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  • GCC compile time division error

    - by kartikmohta
    Can someone explain this behaviour? test.c: #include <stdio.h> int main(void) { printf("%d, %d\n", (int) (300.6000/0.05000), (int) (300.65000/0.05000)); printf("%f, %f\n", (300.6000/0.05000), (300.65000/0.05000)); return 0; } $ gcc test.c $ ./a.out 6012, 6012 6012.000000, 6013.000000 I checked the assembly code and it puts both the arguments of the first printf as 6012, so it seems to be a compile time bug.

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