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  • Got blue screen with a warning that I boot loader may not be properly configured, workaround?

    - by JohnHF
    After running sudo apt-get update got this message: Configuring grub-pc You chose not to install GRUB to any devices. If you continue, the boot loader may not be properly configured, and when your computer next starts up it will use whatever was previously in the boot sector. If there is an earlier version of GRUB 2 in the boot sector, it may be unable to load modules or handle the current configuration file. If you are already running a different boot loader and want to carry on doing so, or if this is a special environment where you do not need a boot loader, then you should continue anyway. Otherwise, you should install GRUB somewhere. Continue without installing GRUB? <Yes> <No> Apparently there is a bug in ubuntu 10.04. But this hang the system. Any ideas on how to fix this? All I wanted was to install gcc that is missing.

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  • Creating array from two arrays

    - by binoculars
    I'm having troubles trying to create a certain array. Basicly, I have an array like this: [0] => Array ( [id] => 12341241 [type] => "Blue" ) [1] => Array ( [id] => 52454235 [type] => "Blue" ) [2] => Array ( [id] => 848437437 [type] => "Blue" ) [3] => Array ( [id] => 387372723 [type] => "Blue" ) [4] => Array ( [id] => 73732623 [type] => "Blue" ) ... Next, I have an array like this: [0] => Array ( [id] => 34141 [type] => "Red" ) [1] => Array ( [id] => 253532 [type] => "Red" ) [2] => Array ( [id] => 94274 [type] => "Red" ) I want to construct an array, which is a combination of the two above, using this rule: after 3 Blues, there must be a Red: Blue1 Blue2 Blue3 Red1 Blue4 Blue5 Blue6 Red2 Blue7 Blue8 Blue9 Red3 Note that the their can be more Red's than Blue's, but also more Blue's than Red's. If the Red's run out, it should begin with the first one again. Example: let's say there are only two Red's: Blue1 Blue2 Blue3 Red1 Blue4 Blue5 Blue6 Red2 Blue7 Blue8 Blue9 Red1 ... ... If the Blue's run out, the Red's should append until they run out too. Example: let's say there are 5 Blue's, and 5 Red's: Blue1 Blue2 Blue3 Red1 Blue4 Blue5 Red2 Red3 Red4 Red5 Note: the arrays come from mysql-fetches. Maybe it's better to fetch them while building the new array? Anyway, the while-loops got to me, I can't figure it out... Any help is much appreciated!

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  • Best practise for meta tags in various languages

    - by Jack Lockyer
    We have a global site, all hosted on one .com domain (www.website.com/en www.website.com/es www.website.com/pt www.website.com/ru etc) each language sub directory is identical to one another (apart from being in different languages) My question is, should I translate each meta keyword for each page or just use the english versions? e.g. English page about private jets : keyword "private jet" French version of exactly the same page : keyword "private jet" or "jet privé" If anyone knows whether language specific keywords carry any weight in search engines when the actual website is a .com and not a country specific domain, that would be really helpful! Thanks in advance!

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  • Tab autocomplete in terminal is not behaving properly

    - by CaptSaltyJack
    There's something odd about my autocomplete in the gnome terminal. I used to be able to type cp Downtab to get cp Downloads/, and then type Jettab to end up with cp Downloads/Jet\ Pack\ Instructions.pdf But now, when I have cp Down typed and hit tab, I get cp Downloads with a space afterwards. And if I backspace that and make it say cp Downloads/Jet and hit tab, I get cp Downloads/Jet Pack Instructions.pdf without the backslashes. It wasn't like this before. How do I fix this? EDIT: There's a problem with my /etc/bash_completion file, it seems. Just not sure what.

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  • iPhone Image Processing--matrix convolution

    - by James
    I am implementing a matrix convolution blur on the iPhone. The following code converts the UIImage supplied as an argument of the blur function into a CGImageRef, and then stores the RGBA values in a standard C char array. CGImageRef imageRef = imgRef.CGImage; int width = imgRef.size.width; int height = imgRef.size.height; CGColorSpaceRef colorSpace = CGColorSpaceCreateDeviceRGB(); unsigned char *pixels = malloc((height) * (width) * 4); NSUInteger bytesPerPixel = 4; NSUInteger bytesPerRow = bytesPerPixel * (width); NSUInteger bitsPerComponent = 8; CGContextRef context = CGBitmapContextCreate(pixels, width, height, bitsPerComponent, bytesPerRow, colorSpace, kCGImageAlphaPremultipliedLast | kCGBitmapByteOrder32Big); CGContextDrawImage(context, CGRectMake(0, 0, width, height), imageRef); CGContextRelease(context); Then the pixels values stored in the pixels array are convolved, and stored in another array. unsigned char *results = malloc((height) * (width) * 4); Finally, these augmented pixel values are changed back into a CGImageRef, converted to a UIImage, and the returned at the end of the function with the following code. context = CGBitmapContextCreate(results, width, height, bitsPerComponent, bytesPerRow, colorSpace, kCGImageAlphaPremultipliedLast | kCGBitmapByteOrder32Big); CGImageRef finalImage = CGBitmapContextCreateImage(context); UIImage *newImage = [UIImage imageWithCGImage:CGBitmapContextCreateImage(context)]; CGImageRelease(finalImage); NSLog(@"edges found"); free(results); free(pixels); CGColorSpaceRelease(colorSpace); return newImage; This works perfectly, once. Then, once the image is put through the filter again, very odd, unprecedented pixel values representing input pixel values that don't exist, are returned. Is there any reason why this should work the first time, but then not afterward? Beneath is the entirety of the function. -(UIImage*) blur:(UIImage*)imgRef { CGImageRef imageRef = imgRef.CGImage; int width = imgRef.size.width; int height = imgRef.size.height; CGColorSpaceRef colorSpace = CGColorSpaceCreateDeviceRGB(); unsigned char *pixels = malloc((height) * (width) * 4); NSUInteger bytesPerPixel = 4; NSUInteger bytesPerRow = bytesPerPixel * (width); NSUInteger bitsPerComponent = 8; CGContextRef context = CGBitmapContextCreate(pixels, width, height, bitsPerComponent, bytesPerRow, colorSpace, kCGImageAlphaPremultipliedLast | kCGBitmapByteOrder32Big); CGContextDrawImage(context, CGRectMake(0, 0, width, height), imageRef); CGContextRelease(context); height = imgRef.size.height; width = imgRef.size.width; float matrix[] = {0,0,0,0,1,0,0,0,0}; float divisor = 1; float shift = 0; unsigned char *results = malloc((height) * (width) * 4); for(int y = 1; y < height; y++){ for(int x = 1; x < width; x++){ float red = 0; float green = 0; float blue = 0; int multiplier=1; if(y>0 && x>0){ int index = (y-1)*width + x; red = matrix[0]*multiplier*(float)pixels[4*(index-1)] + matrix[1]*multiplier*(float)pixels[4*(index)] + matrix[2]*multiplier*(float)pixels[4*(index+1)]; green = matrix[0]*multiplier*(float)pixels[4*(index-1)+1] + matrix[1]*multiplier*(float)pixels[4*(index)+1] + matrix[2]*multiplier*(float)pixels[4*(index+1)+1]; blue = matrix[0]*multiplier*(float)pixels[4*(index-1)+2] + matrix[1]*multiplier*(float)pixels[4*(index)+2] + matrix[2]*multiplier*(float)pixels[4*(index+1)+2]; index = (y)*width + x; red = red+ matrix[3]*multiplier*(float)pixels[4*(index-1)] + matrix[4]*multiplier*(float)pixels[4*(index)] + matrix[5]*multiplier*(float)pixels[4*(index+1)]; green = green + matrix[3]*multiplier*(float)pixels[4*(index-1)+1] + matrix[4]*multiplier*(float)pixels[4*(index)+1] + matrix[5]*multiplier*(float)pixels[4*(index+1)+1]; blue = blue + matrix[3]*multiplier*(float)pixels[4*(index-1)+2] + matrix[4]*multiplier*(float)pixels[4*(index)+2] + matrix[5]*multiplier*(float)pixels[4*(index+1)+2]; index = (y+1)*width + x; red = red+ matrix[6]*multiplier*(float)pixels[4*(index-1)] + matrix[7]*multiplier*(float)pixels[4*(index)] + matrix[8]*multiplier*(float)pixels[4*(index+1)]; green = green + matrix[6]*multiplier*(float)pixels[4*(index-1)+1] + matrix[7]*multiplier*(float)pixels[4*(index)+1] + matrix[8]*multiplier*(float)pixels[4*(index+1)+1]; blue = blue + matrix[6]*multiplier*(float)pixels[4*(index-1)+2] + matrix[7]*multiplier*(float)pixels[4*(index)+2] + matrix[8]*multiplier*(float)pixels[4*(index+1)+2]; red = red/divisor+shift; green = green/divisor+shift; blue = blue/divisor+shift; if(red<0){ red=0; } if(green<0){ green=0; } if(blue<0){ blue=0; } if(red>255){ red=255; } if(green>255){ green=255; } if(blue>255){ blue=255; } int realPos = 4*(y*imgRef.size.width + x); results[realPos] = red; results[realPos + 1] = green; results[realPos + 2] = blue; results[realPos + 3] = 1; }else { int realPos = 4*((y)*(imgRef.size.width) + (x)); results[realPos] = 0; results[realPos + 1] = 0; results[realPos + 2] = 0; results[realPos + 3] = 1; } } } context = CGBitmapContextCreate(results, width, height, bitsPerComponent, bytesPerRow, colorSpace, kCGImageAlphaPremultipliedLast | kCGBitmapByteOrder32Big); CGImageRef finalImage = CGBitmapContextCreateImage(context); UIImage *newImage = [UIImage imageWithCGImage:CGBitmapContextCreateImage(context)]; CGImageRelease(finalImage); free(results); free(pixels); CGColorSpaceRelease(colorSpace); return newImage;} THANKS!!!

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  • I will need a formula showing counts, totals and sub-totals for data set from different sheet

    - by Sapthagiri
    I am using MS2003 EXCEL. I have a cell in Sheet 1 with a color value and totals, with sub-totals. On sheet 2, I have a data set with 3 columns (colors, dress, type). On Sheet 1, I will need a tabulation showing Totals for Colors, with totals at sub-group of dress (shirt,pants) split by type totals (Full, Half, Tee) Below table represents my Data set in Sheet 2 Colors Make Dress Type -------------------------------- Red Arrow shirt full Red Levi shirt half blue Rugger Pant full yellow Wrangler shirt tee yellow Rugger Pant half yellow Arrow shirt tee yellow Wrangler Pant half Green Rugger Pant full Red Levi shirt tee blue Rugger Pant full blue Arrow shirt full blue Wrangler Pant half Green Levi shirt full I will need a formula showing counts, totals and sub-totals on Sheet 1 for data set from Sheet 2. Refer my table below which represent my expected data on Sheet 1, total Shirt Full Half Tees Pants Full Shorts Red 10 8 4 3 1 2 1 1 Blue Green Yellow Please note I am not looking for a Pivot table solution.

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  • Image 1 becomes image 2 with sliding effect from left to right?

    - by Paul
    I would like to show a second image appearing while a "door" is closing on my character. I've got my character in the middle of the screen and a door coming from the left. When the door passes my character, I would like to have this second image appearing little by little. So far, I've gotten by with fadingOut the character and then fadingIn my second image of the character at the same position when the door is completely closed, but I would like to have both of them at the same time. (the effect that image 1 becomes image 2 when the door is sliding from left to right). Would you know how to do this with Cocos2d? Here are the images : at first, the character is blue, and the door is coming from the left : Then, behind the black door, the character becomes red, but only behind this door, so it stays blue when the door is not on him, and will become completely red when the door passes the character : EDIT : with this code, the black door hides the red and blue rectangles : (And if i add each of my layers at a different depth, and only use GL_LESS, same thing) blue.position = ccp( size.width*0.5 , size.height/2 ); red.position = ccp( size.width*0.46 , size.height/2 ); black.position = ccp( size.width*0.1 , size.height/2 ); glEnable(GL_DEPTH_TEST); [batch addChild:red z:0]; [batch addChild:black z:2]; glDepthFunc(GL_GREATER); [batch addChild:blue z:1]; glDepthFunc(GL_LESS); id action1 = [CCMoveTo actionWithDuration:3 position:ccp(size.width,size.height/2)]; [black runAction: [CCSequence actions:action1, nil]];

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  • What's the best way to compare blocks in a matching game that can be multiple colors?

    - by Ryan Detzel
    I have a match 3-4 game and the blocks can be one of 7 colors. There are an addition 7 blocks that are a mix of the original 7 colors so for example there is a red and blue block and there is also a red/blue block which can be matched with either the red or the blue. My original thought is just to use binary operations so. int red = 0x000000001; int blue = 0x000000010; int redblue = 0x000000011; Then just do an & operation so see if they match. Does this sound like a decent plan or am I over complicating it? edit: Better yet so it's more readable. int red = 1; int blue = 2; int red_blue = 3; int yellow = 4; int red_yellow = 5; maybe as defines or static vars?

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  • IIS 6 nested virtual directory redirection

    - by threedaysatsea
    We're running IIS 6 on a WinServer2k3 box and we're having some trouble with the following problem: E-mails were sent out to users asking them to go to the following URL: alias.contoso.com/directory2/view.aspx?queryparam1=no&queryparam2=blue However, the URLS are actually supposed to be: server.contoso.com/directory2/view.aspx?queryparam1=no&queryparam2=blue It's too late to recall all of the e-mails, and we'd like to redirect traffic to make this as seamless as possible for our users. The real problem here is that the server (server.contoso.com) is hosting the alias (alias.contoso.com) as a redirect thusly, and the existing redirect we need to keep functional: Default Web Site (server.contoso.com) --Directory1 --Directory2 --Directory3 Redirection to Directory3 (alias.contoso.com) --Essentially alias.contoso.com will take the user to server.contoso.com/Directory3 Is there any way to host a separate redirect inside of the existing redirect? We need to keep alias.contoso.com taking the user to server.contoso.com/Directory3 but also make alias.contoso.com/directory2/view.aspx?queryparam1=no&queryparam2=blue point to server.contoso.com/directory2/view.aspx?queryparam1=no&queryparam2=blue Any tips? Is this even possible?

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  • Nearest color algorithm using Hex Triplet

    - by Lijo
    Following page list colors with names http://en.wikipedia.org/wiki/List_of_colors. For example #5D8AA8 Hex Triplet is "Air Force Blue". This information will be stored in a databse table (tbl_Color (HexTriplet,ColorName)) in my system Suppose I created a color with #5D8AA7 Hex Triplet. I need to get the nearest color available in the tbl_Color table. The expected anaser is "#5D8AA8 - Air Force Blue". This is because #5D8AA8 is the nearest color for #5D8AA7. Do we have any algorithm for finding the nearest color? How to write it using C# / Java? REFERENCE http://stackoverflow.com/questions/5440051/algorithm-for-parsing-hex-into-color-family http://stackoverflow.com/questions/6130621/algorithm-for-finding-the-color-between-two-others-in-the-colorspace-of-painte Suggested Formula: Suggested by @user281377. Choose the color where the sum of those squared differences is minimal (Square(Red(source)-Red(target))) + (Square(Green(source)-Green(target))) +(Square(Blue(source)-Blue(target)))

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  • Filling up the empty blocks when the player touches the safe zone again! using cocos2d

    - by user3445020
    Hi guys i am stuck with filling up the data of all the blocks which are empty like the ones in the image. As you can see there i have a pacman like object where i will be moving around. But when you are in the empty space where there are no Blue boxes available i should be able to add new blocks in the path of my pacman and when it touches any other blue boxes like in the below case if my pacman touches the top row of the blue box i should be able to fill all the empty boxed inside the border of the path created by pacman. For now i am using a 2d bool array to store all the filled boxed info like if there is a box inside i am making that cell in an array as true. But how to fill the area with blue boxes after player finishes his path ? Any help would be great thank you. More info about this problem is here: filling the empty spaces in a certain region in a grid using c++ Same problem

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  • Boundary fill problem

    - by Taaseen
    hi...Im stuck in this bunch of codes...i cant get the pixel to fill up the circle??...any help #include<iostream> #include<glut.h> struct Color{ float red, green, blue; }; Color getPixel(int x, int y){ // gets the color of the pixel at (x,y) Color c; float color[4]; glReadPixels(x,y,1,1,GL_RGBA, GL_FLOAT, color); c.red = color[0]; c.green = color[1]; c.blue = color[2]; return c; } void setPixel(int x, int y, Color c){ glClear(GL_COLOR_BUFFER_BIT | GL_DEPTH_BUFFER_BIT); glPushAttrib(GL_ALL_ATTRIB_BITS); glColor3f(c.red, c.green, c.blue); glBegin(GL_POINTS); glVertex2i(x,y); glEnd(); glPopAttrib(); glFlush(); } void init() { glClearColor(1.0,1.0,1.0,0.0); gluOrtho2D(0.0,300.0,0.0,300.0); } void drawPixel(int x,int y) { glBegin(GL_POINTS); glVertex2i(x,y); glEnd(); glFlush(); } void Boundary_fill(int x,int y,Color thisColor){ Color boundary_color; boundary_color.red=0.0; boundary_color.green=1.0; boundary_color.blue=0.0; Color nextpixel=getPixel(x,y); if((nextpixel.red!=boundary_color.red)&&(nextpixel.blue!=boundary_color.blue)&&(nextpixel.green!=boundary_color.green) && (nextpixel.red!=thisColor.red)&& (nextpixel.blue!=thisColor.blue)&& (nextpixel.green!=thisColor.green)){ setPixel(x,y,thisColor); Boundary_fill((x+1),y,thisColor); Boundary_fill((x-1),y,thisColor); Boundary_fill(x,(y+1),thisColor); Boundary_fill(x,(y-1),thisColor); } } void draw(int x1,int y1, int x, int y){ drawPixel(x1+x,y1+y);//quadrant1 drawPixel(x1+x,y1-y);//quadrant2 drawPixel(x1-x,y1+y);//quadrant3 drawPixel(x1-x,y1-y);//quadrant4 drawPixel(x1+y,y1+x);//quadrant5 drawPixel(x1+y,y1-x);//quadrant6 drawPixel(x1-y,y1+x);//quadrant7 drawPixel(x1-y,y1-x);//quadrant8 } void circle(int px,int py,int r){ int a,b; float p; a=0; b=r; p=(5/4)-r; while(a<=b){ draw(px,py,a,b); if(p<0){ p=p+(2*a)+1; } else{ b=b-1; p=p+(2*a)+1-(2*b); } a=a+1; } } void Circle(void) { Color thisColor; thisColor.red=1.0; thisColor.blue=0.0; thisColor.green=0.0; glClear(GL_COLOR_BUFFER_BIT); glColor3f(0.0,1.0,0.0); glPointSize(2.0); int x0 = 100; int y0 = 150; circle(x0,y0,50); glColor3f(thisColor.red,thisColor.blue,thisColor.green); Boundary_fill(x0,y0,thisColor); } void main(int argc, char**argv) { glutInit(&argc,argv); glutInitDisplayMode(GLUT_SINGLE | GLUT_RGB); glutInitWindowSize(400,400); glutInitWindowPosition(1,1); glutCreateWindow("Boundary fill in a circle:Taaseen And Abhinav"); init(); glutDisplayFunc(Circle); glutMainLoop(); }

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  • Greyscale Image from YUV420p data

    - by fergs
    From what I have read on the internet the Y value is the luminance value and can be used to create a grey scale image. The following link: http://www.bobpowell.net/grayscale.htm, has some C# code on working out the luminance of a bitmap image : { Bitmap bm = new Bitmap(source.Width,source.Height); for(int y=0;y<bm.Height;y++) public Bitmap ConvertToGrayscale(Bitmap source) { for(int x=0;x<bm.Width;x++) { Color c=source.GetPixel(x,y); int luma = (int)(c.R*0.3 + c.G*0.59+ c.B*0.11); bm.SetPixel(x,y,Color.FromArgb(luma,luma,luma)); } } return bm; } I have a method that returns the YUV values and have the Y data in a byte array. I have the current piece of code and it is failing on Marshal.Copy – attempted to read or write protected memory. public Bitmap ConvertToGrayscale2(byte[] yuvData, int width, int height) { Bitmap bmp; IntPtr blue = IntPtr.Zero; int inputOffSet = 0; long[] pixels = new long[width * height]; try { for (int y = 0; y < height; y++) { int outputOffSet = y * width; for (int x = 0; x < width; x++) { int grey = yuvData[inputOffSet + x] & 0xff; unchecked { pixels[outputOffSet + x] = UINT_Constant | (grey * INT_Constant); } } inputOffSet += width; } blue = Marshal.AllocCoTaskMem(pixels.Length); Marshal.Copy(pixels, 0, blue, pixels.Length); // fails here : Attempted to read or write protected memory bmp = new Bitmap(width, height, width, PixelFormat.Format24bppRgb, blue); } catch (Exception) { throw; } finally { if (blue != IntPtr.Zero) { Marshal.FreeHGlobal(blue); blue = IntPtr.Zero; } } return bmp; } Any help would be appreciated?

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  • jquery toggle and fade in one function?

    - by tony noriega
    I was wondering if toggle() and fadeIn() could be used in one function... i got this to work, but it only fades in after the second click... not on first click of the toggle. $(document).ready(function() { $('#business-blue').hide(); $('a#biz-blue').click(function() { $('#business-blue').toggle().fadeIn('slow'); return false; }); // hides the slickbox on clicking the noted link $('a#biz-blue-hide').click(function() { $('#business-blue').hide('fast'); return false; }); }); <a href="#" id="biz-blue">Learn More</a> <div id="business-blue" style="border:1px soild #00ff00; background:#c6c1b8; height:600px; width:600px; margin:0 auto; position:relative;"> <p>stuff here</p> </div>

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  • Four-color theorem in Prolog (using a dynamic predicate)

    - by outa
    Hi, I'm working on coloring a map according to the four-color theorem (http://en.wikipedia.org/wiki/Four_color_theorem) with SWI-Prolog. So far my program looks like this: colour(red). colour(blue). map_color(A,B,C) :- colour(A), colour(B), colour(C), C \= B, C \= A. (the actual progam would be more complex, with 4 colors and more fields, but I thought I'd start out with a simple case) Now, I want to avoid double solutions that have the same structure. E.g. for a map with three fields, the solution "red, red, blue" would have the same structure as "blue, blue, red", just with different color names, and I don't want both of them displayed. So I thought I would have a dynamic predicate solution/3, and call assert(solution(A,B,C)) at the end of my map_color predicate. And then, for each solution, check if they already exist as a solution/3 fact. The problem is that I would have to assert something like solution(Color1,Color1,Color2), i.e. with variables in order to make a unification check. And I can't think of a way to achieve this. So, the question is, what is the best way to assert a found solution and then make a unification test so that "red, red, blue" would unify with "blue, blue, red"?

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  • Java image conversion to RGB565

    - by Vladimir
    I try to convert image to RGB565 format. I read this image: BufferedImage bufImg = ImageIO.read(imagePathFile); sendImg = new BufferedImage(CONTROLLER_LCD_WIDTH/*320*/, CONTROLLER_LCD_HEIGHT/*240*/, BufferedImage.TYPE_USHORT_565_RGB); sendImg .getGraphics().drawImage(bufImg, 0, 0, CONTROLLER_LCD_WIDTH/*320*/, CONTROLLER_LCD_HEIGHT/*240*/, null); Here is it: Then I convert it to RGB565: int numByte=0; byte[] OutputImageArray = new byte[CONTROLLER_LCD_WIDTH*CONTROLLER_LCD_HEIGHT*2]; int i=0; int j=0; int len = OutputImageArray.length; for (i=0;i<CONTROLLER_LCD_WIDTH;i++) { for (j=0;j<CONTROLLER_LCD_HEIGHT;j++) { Color c = new Color(sendImg.getRGB(i, j)); int aRGBpix = sendImg.getRGB(i, j); int alpha; int red = c.getRed(); int green = c.getGreen(); int blue = c.getBlue(); //RGB888 red = (aRGBpix >> 16) & 0x0FF; green = (aRGBpix >> 8) & 0x0FF; blue = (aRGBpix >> 0) & 0x0FF; alpha = (aRGBpix >> 24) & 0x0FF; //RGB565 red = red >> 3; green = green >> 2; blue = blue >> 3; //A pixel is represented by a 4-byte (32 bit) integer, like so: //00000000 00000000 00000000 11111111 //^ Alpha ^Red ^Green ^Blue //Converting to RGB565 short pixel_to_send = 0; int pixel_to_send_int = 0; pixel_to_send_int = (red << 11) | (green << 5) | (blue); pixel_to_send = (short) pixel_to_send_int; //dividing into bytes byte byteH=(byte)((pixel_to_send >> 8) & 0x0FF); byte byteL=(byte)(pixel_to_send & 0x0FF); //Writing it to array - High-byte is second OutputImageArray[numByte]=byteH; OutputImageArray[numByte+1]=byteL; numByte+=2; } } Then I try to restore this from resulting array OutputImageArray: i=0; j=0; numByte=0; BufferedImage NewImg = new BufferedImage(CONTROLLER_LCD_WIDTH, CONTROLLER_LCD_HEIGHT, BufferedImage.TYPE_USHORT_565_RGB); for (i=0;i<CONTROLLER_LCD_WIDTH;i++) { for (j=0;j<CONTROLLER_LCD_HEIGHT;j++) { int curPixel=0; int alpha=0x0FF; int red; int green; int blue; byte byteL=0; byte byteH=0; byteH = OutputImageArray[numByte]; byteL = OutputImageArray[numByte+1]; curPixel= (byteH << 8) | (byteL); //RGB565 red = (curPixel >> (6+5)) & 0x01F; green = (curPixel >> 5) & 0x03F; blue = (curPixel) & 0x01F; //RGB888 red = red << 3; green = green << 2; blue = blue << 3; //aRGB curPixel = 0; curPixel = (alpha << 24) | (red << 16) | (green << 8) | (blue); NewImg.setRGB(i, j, curPixel); numByte+=2; } } I output this restored image. But I see that it looks very poor. I expected the lost of pictures quality. But as I thought, this picture has to have almost the same quality as the previous picture. - Is it right? Is my code right?

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  • Python: How To copy function parameters into object's fields effortlessly ?

    - by bandana
    Many times I have member functions that copy parameters into object's fields. For Example: class NouveauRiches(object): def __init__(self, car, mansion, jet, bling): self.car = car self.mansion = mansion self.jet = jet self.bling = bling Is there a python language construct that would make the above code less tedious? One could use *args: def __init__(self, *args): self.car, self.mansion, self.jet, self.bling = args +: less tedious -: function signature not revealing enough. need to dive into function code to know how to use function -: does not raise a TypeError on call with wrong # of parameters (but does raise a ValueError) Any other ideas? (Whatever your suggestion, make sure the code calling the function does stays simple)

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  • Windows Vista Nested Desktop Folders Problem

    - by Samuel Walker
    I have no idea how, nor when this happened, and it's started to really quite annoy me. When navigating through Explorer, by clicking on Icons I have C:\Users\Samuel\Desktop (Icon is the blue special Desktop icon), which contains the items I see on my Desktop. I then have the following folder: C:\Users\Samuel\Desktop (Icon is the standard yellow folder icon), which contains many program shortcuts, and is completely seperate from the other C:\Users\Samuel\Desktop Then in the Yellow Icon Desktop I have the sub-folder Desktop with the blue icon that is a direct mirror of the blue C:\Users\Samuel\Desktop folder (as in a new folder / file shows up in both). In explorer when I directly type C:\Users\Samuel\Desktop I am taken to the Yellow folder version. If I go to C:\Users\Samuel\Desktop\Desktop I am taken to the Blue folder version. Finally, from cmd cd'ing to C:\Users\Samuel\Desktop takes me to the Yellow folder version whilst C:\Users\Samuel\Desktop\Desktop takes me to the blue folder version. How on earth can I get rid of the yellow folder version leaving the blue C:\Users\Samuel\Desktop. I can't delete either as it says they're in use. UPDATE: Ok, so it looks like doing a dir from cmd lists only one Desktop folder - the Yellow one. In addition, it looks like I can't delete either of them (given that they both contain my 'Desktop'

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  • My SSD stopped working as it ends up in blue death right after windows 7 launches, how can I reset it for new windows install?

    - by HattoriHanzo
    As I mentioned in the title my SSD suddenly started to fail as after launching Windows 7 it goes straight to completely idle and after a few minutes it goes to blue death and restarts. I have an another HD with a windows xp on it and it works fine and I can also see the SSD and can access everything on it. Windows 7 on the SSD does work in safe mode though yet I didn't manage to find out what causes the problem. Since I can sill access the files and save them to another HD I'm looking for the best way to wipe and reinstall Windows 7. I have yet failed to find an easy to follow (or even understand) guide, different sources on the internet recommend different ways of doing this. And some guides are just simply full of terms I have no clue about. It's an OCZ Vertex 2 120GB. I"d very much appreciate if someone could give me an advice on what I should do, preferably in a way so I could regain the best possible performance as well. it doesn't matter if I don't understand the science behind it as long as I can follow the steps. Thanks!

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  • Diagonal line of sight with two corners

    - by Ash Blue
    Right now I'm using Bresenham's line algorithm for line of sight. The problem is I've found an edge case where players can look through walls. Occurs when the player looks between two corners of a wall with a gap on the other side at specific angles. The result I want is for the tile between two walls to be marked invalid as so. What is the fastest way to modify Bresenham's line algorithm to solve this? If there isn't a good solution, is there a better suited algorithm? Any ideas are welcome. Please note the solution should also be capable of supporting 3d. Edit: For the working source code and an interactive demo of the completed product please see http://ashblue.github.io/javascript-pathfinding/

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  • Turn-based games [closed]

    - by Blue
    I've been looking for tutorials on turn-based games. I found an incomplete tutorial series by InsugentX about turn-based games. I haven't looked through it, but since it's incomplete, I worry that I won't be able to finish the scripts. I'm looking for tutorials or some good tips or advice to create turn-based games(similar to Worms). Recently I finished watching the WalkerBoys' tutorials so I am familiar with code. Where can I find some info and/or tutorials on creating Turn-based games? I'd prefer it to be video format. How can I create turn-based games (not the entire thing, only the set-up) or a turn-based event like in Worms? To explain more, How do I create 2 parties(1st player, 2nd player) exchanging turns(turn-based games and/or hotseat). While parties have characters similar to Worms(having more than 1 character within each party)? Do I use an array, an enum? I don't have any experience in turn-based games, so I would like to know how to actually make turn-based games. I can't find any reference to help me with construction of a turn-based game code similar to Worms in a programming language I can understand.

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  • Running UBUNTU from a USB Flash drive on Acer

    - by Byron Blue
    I've made a bootable USB flash drive to run UBUNTU. The drive works fine on MOST laptops/computers I try: It does not want to start on my (favourite) Acer Aspire 5745 (Windows 7 64 bit). The opening screen has SYSLINUX 4.06 EDD 4.06-pre1 (...) and simply sits there. I was using UBUNTU 12.04.1 64 bit until I tried booting to the Acer this morning. I've tried booting to 10.04 as well (saw this as a fix on a discussion) with the same result. I really want to use the Acer for development and do not want to wipe my Windows 7 from the hard disk. Are there any solutions/answers?

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