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  • SQL Server 2005 RIGHT OUTER JOIN not working

    - by CheeseConQueso
    I'm looking up access logs for specific courses. I need to show all the courses even if they don't exist in the logs table. Hence the outer join.... but after trying (presumably) all of the variations of LEFT OUTER, RIGHT OUTER, INNER and placement of the tables within the SQL code, I couldn't get my result. Here's what I am running: SELECT (a.first_name+' '+a.last_name) instructor, c.course_id, COUNT(l.access_date) course_logins, a.logins system_logins, MAX(l.access_date) last_course_login, a.last_login last_system_login FROM lsn_logs l RIGHT OUTER JOIN courses c ON l.course_id = c.course_id, accounts a WHERE l.object_id = 'LOGIN' AND c.course_type = 'COURSE' AND c.course_id NOT LIKE '%TEST%' AND a.account_rights > 2 AND l.user_id = a.username AND ((a.first_name+' '+a.last_name) = c.instructor) GROUP BY c.course_id, a.first_name, a.last_name, a.last_login, a.logins, c.instructor ORDER BY a.last_name, a.first_name, c.course_id, course_logins DESC Is it something in the WHERE clause that's preventing me from getting course_id's that don't exist in lsn_logs? Is it the way I'm joining the tables? Again, in short, I want all course_id's regardless of their existence in lsn_logs.

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  • Joining on a common table, how do you get a FULL OUTER JOIN to expand on another table?

    - by stimpy77
    I've scoured StackOverflow and Google for an answer to this problem. I'm trying to create a Microsot SQL Server 2008 view. Not a stored procedure. Not a function. Just a query (i.e. a view). I have three tables. The first table defines a common key, let's say "CompanyID". The other two tables have a sometimes-common field, let's say "EmployeeName". I want a single table result that, when my WHERE clause says "WHERE CompanyID = 12" looks like this: CompanyID | TableA | TableB 12 | John Doe | John Doe 12 | Betty Sue | NULL 12 | NULL | Billy Bob I've tried a FULL OUTER JOIN that looks like this: SELECT Company.CompanyID, TableA.EmployeeName, TableB.EmployeeName FROM Company FULL OUTER JOIN TableA ON Company.CompanyID = TableA.CompanyID FULL OUTER JOIN TableB ON Company.CompanyID = TableB.CompanyID AND (TableA.EmployeeName IS NULL OR TableB.EmployeeName IS NULL OR TableB.EmployeeName = TableA.EmployeeName) I'm only getting the NULL from one matched table, I'm not getting the expansion for the other table. In the above sample, I'm basically only getting the first and third rows and not the second. Can someone help me create this query and show me how this is done correctly? BTW I already have a stored procedure that looks very clean and populates an in-memory table, but that isn't what I want. Thanks.

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  • Left Outer Join - SQL2005

    - by Dan beadle
    I thought I knew enough SQL, but I am having problem with a left outer join. I have an expense detail record that needs to link to a table by dept and account_code. The query looks something like this: select Detail.Spend, Budget.BudgetAmt from detail left outer join budget on detail.dept = budget.dept AND dept.account_code = budget.account_code This works great as long as there is a record that exactly matches the join conditions. But sometimes, there is no matching budget item. I want to get back the Detail.Spend from the details table with nulls for the budgetAmt. Instead, I don't get this record at all. Isn't Left Outer Join supposed to return the left (detail) table when there is no match? Is there something different when multiple criteria are used as I do here? Thanks

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  • Linq to Entities and LEFT OUTER JOIN issue with MANY:1 relations

    - by Robert Koritnik
    Can somebody tell me, why does Linq to Entities translate many to 1 relationships to left outer join instead of inner join? Because there's referential constraint on DB itself that ensures there's a record in the right table, so inner join should be used instead (and it would work much faster) If relation was many to 0..1 left outer join would be correct. Question Is it possible to write LINQ in a way so it will translate to inner join rather than left outer join. It would speed query execution a lot... I haven't used eSQL before, but would it be wise to use it in instead of LINQ? Edit I updated my tags to include technology I'm using in the background: Entity Framework V1 Devart dotConnect for Mysql MySql database If someone could test if the same is true on Microsoft SQL server it would also give me some insight if this is Devart's issue or it's a general L2EF functionality... But I suspect EF is the culprit here.

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  • C# Outer Apply in LINQ

    - by JeremySpouken
    How can I achieve Outer Apply in LINQ? I'm having a bit of a problem. Here's the SQL Query I'm using. SELECT u.masterID ,u.user ,h.created FROM dbo.Users u OUTER APPLY (SELECT TOP 1 * FROM UserHistory h where h.masterID = u.masterID ORDER BY created DESC) h

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  • Linq to Entities and outer joins issue

    - by Robert Koritnik
    Can somebody tell me, why does Linq to Entities translate many to 1 relationships to left outer joins instead of inner joins? It relation was many to 0..1. There's referential constraint on DB itself, that ensures there's a record in the right table, so inner join should be used instead. Is it possible to write LINQ in a way so they will translate to inner joins rather than left outer joins. It would speed query execution a lot.

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  • LINQ to SQL - Left Outer Join with multiple join conditions

    - by dan
    I have the following SQL which I am trying to translate to LINQ: SELECT f.value FROM period as p LEFT OUTER JOIN facts AS f ON p.id = f.periodid AND f.otherid = 17 WHERE p.companyid = 100 I have seen the typical implementation of the left outer join (ie. into x from y in x.DefaultIfEmpty() etc.) but am unsure how to introduce the other join condition ('AND f.otherid = 17') EDIT Why is the 'AND f.otherid = 17' condition part of the JOIN instead of in the WHERE clause? Because f may not exist for some rows and I still want these rows to be included. If the condition is applied in the WHERE clause, after the JOIN - then I don't get the behaviour I want. Unfortunately this: from p in context.Periods join f in context.Facts on p.id equals f.periodid into fg from fgi in fg.DefaultIfEmpty() where p.companyid == 100 && fgi.otherid == 17 select f.value seems to be equivalent to this: SELECT f.value FROM period as p LEFT OUTER JOIN facts AS f ON p.id = f.periodid WHERE p.companyid = 100 && AND f.otherid = 17 which is not quite what I'm after.

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  • Remove Duplicates from LEFT OUTER JOIN

    - by Kaushik Gopal
    Hey folk my question is quite similar to http://stackoverflow.com/questions/757957/restricting-a-left-join I have a variation in that request though and the comment didn't allow too many characters hence posting as a new question. I hope this doesn't go against the posting rules/etiquette. Assuming i have a table SHOP and another table LOCATION. Location is a sort of child table of table SHOP, that has two columns of interest, one is a Division Key (calling it just KEY) and a "SHOP" number. This matches to the Number "NO" in table SHOP. I tried this left outer join: SELECT S.NO, L.KEY FROM SHOP S LEFT OUTER JOIN LOCATN L ON S.NO = L.SHOP But i'm getting a lot of duplicates since there are many locations that belong to a single shop. I want to eliminate them and just get a list of "shop, key" entries without duplicates. any ideas how? (edit: ORACLE 10g Database)

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  • Full outer join in django

    - by Ber
    How can I create a query for a full outer join across a M2M relationchip using the django QuerySet API? It that is not supported, some hint about creating my own manager to do this would be welcome. Edited to add: @S.Lott: Thanks for the enlightenment. The need for the OUTER JOIN comes from the application. It has to generate a report showing the data entered, even if it still incomplete. I was not aware of the fact that the result would be a new class/model. Your hints will help me quite a bit.

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  • Linq Left Outer Join

    - by Neil
    I am new to LINQ and am trying to convert a SQL query to LINQ: SQL: left outer join PRODUCT_BEST_USE pbu on pbu.PRODUCT_GUID = @uProductId and pbu.BEST_USE_GUID = bu.BEST_USE_GUID LINQ: from PBU in PRODUCT_BEST_USE.Where(PBU=>PBU.PRODUCT_GUID == p.PRODUCT_GUID).DefaultIfEmpty() When I add and PBU.BEST_USE_GUID equals BU.BEST_USE_GUID, I get an error: "A query body must end with a select clause or a group clause" Here is the full Linq query: from p in PRODUCT join BU in BEST_USE on p.CATEGORY_GUID equals BU.CATEGORY_GUID from PBU in PRODUCT_BEST_USE.Where(PBU=>PBU.PRODUCT_GUID == p.PRODUCT_GUID).DefaultIfEmpty() and PBU.BEST_USE_GUID equals BU.BEST_USE_GUID where p.PRODUCT_GUID == new Guid("d317752b-581d-4f43-92fa-4a4af91009f5") select new { BU.NAME, PBU.PRODUCT_BEST_USE_GUID }

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  • outer join for parent child chain

    - by dotnetcoder
    Considering below tables and relationships: parent --1:Many-- children --1:Many-- shubchildren Parent may or many not have children records. children always have subchildren records. I wan to write a qiery to select parent names where any if matched parent.name,children.name or subchildren.name Here i understand I have to do a left outer join between parent and children. But what kind of join should I put between children and subchildren ?

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  • SQL query for getting count on same table using left outer join

    - by Sasi
    Hi all, I have a table from which i need to get the count grouped on two columns. the table has two columns one datetime column and another one is success value(-1,1,0) What i am looking for is something like this... count of success value for each month month----success-----count 11------- -1 ------- 50 11------- 1 --------- 50 11------- 0 ------- 50 12------- -1 ------- 50 12------- 1 ------- 50 12------- 0 ------- 50 if there is no success value for a month then the count should be null or zero. I have tried with left outer join as well but of no use it gives the count incorrectly. Thanks in advance Sasi

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  • SQL SERVER- Differences Between Left Join and Left Outer Join

    - by pinaldave
    There are a few questions that I had decided not to discuss on this blog because I think they are very simple and many of us know it. Many times, I even receive not-so positive notes from several readers when I am writing something simple. However, assuming that we know all and beginners should know everything is not the right attitude. Since day 1, I have been keeping a small journal regarding questions that I receive in this blog. There are around 200+ questions I receive every day through emails, comments and occasional phone calls. Yesterday, I received a comment with the following question: What are the differences between Left Join and Left Outer Join? Click here to read original comment. This question has triggered the threshold of receiving the same question repeatedly. Here is the answer: There is absolutely no difference between LEFT JOIN and LEFT OUTER JOIN. The same is true for RIGHT JOIN and RIGHT OUTER JOIN. When you use LEFT JOIN keyword in SQL Server, it means LEFT OUTER JOIN only. I have already written in-depth visual diagram discussing the JOINs. I encourage all of you to read the article for further understanding of the JOINs: Read Introduction to JOINs – Basic of JOINs Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, PostADay, SQL, SQL Authority, SQL Joins, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • HQL : LEFT OUTER JOIN

    - by Parama
    Hi all, I have two tables and respective classes in java.The mapping in the HBM.xml is as follows : The query in the HBM.xml is as follows : from Reports as rep left join rep.parts as parts I am getting the following exception while executing the code : May 19, 2010 10:47:04 AM org.hibernate.util.JDBCExceptionReporter logExceptions WARNING: SQL Error: 904, SQLState: 42000 May 19, 2010 10:47:04 AM org.hibernate.util.JDBCExceptionReporter logExceptions SEVERE: ORA-00904: "REPORTS0_"."PARTNO": invalid identifier org.hibernate.exception.SQLGrammarException: could not execute query at org.hibernate.exception.SQLStateConverter.convert(SQLStateConverter.java:67) at org.hibernate.exception.JDBCExceptionHelper.convert(JDBCExceptionHelper.java:43) at org.hibernate.loader.Loader.doList(Loader.java:2223) at org.hibernate.loader.Loader.listIgnoreQueryCache(Loader.java:2104) at org.hibernate.loader.Loader.list(Loader.java:2099) at org.hibernate.loader.hql.QueryLoader.list(QueryLoader.java:378) at org.hibernate.hql.ast.QueryTranslatorImpl.list(QueryTranslatorImpl.java:338) at org.hibernate.engine.query.HQLQueryPlan.performList(HQLQueryPlan.java:172) at org.hibernate.impl.SessionImpl.list(SessionImpl.java:1121) at org.hibernate.impl.QueryImpl.list(QueryImpl.java:79) at com.hcl.spring.db.sample.dao.ItemDAOImpl.loadItems(ItemDAOImpl.java:43) at com.hcl.spring.db.sample.service.ItemServiceImpl.loadItems(ItemServiceImpl.java:20) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source) at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source) at java.lang.reflect.Method.invoke(Unknown Source) at org.springframework.aop.support.AopUtils.invokeJoinpointUsingReflection(AopUtils.java:304) at org.springframework.aop.framework.ReflectiveMethodInvocation.invokeJoinpoint(ReflectiveMethodInvocation.java:182) at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:149) at org.springframework.transaction.interceptor.TransactionInterceptor.invoke(TransactionInterceptor.java:106) at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:171) at org.springframework.aop.framework.JdkDynamicAopProxy.invoke(JdkDynamicAopProxy.java:204) at $Proxy3.loadItems(Unknown Source) at com.hcl.spring.db.sample.Main.loadItems(Main.java:40) at com.hcl.spring.db.sample.Main.main(Main.java:19) Caused by: java.sql.SQLException: ORA-00904: "REPORTS0_"."PARTNO": invalid identifier at oracle.jdbc.driver.DatabaseError.throwSqlException(DatabaseError.java:112) at oracle.jdbc.driver.T4CTTIoer.processError(T4CTTIoer.java:331) at oracle.jdbc.driver.T4CTTIoer.processError(T4CTTIoer.java:288) at oracle.jdbc.driver.T4C8Oall.receive(T4C8Oall.java:743) at oracle.jdbc.driver.T4CPreparedStatement.doOall8(T4CPreparedStatement.java:216) at oracle.jdbc.driver.T4CPreparedStatement.executeForDescribe(T4CPreparedStatement.java:799) at oracle.jdbc.driver.OracleStatement.executeMaybeDescribe(OracleStatement.java:1038) at oracle.jdbc.driver.T4CPreparedStatement.executeMaybeDescribe(T4CPreparedStatement.java:839) at oracle.jdbc.driver.OracleStatement.doExecuteWithTimeout(OracleStatement.java:1133) at oracle.jdbc.driver.OraclePreparedStatement.executeInternal(OraclePreparedStatement.java:3285) at oracle.jdbc.driver.OraclePreparedStatement.executeQuery(OraclePreparedStatement.java:3329) at org.hibernate.jdbc.AbstractBatcher.getResultSet(AbstractBatcher.java:186) at org.hibernate.loader.Loader.getResultSet(Loader.java:1787) at org.hibernate.loader.Loader.doQuery(Loader.java:674) at org.hibernate.loader.Loader.doQueryAndInitializeNonLazyCollections(Loader.java:236) at org.hibernate.loader.Loader.doList(Loader.java:2220) ... 22 more Do request your help on the same.

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  • SQL Full Outer Join

    - by Torment March
    I have a table named 'Logs' with the following values : CheckDate CheckType CheckTime ------------------------------------------- 2011-11-25 IN 14:40:00 2011-11-25 OUT 14:45:00 2011-11-25 IN 14:50:00 2011-11-25 OUT 14:55:00 2011-11-25 IN 15:00:00 2011-11-25 OUT 15:05:00 2011-11-25 IN 15:15:00 2011-11-25 OUT 15:20:00 2011-11-25 IN 15:25:00 2011-11-25 OUT 15:30:00 2011-11-25 OUT 15:40:00 2011-11-25 IN 15:45:00 I want to use the previous table to produce a result of: CheckDate CheckIn CheckOut ----------------------------------------- 2011-11-25 14:40:00 14:45:00 2011-11-25 14:50:00 14:55:00 2011-11-25 15:00:00 15:05:00 2011-11-25 15:15:00 15:20:00 2011-11-25 15:25:00 15:30:00 2011-11-25 NULL 15:40:00 2011-11-25 15:45:00 NULL So far I have come up with this result set : CheckDate CheckIn CheckOut ----------------------------------------- 2011-11-25 14:40:00 14:45:00 2011-11-25 14:50:00 14:55:00 2011-11-25 15:00:00 15:05:00 2011-11-25 15:15:00 15:20:00 2011-11-25 15:25:00 15:30:00 2011-11-25 15:45:00 NULL The problem is I cannot generate the log without CheckIns : CheckDate CheckIn CheckOut ----------------------------------------- 2011-11-25 NULL 15:40:00 The sequence of CheckIn - CheckOut pairing and order is in increasing time value.

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  • How do I write to an outer truecrypt volume when the inner volume protection prevents writng?

    - by con-f-use
    In a nutshell After some time using the outer volume of a hidden volume in Truecrypt I cannot write to the outer volume anymore. The protection of the inner volume always kicks in before. How do I fix this? Details I'm using truecrypt's two layered encryption of a USB stick. The outer container carries my semi-sensitive stuff while the inner hidden values has a bit more valuable information. I use both, the inner and outer volume regularly and that is part of the problem. Truecrypt can mount the outer volume for writing while protecting the inner. Usually the inner volume, when not protected this way (or mounted read-only) would be indistinguishable from free space. That is of course part of the plausible deniability scheme of truecrypt. At the beginning, everything worked as expected. I could copy and delete data to the outer volume as I pleased. Now it seams that I have written and deleted enough data to have filled the outer volume once. Despite the write protection Ubuntu tries now to write to the continuous "free space" that is the inner volume. It does that although enough other free space is on the outer volume. But on this free space there used to be data so its fragmented and the file system write prefers continuous space. The write on the continuous free space of the outer volume of course fails (with the error message in the picture above) as Truecrypt's inner-volume-protection kicks in. The Question I know this is expected behaviour, but is there a better way to write to the outer volume that does not attempt to write to the hidden free space at the end? The whole question could be more generally rephrased to: How do I control, where on a partition data is written in Ubuntu?

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  • In SQL, if we rename INNER JOIN as INTERSECT JOIN, LEFT OUTER JOIN as LEFT UNION JOIN, and FULL OUTE

    - by Jian Lin
    In SQL, the name Join gives an idea of "merging" or a sense of "union", making something bigger. But in fact, as in the other post http://stackoverflow.com/questions/2706051/in-sql-a-join-is-actually-an-intersection-and-it-is-also-a-linkage-or-a-sidew it turns out that a Join (Inner Join) is actually an Intersection. So if we think of Join = Inner Join = Intersect Join Left Outer Join = Left Union Join Full Outer Join = Full Union Join = Union Join then we always get a feel of what's happening, and maybe never forget what they are easily. In a way, we can think of Intersect as "making it less", therefore it is excluding something. That's why the name "Join" won't go with the idea of "Intersect". But in fact, both Intersect and Union can be thought of as: Union: bringing something together and merge them unconditionally. Intersect: bringing something together and merge them based on some condition. so the "bringing something together" is probably what "Join" is all about. It is like, Intersection is a "half glass of water" -- we can thinking of it as "excluding something" or as "bringing something together and accepting the common ones". So if the word "Intersect Join" is used, maybe a clear picture is there, and "Union Join" can be a clear picture too. Maybe the word "Inner Join" and "Outer Join" is very clear when we use SQL a lot. Somehow, the word "Outer" tends to give a feeling that it is "outside" and excluding something rather than a "Union".

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  • Yet another use of OUTER APPLY in defensive programming

    - by Alexander Kuznetsov
    When a SELECT is used to populate variables from a subquery, it fails to change them if the subquery returns nothing - and that can lead to subtle bugs. We shall use OUTER APPLY to eliminate this problem. Prerequisites All we need is the following mock function that imitates a subquery: CREATE FUNCTION dbo.BoxById ( @BoxId INT ) RETURNS TABLE AS RETURN ( SELECT CAST ( 1 AS INT ) AS [Length] , CAST ( 2 AS INT ) AS [Width] , CAST ( 3 AS INT ) AS [Height] WHERE @BoxId = 1 ) ; Let us assume that this...(read more)

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  • Fun with Outer Joins

    Learn how an outer join works and how you can use it in your applications to find the results you need when matching data isn't in all your tables. Keep your database and application development in syncSQL Connect is a Visual Studio add-in that brings your databases into your solution. It then makes it easy to keep your database in sync, and commit to your existing source control system. Find out more.

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  • How to join data frames in R (inner, outer, left, right)?

    - by Dan Goldstein
    Given two data frames df1 = data.frame(CustomerId=c(1:6),Product=c(rep("Toaster",3),rep("Radio",3))) df2 = data.frame(CustomerId=c(2,4,6),State=c(rep("Alabama",2),rep("Ohio",1))) > df1 CustomerId Product 1 Toaster 2 Toaster 3 Toaster 4 Radio 5 Radio 6 Radio > df2 CustomerId State 2 Alabama 4 Alabama 6 Ohio How can I do database style, i.e., sql style, joins? That is, how do I get: An inner join of df1 and df1 An outer join of df1 and df2 A left outer join of df1 and df2 A right outer join of df1 and df2 P.S. IKT-JARQ (I Know This - Just Adding R Questions) Extra credit: How can I do a sql style select statement?

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  • In SQL / MySQL, can a Left Outer Join be used to find out the duplicates when there is no Primary ID

    - by Jian Lin
    I would like to try using Outer Join to find out duplicates in a table: If a table has Primary Index ID, then the following outer join can find out the duplicate names: mysql> select * from gifts; +--------+------------+-----------------+---------------------+ | giftID | name | filename | effectiveTime | +--------+------------+-----------------+---------------------+ | 2 | teddy bear | bear.jpg | 2010-04-24 04:36:03 | | 3 | coffee | coffee123.jpg | 2010-04-24 05:10:43 | | 6 | beer | beer_glass.png | 2010-04-24 05:18:12 | | 10 | heart | heart_shape.jpg | 2010-04-24 05:11:29 | | 11 | ice tea | icetea.jpg | 2010-04-24 05:19:53 | | 12 | cash | cash.png | 2010-04-24 05:27:44 | | 13 | chocolate | choco.jpg | 2010-04-25 04:04:31 | | 14 | coffee | latte.jpg | 2010-04-27 05:49:52 | | 15 | coffee | espresso.jpg | 2010-04-27 06:03:03 | +--------+------------+-----------------+---------------------+ 9 rows in set (0.00 sec) mysql> select * from gifts g1 LEFT JOIN (select * from gifts group by name) g2 on g1.giftID = g2.giftID where g2.giftID IS NULL; +--------+--------+--------------+---------------------+--------+------+----------+---------------+ | giftID | name | filename | effectiveTime | giftID | name | filename | effectiveTime | +--------+--------+--------------+---------------------+--------+------+----------+---------------+ | 14 | coffee | latte.jpg | 2010-04-27 05:49:52 | NULL | NULL | NULL | NULL | | 15 | coffee | espresso.jpg | 2010-04-27 06:03:03 | NULL | NULL | NULL | NULL | +--------+--------+--------------+---------------------+--------+------+----------+---------------+ 2 rows in set (0.00 sec) But what if the table doesn't have a Primary Index ID, then can an outer join still be used to find out duplicates?

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  • Making only the outer vector in vector<vector<int>> fixed

    - by Dennis Ritchie
    I want to create a vector<vector<int>> where the outer vector is fixed (always containing the same vectors), but the inner vectors can be changed. For example: int n = 2; //decided at runtime assert(n>0); vector<vector<int>> outer(n); //outer vector contains n empty vectors outer.push_back(vector<int>()); //modifying outer vector - this should be error auto outer_it = outer.begin(); (*outer_it).push_back(3); //modifying inner vector. should work (which it does). I tried doing simply const vector<vector<int>>, but that makes even the inner vectors const. Is my only option to create my own custom FixedVectors class, or are there better ways out there to do this?

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