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  • Rails ActiveRecord friendly code from a Complex Join, Sum, and Group query

    - by Chad M
    PROBLEM Hello, I am having no luck trying to break down this SQL statement into ActiveRecord/Rails friendly code and I'd like to learn how I can avoid a find_by_sql statement in this situation. Scenario I have users that create audits when they perform an action. Each audit is of a specific audit_activity. Each audit_activity is worth a certain number of points, based on score_weight. I need to find the total scores of each user, based on their total accumulated audit_activity score_weights. Eventually I'll need to rank them which means adding a sort to this as well. My Code Here is my sql and simplified versions of the tables in question. Any thoughts? SQL with full column names (for clarity) SELECT users.id, u.email, SUM(audit_activity.score_weight) FROM users JOIN audits ON users.id = audits.user_id JOIN audit_activities ON audit_activities.id = audits.audit_activity_id GROUP BY users.id; Models: User, Audit, AuditActivity User fields: id, email class User < ActiveRecord::Base include Clearance::User has_many :audits end Audit fields: id, user_id, audit_activity_id class Audit < ActiveRecord::Base belongs_to :user belongs_to :audit_activity end AuditActivity fields: id, score_weight class AuditActivity < ActiveRecord::Base has_many :audits end Example Data Here is a set of SQL statements so you can play with similar data I'm working with and see what comes up when the concerned query is run. You should just be able to copy/paste the whole thing into a database query browser. CREATE TABLE users( id INTEGER NOT NULL, email TEXT (25), PRIMARY KEY (id) ); CREATE TABLE audits( id INTEGER NOT NULL, user_id INTEGER, audit_activity_id INTEGER, PRIMARY KEY (id) ); CREATE TABLE audit_activities( id INTEGER NOT NULL, score_weight INTEGER, PRIMARY KEY (id) ); INSERT INTO users(id, email) VALUES(1, "[email protected]"); INSERT INTO users(id, email) VALUES(2, "[email protected]"); INSERT INTO users(id, email) VALUES(3, "[email protected]"); INSERT INTO audits(id, user_id, audit_activity_id) VALUES(1, 1, 1); INSERT INTO audits(id, user_id, audit_activity_id) VALUES(2, 1, 2); INSERT INTO audits(id, user_id, audit_activity_id) VALUES(3, 1, 1); INSERT INTO audits(id, user_id, audit_activity_id) VALUES(4, 1, 3); INSERT INTO audits(id, user_id, audit_activity_id) VALUES(5, 1, 1); INSERT INTO audits(id, user_id, audit_activity_id) VALUES(6, 1, 4); INSERT INTO audits(id, user_id, audit_activity_id) VALUES(7, 2, 4); INSERT INTO audits(id, user_id, audit_activity_id) VALUES(8, 2, 4); INSERT INTO audits(id, user_id, audit_activity_id) VALUES(9, 2, 4); INSERT INTO audits(id, user_id, audit_activity_id) VALUES(10, 3, 3); INSERT INTO audits(id, user_id, audit_activity_id) VALUES(11, 3, 2); INSERT INTO audits(id, user_id, audit_activity_id) VALUES(12, 3, 2); INSERT INTO audits(id, user_id, audit_activity_id) VALUES(13, 3, 2); INSERT INTO audits(id, user_id, audit_activity_id) VALUES(14, 3, 3); INSERT INTO audits(id, user_id, audit_activity_id) VALUES(15, 3, 1); INSERT INTO audits(id, user_id, audit_activity_id) VALUES(16, 3, 1); INSERT INTO audit_activities(id, score_weight) VALUES(1, 1); INSERT INTO audit_activities(id, score_weight) VALUES(2, 2); INSERT INTO audit_activities(id, score_weight) VALUES(3, 7); INSERT INTO audit_activities(id, score_weight) VALUES(4, 11); The Query Again, here is the query. SELECT u.id, u.email, SUM(aa.score_weight) FROM users u JOIN audits a ON u.id = a.user_id JOIN audit_activities aa ON aa.id = a.audit_activity_id GROUP BY u.id; Many Thanks, Chad

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  • Keyword Selection

    As most marketers know from having experience on line, keyword selection is one of the top priorities to having your sales copy or article found in the search engines. Not only is this a top priority, it's the one thing you must spend time on to make sure you do have the keyword selection correct. You may ask.

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  • SQL Max Group By Query Help

    - by Hcabnettek
    Hi All, I have a quick question. How do I select the two values I need in one query? Currently I'm doing this, which works fine, but it's obviously running two queries when one should do the trick. I tried MAX(columnA) and GROUP BY ColumnB, but that returns multiple row. I only want one row returned. DECLARE @biID bigint , @dtThreshold DateTime SELECT @biID = MAX(biID) FROM tbPricingCalculationCount WITH (NOLOCK) SELECT @dtThreshold = dtDateTime FROM tbPricingCalculationCount WITH (NOLOCK) WHERE biID = @biID I would like both those variables to be set correctly in one query. How can I do that? Thanks, ~ck

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  • Reading Local Group Policy / Active Directory Settings

    - by Shinobi
    I'm writing a C# program that will enforce password complexity in accordance with the Windows Group Policy setting "Password must meet complexity requirements". Specifically, if that policy is set to Enabled either on the local machine (if it's not part of a domain) or by the Domain Security Policy (for domain members), then my software needs to enforce a complex password for its own internal security. The issue is that I can't figure out how to read that GPO setting. Google searches have indicated that I can read GPO settings with one of these two APIs: the System.DirectoryServices library in .NET Framework, and Windows Management Instrumentation (WMI), but I haven't had any success so far. Any insights would be helpful.

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  • MySQL select using datetime, group by date only

    - by Matt
    Is is possible to select a datetime field from a MySQL table and group by the date only? I'm trying to output a list of events that happen at multiple times, grouped by the date it happened on. My table/data looks like this: (the timestamp is a datetime field) 1. 2010-03-21 18:00:00 Event1 2. 2010-03-21 18:30:00 Event2 3. 2010-03-30 13:00:00 Event3 4. 2010-03-30 14:00:00 Event4 I want to output something like this: March 21st 1800 - Event 1 1830 - Event 2 March 30th 1300 - Event 3 1400 - Event 4 Thanks!

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  • Specify which row to return on SQLite Group By

    - by lozzar
    I'm faced with a bit of a difficult problem. I store all the versions of all documents in a single table. Each document has a unique id, and the version is stored as an integer which is incremented everytime there is a new version. I need a query that will only select the latest version of each document from the database. While using GROUP BY works, it appears that it will break if the versions are not inserted in the database in the order of version (ie. it takes the maximum ROWID which will not always be the latest version). Note, that the latest version of each document will most likely be a different number (ie. document A is at version 3, and document B is at version 6). I'm at my wits end, does anybody know how to do this (select all the documents, but only return a single record for each document_id, and that the record returned should have the highest version number)?

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  • mysql query: SELECT DISTINCT column1, GROUP BY column2

    - by Adam
    Right now I have the following query: SELECT name, COUNT(name), time, price, ip, SUM(price) FROM tablename WHERE time >= $yesterday AND time <$today GROUP BY name And what I'd like to do is add a DISTINCT by column 'ip', i.e. SELECT DISTINCT ip FROM tablename So my final output would be all the columns, from all the rows that where time is today, grouped by name (with name count for each repeating name) and no duplicate ip addresses. What should my query look like? (or alternatively, how can I add the missing filter to the output with php)? Thanks in advance.

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  • Grouping with operands question

    - by Filip
    I have a table: mysql> desc kursy_bid; +-----------+-------------+------+-----+---------+-------+ | Field | Type | Null | Key | Default | Extra | +-----------+-------------+------+-----+---------+-------+ | datetime | datetime | NO | PRI | NULL | | | currency | varchar(6) | NO | PRI | NULL | | | value | varchar(10) | YES | | NULL | | +-----------+-------------+------+-----+---------+-------+ 3 rows in set (0.01 sec) I would like to select some rows from a table, grouped by some time interval (can be one day) where I will have the first row and the last row of the group, the max(value) and min(value). I tried: select datetime, (select value order by datetime asc limit 1) open, (select value order by datetime desc limit 1) close, max(value), min(value) from kursy_bid_test where datetime > '2009-09-14 00:00:00' and currency = 'eurpln' group by month(datetime), day(datetime), hour(datetime); but the output is: | open | close | datetime | max(value) | min(value) | +--------+--------+---------------------+------------+------------+ | 1.4581 | 1.4581 | 2009-09-14 00:00:05 | 4.1712 | 1.4581 | | 1.4581 | 1.4581 | 2009-09-14 01:00:01 | 1.4581 | 1.4581 | As you see open and close is the same (but they shouldn't be). What should be the query to do what I want?

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  • How to change out-of-focus text selection color in Xcode?

    - by Jackson
    Okay, I'll bite. I've got really pleasant code/window colors set up in Xcode. Ordinarily, my selection color is very visible. When I am doing a project search and iterating through the results, however, the results list stays in focus and the found text remains out of focus, using a different background color. This color is extremely hard to detect, especially when the text is embedded in a larger code block and the view is shifting around as it scrolls to the results. Here's an example: Left side is in focus (just normal selection), right side is out of focus (during project find) Often it takes a few seconds to find where the heck the selected text is. Unless I'm just missing it, Xcode seems to offer no way to change this particular selection color. Interestingly, it also doesn't seem to follow the selection color from the Appearance panel. Does anyone know a way to change this color or force it to be more visible, short of changing my entire color scheme around?

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  • sql select statement with a group by

    - by user85116
    I have data in 2 tables, and I want to create a report. Table A: tableAID (primary key) name Table B: tableBID (primary key) grade tableAID (foreign key, references Table A) There is much more to both tables, but those are the relevant columns. The query I want to run, conceptually, is this: select TableA.name, avg(TableB.grade) where TableB.tableAID = TableA.tableAID The problem of course is that I'm using an aggregate function (avg), and I can rewrite it like this: select avg(grade), tableAID from TableB group by tableAID but then I only get the ID of TableA, whereas I really need that name column which appears in TableA, not just the ID. Is it possible to write a query to do this in one statement, or would I first need to execute the second query I listed, get the list of id's, then query each record in TableA for the name column... seems to me I'm missing something obvious here, but I'm (quite obviously) not an sql guru...

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  • Top x rows and group by (again)

    - by Tibor Szasz
    Hello, I know it's a frequent question but I just can't figure it out and the examples I found didn't helped. What I learned, the best strategy is to try to find the top and bottom values of the top range and then select the rest, but implementing is a bit tricky. Example table: id | title | group_id | votes I'd like to get the top 3 voted rows from the table, for each group. I'm expecting this result: 91 | hello1 | 1 | 10 28 | hello2 | 1 | 9 73 | hello3 | 1 | 8 84 | hello4 | 2 | 456 58 | hello5 | 2 | 11 56 | hello6 | 2 | 0 17 | hello7 | 3 | 50 78 | hello8 | 3 | 9 99 | hello9 | 3 | 1 I've fond complex queries and examples, but they didn't really helped.

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  • MySQL: filling empty fields with zeroes when using GROUP BY

    - by SaltLake
    I've got MySQL table CREATE TABLE cms_webstat ( ID int NOT NULL auto_increment PRIMARY KEY, TIMESTAMP_X timestamp DEFAULT CURRENT_TIMESTAMP, # ... some other fields ... ) which contains statistics about site visitors. For getting visits per hour I use SELECT hour(TIMESTAMP_X) as HOUR , count(*) AS HOUR_STAT FROM cms_webstat GROUP BY HOUR ORDER BY HOUR DESC which gives me | HOUR | HOUR_STAT | | 24 | 15 | | 23 | 12 | | 22 | 9 | | 20 | 3 | | 18 | 2 | | 15 | 1 | | 12 | 3 | | 9 | 1 | | 3 | 5 | | 2 | 7 | | 1 | 9 | | 0 | 12 | And I'd like to get following: | HOUR | HOUR_STAT | | 24 | 15 | | 23 | 12 | | 22 | 9 | | 21 | 0 | | 20 | 3 | | 19 | 0 | | 18 | 2 | | 17 | 0 | | 16 | 0 | | 15 | 1 | | 14 | 0 | | 13 | 0 | | 12 | 3 | | 11 | 0 | | 10 | 0 | | 9 | 1 | | 8 | 0 | | 7 | 0 | | 6 | 0 | | 5 | 0 | | 4 | 0 | | 3 | 5 | | 2 | 7 | | 1 | 9 | | 0 | 12 | How should I modify the query to get such result? Thanks.

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  • SQL vs MySQL: Rules about aggregate operations and GROUP BY

    - by Phazyck
    In this book I'm currently reading while following a course on databases, the following example of an illegal query using an aggregate operator is given: Find the name and age of the oldest sailor. Consider the following attempt to answer this query: SELECT S.name, S.age FROM Sailors.S The intent is for this query to return not only the maximum age but also the name of the sailors having that age. However, this query is illegal in SQL--if the SELECT clause uses an aggregate operation, then it must use only aggregate operations unless the query contains a GROUP BY clause! Some time later while doing an exercise using MySQL, I faced a similar problem, and made a mistake similar to the one mentioned. However, MySQL didn't complain and just spit out some tables which later turned out not be what I needed. Is the query above really illegal in SQL, but legal in MySQL, and if so, why is that? In what situation would one need to make such a query?

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  • Getting counts of 0 from a query with a double group by

    - by Maltiriel
    I'm trying to write a query that gets the counts for a table (call it item) categorized by two different things, call them type and code. What I'm hoping for as output is the following: Type Code Count 1 A 3 1 B 0 1 C 10 2 A 0 2 B 13 2 C 2 And so forth. Both type and code are found in lookup tables, and each item can have just one type but more than one code, so there's also a pivot (aka junction or join) table for the codes. I have a query that can get this result: Type Code Count 1 A 3 1 C 10 2 B 13 2 C 2 and it looks like (with join conditions omitted): SELECT typelookup.name, codelookup.name, COUNT(item.id) FROM typelookup LEFT OUTER JOIN item JOIN itemcodepivot RIGHT OUTER JOIN codelookup GROUP BY typelookup.name, codelookup.name Is there any way to alter this query to get the results I'm looking for? This is in MySQL, if that matters. I'm not actually sure this is possible all in one query, but if it is I'd really like to know how. Thanks for any ideas.

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  • Working by group by for grouping data into string format

    - by Shantanu Gupta
    I have a table that contains some data given below. It uses a tree like structure i.e. Department SubD1, SubD2 ..... PreSubD1, PreSubD1... PreSubD2, PreSubD2... pk_map_id preferences ImmediateParent Department_Id -------------------- -------------------- -------------------- -------------------- 20 14 5 1 21 15 5 1 22 16 6 1 23 9 4 2 24 4 3 2 25 24 20 2 26 25 20 2 27 23 13 2 I want to group my records on behalf of department then immediate parent then preferences each seperated by ',' i.e. department Immediate Parent preferences 1 5,6 14,15,16 2 4,3,20,13 9,4,24,25,23 and this table also Immediate parent preferences 5 14,15 6 16 4 9 3 4 20 24,25 13 13 In actual scenario all these are my ids which are to be replaced by their string fields. I am using sql server 2k5

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  • how to select and group mysql data based on the follwoing table

    - by user1151680
    how can I achieve the desired result in mysql if my table looks like this. result|year 1 |2011 2 |2011 1 |2011 0 |2011 1 |2012 2 |2012 1 = Won, 2 = lost, 0 = draw Every year can have multiple values like this. Not sure how I can get the desired result like below. year won lost draw totalPlayed 2011 2 1 1 3 2012 1 1 0 2 I have tried the following query but does not get the desired result select year, league_types.league_name, sum(if(result = 1,1,0)) as won, sum(if(result = 0,1,0)) as draw, sum(if(result = 4,1,0)) as noResult, sum(if(result = 2,1,0)) as lost, sum(if(result = 3,1,0)) as tied, sum(if(result > 0 and result < 4,1,0)) as played from match_score_card inner join fixtures on match_score_card.match_id = fixtures.match_id inner join league_types on fixtures.league_id = league_types.league_id where team_id = 1 group by year order by year desc

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  • MySQL query with JOINS and GROUP BY

    - by user1854049
    I'm building a MySQL query but I can't seem to get it right. I have four tables: - customers - orders - sales_rates - purchase_rates There is a 1:n relation 'customernr' between customers and orders. There is a 1:n relation 'ordernr' between orders and sales_rates. There is a 1:n relation 'ordernr' between orders and purchase_rates. What I would like to do is produce an output of all customers with their total purchase and sales amounts. So far I have the following query. SELECT c.customernr, c.customer_name, SUM(sr.sales_price) AS sales_price, SUM(pr.purchase_price) AS purchase_price FROM orders o, customers c, sales_rates sr, purchase_rates pr WHERE o.customernr = c.customernr AND o.ordernr = sr.ordernr AND o.ordernr = pr.ordernr GROUP BY k.bedrijfsnaam The result of the sales_price and purchase_price is far too high. I seem to be getting double counts. What am I doing wrong? Is it possible to perform this in a single query? Thank for your response!

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  • Oracle Group By Issue

    - by m_oLogin
    Hello community, I am strugling with what seems an easy problem to tackle (at least for me in MySQL / SqlServer!) I'll simplify the problem. Let's say I have the following table: Table VOTE ID ID_IDEA DATE_VOTE with ID_IDEA FK(IDEA.ID) 1 3 10/10/10 2 0 09/09/10 3 3 08/08/10 4 3 11/11/10 5 0 06/06/10 6 1 05/05/10 I'm trying to find the latest votes given for each individual idea, meaning I want to return only rows with ID 4, 2 and 6. It seems with Oracle that you can't use GROUP BY without using a function like SUM(), AVG, etc. I'm a bit confused about how it's supposed to work. Please advise, Thanks.

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  • Oracle Utilities Application Framework V4.1 Group Fix 4 available

    - by ACShorten
    Oracle Utilities Application Framework V4.1 Group Fix 4 is available from My Oracle Support as Patch 13523301. This Group Fix contains a number of enhancements and keeps fixes up to date to the latest patch level. The enhancements included in this Group Fix include: UI Hints - In previous group fixes of the Oracle Utilities Application Framework the infrastructure to support UI Hints was introduced. This group fix completes the release of this functionality. Prior to this enhancement, products and implementers typically would build at least one UI Map per Business Object to display and/or maintain the object. Whilst, this can be generated using the UI Map maintenance function and stored, this enhancement allows additional tags and elements to be added to the Business Object directly to allow dynamic generation of the UI Map for maintenance and viewing the object. This reduces the need to generate and build a UI Map at all for that object. This will reduce maintenance effort of maintaining the product and implementation by eliminating the need to maintain the HTML for the UI Map. This also allows lower skilled personnel to maintain the system. Help and working examples are available from the View schema attributes and node names option from the Schema Tips dashboard zone. For example: Note: For examples of the hints, refer to an of the following Business Objects F1_OutcomeStyleLookup, F1-TodoSumEmailType, F1-BOStatusReason or F1-BIGeneralMasterConfig. Setting batch log file names -  By default the batch infrastructure supplied with the Oracle Utilities Application Framework sets the name and location of the log files to set values. In Group Fix 4 a set of user exits have been added to allow implementers and partners to set their own filename and location.  Refer to the Release Notes in the download for more details.

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  • Setting up group disk quotas

    - by Ray
    I am hoping to get some advice in setting up disk quotas. So, I know about: Adding usrquota and grpquota on to /etc/fstab for the file systems that need to be managed. Using edquota to assign disk quotas to users. However, I need to do the last step for multiple users and edquota seems to be a bit troublesome. One solution that I have found is that I can do: sudo edquota -u foo -p bar. This will copy the disk quota of bar to user foo. I was wondering if this is the best solution? I tried setting up group disk quotas but they don't seem to be working. Are group quotas meant to help in the assignment of the same quota to multiple users? Or are they suppose to give a total limit to a set of users? For example, if users A, B, C are in group X then assigning a quota of 20 GB gives each user 20 GB or does it give 20 GB to the entire group X to divide up? I'm interested in doing the former, but not the latter. Right now, I've assigned group disk quotas and they aren't working. So, I guess it is due to my misunderstanding of group disk quotas... My problem is I want to easily give the same quota to multiple users; any suggestions on the best way to do this out of what I've tried above or anything else I may not have thought of? Thank you!

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  • GROUP BY ID range?

    - by d0ugal
    Given a data set like this; +-----+---------------------+--------+ | id | date | result | +-----+---------------------+--------+ | 121 | 2009-07-11 13:23:24 | -1 | | 122 | 2009-07-11 13:23:24 | -1 | | 123 | 2009-07-11 13:23:24 | -1 | | 124 | 2009-07-11 13:23:24 | -1 | | 125 | 2009-07-11 13:23:24 | -1 | | 126 | 2009-07-11 13:23:24 | -1 | | 127 | 2009-07-11 13:23:24 | -1 | | 128 | 2009-07-11 13:23:24 | -1 | | 129 | 2009-07-11 13:23:24 | -1 | | 130 | 2009-07-11 13:23:24 | -1 | | 131 | 2009-07-11 13:23:24 | -1 | | 132 | 2009-07-11 13:23:24 | -1 | | 133 | 2009-07-11 13:23:24 | -1 | | 134 | 2009-07-11 13:23:24 | -1 | | 135 | 2009-07-11 13:23:24 | -1 | | 136 | 2009-07-11 13:23:24 | -1 | | 137 | 2009-07-11 13:23:24 | -1 | | 138 | 2009-07-11 13:23:24 | 1 | | 139 | 2009-07-11 13:23:24 | 0 | | 140 | 2009-07-11 13:23:24 | -1 | +-----+---------------------+--------+ How would I go about grouping the results by day 5 records at a time. The above results is part of the live data, there is over 100,000 results rows in the table and its growing. Basically I want to measure the change over time, so want to take a SUM of the result every X records. In the real data I'll be doing it ever 100 or 1000 but for the data above perhaps every 5. If i could sort it by date I would do something like this; SELECT DATE_FORMAT(date, '%h%i') ym, COUNT(result) 'Total Games', SUM(result) as 'Score' FROM nn_log GROUP BY ym; I can't figure out a way of doing something similar with numbers. The order is sorted by the date but I hope to split the data up every x results. It's safe to assume there are no blank rows. Doing it above with the data you could do multiple selects like; SELECT SUM(result) FROM table LIMIT 0,5; SELECT SUM(result) FROM table LIMIT 5,5; SELECT SUM(result) FROM table LIMIT 10,5; Thats obviously not a very good way to scale up to a bigger problem. I could just write a loop but I'd like to reduce the number of queries.

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  • MySQL Update query with left join and group by

    - by Rob
    I am trying to create an update query and making little progress in getting the right syntax. The following query is working: SELECT t.Index1, t.Index2, COUNT( m.EventType ) FROM Table t LEFT JOIN MEvents m ON (m.Index1 = t.Index1 AND m.Index2 = t.Index2 AND (m.EventType = 'A' OR m.EventType = 'B') ) WHERE (t.SpecialEventCount IS NULL) GROUP BY t.Index1, t.Index2 It creates a list of triplets Index1,Index2,EventCounts. It only does this for case where t.SpecialEventCount is NULL. The update query I am trying to write should set this SpecialEventCount to that count, i.e. COUNT(m.EventType) in the query above. This number could be 0 or any positive number (hence the left join). Index1 and Index2 together are unique in Table t and they are used to identify events in MEvent. How do I have to modify the select query to become an update query? I.e. something like UPDATE Table SET SpecialEventCount=COUNT(m.EventType)..... but I am confused what to put where and have failed with numerous different guesses.

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  • Ext3 fs: Block bitmap for group 1 not in group (block 0). is fs dead?

    - by ip
    My company has a server with one big partition with Mysql database and php files. Now this partition seems to be corrupted, as reported from kernel messages when I tried to mount it manually: [329862.817837] EXT3-fs error (device loop1): ext3_check_descriptors: Block bitmap for group 1 not in group (block 0)! [329862.817846] EXT3-fs: group descriptors corrupted! I've tried to recovery it running tools from a PLD livecd. These are the tools I have tested: - e2retrieve - testdisk - photorec - dd_rescue/dd_rhelp - ddrescue - fsck.ext2 - e2salvage without any success. dumpe2fs 1.41.3 (12-Oct-2008) Filesystem volume name: /dev/sda3 Last mounted on: <not available> Filesystem UUID: dd51610b-6de0-4392-a6f3-67160dbc0343 Filesystem magic number: 0xEF53 Filesystem revision #: 1 (dynamic) Filesystem features: has_journal filetype sparse_super Default mount options: (none) Filesystem state: not clean with errors Errors behavior: Continue Filesystem OS type: Linux Inode count: 9502720 Block count: 18987570 Reserved block count: 949378 Free blocks: 11555345 Free inodes: 11858398 First block: 0 Block size: 4096 Fragment size: 4096 Blocks per group: 32768 Fragments per group: 32768 Inodes per group: 16384 Inode blocks per group: 512 Last mount time: Wed Mar 24 09:31:03 2010 Last write time: Mon Apr 12 11:46:32 2010 Mount count: 10 Maximum mount count: 30 Last checked: Thu Jan 1 01:00:00 1970 Check interval: 0 (<none>) Reserved blocks uid: 0 (user root) Reserved blocks gid: 0 (group root) First inode: 11 Inode size: 128 Journal inode: 8 Journal backup: inode blocks dumpe2fs: A block group is missing an inode table while reading journal inode e2fsck 1.41.3 (12-Oct-2008) fsck.ext3: Group descriptors look bad... trying backup blocks... fsck.ext3: A block group is missing an inode table while checking ext3 journal for /dev/sda3 I tried also backup superblocks, same error result. There's any other tools I have to test before considering these disk definitely unrecoverable? Many thanks, ip

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  • Organizational characteristics that impact the selection of Development Methodology concepts applied to a project

    Based on my experience, no one really follows a specific methodology exactly as it is formally designed. In fact, the key concepts of a few methodologies are usually combined to form a hybrid methodology for each project based on the current organizational makeup and the project need/requirements to be accomplished. Organizational characteristics that impact the selection of methodology concepts applied to a project. Prior subject knowledge pertaining to a project can be critical when deciding on what methodology or combination of methodologies to apply to a project. For example, if a project is very straight forward, and the development staff has experience in developing  that are similar, then the waterfall method could possibly be the best choice because little to no research is needed  in order to complete the project tasks and there is very little need for changes to occur.  On the other hand, if the development staff has limited subject knowledge or the requirements/specification of the project could possibly change as the project progresses then the use of spiral, iterative, incremental, agile, or any combination would be preferred. The previous methodologies used by an organization typically do not change much from project to project unless the needs of a project dictate differently. For example, if the waterfall method is the preferred development methodology then most projects will be developed by the waterfall method. Depending on the time allotted to a project each day can impact the selection of a development methodology. In one example, if the staff can only devote a few hours a day to a project then the incremental methodology might be ideal because modules can be added to the final project as they are developed. On the other hand, if daily time allocation is not an issue, then a multitude of methodologies could work well for a project. Project characteristics that impact the selection of methodology concepts applied to a project. The type of project being developed can often dictate the type of methodology used for the project. Based on my experience, projects that tend to have a lot of user interaction, follow a more iterative, incremental, or agile approach typically using a prototype that develops into a final project. These methodologies desire back and forth communication between users, clients, and developers to allow for requirements to change and functionality to be enhanced. Conversely, limited interaction applications or automated services can still sometimes get away with using the waterfall or transactional approach. The timeline of a project can also force an organization to prefer a particular methodology over the rest. For instance, if the project must be completed within 24 hours, then there is very little time for discussions back and forth between clients, users and the development team. In this scenario, the waterfall method would be perfect because the only interaction with the client occurs prior to a development project to outline the system requirements, and the development team can quickly move through the software development stages in order to complete the project within the deadline. If the team had more time, then the other methodologies could also be considered because there is more time for client and users to review the project and make changes as they see fit, and/or allow for more time to review the project in order to enhance the business performance and functionality. Sometimes the client and or user involvement can dictate the selection of methodologies applied to a project. One example of this is if a client is highly motivated to get a project completed and desires to play an active part in the development process then the agile development approach would work perfectly with this client because it allows for frequent interaction between clients, users and the development team. The inverse of this situation is a client that just wants to provide the project requirements and only wants to get involved when the project is to be delivered. In this case the waterfall method would work well because there is no room for changes and no back and forth between the users, clients or the development team.

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  • using group_concat in PHPMYADMIN will show the result as [BLOB - 3B]

    - by Itay Moav
    I have a query which uses the GROUP_CONCAT of mysql on an integer field. I am using PHPMYADMIN to develop this query. My problem that instead of showing 1,2 which is the result of the concatenated field, I get [BLOB - 3B]. Query is SELECT rec_id,GROUP_CONCAT(user_id) FROM t1 GROUP BY rec_id (both fields are unsigned int, both are not unique) What should I add to see the actual results?

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