce with "Hi, NAME", and then change to "Log out" after 5 seconds(jquery) + set the session How can i make this simpler?

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CSS/jQuery: make the icon blink

- by Karem

I remember doing some css learning where i learned to make text-decoration: blink, and the text started blinking. Now i have a icon, .iconPM{ background: url(../images/icons/mail_16x16.png) no-repeat; width: 16px; height: 16px; border: none; display:inline-block; } Wonder if i can make this blink, either by simple css or jquery if required. Or maybe any other nice effects available in jquery recommended

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protect form hijacking hack

- by Karem

Yes hello today I discovered a hack for my site. When you write a msg on a users wall (in my communitysite) it runs a ajax call, to insert the msg to the db and will then on success slide down and show it. Works fine with no problem. So I was rethinking alittle, I am using POST methods for this and if it was GET method you could easily do ?msg=haxmsg&usr=12345679. But what could you do to come around the POST method? I made a new html document, made a form and on action i set "site.com/insertwall.php" (the file that normally are being used in ajax), i made some input fields with names exactly like i am doing with the ajaxcall (msg, uID (userid), BuID (by userid) ) and made a submit button. I know I have a page_protect() function on which requires you to login and if you arent you will be header to index.php. So i logged in (started session on my site.com) and then I pressed on this submit button. And then wops I saw on my site that it has made a new message. I was like wow, was it so easy to hijack POST method i thought maybe it was little more secure or something. I would like to know what could I do to prevent this hijacking? As i wouldnt even want to know what real hackers could do with this "hole". The page_protect secures that the sessions are from the same http user agent and so, and this works fine (tried to run the form without logging in, and it just headers me to startpage) but yea wouldnt take long time to figure out to log in first and then run it. Any advices are appreciated alot. I would like to keep my ajax calls most secure as possible and all of them are running on the POST method. What could I do to the insertwall.php, to check that it comes from the server or something.. Thank you

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PHP: include inside include

- by Karem

In dbc.php I have where the connection to the mysql db gets made, and all my functions is there. dbc.php is included on all my files. Now all functions are in dbc.php and i would like to sort out alittle. I was thinking about putting all form_*() functions to form_api.php, and then include it in dbc.php. But will this work? Can i just include inside a file i included? Or should i use require/include_once ? help me out thank you

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PHP: image size help me out

- by Karem

Yes following from this: PHP: if more than ..px resize to.. As you can see it resizes if: if($width > 604 && $height > 453) { This works fine.. Although what if $width is over 604, and $height is under 453.. eg: 604x300, then this will skip the resize procedure..and same contrary(width is under, height is over). Also, if the dimensions on a picture is 500x900, and it gets resized, it gets really ugly resized. any great fix? Any good suggestion on how I should handle this please?

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Manipulating/changing adressbar link Help

- by Karem

I am out of my own "ideas" going through this. I have a album viewer. When you click next I want the adressbar to hang with it, e.g if you start on ?photoid=1, and click next (next picture appends and stuff), and then i want it to say ?photoid=2. Now I cant make it say ?photoid=2 without changing/manipulating, and this you cant do without HTML5. I have made a script in HTML5 that works fine, but then I need to take care of those who dont have HTML5(only chrome, ff4 etc supports html5) Made the script from this( https://developer.mozilla.org/en/DOM/Manipulating_the_browser_history ) I thought of adding #photoid=2 so, ?photoid=1#photoid=2 and then check if theres anything in # then use that instead of the $_GET.. But apparently you cannot do that as # is client side handled and never sent to the server. So what should I then do? Any suggestions please to make a workaround this? I checked facebook, what they did to IE users, and I could hear that it "clicked" (the annoying click sound from IE) twice.. the first was to get to the next picture, the second click sound changed the adressbar?!(how?). And then I also thought hey, html5 is only supported in ff4, and I got ff3.6, and they manipulate the adress bar url when you browse through the album photos, exactly like how I wanted (and what I have written for but it only works in Chrome and ff4..?). How could they do that?

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PHP: exif_imagetype() not working?

- by Karem

I have this extension checker: $upload_name = "file"; $max_file_size_in_bytes = 8388608; $extension_whitelist = array("jpg", "gif", "png", "jpeg"); /* checking extensions */ $path_info = pathinfo($_FILES[$upload_name]['name']); $file_extension = $path_info["extension"]; $is_valid_extension = false; foreach ($extension_whitelist as $extension) { if (strcasecmp($file_extension, $extension) == 0) { $is_valid_extension = true; break; } } if (!$is_valid_extension) { echo "{"; echo "error: 'ext not allowed!'\n"; echo "}"; exit(0); } And then i added this: if (exif_imagetype($_FILES[$upload_name]['name']) != IMAGETYPE_GIF OR exif_imagetype($_FILES[$upload_name]['name']) != IMAGETYPE_JPEG OR exif_imagetype($_FILES[$upload_name]['name']) != IMAGETYPE_PNG) { echo "{"; echo "error: 'This is no photo..'\n"; echo "}"; exit(0); } As soon when I added this to my imageupload function, the function stops working. I dont get any errors, not even the one i made myself "this is no photo", what could be wrong? Just checked with my host. They support the function exif_imagetype()

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PHP: Using a variable that are inside a function.

- by Karem

I have: include ('functions.php'); check_blocked(); echo $blocked; in functions.php, check_blocked(); exists. Inside check_blocked I got: global $blocked; $blocked = '1234'; I want to echo $blocked variable, that are inside check_blocked(). It doesnt work, no output.. This is an example of my original problem, so please dont say that I could just have the echo inside the function, as I cannot have in my original code.

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