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  • What type of command can I use for shortcut assignment?

    - by navie
    We all know that Ubuntu 12 has a shortcut mapper under "Keyboard" utility. I wonder when it asks for "command" in the new shortcut dialog, what type of command can I use? I used to think that commands in terminal can also be used here, but it seems xdotool is not like that. btw, if xdotool is not the right solution, how to map a key combination to a another key? for e.g.: alt+j to Down arrow key Thank you

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  • Bison input analyzer - basic question on optional grammer and input interpretation

    - by kumar_m_kiran
    Hi All, I am very new to Flex/Bison, So it is very navie question. Pardon me if so. May look like homework question - but I need to implement project based on below concept. My question is related to two parts, Question 1 In Bison parser, How do I provide rules for optional input. Like, I need to parse the statment Example : -country='USA' -state='INDIANA' -population='100' -ratio='0.5' -comment='Census study for Indiana' Here the ratio token can be optional. Similarly, If I have many tokens optional, then How do I provide the grammer in the parser for the same? My code looks like, %start program program : TK_COUNTRY TK_IDENTIFIER TK_STATE TK_IDENTIFIER TK_POPULATION TK_IDENTIFIER ... where all the tokens are defined in the lexer. Since there are many tokens which are optional, If I use "|" then there will be many different ways of input combination possible. Question 2 There are good chance that the comment might have quotes as part of the input, so I have added a token -tag which user can provide to interpret the same, Example : -country='USA' -state='INDIANA' -population='100' -ratio='0.5' -comment='Census study for Indiana$'s population' -tag=$ Now, I need to reinterpret Indiana$'s as Indiana's since -tag=$. Please provide any input or related material for to understand these topic. Thanks for your input in advance.

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  • multiple definition of inline function

    - by K71993
    Hi, I have gone through some posts related to this topic but was not able to sort out my doubt completly. This might be a very navie question. Code Description I have a header file "inline.h" and two translation unit "main.cpp" and "tran.cpp". Details of code are as below inline.h file details #ifndef __HEADER__ #include <stdio.h> extern inline int func1(void) { return 5; } static inline int func2(void) { return 6; } inline int func3(void) { return 7; } #endif main.c file details are below #define <stdio.h> #include <inline.h> int main(int argc, char *argv[]) { printf("%d\n",func1()); printf("%d\n",func2()); printf("%d\n",func3()); return 0; } tran.cpp file details (Not that the functions are not inline here) #include <stdio.h> int func1(void) { return 500; } int func2(void) { return 600; } int func3(void) { return 700; } Question The above code does not compile in gcc compiler whereas compiles in g++ (Assuming you make changes related to gcc in code like changing the code to .c not using any C++ header files... etc). The error displayed is "duplicate definition of inline function - func3". Can you clarify why this difference is present across compile? When you run the program (g++ compiled) by creating two seperate compilation unit (main.o and tran.o and create an executable a.out), the output obtained is 500 6 700 Why does the compiler pick up the definition of the function which is not inline. Actually since #include is used to "add" the inline definiton I had expected 5,6,7 as the output. My understanding was during compilation since the inline definition is found, the function call would be "replaced" by inline function definition. Can you please tell me in detailed steps the process of compilation and linking which would lead us to 500,6,700 output. I can only understand the output 6. Thanks in advance for valuable input.

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