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  • Get to Know a Candidate (8 of 25): Rocky Anderson–Justice Party

    - by Brian Lanham
    DISCLAIMER: This is not a post about “Romney” or “Obama”. This is not a post for whom I am voting. Information sourced for Wikipedia. Ross Carl “Rocky” Anderson served two terms as the 33rd mayor of Salt Lake City, Utah, between 2000 and 2008.  He is the Executive Director of High Road for Human Rights.  Prior to serving as Mayor, he practiced law for 21 years in Salt Lake City, during which time he was listed in Best Lawyers in America, was rated A-V (highest rating) by Martindale-Hubbell, served as Chair of the Utah State Bar Litigation Section[4] and was Editor-in-Chief of, and a contributor to, Voir Dire legal journal. As mayor, Anderson rose to nationwide prominence as a champion of several national and international causes, including climate protection, immigration reform, restorative criminal justice, LGBT rights, and an end to the "war on drugs". Before and after the invasion by the U.S. of Iraq in 2003, Anderson was a leading opponent of the invasion and occupation of Iraq and related human rights abuses. Anderson was the only mayor of a major U.S. city who advocated for the impeachment of President George W. Bush, which he did in many venues throughout the United States. Anderson's work and advocacy led to local, national, and international recognition in numerous spheres, including being named by Business Week as one of the top twenty activists in the world on climate change,serving on the Newsweek Global Environmental Leadership Advisory Board, and being recognized by the Human Rights Campaign as one of the top ten straight advocates in the United States for LGBT equality. He has also received numerous awards for his work, including the EPA Climate Protection Award, the Sierra Club Distinguished Service Award, the Respect the Earth Planet Defender Award, the National Association of Hispanic Publications Presidential Award, The Drug Policy Alliance Richard J. Dennis Drugpeace Award, the Progressive Democrats of America Spine Award, the League of United Latin American Citizens Profile in Courage Award, the Bill of Rights Defense Committee Patriot Award, the Code Pink (Salt Lake City) Pink Star honor, the Morehouse University Gandhi, King, Ikeda Award, and the World Leadership Award for environmental programs. Formerly a member of the Democratic Party, Anderson expressed his disappointment with that Party in 2011, stating, “The Constitution has been eviscerated while Democrats have stood by with nary a whimper. It is a gutless, unprincipled party, bought and paid for by the same interests that buy and pay for the Republican Party." Anderson announced his intention to run for President in 2012 as a candidate for the newly-formed Justice Party. Although founded by Rocky Anderson of Utah, the Justice Party was first recognized by Mississippi and describes itself as advocating economic justice through measures such as green jobs and a right to organize, environment justice through enforcing employee safeguards in trade agreements, and social and civic justice through universal health care. In its first press release, the Utah Justice Party set forth its goals for justice in the economic, environmental, social and civic realms, along with a call to rid the corrupting influence of big money from government, to reverse the erosion of rights guaranteed by the Constitution, and to stop draining American resources to support illegal wars of aggression. Its press release says its grassroots supporters believe that now is the time for all to "shed their skeptical view that their voices don't matter", that "our 2-party system is a 'duopoly' controlled by the same corporate and military interests", and that the people must act to ensure "that our nation will achieve a brighter, sustainable future.” Anderson has ballot access in CO, CT, FL, ID, LA, MI, MN, MS, NJ, NM, OR, RI, TN, UT, VT, WA (152 electoral votes) and has write-in access in AL, AK, DE, GA, IL, IO, KS, MD, MO, NE, NH, NY, PA, TX Learn more about Rocky Anderson and Justice Party on Wikipedia.

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  • Congratulations Nick Colebourn - Microsoft Certified Master

    - by Christian
    Congratulations to Nick Colebourn who was brave enough to take his MCM lab exam in Seattle during PASS last month (at very short notice!) and is now a Microsoft Certified Master in SQL Server! Nick’s momentous achievement is especially exciting for us as he’s now the 5th member of our team to achieve Microsoft’s highest technical qualification for SQL Server – Coeo now has more SQL Server MCM’s than any other Microsoft customer or partner in the WORLD! Thank you Nick, and congratulations; it’s well deserved and we’re all very proud of you!   Christian Bolton - MCA, MCM, MVP Technical Director http://coeo.com - SQL Server Consulting & Managed Services You can read more about the Certified Master program on Microsoft’s website here: http://bit.ly/aOFLxm

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  • Is Nick Clegg a man or a mouse?

    - by BizTalk Visionary
    Well we got the hung election so many of us wanted! I believe it really is time for electoral change. Why? Consider: the ConMen under Cameroon have polled 36% of the great British voting public – well those that got to vote!! That means 64% of us don’t want him as PM. So what gives him the right to govern? Well an ancient voting system ideal for two party politics. But for the last 30 years we’ve had multi-party politics and going forward we may see 4 or 5 parties stepping up. We have to set in place a system that makes this work! So what does that mean today: Nick has a golden chance to push forward the case and in fact the absolute right for the change. He needs to keep this in mind when he discusses coalition with both Labour and the ConMen. So the mouse approach: Decides it is only fair to side with the ‘biggest’ vote and team up with the ConMen. Chances of electoral change? Big fat zero. Chance of achieving any of his other targets. Big fat zero. Why? Simple (as the Meer Kat would say). Cameroon needs to become PM by hook or crook. Once PM he holds the whip hand. Labour will dump Brown and head off into Leadership race land, Clegg will be knocking on number 10, having meaningless meetings and seeing no reward. Finally while Labour is at 6‘s and 7’s  the ‘new’ PM will call a new election, gain the majority they need and dump luckless Nick!! So the man approach: Team up with Labour. As one of the conditions – Brown to go. Run referendum for PR. Get PR through then force Labour to have new election under PR. Nick now hero and should be in a much better place following a PR election!! The man bit is standing up to the media attack for supporting Labour. Come Nick – be a man for a better Britain!!

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  • Is Nick Clegg a man or a mouse?

    - by BizTalk Visionary
    Well we got the hung election so many of us wanted! I believe it really is time for electoral change. Why? Consider: the ConMen under Cameroon have polled 36% of the great British voting public – well those that got to vote!! That means 64% of us don’t want him as PM. So what gives him the right to govern? Well an ancient voting system ideal for two party politics. But for the last 30 years we’ve had multi-party politics and going forward we may see 4 or 5 parties stepping up. We have to set in place a system that makes this work! So what does that mean today: Nick has a golden chance to push forward the case and in fact the absolute right for the change. He needs to keep this in mind when he discusses coalition with both Labour and the ConMen. So the mouse approach: Decides it is only fair to side with the ‘biggest’ vote and team up with the ConMen. Chances of electoral change? Big fat zero. Chance of achieving any of his other targets. Big fat zero. Why? Simple (as the Meer Kat would say). Cameroon needs to become PM by hook or crook. Once PM he holds the whip hand. Labour will dump Brown and head off into Leadership race land, Glegg will be knocking on number 10, having meaningless meetings and seeing no reward. Finally while Labour is at 6‘s and 7’s  the ‘new’ PM will call a new election, gain the majority they need and dump luckless Nick!! So the man approach: Team up with Labour. As one of the conditions – Brown to go. Run referendum for PR. Get PR through then force Labour to have new election under PR. Nick now hero and should be in a much better place following a PR election!! The man bit is standing up to the media attack for supporting Labour. Come Nick – be a man for a better Britain!!

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  • 50 Years of LEDs: An Interview with Inventor Nick Holonyak [Video]

    - by Jason Fitzpatrick
    The man who powered on the first LED half a century ago is still around to talk about it; read on to watch an interview with LED inventor Nick Holonyak. The most fascinating thing about Holonyak’s journey to the invention of the LED was that he started off trying to build a laser and ended up inventing a super efficient light source: Holonyak got his PhD in 1954. In 1957, after a year at Bell Labs and a two year stint in the Army, he joined GE’s research lab in Syracuse, New York. GE was already exploring semiconductor applications and building the forerunners of modern diodes called thyristors and rectifiers. At a GE lab in Schenectady, the scientist Robert Hall was trying to build the first diode laser. Hall, Holonyak and others noticed that semiconductors emit radiation, including visible light, when electricity flows through them. Holonyak and Hall were trying to “turn them on,” and channel, focus and multiply the light. Hall was the first to succeed. He built the world’s first semiconductor laser. Without it, there would be no CD and DVD players today. “Nobody knew how to turn the semiconductor into the laser,” Holonyak says. “We arrived at the answer before anyone else.” But Hall’s laser emitted only invisible, infrared light. Holonyak spent more time in his lab, testing, cutting and polishing his hand-made semiconducting alloys. In the fall of 1962, he got first light. “People thought that alloys were rough and turgid and lumpy,” he says. “We knew damn well what happened and that we had a very powerful way of converting electrical current directly into light. We had the ultimate lamp.” How To Get a Better Wireless Signal and Reduce Wireless Network Interference How To Troubleshoot Internet Connection Problems 7 Ways To Free Up Hard Disk Space On Windows

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  • Why isn't this driver install working (sudo code)?

    - by Nick
    I have a soundcard that I'd like to use and I've been trying to install it and being a new Ubuntu user, I get about half way through this in the Terminal and it stops cooperating with me... See the link (soundcard hyperlink) but basically what I have here: I do the following and it works: sudo apt-get install subversion svn co https://line6linux.svn.sourceforge.net/svnroot/line6linux Change to the directory cd line6linux/driver/trunk Time to build from the source but first make sure you have the latest build and headers sudo apt-get install build-essential sudo apt-get install linux-headers Then after this point it says must specify file to install. Not sure how to do this or what it means. Then, running make gives the following output: ./set_revision.sh ./set_revision.sh: 9: test: https://line6linux.svn.sourceforge.net/svnroot/line6linux/driver/trunk: unexpected operator make -C /lib/modules/3.2.0-29-generic-pae/build CONFIG_LINE6_USB=m SUBDIRS=/home/nick/line6linux/driver/trunk modules make[1]: Entering directory /usr/src/linux-headers-3.2.0-29-generic-pae' CC [M] /home/nick/line6linux/driver/trunk/audio.o /home/nick/line6linux/driver/trunk/audio.c: In function ‘line6_init_audio’: /home/nick/line6linux/driver/trunk/audio.c:30:57: error: ‘THIS_MODULE’ undeclared (first use in this function) /home/nick/line6linux/driver/trunk/audio.c:30:57: note: each undeclared identifier is reported only once for each function it appears in make[2]: * [/home/nick/line6linux/driver/trunk/audio.o] Error 1 make[1]: * [module/home/nick/line6linux/driver/trunk] Error 2 make[1]: Leaving directory/usr/src/linux-headers-3.2.0-29-generic-pae' make: * [default] Error 2 This is in Ubuntu 12.04.1 LTS Another thing, semi related. Cut, copy, paste? Seems like it's different from program to program. I was in the terminal and hit Ctrl-C and then Ctrl-Shift-V in Firefox and it won't paste. But in terminal it will paste. I'm confused. Here is what it's giving me after I hit "Make": nick@NickUbuntu:~/line6linux/driver/trunk$ make ./set_revision.sh ./set_revision.sh: 9: test: https://line6linux.svn.sourceforge.net/svnroot/line6linux/driver/trunk: unexpected operator make -C /lib/modules/3.2.0-29-generic-pae/build CONFIG_LINE6_USB=m SUBDIRS=/home/nick/line6linux/driver/trunk modules make[1]: Entering directory /usr/src/linux-headers-3.2.0-29-generic-pae' CC [M] /home/nick/line6linux/driver/trunk/audio.o /home/nick/line6linux/driver/trunk/audio.c: In function ‘line6_init_audio’: /home/nick/line6linux/driver/trunk/audio.c:30:57: error: ‘THIS_MODULE’ undeclared (first use in this function) /home/nick/line6linux/driver/trunk/audio.c:30:57: note: each undeclared identifier is reported only once for each function it appears in make[2]: *** [/home/nick/line6linux/driver/trunk/audio.o] Error 1 make[1]: *** [_module_/home/nick/line6linux/driver/trunk] Error 2 make[1]: Leaving directory/usr/src/linux-headers-3.2.0-29-generic-pae' make: * [default] Error 2 Looks like these folks also had similar problems: http://ubuntuforums.org/showthread.php?t=1163608&page=3

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  • Accessing the same service more than twice in the nick of time

    - by PointedC
    I have an application that will access interface service A which is to run from windows startup. This service is used by program B and my application functions on B's presence after getting a pointer to A. The scenario is translated as follows, public interface A{} ///my program public class MyProgram { public MyProgram() { ProgramB.DoA(); } public A GetA(){} } public class ProgramB { void DoA(){} } The translated source is not true, but that seems to be what I am looking for. In order to eliminate the overhead of allocating and realocating dynamic accesses to the same service used by other processes, would you please provide an actual solution to the problem ?(I am all out of any idea now)

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  • How to get the Jabber ID for a Multi User Chat nick

    - by Kutzi
    I'm trying to get the Jabber ID for a nick in a multi user chat, but the following code returns only null: class JabberMUCMessageListenerAdapter implements PacketListener { private final MultiUserChat muc; public JabberMUCMessageListenerAdapter(MultiUserChat muc) { this.muc = muc; } @Override public void processPacket(Packet p) { if (p instanceof Message) { final Message msg = (Message) p; String jid = muc.getOccupant(msg.getFrom()).getJid(); // returns null ... } } } Does anyone know, what I'm doing wrong?

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  • storing and retrieving socket

    - by Trevor Newhook
    From what I can understand, once I create a socket, I can then create an array to store it with userArray[socket.nickname]=socket; I can then send a message to it with: io.sockets.socket(userArray[data.to]).emit('private message', tstamp(), socket.nickname, message); The basic logic is to store a copy of each socket in an object, identified by nickname. When I want to send a message to that socket, I use the copy of the socket, and send the message via io.sockets.socket(id).emit(). The entire server code is below: io.sockets.on('connection', function (socket) { socket.on('user message', function (msg) { socket.broadcast.emit('user message', tstamp(), socket.nickname, msg); updateLog('user message', socket.nickname, msg); }); socket.on('private message', function(data) { socket.get(data.nickname, function (err, name) { console.log('Chat message by ', name); }); updateLog('private message', socket.nickname, data.message); message=data.message; io.sockets.socket(userArray[data.to]).emit('private message', tstamp(), socket.nickname, message); }); socket.on('get log', function () { updateLog(); // Ensure old entries are cleared out before sending it. io.sockets.emit('chat log', log); }); socket.on('nickname', function (nick, fn) { var i = 1; var orignick = nick; while (nicknames[nick]) { nick = orignick+i; i++; } fn(nick); nicknames[nick] = socket.nickname = nick; userArray[socket.nickname]=socket; socket.set('nickname', nick, function () { socket.emit('ready'); }); socket.broadcast.emit('announcement', nick + ' connected'); // io.sockets.socket(userArray[nick]).emit('newID', 'Your name is: ' + nick, '. Your ID is: '+ userArray[nick]); io.sockets.emit('nicknames', nicknames); });

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  • Linux Unable to Write to Directory Despite Permissions

    - by Nick Q.
    I'm trying to give myself permissions to /var/www/ however for some reason I am unable to do so. Currently what I'm facing is this: nick@server1:/var$ ls -l drwxrwxr-x 5 root wwwusers 232 Mar 15 19:31 www nick@server1:/var$ groups nick wwwusers nick@server1:/var$ mkdir www/trying mkdir: cannot create directory `www/trying': Permission denied I am running Ubuntu 10.04 LTS on a VPS and am used to running unix on my own machine so I may be doing something absolutely stupid, but I would like to be able to have the group wwwusers be able to write to www.

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  • Linux Unable to Write to Directory Despite Permissions

    - by Nick Q.
    I'm trying to give myself permissions to /var/www/ however for some reason I am unable to do so. Currently what I'm facing is this: nick@server1:/var$ ls -l drwxrwxr-x 5 root wwwusers 232 Mar 15 19:31 www nick@server1:/var$ groups nick wwwusers nick@server1:/var$ mkdir www/trying mkdir: cannot create directory `www/trying': Permission denied I am running Ubuntu 10.04 LTS on a VPS and am used to running unix on my own machine so I may be doing something absolutely stupid, but I would like to be able to have the group wwwusers be able to write to www.

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  • Still confused about JavaScript's 'this'.

    - by Nick Lowman
    I've been reading through quite a few articles on the 'this' keyword when using JavaScript objects and I'm still somewhat confused. I'm quite happy writing object orientated Javascript and I get around the 'this' issue by referring the full object path but I don't like the fact I still find 'this' confusing. I found a good answer here which helped me but I'm still not 100% sure. So, onto the example. The following script is linked from test.html with <script src="js/test.js"></script> if (!nick) { var nick = {}; } nick.lowman = function(){ var helloA = 'Hello A'; console.log('1.',this, this.helloA); var init = function(){ var helloB = 'Hello B'; console.log('2.',this, this.helloB); } return { init: init } }(); nick.lowman.init(); What kind of expected to see was 1. Object {} nick.lowman, 'Hello A' 2. Object {} init, 'Hello B' But what I get is this? 1. Window test.html, undefined 2. Object {} init, undefined I think I understand some of what's happening there but I would mind if someone out there explains it to me. Also, I'm not entirely sure why the first 'console.log' is being called at all? If I remove the call to the init function //nick.lowman.init() firebug still outputs 1. Window test.html, undefined. Why is that? Why does nick.lowman() get called by the window object when the html page loads? Many thanks

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  • Can the public ssh key from my local machine be used to access two different users on a remote serve

    - by Nick
    I have an new ubuntu (hardy 8.04) server, it has two users, User1 and User2. User1 is listed in sudoers. I appended my public ssh key (my local machine's public key local/Users/nick/.ssh/id_rsa.pub) to authorized_keys in remote_server/home/user1/.ssh/authorized_keys, changed the permissions on user1/.ssh/ to 700 and user1/.ssh/authorized_keys to 600 and both file and folder are owned my User1. Then added I User1 to sshd_config (AllowUsers User1). This works and I can login into User1 debug1: Offering public key: /Users/nick/.ssh/id_rsa debug1: Server accepts key: pkalg ssh-rsa blen 277 debug1: Authentication succeeded (publickey). debug1: channel 0: new [client-session] debug1: Entering interactive session. Last login: Mon Mar 15 09:51:01 2010 from ..*.* I then copied the authorized_keys file remote_server/home/user1/.ssh/authorized_keys to remote_server/home/user2/.shh/authorized_keys and changed the permissions and ownership and added User2 to AllowUsers in sshd_config (AllowUsers User1 User2). Now when I try to login to User2 it will not authenticate the same public key. debug1: Offering public key: /Users/nick/.ssh/id_rsa debug1: Authentications that can continue: publickey debug1: Trying private key: /Users/nick/.ssh/identity debug1: Trying private key: /Users/nick/.ssh/id_dsa debug1: No more authentication methods to try. Permission denied (publickey). Am I missing something fundamental about the way ssh works? Thanks in advance, Nick

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  • In a SQL GROUP BY query, what value is used for the non-aggregate columns?

    - by Queencity13
    Say I've got the following data back from a SQL query: Lastname Firstname Age Anderson Jane 28 Anderson Lisa 22 Anderson Jack 37 If I want to know the age of the oldest person with the last name Anderson, I can select MAX(Age) and GROUP BY Lastname. But I also want to know the first name of that oldest person. How can I make sure that, when the Firstname values are collapsed into one row by the GROUP BY, I get the Firstname value from the same row where I got the max age?

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  • How LINQ to Object statements work

    - by rajbk
    This post goes into detail as to now LINQ statements work when querying a collection of objects. This topic assumes you have an understanding of how generics, delegates, implicitly typed variables, lambda expressions, object/collection initializers, extension methods and the yield statement work. I would also recommend you read my previous two posts: Using Delegates in C# Part 1 Using Delegates in C# Part 2 We will start by writing some methods to filter a collection of data. Assume we have an Employee class like so: 1: public class Employee { 2: public int ID { get; set;} 3: public string FirstName { get; set;} 4: public string LastName {get; set;} 5: public string Country { get; set; } 6: } and a collection of employees like so: 1: var employees = new List<Employee> { 2: new Employee { ID = 1, FirstName = "John", LastName = "Wright", Country = "USA" }, 3: new Employee { ID = 2, FirstName = "Jim", LastName = "Ashlock", Country = "UK" }, 4: new Employee { ID = 3, FirstName = "Jane", LastName = "Jackson", Country = "CHE" }, 5: new Employee { ID = 4, FirstName = "Jill", LastName = "Anderson", Country = "AUS" }, 6: }; Filtering We wish to  find all employees that have an even ID. We could start off by writing a method that takes in a list of employees and returns a filtered list of employees with an even ID. 1: static List<Employee> GetEmployeesWithEvenID(List<Employee> employees) { 2: var filteredEmployees = new List<Employee>(); 3: foreach (Employee emp in employees) { 4: if (emp.ID % 2 == 0) { 5: filteredEmployees.Add(emp); 6: } 7: } 8: return filteredEmployees; 9: } The method can be rewritten to return an IEnumerable<Employee> using the yield return keyword. 1: static IEnumerable<Employee> GetEmployeesWithEvenID(IEnumerable<Employee> employees) { 2: foreach (Employee emp in employees) { 3: if (emp.ID % 2 == 0) { 4: yield return emp; 5: } 6: } 7: } We put these together in a console application. 1: using System; 2: using System.Collections.Generic; 3: //No System.Linq 4:  5: public class Program 6: { 7: [STAThread] 8: static void Main(string[] args) 9: { 10: var employees = new List<Employee> { 11: new Employee { ID = 1, FirstName = "John", LastName = "Wright", Country = "USA" }, 12: new Employee { ID = 2, FirstName = "Jim", LastName = "Ashlock", Country = "UK" }, 13: new Employee { ID = 3, FirstName = "Jane", LastName = "Jackson", Country = "CHE" }, 14: new Employee { ID = 4, FirstName = "Jill", LastName = "Anderson", Country = "AUS" }, 15: }; 16: var filteredEmployees = GetEmployeesWithEvenID(employees); 17:  18: foreach (Employee emp in filteredEmployees) { 19: Console.WriteLine("ID {0} First_Name {1} Last_Name {2} Country {3}", 20: emp.ID, emp.FirstName, emp.LastName, emp.Country); 21: } 22:  23: Console.ReadLine(); 24: } 25: 26: static IEnumerable<Employee> GetEmployeesWithEvenID(IEnumerable<Employee> employees) { 27: foreach (Employee emp in employees) { 28: if (emp.ID % 2 == 0) { 29: yield return emp; 30: } 31: } 32: } 33: } 34:  35: public class Employee { 36: public int ID { get; set;} 37: public string FirstName { get; set;} 38: public string LastName {get; set;} 39: public string Country { get; set; } 40: } Output: ID 2 First_Name Jim Last_Name Ashlock Country UK ID 4 First_Name Jill Last_Name Anderson Country AUS Our filtering method is too specific. Let us change it so that it is capable of doing different types of filtering and lets give our method the name Where ;-) We will add another parameter to our Where method. This additional parameter will be a delegate with the following declaration. public delegate bool Filter(Employee emp); The idea is that the delegate parameter in our Where method will point to a method that contains the logic to do our filtering thereby freeing our Where method from any dependency. The method is shown below: 1: static IEnumerable<Employee> Where(IEnumerable<Employee> employees, Filter filter) { 2: foreach (Employee emp in employees) { 3: if (filter(emp)) { 4: yield return emp; 5: } 6: } 7: } Making the change to our app, we create a new instance of the Filter delegate on line 14 with a target set to the method EmployeeHasEvenId. Running the code will produce the same output. 1: public delegate bool Filter(Employee emp); 2:  3: public class Program 4: { 5: [STAThread] 6: static void Main(string[] args) 7: { 8: var employees = new List<Employee> { 9: new Employee { ID = 1, FirstName = "John", LastName = "Wright", Country = "USA" }, 10: new Employee { ID = 2, FirstName = "Jim", LastName = "Ashlock", Country = "UK" }, 11: new Employee { ID = 3, FirstName = "Jane", LastName = "Jackson", Country = "CHE" }, 12: new Employee { ID = 4, FirstName = "Jill", LastName = "Anderson", Country = "AUS" } 13: }; 14: var filterDelegate = new Filter(EmployeeHasEvenId); 15: var filteredEmployees = Where(employees, filterDelegate); 16:  17: foreach (Employee emp in filteredEmployees) { 18: Console.WriteLine("ID {0} First_Name {1} Last_Name {2} Country {3}", 19: emp.ID, emp.FirstName, emp.LastName, emp.Country); 20: } 21: Console.ReadLine(); 22: } 23: 24: static bool EmployeeHasEvenId(Employee emp) { 25: return emp.ID % 2 == 0; 26: } 27: 28: static IEnumerable<Employee> Where(IEnumerable<Employee> employees, Filter filter) { 29: foreach (Employee emp in employees) { 30: if (filter(emp)) { 31: yield return emp; 32: } 33: } 34: } 35: } 36:  37: public class Employee { 38: public int ID { get; set;} 39: public string FirstName { get; set;} 40: public string LastName {get; set;} 41: public string Country { get; set; } 42: } Lets use lambda expressions to inline the contents of the EmployeeHasEvenId method in place of the method. The next code snippet shows this change (see line 15).  For brevity, the Employee class declaration has been skipped. 1: public delegate bool Filter(Employee emp); 2:  3: public class Program 4: { 5: [STAThread] 6: static void Main(string[] args) 7: { 8: var employees = new List<Employee> { 9: new Employee { ID = 1, FirstName = "John", LastName = "Wright", Country = "USA" }, 10: new Employee { ID = 2, FirstName = "Jim", LastName = "Ashlock", Country = "UK" }, 11: new Employee { ID = 3, FirstName = "Jane", LastName = "Jackson", Country = "CHE" }, 12: new Employee { ID = 4, FirstName = "Jill", LastName = "Anderson", Country = "AUS" } 13: }; 14: var filterDelegate = new Filter(EmployeeHasEvenId); 15: var filteredEmployees = Where(employees, emp => emp.ID % 2 == 0); 16:  17: foreach (Employee emp in filteredEmployees) { 18: Console.WriteLine("ID {0} First_Name {1} Last_Name {2} Country {3}", 19: emp.ID, emp.FirstName, emp.LastName, emp.Country); 20: } 21: Console.ReadLine(); 22: } 23: 24: static bool EmployeeHasEvenId(Employee emp) { 25: return emp.ID % 2 == 0; 26: } 27: 28: static IEnumerable<Employee> Where(IEnumerable<Employee> employees, Filter filter) { 29: foreach (Employee emp in employees) { 30: if (filter(emp)) { 31: yield return emp; 32: } 33: } 34: } 35: } 36:  The output displays the same two employees.  Our Where method is too restricted since it works with a collection of Employees only. Lets change it so that it works with any IEnumerable<T>. In addition, you may recall from my previous post,  that .NET 3.5 comes with a lot of predefined delegates including public delegate TResult Func<T, TResult>(T arg); We will get rid of our Filter delegate and use the one above instead. We apply these two changes to our code. 1: public class Program 2: { 3: [STAThread] 4: static void Main(string[] args) 5: { 6: var employees = new List<Employee> { 7: new Employee { ID = 1, FirstName = "John", LastName = "Wright", Country = "USA" }, 8: new Employee { ID = 2, FirstName = "Jim", LastName = "Ashlock", Country = "UK" }, 9: new Employee { ID = 3, FirstName = "Jane", LastName = "Jackson", Country = "CHE" }, 10: new Employee { ID = 4, FirstName = "Jill", LastName = "Anderson", Country = "AUS" } 11: }; 12:  13: var filteredEmployees = Where(employees, emp => emp.ID % 2 == 0); 14:  15: foreach (Employee emp in filteredEmployees) { 16: Console.WriteLine("ID {0} First_Name {1} Last_Name {2} Country {3}", 17: emp.ID, emp.FirstName, emp.LastName, emp.Country); 18: } 19: Console.ReadLine(); 20: } 21: 22: static IEnumerable<T> Where<T>(IEnumerable<T> source, Func<T, bool> filter) { 23: foreach (var x in source) { 24: if (filter(x)) { 25: yield return x; 26: } 27: } 28: } 29: } We have successfully implemented a way to filter any IEnumerable<T> based on a  filter criteria. Projection Now lets enumerate on the items in the IEnumerable<Employee> we got from the Where method and copy them into a new IEnumerable<EmployeeFormatted>. The EmployeeFormatted class will only have a FullName and ID property. 1: public class EmployeeFormatted { 2: public int ID { get; set; } 3: public string FullName {get; set;} 4: } We could “project” our existing IEnumerable<Employee> into a new collection of IEnumerable<EmployeeFormatted> with the help of a new method. We will call this method Select ;-) 1: static IEnumerable<EmployeeFormatted> Select(IEnumerable<Employee> employees) { 2: foreach (var emp in employees) { 3: yield return new EmployeeFormatted { 4: ID = emp.ID, 5: FullName = emp.LastName + ", " + emp.FirstName 6: }; 7: } 8: } The changes are applied to our app. 1: public class Program 2: { 3: [STAThread] 4: static void Main(string[] args) 5: { 6: var employees = new List<Employee> { 7: new Employee { ID = 1, FirstName = "John", LastName = "Wright", Country = "USA" }, 8: new Employee { ID = 2, FirstName = "Jim", LastName = "Ashlock", Country = "UK" }, 9: new Employee { ID = 3, FirstName = "Jane", LastName = "Jackson", Country = "CHE" }, 10: new Employee { ID = 4, FirstName = "Jill", LastName = "Anderson", Country = "AUS" } 11: }; 12:  13: var filteredEmployees = Where(employees, emp => emp.ID % 2 == 0); 14: var formattedEmployees = Select(filteredEmployees); 15:  16: foreach (EmployeeFormatted emp in formattedEmployees) { 17: Console.WriteLine("ID {0} Full_Name {1}", 18: emp.ID, emp.FullName); 19: } 20: Console.ReadLine(); 21: } 22:  23: static IEnumerable<T> Where<T>(IEnumerable<T> source, Func<T, bool> filter) { 24: foreach (var x in source) { 25: if (filter(x)) { 26: yield return x; 27: } 28: } 29: } 30: 31: static IEnumerable<EmployeeFormatted> Select(IEnumerable<Employee> employees) { 32: foreach (var emp in employees) { 33: yield return new EmployeeFormatted { 34: ID = emp.ID, 35: FullName = emp.LastName + ", " + emp.FirstName 36: }; 37: } 38: } 39: } 40:  41: public class Employee { 42: public int ID { get; set;} 43: public string FirstName { get; set;} 44: public string LastName {get; set;} 45: public string Country { get; set; } 46: } 47:  48: public class EmployeeFormatted { 49: public int ID { get; set; } 50: public string FullName {get; set;} 51: } Output: ID 2 Full_Name Ashlock, Jim ID 4 Full_Name Anderson, Jill We have successfully selected employees who have an even ID and then shaped our data with the help of the Select method so that the final result is an IEnumerable<EmployeeFormatted>.  Lets make our Select method more generic so that the user is given the freedom to shape what the output would look like. We can do this, like before, with lambda expressions. Our Select method is changed to accept a delegate as shown below. TSource will be the type of data that comes in and TResult will be the type the user chooses (shape of data) as returned from the selector delegate. 1:  2: static IEnumerable<TResult> Select<TSource, TResult>(IEnumerable<TSource> source, Func<TSource, TResult> selector) { 3: foreach (var x in source) { 4: yield return selector(x); 5: } 6: } We see the new changes to our app. On line 15, we use lambda expression to specify the shape of the data. In this case the shape will be of type EmployeeFormatted. 1:  2: public class Program 3: { 4: [STAThread] 5: static void Main(string[] args) 6: { 7: var employees = new List<Employee> { 8: new Employee { ID = 1, FirstName = "John", LastName = "Wright", Country = "USA" }, 9: new Employee { ID = 2, FirstName = "Jim", LastName = "Ashlock", Country = "UK" }, 10: new Employee { ID = 3, FirstName = "Jane", LastName = "Jackson", Country = "CHE" }, 11: new Employee { ID = 4, FirstName = "Jill", LastName = "Anderson", Country = "AUS" } 12: }; 13:  14: var filteredEmployees = Where(employees, emp => emp.ID % 2 == 0); 15: var formattedEmployees = Select(filteredEmployees, (emp) => 16: new EmployeeFormatted { 17: ID = emp.ID, 18: FullName = emp.LastName + ", " + emp.FirstName 19: }); 20:  21: foreach (EmployeeFormatted emp in formattedEmployees) { 22: Console.WriteLine("ID {0} Full_Name {1}", 23: emp.ID, emp.FullName); 24: } 25: Console.ReadLine(); 26: } 27: 28: static IEnumerable<T> Where<T>(IEnumerable<T> source, Func<T, bool> filter) { 29: foreach (var x in source) { 30: if (filter(x)) { 31: yield return x; 32: } 33: } 34: } 35: 36: static IEnumerable<TResult> Select<TSource, TResult>(IEnumerable<TSource> source, Func<TSource, TResult> selector) { 37: foreach (var x in source) { 38: yield return selector(x); 39: } 40: } 41: } The code outputs the same result as before. On line 14 we filter our data and on line 15 we project our data. What if we wanted to be more expressive and concise? We could combine both line 14 and 15 into one line as shown below. Assuming you had to perform several operations like this on our collection, you would end up with some very unreadable code! 1: var formattedEmployees = Select(Where(employees, emp => emp.ID % 2 == 0), (emp) => 2: new EmployeeFormatted { 3: ID = emp.ID, 4: FullName = emp.LastName + ", " + emp.FirstName 5: }); A cleaner way to write this would be to give the appearance that the Select and Where methods were part of the IEnumerable<T>. This is exactly what extension methods give us. Extension methods have to be defined in a static class. Let us make the Select and Where extension methods on IEnumerable<T> 1: public static class MyExtensionMethods { 2: static IEnumerable<T> Where<T>(this IEnumerable<T> source, Func<T, bool> filter) { 3: foreach (var x in source) { 4: if (filter(x)) { 5: yield return x; 6: } 7: } 8: } 9: 10: static IEnumerable<TResult> Select<TSource, TResult>(this IEnumerable<TSource> source, Func<TSource, TResult> selector) { 11: foreach (var x in source) { 12: yield return selector(x); 13: } 14: } 15: } The creation of the extension method makes the syntax much cleaner as shown below. We can write as many extension methods as we want and keep on chaining them using this technique. 1: var formattedEmployees = employees 2: .Where(emp => emp.ID % 2 == 0) 3: .Select (emp => new EmployeeFormatted { ID = emp.ID, FullName = emp.LastName + ", " + emp.FirstName }); Making these changes and running our code produces the same result. 1: using System; 2: using System.Collections.Generic; 3:  4: public class Program 5: { 6: [STAThread] 7: static void Main(string[] args) 8: { 9: var employees = new List<Employee> { 10: new Employee { ID = 1, FirstName = "John", LastName = "Wright", Country = "USA" }, 11: new Employee { ID = 2, FirstName = "Jim", LastName = "Ashlock", Country = "UK" }, 12: new Employee { ID = 3, FirstName = "Jane", LastName = "Jackson", Country = "CHE" }, 13: new Employee { ID = 4, FirstName = "Jill", LastName = "Anderson", Country = "AUS" } 14: }; 15:  16: var formattedEmployees = employees 17: .Where(emp => emp.ID % 2 == 0) 18: .Select (emp => 19: new EmployeeFormatted { 20: ID = emp.ID, 21: FullName = emp.LastName + ", " + emp.FirstName 22: } 23: ); 24:  25: foreach (EmployeeFormatted emp in formattedEmployees) { 26: Console.WriteLine("ID {0} Full_Name {1}", 27: emp.ID, emp.FullName); 28: } 29: Console.ReadLine(); 30: } 31: } 32:  33: public static class MyExtensionMethods { 34: static IEnumerable<T> Where<T>(this IEnumerable<T> source, Func<T, bool> filter) { 35: foreach (var x in source) { 36: if (filter(x)) { 37: yield return x; 38: } 39: } 40: } 41: 42: static IEnumerable<TResult> Select<TSource, TResult>(this IEnumerable<TSource> source, Func<TSource, TResult> selector) { 43: foreach (var x in source) { 44: yield return selector(x); 45: } 46: } 47: } 48:  49: public class Employee { 50: public int ID { get; set;} 51: public string FirstName { get; set;} 52: public string LastName {get; set;} 53: public string Country { get; set; } 54: } 55:  56: public class EmployeeFormatted { 57: public int ID { get; set; } 58: public string FullName {get; set;} 59: } Let’s change our code to return a collection of anonymous types and get rid of the EmployeeFormatted type. We see that the code produces the same output. 1: using System; 2: using System.Collections.Generic; 3:  4: public class Program 5: { 6: [STAThread] 7: static void Main(string[] args) 8: { 9: var employees = new List<Employee> { 10: new Employee { ID = 1, FirstName = "John", LastName = "Wright", Country = "USA" }, 11: new Employee { ID = 2, FirstName = "Jim", LastName = "Ashlock", Country = "UK" }, 12: new Employee { ID = 3, FirstName = "Jane", LastName = "Jackson", Country = "CHE" }, 13: new Employee { ID = 4, FirstName = "Jill", LastName = "Anderson", Country = "AUS" } 14: }; 15:  16: var formattedEmployees = employees 17: .Where(emp => emp.ID % 2 == 0) 18: .Select (emp => 19: new { 20: ID = emp.ID, 21: FullName = emp.LastName + ", " + emp.FirstName 22: } 23: ); 24:  25: foreach (var emp in formattedEmployees) { 26: Console.WriteLine("ID {0} Full_Name {1}", 27: emp.ID, emp.FullName); 28: } 29: Console.ReadLine(); 30: } 31: } 32:  33: public static class MyExtensionMethods { 34: public static IEnumerable<T> Where<T>(this IEnumerable<T> source, Func<T, bool> filter) { 35: foreach (var x in source) { 36: if (filter(x)) { 37: yield return x; 38: } 39: } 40: } 41: 42: public static IEnumerable<TResult> Select<TSource, TResult>(this IEnumerable<TSource> source, Func<TSource, TResult> selector) { 43: foreach (var x in source) { 44: yield return selector(x); 45: } 46: } 47: } 48:  49: public class Employee { 50: public int ID { get; set;} 51: public string FirstName { get; set;} 52: public string LastName {get; set;} 53: public string Country { get; set; } 54: } To be more expressive, C# allows us to write our extension method calls as a query expression. Line 16 can be rewritten a query expression like so: 1: var formattedEmployees = from emp in employees 2: where emp.ID % 2 == 0 3: select new { 4: ID = emp.ID, 5: FullName = emp.LastName + ", " + emp.FirstName 6: }; When the compiler encounters an expression like the above, it simply rewrites it as calls to our extension methods.  So far we have been using our extension methods. The System.Linq namespace contains several extension methods for objects that implement the IEnumerable<T>. You can see a listing of these methods in the Enumerable class in the System.Linq namespace. Let’s get rid of our extension methods (which I purposefully wrote to be of the same signature as the ones in the Enumerable class) and use the ones provided in the Enumerable class. Our final code is shown below: 1: using System; 2: using System.Collections.Generic; 3: using System.Linq; //Added 4:  5: public class Program 6: { 7: [STAThread] 8: static void Main(string[] args) 9: { 10: var employees = new List<Employee> { 11: new Employee { ID = 1, FirstName = "John", LastName = "Wright", Country = "USA" }, 12: new Employee { ID = 2, FirstName = "Jim", LastName = "Ashlock", Country = "UK" }, 13: new Employee { ID = 3, FirstName = "Jane", LastName = "Jackson", Country = "CHE" }, 14: new Employee { ID = 4, FirstName = "Jill", LastName = "Anderson", Country = "AUS" } 15: }; 16:  17: var formattedEmployees = from emp in employees 18: where emp.ID % 2 == 0 19: select new { 20: ID = emp.ID, 21: FullName = emp.LastName + ", " + emp.FirstName 22: }; 23:  24: foreach (var emp in formattedEmployees) { 25: Console.WriteLine("ID {0} Full_Name {1}", 26: emp.ID, emp.FullName); 27: } 28: Console.ReadLine(); 29: } 30: } 31:  32: public class Employee { 33: public int ID { get; set;} 34: public string FirstName { get; set;} 35: public string LastName {get; set;} 36: public string Country { get; set; } 37: } 38:  39: public class EmployeeFormatted { 40: public int ID { get; set; } 41: public string FullName {get; set;} 42: } This post has shown you a basic overview of LINQ to Objects work by showning you how an expression is converted to a sequence of calls to extension methods when working directly with objects. It gets more interesting when working with LINQ to SQL where an expression tree is constructed – an in memory data representation of the expression. The C# compiler compiles these expressions into code that builds an expression tree at runtime. The provider can then traverse the expression tree and generate the appropriate SQL query. You can read more about expression trees in this MSDN article.

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  • Active directory integration not working properly with winbind and samba

    - by tubaguy50035
    I'm trying to get my linux box to use active directory authentication. I believe I have almost everything setup correctly. I'm able to issue wbinfo -g and wbinfo -u and see all the groups and users respectively. Brief intro to my setup: The username I use on my linux box to do admin things is nick. My active directory username is nwalke. They have two different passwords. I am able to log in to the box with nick and that user's password and I'm also able to login as nwalke with nwalke's password. The curious bit: Upon creating the active directory user's home directory, I run a script that requires root access. This is to setup some system wide things like a samba share for them. When I log in as nwalke, I enter my nwalke password and it succeeds. I'm then greeted with [sudo] password for nick:. If I enter my nwalke password here, it says Sorry, try again.. If I enter nick's password, it says Sorry, user nick is not allowed to execute scriptname as root. If I do groups as nwalke, I see that magically my user has been given the group nick. Now, I accidentally thought that nick had a UID of 100, not 1000. So originally in my smb.conf I had idmap uid 1000-10000. The only thing I can think of, is that I logged in with nwalke while that was still set and now I'm just being presented with a UID of 1000 forcing linux to think I'm nick. I'm not really sure where to go from here. Like I said, I'm fairly certain active directory is communicating with my server properly, but something must not be mapped right on the linux side. Any thoughts? Here is my smb.conf: [global] security = ads netbios name = hostname realm = COMPANY.COM password server = adshost.company.com workgroup = COMPANY idmap uid = 10000-90000 idmap gid = 10000-90000 winbind separator = + winbind enum users = no winbind enum groups = no winbind use default domain = yes template homedir = /home/%D/%U template shell = /bin/bash client use spnego = yes domain master = no load printers = no printing = bsd printcap name = /dev/null disable spoolss = yes Let me know if more information about something is required.

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  • It is possible to record a data that have a straight row in mysql based on date or sequence?

    - by user1987816
    I want to get the data that have a straight Sell more than 3 times, it is possible in mysql? If not, how to get it right? I'm need it on mysql or php. my database:- +----------+---------------------+--------+ | Username | Date | Action | +----------+---------------------+--------+ | Adam | 2014-08-20 22:30:20 | Sell | | Adam | 2014-08-20 22:30:20 | Sell | | Adam | 2014-08-20 22:30:20 | Sell | | Adam | 2014-08-20 22:30:20 | Buy | | Adam | 2014-08-20 22:30:20 | Buy | | Adam | 2014-08-20 22:30:20 | Sell | | Adam | 2014-08-20 22:30:20 | Sell | | Adam | 2014-08-20 22:30:20 | Sell | | Adam | 2014-08-20 22:30:20 | Sell | | Nick | 2014-08-20 22:30:20 | Sell | | Nick | 2014-08-20 22:30:20 | Sell | | Nick | 2014-08-20 22:30:20 | Sell | | Nick | 2014-08-20 22:30:20 | Sell | | Nick | 2014-08-20 22:30:20 | Buy | +----------+---------------------+--------+ From the table above, I need to list out all data that have a straight sell more then 3 times. RESULT +----------+---------------------+--------+-------------+ | Username | Date | Action | Straight 3+ | +----------+---------------------+--------+-------------+ | Adam | 2014-08-20 22:30:20 | Sell | 3 | | Adam | 2014-08-20 22:30:20 | Sell | 4 | | Nick | 2014-08-20 22:30:20 | Sell | 4 | +----------+---------------------+--------+-------------+

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  • How properly perform passing operation result to View

    - by atomAltera
    I'm developing web site on self made MVC engine. I have actionController that handles operations like register, login, post submit and etc. actionController receives operation name and parameters. Of course it mast handle errors such user with same nick already exists or password is to short about which action handler have to notify user. The question is which is the best way to organize errors, such that View could easily get localized user notification message. I see two ways First one: define error constants like ERR_NICK_BUSY = '1' ERR_NICK_INVALID = '2' ... and localization map local[ERR_NICK_BUSY] = 'User with the same nick already registered' local[ERR_NICK_INVALID ] = 'Nick, you entered is invalid' ... And second one: define abstract constants like ERR_FIELD_BUSY = '1' ERR_FIELD_INVALID = '2' ... and pass them with field name. In this case localization looks like local['nick_'+ERR_FIELD_BUSY] = 'User with the same nick already registered' ... I don't like both this methods. Can you advise something else?

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  • Using the public ssh key from local machine to access two remote users [closed]

    - by Nick
    I have an new Ubuntu (Hardy 8.04) server; it has two users, Alice and Bob. Alice is listed in sudoers. I appended my public ssh key (my local machine's public key local/Users/nick/.ssh/id_rsa.pub) to authorized_keys in remote_server/home/Alice/.ssh/authorized_keys, changed the permissions on Alice/.ssh/ to 700 and Alice/.ssh/authorized_keys to 600, and both the file and folder are owned my Alice. Then added I Alice to sshd_config (AllowUsers Alice). This works and I can login into Alice: ssh -v [email protected] ... debug1: Offering public key: /Users/nick/.ssh/id_rsa debug1: Server accepts key: pkalg ssh-rsa blen 277 debug1: Authentication succeeded (publickey). debug1: channel 0: new [client-session] debug1: Entering interactive session. Last login: Mon Mar 15 09:51:01 2010 from 123.456.789.00 I then copied the authorized_keys file remote_server/home/Alice/.ssh/authorized_keys to remote_server/home/Bob/.shh/authorized_keys and changed the permissions and ownership and added Bob to AllowUsers in sshd_config (AllowUsers Alice Bob). Now when I try to login to Bob it will not authenticate the same public key. ssh -v [email protected] ... debug1: Offering public key: /Users/nick/.ssh/id_rsa debug1: Authentications that can continue: publickey debug1: Trying private key: /Users/nick/.ssh/identity debug1: Trying private key: /Users/nick/.ssh/id_dsa debug1: No more authentication methods to try. Permission denied (publickey). Am I missing something fundamental about the way ssh works?

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  • Can the same ssh key be used to access two different users on the same server?

    - by Nick
    I have an new ubuntu (hardy 8.04) server, it has two users, User1 and User2. User1 is listed in sudoers. I appended my public ssh key to authorized_keys in /home/user1/.ssh/authorized_keys, changed the permissions on user1/.ssh/ to 700 and user1/.ssh/authorized_keys to 600 and both file and folder are owned my User1. Then added I User1 to sshd_config (AllowUsers User1). This works and I can login into User1 debug1: Offering public key: /Users/nick/.ssh/id_rsa debug1: Server accepts key: pkalg ssh-rsa blen 277 debug1: Authentication succeeded (publickey). debug1: channel 0: new [client-session] debug1: Entering interactive session. Last login: Mon Mar 15 09:51:01 2010 from 86.141.61.197 I then copied the authorized_keys file to /home/user2/.shh/ and changed the permissions and ownership and added User2 to AllowUsers in sshd_config (AllowUsers User1 User2). Now when I try to login to User2 it will not authenticate the same public key. debug1: Offering public key: /Users/nick/.ssh/id_rsa debug1: Authentications that can continue: publickey debug1: Trying private key: /Users/nick/.ssh/identity debug1: Trying private key: /Users/nick/.ssh/id_dsa debug1: No more authentication methods to try. Permission denied (publickey). Am I missing something fundamental about the way ssh works? Thanks in advance, Nick

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  • Postfix rewrite sender: why doesn't this work

    - by Nick Coleman
    I have server A with an IP address only and a dummy FQDN (on the basis all machines should have a FQDN): pants.net.invalid. All mail is relayed through another server elsewhere, which works fine. On server A, Postfix rewrites the sender address with smtp_generic_maps = hash:/etc/postfix/generic. According to the Rewrite manual at http://www.postfix.org/ADDRESS_REWRITING_README.html#remote, this should rewrite all outgoing external mail's Sender address: $ cat /etc/postfix/generic @pants.net.invalid [email protected] but it does not. postmap -q [email protected] returns nothing. This works: [email protected] [email protected] It seems as though it is doing regex matching even though I specify type hash:. Clearly I am misunderstanding the manual. I don't want to use regex or pcre expressions because there are only a couple of users (root and two others) and I don't want the overhead. I can specify the users exactly and it works. But, I would like to know what I am misunderstanding for future reference. Thanks.

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