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• Finland Specialization Campaig - achive your assessments -get cinematicket

  - by ann-kristin.hahne(at)oracle.com

  GET SPECIALIZED!Suorita ONLINE-testi - saat itsellesi elokuvalipun! Suorita online-testi ja saat elokuvalipun!Kumppaniyrityksen palkitsemisen lisäksi haluamme palkita testin suorittaneet henkilöt. Jokainen ennen 31.1.2011 jollakin kolmesta osa-alueesta (Pre-Sales, Sales, Support) hyväksytysti suoritetun testin tekijä palkitaan yhdellä elokuvalipulla. Tee näin: kun olet suorittanut testin, lähetä saamasi OPN-sertifikaatti ja täydelliset yhteystiedot (nimi, e-mail, yritys, puhelinnumero) osoitteeseen:[email protected] päivittää oracle.com -profiiliisi yrityksesi OPN yritys-ID!

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• Haskell. Numbers in binary numbers. words

  - by Katja

  Hi! I need to code words into binary numbers. IN: "BCD..." OUT:1011... I have written already funktion for coding characters into siple numbers IN: 'C' OUT: 3 IN: 'c' OUT: 3 lett2num :: Char -> Int lett2num x | (ord 'A' <= ord x) && (ord x <= ord 'Z') = (ord x - ord 'A') + 1 | (ord 'a' <= ord x) && (ord x <= ord 'z') = (ord x - ord 'a') +1 num2lett :: Int -> Char num2lett n | (n <= ord 'A') && (n <= ord 'Z') = chr(ord 'A'+ n - 1) | (n <= ord 'a') && (n <= ord 'Z') = chr(ord 'A'+ n - 1) I wrote as well function for codind simple numbers into binary. num2bin :: Int->[Int] num2bin 0 = [] num2bin n | n>=0 = n `mod` 2 : (num2bin( n `div` 2)) | otherwise = error but I donw want those binary numbers to be in a list how can I get rid of the lists? Thanks

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• haskell. words into binary numbers

  - by Katja

  I need to convert words into binary numbers. With a bit help of yours I got this blCo::String -> Integer blCo x = num2bin(lett2num x) blCo (x:xs) | x:xs = num2bin(lett2num x):blCo xs num2lett :: Int -> Char num2lett n | (n <= ord 'A') && (n <= ord 'Z') = chr(ord 'A'+ n - 1) | (n <= ord 'a') && (n <= ord 'Z') = chr(ord 'A'+ n - 1) num2bin :: Integer -> String num2bin n | n >= 0 = concatMap show (reverse ( n2b n)) | otherwise = error "num2bin: negative number" where n2b 0 = [] n2b n = n `mod` 2 : n2b (n `div` 2) he tells me a mistake.I dont undertsand it mistake: Couldn't match expected type `Char' against inferred type `String' In the first argument of `lett2num', namely `x' In the first argument of `num2bin', namely `(lett2num x)' In the expression: num2bin (lett2num x)

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