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  • Java resource closing

    - by Bob
    Hi, I'm writing an app that connect to a website and read one line from it. I do it like this: try{ URLConnection connection = new URL("www.example.com").openConnection(); BufferedReader rd = new BufferedReader(new InputStreamReader(connection.getInputStream())); String response = rd.readLine(); rd.close(); }catch (Exception e) { //exception handling } Is it good? I mean, I close the BufferedReader in the last line, but I do not close the InputStreamReader. Should I create a standalone InputStreamReader from the connection.getInputStream, and a BufferedReader from the standalone InputStreamReader, than close all the two readers? I think it will be better to place the closing methods in the finally block like this: InputStreamReader isr = null; BufferedReader br = null; try{ URLConnection connection = new URL("www.example.com").openConnection(); isr = new InputStreamReader(connection.getInputStream()); br = new BufferedReader(isr); String response = br.readLine(); }catch (Exception e) { //exception handling }finally{ br.close(); isr.close(); } But it is ugly, because the closing methods can throw exception, so I have to handle or throw it. Which solution is better? Or what would be the best solution?

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  • Where to put a textfile I want to use in eclipse?

    - by Jayomat
    hi there, I need to read a text file when I start my program. I'm using eclipse and started a new java project. In my project folder I got the "src" folder and the standard "JRE System Library"... I just don't know where to put the text file. I cannot use a "hard coded" path because the text file needs to be included with my app... I also tried to create a new folder like "Files" and use the pathe "Files/staedteliste.txt".. doesn't work too... I use the following code to read the file, but I get this error: Error:java.io.FileNotFoundException:staedteliste.txt(No such file or directory) import java.io.BufferedReader; import java.io.FileReader; import java.io.IOException; import java.util.ArrayList; public class Test { ArrayList<String[]> values; public static void main(String[] args) { // TODO Auto-generated method stub loadList(); } public static void loadList() { BufferedReader reader; String zeile = null; try { reader = new BufferedReader(new FileReader("staedteliste.txt")); zeile = reader.readLine(); ArrayList<String[]> values = new ArrayList<String[]>(); while (zeile != null) { values.add(zeile.split(";")); zeile = reader.readLine(); } System.out.println(values.size()); System.out.println(zeile); } catch (IOException e) { System.err.println("Error :"+e); } } } thx for help!

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  • How to read a string one letter at a time in python

    - by dan
    I need to convert a string inputed by a user into morse code. The way our professor wants us to do this is to read from a morseCode.txt file, seperate the letters from the morseCode into two lists, then convert each letter to morse code (inserting a new line when there is a space). I have the beginning. What it does is reads the morseCode.txt file and seperates the letters into a list [A, B, ... Z] and the codes into a list ['– – . . – –\n', '. – . – . –\n'...]. We haven't learned "sets" yet, so I can't use that. How would I then take the string that they inputed, go through letter by letter, and convert it to morse code? I'm a bit caught up. Here's what I have right now (not much at all...) morseCodeFile = open('morseCode.txt', 'r') letterList = [] codeList = [] line = morseCodeFile.readline() while line != '': letterList.append(line[0]) codeList.append(line[2:]) line = morseCodeFile.readline() morseCodeFile.close() userInput = input("Enter a string to be converted to morse code or press <enter> to quit ")

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  • Can this code be further optimized??

    - by kaki
    i understand that the code given below will not be compltely understood unless i explain my whole of previous and next lines of code. But this is part of the code which is causing so much of delay in my project and want to optimize this. i want to know which code part is faulty and how could this be replaced. i guess,few can say that use of this function is heavy compared and other ligher method are available to do this work please help, thanks in advance for i in range(len(lists)): save=database_index[lists[i]] #print save #if save[1]!='text0194'and save[1]!='text0526': using_data[save[0]]=save p=os.path.join("c:/begpython/wavnk/",str(str(str(save[1]).replace('phone','text'))+'.pm')) x1=open(p , 'r') x2=open(p ,'r') for i in range(6): x1.readline() x2.readline() gen = (float(line.partition(' ')[0]) for line in x1) r= min(enumerate(gen), key=lambda x: abs(x[1] - float(save[4]))) #print r[0] a1=linecache.getline(str(str(p).replace('.pm','.mcep')), (r[0]+1)) #print a1 p1=str(str(a1).rstrip('\n')).split(' ') #print p1 join_cost_index_end[save[0]]=p1 #print join_cost_index_end gen = (float(line.partition(' ')[0]) for line in x2) r= min(enumerate(gen), key=lambda x: abs(x[1] - float(save[3]))) #print r[0] a2=linecache.getline(str(str(p).replace('.pm','.mcep')), (r[0]+1)) #print a2 p2=str(str(a2).rstrip('\n')).split(' ') #print p2 join_cost_index_strt[save[0]]=p2 #print join_cost_index_strt j=j+1 #print j #print join_cost_index_end #print join_cost_index_strt enter code here here my database_index has about 2,50,000 entries`

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  • java - codesprint2 programming contest answer

    - by arya
    I recently took part in Codesprint2. I was unable to submit the solution to the following question. http://www.spoj.pl/problems/COINTOSS/ ( I have posted the link to the problem statement at spoj because the codesprint link requires login ) I checked out one of the successful solutions, ( url : http://pastebin.com/uQhNh9Rc ) and the logic used is exactly the same as mine, yet I am still getting "Wrong Answer" I would be very thankful if someone could please tell me what error I have made, as I am unable to find it. Thank you. My code : import java.io.BufferedReader; import java.io.IOException; import java.io.InputStreamReader; import java.text.DecimalFormat; import java.util.StringTokenizer; public class Solution { static double solve( int n, int m ) { if( m==n ) return 0; if( m==0 ) return ( Math.pow( 2, n+1 ) - 2 ); else { double res = 1 + ( Double )( solve( n, m+1 ) + solve( n, 0 ))/2; return res; } } public static void main( String[] args ) throws IOException { BufferedReader br = new BufferedReader( new InputStreamReader( System.in )); int n, m; int t = Integer.parseInt( br.readLine() ); StringTokenizer tok; String s; for( int T=0; T<t; T++ ) { s = br.readLine(); tok = new StringTokenizer( s ); n = Integer.parseInt( tok.nextToken() ); m = Integer.parseInt( tok.nextToken() ); DecimalFormat df = new DecimalFormat(); df.setMaximumFractionDigits(2); df.setMinimumFractionDigits(2); System.out.println( df.format ( solve( n, m ) )); } } }

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  • Java InputReader. Detect if file being read is binary?

    - by Trizicus
    I had posted a question in regards to this code. I found that JTextArea does not support the binary type data that is loaded. So my new question is how can I go about detecting the 'bad' file and canceling the file I/O and telling the user that they need to select a new file? class Open extends SwingWorker<Void, String> { File file; JTextArea jta; Open(File file, JTextArea jta) { this.file = file; this.jta = jta; } @Override protected Void doInBackground() throws Exception { BufferedReader br = null; try { br = new BufferedReader(new FileReader(file)); String line = br.readLine(); while(line != null) { publish(line); line = br.readLine(); } } finally { try { br.close(); } catch (IOException e) { } } return null; } @Override protected void process(List<String> chunks) { for(String s : chunks) jta.append(s + "\n"); } }

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  • To have efficient many-to-many relation in Java

    - by Masi
    How can you make the efficient many-to-many -relation from fileID to Words and from word to fileIDs without database -tools like Postgres in Java? I have the following classes. The relation from fileID to words is cheap, but not the reverse, since I need three for -loops for it. My solution is not apparently efficient. Other options may be to create an extra class that have word as an ID with the ArrayList of fileIDs. Reply to JacobM's answer The relevant part of MyFile's constructors is: /** * Synopsis of data in wordToWordConutInFile.txt: * fileID|wordID|wordCount * * Synopsis of the data in the file wordToWordID.txt: * word|wordID **/ /** * Getting words by getting first wordIDs from wordToWordCountInFile.txt and then words in wordToWordID.txt. */ InputStream in2 = new FileInputStream("/home/dev/wordToWordCountInFile.txt"); BufferedReader fi2 = new BufferedReader(new InputStreamReader(in2)); ArrayList<Integer> wordIDs = new ArrayList<Integer>(); String line = null; while ((line = fi2.readLine()) != null) { if ((new Integer(line.split("|")[0]) == currentFileID)) { wordIDs.add(new Integer(line.split("|")[6])); } } in2.close(); // Getting now the words by wordIDs. InputStream in3 = new FileInputStream("/home/dev/wordToWordID.txt"); BufferedReader fi3 = new BufferedReader(new InputStreamReader(in3)); line = null; while ((line = fi3.readLine()) != null) { for (Integer wordID : wordIDs) { if (wordID == (new Integer(line.split("|")[1]))) { this.words.add(new Word(new String(line.split("|")[0]), fileID)); break; } } } in3.close(); this.words.addAll(words); The constructor of Word is at the paste.

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  • to connect matlab with java

    - by user304005
    Through the below given code I was able to connect to matlab. But I was not able to execute the script file containing matlab code...Please help me to modify the code so as to execute the matlab code.... Here luck2 is a .m file.... import java.io.InputStreamReader; import java.io.*; public class matlab { private static File myMATLABScript; public static String runScript(File luck2) { String output = "" ; String error = ""; try { String commandToRun ="C:\\Program Files\\MATLAB\\R2009a\\bin\\matlab -nodisplay <" + "Z:\\sem\\java\\luck2"; //String commandToRun = "matlab -nosplash -r myMATLABScript -nodisplay -nodesktop < " + opentxt; System.out.println(commandToRun); Process p = Runtime.getRuntime().exec(commandToRun); String s; BufferedReader stdInput = new BufferedReader(new InputStreamReader(p.getInputStream())); BufferedReader stdError = new BufferedReader(new InputStreamReader(p.getErrorStream())); System.out.println("\nHere is the standard output of the command:\n"); while ((s = stdInput.readLine()) != null) { System.out.println("haiiiiiiiiiiii"); output = s + "\n"; System.out.println(s); } while ((s = stdError.readLine()) != null) { error = s + "\n"; System.out.println(s); } } catch (Exception e) { System.out.println("exception happened here what I know:"); e.printStackTrace(); System.exit(-1); } return output + error; } public static void main(String[] args) throws IOException { matlab m = new matlab(); matlab.runScript(myMATLABScript); //matlab.runScript(); } }

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  • How do I get column names to print in this C# program?

    - by Kevin
    I've cobbled together a C# program that takes a .csv file and writes it to a datatable. Using this program, I can loop through each row of the data table and print out the information contained in the row. The console output looks like this: --- Row --- Item: 1 Item: 545 Item: 507 Item: 484 Item: 501 I'd like to print the column name beside each value, as well, so that it looks like this: --- Row --- Item: 1 Hour Item: 545 Day1 KW Item: 507 Day2 KW Item: 484 Day3 KW Item: 501 Day4 KW Can someone look at my code and tell me what I can add so that the column names will print? I am very new to C#, so please forgive me if I've overlooked something. Here is my code: // Write load_forecast data to datatable. DataTable loadDT = new DataTable(); StreamReader sr = new StreamReader(@"c:\load_forecast.csv"); string[] headers = sr.ReadLine().Split(','); foreach (string header in headers) { loadDT.Columns.Add(header); // I've added the column headers here. } while (sr.Peek() > 0) { DataRow loadDR = loadDT.NewRow(); loadDR.ItemArray = sr.ReadLine().Split(','); loadDT.Rows.Add(loadDR); } foreach (DataRow row in loadDT.Rows) { Console.WriteLine("--- Row ---"); foreach (var item in row.ItemArray) { Console.Write("Item:"); Console.WriteLine(item); // Can I add something here to also print the column names? } }

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  • How to sort HashSet() function data in sequence?

    - by vincent low
    I am new to Java, the function I would like to perform is to load a series of data from a file, into my hashSet() function. the problem is, I able to enter all the data in sequence, but I can't retrieve it out in sequence base on the account name in the file. Can anyone help? below is my code: public Set retrieveHistory(){ Set dataGroup = new HashSet(); try{ File file = new File("C:\\Documents and Settings\\vincent\\My Documents\\NetBeansProjects\\vincenttesting\\src\\vincenttesting\\vincenthistory.txt"); BufferedReader br = new BufferedReader(new FileReader(file)); String data = br.readLine(); while(data != null){ System.out.println("This is all the record:"+data); Customer cust = new Customer(); //break the data based on the , String array[] = data.split(","); cust.setCustomerName(array[0]); cust.setpassword(array[1]); cust.setlocation(array[2]); cust.setday(array[3]); cust.setmonth(array[4]); cust.setyear(array[5]); cust.setAmount(Double.parseDouble(array[6])); cust.settransaction(Double.parseDouble(array[7])); dataGroup.add(cust); //then proced to read next customer. data = br.readLine(); } br.close(); }catch(Exception e){ System.out.println("error" +e); } return dataGroup; } public static void main(String[] args) { FileReadDataModel fr = new FileReadDataModel(); Set customerGroup = fr.retrieveHistory(); System.out.println(e); for(Object obj : customerGroup){ Customer cust = (Customer)obj; System.out.println("Cust name :" +cust.getCustomerName()); System.out.println("Cust amount :" +cust.getAmount()); }

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  • How to use a loop to download HTML with paging?

    - by Nai
    I want to loop through this URL and download the HTML. https://www.googleapis.com/customsearch/v1?key=AIzaSyAAoPQprb6aAV-AfuVjoCdErKTiJHn-4uI&cx=017576662512468239146:omuauf_lfve&q=" + searchTermFormat + "&num=10" +"&start=" + i start and num controls the paging of the URL. So if &start=2, and &num=10, it will scrape 10 results from page 2. Given that Google has a max limit of num = 10, how can I write a loop that loops through the HTML and scrape the results for the first 10 pages? This is what I have so far which just scrapes the first page. //input search term Console.WriteLine("What is your search query?:"); string searchTerm = Console.ReadLine(); //concantenate the strings using + symbol to make it URL friendly for google string searchTermFormat = searchTerm.Replace(" ", "+"); //create a new instance of Webclient and use DownloadString method from the Webclient class to extract download html WebClient client = new WebClient(); int i = 1; string Json = client.DownloadString("https://www.googleapis.com/customsearch/v1?key=AIzaSyAAoPQprb6aAV-AfuVjoCdErKTiJHn-4uI&cx=017576662512468239146:omuauf_lfve&q=" + searchTermFormat + "&num=10" + "&start=" + i); //create a new instance of JavaScriptSerializer and deserialise the desired content JavaScriptSerializer js = new JavaScriptSerializer(); GoogleSearchResults results = js.Deserialize<GoogleSearchResults>(Json); //output results to console Console.WriteLine(js.Serialize(results)); Console.ReadLine();

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  • Looping through a file in VB.NET

    - by Ousman
    I am writing a VB.NET program and I'm trying to accomplish the following: Read and loop through a text file line by line Show the event of the loop on a textbox or label until a button is pressed The loop will then stop on any number that happened to be at the loop event and When a button is pressed again the loop will continue. Code Imports System.IO Public Class Form1 'Dim nFileNum As Integer = FreeFile() ' Get a free file number Dim strFileName As String = "C:\scb.txt" Dim objFilename As FileStream = New FileStream(strFileName, _ FileMode.Open, FileAccess.Read, FileShare.Read) Dim objFileRead As StreamReader = New StreamReader(objFilename) 'Dim lLineCount As Long 'Dim sNextLine As String Private Sub btStart_Click(ByVal sender As System.Object, _ ByVal e As System.EventArgs) _ Handles btStart.Click Try If objFileRead.ReadLine = Nothing Then MsgBox("No Accounts Available to show!", _ MsgBoxStyle.Information, _ MsgBoxStyle.DefaultButton2 = MsgBoxStyle.OkOnly) Return Else Do While (objFileRead.Peek() > -1) Loop lblAccounts.Text = objFileRead.ReadLine() 'objFileRead.Close() 'objFilename.Close() End If Catch ex As Exception MessageBox.Show(ex.Message) Finally 'objFileRead.Close() 'objFilename.Close() End Try End Sub Private Sub Form1_Load(ByVal sender As System.Object, _ ByVal e As System.EventArgs) _ Handles MyBase.Load End Sub End Class Problem I'm able to read the text file but my label will only loop if I hit the start button. It goes to the next line, but I want it to continue to loop through the entire file until I hit a button telling it to stop.

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  • Wrong answer on c# application, finding the n prime of a list of prime numbers.

    - by user300484
    Hello, I am new to C# and I am practicing by trying to solve this easy C# problem. This application will receive an "n" number. After receiving this number, the program has to show the n prime of the list of primes. For example, if the user enters "3", the program is supposed to display "5", because 5 is the third prime starting at 2. I koow that something is wrong with my code but I dont know where is the problem and how I can fix it. Can you please tell me? Thank you :P using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace ConsoleApplication1 { class Program { static void Main(string[] args) { Console.WriteLine("Determinar el n-esimo primo."); long n = Convert.ToInt64(Console.ReadLine()); // N lugar de primos long[] array = new long[n]; long c=0; while (c >= 2) { if(siprimo(c++) == true) for (long i = 0; i < n; i++) { array[i] = c; } } Console.WriteLine(array[n - 1]); Console.ReadLine(); } static private bool siprimo(long x) { bool sp = true; for (long k = 2; k <= x / 2; k++) if (x % k == 0) sp = false; return sp; } } }

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  • c# string interning

    - by CodingThunder
    I am trying to understand string interning and why is doesn't seem to work in my example. The point of the example is to show Example 1 uses less (a lot less memory) as it should only have 10 strings in memory. However, in the code below both example use roughly the same amount of memory (virtual size and working set). Please advice why example 1 isn't using a lot less memory? Thanks Example 1: IList<string> list = new List<string>(10000); for (int i = 0; i < 10000; i++) { for (int k = 0; k < 10; k++) { list.Add(string.Intern(k.ToString())); } } Console.WriteLine("intern Done"); Console.ReadLine(); Example 2: IList<string> list = new List<string>(10000); for (int i = 0; i < 10000; i++) { for (int k = 0; k < 10; k++) { list.Add(k.ToString()); } } Console.WriteLine("intern Done"); Console.ReadLine();

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  • Trying to use HttpWebRequest to load a page in a file.

    - by Malcolm
    Hi, I have a ASP.NET MVC app that works fine in the browser. I am using the following code to be able to write the html of a retrieved page to a file. (This is to use in a PDF conversion component) But this code errors out continually but not in the browser. I get timeout errors sometimes asn 500 errors. Public Function GetPage(ByVal url As String, ByVal filename As String) As Boolean Dim request As HttpWebRequest Dim username As String Dim password As String Dim docid As String Dim poststring As String Dim bytedata() As Byte Dim requestStream As Stream Try username = "pdfuser" password = "pdfuser" docid = "docid=inv12154" poststring = String.Format("username={0}&password={1}&{2}", username, password, docid) bytedata = Encoding.UTF8.GetBytes(poststring) request = WebRequest.Create(url) request.Method = "Post" request.ContentLength = bytedata.Length request.ContentType = "application/x-www-form-urlencoded" requestStream = request.GetRequestStream() requestStream.Write(bytedata, 0, bytedata.Length) requestStream.Close() request.Timeout = 60000 Dim response As HttpWebResponse Dim responseStream As Stream Dim reader As StreamReader Dim sb As New StringBuilder() Dim line As String = String.Empty response = request.GetResponse() responseStream = response.GetResponseStream() reader = New StreamReader(responseStream, System.Text.Encoding.ASCII) line = reader.ReadLine() While (Not line Is Nothing) sb.Append(line) line = reader.ReadLine() End While File.WriteAllText(filename, sb.ToString()) Catch ex As Exception MsgBox(ex.Message) End Try Return True End Function

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  • Convert InputStream to String with encoding given in stream data

    - by Quentin
    Hi, My input is a InputStream which contains an XML document. Encoding used in XML is unknown and it is defined in the first line of XML document. From this InputStream, I want to have all document in a String. To do this, I use a BufferedInputStream to mark the beginning of the file and start reading first line. I read this first line to get encoding and then I use an InputStreamReader to generate a String with the correct encoding. It seems that it is not the best way to achieve this goal because it produces an OutOfMemory error. Any idea, how to do it ? public static String streamToString(final InputStream is) { String result = null; if (is != null) { BufferedInputStream bis = new BufferedInputStream(is); bis.mark(Integer.MAX_VALUE); final StringBuilder stringBuilder = new StringBuilder(); try { // stream reader that handle encoding final InputStreamReader readerForEncoding = new InputStreamReader(bis, "UTF-8"); final BufferedReader bufferedReaderForEncoding = new BufferedReader(readerForEncoding); String encoding = extractEncodingFromStream(bufferedReaderForEncoding); if (encoding == null) { encoding = DEFAULT_ENCODING; } // stream reader that handle encoding bis.reset(); final InputStreamReader readerForContent = new InputStreamReader(bis, encoding); final BufferedReader bufferedReaderForContent = new BufferedReader(readerForContent); String line = bufferedReaderForContent.readLine(); while (line != null) { stringBuilder.append(line); line = bufferedReaderForContent.readLine(); } bufferedReaderForContent.close(); bufferedReaderForEncoding.close(); } catch (IOException e) { // reset string builder stringBuilder.delete(0, stringBuilder.length()); } result = stringBuilder.toString(); }else { result = null; } return result; } Regards, Quentin

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  • Sending Email over VPN SmtpException net_io_connectionclosed

    - by Holy Christ
    I am sending an email from a WPF application. When sending as a domain user on the network, the emails sends as expected. However, when I attempt to send email over a VPN connection, I get the following exception: Exception: System.Net.Mail.SmtpException: Failure sending mail. --- System.IO.IOException: Unable to read data from the transport connection: net_io_connectionclosed. at System.Net.Mail.SmtpReplyReaderFactory.ProcessRead(Byte[] buffer, Int32 offset, Int32 read, Boolean readLine) at System.Net.Mail.SmtpReplyReaderFactory.ReadLines(SmtpReplyReader caller, Boolean oneLine) at System.Net.Mail.SmtpReplyReaderFactory.ReadLine(SmtpReplyReader caller) at System.Net.Mail.SmtpConnection.GetConnection(String host, Int32 port) at System.Net.Mail.SmtpTransport.GetConnection(String host, Int32 port) at System.Net.Mail.SmtpClient.GetConnection() at System.Net.Mail.SmtpClient.Send(MailMessage message) I have tried using impersonation as well as setting the Credentials on the SmtpClient. Neither seem to work: using (new ImpersonateUser("myUser", "MYDOMAIN", "myPass")) { var client = new SmtpClient("myhost.com"); client.UseDefaultCredentials = true; client.Credentials = new NetworkCredential("myUser", "myPass", "MYDOMAIN"); client.Send(mailMessage); } I've also tried using Wireshark to view the message over the wire, but I don't know enough about SMTP to know what I'm looking for. One other variable is that the machine I'm using on the VPN is Vista Business and the machine on the network is Win7. I don't think it's related, but then I wouldn't be asking if I knew the issue! :) Any ideas?

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  • Break a while loop without using If or Break

    - by Justin
    I need to create a program that uses while to find the volume of a cylinder. I need the while loop to break if the user inputs a negative value for the height. My code looks like this: double sentinel=1, h=1, v=0, r, count=0; // declares all variables needed final double PI=3.14159; boolean NotNegative=true; while(NotNegative){// && count==0){ // while both the height is positive AND the total times run is 0 System.out.print("Enter height (Use negative to exit): "); // has the user input the height h=Double.parseDouble(br.readLine()); sentinel=h; // save sentinel as the inputted height while(sentinel>0){ System.out.print("Enter radius: "); // have the user input the radius r=Double.parseDouble(br.readLine()); v=PI*(r*r)*h; // find the volume System.out.println("The volume is " + v); // print out the volume count++; // increase the count each time this runs NotNegative=true; sentinel=-1; } } Any help?

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  • serial port does not exist in current context: c#

    - by I__
    here's the code: using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Linq; using System.Text; using System.Windows.Forms; using System.Threading; namespace WindowsFormsApplication1 { public partial class Form1 : Form { public Form1() { InitializeComponent(); } public class ThreadWork { private static SerialPort serialPort1; public static void DoWork() { serialPort1.Open(); serialPort1.Write("AT+CMGF=1\r\n"); //Thread.Sleep(500); serialPort1.Write("AT+CNMI=2,2\r\n"); //Thread.Sleep(500); serialPort1.Write("AT+CSCA=\"+4790002100\"\r\n"); //Thread.Sleep(500); serialPort1.DataReceived += serialPort1_DataReceived_1; } } private void Form1_Load(object sender, EventArgs e) { ThreadStart myThreadDelegate = new ThreadStart(ThreadWork.DoWork); Thread myThread = new Thread(myThreadDelegate); myThread.Start(); } private void serialPort1_DataReceived_1(object sender, System.IO.Ports.SerialDataReceivedEventArgs e) { string response = serialPort1.ReadLine(); this.BeginInvoke(new MethodInvoker(() => textBox1.AppendText(response + "\r\n"))); } } } and i get an error on this line: string response = serialPort1.ReadLine(); it says:: Error 1 The name 'serialPort1' does not exist in the current context C:\Users\alexluvsdanielle\AppData\Local\Temporary Projects\WindowsFormsApplication1\Form1.cs 44 31 WindowsFormsApplication1 what am i doing wrong?

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  • real time stock quotes, StreamReader performance optimization

    - by sean717
    I am working on a program that extracts real time quote for 900+ stocks from a website. I use HttpWebRequest to send HTTP request to the site and store the response to a stream and open a stream using the following code: HttpWebResponse response = (HttpWebResponse)request.GetResponse(); Stream stream = response.GetResponseStream (); StreamReader reader = new StreamReader( stream ) the size of the received HTML is large (5000+ lines), so it takes a long time to parse it and extract the price. For 900 files, It takes about 6 mins for parsing and extracting. Which my boss isn't happy with, he told me he'd want the whole process to be done in TWO mins. I've identified the part of the program that takes most of time to finish is parsing and extracting. I've tried to optimize the code to make it faster, the following is what I have now after some optimization: // skip lines at the top for(int i=0;i<1500;++i) reader.ReadLine(); // read the line that contains the price string theLine = reader.ReadLine(); // ... extract the price from the line now it takes about 4 mins to process all the files, there is still a significant gap to what my boss's expecting. So I am wondering, is there other way that I can further speed up the parsing and extracting and have everything done within 2 mins?

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  • Java: How to make this main thread wait for the new thread to terminate

    - by Jeff Bullard
    I have a java class that creates a process, called child, using ProcessBuilder. The child process generates a lot of output that I am draining on a separate thread to keep the main thread from getting blocked. However, a little later on I need to wait for the output thread to complete/terminate before going on, and I'm not sure how to do that. I think that join() is the usual way to do this but I'm not sure how to do that in this case. Here is the relevant part of the java code. // Capture output from process called child on a separate thread final StringBuffer outtext = new StringBuffer(""); new Thread(new Runnable() { public void run() { InputStream in = null; in = child.getInputStream(); try { if (in != null) { BufferedReader reader = new BufferedReader(new InputStreamReader(in)); String line = reader.readLine(); while ((line != null)) { outtext.append(line).append("\n"); ServerFile.appendUserOpTextFile(userName, opname, outfile, line+"\n"); line = reader.readLine(); } } } catch (IOException iox) { throw new RuntimeException(iox); } } }).start(); // Write input to for the child process on this main thread // String intext = ServerFile.readUserOpTextFile(userName, opname, infile); OutputStream out = child.getOutputStream(); try { out.write(intext.getBytes()); out.close(); } catch (IOException iox) { throw new RuntimeException(iox); } // ***HERE IS WHERE I NEED TO WAIT FOR THE THREAD TO FINISH *** // Other code goes here that needs to wait for outtext to get all // of the output from the process // Then, finally, when all the remaining code is finished, I return // the contents of outtext return outtext.toString();

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  • Error: "an object reference is required for the non-static field, method or property..."

    - by user300484
    Hi! Im creating an application on C#. Its function is to evualuate if a given is prime and if the same swapped number is prime as well. When I build my solution on Visual Studio, it says that "an object reference is required for the non-static field, method or property...". Im having this problem with the "volteado" and "siprimo" methods. Can you tell me where is the problem and how i can fix it? thank you! namespace ConsoleApplication1 { class Program { static void Main(string[] args) { Console.Write("Write a number: "); long a= Convert.ToInt64(Console.ReadLine()); // a is the number given by the user long av = volteado(a); // av is "a" but swapped if (siprimo(a) == false && siprimo(av) == false) Console.WriteLine("Both original and swapped numbers are prime."); else Console.WriteLine("One of the numbers isnt prime."); Console.ReadLine(); } private bool siprimo(long a) {// evaluate if the received number is prime bool sp = true; for (long k = 2; k <= a / 2; k++) if (a % k == 0) sp = false; return sp; } private long volteado(long a) {// swap the received number long v = 0; while (a > 0) { v = 10 * v + a % 10; a /= 10; } return v; } } }

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  • Is there a faster way to parse through a large file with regex quickly?

    - by Ray Eatmon
    Problem: Very very, large file I need to parse line by line to get 3 values from each line. Everything works but it takes a long time to parse through the whole file. Is it possible to do this within seconds? Typical time its taking is between 1 minute and 2 minutes. Example file size is 148,208KB I am using regex to parse through every line: Here is my c# code: private static void ReadTheLines(int max, Responder rp, string inputFile) { List<int> rate = new List<int>(); double counter = 1; try { using (var sr = new StreamReader(inputFile, Encoding.UTF8, true, 1024)) { string line; Console.WriteLine("Reading...."); while ((line = sr.ReadLine()) != null) { if (counter <= max) { counter++; rate = rp.GetRateLine(line); } else if(max == 0) { counter++; rate = rp.GetRateLine(line); } } rp.GetRate(rate); Console.ReadLine(); } } catch (Exception e) { Console.WriteLine("The file could not be read:"); Console.WriteLine(e.Message); } } Here is my regex: public List<int> GetRateLine(string justALine) { const string reg = @"^\d{1,}.+\[(.*)\s[\-]\d{1,}].+GET.*HTTP.*\d{3}[\s](\d{1,})[\s](\d{1,})$"; Match match = Regex.Match(justALine, reg, RegexOptions.IgnoreCase); // Here we check the Match instance. if (match.Success) { // Finally, we get the Group value and display it. string theRate = match.Groups[3].Value; Ratestorage.Add(Convert.ToInt32(theRate)); } else { Ratestorage.Add(0); } return Ratestorage; } Here is an example line to parse, usually around 200,000 lines: 10.10.10.10 - - [27/Nov/2002:16:46:20 -0500] "GET /solr/ HTTP/1.1" 200 4926 789

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  • Can someone tell me what this Java class does? I/O related

    - by anon
    I am relatively new to Java and trying to learn the I/O syntax. Could someone give me a general overview of what this code does? Thanks!! import java.io.*; public class FileReader { private String openFile=""; private String saveFile=""; FileReader(openFile, saveFile) { this.openFile=openFile; this.saveFile=saveFile; } public String process(){ System.out.println(this.openFile); System.out.println(this.saveFile); BufferedReader open=null; FileReader openFR=null; FileWriter save=null; int counter=0; String output=""; if(openFile.equals("")){ return "No open file specifified\n"; } if(this.saveFile.equals("")){ return "No save file specified\n"; } try { openFR = new FileReader(this.openFile); open = new BufferedReader(openFR); } catch (FileNotFoundException e) { return ("Open file no longer exists\n"); } try { save = new FileWriter(saveFile); } catch (IOException e){ return ("Error saving the file\n"); } try{ String temp = open.readLine(); while(temp != null){ temp = open.readLine(); counter++; save.write(output + "\n"); } } catch (IOException e){ e.getStackTrace(); return ("Error reading open file"); } try { save.flush(); } catch (IOException e) { e.printStackTrace(); return ("Error writing save file"); } return "Operation completed successfully"; } }

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  • Conditionaly strip the last line from a text file

    - by fraXis
    Hello, I posted this yesterday on SO, and I received an answer that works great, but I need to change it around and I don't know how. Here is my original message: I need to strip the last line from a text file. I know how to open and save text files in C#, but how would I strip the last line of the text file? The text file will always be different sizes (some have 80 lines, some have 20). Can someone please show me how to do this? Here is the code that someone gave me to do this (which works fine) //Delete the last line from the file. This line could be 8174, 10000, or anything. This is from SO string tempfile = @"C:\junk_temp.txt"; using (StreamReader reader2 = new StreamReader(newfilename)) { using (StreamWriter writer2 = new StreamWriter(tempfile)) { string line = reader2.ReadLine(); while (!reader2.EndOfStream) { writer2.WriteLine(line); line = reader2.ReadLine(); } // by reading ahead, will not write last line to file } } File.Delete(newfilename); File.Move(tempfile, newfilename); File.Delete(tempfile); How would I change this to only delete the last line of the text file if it is a 4 or 5 digit string (such as 8001 or 99999). If it is anything other than that, such as a %, then I don't want to delete the last line. Can someone please modify the above code to do this for me? Thanks so much.

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