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  • How do I insert a row with a TimeUUIDType column in Cassandra?

    - by mixmasteralan
    In Cassandra, I have the following Column Family: <ColumnFamily CompareWith="TimeUUIDType" Name="Posts"/> I'm trying to insert a record into it as follows using a C++ generated function generated by Thrift: ColumnPath new_col; new_col.__isset.column = true; /* this is required! */ new_col.column_family.assign("Posts"); new_col.super_column.assign(""); new_col.column.assign("1968ec4a-2a73-11df-9aca-00012e27a270"); client.insert("Keyspace1", "somekey", new_col, "Random Value", 1234, ONE); However, I'm getting the following error: "UUIDs must be exactly 16 bytes" I've even tried the Cassandra CLI with the following command: set Keyspace1.Posts['somekey']['1968ec4a-2a73-11df-9aca-00012e27a270'] = 'Random Value' but I still get the following error: Exception null InvalidRequestException(why:UUIDs must be exactly 16 bytes) at org.apache.cassandra.thrift.Cassandra$insert_result.read(Cassandra.java:11994) at org.apache.cassandra.thrift.Cassandra$Client.recv_insert(Cassandra.java:659) at org.apache.cassandra.thrift.Cassandra$Client.insert(Cassandra.java:632) at org.apache.cassandra.cli.CliClient.executeSet(CliClient.java:420) at org.apache.cassandra.cli.CliClient.executeCLIStmt(CliClient.java:80) at org.apache.cassandra.cli.CliMain.processCLIStmt(CliMain.java:132) at org.apache.cassandra.cli.CliMain.main(CliMain.java:173)

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