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  • How long do servers usually last?

    - by AX1
    I'm trying to estimate ROI for a new server and how long it will most likely be in service. Are there any average numbers for how long you can expect a server to last that's in 24/7 use? In other words, is it likely to find 10-year old server from 2010 in today's racks? How about servers from 2005? I'd love to get an idea for how long a server will most likely be in use. By the way, this is meant irrespective of growing or changing application needs. I'm talking only about the hardware.

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  • Identify Long Running or Slow PHP Scripts

    - by Kirk
    I have web server that is getting around 25K visits a day up at yougetsignal.com. Sometimes the site feels a bit sluggish. I am hosting it on nginx with php5-fpm. Is there a way for me to see a list of all of the long running requests that are coming to the site? I'd love to have a real-time list of all of the active requests that PHP is handling and how long they have been running. Kind of like top, but just for the web server. This would let me know how long requests are taking and which script is the culprit. Anyone have any ideas on how I can do this?

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  • MS Windows issue - "Filename or extension is too long"

    - by Daniel
    I run Microsoft windows on a few of my machines. I don't know if many people know about this issue in the OS but you can't have very long filenames, from what I know Linux can have longer names, I have never run into this issue on my Linux machines. Anyway I run into issues whenever copying folders & files to backup drives. I manually backup of my data, finding and changing names of files, this is very very tedious. Is there a software tool to shorten folders or filenames that are found to be to long on Windows? I have drive image duplication software which does the job but in a way that I don't like, plus moving files can become a hassle at times if the names are too long to copy.

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  • How to convert long timestamp to UTC timestamp on Objective C

    - by David
    Hey I had a iphone app, the code has a method to retrieve current time stamp from iphone and upload to server. Here is my code: long long timestampMillis = (long long)([[NSDate date] timeIntervalSince1970] * 1000); However, one of customer use the app in Japan sent data shown on server is tomorrow time. How can I retrieve UTC timestamp? Thanks advanced

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  • Is "long" still useful in C?

    - by dan04
    It's not the largest integer type anymore now that there's "long long". It's not a fixed-width type: It's 32 bits on some platforms and 64 on others. It's not necessarily the same size as a pointer (for example, on 64-bit Windows) So, does "long" have any meaning anymore? Is there ever a reason to declare a long instead of a ptrdiff_t or int64_t?

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  • How long do DDoS attacks last?

    - by Susan
    I realize the answer to this question will vary, which is why I'm asking it. If you've suffered a DDoS attack before - how long did it last? Just trying to get an idea of how long we'll have to continue to wage this battle (going on a couple weeks now).

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  • In ear headphones with a long cable

    - by cust0s
    I'm looking for some in ear headphones with a long cable (no more than 3m). Is their such a product out there? I'm looking to spend no more than £30 ($50) If not could someone reccomend me some small headphones with a long cable?

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  • alternatives to System.Diagnostics.Process.Start when command is too long

    - by Frank Schwieterman
    I have some code which is generating a rather long command that is being sent to System.Diagnostics.Process.Start(). The call fails with a Win32Exception, message "The filename or extension is too long". The path to the program itself is not very long, but the parameters passed in are quite long. I am calling the version where an instance of ProcessStartInfo is passed as the parameter, and in this case its the ProcessStartInfo.Arguments .Field that is very long. (other parameters: CreateNoWindow = true, UseShellExecute = false, RedirectStandardError = true). It looks like the exception is coming from a call to win32 function CreateProcess. Does anyone have an idea of another way to start the process?

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  • How to tell endianness from this output?

    - by Nick Rosencrantz
    I'm running this example program and I'm suppossed to be able to tell from the output what machine type it is. I'm certain it's from inspecting one or two values but how should I perform this inspection? /* pointers.c - Test pointers * Written 2012 by F Lundevall * Copyright abandoned. This file is in the public domain. * * To make this program work on as many systems as possible, * addresses are converted to unsigned long when printed. * The 'l' in formatting-codes %ld and %lx means a long operand. */ #include <stdio.h> #include <stdlib.h> int * ip; /* Declare a pointer to int, a.k.a. int pointer. */ char * cp; /* Pointer to char, a.k.a. char pointer. */ /* Declare fp as a pointer to function, where that function * has one parameter of type int and returns an int. * Use cdecl to get the syntax right, http://cdecl.org/ */ int ( *fp )( int ); int val1 = 111111; int val2 = 222222; int ia[ 17 ]; /* Declare an array of 17 ints, numbered 0 through 16. */ char ca[ 17 ]; /* Declare an array of 17 chars. */ int fun( int parm ) { printf( "Function fun called with parameter %d\n", parm ); return( parm + 1 ); } /* Main function. */ int main() { printf( "Message PT.01 from pointers.c: Hello, pointy World!\n" ); /* Do some assignments. */ ip = &val1; cp = &val2; /* The compiler should warn you about this. */ fp = fun; ia[ 0 ] = 11; /* First element. */ ia[ 1 ] = 17; ia[ 2 ] = 3; ia[ 16 ] = 58; /* Last element. */ ca[ 0 ] = 11; /* First element. */ ca[ 1 ] = 17; ca[ 2 ] = 3; ca[ 16 ] = 58; /* Last element. */ printf( "PT.02: val1: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &val1, val1, val1 ); printf( "PT.03: val2: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &val2, val2, val2 ); printf( "PT.04: ip: stored at %lx (hex); value is %ld (dec), %lx (hex)\n", (long) &ip, (long) ip, (long) ip ); printf( "PT.05: Dereference pointer ip and we find: %d \n", *ip ); printf( "PT.06: cp: stored at %lx (hex); value is %ld (dec), %lx (hex)\n", (long) &cp, (long) cp, (long) cp ); printf( "PT.07: Dereference pointer cp and we find: %d \n", *cp ); *ip = 1234; printf( "\nPT.08: Executed *ip = 1234; \n" ); printf( "PT.09: val1: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &val1, val1, val1 ); printf( "PT.10: ip: stored at %lx (hex); value is %ld (dec), %lx (hex)\n", (long) &ip, (long) ip, (long) ip ); printf( "PT.11: Dereference pointer ip and we find: %d \n", *ip ); printf( "PT.12: val1: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &val1, val1, val1 ); *cp = 1234; /* The compiler should warn you about this. */ printf( "\nPT.13: Executed *cp = 1234; \n" ); printf( "PT.14: val2: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &val2, val2, val2 ); printf( "PT.15: cp: stored at %lx (hex); value is %ld (dec), %lx (hex)\n", (long) &cp, (long) cp, (long) cp ); printf( "PT.16: Dereference pointer cp and we find: %d \n", *cp ); printf( "PT.17: val2: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &val2, val2, val2 ); ip = ia; printf( "\nPT.18: Executed ip = ia; \n" ); printf( "PT.19: ia[0]: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &ia[0], ia[0], ia[0] ); printf( "PT.20: ia[1]: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &ia[1], ia[1], ia[1] ); printf( "PT.21: ip: stored at %lx (hex); value is %ld (dec), %lx (hex)\n", (long) &ip, (long) ip, (long) ip ); printf( "PT.22: Dereference pointer ip and we find: %d \n", *ip ); ip = ip + 1; /* add 1 to pointer */ printf( "\nPT.23: Executed ip = ip + 1; \n" ); printf( "PT.24: ip: stored at %lx (hex); value is %ld (dec), %lx (hex)\n", (long) &ip, (long) ip, (long) ip ); printf( "PT.25: Dereference pointer ip and we find: %d \n", *ip ); cp = ca; printf( "\nPT.26: Executed cp = ca; \n" ); printf( "PT.27: ca[0]: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &ca[0], ca[0], ca[0] ); printf( "PT.28: ca[1]: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &ca[1], ca[1], ca[1] ); printf( "PT.29: cp: stored at %lx (hex); value is %ld (dec), %lx (hex)\n", (long) &cp, (long) cp, (long) cp ); printf( "PT.30: Dereference pointer cp and we find: %d \n", *cp ); cp = cp + 1; /* add 1 to pointer */ printf( "\nPT.31: Executed cp = cp + 1; \n" ); printf( "PT.32: cp: stored at %lx (hex); value is %ld (dec), %lx (hex)\n", (long) &cp, (long) cp, (long) cp ); printf( "PT.33: Dereference pointer cp and we find: %d \n", *cp ); ip = ca; /* The compiler should warn you about this. */ printf( "\nPT.34: Executed ip = ca; \n" ); printf( "PT.35: ca[0]: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &ca[0], ca[0], ca[0] ); printf( "PT.36: ca[1]: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &ca[1], ca[1], ca[1] ); printf( "PT.37: ip: stored at %lx (hex); value is %ld (dec), %lx (hex)\n", (long) &ip, (long) ip, (long) ip ); printf( "PT.38: Dereference pointer ip and we find: %d \n", *ip ); cp = ia; /* The compiler should warn you about this. */ printf( "\nPT.39: Executed cp = ia; \n" ); printf( "PT.40: cp: stored at %lx (hex); value is %ld (dec), %lx (hex)\n", (long) &cp, (long) cp, (long) cp ); printf( "PT.41: Dereference pointer cp and we find: %d \n", *cp ); printf( "\nPT.42: fp: stored at %lx (hex); value is %ld (dec), %lx (hex)\n", (long) &fp, (long) fp, (long) fp ); printf( "PT.43: Dereference fp and see what happens.\n" ); val1 = (*fp)(42); printf( "PT.44: Executed val1 = (*fp)(42); \n" ); printf( "PT.45: val1: stored at %lx (hex); value is %d (dec), %x (hex)\n", (long) &val1, val1, val1 ); return( 0 ); } Output Message PT.01 from pointers.c: Hello, pointy World! PT.02: val1: stored at 21e50 (hex); value is 111111 (dec), 1b207 (hex) PT.03: val2: stored at 21e54 (hex); value is 222222 (dec), 3640e (hex) PT.04: ip: stored at 21eb8 (hex); value is 138832 (dec), 21e50 (hex) PT.05: Dereference pointer ip and we find: 111111 PT.06: cp: stored at 21e6c (hex); value is 138836 (dec), 21e54 (hex) PT.07: Dereference pointer cp and we find: 0 PT.08: Executed *ip = 1234; PT.09: val1: stored at 21e50 (hex); value is 1234 (dec), 4d2 (hex) PT.10: ip: stored at 21eb8 (hex); value is 138832 (dec), 21e50 (hex) PT.11: Dereference pointer ip and we find: 1234 PT.12: val1: stored at 21e50 (hex); value is 1234 (dec), 4d2 (hex) PT.13: Executed *cp = 1234; PT.14: val2: stored at 21e54 (hex); value is -771529714 (dec), d203640e (hex) PT.15: cp: stored at 21e6c (hex); value is 138836 (dec), 21e54 (hex) PT.16: Dereference pointer cp and we find: -46 PT.17: val2: stored at 21e54 (hex); value is -771529714 (dec), d203640e (hex) PT.18: Executed ip = ia; PT.19: ia[0]: stored at 21e74 (hex); value is 11 (dec), b (hex) PT.20: ia[1]: stored at 21e78 (hex); value is 17 (dec), 11 (hex) PT.21: ip: stored at 21eb8 (hex); value is 138868 (dec), 21e74 (hex) PT.22: Dereference pointer ip and we find: 11 PT.23: Executed ip = ip + 1; PT.24: ip: stored at 21eb8 (hex); value is 138872 (dec), 21e78 (hex) PT.25: Dereference pointer ip and we find: 17 PT.26: Executed cp = ca; PT.27: ca[0]: stored at 21e58 (hex); value is 11 (dec), b (hex) PT.28: ca[1]: stored at 21e59 (hex); value is 17 (dec), 11 (hex) PT.29: cp: stored at 21e6c (hex); value is 138840 (dec), 21e58 (hex) PT.30: Dereference pointer cp and we find: 11 PT.31: Executed cp = cp + 1; PT.32: cp: stored at 21e6c (hex); value is 138841 (dec), 21e59 (hex) PT.33: Dereference pointer cp and we find: 17 PT.34: Executed ip = ca; PT.35: ca[0]: stored at 21e58 (hex); value is 11 (dec), b (hex) PT.36: ca[1]: stored at 21e59 (hex); value is 17 (dec), 11 (hex) PT.37: ip: stored at 21eb8 (hex); value is 138840 (dec), 21e58 (hex) PT.38: Dereference pointer ip and we find: 185664256 PT.39: Executed cp = ia; PT.40: cp: stored at 21e6c (hex); value is 138868 (dec), 21e74 (hex) PT.41: Dereference pointer cp and we find: 0 PT.42: fp: stored at 21e70 (hex); value is 69288 (dec), 10ea8 (hex) PT.43: Dereference fp and see what happens. Function fun called with parameter 42 PT.44: Executed val1 = (*fp)(42); PT.45: val1: stored at 21e50 (hex); value is 43 (dec), 2b (hex)

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  • Why does C qicksort function implementation works much slower (tape comparations, tape swapping) than bobble sort function?

    - by Artur Mustafin
    I'm going to implement a toy tape "mainframe" for a students, showing the quickness of "quicksort" class functions (recursive or not, does not really matters, due to the slow hardware, and well known stack reversal techniques) comparatively to the "bubblesort" function class, so, while I'm clear about the hardware implementation ans controllers, i guessed that quicksort function is much faster that other ones in terms of sequence, order and comparation distance (it is much faster to rewind the tape from the middle than from the very end, because of different speed of rewind). Unfortunately, this is not the true, this simple "bubble" code shows great improvements comparatively to the "quicksort" functions in terms of comparison distances, direction and number of comparisons and writes. So I have 3 questions: Does I have mistaken in my implememtation of quicksort function? Does I have mistaken in my implememtation of bubblesoft function? If not, why the "bubblesort" function is works much faster in (comparison and write operations) than "quicksort" function? I already have a "quicksort" function: void quicksort(float *a, long l, long r, const compare_function& compare) { long i=l, j=r, temp, m=(l+r)/2; if (l == r) return; if (l == r-1) { if (compare(a, l, r)) { swap(a, l, r); } return; } if (l < r-1) { while (1) { i = l; j = r; while (i < m && !compare(a, i, m)) i++; while (m < j && !compare(a, m, j)) j--; if (i >= j) { break; } swap(a, i, j); } if (l < m) quicksort(a, l, m, compare); if (m < r) quicksort(a, m, r, compare); return; } } and the kind of my own implememtation of the "bubblesort" function: void bubblesort(float *a, long l, long r, const compare_function& compare) { long i, j, k; if (l == r) { return; } if (l == r-1) { if (compare(a, l, r)) { swap(a, l, r); } return; } if (l < r-1) { while(l < r) { i = l; j = l; while (i < r) { i++; if (!compare(a, j, i)) { continue; } j = i; } if (l < j) { swap(a, l, j); } l++; i = r; k = r; while(l < i) { i--; if (!compare(a, i, k)) { continue; } k = i; } if (k < r) { swap(a, k, r); } r--; } return; } } I have used this sort functions in a test sample code, like this: #include <stdio.h> #include <stdlib.h> #include <math.h> #include <conio.h> long swap_count; long compare_count; typedef long (*compare_function)(float *, long, long ); typedef void (*sort_function)(float *, long , long , const compare_function& ); void init(float *, long ); void print(float *, long ); void sort(float *, long, const sort_function& ); void swap(float *a, long l, long r); long less(float *a, long l, long r); long greater(float *a, long l, long r); void bubblesort(float *, long , long , const compare_function& ); void quicksort(float *, long , long , const compare_function& ); void main() { int n; printf("n="); scanf("%d",&n); printf("\r\n"); long i; float *a = (float *)malloc(n*n*sizeof(float)); sort(a, n, &bubblesort); print(a, n); sort(a, n, &quicksort); print(a, n); free(a); } long less(float *a, long l, long r) { compare_count++; return *(a+l) < *(a+r) ? 1 : 0; } long greater(float *a, long l, long r) { compare_count++; return *(a+l) > *(a+r) ? 1 : 0; } void swap(float *a, long l, long r) { swap_count++; float temp; temp = *(a+l); *(a+l) = *(a+r); *(a+r) = temp; } float tg(float x) { return tan(x); } float ctg(float x) { return 1.0/tan(x); } void init(float *m,long n) { long i,j; for (i = 0; i < n; i++) { for (j=0; j< n; j++) { m[i + j*n] = tg(0.2*(i+1)) + ctg(0.3*(j+1)); } } } void print(float *m, long n) { long i, j; for(i = 0; i < n; i++) { for(j = 0; j < n; j++) { printf(" %5.1f", m[i + j*n]); } printf("\r\n"); } printf("\r\n"); } void sort(float *a, long n, const sort_function& sort) { long i, sort_compare = 0, sort_swap = 0; init(a,n); for(i = 0; i < n*n; i+=n) { if (fmod (i / n, 2) == 0) { compare_count = 0; swap_count = 0; sort(a, i, i+n-1, &less); if (swap_count == 0) { compare_count = 0; sort(a, i, i+n-1, &greater); } sort_compare += compare_count; sort_swap += swap_count; } } printf("compare=%ld\r\n", sort_compare); printf("swap=%ld\r\n", sort_swap); printf("\r\n"); }

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  • Recommendations on laptops - long battery life, slim, Windows 7

    - by molecule
    Hi, I have been looking at a couple of laptops... The most important requirement is long battery life, slim & light, and runs Windows 7. One that seems to fit the bill is the Sony Vaio Z series laptops. They claim to have long battery life, have some really impressive specs (on paper) and a very nice design. They are not on sale where I am yet but has seen/used them? Second would be the Lenovo Thinkpad IBM x301 For business users, Thinkpad seems to be the way to go. I have also considered Dell Alienware M11x but may not be completely appropriate for business use? What would you recommend with a budget of USD1500-2000?

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  • Long file path returning 404 for "hello.htm"

    - by Adam Kane
    Hello, I have a long file path that works on my server, but a simliar path returns a 404 error when it is on my clients (IIS6) server (http://ddmat.com/). Here's the functioning file path on my server: http://www.forgefx.com/projects/ddmat/install/Application Files/McCurdys_1_0_0_0/Content/FBX/CCAE1B33/Roof-sectionB-02.fbm/hello.htm My guesses: Maybe the file path is too long? Maybe the ".fbm" in the directory path is invalid? Sorry for the vauge problem description. Please let me know what additional info I can provide that'd be helpful. Update: The problem happens even in short paths, with no spaces: http://www.myserver/test.folder/hell.htm Thanks, Adam

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  • Shorten Long DNS names

    - by user32425
    Hi, Amazon gives us a very long dns names i.e. c-123-123-123-255.compute-1.amazonaws.com Is there a way to map this name into a shorter name i.e. essentially what i want to do is to modify /etc/hosts file, and map the long name into a short one, i.e. aws1 c-123-123-123-255.compute-1.amazonaws.com but because /etc/hosts file only accepts ip address mapping, then I cannot do that. Is there any other way to do this? Thanks

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  • Long wait until POST...

    - by Wesley
    Here are the specs to put things into context: ECS P4VXASD2+ (V5.0) motherboard Intel Pentium 4 Northwood 2.8 GHz (512 KB L2, 533 MHz FSB) 2x 512 MB PC2100 DDR266 RAM 128 MB NVIDIA GeForce FX 5200 AGP WD Caviar SE 80 GB IDE HDD Gigabyte CD-RW drive OKIA 300W ATX PSU So, everytime I try to boot up this computer, it takes at least 10-15 seconds before it will POST. All my other machines will post within 1-2 seconds, but this one takes a particularly long time. I've read suggestions from a Google search to swap the CMOS battery, check BIOS settings, and double check CMOS jumper. Still after follow those, it takes a while to POST. What else could be causing a long delay before POSTing?

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  • Diagnose cause of long running requests in IIS 7.0

    - by Shlomi Fruchter
    We are running an ASP.NET web application on IIS 7.0, Windows Server 2008 R2, with SQL Server 2008 R2 for DB. On weekends, when the traffic is high, the request queue length in the IIS servers increase (up to 800 requests) and then drops, every minute or so. I can see that the servers are handling some requests which, according to the 'Current Requests' view in IIS Manager, are long running (thier Time Elapsed value ranges from 20 to 50 seconds). Those requests are not necessarily heavy queries, actually, I can't understand why they are taking so long. Can it be because the client is closing the connection on his side? Thanks, Shlomi

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  • when long polling, Why are my other requests taking so long?

    - by Pascal
    The client makes 2 concurrent requests. (1 which takes 60 seconds - long polling) and another which is NOT long polling - supposed to return right away. It does return right away when I'm not doing long polling. But as soon as I start doing long polling with the other thread, the other one takes forever to execute. Firebug shows that the request is waiting for 10-50 seconds. On the server, I profiled ALL requests from the moment the php script starts to the time it goes back to the client, and it shows that each one only took 300ms or less. This problem started about the same time I started doing long polling (with the other XHR requests). I'm using jquery for both requests. The server shows that it is under very light load. CPU and memory less then 2%. 8 processes running out of a pool of 15. (it doesn't seem to deviate much from that number 8, even when I run more ajax requests). I guess each process can run multiple ajax threads concurrently. I made sure to EXIT from all processes as soon as their done executing. I don't see how the process pool has run out, if there are still 7 unused processes listed under prstat -J. Also, the problem happens somewhat intermittently. Firefox should be able to handle 2 concurrent ajax requests. i dont get what the problem is.

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  • Oracle Long Raw Problem.

    - by oraclee
    Hi All; select utl_raw.cast_to_varchar2(DCFILE) hexchar from T_FILE ORA-00997: illegal use of LONG datatype select to_char(DOC_FILE) hexchar from T_DOC_FILE ORA-00932: inconsistent datatypes: expected CHAR got LONG BINARY My column type long raw, how to make varchar2 ?

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  • Splitting only long words in string

    - by owca
    I have some random string, let's say : s = "This string has some verylongwordsneededtosplit" I'm trying to write a function trunc_string(string, len) that takes string as argument to operate on and 'len' as the number of chars after long words will be splitted. The result should be something like that str = trunc_string(s, 10) str = "This string has some verylongwo rdsneededt osplit" For now I have something like this : def truncate_long_words(s, num): """Splits long words in string""" words = s.split() for word in words: if len(word) > num: split_words = list(words) After this part I have this long word as a list of chars. Now I need to : join 'num' chars together in some word_part temporary list join all word_parts into one word join this word with the rest of words, that weren't long enough to be splitted. Should I make it in somehow similar way ? : counter = 0 for char in split_words: word_part.append(char) counter = counter+1 if counter == num And here I should somehow join all the word_part together creating word and further on

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  • How to format long strings in arrays

    - by takeshin
    How should I format very long strings in my source code? I follow the rule, that line of code should not be longer than 80 characters. (The other rules are Zend Framework formatting standard) e.g. protected $_messages = array( 'key1' => 'very, very long string lorem ipsum dolor sit amet…', 'key2' => 'this one it very long too, and exceeds 80 characters len…' );

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  • Range of int and long datatypes

    - by n00b8688
    I learned the range of int and long on 32 bit windows is: signed int: -32767 to 32767 signed long: -2147483647 to 2147483647 why does the int has same range as long type as mentioned here? http://msdn.microsoft.com/en-us/library/s3f49ktz%28VS.80%29.aspx

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  • Unsigned long with negative value

    - by egiakoum1984
    Please see the simple code below: #include <iostream> #include <stdlib.h> using namespace std; int main(void) { unsigned long currentTrafficTypeValueDec; long input; input=63; currentTrafficTypeValueDec = (unsigned long) 1LL << input; cout << currentTrafficTypeValueDec << endl; printf("%u \n", currentTrafficTypeValueDec); printf("%ld \n", currentTrafficTypeValueDec); return 0; } Why printf() displays the currentTrafficTypeValueDec (unsigned long) with negative value? The output is: 9223372036854775808 0 -9223372036854775808

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  • Long running transactions with Spring and Hibernate?

    - by jimbokun
    The underlying problem I want to solve is running a task that generates several temporary tables in MySQL, which need to stay around long enough to fetch results from Java after they are created. Because of the size of the data involved, the task must be completed in batches. Each batch is a call to a stored procedure called through JDBC. The entire process can take half an hour or more for a large data set. To ensure access to the temporary tables, I run the entire task, start to finish, in a single Spring transaction with a TransactionCallbackWithoutResult. Otherwise, I could get a different connection that does not have access to the temporary tables (this would happen occasionally before I wrapped everything in a transaction). This worked fine in my development environment. However, in production I got the following exception: java.sql.SQLException: Lock wait timeout exceeded; try restarting transaction This happened when a different task tried to access some of the same tables during the execution of my long running transaction. What confuses me is that the long running transaction only inserts or updates into temporary tables. All access to non-temporary tables are selects only. From what documentation I can find, the default Spring transaction isolation level should not cause MySQL to block in this case. So my first question, is this the right approach? Can I ensure that I repeatedly get the same connection through a Hibernate template without a long running transaction? If the long running transaction approach is the correct one, what should I check in terms of isolation levels? Is my understanding correct that the default isolation level in Spring/MySQL transactions should not lock tables that are only accessed through selects? What can I do to debug which tables are causing the conflict, and prevent those tables from being locked by the transaction?

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  • Deterministic and non uniform long string generation from seed

    - by Limonup
    I had this weird idea for an encryption that I wanted to try out, it may be bad, and it may have done before, but I'm just doing it for fun. The short version of the question is: Is it possible to generate a long, deterministic and non-uniformly distributed string/sequence of numbers from a small seed? Long(er) version: I was thinking to encrypt a text by changing encoding. The new encoding would be generated via Huffman algorithm. To work well, the Huffman algorithm would need a fairly long text with non uniform distribution. Then characters can have different bit-lengths which would be the primary strength of this encryption. The problem is that its impractical to enter in/remember a long text each time you want to decrypt the text. So I was wondering if it was possible to generate a text from password seed? It doesn't matter what the text is, as long as it has non uniform distribution of characters and that the exact same sequence can be recreated each time you give it the same seed. Preferably, are there any functions/extensions in Python that can do this? EDIT: To expand on the "strength" of varying bit length: if I have a string "test", ASCII values 116, 101, 115, 116, which gives bit values of 1110100 1100101 1110011 1110100 Then, say my Huffman algorithm generates encoding like t = 101 e = 1100111 s = 10001 The final string is 101 1100111 10001 101, if we encode this back to ASCII, we get 1011100 1111000 1101000, which is 3 entirely different characters. Obviously its impossible to perform any kind of frequency analysis or something like that on this.

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  • Use the long reserved word as a variable name in C#

    - by Mark Pearl
    Hi... a bit of an unusual one.. but I was wondering if anyone knew how I could declare a reserved word as a variable. I have the following code, but it does not like my use of the long variable name. I know I could rename it, but for instrest sakes I would like to know if this is at all possible. private string lat; private string long; public string Lat { get { return lat; } } public string Long { get { return long; } }

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  • How to get a long url from a short url

    - by JK
    I would like to determine what the long url of a short url is. I have tried using http HEAD requests, but very few of the returned header fields actually contain any data pertaining to the destination/long url. Is there: 1. Any way to determine the long url? 2. If so, can it be done without downloading the body of the destination? Thank you

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