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  • Loop through SimpleXml object in php

    - by chirs
    I have a simpleXml object and want to read the data from the object.I am new to php.The object details are as follows.I want to read name like general and name which is inside company array i.e Korey Kay & Partners.What is the syntax for it? SimpleXMLElement Object ( [@attributes] = Array ( [type] = array ) [project] = Array ( [0] = SimpleXMLElement Object ( [created-on] = 2008-07-18 [id] = 2257372 [last-changed-on] = 2010-05-27T22:28:29Z [name] = *GENERAL [status] = active [company] = SimpleXMLElement Object ( [id] = 406952 [name] = Korey Kay & Partners ) )

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  • Is context inheritance, as shown by Head First Design Patterns' Duck example, irrelevant to strategy pattern?

    - by Korey Hinton
    In Head First Design Patterns it teaches the strategy pattern by using a Duck example where different subclasses of Duck can be assigned a particular behavior at runtime. From my understanding the purpose of the strategy pattern is to change an object's behavior at runtime. Emphasis on "an" meaning one. Could I further simplify this example by just having a Duck class (no derived classes)? Then when implementing one duck object it can be assigned different behaviors based on certain circumstances that aren't dependent on its own object type. For example: FlyBehavior changes based on the weather or QuackBehavior changes based on the time of day or how hungry a duck is. Would my example above constitute the strategy pattern as well? Is context inheritance (Duck) irrelevant to the strategy pattern or is that the reason for the strategy pattern? Here is the UML diagram from the Head First book:

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  • Memento with optional state?

    - by Korey Hinton
    EDIT: As pointed out by Steve Evers and pdr, I am not correctly implementing the Memento pattern, my design is actually State pattern. Menu Program I built a console-based menu program with multiple levels that selects a particular test to run. Each level more precisely describes the operation. At any level you can type back to go back one level (memento). Level 1: Server Type? [1] Server A [2] Server B Level 2: Server environment? [1] test [2] production Level 3: Test type? [1] load [2] unit Level 4: Data Collection? [1] Legal docs [2] Corporate docs Level 4.5 (optional): Load Test Type [2] Multi TIF [2] Single PDF Level 5: Command Type? [1] Move [2] Copy [3] Remove [4] Custom Level 6: Enter a keyword [setup, cleanup, run] Design States PROBLEM: Right now the STATES enum is the determining factor as to what state is BACK and what state is NEXT yet it knows nothing about what the current memento state is. Has anyone experienced a similar issue and found an effective way to handle mementos with optional state? static enum STATES { SERVER, ENVIRONMENT, TEST_TYPE, COLLECTION, COMMAND_TYPE, KEYWORD, FINISHED } Possible Solution (Not-flexible) In reference to my code below, every case statement in the Menu class could check the state of currentMemo and then set the STATE (enum) accordingly to pass to the Builder. However, this doesn't seem flexible very flexible to change and I'm struggling to see an effective way refactor the design. class Menu extends StateConscious { private State state; private Scanner reader; private ServerUtils utility; Menu() { state = new State(); reader = new Scanner(System.in); utility = new ServerUtils(); } // Recurring menu logic public void startPromptingLoop() { List<State> states = new ArrayList<>(); states.add(new State()); boolean redoInput = false; boolean userIsDone = false; while (true) { // get Memento from last loop Memento currentMemento = states.get(states.size() - 1) .saveMemento(); if (currentMemento == null) currentMemento = new Memento.Builder(0).build(); if (!redoInput) System.out.println(currentMemento.prompt); redoInput = false; // prepare Memento for next loop Memento nextMemento = null; STATES state = STATES.values()[states.size() - 1]; // get user input String selection = reader.nextLine(); switch (selection) { case "exit": reader.close(); return; // only escape case "quit": nextMemento = new Memento.Builder(first(), currentMemento, selection).build(); states.clear(); break; case "back": nextMemento = new Memento.Builder(previous(state), currentMemento, selection).build(); if (states.size() <= 1) { states.remove(0); } else { states.remove(states.size() - 1); states.remove(states.size() - 1); } break; case "1": nextMemento = new Memento.Builder(next(state), currentMemento, selection).build(); break; case "2": nextMemento = new Memento.Builder(next(state), currentMemento, selection).build(); break; case "3": nextMemento = new Memento.Builder(next(state), currentMemento, selection).build(); break; case "4": nextMemento = new Memento.Builder(next(state), currentMemento, selection).build(); break; default: if (state.equals(STATES.CATEGORY)) { String command = selection; System.out.println("Executing " + command + " command on: " + currentMemento.type + " " + currentMemento.environment); utility.executeCommand(currentMemento.nickname, command); userIsDone = true; states.clear(); nextMemento = new Memento.Builder(first(), currentMemento, selection).build(); } else if (state.equals(STATES.KEYWORD)) { nextMemento = new Memento.Builder(next(state), currentMemento, selection).build(); states.clear(); nextMemento = new Memento.Builder(first(), currentMemento, selection).build(); } else { redoInput = true; System.out.println("give it another try"); continue; } break; } if (userIsDone) { // start the recurring menu over from the beginning for (int i = 0; i < states.size(); i++) { if (i != 0) { states.remove(i); // remove all except first } } reader = new Scanner(System.in); this.state = new State(); userIsDone = false; } if (!redoInput) { this.state.restoreMemento(nextMemento); states.add(this.state); } } } }

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  • Do leaderboard sets (in Game Center) allow 500 unique leaderboards?

    - by Korey Hinton
    The Game Kit Programming Guide for iOS claims: The number of different leaderboards allowed increases to 500 leaderboards per game when leaderboard sets have been enabled...Leaderboard sets offer developers the ability to combine several leaderboards into a single group. But their example (see image below) implies that a single leaderboard is placed into multiple leaderboard sets. Is that the only way to be able to use the full 500 leaderboards? by combining the same leaderboard into multiple sets? I want to be able to have 500 unique leaderboards that are not duplicated between sets. Is this possible?

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  • Developing wheel reinventing tendencies into a skill as opposed to reluctantly learning wheel-finding skills? [duplicate]

    - by Korey Hinton
    This question already has an answer here: Is reinventing the wheel really all that bad? 20 answers I am more of a high-level wheel reinventor. I definitely prefer to make use of existing API features built into a language and popular third-party frameworks that I know can solve the problem, however when I have a particular problem that I feel capable of solving within a reasonable time I am very reluctant to find someone else's solution. Here are a few reasons why I reinvent: It takes time to learn a new API API restrictions might exist that I don't know about Avoiding re-work of unfamiliar code I am conflicted between doing what I know and shifting to a new technique I don't feel comfortable with. On one hand I feel like following my instincts and getting really good at solving problems, especially ones that I would never challenge myself with if all I did was try to find answers. And on the other hand I feel like I might be missing out on important skills like saving time by finding the right framework and expanding my knowledge by learning how to use a new framework. I guess my question comes down to this: My current attitude is to stick to the built-in API and APIs I know well* and to not spend my time searching github for a solution to a problem I know I can solve myself within a reasonable amount of time. Is that a reasonable balance for a successful programmer? *Obviously I will still look around for new frameworks that save time and solve/simplify difficult problems.

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  • Effective way of keeping past projects with their working development environment?

    - by Korey Hinton
    I find that whenever I want to go run a past project, it will take a long time before I can find it and before I have everything set-up again for it to be able to run. For example, I have python projects I created in Linux, and it depends on software packages that are easily installed in Linux, yet I no longer have the Linux VM I was using. And some of my other projects depend on other variables like web server configuration, PATH variables, sdk, IDE, OS version, device, etc. Does someone have an effective way of handling this issue? As of now I have only concerned myself with keeping the source code backed up yet it is difficult re-establish the working development environment and it is also difficult to keep the working development environment around as well.

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  • sharepoint list relationship question

    - by Korey
    I have two custom lists in sharepoint with a one to many relationship on a column in both lists. So list A has text column 1 and list B has a lookup column 1' on list A's column 1. I want to display the rows in list A, where column 1 has a match on column 1' and a 2nd column in list B with a specific text string. I have Sharepoint Designer and am fumbling along with linked sources described here http://office.microsoft.com/en-us/sharepointdesigner/HA100991441033.aspx, but can't get exactly what I'm looking for.

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