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  • Mathematica quickie: About making cells Input cells by default.

    - by andrz
    I'm going through some lecture notes, Fundamentals of Mathematica Programming (see the .nb file there). I'd like to be able to do the exercises right there in the notebook; but for some reason I can't figure out how to make the default cell an Input cell. In other words, when I'm clicking in that notebook to create a new cell--in the exercises--the cell is by default a text cell. I'd like for it to be an Input cell so that I don't have to manually change it each time. Ideas?

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  • Highlight table view cells when user drags across rows

    - by chronos
    I have a grouped table view that does not need to scroll. I'd like each cell to highlight as the user moves their finger down the screen and call didSelectRowAtIndexPath on release. This behaviour can be seen done by apple in 'settings mail add account'? I can't seem to replicate it myself, all I can get is the default, where the cell deselects as soon as the user moves their finger.

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  • How to display a border-bottom only if table cells are not empty (CSS)

    - by Polarpro
    Hey there, I've got a Filemaker calculation that generates an HTML page with several tables. If the calculation results in values for certain fields the result would be <table> <tr><td>Example value 1</td></tr> <tr><td>Example value 2</td></tr> ... </table> If the calculation finds no values to be displayed, the result would simply be <table> </table> In the first case, I want to the table to display a border at the bottom (or any other horizontal line); in the second case, I don't want to display a border at the bottom. I cannot find a way to get this done using a CSS... Thanks in adavance :-)

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  • Inserting Cells Into A Table ?

    - by lentlesoup
    How do i go about inserting a cell into a table? For example, i retrieve data from a database using MySql and PHP, how do i then go about inserting a cell into an already scripted table? In my case, how would i insert a cell into a row 150 pixels from the start of the row? example: ___________________________________________ | <--150px--> |cell| |

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  • Sum if ONLY all the cells have a value?

    - by Mike
    Hi I need to sum 9 cells of data, each one on a separate sheet, but always in the same location. I only want a figure returned when all the cells have data, even if it's a 0. But, if one of the cells is blank I want a blank return. I'm trying to get my head around, making it up actually, where the IFs and ISBLANK and SUMS would go. Any pointers would be greatly appreciated. SUM(IF(ISBLANK(RANGEA,OR(RANGEB),0,ALLRANGES))) Many thanks Michael

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  • DataGridView fails SelectedCells property

    - by ghiboz
    Hi! in my project I have 3 DataGridView and I need to retrieve the SelectedCells of the grid in 2 grids this works fine, but in one ( and the code is exactly the same of the other 2) the grid.SelectedCells.Count is 1 but If I go in the inspector to view which cell is selected, the result is 0,0... thanks

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  • Excel VBA - export to UTF-8

    - by Tom
    The macro I created works fine, I just need to sort out the saving business. Now I get a popup asking me where to save it, but I would like it to save it under a default name and path AND encoded in UTF-8. This is my full code I use, the bottom part saves the document I presume. Public Sub ExportToTextFile(FName As String, Sep As String, SelectionOnly As Boolean, AppendData As Boolean) Dim WholeLine As String Dim fnum As Integer Dim RowNdx As Long Dim ColNdx As Integer Dim StartRow As Long Dim EndRow As Long Dim StartCol As Integer Dim EndCol As Integer Dim CellValue As String Dim teller As Integer 'Teller aangemaakt ter controle voor het aantal velden 'teller = 1 Application.ScreenUpdating = False On Error GoTo EndMacro: fnum = FreeFile If SelectionOnly = True Then With Selection StartRow = .Cells(1).Row StartCol = .Cells(26).Column EndRow = .Cells(.Cells.Count).Row EndCol = .Cells(.Cells.Count).Column End With Else With ActiveSheet.UsedRange StartRow = .Cells(1).Row StartCol = .Cells(26).Column EndRow = .Cells(.Cells.Count).Row EndCol = .Cells(26).Column End With End If If AppendData = True Then Open FName For Append Access Write As #fnum Else Open FName For Output Access Write As #fnum End If For RowNdx = StartRow To EndRow WholeLine = "" For ColNdx = StartCol To EndCol If Cells(RowNdx, ColNdx).Value = "" Then CellValue = "" Else CellValue = Cells(RowNdx, ColNdx).Value End If WholeLine = WholeLine & CellValue & Sep Next ColNdx WholeLine = Left(WholeLine, Len(WholeLine) - Len(Sep)) Print #fnum, WholeLine, "" 'Print #fnum, teller, WholeLine, "" 'teller = teller + 1 Next RowNdx EndMacro: On Error GoTo 0 Application.ScreenUpdating = True Close #fnum End Sub Sub Dump4Mini() Dim FileName As Variant Dim Sep As String FileName = Application.GetSaveAsFilename(InitialFileName:=Blank, filefilter:="Text (*.txt),*.txt") If FileName = False Then Exit Sub End If Sep = "|" If Sep = vbNullString Then Exit Sub End If Debug.Print "FileName: " & FileName, "Separator: " & Sep ExportToTextFile FName:=CStr(FileName), Sep:=CStr(Sep), SelectionOnly:=False, AppendData:=False End Sub

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  • UITableView insertRowsAtIndexPaths out of order

    - by bschlenk
    I currently have a UISegmentedControl set to add/remove table view cells when its value changes. Removing cells works perfectly, however when I insert cells they're in reverse order every other time. NSArray *addindexes = [NSArray arrayWithObjects:[NSIndexPath indexPathForRow:2 inSection:0], [NSIndexPath indexPathForRow:3 inSection:0], [NSIndexPath indexPathForRow:4 inSection:0], nil]; NSArray *removeindexes = [NSArray arrayWithObjects:[NSIndexPath indexPathForRow:2 inSection:0], [NSIndexPath indexPathForRow:3 inSection:0], [NSIndexPath indexPathForRow:4 inSection:0], nil]; [self.tableView beginUpdates]; switch (switchType.selectedSegmentIndex) { case 0: [self.tableView insertRowsAtIndexPaths:addindexes withRowAnimation:UITableViewRowAnimationTop]; break; case 1: [self.tableView deleteRowsAtIndexPaths:removeindexes withRowAnimation:UITableViewRowAnimationTop]; break; default: break; } [self.tableView endUpdates];} For example, every other time I add/remove cells they're in reverse order. (4, 3, 2 instead of 2, 3, 4) 1) Remove cells- add cells- correct order 2) Remove cells- add cells- incorrect order 3) Remove cells- add cells- correct order

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  • c# converting select case VBA to c# SWITCH

    - by herrow
    i have some vba code that i need to convert to c# Select Case letter0 Case "A01" Cells(rownum, 2).Value = "1" Case "B01" Cells(rownum, 2).Value = "2" Case "C01" Cells(rownum, 2).Value = "3" Case "D01" Cells(rownum, 2).Value = "4" Case "E01" Cells(rownum, 2).Value = "5" Case "F01" Cells(rownum, 2).Value = "6" Case "G01" Cells(rownum, 2).Value = "7" Case "H01" Cells(rownum, 2).Value = "8" Case "A02" Cells(rownum, 2).Value = "9" Case "B02" ... .. i understand how to do a switch on this, but is there an easier method? i will not be checking CELLS(rownum.........) instead of will be doing switch(somestring) is there an easier way to do this than explicitly write every single case?

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  • Conditional relation

    - by Lowgain
    I've got a model like this: Stem -id -etc And then I have Stemrelation -stem_id -related_stem_id -active I can get the related stems with the following relations class Stem < ActiveRecord::Base has_many :stemrelations has_many :related_stems, :through => :stemrelations end class Stemrelation < ActiveRecord::Base belongs_to :stem belongs_to :related_stem, :class_name => "Stem", :foreign_key => "related_stem_id" end But now I'd only like to get the active relations. I tried adding this to the Stem model: has_many :active_related, :through => :stemrelations, :source => :related_stem, :conditions => {:active => true} but this gives me an error becasue it tries to check the active flag on the stem model instead of the stemrelation. What do I change here? Thanks!

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  • Extract data from specific range of cells in multiple worksheet in multiple files.

    - by Michele
    Extract data from specific range of cells(always the same cells) in multiple worksheet in multiple files. 1 file=1 day. I have 6 technicians each day of the week, Monday thru Friday. So, 5 files with 6 worksheets. I have entered specific info in specific cells of every work sheet. The range is constant(the same address in EVERY worksheet in every file.) So, I need a formula to extract and calculate the data in the given range and dump it into another spreadsheet. I can forward an example a file if it will help anyone to answer my question. Or more explanation if necessary is available upon request. JUST PLEASE SOMEBODY HELP ME!!!!! Thank you all in advance. Regards, Michele

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  • jqGrid > datatype : "local" > get and save (at once) all edited cells of a column ?

    - by Qualliarys
    Hi, i have a grid with a datatype = "local". The data are an array as follows : var mydata = [{id:1,valeur:"a_value",designation:"a_designation"}, {id:2,...}, ...]; The second column (named valeur) is the only editable column of the grid (editable:true set in colModel) In the pager of the grid, i have 2 buttons. One to edit all cells (at once) of the column named valeur: $("#mygrid").jqGrid('navButtonAdd','#pager',{caption:"Edit values", onClickButton:function(){ var ids = $('#mygrid').jqGrid('getDataIDs'); for(var i=0;i<ids.length+1;i++){ $('#mygrid').jqGrid('editRow',ids[i],true);} }}); and another one to save (at once) all the changes of the edited cells: $("#mygrid").jqGrid('navButtonAdd','#pager',{caption:"Save changes", onClickButton:function(){var ids = $('#mygrid').jqGrid('getDataIDs'); for(var i=0;i<ids.length+1;i++){ ... ??? ... }}}); when i use : var rd = $("#mygrid").jqGrid('getRowData',ids[i]); alert("valeur="+rd.valeur); for each display i get something like that: valeur=< input class="editable" role="textbox" name="valeur" id="1_valeur" style="width: 98%;" type="text" ... So, when cells are in edition mode, all rd.valeur are an input text tag ! when they are not, i get the initials values of the cells ! How to get and save all changes of this column (all cells in edition mode)?

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  • How can I make datagridview can only select the cells in the same column at a time?

    - by MemoryLeak
    I am using winforms to develop my application. And I set my datagridview control's selectionmode to "CellSelect", and this allow the user to select as many cells as he want which spread over several columns; but I want to constraint my user can only select cells in single column at a time, and there isn't any such kind of selectionmode for me. So If I want to implement this, how can I extend the datagridview class ? I also think that I can check in eventhandler whenever the selection cells are changed, through which I might make the user can not select cells spread over multiple columns, but this is not that good, I think. Can any other people help me to find out a better solution ?

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  • Using JQuery to insert new cells in a table row?

    - by Michael Smith
    I know that JQuery is a very powerful library and was just wondering if it had the following capability that I really need. Lets say I need to insert new cells into a table row, I know how to do this basic task, but I need to insert my cells in a highly unusual way due to some of the requirements that are needed for the new cells. I need to be able to insert cells a certain distance into the row, For example, if a row was 1000pixels wide, is there a feature in JQuery that would allow me to insert the cell 250pixels into the row and have a cell width of 50pixels and insert another cell 500pixels into the row with a cell width of 100pixels. I know how to set a cells width using JQuery, just not distance into a row. The values wont ever be the exact same as above though because they are actually read from a database, so for example, one cell would have the following values: CELL_01 $start=100; $finish=150; the above would mean a new cell is needed that needs to be inserted 100pixels into the row and has a width of 50pixels, I just cant seem to find a way to implement this feature into my application. How could I accomplish this task? Sorry for such a strange question, but i just cant seem to get this working. Thanks!

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  • How to create a new widget for dojox.grid.cells.dijit?

    - by the_drow
    I am trying to create a button widget for dojox.grid. My problems are: 1) The button is only shown when I double click the grid. 2) I can't figure out how to set attributes through declarative markup. It seems that the markupFactory function is responsible for it but it doesn't set the widget's label. The following code demonstrates what I've got so far: dojo.require("dojox.grid.DataGrid"); dojo.require("dojo.data.ItemFileWriteStore"); dojo.require("dijit.form.Button"); dojo.require("dojox.grid.cells.dijit"); dojo.require("dojo.parser"); dojo.declare("dojox.grid.cells.Button", dojox.grid.cells._Widget, { widgetClass: dijit.form.Button, alwaysEditing: true, constructor: function(inCell) { this.inherited(arguments); this.widget = new dijit.form.Button; }, setValue: function(inRowIndex, inValue){ if (this.widget) { this.widget.attr('value', inValue); } else { this.inherited(arguments); } } }); dojox.grid.cells.Button.markupFactory = function(node, cell) { dojox.grid.cells._Widget.markupFactory(node, cell); }

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  • How do I detect a Word table with (horizontally) merged cells?

    - by Reuben
    When a Word table contains horizontally merged cells, accessing aTable.Columns.First or performing a For Each over aTable.Columns will result in an error. Is there a way to determine if a table contains horizontally merged cells without resulting in an error? I've read Determine if a Word cell is merged, but that is about detecting if a particular Word table cell is merged, rather than does the whole table have any merged cells.

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  • in Open Office Calc, how do I drag and drop cells to insert rather than replace their destination?

    - by joachim
    I want to rearrange rows with the mouse in Calc. In Excel, I select the whole row, then drag and drop it while holding SHIFT. This causes the drag and drop cursor to turn into a bar rather than cells, and the cells are inserted at the bar's position. Is there a way to accomplish the same sort of thing in Calc without going round the houses inserting columns before the drag operation?

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  • In OpenOffice Calc, how do I drag and drop cells to insert rather than replace their destination?

    - by joachim
    I want to rearrange rows with the mouse in Calc. In Excel, I select the whole row, then drag and drop it while holding Shift. This causes the drag and drop cursor to turn into a bar rather than cells, and the cells are inserted at the bar's position. Is there a way to accomplish the same sort of thing in Calc without going around the houses inserting columns before the drag operation?

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  • Creating and Saving an Excel File

    - by Kris
    I have the following code that creates a new Excel file in my C# code behind. When I attempt to save the file I would like the user to select the location of the save. In Method #1, I can save the file my using the workbook SaveCopyAs without prompting the user for a location. This saves one file to the C:\Temp directory. Method #2 will save the file in my Users\Documents folder, then prompt the user to select the location and save a second copy. How can I eliminate the first copy from saving in the Users\Documents folder? Excel.Application oXL; Excel._Workbook oWB; Excel._Worksheet oSheet; Excel.Range oRng; try { //Start Excel and get Application object. oXL = new Excel.Application(); oXL.Visible = false; //Get a new workbook. oWB = (Excel._Workbook)(oXL.Workbooks.Add(Missing.Value)); oSheet = (Excel._Worksheet)oWB.ActiveSheet; // ***** oSheet.Cells[2, 6] = "Ship To:"; oSheet.get_Range("F2", "F2").Font.Bold = true; oSheet.Cells[2, 7] = sShipToName; oSheet.Cells[3, 7] = sAddress; oSheet.Cells[4, 7] = sCityStateZip; oSheet.Cells[5, 7] = sContactName; oSheet.Cells[6, 7] = sContactPhone; oSheet.Cells[9, 1] = "Shipment No:"; oSheet.get_Range("A9", "A9").Font.Bold = true; oSheet.Cells[9, 2] = sJobNumber; oSheet.Cells[9, 6] = "Courier:"; oSheet.get_Range("F9", "F9").Font.Bold = true; oSheet.Cells[9, 7] = sCarrierName; oSheet.Cells[11, 1] = "Requested Delivery Date:"; oSheet.get_Range("A11", "A11").Font.Bold = true; oSheet.Cells[11, 2] = sRequestDeliveryDate; oSheet.Cells[11, 6] = "Courier Acct No:"; oSheet.get_Range("F11", "F11").Font.Bold = true; oSheet.Cells[11, 7] = sCarrierAcctNum; // ***** Method #1 //oWB.SaveCopyAs(@"C:\Temp\" + sJobNumber +".xls"); Method #2 oXL.SaveWorkspace(sJobNumber + ".xls"); } catch (Exception theException) { String errorMessage; errorMessage = "Error: "; errorMessage = String.Concat(errorMessage, theException.Message); errorMessage = String.Concat(errorMessage, " Line: "); errorMessage = String.Concat(errorMessage, theException.Source); }

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  • When working with gems in Rails, what does 'cannot remove Object::ClassMethods' stem from?

    - by Matt
    Frequently I have run into a problem when installing gems that provides a problem like: Does anyone know what this stems from? I've seen in it several different cases, yet still haven't learned what exactly is causing it. $ sudo rake gems:install --trace (in /u/app/releases/20100213003957) ** Invoke gems:install (first_time) ** Invoke gems:base (first_time) ** Execute gems:base ** Invoke environment (first_time) ** Execute environment rake aborted! cannot remove Object::ClassMethods /u/app/releases/20100213003957/vendor/rails/activesupport/lib/active_support/dependencies.rb:603:in `remove_const' /u/app/releases/20100213003957/vendor/rails/activesupport/lib/active_support/dependencies.rb:603:in `remove_constant' /u/app/releases/20100213003957/vendor/rails/activesupport/lib/active_support/dependencies.rb:603:in `instance_eval' /u/app/releases/20100213003957/vendor/rails/activesupport/lib/active_support/dependencies.rb:603:in `remove_constant' /u/app/releases/20100213003957/vendor/rails/activesupport/lib/active_support/dependencies.rb:549:in `new_constants_in' /u/app/releases/20100213003957/vendor/rails/activesupport/lib/active_support/dependencies.rb:549:in `each' /u/app/releases/20100213003957/vendor/rails/activesupport/lib/active_support/dependencies.rb:549:in `new_constants_in' /u/app/releases/20100213003957/vendor/rails/activesupport/lib/active_support/dependencies.rb:156:in `require' /u/app/releases/20100213003957/vendor/rails/railties/lib/tasks/misc.rake:4 /usr/lib64/ruby/gems/1.8/gems/rake-0.8.4/lib/rake.rb:617:in `call' /usr/lib64/ruby/gems/1.8/gems/rake-0.8.4/lib/rake.rb:617:in `execute' /usr/lib64/ruby/gems/1.8/gems/rake-0.8.4/lib/rake.rb:612:in `each' /usr/lib64/ruby/gems/1.8/gems/rake-0.8.4/lib/rake.rb:612:in `execute' /usr/lib64/ruby/gems/1.8/gems/rake-0.8.4/lib/rake.rb:578:in `invoke_with_call_chain' /usr/lib64/ruby/1.8/monitor.rb:242:in `synchronize' /usr/lib64/ruby/gems/1.8/gems/rake-0.8.4/lib/rake.rb:571:in `invoke_with_call_chain' /usr/lib64/ruby/gems/1.8/gems/rake-0.8.4/lib/rake.rb:564:in `invoke' /u/app/releases/20100213003957/vendor/rails/railties/lib/tasks/gems.rake:17 /usr/lib64/ruby/gems/1.8/gems/rake-0.8.4/lib/rake.rb:617:in `call' /usr/lib64/ruby/gems/1.8/gems/rake-0.8.4/lib/rake.rb:617:in `execute' /usr/lib64/ruby/gems/1.8/gems/rake-0.8.4/lib/rake.rb:612:in `each' /usr/lib64/ruby/gems/1.8/gems/rake-0.8.4/lib/rake.rb:612:in `execute' /usr/lib64/ruby/gems/1.8/gems/rake-0.8.4/lib/rake.rb:578:in `invoke_with_call_chain' /usr/lib64/ruby/1.8/monitor.rb:242:in `synchronize' /usr/lib64/ruby/gems/1.8/gems/rake-0.8.4/lib/rake.rb:571:in `invoke_with_call_chain' /usr/lib64/ruby/gems/1.8/gems/rake-0.8.4/lib/rake.rb:588:in `invoke_prerequisites' /usr/lib64/ruby/gems/1.8/gems/rake-0.8.4/lib/rake.rb:585:in `each' /usr/lib64/ruby/gems/1.8/gems/rake-0.8.4/lib/rake.rb:585:in `invoke_prerequisites' /usr/lib64/ruby/gems/1.8/gems/rake-0.8.4/lib/rake.rb:577:in `invoke_with_call_chain' /usr/lib64/ruby/1.8/monitor.rb:242:in `synchronize' /usr/lib64/ruby/gems/1.8/gems/rake-0.8.4/lib/rake.rb:571:in `invoke_with_call_chain' /usr/lib64/ruby/gems/1.8/gems/rake-0.8.4/lib/rake.rb:564:in `invoke' /usr/lib64/ruby/gems/1.8/gems/rake-0.8.4/lib/rake.rb:2027:in `invoke_task' /usr/lib64/ruby/gems/1.8/gems/rake-0.8.4/lib/rake.rb:2005:in `top_level' /usr/lib64/ruby/gems/1.8/gems/rake-0.8.4/lib/rake.rb:2005:in `each' /usr/lib64/ruby/gems/1.8/gems/rake-0.8.4/lib/rake.rb:2005:in `top_level' /usr/lib64/ruby/gems/1.8/gems/rake-0.8.4/lib/rake.rb:2044:in `standard_exception_handling' /usr/lib64/ruby/gems/1.8/gems/rake-0.8.4/lib/rake.rb:1999:in `top_level' /usr/lib64/ruby/gems/1.8/gems/rake-0.8.4/lib/rake.rb:1977:in `run' /usr/lib64/ruby/gems/1.8/gems/rake-0.8.4/lib/rake.rb:2044:in `standard_exception_handling' /usr/lib64/ruby/gems/1.8/gems/rake-0.8.4/lib/rake.rb:1974:in `run' /usr/lib64/ruby/gems/1.8/gems/rake-0.8.4/bin/rake:31 /usr/bin/rake:19:in `load' /usr/bin/rake:19

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