Search Results

Search found 4856 results on 195 pages for 'john boy'.

Page 10/195 | < Previous Page | 6 7 8 9 10 11 12 13 14 15 16 17  | Next Page >

  • Mexico leading in Business Transformation Strategies:

    - by [email protected]
    By john[email protected] on April 15, 2010 8:31 AM By John Burke Group Vice President Oracle Applications Business Unit I recently completed a business tour in Mexico, and was surprised by both the economic vibrancy of the country and the thought leadership expressed by many of the customers I met. An example of the economic vibrancy of the country: across the street from my hotel was the local Bentley dealership, Coach Store, Yves Saint Laurent and of course a Starbucks. I only made it to Starbucks. Both the Coach Store and YSL had a line of folks waiting to get in... As for thought leadership, there were several illustrations only on the first day. I had the opportunity to meet with a branch of the Mexican Federal Government. Their questions were not about clerical task automation, far from it! We discussed citizen on-line access to fees and services - for example looking up the duty on an international goods shipment, or tracking that my taxes have been received, or the status of my request for a certain service. Eligibility, policies and status. Having an integrated rules or policy automation system that would allow businesses and citizens to access accurate information and ensure the proper collection of fees and payment for 3rd party provided services. Then in the afternoon, I met with the owner of a roofing company (note: most roofs in Mexico are flat and made of cement). This CEO started discussing how he wanted to transform his business from a cement products company to a service company and market 5-10-15 year service contracts which would guarantee the structural integrity of the roof and of course that the roof would remain waterproof. Although his products were guaranteed, they required an annual inspection and most home owners never schedule that inspection until it is too late and water damage has occurred. These emergency calls reduce his margin and reduce customer satisfaction. This lead to a discussion of business models in general and why long term differentiation can only come from service, not just for the music or news industries, but also for roofing companies! I completely agreed with the transformational concepts described in both meetings and quickly understood why there is a Bentley dealership near my hotel.

    Read the article

  • Ubuntu 12.10 unmet dependencies

    - by John
    I have Ubuntu 12.10 with 3.2.0.24-generic #39-Ubuntu running on a Dell Inspiron 700m laptop. I have unmet dependencies as follows: root@John-700m:/home/John# sudo apt-get remove --purge linux-image-3.5.0-{18,27,31,34}-generic Reading package lists... Done Building dependency tree Reading state information... Done Package 'linux-image-3.5.0-18-generic' is not installed, so not removed Package 'linux-image-3.5.0-27-generic' is not installed, so not removed Package 'linux-image-3.5.0-31-generic' is not installed, so not removed Package 'linux-image-3.5.0-34-generic' is not installed, so not removed You might want to run 'apt-get -f install' to correct these: The following packages have unmet dependencies: linux-generic : Depends: linux-image-generic but it is not going to be installed linux-image-extra-3.5.0-18-generic : Depends: linux-image-3.5.0-18-generic but it is not going to be installed linux-image-extra-3.5.0-27-generic : Depends: linux-image-3.5.0-27-generic but it is not going to be installed linux-image-extra-3.5.0-31-generic : Depends: linux-image-3.5.0-31-generic but it is not going to be installed linux-image-extra-3.5.0-34-generic : Depends: linux-image-3.5.0-34-generic but it is not going to be installed E: Unmet dependencies. Try 'apt-get -f install' with no packages (or specify a solution). I tried to remove the packages, but I still get the same error message. Any help would certainly be appreciated. @Eric, well noted. Here is the reults: model name : Intel(R) Pentium(R) M processor 1.60GHz flags : fpu vme de pse tsc msr mce cx8 mtrr pge mca cmov clflush dts acpi mmx fxsr sse sse2 ss tm pbe up bts est tm2 Thanks again. @Eric, If I need to downgrade to Ubuntu 12.04 from 12.10, can I do it without having to mess my current partition or files? I also have Windows XP running on the machine. Best. @Eric, if you are online, I could use your help (or anybody's else). I installed the package for non-pae unit and I still get the same error. Any suggestions? Thanks

    Read the article

  • C++ match string in file and get line number

    - by Corey
    I have a file with the top 1000 baby names. I want to ask the user for a name...search the file...and tell the user what rank that name is for boy names and what rank for girl names. If it isn't in boy names or girl names, it tells the user it's not among the popular names for that gender. The file is laid out like this: Rank Boy-Names Girl-Names 1 Jacob Emily 2 Michael Emma . . . Desired output for input Michael would be: Michael is 2nd most popular among boy names. If Michael is not in girl names it should say: Michael is not among the most popular girl names Though if it was, it would say: Micheal is (rank) among girl names The code I have so far is below.. I can't seem to figure it out. Thanks for any help. #include <iostream> #include <fstream> #include <string> #include <cctype> using namespace std; void find_name(string name); int main(int argc, char **argv) { string name; cout << "Please enter a baby name to search for:\n"; cin >> name; /*while(!(cin>>name)) { cout << "Please enter a baby name to search for:\n"; cin >> name; }*/ find_name(name); cin.get(); cin.get(); return 0; } void find_name(string name) { ifstream input; int line = 0; string line1 = " "; int rank; string boy_name = ""; string girl_name = ""; input.open("/<path>/babynames2004.rtf"); if (!input) { cout << "Unable to open file\n"; exit(1); } while(input.good()) { while(getline(input,line1)) { input >> rank >> boy_name >> girl_name; if (boy_name == name) { cout << name << " is ranked " << rank << " among boy names\n"; } else { cout << name << " is not among the popular boy names\n"; } if (girl_name == name) { cout << name << " is ranked " << rank << " among girl names\n"; } else { cout << name << " is not among the popular girl names\n"; } } } input.close(); }

    Read the article

  • To ref or not to ref

    - by nmarun
    So the question is what is the point of passing a reference type along with the ref keyword? I have an Employee class as below: 1: public class Employee 2: { 3: public string FirstName { get; set; } 4: public string LastName { get; set; } 5:  6: public override string ToString() 7: { 8: return string.Format("{0}-{1}", FirstName, LastName); 9: } 10: } In my calling class, I say: 1: class Program 2: { 3: static void Main() 4: { 5: Employee employee = new Employee 6: { 7: FirstName = "John", 8: LastName = "Doe" 9: }; 10: Console.WriteLine(employee); 11: CallSomeMethod(employee); 12: Console.WriteLine(employee); 13: } 14:  15: private static void CallSomeMethod(Employee employee) 16: { 17: employee.FirstName = "Smith"; 18: employee.LastName = "Doe"; 19: } 20: }   After having a look at the code, you’ll probably say, Well, an instance of a class gets passed as a reference, so any changes to the instance inside the CallSomeMethod, actually modifies the original object. Hence the output will be ‘John-Doe’ on the first call and ‘Smith-Doe’ on the second. And you’re right: So the question is what’s the use of passing this Employee parameter as a ref? 1: class Program 2: { 3: static void Main() 4: { 5: Employee employee = new Employee 6: { 7: FirstName = "John", 8: LastName = "Doe" 9: }; 10: Console.WriteLine(employee); 11: CallSomeMethod(ref employee); 12: Console.WriteLine(employee); 13: } 14:  15: private static void CallSomeMethod(ref Employee employee) 16: { 17: employee.FirstName = "Smith"; 18: employee.LastName = "Doe"; 19: } 20: } The output is still the same: Ok, so is there really a need to pass a reference type using the ref keyword? I’ll remove the ‘ref’ keyword and make one more change to the CallSomeMethod method. 1: class Program 2: { 3: static void Main() 4: { 5: Employee employee = new Employee 6: { 7: FirstName = "John", 8: LastName = "Doe" 9: }; 10: Console.WriteLine(employee); 11: CallSomeMethod(employee); 12: Console.WriteLine(employee); 13: } 14:  15: private static void CallSomeMethod(Employee employee) 16: { 17: employee = new Employee 18: { 19: FirstName = "Smith", 20: LastName = "John" 21: }; 22: } 23: } In line 17 you’ll see I’ve ‘new’d up the incoming Employee parameter and then set its properties to new values. The output tells me that the original instance of the Employee class does not change. Huh? But an instance of a class gets passed by reference, so why did the values not change on the original instance or how do I keep the two instances in-sync all the times? Aah, now here’s the answer. In order to keep the objects in sync, you pass them using the ‘ref’ keyword. 1: class Program 2: { 3: static void Main() 4: { 5: Employee employee = new Employee 6: { 7: FirstName = "John", 8: LastName = "Doe" 9: }; 10: Console.WriteLine(employee); 11: CallSomeMethod(ref employee); 12: Console.WriteLine(employee); 13: } 14:  15: private static void CallSomeMethod(ref Employee employee) 16: { 17: employee = new Employee 18: { 19: FirstName = "Smith", 20: LastName = "John" 21: }; 22: } 23: } Viola! Now, to prove it beyond doubt, I said, let me try with another reference type: string. 1: class Program 2: { 3: static void Main() 4: { 5: string name = "abc"; 6: Console.WriteLine(name); 7: CallSomeMethod(ref name); 8: Console.WriteLine(name); 9: } 10:  11: private static void CallSomeMethod(ref string name) 12: { 13: name = "def"; 14: } 15: } The output was as expected, first ‘abc’ and then ‘def’ - proves the 'ref' keyword works here as well. Now, what if I remove the ‘ref’ keyword? The output should still be the same as the above right, since string is a reference type? 1: class Program 2: { 3: static void Main() 4: { 5: string name = "abc"; 6: Console.WriteLine(name); 7: CallSomeMethod(name); 8: Console.WriteLine(name); 9: } 10:  11: private static void CallSomeMethod(string name) 12: { 13: name = "def"; 14: } 15: } Wrong, the output shows ‘abc’ printed twice. Wait a minute… now how could this be? This is because string is an immutable type. This means that any time you modify an instance of string, new memory address is allocated to the instance. The effect is similar to ‘new’ing up the Employee instance inside the CallSomeMethod in the absence of the ‘ref’ keyword. Verdict: ref key came to the rescue and saved the planet… again!

    Read the article

  • Merge\Combine two datatables

    - by madlan
    I'm trying to merge\combine two datatables. I've looked at various examples and answers but they seem to create duplicate rows or require indexes (merge on datatable etc) I can't do this via SQL as one source is from a linked Oracle server accessed via MSSQL and the other from a different MSSQL Server that does not have linked access. The data is currently very simple: Name, Email, Phone DataTable1: "John Clark", "", "01522 55231" "Alex King", "[email protected]", "01522 55266" "Marcus Jones", "[email protected]", "01522 55461" DataTable2: "John Clark", "john[email protected]", "01522 55231" "Alex King", "[email protected]", "" "Marcus Jones", "[email protected]", "01522 55461" "Warren bean", "[email protected]", "01522 522311" Giving a datatable with the following: "John Clark", "john[email protected]", "01522 55231" "Alex King", "[email protected]", "01522 55266" "Marcus Jones", "[email protected]", "01522 55461" "Warren bean", "[email protected]", "01522 522311" Name is the field to match records on, with the first datatable taking priority.

    Read the article

  • SQL group and order

    - by John Lambert
    I have multiple users with multiple entries recording times they arrive at destinations Somehow, with my select query I would like to only show the most recent entries for each unique user name. Here is the code that doesn't work: SELECT * FROM $dbTable GROUP BY xNAME ORDER BY xDATETIME DESC This does the name grouping fine, but as far as showing ONLY their most recent entry, is just shows the first entry it sees in the SQL table. I guess my question is, is this possible? Here is my data sample: john 7:00 chris 7:30 greg 8:00 john 8:15 greg 8:30 chris 9:00 and my desired result should only be john 8:15 chris 9:00 greg 8:30

    Read the article

  • C# - Determine if class initializaion causes infinite recursion?

    - by John M
    I am working on porting a VB6 application to C# (Winforms 3.5) and while doing so I'm trying to break up the functionality into various classes (ie database class, data validation class, string manipulation class). Right now when I attempt to run the program in Debug mode the program pauses and then crashes with a StackOverFlowException. VS 2008 suggests a infinite recursion cause. I have been trying to trace what might be causing this recursion and right now my only hypothesis is that class initializations (which I do in the header(?) of each class). My thought is this: mainForm initializes classA classA initializes classB classB initializes classA .... Does this make sense or should I be looking elsewhere? UPDATE1 (a code sample): mainForm namespace john { public partial class frmLogin : Form { stringCustom sc = new sc(); stringCustom namespace john { class stringCustom { retrieveValues rv = new retrieveValues(); retrieveValues namespace john { class retrieveValues { stringCustom sc = new stringCustom();

    Read the article

  • struct assignment operator on arrays

    - by Django fan
    Suppose I defined a structure like this: struct person { char name [10]; int age; }; and declared two person variables: person Bob; person John; where Bob.name = "Bob", Bob.age = 30 and John.name = "John",John.age = 25. and I called Bob = John; struct person would do a Memberwise assignment and assign Johns's member values to Bob's. But arrays can't assign to arrays, so how does the assignment of the "name" array work?

    Read the article

  • How do I average the difference between specific values in TSQL?

    - by jvenema
    Hey folks, sorry this is a bit of a longer question... I have a table with the following columns: [ChatID] [User] [LogID] [CreatedOn] [Text] What I need to find is the average response time for a given user id, to another specific user id. So, if my data looks like: [1] [john] [20] [1/1/11 3:00:00] [Hello] [1] [john] [21] [1/1/11 3:00:23] [Anyone there?] [1] [susan] [22] [1/1/11 3:00:43] [Hello!] [1] [susan] [23] [1/1/11 3:00:53] [What's up?] [1] [john] [24] [1/1/11 3:01:02] [Not much] [1] [susan] [25] [1/1/11 3:01:08] [Cool] ...then I need to see that Susan has an average response time of (20 + 6) / 2 = 13 seconds to John, and John has an average of (9 / 1) = 9 seconds to Susan. I'm not even sure this can be done in set-based logic, but if anyone has any ideas, they'd be much appreciated!

    Read the article

  • Must I loop to search results for a specific value?

    - by tag
    I have a table in the database: name Opinion Tim Tim has an opinion John other random text Dan Dan's random text Al Al says something else I call this data and get it back in getRecords.lastResult To access John's opinion, I could use: getRecords.lastResult[1].opinion But that's only because I know that John is the second record (record 1), but this may change. So the right way is to search through the results to first find the record index for John, then access his opinion. My guess is I need some sort of a loop? Is there an easier way to search for John directly without a loop?

    Read the article

  • Installing CUDA on Ubuntu 12.04 with nvidia driver 295.59

    - by johnmcd
    I have been trying to get cuda to run on a nvidia gt 650m based laptop. I am running Ubuntu 12.04 with the nvidia 295.59 driver. Also, my laptop uses Optimus so I have install the driver via bumblebee. Bumblebee is not working correctly yet -- however I believe it is possible to install CUDA independently. To install CUDA I have followed the instructions detailed here: How can I get nVidia CUDA or OpenCL working on a laptop with nVidia discrete card/Intel Integrated Graphics? However I am still running into problem building the sdk. I made the changes specified at the above link in common.mk, but I got the following (snippet) from the build process: make[2]: Entering directory `/home/john/NVIDIA_GPU_Computing_SDK/C/src/fluidsGL' /usr/bin/ld: warning: libnvidia-tls.so.302.17, needed by /usr/lib/nvidia-current/libGL.so, not found (try using -rpath or -rpath-link) /usr/bin/ld: warning: libnvidia-glcore.so.302.17, needed by /usr/lib/nvidia-current/libGL.so, not found (try using -rpath or -rpath-link) /usr/lib/nvidia-current/libGL.so: undefined reference to `_nv018tls' /usr/lib/nvidia-current/libGL.so: undefined reference to `_nv012glcore' /usr/lib/nvidia-current/libGL.so: undefined reference to `_nv017glcore' /usr/lib/nvidia-current/libGL.so: undefined reference to `_nv012tls' /usr/lib/nvidia-current/libGL.so: undefined reference to `_nv015tls' /usr/lib/nvidia-current/libGL.so: undefined reference to `_nv019tls' /usr/lib/nvidia-current/libGL.so: undefined reference to `_nv000glcore' /usr/lib/nvidia-current/libGL.so: undefined reference to `_nv017tls' /usr/lib/nvidia-current/libGL.so: undefined reference to `_nv013tls' /usr/lib/nvidia-current/libGL.so: undefined reference to `_nv013glcore' /usr/lib/nvidia-current/libGL.so: undefined reference to `_nv018glcore' /usr/lib/nvidia-current/libGL.so: undefined reference to `_nv022tls' /usr/lib/nvidia-current/libGL.so: undefined reference to `_nv007tls' /usr/lib/nvidia-current/libGL.so: undefined reference to `_nv009tls' /usr/lib/nvidia-current/libGL.so: undefined reference to `_nv020tls' /usr/lib/nvidia-current/libGL.so: undefined reference to `_nv014glcore' /usr/lib/nvidia-current/libGL.so: undefined reference to `_nv015glcore' /usr/lib/nvidia-current/libGL.so: undefined reference to `_nv016tls' /usr/lib/nvidia-current/libGL.so: undefined reference to `_nv001glcore' /usr/lib/nvidia-current/libGL.so: undefined reference to `_nv006tls' /usr/lib/nvidia-current/libGL.so: undefined reference to `_nv021tls' /usr/lib/nvidia-current/libGL.so: undefined reference to `_nv011tls' /usr/lib/nvidia-current/libGL.so: undefined reference to `_nv020glcore' /usr/lib/nvidia-current/libGL.so: undefined reference to `_nv019glcore' /usr/lib/nvidia-current/libGL.so: undefined reference to `_nv002glcore' /usr/lib/nvidia-current/libGL.so: undefined reference to `_nv021glcore' /usr/lib/nvidia-current/libGL.so: undefined reference to `_nv014tls' collect2: ld returned 1 exit status make[2]: *** [../../bin/linux/release/fluidsGL] Error 1 make[2]: Leaving directory `/home/john/NVIDIA_GPU_Computing_SDK/C/src/fluidsGL' make[1]: *** [src/fluidsGL/Makefile.ph_build] Error 2 make[1]: Leaving directory `/home/john/NVIDIA_GPU_Computing_SDK/C' make: *** [all] Error 2 The libraries that ld warns about are on my system and are installed on the system: $ locate libnvidia-tls.so.302.17 libnvidia-glcore.so.302.17 /usr/lib/nvidia-current/libnvidia-glcore.so.302.17 /usr/lib/nvidia-current/libnvidia-tls.so.302.17 /usr/lib/nvidia-current/tls/libnvidia-tls.so.302.17 /usr/lib32/nvidia-current/libnvidia-glcore.so.302.17 /usr/lib32/nvidia-current/libnvidia-tls.so.302.17 /usr/lib32/nvidia-current/tls/libnvidia-tls.so.302.17 however /usr/lib/nvidia-current and /usr/lib32/nvidia-current are not being picked up by ldconfig. I have tried adding them by adding a file to /etc/ld.so.conf.d/ which gets past this error, however now I am getting the following error: make[2]: Entering directory `/home/john/NVIDIA_GPU_Computing_SDK/C/src/deviceQueryDrv' cc1plus: warning: command line option ‘-Wimplicit’ is valid for C/ObjC but not for C++ [enabled by default] obj/x86_64/release/deviceQueryDrv.cpp.o: In function `main': deviceQueryDrv.cpp:(.text.startup+0x5f): undefined reference to `cuInit' deviceQueryDrv.cpp:(.text.startup+0x99): undefined reference to `cuDeviceGetCount' deviceQueryDrv.cpp:(.text.startup+0x10b): undefined reference to `cuDeviceComputeCapability' deviceQueryDrv.cpp:(.text.startup+0x127): undefined reference to `cuDeviceGetName' deviceQueryDrv.cpp:(.text.startup+0x16a): undefined reference to `cuDriverGetVersion' deviceQueryDrv.cpp:(.text.startup+0x1f0): undefined reference to `cuDeviceTotalMem_v2' deviceQueryDrv.cpp:(.text.startup+0x262): undefined reference to `cuDeviceGetAttribute' deviceQueryDrv.cpp:(.text.startup+0x457): undefined reference to `cuDeviceGetAttribute' deviceQueryDrv.cpp:(.text.startup+0x4bc): undefined reference to `cuDeviceGetAttribute' deviceQueryDrv.cpp:(.text.startup+0x502): undefined reference to `cuDeviceGetAttribute' deviceQueryDrv.cpp:(.text.startup+0x533): undefined reference to `cuDeviceGetAttribute' obj/x86_64/release/deviceQueryDrv.cpp.o:deviceQueryDrv.cpp:(.text.startup+0x55e): more undefined references to `cuDeviceGetAttribute' follow collect2: ld returned 1 exit status make[2]: *** [../../bin/linux/release/deviceQueryDrv] Error 1 make[2]: Leaving directory `/home/john/NVIDIA_GPU_Computing_SDK/C/src/deviceQueryDrv' make[1]: *** [src/deviceQueryDrv/Makefile.ph_build] Error 2 make[1]: Leaving directory `/home/john/NVIDIA_GPU_Computing_SDK/C' make: *** [all] Error 2 I would appreciate any help that anyone can provide me with. If I can provide any further information please let me know. Thanks.

    Read the article

  • problem in split text by php

    - by moustafa
    Hi Team, I need to split the below contents by using the mobile number and email id. If the mobile number and email id found the content is splitted into some blocks. I am using the preg_match_all to check the mobile number and email id. For example : The Given Content: WANTED B'ful Non W'kingEdu Fair Girl for MBA 28/175 H'some Fair Mangal Gotra Boy Well estd. B'ness HI Income Status family Email: [email protected] PQM4 h'some Convent Educated B.techIIT, MS/28/5'9" Wkg in US frm repu fmlyseek b'ful,tall g i r l . Mo:09893029129 Em:[email protected] 5' 2" to 5' 5" b'ful QLFD girl for h a n d s o m e 5' 8" BPT (I) MPT G.Medalist (AUS) wkg in Australia Physiotherapist boy from V.respectable fmly of Surat / DeUli. Tel: 09825147614. EmaU: [email protected] The Desired output should be: 1st block: WANTED B'ful Non W'kingEdu Fair Girl for MBA 28/175 H'some Fair Mangal Gotra Boy Well estd. B'ness HI Income Status family Email: [email protected] 2nd block: PQM4 h'some Convent Educated B.techIIT, MS/28/5'9" Wkg in US frm repu fmlyseek b'ful,tall g i r l . Mo:09893029129 Em:[email protected] 3rd block: 5' 2" to 5' 5" b'ful QLFD girl for h a n d s o m e 5' 8" BPT (I) MPT G.Medalist (AUS) wkg in Australia Physiotherapist boy from V.respectable fmly of Surat / DeUli. Tel: 09825147614. EmaU: [email protected] I do no how to split it.I need some logics. When i am using preg_match_all when ever a mobile number found i inserted a new line and split the blocks.But email id is splitted independently.

    Read the article

  • Checking data of all same class elements

    - by Tiffani
    I need the code to check the data-name value of all instances of .account-select. Right now it just checks the first .account-select element and not any subsequent ones. The function right now is on click of an element such as John Smith, it checks the data-name of the .account-select lis. If the data-names are the same, it does not create a new li with the John Smith data. If no data-names are equal to John Smith, then it adds an li with John Smith. This is the JS-Fiddle I made for it so you can see what I am referring to: http://jsfiddle.net/rsxavior/vDCNy/22/ Any help would be greatly appreciated. This is the Jquery Code I am using right now. $('.account').click(function () { var acc = $(this).data("name"); var sel = $('.account-select').data("name"); if (acc === sel) { } else { $('.account-hidden-li').append('<li class="account-select" data-name="'+ $(this).data("name") +'">' + $(this).data("name") + '<a class="close bcn-close" data-dismiss="alert" href="#">&times;</a></li>'); } }); And the HTML: <ul> <li><a class="account" data-name="All" href="#">All</a></li> <li><a class="account" data-name="John Smith" href="#">John Smith</a></li> </ul> <ul class="account-hidden-li"> <ul>

    Read the article

  • Parsing back to 'messy' API strcuture

    - by Eric Fail
    I'm fetching data from an online database (REDcap) via API and the data gets delivered in as comma separated string like this, RAW.API <- structure("id,event_arm,name,dob,pushed_text,pushed_calc,complete\n\"01\",\"event_1_arm_1\",\"John\",\"1979-05-01\",\"\",\"\",2\n\"01\",\"event_2_arm_1\",\"John\",\"2012-09-02\",\"abc\",\"123\",1\n\"01\",\"event_3_arm_1\",\"John\",\"2012-09-10\",\"\",\"\",2\n\"02\",\"event_1_arm_1\",\"Mary\",\"1951-09-10\",\"def\",\"456\",2\n\"02\",\"event_2_arm_1\",\"Mary\",\"1978-09-12\",\"\",\"\",2\n", "`Content-Type`" = structure(c("text/html", "utf-8"), .Names = c("", "charset"))) I have this script that nicely parses it into a data frame, (df <- read.table(file = textConnection(RAW.API), header = TRUE, sep = ",", na.strings = "", stringsAsFactors = FALSE)) id event_arm name dob pushed_text pushed_calc complete 1 1 event_1_arm_1 John 1979-05-01 <NA> NA 2 2 1 event_2_arm_1 John 2012-09-02 abc 123 1 3 1 event_3_arm_1 John 2012-09-10 <NA> NA 2 4 2 event_1_arm_1 Mary 1951-09-10 def 456 2 5 2 event_2_arm_1 Mary 1978-09-12 <NA> NA 2 I then do some calculations and write them to pushed_text and pushed_calc whereafter I need to format the data back to the messy comma separated structure it came in. I imagine something like this, API.back <- `some magic command`(df, ...) identical(RAW.API, API.back) [1] TRUE Some command that can format my data from the data frame I made, df, back to the structure that the raw API-object came in, RAW.API. Any help would be very appreciated.

    Read the article

  • Pattern/Matcher in Java?

    - by user1007059
    I have a certain text in Java, and I want to use pattern and matcher to extract something from it. This is my program: public String getItemsByType(String text, String start, String end) { String patternHolder; StringBuffer itemLines = new StringBuffer(); patternHolder = start + ".*" + end; Pattern pattern = Pattern.compile(patternHolder); Matcher matcher = pattern.matcher(text); while (matcher.find()) { itemLines.append(text.substring(matcher.start(), matcher.end()) + "\n"); } return itemLines.toString(); } This code works fully WHEN the searched text is on the same line, for instance: String text = "My name is John and I am 18 years Old"; getItemsByType(text, "My", "John"); immediately grabs the text "My name is John" out of the text. However, when my text looks like this: String text = "My name\nis John\nand I'm\n18 years\nold"; getItemsByType(text, "My", "John"); It doesn't grab anything, since "My" and "John" are on different lines. How do I solve this?

    Read the article

  • web application load / stress testing services

    - by Booji Boy
    Can you recommend reputable companies that offer help (consulting services, etc) in load testing (ASP.NET) web applications? We have a client looking to load test an ASP.NET application and we don't have any expertise in load testing web applications. The client is located in central Massachusetts. My employer http://www.goADNET.com was looking for an option besides, “I can figure out how to do it”.

    Read the article

  • Live CD doesn't boot, drops to Busy Box shell

    - by D3c3nt Boy
    I am a Windows user and I'm keen to shift to Linux, so I made live CD of Ubuntu 10.10 (Maverick). This is my very first time to use Ubuntu. I put CD in the drive and set the BIOS to boot it, and the Ubuntu CD worked and logo of Ubuntu appears on screen. But suddenly before the start up screen it shows this: Busy Box v 1.5 (Ubuntu 1: 1.15.31 ubuntu5) built in shell (ash) enter help for a list of built in commands When I type help and press enter, the list of commands appear like below: alias break cd chdir command continue echo eval exec export ... This is my first time so i have no idea what to do. I restarted my pc several times but it happens every time. Please help me. What should I do?

    Read the article

  • Unbutu 10.10 (MAVERICK) live cd booting?

    - by D3c3nt Boy
    I am user of window and i had keen to shift on LINUX so i made live cd of UNBUTU 10.10 (MAVERICK) THIS IS MY VERY FIRST TIME TO USE UNBUTU I put cd in cd drive and set bios setup and unbutu cd worked and logo of unbutu appear on screen but suddenly before start up screen it shows this Busy Box v 1.5 (Unbutu 1: 1.15.31 unbutu5) built in shell (ash) enter help for a list of built in commands When i type help and press enter the list of commands appear like below alias break cd chdir command continue echo eval exec export filse getopts hash help let local printf pwd read readonly return set shift source test This is my first time so i have no idea what to do i restart my pc several but it happens every time plz help me. what should i do? Sorry for my

    Read the article

  • What Programming languages/technologies stack to use when building Facebook like website ?

    - by Blaze Boy
    I'm developing a website idea that will perform the same as Facebook functionality without the applications extensibility. the site will have a client application to perform a task similar to dropbox.com the site will be a social network of some sort of professionalism, it will highlight code of almost all languages has a high speed backend database Now what languages/techniques do I need to use to achieve that?

    Read the article

  • Where is the "pysdm" package?

    - by John Boy
    I am new to Ubuntu. I have some old hardware lying around so I decided to build a backup/storage device. I am trying to follow this lifehacker article. It asks me to open a terminal and run sudo apt-get install pysdm. However, I keep getting Unable to locate package pysdm. Does anyone know where my pysdm is or where I can get one. I have run ubuntu from a usb key and have installed it on a hard drive and get the same message.

    Read the article

  • What's a good open source cloud computing software? [closed]

    - by boy
    In particular, the "cloud" computing that I'm referring to is: I'm going to get some Linux servers. Then I have pretty big computing tasks to do every day. So my goal is to be able to run some shell command to request an "instance" (ie, if a server has 4 CPU, then the computing software will configure that server to have 4 instances, assuming all my tasks are single thread). Ideally, then I can run the following command: ./addjobs somebatchfile where somebatch file contains one command per line ./removejobs all ./listalljobs (ie, everything is done in shell. And the "computing software" can return me the hostname that's available in some environment variable, etc) And that's all I needed. I run into OpenStack.. but it seems too complicated for this purpose (ie, it does all the Imagine sharing stuff, etc).. All I want, is something SIMPLE that manages the Linux boxes for me and I'm just going to run shell commands on them... Is there such open source software? Thanks,

    Read the article

  • Rewriting from headers in Postfix

    - by inxilpro
    I want to configure Postfix to replace the 'From' header in all forwarded/aliased messages with a custom email address, and the 'Reply-To' header with the original sender's address. Is that something that can be done with a simple configuration change, or am I looking at a more complex problem? For example: Original Message: From: "John Smith" <[email protected]> To: "Jane Rice" <[email protected]> Would get translated to: From: "My Email Forwarding Service" <[email protected]> Reply-To: "John Smith" <[email protected]> To: "Jane Rice" <[email protected]> Ideally, I would also have it rewrite the message body (adding something about how the message was forwarded for them), but I know that's much more difficult. We have a number of email aliases, and everytime someone reports spam they received through their alias, our server gets flagged. I'm trying to minimize that damage as much as possible. Any help is greatly appreciated!

    Read the article

  • ubuntu apache subdomains pointing to main domain

    - by Suhail Thakur
    i have a ubuntu server with apache setup, the main domain on the server is a subdomain app.example.com, which is working fine, now if i setup john.app.example.com, then that also is displaying the web page of app.example.com, the DocumentRoot for john.app.example.com is different, still it shows the web page of app.example.com. how can i resolve this, so john.app.example.com displays the pages that are there in its DocumentRoot.

    Read the article

< Previous Page | 6 7 8 9 10 11 12 13 14 15 16 17  | Next Page >