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  • Is Programming == Math?

    - by moffdub
    I've heard many times that all programming is really a subset of math. Some suggest that OO, at its roots, is mathematically based. I don't get the connection. Aside from some obvious examples: using induction to prove a recursive algorithm formal correctness proofs functional languages lambda calculus asymptotic complexity DFAs, NFAs, Turing Machines, and theoretical computation in general the fact that everything on the box is binary In what ways is programming really a subset of math? I'm looking for an explanation that might have relevance to enterprise/OO development (if there is a strong enough connection, that is). Thanks in advance. Edit: as I stated in a comment to an answer, math is uber important to programming, but what I struggle with is the "subset" argument.

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  • how to log digester with apache commons?

    - by Bruce
    Hi all I'm having trouble getting digester to log anything. I'd be hugely grateful for any light anyone can shed. In my code I'm doing this: Digester digester = new Digester(); .. some digester set up stuff // What on earth should go in here???? digester.setLogger(LogFactory.getLog("org.apache.commons.logging.Log")); I have a commons-logging.properties file in my classpath as follows: org.apache.commons.logging.Log=org.apache.commons.logging.impl.SimpleLog org.apache.commons.logging.simplelog.log.org.apache.commons.digester.Digester=debug org.apache.commons.logging.simplelog.log.org.apache.commons.digester.Digester.sax=info I just get no debug info at all.. Thanks for your help!

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  • Math Problem With Percentages

    - by TheDarkIn1978
    i'm terrible at math. trust me, you math experts will see why after reading my question. i have an object that is 300px in height. i need to calculate the percentage of that height where 90% = 300px (or the full height), 45% = 150px, 0% = 0px. so essentially, if i ask for 45% of the object's height, it will return 150px, or if i ask for 32% of the object's height, it will return __? i believe this is really basic math, so i apologize in advance.

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  • What Math topics & resources to consider as beginner to indulge the book - Introduction to Algorithm

    - by sector7
    I'm a programmer who's beginning to appreciate the knowledge & usability of Algorithms in my work as I move forward with my skill-set. I don't want to take the short path by learning how to apply algorithms "as-is" but would rather like to know the foundation and fundamentals behind them. For that I need Math, at which I'm pretty "basic". I'm considering getting tuition's for that. What I would like is to have a concise syllabus/set of topics/book which I could hand over to my math tutor to get started. HIGHLY DESIRED: one book. the silver bullet. (fingers crossed!) PS: I've got some leads but want to hear you guys/gurus out: Discrete Math, Combinatorics, Graph theory, Calculus, Linear Algebra, and Number Theory. Looking forward to your answers. Thanks!

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  • The Apache License, v2.0: Copyright License vs Patent License

    - by user278064
    The Apache License, v2.0 [..] 2. Grant of Copyright License Subject to the terms and conditions of this License, each Contributor hereby grants to You a perpetual, worldwide, non-exclusive, no-charge, royalty-free, irrevocable copyright license to reproduce, prepare Derivative Works of, publicly display, publicly perform, sublicense and distribute the Work and such Derivative Works in Source or Object form. [..] 3. Grant of Patent License Subject to the terms and conditions of this License, each Contributor hereby grants to you a perpetual, worldwide, non-exclusive, no-charge, royalty-free, irrevocable (except as stated in this section) patent license to make, have made, use offer to sell, sell, import, and otherwise transfer the Work, where such license applies only to those patent claims licensable by such Contributor that are necessarily infringed by their Contribution(s) alone or by combination of their Contribution(s) with the Work to which such Contribution(s) was submitted. If You institute patent litigation against any entity (including cross-claim or counterclaim in lawsuit) alleging that the Work or a Contribution incorporated within theWork constitutes direct or contributory patent infringement, then any patent licenses granted to You under this License for that Work shall terminate as of the date such litigation is filed. While the meaning of the Copyright License provision is rather clear, I did not get the meaning of the Patent License provision. Which advantages does the "Grant of Patent License" provision further give to Contributors? Why are they useful? Is the "Grant of Patent License" provision useful only in case of patent litigation?

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  • Apache httpd Problem

    - by Christopher
    Hey, I am getting intermittent issues with my site. Pages often hang with huge loading times and sometimes fail to load. The httpd error logs contain the following: [Wed Feb 23 06:54:17 2011] [debug] proxy_util.c(1854): proxy: grabbed scoreboard slot 0 in child 5871 for worker proxy:reverse [Wed Feb 23 06:54:17 2011] [debug] proxy_util.c(1967): proxy: initialized single connection worker 0 in child 5871 for (*) [Wed Feb 23 06:54:24 2011] [debug] proxy_util.c(1854): proxy: grabbed scoreboard slot 0 in child 5872 for worker proxy:reverse [Wed Feb 23 06:54:24 2011] [debug] proxy_util.c(1873): proxy: worker proxy:reverse already initialized [Wed Feb 23 06:54:24 2011] [debug] proxy_util.c(1967): proxy: initialized single connection worker 0 in child 5872 for (*) [Wed Feb 23 06:59:15 2011] [debug] proxy_util.c(1854): proxy: grabbed scoreboard slot 0 in child 5954 for worker proxy:reverse [Wed Feb 23 06:59:15 2011] [debug] proxy_util.c(1873): proxy: worker proxy:reverse already initialized The server is currently running with 800mb free memory, so it is not caused by lack of RAM. Any suggestions would be greatly appreciated. Many thanks, Chris. EDIT The current number of httpd procceses is 11. This does increase as the error persists and can rise up to 25+. I am running Apache/2.2.3 (CentOS).

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  • Finding the normal of OBB face with an OBB penetrating

    - by Milo
    Below is an illustration: I have an OBB in an OBB (see below for OBB2D code if needed). What I need to determine is, what face it is in, and what direction do I point the normal? The goal is to get the OBB out of the OBB so the normal needs to face outward of the OBB. How could I go about: Finding what face the line is penetrating given the 4 corners of the OBB and the class below: if we define dx=x2-x1 and dy=y2-y1, then the normals are (-dy, dx) and (dy, -dx). Which normal points outward of the OBB? Thanks public class OBB2D { // Corners of the box, where 0 is the lower left. private Vector2D corner[] = new Vector2D[4]; private Vector2D center = new Vector2D(); private Vector2D extents = new Vector2D(); private RectF boundingRect = new RectF(); private float angle; //Two edges of the box extended away from corner[0]. private Vector2D axis[] = new Vector2D[2]; private double origin[] = new double[2]; public OBB2D(Vector2D center, float w, float h, float angle) { set(center,w,h,angle); } public OBB2D(float left, float top, float width, float height) { set(new Vector2D(left + (width / 2), top + (height / 2)),width,height,0.0f); } public void set(Vector2D center,float w, float h,float angle) { Vector2D X = new Vector2D( (float)Math.cos(angle), (float)Math.sin(angle)); Vector2D Y = new Vector2D((float)-Math.sin(angle), (float)Math.cos(angle)); X = X.multiply( w / 2); Y = Y.multiply( h / 2); corner[0] = center.subtract(X).subtract(Y); corner[1] = center.add(X).subtract(Y); corner[2] = center.add(X).add(Y); corner[3] = center.subtract(X).add(Y); computeAxes(); extents.x = w / 2; extents.y = h / 2; computeDimensions(center,angle); } private void computeDimensions(Vector2D center,float angle) { this.center.x = center.x; this.center.y = center.y; this.angle = angle; boundingRect.left = Math.min(Math.min(corner[0].x, corner[3].x), Math.min(corner[1].x, corner[2].x)); boundingRect.top = Math.min(Math.min(corner[0].y, corner[1].y),Math.min(corner[2].y, corner[3].y)); boundingRect.right = Math.max(Math.max(corner[1].x, corner[2].x), Math.max(corner[0].x, corner[3].x)); boundingRect.bottom = Math.max(Math.max(corner[2].y, corner[3].y),Math.max(corner[0].y, corner[1].y)); } public void set(RectF rect) { set(new Vector2D(rect.centerX(),rect.centerY()),rect.width(),rect.height(),0.0f); } // Returns true if other overlaps one dimension of this. private boolean overlaps1Way(OBB2D other) { for (int a = 0; a < axis.length; ++a) { double t = other.corner[0].dot(axis[a]); // Find the extent of box 2 on axis a double tMin = t; double tMax = t; for (int c = 1; c < corner.length; ++c) { t = other.corner[c].dot(axis[a]); if (t < tMin) { tMin = t; } else if (t > tMax) { tMax = t; } } // We have to subtract off the origin // See if [tMin, tMax] intersects [0, 1] if ((tMin > 1 + origin[a]) || (tMax < origin[a])) { // There was no intersection along this dimension; // the boxes cannot possibly overlap. return false; } } // There was no dimension along which there is no intersection. // Therefore the boxes overlap. return true; } //Updates the axes after the corners move. Assumes the //corners actually form a rectangle. private void computeAxes() { axis[0] = corner[1].subtract(corner[0]); axis[1] = corner[3].subtract(corner[0]); // Make the length of each axis 1/edge length so we know any // dot product must be less than 1 to fall within the edge. for (int a = 0; a < axis.length; ++a) { axis[a] = axis[a].divide((axis[a].length() * axis[a].length())); origin[a] = corner[0].dot(axis[a]); } } public void moveTo(Vector2D center) { Vector2D centroid = (corner[0].add(corner[1]).add(corner[2]).add(corner[3])).divide(4.0f); Vector2D translation = center.subtract(centroid); for (int c = 0; c < 4; ++c) { corner[c] = corner[c].add(translation); } computeAxes(); computeDimensions(center,angle); } // Returns true if the intersection of the boxes is non-empty. public boolean overlaps(OBB2D other) { if(right() < other.left()) { return false; } if(bottom() < other.top()) { return false; } if(left() > other.right()) { return false; } if(top() > other.bottom()) { return false; } if(other.getAngle() == 0.0f && getAngle() == 0.0f) { return true; } return overlaps1Way(other) && other.overlaps1Way(this); } public Vector2D getCenter() { return center; } public float getWidth() { return extents.x * 2; } public float getHeight() { return extents.y * 2; } public void setAngle(float angle) { set(center,getWidth(),getHeight(),angle); } public float getAngle() { return angle; } public void setSize(float w,float h) { set(center,w,h,angle); } public float left() { return boundingRect.left; } public float right() { return boundingRect.right; } public float bottom() { return boundingRect.bottom; } public float top() { return boundingRect.top; } public RectF getBoundingRect() { return boundingRect; } public boolean overlaps(float left, float top, float right, float bottom) { if(right() < left) { return false; } if(bottom() < top) { return false; } if(left() > right) { return false; } if(top() > bottom) { return false; } return true; } };

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  • Apache mod_rewrite for multiple domains to SSL

    - by Aaron Vegh
    Hi there, I'm running a web service that will allow people to create their own "instances" of my application, running under their own domain. These people will create an A record to forward a subdomain of their main domain to my server. The problem is that my server runs everything under SSL. So in my configuration for port 80, I have the following: <VirtualHost *:80> ServerName mydomain.com ServerAlias www.mydomain.com RewriteEngine On RewriteCond %{HTTPS} !=on RewriteRule /(.*) https://mydomain.com/$1 [R=301] </VirtualHost> This has worked well to forward all requests from the http: to https: domain. But as I said, I now need to let any domain automatically forward to the secure version of itself. Is there a rewrite rule that will let me take the incoming domain and rewrite it to the https version of same? So that the following matches would occur: http://some.otherdomain.com -> https://some.otherdomain.com http://evenanotherdomain.com -> https://evenanotherdomain.com Thanks for your help! Apache mod_rewrite makes my brain hurt. Aaron.

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  • Apache: Virtual Host and .htacess for URL Rewriting not working

    - by parth
    I have configured a virtual host in my local machine and every thing is working fine. Now I want to use SEO friendly urls. To achieve this I have used the .htaccess file. My virtual host configuration is: <VirtualHost *:80> DocumentRoot "C:/xampp/htdocs/ypp" ServerName ypp.com ServerAlias www.ypp.com ##ErrorLog "logs/dummy-host2.localhost-error.log" ##CustomLog "logs/dummy-host2.localhost-access.log" combined </VirtualHost> and my .htaccess file has: AllowOverride All RewriteEngine On RewriteBase /ypp/ RewriteRule ^/browse$ /browse.php RewriteRule ^/browse/([a-z]+)$ /browse.php?cat=$1 RewriteRule ^/browse/([a-z]+)/([a-z]+)$ /browse.php?cat=$1&subcat=$2 The above .htaccess setting is not working. After that I modified my virtual host setting and it is working. The new virtual host setting is: <VirtualHost *:80> RewriteEngine On RewriteRule ^/browse$ /browse.php RewriteRule ^/browse/([a-z]+)$ /browse.php?cat=$1 RewriteRule ^/browse/([a-z]+)/([a-z]+)$ /browse.php?cat=$1&subcat=$2 ServerAdmin [email protected] DocumentRoot "C:/xampp/htdocs/ypp" ServerName ypp.com ServerAlias www.ypp.com ##ErrorLog "logs/dummy-host2.localhost-error.log" ##CustomLog "logs/dummy-host2.localhost-access.log" combined <Directory "C:/xampp/htdocs/ypp"> AllowOverride All </Directory> </VirtualHost> Please let me know where I am going wrong in the .htacess file for url rewriting. I do not want to use the settings in virtual host, since for every change I have restart apache.

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  • Writing files in a sub folder of the web folder (apache security)

    - by Homunculus Reticulli
    I need to save session data for a dynamic web page script by writing to file. I have two questions: Are there any security preferences as to whether to save the data UNDER the web folder, or OUTSIDE the web folder? I attempted to write to the folder an (unsuprisingly), I had a 'file permission refused' type error. Should I set the folder ownership to the apache user (600, 640 or 644?) [[Edit]] core <- 'OUTSIDE' web folder (php script live here) data <- 'OUTSIDE' web folder (session data and other misc data resides here) web <- web root folder js <- any folder below is 'INSIDE' the web folder css html For example, in a php script (i.e. a dynamic PHP page), I can attempt to write to a file using something like fput('../data',data) yet (as I understand it) ../data should not be accessible - for security reasons. Could someone please provide a simple example that shows how to provide access to ../data/ in the example given above?. What are the actual SPECIFIC steps required? BTW, I am running on a LAMP stack.

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  • Apache (XAMPP 1.8.0) access.log/Intrusion Detection Concern

    - by Andy Holaday
    [I originally posted on SO but it earned me a Tumbleweed badge. This looks like a better venue for the question.] I have Apache (XAMPP 1.8.0) running on Vista Pro x64. A couple times now I have seen a pattern like the example below in access.log. Concerning is the "attack" seems to somehow shift from a public IP to a valid private IP on my network (happens to be the WAN address of one of my routers). Two questions: How is this possible, and what happens if the "attacker" stumbles on a valid request? I've googled this to no avail. 177.0.X.X - - [03/Jun/2012:08:19:34 -0400] "GET /phpMyAdmin-2.5.4/index.php HTTP/1.1" 403 177.0.X.X - - [03/Jun/2012:08:19:34 -0400] "GET /phpMyAdmin-2.5.5-rc1/index.php HTTP/1.1" 403 177.0.X.X - - [03/Jun/2012:08:19:34 -0400] "GET /phpMyAdmin-2.2.6/index.php HTTP/1.1" 403 177.0.X.X - - [03/Jun/2012:08:19:34 -0400] "GET /phpMyAdmin-2.5.5-rc2/index.php HTTP/1.1" 403 192.168.15.3 - - [03/Jun/2012:08:19:56 -0400] "GET /phpMyAdmin-2.5.6-rc2/index.php HTTP/1.1" 403 177.0.X.X - - [03/Jun/2012:08:19:56 -0400] "GET /phpMyAdmin-2.5.6-rc1/index.php HTTP/1.1" 403 177.0.X.X - - [03/Jun/2012:08:19:56 -0400] "GET /phpMyAdmin-2.5.5-pl1/index.php HTTP/1.1" 403 192.168.15.3 - - [03/Jun/2012:08:19:59 -0400] "GET /phpMyAdmin-2.5.7/index.php HTTP/1.1" 403 192.168.15.3 - - [03/Jun/2012:08:20:01 -0400] "GET /phpMyAdmin-2.5.7-pl1/index.php HTTP/1.1" 403 192.168.15.3 - - [03/Jun/2012:08:20:02 -0400] "GET HTTP/1.1" 400 1060 "-" "-"

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  • Apache: Virtual Host and .htacess for URL Rewriting not working

    - by parth
    I have configured virtual host in my local machine and every thing working fine . Now I want to use SEO friendly urls. To achive this I have used .htacess file . My virtual host configuration is : <VirtualHost *:80> DocumentRoot "C:/xampp/htdocs/ypp" ServerName ypp.com ServerAlias www.ypp.com ##ErrorLog "logs/dummy-host2.localhost-error.log" ##CustomLog "logs/dummy-host2.localhost-access.log" combined </VirtualHost> and my .htacess file has : AllowOverride All RewriteEngine On RewriteBase /ypp/ RewriteRule ^/browse$ /browse.php RewriteRule ^/browse/([a-z]+)$ /browse.php?cat=$1 RewriteRule ^/browse/([a-z]+)/([a-z]+)$ /browse.php?cat=$1&subcat=$2 The above .htacess setting is not working . After that I have modigied my virtual host setting and it is working . new virtual host setting is : <VirtualHost *:80> RewriteEngine On RewriteRule ^/browse$ /browse.php RewriteRule ^/browse/([a-z]+)$ /browse.php?cat=$1 RewriteRule ^/browse/([a-z]+)/([a-z]+)$ /browse.php?cat=$1&subcat=$2 ServerAdmin [email protected] DocumentRoot "C:/xampp/htdocs/ypp" ServerName ypp.com ServerAlias www.ypp.com ##ErrorLog "logs/dummy-host2.localhost-error.log" ##CustomLog "logs/dummy-host2.localhost-access.log" combined <Directory "C:/xampp/htdocs/ypp"> AllowOverride All </Directory> </VirtualHost> Please guide me where I am wrong in .htacess file for url rewriting . I donot want to use setting in virtual host because for every change I have restart apache .

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  • Bouncing off a circular Boundary with multiple balls?

    - by Anarkie
    I am making a game like this : Yellow Smiley has to escape from red smileys, when yellow smiley hits the boundary game is over, when red smileys hit the boundary they should bounce back with the same angle they came, like shown below: Every 10 seconds a new red smiley comes in the big circle, when red smiley hits yellow, game is over, speed and starting angle of red smileys should be random. I control the yellow smiley with arrow keys. The biggest problem I have reflecting the red smileys from the boundary with the angle they came. I don't know how I can give a starting angle to a red smiley and bouncing it with the angle it came. I would be glad for any tips! My js source code : var canvas = document.getElementById("mycanvas"); var ctx = canvas.getContext("2d"); // Object containing some global Smiley properties. var SmileyApp = { radius: 15, xspeed: 0, yspeed: 0, xpos:200, // x-position of smiley ypos: 200 // y-position of smiley }; var SmileyRed = { radius: 15, xspeed: 0, yspeed: 0, xpos:350, // x-position of smiley ypos: 65 // y-position of smiley }; var SmileyReds = new Array(); for (var i=0; i<5; i++){ SmileyReds[i] = { radius: 15, xspeed: 0, yspeed: 0, xpos:350, // x-position of smiley ypos: 67 // y-position of smiley }; SmileyReds[i].xspeed = Math.floor((Math.random()*50)+1); SmileyReds[i].yspeed = Math.floor((Math.random()*50)+1); } function drawBigCircle() { var centerX = canvas.width / 2; var centerY = canvas.height / 2; var radiusBig = 300; ctx.beginPath(); ctx.arc(centerX, centerY, radiusBig, 0, 2 * Math.PI, false); // context.fillStyle = 'green'; // context.fill(); ctx.lineWidth = 5; // context.strokeStyle = '#003300'; // green ctx.stroke(); } function lineDistance( positionx, positiony ) { var xs = 0; var ys = 0; xs = positionx - 350; xs = xs * xs; ys = positiony - 350; ys = ys * ys; return Math.sqrt( xs + ys ); } function drawSmiley(x,y,r) { // outer border ctx.lineWidth = 3; ctx.beginPath(); ctx.arc(x,y,r, 0, 2*Math.PI); //red ctx.fillStyle="rgba(255,0,0, 0.5)"; ctx.fillStyle="rgba(255,255,0, 0.5)"; ctx.fill(); ctx.stroke(); // mouth ctx.beginPath(); ctx.moveTo(x+0.7*r, y); ctx.arc(x,y,0.7*r, 0, Math.PI, false); // eyes var reye = r/10; var f = 0.4; ctx.moveTo(x+f*r, y-f*r); ctx.arc(x+f*r-reye, y-f*r, reye, 0, 2*Math.PI); ctx.moveTo(x-f*r, y-f*r); ctx.arc(x-f*r+reye, y-f*r, reye, -Math.PI, Math.PI); // nose ctx.moveTo(x,y); ctx.lineTo(x, y-r/2); ctx.lineWidth = 1; ctx.stroke(); } function drawSmileyRed(x,y,r) { // outer border ctx.lineWidth = 3; ctx.beginPath(); ctx.arc(x,y,r, 0, 2*Math.PI); //red ctx.fillStyle="rgba(255,0,0, 0.5)"; //yellow ctx.fillStyle="rgba(255,255,0, 0.5)"; ctx.fill(); ctx.stroke(); // mouth ctx.beginPath(); ctx.moveTo(x+0.4*r, y+10); ctx.arc(x,y+10,0.4*r, 0, Math.PI, true); // eyes var reye = r/10; var f = 0.4; ctx.moveTo(x+f*r, y-f*r); ctx.arc(x+f*r-reye, y-f*r, reye, 0, 2*Math.PI); ctx.moveTo(x-f*r, y-f*r); ctx.arc(x-f*r+reye, y-f*r, reye, -Math.PI, Math.PI); // nose ctx.moveTo(x,y); ctx.lineTo(x, y-r/2); ctx.lineWidth = 1; ctx.stroke(); } // --- Animation of smiley moving with constant speed and bounce back at edges of canvas --- var tprev = 0; // this is used to calculate the time step between two successive calls of run function run(t) { requestAnimationFrame(run); if (t === undefined) { t=0; } var h = t - tprev; // time step tprev = t; SmileyApp.xpos += SmileyApp.xspeed * h/1000; // update position according to constant speed SmileyApp.ypos += SmileyApp.yspeed * h/1000; // update position according to constant speed for (var i=0; i<SmileyReds.length; i++){ SmileyReds[i].xpos += SmileyReds[i].xspeed * h/1000; // update position according to constant speed SmileyReds[i].ypos += SmileyReds[i].yspeed * h/1000; // update position according to constant speed } // change speed direction if smiley hits canvas edges if (lineDistance(SmileyApp.xpos, SmileyApp.ypos) + SmileyApp.radius > 300) { alert("Game Over"); } // redraw smiley at new position ctx.clearRect(0,0,canvas.height, canvas.width); drawBigCircle(); drawSmiley(SmileyApp.xpos, SmileyApp.ypos, SmileyApp.radius); for (var i=0; i<SmileyReds.length; i++){ drawSmileyRed(SmileyReds[i].xpos, SmileyReds[i].ypos, SmileyReds[i].radius); } } // uncomment these two lines to get every going // SmileyApp.speed = 100; run(); // --- Control smiley motion with left/right arrow keys function arrowkeyCB(event) { event.preventDefault(); if (event.keyCode === 37) { // left arrow SmileyApp.xspeed = -100; SmileyApp.yspeed = 0; } else if (event.keyCode === 39) { // right arrow SmileyApp.xspeed = 100; SmileyApp.yspeed = 0; } else if (event.keyCode === 38) { // up arrow SmileyApp.yspeed = -100; SmileyApp.xspeed = 0; } else if (event.keyCode === 40) { // right arrow SmileyApp.yspeed = 100; SmileyApp.xspeed = 0; } } document.addEventListener('keydown', arrowkeyCB, true); JSFiddle : http://jsfiddle.net/gj4Q7/

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  • Java Apache Commons users

    - by Tom Brito
    Is there anything in apache commons to convert a Object to byte array, like the following method does? public static byte[] toByteArray(Object obj) throws IOException { ByteArrayOutputStream baos = new ByteArrayOutputStream(); ObjectOutputStream oos = new ObjectOutputStream(baos); oos.writeObject(obj); oos.flush(); byte[] data = baos.toByteArray(); return data; } [try-finally block closing buffers were omitted to simplify]

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  • httpURLConnection vs apache commons http

    - by Pablo Fernandez
    Hi everyone! I just wanted to know if any of you had any problems using java default HttpURLConnection class. Some kind of bug that made you switch to apache commons. Or is it just the (ugly) interface that class exposes that justifies the birth of 3rd party http lib? Disclosure: I heard some arguments against java.net having some serious problems, but I'm finding hard to believe that a class that is part of the java core distribution still has issues after several releases of the JDK

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  • How safe is apache Commons-javaflow while using jasperreports

    - by Nayn
    Hi, I am using jasperreport and trying to pass an alternate report runner. • net.sf.jasperreports.engine.fill.JRThreadSubreportRunner: The initial thread-based implementation • net.sf.jasperreports.engine.fill.JRContinuationSubreportRunner: A Javaflow-based implementation I am using the second one (for the reason, it runs on tomcat server, and creating threads wouldn't be good while writing subreports). The second one depends on commons-javaflow which is a sandbox version. Not sure if I should use it, Could somebody suggest a better way. Thanks

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  • Java apache commons library source license question

    - by llm
    I want to use functionality from a certain method in apache commons StringUtils. I currently do not have the option of just using the library as one would normally do. I found the source for the method I need and my question is: am I free (legally) to use this code (just a method out of the library) or do I have to use the entire library? If its ok, what kind of attribution would I need in my code, if any? Thanks.

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  • How to fetch parameters when using the Apache Commons CLI library

    - by Mridang Agarwalla
    I'm using the Apache Commons CLI to handle command line arguments in Java. I've figured out my way around it to a decent extent but I need a little help. I've declared the a and b options and I'm able to access the value using CommandLine.getOptionValue. Usage: myapp [OPTION] [DIRECTORY] Options: -a Option A -b Option B How do I declare and access the DIRECTORY variable? Thank you.

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  • Correct PHP5 DLL for Apache 2.2?

    - by Nathan Long
    I have installed Apache 2.2.14 (Win32) on a Windows XP machine and am trying to add the latest PHP module. I downloaded the ZIP file from here labeled "VC9 x86 Non Thread Safe" and extracted to my Apache directory. I then copied php5.dll to Apache's bin directory and copied php.ini to C:\Windows. In httpd.conf, I added these lines: LoadModule php5_module "C:/Program Files/Apache Software Foundation/Apache2.2/bin/php5.dll" AddType application/x-httpd-php .php Now Apache will not start. error.log says this: "Can't locate API module structure php5_module in file C:/Program Files/Apache Software Foundation/Apache2.2/bin/php5.dll": No error" I think I may have the wrong .dll file, because I found tutorials that use the filename php5apache2.dll and I didn't see that in the PHP package I got. Also, I have seen references to a file called php5ts.dll, but I don't see that either. What exactly do I need to make PHP5 work?

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  • Starting phusion passenger on working apache

    - by fl00r
    Hi! I've got Apache (-v): Server version: Apache/2.0.63 Server built: Nov 29 2009 15:23:34 Cpanel::Easy::Apache v3.2.0 rev4899 I want to start new Sinatra application on passenger. I've just installed passenger gem. So now I need to set up apache configuration. In httpd.conf there are many settings of others applications on server. So I just can't reinstall apache with passenger-install-apache2-module. I need to set up exist Apache with passenger. What have I do now?

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  • What is the correct way to setup my virtual hosts in Apache to serve 2 differnt domains?

    - by Michael
    I have a current website on an Apache server (foo.com) and I want the same server to serve a new site (bar.com), is this the correct way to setup my virtual hosts? <VirtualHost *:80 ServerName foo.com ServerAlias www.foo.com Include conf.d/foo.conf </VirtualHost <VirtualHost *:80 ServerName bar.com ServerAlias www.bar.com Include conf.d/bar.conf </VirtualHost I'm hesitant to do an /etc/init.d/httpd reload without someone double checking! :)

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  • How to bind Apache to specific IP and port on Windows Server 2008

    - by webworm
    I have a Windows Server 2008 R2 that I use to host various ASP.NET applications under IIS7. I would also like to run various PHP based web apps using Apache (or Apache 2). The server has three static IP addresses assigned to it and I would like to bind one of the IP addresses to Apache while using the other two IP addresses for IIS. I can use the IIS Manager to bind the specific IP addresses to IIS, but I am unaware of how to do this with Apache. Can anyone tell me how to go about binding Apache to a specific IP address and port (port 80 is what I want to use). Please note .. I am aware that PHP can run under IIS. In fact that is how I have been running my PHP web applications. However, there are so many inconsistencies and pitfalls with PHP running under IIS that I just prefer to use Apache.

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  • Making working passenger on working apache

    - by fl00r
    Hi! I've got Apache (-v): Server version: Apache/2.0.63 Server built: Nov 29 2009 15:23:34 Cpanel::Easy::Apache v3.2.0 rev4899 I want to start new Sinatra application on passenger. I've just installed passenger gem. So now I need to set up apache configuration. In httpd.conf there are many settings of others applications on server. So I just can't reinstall apache with passenger-install-apache2-module. I need to set up exist Apache with passenger. What have I do now?

    Read the article

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