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• Getting error - This application has failed to start because the application configuration is incorrect. Reinsta

  - by Kaye

  I am sorry if I am repeating this issue. But I am a layman and cant understand the answers posted. I want to do away with Windows XP Professional (I have lost the product key) that I have on an old desktop PC that is more than 7/8 years old. I didnt use the PC for a couple of years as this laptop was more convenient. Now I have started to use this PC but cannot download SP2 onto the PC as it keeps asking for product key and I dont remember where I wrote it down or where I kept it. So I downloaded Ubuntu 12.10 onto the desktop screen (about 753MB and 3 hours) and then used Unetbootin to put this on my pendrive. After completing the process, I have on my pendrive 9 folders, 3 text files, 1 autorun file, 1 ldlinux file, 1 wubi application file and 5 other files - total 20 items. Though on bootup I opted for USB boot, the boot-up opens into Windows. It simply bypasses the USB where ubuntu lies. What do I do? Am I doing things correctly. Pls explain in simple terms.

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• Apache can't access /assets directory (OS X 10.6 Snow Leaopard)

  - by Doug Kaye

  I know this will turn out to be something really stoopid, but I can't find it. Everything was great until I upgraded to OS X 10.6.2 (Snow Leopard) and the supplied Apache 2.2.13. I've replaced all the httpd conf files with my own that were previously working just fine. Everything is great except for one thing: Apache returns a 404 error for any requests to /assets/*. If I rename the directory from 'assets' to anything else, it works fine. I'm going crazy trying to find out why it's sensitive to the string 'assets'. I have no .htaccess files. All permissions have been checked. I've scoured all conf files (including vhosts) for what might cause this and haven't found it. Is there any reason why Apache would treat 'assets' different from anything else? Is there anywhere to check other than conf and .htaccess files?

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• What Are The Web Page Musts Yours Should Have

  If your home based business does not have a web page, well, you are definitely missing a lot. In today';s world, a home business without a web page is like a business without an address or a phone num... [Author: Kaye Z. Marks - Web Design and Development - April 29, 2010]

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• FF3/Windows CSS z-index problem with YouTube player

  - by Doug Kaye

  I'm stuck on what appears to be a CSS/z-index conflict with the YouTube player. In Firefox 3 under Windows XP, Take a look at this page: http://spokenword.org/program/21396 Click on the Collect button and note that the pop-up <div appears under the YouTube player. On other browsers the <div appears on top. It has a z-index value of 999999. I've tried setting the z-index of the <object element containing the player to a lower value, but that didn't work. Any idea how to get the pop-up to appear over the player?

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• How to display image from server (newest-oldest) to a new php page?

  - by Jben Kaye

  i have a form that create images and save it on a folder in the server. What i need to do is to display ALL created images to another page, the newest on the top and so that the oldest is at the bottom. i have a form called formdisplay.php but it's just displaying a broken image and not newest to oldest. hope you can help me with this. really need to get this working. thanks in advance for your help. i have read the posts but none of those worked for me. Pull dedicated images from folder - show image + filename (strip part of filename + file-extension) How can I display latest uploaded image first? (PHP+CSS) getting images from the server and display them Displaying images from folder in php display image from server embedding php in html formcreatesave.php imagecopymerge($im, $img2, 10, 350, 0, 0, imagesx($img2), imagesy($img2), 100); $date_created = date("YmdHis");//get date created $img_name = "-img_entry.jpg"; //the file name of the generated image $img_newname = $date_created . $img_name; //datecreated+name $img_dir =dirname($_SERVER['SCRIPT_FILENAME']) ."/". $img_newname; //the location to save imagejpeg($im, $img_dir , 80); //function to save the image with the name and quality imagedestroy($im); formdisplay.php $dir = '/home3/birdieon/public_html/Amadeus/uploader/uploader'; $base_url = 'http://birdieonawire.com/Amadeus/uploader/uploader/20131027024705-img_entry.jpg'; $newest_mtime = 0; $show_file = 'BROKEN'; if ($handle = opendir($dir)) { while (false !== ($file = readdir($handle))) { if (($file != '.') && ($file != '..')) { $mtime = filemtime("$dir/$file"); if ($mtime > $newest_mtime) { $newest_mtime = $mtime; $show_file = "$base_url/$file"; } } } } print '<img src="' .$show_file. '" alt="Image Title Here">'; please feel free to edit my code. thanks :)

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• Python Terminated Thread Cannot Restart

  - by Mel Kaye

  Hello, I have a thread that gets executed when some action occurs. Given the logic of the program, the thread cannot possibly be started while another instance of it is still running. Yet when I call it a second time, I get a "RuntimeError: thread already started" error. I added a check to see if it is actually alive using the Thread.is_alive() function, and it is actually dead. What am I doing wrong? I can provide more details as are needed.

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