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  • why am i getting error in this switch statement written in c

    - by mekasperasky
    I have a character array b which stores different identifiers in different iterations . I have to compare b with various identifiers of the programming language C and print it into a file . When i do it using the following switch statement it gives me errors b[i]='\0'; switch(b[i]) { case "if":fprintf(fp2,"if ----> IDENTIFIER \n"); case "then":fprintf(fp2,"then ----> IDENTIFIER \n"); case "else":fprintf(fp2,"else ----> IDENTIFIER \n"); case "switch":fprintf(fp2,"switch ----> IDENTIFIER \n"); case 'printf':fprintf(fp2,"prtintf ----> IDENTIFIER \n"); case 'scanf':fprintf(fp2,"else ----> IDENTIFIER \n"); case 'NULL':fprintf(fp2,"NULL ----> IDENTIFIER \n"); case 'int':fprintf(fp2,"INT ----> IDENTIFIER \n"); case 'char':fprintf(fp2,"char ----> IDENTIFIER \n"); case 'float':fprintf(fp2,"float ----> IDENTIFIER \n"); case 'long':fprintf(fp2,"long ----> IDENTIFIER \n"); case 'double':fprintf(fp2,"double ----> IDENTIFIER \n"); case 'char':fprintf(fp2,"char ----> IDENTIFIER \n"); case 'const':fprintf(fp2,"const ----> IDENTIFIER \n"); case 'continue':fprintf(fp2,"continue ----> IDENTIFIER \n"); case 'break':fprintf(fp2,"long ----> IDENTIFIER \n"); case 'for':fprintf(fp2,"long ----> IDENTIFIER \n"); case 'size of':fprintf(fp2,"size of ----> IDENTIFIER \n"); case 'register':fprintf(fp2,"register ----> IDENTIFIER \n"); case 'short':fprintf(fp2,"short ----> IDENTIFIER \n"); case 'auto':fprintf(fp2,"auto ----> IDENTIFIER \n"); case 'while':fprintf(fp2,"while ----> IDENTIFIER \n"); case 'do':fprintf(fp2,"do ----> IDENTIFIER \n"); case 'case':fprintf(fp2,"case ----> IDENTIFIER \n"); } the error being lex.c:94:13: warning: character constant too long for its type lex.c:95:13: warning: character constant too long for its type lex.c:96:13: warning: multi-character character constant lex.c:97:13: warning: multi-character character constant lex.c:98:13: warning: multi-character character constant lex.c:99:13: warning: character constant too long for its type lex.c:100:13: warning: multi-character character constant lex.c:101:13: warning: character constant too long for its type lex.c:102:13: warning: multi-character character constant lex.c:103:13: warning: character constant too long for its type lex.c:104:13: warning: character constant too long for its type lex.c:105:13: warning: character constant too long for its type lex.c:106:13: warning: multi-character character constant lex.c:107:13: warning: character constant too long for its type lex.c:108:13: warning: character constant too long for its type lex.c:109:13: warning: character constant too long for its type lex.c:110:12: warning: multi-character character constant lex.c:111:13: warning: character constant too long for its type lex.c:112:13: warning: multi-character character constant lex.c:113:13: warning: multi-character character constant lex.c: In function ‘int main()’: lex.c:90: error: case label does not reduce to an integer constant lex.c:91: error: case label does not reduce to an integer constant lex.c:92: error: case label does not reduce to an integer constant lex.c:93: error: case label does not reduce to an integer constant lex.c:94: warning: overflow in implicit constant conversion lex.c:95: warning: overflow in implicit constant conversion lex.c:95: error: duplicate case value lex.c:94: error: previously used here lex.c:96: warning: overflow in implicit constant conversion lex.c:97: warning: overflow in implicit constant conversion lex.c:98: warning: overflow in implicit constant conversion lex.c:99: warning: overflow in implicit constant conversion lex.c:99: error: duplicate case value lex.c:97: error: previously used here lex.c:100: warning: overflow in implicit constant conversion lex.c:101: warning: overflow in implicit constant conversion lex.c:102: warning: overflow in implicit constant conversion lex.c:102: error: duplicate case value lex.c:98: error: previously used here lex.c:103: warning: overflow in implicit constant conversion lex.c:103: error: duplicate case value lex.c:97: error: previously used here lex.c:104: warning: overflow in implicit constant conversion lex.c:104: error: duplicate case value lex.c:101: error: previously used here lex.c:105: warning: overflow in implicit constant conversion lex.c:106: warning: overflow in implicit constant conversion lex.c:106: error: duplicate case value lex.c:98: error: previously used here lex.c:107: warning: overflow in implicit constant conversion lex.c:107: error: duplicate case value lex.c:94: error: previously used here lex.c:108: warning: overflow in implicit constant conversion lex.c:108: error: duplicate case value lex.c:98: error: previously used here lex.c:109: warning: overflow in implicit constant conversion lex.c:109: error: duplicate case value lex.c:97: error: previously used here lex.c:110: warning: overflow in implicit constant conversion lex.c:111: warning: overflow in implicit constant conversion lex.c:111: error: duplicate case value lex.c:101: error: previously used here lex.c:112: warning: overflow in implicit constant conversion lex.c:112: error: duplicate case value lex.c:110: error: previously used here lex.c:113: warning: overflow in implicit constant conversion lex.c:113: error: duplicate case value lex.c:101: error: previously used here

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  • error in coding a lexer in c

    - by mekasperasky
    #include<stdio.h> #include<ctype.h> #include<string.h> /* this is a lexer which recognizes constants , variables ,symbols, identifiers , functions , comments and also header files . It stores the lexemes in 3 different files . One file contains all the headers and the comments . Another file will contain all the variables , another will contain all the symbols. */ int main() { int i=0,j,k,count=0; char a,b[100],c[10000],d[100]; memset ( d, 0, 100 ); j=30; FILE *fp1,*fp2; fp1=fopen("source.txt","r"); //the source file is opened in read only mode which will passed through the lexer fp2=fopen("lext.txt","w"); //now lets remove all the white spaces and store the rest of the words in a file if(fp1==NULL) { perror("failed to open source.txt"); //return EXIT_FAILURE; } i=0; k=0; while(!feof(fp1)) { a=fgetc(fp1); if(a!=' '&&a!='\n') { if (!isalpha(a)) { switch(a) { case '+':{fprintf(fp2,"+ ----> PLUS \n"); i=0;break;} case '-':{fprintf(fp2,"- ---> MINUS \n"); i=0;break;} case '*':{fprintf(fp2, "* --->MULT \n"); i=0;break;} case '/':{fprintf(fp2, "/ --->DIV \n"); i=0;break;} //case '+=':fprintf(fp2, "%.20s\n", "ADD_ASSIGN"); //case '-=':fprintf(fp2, "%.20s\n", "SUB_ASSIGN"); case '=':{fprintf(fp2, "= ---> ASSIGN \n"); i=0;break;} case '%':{fprintf(fp2, "% ---> MOD \n"); i=0;break;} case '<':{fprintf(fp2, "< ---> LESSER_THAN \n"); i=0;break;} case '>':{fprintf(fp2, "> --> GREATER_THAN \n"); i=0;break;} //case '++':fprintf(fp2, "%.20s\n", "INCREMENT"); //case '--':fprintf(fp2, "%.20s\n", "DECREMENT"); //case '==':fprintf(fp2, "%.20s\n", "ASSIGNMENT"); case ';':{fprintf(fp2, "; --->SEMI_COLUMN \n"); i=0;break;} case ':':{fprintf(fp2, ": --->COLUMN \n"); i=0;break;} case '(':{fprintf(fp2, "( --->LPAR \n"); i=0;break;} case ')':{fprintf(fp2, ") --->RPAR \n"); i=0;break;} case '{':{fprintf(fp2, "{ --->LBRACE \n"); i=0;break;} case '}':{fprintf(fp2, "} ---> RBRACE \n"); i=0;break;} } } else { d[i]=a; //printf("%c\n",d[i]); i=i+1; } //} /* we can make the lexer more complex by including even more depths of checks for the symbols*/ } else { d[i+1]='\0'; printf("\n"); if((strcmp(d,"if ")==0)){fprintf(fp2,"if ----> IDENTIFIER \n"); //printf("%s \n",d); memset ( d, 0, 100 ); //printf("%s \n",d); count=count+1;} else if(strcmp(d,"then")==0){fprintf(fp2,"then ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"else")==0){fprintf(fp2,"else ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"switch")==0){fprintf(fp2,"switch ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"printf")==0){fprintf(fp2,"prtintf ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"scanf")==0){fprintf(fp2,"scanf ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"NULL")==0){fprintf(fp2,"NULL ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"int")==0){fprintf(fp2,"INT ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"char")==0){fprintf(fp2,"char ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"float")==0){fprintf(fp2,"float ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"long")==0){fprintf(fp2,"long ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"double")==0){fprintf(fp2,"double ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"const")==0){fprintf(fp2,"const ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"continue")==0)fprintf(fp2,"continue ----> IDENTIFIER \n"); else if(strcmp(d,"size of")==0){fprintf(fp2,"size of ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"register")==0){fprintf(fp2,"register ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"short")==0){fprintf(fp2,"short ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"auto")==0){fprintf(fp2,"auto ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"while")==0){fprintf(fp2,"while ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"do")==0){fprintf(fp2,"do ----> IDENTIFIER \n"); count=count+1;} else if(strcmp(d,"case")==0){fprintf(fp2,"case ----> IDENTIFIER \n"); count=count+1;} else if (isdigit(d[i])) { fprintf(fp2,"%s ---->NUMBER",d); } else if (isalpha(a)) { fprintf(fp2,"%s ----> Variable",d); //printf("%s",d); // memset ( d, 0, 100 );} //fprintf(fp2, "s\n", b); i=0; k=k+1; continue; } i=i+1; k=k+1; } fclose(fp1); fclose(fp2); printf("%d",count); return 0; } In this code , my source.txt has if (a+b) stored . But only ( , + and ) is getting written into lext.txt and not the identifier if or the variable a and b . Any particular reason why?

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  • str is not callable error in python .

    - by mekasperasky
    import sys import md5 from TOSSIM import * from RadioCountMsg import * t = Tossim([]) #The Tossim object is defined here m = t.mac()#The mac layer is defined here , in which the communication takes place r = t.radio()#The radio communication link object is defined here , as the communication needs Rf frequency to transfer t.addChannel("RadioCountToLedsC", sys.stdout)# The various channels through which communication will take place t.addChannel("LedsC", sys.stdout) #The no of nodes that would be required in the simulation has to be entered here print("enter the no of nodes you want ") n=input() for i in range(0, n): m = t.getNode(i) m.bootAtTime((31 + t.ticksPerSecond() / 10) * i + 1) #The booting time is defined so that the time at which the node would be booted is given f = open("topo.txt", "r") #The topography is defined in topo.txt so that the RF frequencies of the transmission between nodes are are set lines = f.readlines() for line in lines: s = line.split() if (len(s) > 0): if (s[0] == "gain"): r.add(int(s[1]), int(s[2]), float(s[3])) #The topogrography is added to the radio object noise = open("meyer-heavy.txt", "r") #The noise model is defined for the nodes lines = noise.readlines() for line in lines: str = line.strip() if (str != ""): val = int(str) for i in range(0, 4): t.getNode(i).addNoiseTraceReading(val) for i in range (0, n): t.getNode(i).createNoiseModel() #The noise model is created for each node for i in range(0,n): t.runNextEvent() fk=open("key.txt","w") for i in range(0,n): if i ==0 : key=raw_input() fk.write(key) ak=key key=md5.new() key.update(str(ak)) ak=key.digest() fk.write(ak) fk.close() fk=open("key.txt","w") plaint=open("pt.txt") for i in range(0,n): msg = RadioCountMsg() msg.set_counter(7) pkt = t.newPacket()#A packet is defined according to a certain format print("enter message to be transported") ms=raw_input()#The message to be transported is taken as input #The RC5 encryption has to be done here plaint.write(ms) pkt.setData(msg.data) pkt.setType(msg.get_amType()) pkt.setDestination(i+1)#The destination to which the packet will be sent is set print "Delivering " + " to" ,i+1 pkt.deliver(i+1, t.time() + 3) fk.close() print "the key to be displayed" ki=raw_input() fk=open("key.txt") for i in range(0,n): if i==ki: ms=fk.readline() for i in range(0,n): msg=RadioCountMsg() msg.set_counter(7) pkt=t.newPacket() msg.data=ms pkt.setData(msg.data) pkt.setType(msg.get_amType()) pkt.setDestination(i+1) pkt.deliver(i+1,t.time()+3) #The key has to be broadcasted here so that the decryption can take place for i in range(0, n): t.runNextEvent(); this code gives me error here key.update(str(ak)) . when i run a similar code on the python terminal there is no such error but this code pops up an error . why so?

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  • ./a.out termniated . Garbage output due to smashing of stack . How to remove this error ?

    - by mekasperasky
    #include <iostream> #include <fstream> #include <cstring> using namespace std; typedef unsigned long int WORD; /* Should be 32-bit = 4 bytes */ #define w 32 /* word size in bits */ #define r 12 /* number of rounds */ #define b 16 /* number of bytes in key */ #define c 4 /* number words in key */ /* c = max(1,ceil(8*b/w)) */ #define t 26 /* size of table S = 2*(r+1) words */ WORD S [t],L[c]; /* expanded key table */ WORD P = 0xb7e15163, Q = 0x9e3779b9; /* magic constants */ /* Rotation operators. x must be unsigned, to get logical right shift*/ #define ROTL(x,y) (((x)<<(y&(w-1))) | ((x)>>(w-(y&(w-1))))) #define ROTR(x,y) (((x)>>(y&(w-1))) | ((x)<<(w-(y&(w-1))))) void RC5_ENCRYPT(WORD *pt, WORD *ct) /* 2 WORD input pt/output ct */ { WORD i, A=pt[0]+S[0], B=pt[1]+S[1]; for (i=1; i<=r; i++) { A = ROTL(A^B,B)+S[2*i]; B = ROTL(B^A,A)+S[2*i+1]; } ct [0] = A ; ct [1] = B ; } void RC5_DECRYPT(WORD *ct, WORD *pt) /* 2 WORD input ct/output pt */ { WORD i, B=ct[1], A=ct[ 0]; for (i=r; i>0; i--) { B = ROTR(B-S [2*i+1],A)^A; A = ROTR(A-S [2*i],B)^B; } pt [1] = B-S [1] ;pt [0] = A-S [0]; } void RC5_SETUP(unsigned char *K) /* secret input key K 0...b-1] */ { WORD i, j, k, u=w/8, A, B, L [c]; /* Initialize L, then S, then mix key into S */ for (i=b-1,L[c-1]=0; i!=-1; i--) L[i/u] = (L[i/u]<<8)+K[ i]; for (S [0]=P,i=1; i<t; i++) S [i] = S [i-1]+Q; for (A=B=i=j=k=0; k<3*t; k++,i=(i+1)%t,j=(j+1)%c) /* 3*t > 3*c */ { A = S[i] = ROTL(S [i]+(A+B),3); B = L[j] = ROTL(L[j]+(A+B),(A+B)); } } void printword(WORD A) { WORD k; for (k=0 ;k<w; k+=8) printf("%c"); } int main() { WORD i, j, k,ptext, pt1 [2], pt2 [2], ct [2] = {0,0}; ifstream in("key1.txt"); ifstream in1("plt.txt"); ofstream out1("cpt.txt"); if(!in) { cout << "Cannot open file.\n"; return 1; } if(!in1) { cout << "Cannot open file.\n"; return 1; } unsigned char key[b]; in >> key; in1 >> pt1[0]; in1 >> pt1[0]; if (sizeof(WORD)!=4) printf("RC5 error: WORD has %d bytes.\n",sizeof(WORD)); RC5_SETUP(key); RC5_ENCRYPT(pt1,ct); printf("\n plaintext "); printword(pt1 [0]); printword(pt1 [1]); printf(" ---> ciphertext "); printword(ct [0]); printword(ct [1]); printf("\n"); RC5_SETUP(key); RC5_DECRYPT(ct,pt2); out1<<ct[0]; out1<<ct[1]; out1 <<"\n"; printf("\n plaintext "); printword(pt1 [0]); printword(pt1 [1]); return 0; } Let the plt.txt file contain 101 100 let the key be 111

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  • python lists error

    - by mekasperasky
    #defining the magic constants p=0xb7e15163 q=0x9e3779b9 pt=list() pt1=list() ct=list() pt2=list() #pt[0]=0pt1[0]=ct[0]=pt1[1]=ct[1]=0 s=[] l=[] b=8 key=[0,0,0,0,0,0,0,0,0] w=8 t=16 def enc(c,d): for i in range(1,r): A=A+s[0] B=B+s[1] A=A^B A=str(A) B=str(B) A=A[len(B):]+A[:len(B)] B=B^A A=str(A) B=str(B) B=B[len(A):]+B[:len(B)] A=A+s[2*i] B=B+s[2*i+1] ct.append(A) ct.append(B) def denc(): for i in range(r,1): A=ct[0] B=ct[1] B=B-s[2*i+1] B=B[len(c):] + B[:len(c)] B=B^A A=A-s[2*i] A=A[:len(B)]+c[len(B):] A=A^B pt1[1]=B-S[1] pt1[0]=A-S[0] def setup(k): u=w/8 for i in range(b-1,0): l.append(l[i/u:8]+l[8:i/u]+k[i]) s.append(p) for i in range(1,t-1): s.append(s[i-1] + q) i=j=0 A=B=0 for i in range(0,3*t): A=s.append(s[i]+A+B) B=s.append(s[:3]+s[3:]) #B=l.append((l[j]+A+B)) ll=len(str(A))+len(str(B)) B=l.append(l[:ll]+l[ll:]) i=(i+1)%t j=(j+1)%t def pri(g): for k in range(0,w): print g & 0xFF #for i in range(0,b): #key[i]=ct[0]%(255-j) pt1=[raw_input()] pt1=[raw_input()] setup(key) enc(pt1,ct) denc(ct,pt2) print("key") print(key) print("plaintext") printword(pt1[0]),printword(pt1[1]) printword(ct[0]),printword(ct[1]) the list l is always going out of index though it should not . I am not able to take the length of the string A even though it is a string .Once i convert it to string i am not able to add it in s[j]+A+B. How to get around such errors and make the code more hygenic .. This is an rc5 cipher.

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  • Error while trying to parse a website url using python . how to debug it ?

    - by mekasperasky
    #!/usr/bin/python import json import urllib from BeautifulSoup import BeautifulSoup from BeautifulSoup import BeautifulStoneSoup import BeautifulSoup def showsome(searchfor): query = urllib.urlencode({'q': searchfor}) url = 'http://ajax.googleapis.com/ajax/services/search/web?v=1.0&%s' % query search_response = urllib.urlopen(url) search_results = search_response.read() results = json.loads(search_results) data = results['responseData'] print 'Total results: %s' % data['cursor']['estimatedResultCount'] hits = data['results'] print 'Top %d hits:' % len(hits) for h in hits: print ' ', h['url'] resp = urllib.urlopen(h['url']) res = resp.read() soup = BeautifulSoup(res) print soup.prettify() print 'For more results, see %s' % data['cursor']['moreResultsUrl'] showsome('sachin') What is the wrong in this code ? Note all the 4 links that I am getting out of the search , I am feeding it back to extract the contents out of it , and then use BeautifulSoup to parse it . How should I go about it ?

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  • assigning a list in python

    - by mekasperasky
    pt=[2] pt[0]=raw_input() when i do this , and give an input suppose 1011 , it says list indexing error- " list assignment index out of range" . may i know why? i think i am not able to assign a list properly . how to assign an array of 2 elements in python then?

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  • error in finding out the lexems and no of lines of a text file in C

    - by mekasperasky
    #include<stdio.h> #include<ctype.h> #include<string.h> int main() { int i=0,j,k,lines_count[2]={1,1},operand_count[2]={0},operator_count[2]={0},uoperator_count[2]={0},control_count[2]={0,0},cl[13]={0},variable_dec[2]={0,0},l,p[2]={0},ct,variable_used[2]={0,0},constant_count[2],s[2]={0},t[2]={0}; char a,b[100],c[100]; char d[100]={0}; j=30; FILE *fp1[2],*fp2; fp1[0]=fopen("program1.txt","r"); fp1[1]=fopen("program2.txt","r"); //the source file is opened in read only mode which will passed through the lexer fp2=fopen("ccv1ouput.txt","wb"); //now lets remove all the white spaces and store the rest of the words in a file if(fp1[0]==NULL) { perror("failed to open program1.txt"); //return EXIT_FAILURE; } if(fp1[1]==NULL) { perror("failed to open program2.txt"); //return EXIT_FAILURE; } i=0; k=0; ct=0; while(ct!=2) { while(!feof(fp1[ct])) { a=fgetc(fp1[ct]); if(a!=' '&&a!='\n') { if (!isalpha(a) && !isdigit(a)) { switch(a) { case '+':{ i=0; cl[0]=1; operator_count[ct]=operator_count[ct]+1;break;} case '-':{ cl[1]=1; operator_count[ct]=operator_count[ct]+1;i=0;break;} case '*':{ cl[2]=1; operator_count[ct]=operator_count[ct]+1;i=0;break;} case '/':{ cl[3]=1; operator_count[ct]=operator_count[ct]+1;i=0;break;} case '=':{a=fgetc(fp1[ct]); if (a=='='){cl[4]=1; operator_count[ct]=operator_count[ct]+1; operand_count[ct]=operand_count[ct]+1;} else { cl[5]=1; operator_count[ct]=operator_count[ct]+1; operand_count[ct]=operand_count[ct]+1; ungetc(1,fp1[ct]); } break;} case '%':{ cl[6]=1; operator_count[ct]=operator_count[ct]+1;i=0;break;} case '<':{ a=fgetc(fp1[ct]); if (a=='=') {cl[7]=1; operator_count[ct]=operator_count[ct]+1;} else { cl[8]=1; operator_count[ct]=operator_count[ct]+1; ungetc(1,fp1[ct]); } break; } case '>':{ ; a=fgetc(fp1[ct]); if (a=='='){cl[9]=1; operator_count[ct]=operator_count[ct]+1;} else { cl[10]=1; operator_count[ct]=operator_count[ct]+1; ungetc(1,fp1[ct]); } break;} case '&':{ cl[11]=1; a=fgetc(fp1[ct]); operator_count[ct]=operator_count[ct]+1; operand_count[ct]=operand_count[ct]+1; variable_used[ct]=variable_used[ct]-1; break; } case '|':{ cl[12]=1; a=fgetc(fp1[ct]); operator_count[ct]=operator_count[ct]+1; operand_count[ct]=operand_count[ct]+1; variable_used[ct]=variable_used[ct]-1; break; } case '#':{ while(a!='\n') { a=fgetc(fp1[ct]); } } } } else { d[i]=a; i=i+1; k=k+1; } } else { //printf("%s \n",d); if((strcmp(d,"if")==0)){ memset ( d, 0, 100 ); i=0; control_count[ct]=control_count[ct]+1; } else if(strcmp(d,"then")==0){ i=0;memset ( d, 0, 100 );control_count[ct]=control_count[ct]+1;} else if(strcmp(d,"else")==0){ i=0;memset ( d, 0, 100 );control_count[ct]=control_count[ct]+1;} else if(strcmp(d,"while")==0){ i=0;memset ( d, 0, 100 );control_count[ct]=control_count[ct]+1;} else if(strcmp(d,"int")==0){ while(a != '\n') { a=fgetc(fp1[ct]); if (isalpha(a) ) variable_dec[ct]=variable_dec[ct]+1; } memset ( d, 0, 100 ); lines_count[ct]=lines_count[ct]+1; } else if(strcmp(d,"char")==0){while(a != '\n') { a=fgetc(fp1[ct]); if (isalpha(a) ) variable_dec[ct]=variable_dec[ct]+1; } memset ( d, 0, 100 ); lines_count[ct]=lines_count[ct]+1; } else if(strcmp(d,"float")==0){while(a != '\n') { a=fgetc(fp1[ct]); if (isalpha(a) ) variable_dec[ct]=variable_dec[ct]+1; } memset ( d, 0, 100 ); lines_count[ct]=lines_count[ct]+1; } else if(strcmp(d,"printf")==0){while(a!='\n') a=fgetc(fp1[ct]); memset(d,0,100); } else if(strcmp(d,"scanf")==0){while(a!='\n') a=fgetc(fp1[ct]); memset(d,0,100);} else if (isdigit(d[i-1])) { memset ( d, 0, 100 ); i=0; constant_count[ct]=constant_count[ct]+1; operand_count[ct]=operand_count[ct]+1; } else if (isalpha(d[i-1]) && strcmp(d,"int")!=0 && strcmp(d,"char")!=0 && strcmp(d,"float")!=0 && (strcmp(d,"if")!=0) && strcmp(d,"then")!=0 && strcmp(d,"else")!=0 && strcmp(d,"while")!=0 && strcmp(d,"printf")!=0 && strcmp(d,"scanf")!=0) { memset ( d, 0, 100 ); i=0; operand_count[ct]=operand_count[ct]+1; } else if(a=='\n') { lines_count[ct]=lines_count[ct]+1; memset ( d, 0, 100 ); } } } fclose(fp1[ct]); operand_count[ct]=operand_count[ct]-5; variable_used[0]=operand_count[0]-constant_count[0]; variable_used[1]=operand_count[1]-constant_count[1]; for(j=0;j<12;j++) uoperator_count[ct]=uoperator_count[ct]+cl[j]; fprintf(fp2,"\n statistics of program %d",ct+1); fprintf(fp2,"\n the no of lines ---> %d",lines_count[ct]); fprintf(fp2,"\n the no of operands --->%d",operand_count[ct]); fprintf(fp2,"\n the no of operator --->%d",operator_count[ct]); fprintf(fp2,"\n the no of control statments --->%d",control_count[ct]); fprintf(fp2,"\n the no of unique operators --->%d",uoperator_count[ct]); fprintf(fp2,"\n the no of variables declared--->%d",variable_dec[ct]); fprintf(fp2,"\n the no of variables used--->%d",variable_used[ct]); fprintf(fp2,"\n ---------------------------------"); fprintf(fp2,"\n \t \t \t"); ct=ct+1; } t[0]=lines_count[0]+control_count[0]+uoperator_count[0]; t[1]=lines_count[1]+control_count[1]+uoperator_count[1]; s[0]=operator_count[0]+operand_count[0]+variable_dec[0]+variable_used[0]; s[1]=operator_count[1]+operand_count[1]+variable_dec[1]+variable_used[1]; fprintf(fp2,"\n the time complexity of program 1 is %d",t[0]); fprintf(fp2,"\n the time complexity of program 2 is %d",t[1]); fprintf(fp2,"\n the space complexity of program 1 is %d",s[0]); fprintf(fp2,"\n the space complexity of program 2 is %d",s[1]); if((t[0]>t[1]) && (s[0] >s[1])) fprintf(fp2,"\n the efficiency of program 2 is greater than program 1"); else if(t[0]<t[1] && s[0] < s[1]) fprintf(fp2,"\n the efficiency of program 1 is greater than program 2 " ); else if (t[0]+s[0] > t[1]+s[1]) fprintf(fp2,"\n the efficiency of program 1 is greater than program 2"); else if (t[0]+s[0] < t[1]+s[1]) fprintf(fp2,"\n the efficiency of program 2 is greater than program 1"); else if (t[0]+s[0] == t[1]+s[1]) fprintf(fp2,"\n the efficiency of program 1 is equal to that of program 2"); fclose(fp2); return 0; } this code basically compares two c codes and finds out the no. of variables declared , used , no. of control statements , no. of lines and no. of unique operators , and operands , so as to find out the time complexity and space complexity of of the two programs given in the text file program1.txt and program2.txt ... Lets say program1.txt is this #include<stdio.h> #include<math.h> int main () { FILE *fp; fp=fopen("output.txt","w"); long double t,y=0,x=0,e=5,f=1,w=1; for (t=0;t<10;t=t+0.01) { //if (isnan(y) || isinf(y)) //break; fprintf(fp,"%ld\t%ld\n",y,x); y = y + ((e*(1 - (x*x))*y) - x + f*cos(w*0.1))*0.1; x = x + y*0.1; } fclose(fp); return (0); } i havent indented it as its just a text file . But my output is totally faulty . Its not able to find the any of the ouput that i need . Where is the bug in this ? I am not able to figure out as the algorithm looks fine .

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  • error in a pygame code

    - by mekasperasky
    # INTIALISATION import pygame, math, sys from pygame.locals import * screen = pygame.display.set_mode((1024, 768)) car = pygame.image.load('car.png') clock = pygame.time.Clock() k_up = k_down = k_left = k_right = 0 speed = direction = 0 position = (100, 100) TURN_SPEED = 5 ACCELERATION = 2 MAX_FORWARD_SPEED = 10 MAX_REVERSE_SPEED = ­5 BLACK = (0,0,0) while 1: # USER INPUT clock.tick(30) for event in pygame.event.get(): if not hasattr(event, 'key'): continue down = event.type == KEYDOWN # key down or up? if event.key == K_RIGHT: k_right = down * ­5 elif event.key == K_LEFT: k_left = down * 5 elif event.key == K_UP: k_up = down * 2 elif event.key == K_DOWN: k_down = down * ­2 elif event.key == K_ESCAPE: sys.exit(0) # quit the game screen.fill(BLACK) # SIMULATION # .. new speed and direction based on acceleration and turn speed += (k_up + k_down) if speed > MAX_FORWARD_SPEED: speed = MAX_FORWARD_SPEED if speed < MAX_REVERSE_SPEED: speed = MAX_REVERSE_SPEED direction += (k_right + k_left) # .. new position based on current position, speed and direction x, y = position rad = direction * math.pi / 180 x += ­speed*math.sin(rad) y += ­speed*math.cos(rad) position = (x, y) # RENDERING # .. rotate the car image for direction rotated = pygame.transform.rotate(car, direction) # .. position the car on screen rect = rotated.get_rect() rect.center = position # .. render the car to screen screen.blit(rotated, rect) pygame.display.flip() enter code here the error i get is this Non-ASCII character '\xc2' in file race1.py on line 13, but no encoding declared; see http://www.python.org/peps/pep-0263.html for details Not able to understand what the error is and how to get rid of it?

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  • segmentation fault in file operations in c

    - by mekasperasky
    #include<stdio.h> /* this is a lexer which recognizes constants , variables ,symbols, identifiers , functions , comments and also header files . It stores the lexemes in 3 different files . One file contains all the headers and the comments . Another file will contain all the variables , another will contain all the symbols. */ int main() { int i; char a,b[20],c; FILE *fp1; fp1=fopen("source.txt","r"); //the source file is opened in read only mode which will passed through the lexer //now lets remove all the white spaces and store the rest of the words in a file if(fp1==NULL) { perror("failed to open source.txt"); //return EXIT_FAILURE; } i=0; while(1) { a=fgetc(fp1); if(a !="") { b[i]=a; } else { fprintf(fp1, "%.20s\n", b); i=0; continue; } i=i+1; /*Switch(a) { case EOF :return eof; case '+':sym=sym+1; case '-':sym=sym+1; case '*':sym=sym+1; case '/':sym=sym+1; case '%':sym=sym+1; case ' */ } return 0; } how does this code end up in segmentation fault?

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  • what does this error mean in c?

    - by mekasperasky
    #include<stdio.h> #include<ctype.h> int main() { char a,b; FILE *fp; fp=fopen("lext.txt","w"); fprintf(fp,"PLUS"); return 0; } the error i get is this /tmp/ccQyyhxo.o:(.eh_frame+0x11): undefined reference to `__gxx_personality_v0' collect2: ld returned 1 exit status

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  • error in coding in pygame.

    - by mekasperasky
    import pygame from pygame.locals import * screen=pygame.display.set_mode() nin=pygame.image.load('/home/satyajit/Desktop/nincompoop0001.bmp') screen.blit(nin,(50,100)) according to the code i should get a screen with an image of nin on it . But I only get a black screen which doesnt go even though i press the exit button on it. how to get the image on the screen?

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  • A python code to convert a number from any base to the base of 10 giving errors . What is wrong with this code?

    - by mekasperasky
    import math def baseencode(number, base): ##Converting a number of any base to base10 if number == 0: return '0' for i in range(0,len(number)): if number[i]!= [A-Z]: num = num + number[i]*pow(i,base) else : num = num + (9 + ord(number[i])) *pow(i,base) return num a = baseencode('20',5) print a Errors I get are Traceback (most recent call last): File "doubtrob.py", line 19, in <module> a = baseencode('20',5) File "doubtrob.py", line 13, in baseencode if number[i]!= [A-Z]: NameError: global name 'A' is not defined

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  • where is the error in this C code , and how to get rid of the warnings?

    - by mekasperasky
    #include<stdio.h> #include<string.h> //This program is a sorting application that reads a sequence of numbers from a file and prints them on the screen . The reading from the file here , is a call back function . typedef int (*CompFunc)(const char* , const char* ); typedef int (*ReadCheck)(char nullcheck); char array[100]; //Let this fucntion be done in the library itself . It doesnt care as to where the compare function and how is it implemented . Meaning suppose the function wants to do sort in ascending order or in descending order then the changes have to be done by the client code in the "COMPARE" function who will be implementing the lib code . void ReadFile(FILE *fp,ReadCheck rc) { char a; char d[100]; int count = 0,count1=0; a=fgetc(fp); while(1 != (*rc)(a)) { if(a=='\0') { strcpy(array[count],d); count=count+1; } else { d[count1]=a; count1=count1+1; } } } void Bubblesort(int* array , int size , int elem_size , CompFunc cf) { int i,j; int *temp; for( i=0;i < size ;i++) { for ( j=0;j < size -1 ; j++) { // make the callback to the comparision function if(1 == (*cf)(array+j*elem_size,array+ (j+1)*elem_size)) { //interchanging of elements temp = malloc(sizeof(int *) * elem_size); memcpy(temp , array+j*elem_size,elem_size); memcpy(array+j*elem_size,array+(j+1)*elem_size,elem_size); memcpy(array + (j+1)*elem_size , temp , elem_size); free(temp); } } } } //Let these functions be done at the client side int Compare(const char* el1 , const char* el2) { int element1 = *(int*)el1; int element2 = *(int*)el2; if(element1 < element2 ) return -1; if(element1 > element2) return 1 ; return 0; } int ReadChecked(char nullcheck) { if (nullcheck=='\n') return 1; else return 0; } int main() { FILE fp1; int k; fp1=fopen("readdata.txt","r"); Readfile(fp1,&ReadChecked); Bubblesort((char*)array,5,sizeof(array[0]),&Compare); printf("after sorting \n"); for (k=0;k<5;k++) printf("%d",array[k]); return 0; } The error i get is fsc1.c: In function ‘ReadFile’: fsc1.c:19: warning: passing argument 1 of ‘strcpy’ makes pointer from integer without a cast fsc1.c: In function ‘Bubblesort’: fsc1.c:40: warning: passing argument 1 of ‘cf’ from incompatible pointer type fsc1.c:40: warning: passing argument 2 of ‘cf’ from incompatible pointer type fsc1.c:43: warning: incompatible implicit declaration of built-in function ‘malloc’ fsc1.c:47: warning: incompatible implicit declaration of built-in function ‘free’ fsc1.c: In function ‘main’: fsc1.c:80: error: incompatible types in assignment fsc1.c:82: warning: passing argument 1 of ‘Bubblesort’ from incompatible pointer type

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