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  • Python: Open() using a variable

    - by nuustik
    Good day, I've ran into a problem with opening a file with randomly generated name in Python 2.6. import random random = random.randint(1,10) localfile = file("%s","wb") % random Then I get an error message about the last line TypeError: unsupported operand type(s) for %: 'file' and 'int' I just couldn't figure this out by myself nor with Google, but there has to be a cure for this, I believe. Thanks.

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