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  • java.util.zip.ZipException: Error opening file When Deploying an Application to Weblogic Server

    - by lmestre
    The latest weeks we had a hard time trying to solve a deployment issue.* WebLogic Server 10.3.6* Target: WLS Cluster<21-10-2013 05:29:40 PM CLST> <Error> <Console> <BEA-240003> <Console encountered the following error weblogic.management.DeploymentException:        at weblogic.servlet.internal.WarDeploymentFactory.findOrCreateComponentMBeans(WarDeploymentFactory.java:69)        at weblogic.application.internal.MBeanFactoryImpl.findOrCreateComponentMBeans(MBeanFactoryImpl.java:48)        at weblogic.application.internal.MBeanFactoryImpl.createComponentMBeans(MBeanFactoryImpl.java:110)        at weblogic.application.internal.MBeanFactoryImpl.initializeMBeans(MBeanFactoryImpl.java:76)        at weblogic.management.deploy.internal.MBeanConverter.createApplicationMBean(MBeanConverter.java:89)        at weblogic.management.deploy.internal.MBeanConverter.createApplicationForAppDeployment(MBeanConverter.java:67)        at weblogic.management.deploy.internal.MBeanConverter.setupNew81MBean(MBeanConverter.java:315)        at weblogic.deploy.internal.targetserver.operations.ActivateOperation.compatibilityProcessor(ActivateOperation.java:81)        at weblogic.deploy.internal.targetserver.operations.AbstractOperation.setupPrepare(AbstractOperation.java:295)        at weblogic.deploy.internal.targetserver.operations.ActivateOperation.doPrepare(ActivateOperation.java:97)        at weblogic.deploy.internal.targetserver.operations.AbstractOperation.prepare(AbstractOperation.java:217)        at weblogic.deploy.internal.targetserver.DeploymentManager.handleDeploymentPrepare(DeploymentManager.java:747)        at weblogic.deploy.internal.targetserver.DeploymentManager.prepareDeploymentList(DeploymentManager.java:1216)        at weblogic.deploy.internal.targetserver.DeploymentManager.handlePrepare(DeploymentManager.java:250)        at weblogic.deploy.internal.targetserver.DeploymentServiceDispatcher.prepare(DeploymentServiceDispatcher.java:159)        at weblogic.deploy.service.internal.targetserver.DeploymentReceiverCallbackDeliverer.doPrepareCallback(DeploymentReceiverCallbackDeliverer.java:171)        at weblogic.deploy.service.internal.targetserver.DeploymentReceiverCallbackDeliverer.access$000(DeploymentReceiverCallbackDeliverer.java:13)        at weblogic.deploy.service.internal.targetserver.DeploymentReceiverCallbackDeliverer$1.run(DeploymentReceiverCallbackDeliverer.java:46)        at weblogic.work.SelfTuningWorkManagerImpl$WorkAdapterImpl.run(SelfTuningWorkManagerImpl.java:545)        at weblogic.work.ExecuteThread.execute(ExecuteThread.java:256)        at weblogic.work.ExecuteThread.run(ExecuteThread.java:221)Caused by: java.util.zip.ZipException: Error opening file - C:\Oracle\Middleware\user_projects\domains\MyDomain\servers\MyServer\stage\myapp\myapp.war Message - error in opening zip file        at weblogic.servlet.utils.WarUtils.existsInWar(WarUtils.java:87)        at weblogic.servlet.utils.WarUtils.isWebServices(WarUtils.java:76)        at weblogic.servlet.internal.WarDeploymentFactory.findOrCreateComponentMBeans(WarDeploymentFactory.java:61) So the first idea you have with that error is that the war file is corrupted or has incorrect privileges.        We tried:1. Unzipping the  war file, the file was perfect.2. Checking the size, same size as in other environments.3. Checking the ownership of the file, same as in other environments.4. Checking the permissions of the file, same as other applications.Then we accepted the file was fine, so we tried enabling some deployment debugs, but no clues.We also tried:1. Delete all contents of <MyDomain/servers/<MyServer>/tmp> a and <MyDomain/servers/<MyServer>/cache> folders, the issue persisted.2. When renaming the application the deployment was sucessful3. When targeting to the Admin Server, deployment was also working.4. Using 'Copy this application onto every target for me' didn't help either.Finally, my friend 'Test Case' solved the issue again.I saw this name in the config.xml<jdbc-system-resource>    <name>myapp</name>    <target></target>    <descriptor-file-name>jdbc/myapp-jdbc.xml</descriptor-file-name>  </jdbc-system-resource> So, it turned out that customer had created a DataSource with the same name as the application 'myapp' in the above example.By deleting the datasource and created another exact DataSource with a different name the issue was solved.At this point, Do you know Why 'java.util.zip.ZipException: Error opening file' was occurring?Because all names is WebLogic Server need to be unique.References: http://docs.oracle.com/cd/E23943_01/web.1111/e13709/setup.htm"Assigning Names to WebLogic Server ResourcesMake sure that each configurable resource in your WebLogic Server environment has a unique name. Each, domain, server, machine, cluster, JDBC data source, virtual host, or other resource must have a unique name." Enjoy!

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  • Inconsistent file downloads of (what should be) the same file

    - by Austin A.
    I'm working on a system that archives large collections of timetstamped images. Part of the system deals with saving an image to a growing .zip file. This morning I noticed that the log system said that an image was successfully downloaded and placed in the zip file, but when I downloaded the .zip (from an apache alias running on our server), the images didn't match the log. For example, although the log said that camera 3484 captured on January 17, 2011, when I download from the apache alias, the downloaded zip file only contains images up to January 14. So, I sshed onto the server, and unzipped the file in its own directory, and that zip file has images from January 14 to today (January 17). What strikes me as odd is that this should be the exact same file as the one I downloaded from the apache alias. Other experiments: I scp-ed the file from the server to my local machine, and the zip file has the newer images. But when I use an SCP client (in this case, Fugu for OSX), I get the zip file for the older images. In short: unzipping a file on the server or after downloading through scp or after downloading through wget gives one zip file, but unzipping a file from Chrome, Firefox, or SCP client gives a different zip file, when they should be exactly the same. Unzipping on the server... [user@server ~]$ cd /export1/amos/images/2011/84/3484/00003484/ [user@server 00003484]$ ls -la total 6180 drwxr-sr-x 2 user groupname 24 Jan 17 11:20 . drwxr-sr-x 4 user groupname 36 Jan 11 19:58 .. -rw-r--r-- 1 user groupname 6309980 Jan 17 12:05 2011.01.zip [user@server 00003484]$ unzip 2011.01.zip Archive: 2011.01.zip extracting: 20110114_140547.jpg extracting: 20110114_143554.jpg replace 20110114_143554.jpg? [y]es, [n]o, [A]ll, [N]one, [r]ename: y extracting: 20110114_143554.jpg extracting: 20110114_153458.jpg (...bunch of files...) extracting: 20110117_170459.jpg extracting: 20110117_173458.jpg extracting: 20110117_180501.jpg Using the wget through apache alias. local:~ user$ wget http://example.com/zipfiles/2011/84/3484/00003484/2011.01.zip --12:38:13-- http://example.com/zipfiles/2011/84/3484/00003484/2011.01.zip => `2011.01.zip' Resolving example.com... ip.ip.ip.ip Connecting to example.com|ip.ip.ip.ip|:80... connected. HTTP request sent, awaiting response... 200 OK Length: 6,327,747 (6.0M) [application/zip] 100% [=====================================================================================================>] 6,327,747 1.03M/s ETA 00:00 12:38:56 (143.23 KB/s) - `2011.01.zip' saved [6327747/6327747] local:~ user$ unzip 2011.01.zip Archive: 2011.01.zip extracting: 20110114_140547.jpg (... same as before...) extracting: 20110117_183459.jpg Using scp to grab the zip local:~ user$ scp user@server:/export1/amos/images/2011/84/3484/00003484/2011.01.zip . 2011.01.zip 100% 6179KB 475.3KB/s 00:13 local:~ user$ unzip 2011.01.zip Archive: 2011.01.zip extracting: 20110114_140547.jpg (...same as before...) extracting: 20110117_183459.jpg Using Fugu to download 2011.01.zip from /export1/amos/images/2011/84/3484/00003484/ gives images 20110113_090457.jpg through 201100114_010554.jpg Using Firefox to download 2011.01.zip from http://example.com/zipfiles/2011/84/3484/00003484/2011.01.zip gives images 20110113_090457.jpg through 201100114_010554.jpg Using Chrome gives same results as Firefox. Relevant section from apache httpd.conf: # ScriptAlias: This controls which directories contain server scripts. # ScriptAliases are essentially the same as Aliases, except that # documents in the realname directory are treated as applications and # run by the server when requested rather than as documents sent to the client. # The same rules about trailing "/" apply to ScriptAlias directives as to # Alias. # ScriptAlias /cgi-bin/ "/var/www/cgi-bin/" Alias /zipfiles/ /export1/amos/images/

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  • CVE-2004-1010 Buffer Overflow vulnerability in Zip utility

    - by chandan
    CVE DescriptionCVSSv2 Base ScoreComponentProduct and Resolution CVE-2004-1010 Buffer Overflow vulnerability 10.0 Zip Solaris 10 SPARC: 147378-01 X86: 147379-01 Solaris 9 Contact Support This notification describes vulnerabilities fixed in third-party components that are included in Sun's product distribution.Information about vulnerabilities affecting Oracle Sun products can be found on Oracle Critical Patch Updates and Security Alerts page.

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  • CVE-2008-6536 Unspecified vulnerability in 7-zip

    - by chandan
    CVE DescriptionCVSSv2 Base ScoreComponentProduct and Resolution CVE-2008-6536 Unspecified vulnerability 10.0 7-zip Solaris 10 SPARC: 137321-02 x86: 137322-02 Solaris 9 SPARC: 137477-02 x86: 137478-02 This notification describes vulnerabilities fixed in third-party components that are included in Oracle's product distributions.Information about vulnerabilities affecting Oracle products can be found on Oracle Critical Patch Updates and Security Alerts page.

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  • I forgot the password to a cbz/zip file

    - by hurley
    I forgot the password to a cbz file, which when I open it says it only contains empty pages, so i rename it to zip, since I read it will open anyway, and I enter what I supposed to be the password, and it starts extracting some 100 files, but it stops and asks for a password again and none of my known passwords work. Help? it's a backup for over 2 years of work. I'm using Archive Manager at Ubuntu 13.

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  • How to download an MP3 or ZIP file onto mobile devices

    - by Hope4You
    I want to be able to download digital goods to smartphone users (music in format .mp3 or .zip). But iPhone and iPad do not allow direct forced downloads. How can I provide mobile users with digital downloads? I use PHP. The only way I can think of to do this is to use the Dropbox Web API to transfer files to the user's Dropbox account, which then synchronizes with their mobile device. Any other suggestions would be appreciated.

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  • How can I mount .IMG floppy disk images which are not 1.44MB or any other floppy format?

    - by Frank Computer
    I have several .IMG files, but they are different sizes which do not comform to any floppy disk format, i.e. not 1.44MB, 720K, 2.88MB... these .IMG files are like 420K, 832K, etc. Additional info: Winimage, rar, Magic ISO... none of these worked. The files I want to download are located in www.vetusware.com under DBMSOracle6. They are 2 files in rar format, but when I extract the rar's, I get forty-two .IMG files with varied sizes, not 1.44MB, etc. If anyone could please give it a try and succeed in mounting or reading the extractd IMG files, I would appreciate you letting me know how you achieved it, I really need this legacy Oracle 6/DOS version!.. IMPORTANT: I have DOS 6.22 running under Microsoft Virtual PC 2007. VPC07 can only mount IMG's which are only 1.44MB ot 720K. Screenshot of IMG file sizes Screenshot of the first IMZ file

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  • Find RARs with duplicate content

    - by Scott McClenning
    I need a utility to find RAR files that contain duplicate data (i.e. files within the RAR that hash the same, but could have different names). I can open the RARs and see the CRCs are the same, but I was hoping for a more automated process that would work in bulk (hundreds of files). Hashing the overall RAR won't help because the file contained within could have different names, or the archive could be compressed at different levels. If needed, a utility that would extract the contents of the RARs and then compare would work, but is not preferred. I would prefer a free utility for Windows, but a pay utility or a utility for Linux would be acceptable.

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  • Is there a way to determine the original size or file count of a 7-zip archive?

    - by Zac B
    I know that when I compress an archive with the 7za utility, it gives me stats like the number of files processed and the amount of bytes processed (the original size of the data). Is it possible, using the commandline (on linux) or some programming language, to determine: the original size of an archive, before it was compressed? the number of files/directories contained within an archive? The answer might be "no, just decompress the whole archive and do counting/sizing then", but it would be useful to know if there was a faster/less space-greedy way.

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  • ASP.NET Create zip file for download: the compressed zipped folder is invalid or corrupted

    - by Jason Braswell
    string fileName = "test.zip"; string path = "c:\\temp\\"; string fullPath = path + fileName; FileInfo file = new FileInfo(fullPath); Response.Clear(); Response.ClearContent(); Response.ClearHeaders(); Response.Buffer = true; Response.AppendHeader("content-disposition", "attachment; filename=" + fileName ); Response.AppendHeader("content-length", file.Length.ToString()); Response.ContentType = "application/x-compressed"; Response.TransmitFile(fullPath); Response.Flush(); Response.End(); The actual zip file c:\temp\test.zip is good, valid, whatever you want to call it. When I navigate to the directory c:\temp\ and double-click on the test.zip file; it opens right up. My problem seems only to be with the download. The code above executes without any issue. A file download dialog is presented. I can chose to either save or open. If I try to open the file from the dialog, or save it and then open it. I get the following dialog message: The Compressed (zipped) Folder is invalid or corrupted. For Response.ContentType I've tried: application/x-compressed application/x-zip-compressed application/x-gzip-compresse application/octet-stream application/zip The zip file is being created with some prior code (that I'm sure is working fine due to my ability to open the created file directly) using: Ionic.zip http://www.codeplex.com/DotNetZip

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  • uncompressing .zip file in linux [closed]

    - by Suren
    hi, I have a .zip file (It contains multiple files, ex: file1.txt file2.txt file3.txt.. n so on) in a directory. And my query is: How to extract the files from .zip archive to the very same directory and how to create the list of all the files extracted from .zip archive.** The extracted file name should be printed like this in the file named: file_list: file1.txt file2.txt file3.txt filen.txt I have tried the following command assuming that my .zip file name is "data.zip". unzip -qoj data.zip | unzip -ql data.zip > file_list I have used unzip -qoj data.zip to extract all the files in the same directory(quietly,overwrite,junk_path). When I try to insert -l with the first unzip command then the command doesn't extract the file in the current and only files are listed thats why I have to used unzip again after the first pipe(If I am making a mistake here let me know please). I get the following output Length Date Time Name -------- ---- ---- ---- 0 12-21-09 14:25 data/ 6148 12-21-09 14:25 data/.DS_Store 0 12-21-09 14:25 __MACOSX/ 0 12-21-09 14:25 __MACOSX/data/ 82 12-21-09 14:25 __MACOSX/data/._.DS_Store 82 12-11-09 13:59 data/file1.txt 120 12-11-09 13:59 data/file2.txt 166 12-11-09 13:59 data/file3.txt -------- ------- 6598 8 files How do I extract only file1.txt file2.txt file3.txt from this stdout? Is it possible to do this with linux command or I have to write a perl script for this? Thank you.

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  • How to create a zip file and keep entries for directories?

    - by NathanZ
    I would like to create a zip archive from a folder and keep entries for (non-empty) directories. In the code below, FileInputStream throws a FileNotFoundException when a directory is passed to AddToZip. I have tried to put a condition around the actual writing of bytes but it makes the whole archive invalid. How can I add directory entries to the archive? public static void addToZip(File directoryToZip, File file, ZipOutputStream zos) throws FileNotFoundException, IOException { String zipFilePath = file.getCanonicalPath().substring(directoryToZip.getCanonicalPath().length() + 1,file.getCanonicalPath().length()); System.out.println("Writing '" + zipFilePath + "' to zip file"); ZipEntry zipEntry = new ZipEntry(zipFilePath); zos.putNextEntry(zipEntry); FileInputStream fis = new FileInputStream(file); // Throws a FileNotFoundException when directory byte[] bytes = new byte[1024]; int length; while ((length = fis.read(bytes)) >= 0) { zos.write(bytes, 0, length); } zos.closeEntry(); fis.close(); }

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  • I am trying to zip files individually, but the file type is unknown

    - by Jason Mander
    I am trying to zip some files with an unknown file type individually. I am using the following code in a batch script to do that: @ECHO OFF FOR %%A IN (bestbuy*nat*component.cpi*) DO "C:\Program Files\7-Zip\7z.exe" a -mx9 -m0=lzma2:d256m "%%~nA.7z" "%%A" The code will compress files individually ONLY if the file has an extension. Unfortunately the files that I have don't have any extension. In the code I am trying to zip files by doing a pattern match, the files are getting compressed into ONE file (which I do not want, I want each file compressed individually). Why does this code create separate zip files when the files have an extension (for example if I add .txt to the end of the files) and when there is no extension the code creates one zipped file. Can anyone please help me with the code to compress files with unknown file type so that each file gets compressed individually Your help would be greatly appreciated. Jason

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  • MDW Reports–New Source Code ZIP File Available

    - by billramo
    In my MDW Reports series, I attached V1 of the RDL files in my post - May the source be with you! MDW Report Series Part 6–The Final Edition. Since that post, Rachna Agarwal from MSIT in India updated the RDL files that are ready to go in a single ZIP. The reports assume that they will ne uploaded to the Report Manager’s root folder and use a shared data source named MDW. The reports also integrate with the new Query Hash Statistics reports. You can download them from my SQLBlog.com download site.

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  • Why Can't I Pre-Zip Server Files?

    - by ThinkBohemian
    It's just good common sense to have your server gzip your files before they send them to users (I use Nginx) Is there anyway to save the server some overhead and pre-zip those files for the server, and if not why? For instance rather than giving the server an myscript.js and having the server zip the file and send it to the user, is there a way to create myscript.js.zip so the server doesn't have to?

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  • Extract files from zip folder and store these files in blobstore

    - by Eng_Engineer
    i want to upload zip folder from file input in form the i want to extract the contents of this uploaded zip folder,and store the contents (files)of this zip in the blobstore in order to download them after putting these files in one folder,but the problem is that i can't deal with the zip folder directly(to read it), i tried as this: form = cgi.FieldStorage() file_upload = form['file'] zip1=file_upload.filename zipstream=StringIO.StringIO(zip1.read()) But the problem still that i can't read the zip as previous,also i tried to read zip folder directly like this: z1=zipfile.ZipFile(zip1,"r") But there was an error in this way.Please can any one help me.Thanks in advance.

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  • javascript validate zip regular expression

    - by phil
    It's not working. Probably it's syntax error, but I can't figure it out. <script src="jquery-1.4.2.min.js" type="text/javascript"></script> <script> pattern=/^[0-9]{5}$/; if (!pattern.test($('#zip').val)) {$('#zip').append($('<p>',{html: zip is invalid}));} </script> zip (US only): <input type="text" name='zip' id='zip' maxlength="5">

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  • winrar command line folder stucture

    - by Lee Hull
    I am trying to zip up a folder.. Example: C:\Test*.* C:\Test\bin*.* I want to be able to zip up the Test folder with bin subfolder, however, I need the Test folder contents in the zip root. I am trying to do this using the WinRar command line (rar.exe) I've tried using rar.exe a "C:\File.zip" -ep "C:\Test" but it puts all the folder contents in root... Tried rar.exe a "C:\File.zip" -ep "C:\Test*.*" "C:\Test\bin" same thing.. any ideas?

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  • Compress a directory in linux

    - by user9589
    I'm trying to compress a directory and ftp it to a windows ftp. I have tried ever tar command i can find to compress a directory. It appears to be ok then I try and view it's contents using winrar. Winrar keeps telling me the file is corrupt. I have viewed other .gz or .bz2 files using winrar but for some odd reason I can't get it to work. Does anyone else have a suggestion as to something else to try. I would prefer just to have it zip the files so they have a .zip extension but even then when i try to browse it's contents both windows and winrar claim it's corrupt.

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  • How do I compress a directory?

    - by user9589
    I'm trying to compress a directory and ftp it to a windows ftp. I have tried every tar command I can find to compress a directory. It appears to be ok. Then I transfer it and view it's contents using Winrar. Winrar keeps telling me the file is corrupted. I have viewed other .gz or .bz2 files using winrar but for some odd reason I can't get it to work. I would prefer just to have it zip the files so they have a .zip extension but even then when i try to browse it's contents both windows and winrar claim it's corrupt. Does anyone else have a suggestion as to something else to try?

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  • RAR password recovery on GPU using ATI Stream processor

    - by Wajdy Essam
    Hello, I'm newbie in GPU programming , and i work on brute force RAR Password Recovery on ATI Stream Processor using brook+ language, but i see that the kernel written in brook+ language doesn't allow any calling to normal functions (except kernel functions) , my questions is : 1) how to use unrar.dll (to unrar archive files) API in this situation? and is this the only way to program RAR password recovery? 2) what about crack and ElcomSoft software that use GPU , how they work ? 3) what exactly the role for the function work inside GPU (ATI Stream processor or CUDA) in this program? 4) is nVidia/CUDA technology is easier/more flexible than ATI/brook+ language ?

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  • Python Script to backup a directory

    - by rgolwalkar
    Filename:backup_ver1 import os import time 1 Using list to specify the files and directory to be backed up source = r'C:\Documents and Settings\rgolwalkar\Desktop\Desktop\Dr Py\Final_Py' 2 define backup directory destination = r'C:\Documents and Settings\rgolwalkar\Desktop\Desktop\PyDevResourse' 3 Setting the backup name targetBackup = destination + time.strftime('%Y%m%d%H%M%S') + '.rar' rar_command = "rar.exe a -ag '%s' %s" % (targetBackup, ''.join(source)) i am sure i am doing something wrong here - rar command please let me know if os.system(rar_command) == 0: print 'Successful backup to', targetBackup else: print 'Backup FAILED' O/P:- Backup FAILED winrar is added to Path and CLASSPATH under Environment variables as well - anyone else with a suggestion for backing up the directory is most welcome

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