The problem is I am using get_info() to make a ajax call to Result.lasso and paste the response in div with id 'test'.I am unable to use the sendForm() function from the page where i am calling the get_info(). I have also tried using different versions of jQuery 1.1.1.3 is working fine.But i am facing the problem while using higher versions of jquery. The error with higher versions is as follows missing } in XML expression [Break on this error] alert('hi');\n test.lasso (line 3) sendForm is not defined [Break on this error] sendForm(); get_info() function definition <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.2.6/jquery.min.js" type="text/javascript"></script> <SCRIPT> function get_info() { $.ajax({url: "Result.lasso", context: document.body, success: function(response){ document.getElementById('test').innerHTML = response ;},dataType:"script"}); } </SCRIPT> The code in Result.lasso is as follows [Content_Type: 'text/html; charset=UTF-8'] <script type="text/javascript"> function sendForm() { alert('hi'); } </script> [Date] form name= "abc" method = "get" action = "abcd.lasso"> input type ="text" name = "element1"/> input type = "button" value="Click" onClick = "javascript: sendForm();"/> </form> Please help me out in resolving this problem Thanks, Rajesh Konatham