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  • Zend_Feed_Reader Not supported Schema

    - by LookUp Webmaster
    Hello, I'm using Zend FW and wanted to make a feed reader. I did the following: $feed = Zend_Feed_Reader::import('feed://blog.lookup.cl/?feed=rss2'); $data = array( 'title' => $feed->getTitle(), 'link' => $feed->getLink(), 'dateModified' => $feed->getDateModified(), 'description' => $feed->getDescription(), 'language' => $feed->getLanguage(), 'entries' => array(), ); foreach ($feed as $entry) { $edata = array( 'title' => $entry->getTitle(), 'description' => $entry->getDescription(), 'dateModified' => $entry->getDateModified(), 'authors' => $entry->getAuthors(), 'link' => $entry->getLink(), 'content' => $entry->getContent() ); $data['entries'][] = $edata; } And it throws the following exception: Scheme "feed" is not supported The blog was made using Wordpress. What's wrong? If "feed it's not supported", how can I change the type of feed that Wordpress does? Thanks in advance, Take care,

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  • Multiple/nested "select where" with Zend_Db_Select

    - by DJRayon
    Hi there I need to create something like this: select name from table where active = 1 AND (name LIKE 'bla' OR description LIKE 'bla') The first part is easy: $sqlcmd = $db->select() ->from("table", "name") ->where("active = ?", 1) Now comes the tricky part. How can I nest? I know that I can just write ->orWhere("name LIKE ? OR description LIKE ?", "bla") But thats wron, because I need to dynamically change all the parts. The query will be built all the time the script runs. Some parts get deleted, some altered. In this example I need to add those OR-s because sometimes I need to search wider. "My Zend Logic" tells me that the correct way is like this: $sqlcmd = $db->select() ->from("table", "name") ->where("active = ?", 1) ->where(array( $db->select->where("name LIKE ?", "bla"), $db->select->orWhere("description LIKE ?", "bla") )) But that doesn't work (atleast I dont remember it working). Please. Can someone help me to find a object oriented way for nesting "where"-s

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  • Zend_Test: No default module defined for this application

    - by jiewmeng
    UPDATE 23 Dec I had the problem where Zend Framework complains about "No default module defined for this application". I didn't use Modules and the main app works fine. I finally solved the problem with the help from weierophinney.net Your bootstrap needs to minimally set the controller directory -- do a call to $this->frontController->addControllerDirectory(...) in your appBootstrap() method. I didn't in my example, as my Initialization plugin does that sort of thing for me. The problem is solved by adding the below to setUp() $this->getFrontController()->setControllerDirectory(APPLICATION_PATH . '/controllers'); But now, I have afew other questions: 1. Why does that value not get initialized by application.ini? In application.ini, I have [production] resources.frontController.controllerDirectory = APPLICATION_PATH "/controllers" [testing : production] // didn't change anything regarding modules nor controllers 2. I tried setting the controllerDirectory in bootstrap.php of my unit test, but it does not work $front = Zend_Controller_Front::getInstance(); $front->setControllerDirectory(APPLICATION_PATH . '/controllers'); The only way that works is using setUp(). Why is that? END UPDATE 23 Dec I am getting the above error when unit testing my controller plugins. I am not using any modules. in my bootstrap.php for unit testing, I even tried adding $front = Zend_Controller_Front::getInstance(); $front->setDefaultModule('default'); But it still does not work. Anyways my bootstrap.php looks like this UPDATE: the error looks something like There were 2 errors: 1) Application_Controller_Plugin_AclTest::testAccessToUnauthorizedPageRedirectsToLogin Zend_Controller_Exception: No default module defined for this application D:\ResourceLibrary\Frameworks\PHPFrameworks\Zend\Controller\Dispatcher\Standard.php:391 D:\ResourceLibrary\Frameworks\PHPFrameworks\Zend\Controller\Dispatcher\Standard.php:204 D:\ResourceLibrary\Frameworks\PHPFrameworks\Zend\Controller\Dispatcher\Standard.php:244 D:\ResourceLibrary\Frameworks\PHPFrameworks\Zend\Controller\Front.php:954 D:\ResourceLibrary\Frameworks\PHPFrameworks\Zend\Test\PHPUnit\ControllerTestCase.php:205 D:\Projects\Tickle\tests\application\controllers\plugins\aclTest.php:6 2) Application_Controller_Plugin_AclTest::testAccessToAllowedPageWorks Zend_Controller_Exception: No default module defined for this application D:\ResourceLibrary\Frameworks\PHPFrameworks\Zend\Controller\Dispatcher\Standard.php:391 D:\ResourceLibrary\Frameworks\PHPFrameworks\Zend\Controller\Dispatcher\Standard.php:204 D:\ResourceLibrary\Frameworks\PHPFrameworks\Zend\Controller\Dispatcher\Standard.php:244 D:\ResourceLibrary\Frameworks\PHPFrameworks\Zend\Controller\Front.php:954 D:\ResourceLibrary\Frameworks\PHPFrameworks\Zend\Test\PHPUnit\ControllerTestCase.php:205 D:\Projects\Tickle\tests\application\controllers\plugins\aclTest.php:16 UPDATE I tried adding public function setUp() { $front = Zend_Controller_Front::getInstance(); $front->setDefaultModule('default'); } then 1 part works. public function testAccessToUnauthorizedPageRedirectsToLogin() { // this fails with exception "Zend_Controller_Exception: No default module defined for this application" $this->dispatch('/projects'); $this->assertController('auth'); $this->assertAction('login'); } public function testAccessToAllowedPageWorks() { // this passes $auth = Zend_Auth::getInstance(); $authAdapter = new Application_Auth_Adapter('jiewmeng', 'password'); $auth->authenticate($authAdapter); $this->dispatch('/projects'); $this->assertController('projects'); $this->assertAction('index'); }

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  • Virtual host in Apache Zend

    - by llocani
    I'd like to ask you if you can tell me why I can't get Vhost in Apache to work my Vhostconf is: NameVirtualHost *:80 <VirtualHost _default_:80> ServerAdmin [email protected] DocumentRoot "E:/Archivos de programa/Zend/Apache2/htdocs" ServerName localhost <Directory "E:/Archivos de programa/Zend/Apache2/htdocs"> Options FollowSymLinks AllowOverride All Order allow,deny Allow from all </Directory> #AllowOveride all </VirtualHost> <VirtualHost *:80> ServerAdmin [email protected] DocumentRoot "E:/Documents and Settings/dvieira/Mis documentos/NetBeansProjects/HealingHands" ServerName healinghands.loc <Directory "E:/Documents and Settings/dvieira/Mis documentos/NetBeansProjects/HealingHands"> Options FollowSymLinks AllowOverride All Order allow,deny Allow from all </Directory> ErrorLog "E:/Documents and Settings/dvieira/Mis documentos/NetBeansProjects/HealingHands/logs/error.log" CustomLog "E:/Documents and Settings/dvieira/Mis documentos/NetBeansProjects/HealingHands/logs/access.log" common #AllowOveride all </VirtualHost> <VirtualHost *:80> ServerAdmin [email protected] DocumentRoot "E:/Documents and Settings/dvieira/Mis documentos/NetBeansProjects" ServerName dev.loc <Directory "E:/Documents and Settings/dvieira/Mis documentos/NetBeansProjects"> Options FollowSymLinks AllowOverride All Order allow,deny Allow from all </Directory> ErrorLog "E:/Documents and Settings/dvieira/Mis documentos/NetBeansProjects/logs/error.log" CustomLog "E:/Documents and Settings/dvieira/Mis documentos/NetBeansProjects/logs/access.log" common #AllowOveride all </VirtualHost> My httpd.conf is: ServerRoot "E:\Archivos de programa\Zend\Apache2" Listen 80 LoadModule actions_module modules/mod_actions.so LoadModule alias_module modules/mod_alias.so LoadModule asis_module modules/mod_asis.so LoadModule auth_basic_module modules/mod_auth_basic.so LoadModule auth_digest_module modules/mod_auth_digest.so LoadModule authn_default_module modules/mod_authn_default.so LoadModule authn_file_module modules/mod_authn_file.so LoadModule authz_default_module modules/mod_authz_default.so LoadModule authz_groupfile_module modules/mod_authz_groupfile.so LoadModule authz_host_module modules/mod_authz_host.so LoadModule authz_user_module modules/mod_authz_user.so LoadModule autoindex_module modules/mod_autoindex.so LoadModule cgi_module modules/mod_cgi.so LoadModule dir_module modules/mod_dir.so LoadModule env_module modules/mod_env.so LoadModule filter_module modules/mod_filter.so LoadModule headers_module modules/mod_headers.so LoadModule imagemap_module modules/mod_imagemap.so LoadModule include_module modules/mod_include.so LoadModule info_module modules/mod_info.so LoadModule isapi_module modules/mod_isapi.so LoadModule log_config_module modules/mod_log_config.so LoadModule mime_module modules/mod_mime.so LoadModule mime_magic_module modules/mod_mime_magic.so LoadModule negotiation_module modules/mod_negotiation.so LoadModule rewrite_module modules/mod_rewrite.so LoadModule setenvif_module modules/mod_setenvif.so LoadModule ssl_module modules/mod_ssl.so LoadModule status_module modules/mod_status.so LoadModule userdir_module modules/mod_userdir.so <IfModule !mpm_netware_module> <IfModule !mpm_winnt_module> User daemon Group daemon </IfModule> </IfModule> ServerAdmin [email protected] DocumentRoot "E:\Archivos de programa\Zend\Apache2/htdocs" <Directory /> Options FollowSymLinks AllowOverride all Order allow,deny Allow from all </Directory> <IfModule dir_module> DirectoryIndex index.php index.html home.php </IfModule> <FilesMatch "^\.ht"> Order allow,deny Deny from all Satisfy All </FilesMatch> ErrorLog "logs/error.log" LogLevel warn <IfModule log_config_module> LogFormat "%h %l %u %t \"%r\" %>s %b \"%{Referer}i\" \"%{User-Agent}i\"" combined LogFormat "%h %l %u %t \"%r\" %>s %b" common <IfModule logio_module> LogFormat "%h %l %u %t \"%r\" %>s %b \"%{Referer}i\" \"%{User-Agent}i\" %I %O" combinedio </IfModule> CustomLog "logs/access.log" common </IfModule> <IfModule alias_module> Alias /NetBeansProjects "E:\Documents and Settings\dvieira\Mis documentos\NetBeansProjects" ScriptAlias /cgi-bin/ "E:\Archivos de programa\Zend\Apache2/cgi-bin/" </IfModule> <IfModule cgid_module> </IfModule> <Directory "E:\Archivos de programa\Zend\Apache2/cgi-bin"> AllowOverride None Options None Order allow,deny Allow from all </Directory> DefaultType text/plain <IfModule mime_module> TypesConfig conf/mime.types AddType application/x-compress .Z AddType application/x-gzip .gz .tgz </IfModule> Include conf/extra/httpd-vhosts.conf <IfModule ssl_module> SSLRandomSeed startup builtin SSLRandomSeed connect builtin </IfModule> Include "conf/zend.conf" NameVirtualHost *:80 <VirtualHost *:80> Include "E:\Archivos de programa\Zend\ZendServer/etc/sites.d/zend-default-vhost-80.conf" </VirtualHost> Include "E:\Archivos de programa\Zend\ZendServer/etc/sites.d/globals-*.conf" Include "E:\Archivos de programa\Zend\ZendServer/etc/sites.d/vhost_*.conf" And my host in Windows: 127.0.0.1 localhost 127.0.0.1 healinghands.loc 127.0.0.1 dev.loc And I can't get any of the browser to recognize dev.loc or healinghands.loc but a ping does it. Localhost is working fine. I've spent 3 days now traying to solve this for my one but I finally quit and have to ask. The error should be this Error Code 11002: host not found. Background: this error indicates that the gateway could not find an authoritative DNS server for the website you are trying to access. Date: 5/20/2013 5:51:03 PM Server: Source: DNS problem. i'd like to add this ping Haciendo ping a healinghands.loc [127.0.0.1] con 32 bytes de datos: Respuesta desde 127.0.0.1: bytes=32 tiempo<1m TTL=128 Respuesta desde 127.0.0.1: bytes=32 tiempo<1m TTL=128 Respuesta desde 127.0.0.1: bytes=32 tiempo<1m TTL=128 Respuesta desde 127.0.0.1: bytes=32 tiempo<1m TTL=128 Estadísticas de ping para 127.0.0.1: Paquetes: enviados = 4, recibidos = 4, perdidos = 0 (0% perdidos), Tiempos aproximados de ida y vuelta en milisegundos: Mínimo = 0ms, Máximo = 0ms, Media = 0ms Today i've tryed something: i've add this domains into the exceptions of mi ie proxy config. This worked for healinghands.loc but not for dev.loc i really do not understand why, both config are exactly the same except for de documentroot. I will continue searching

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  • Is there any real advantage to use zend ce server over just referencing (include) the zend framework library?

    - by Marcos Roriz
    Hi, I'm new to PHP frameworks, and currently I'm trying Zend Framework (ZF). I'm old fashioned when it comes to installing software, I like to install apache/mysql/php all separetely since I find easier and it gives me more control of it. It seems that the "encouraged" way to develop with Zend Framework is using the Zend (CE) Server. I personally don't like this idea of a app install everything else (PHP/Apache and so on). From what I've seen if I include Zend Framework Library in php.ini path I'm ready to go. So is there any real advantage to use the Full Zend (CE) Server??

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  • Is DB2 Connect neccessary if I'm using Zend Server for i5/OS?

    - by tiraeth
    I have Zend Server for i5/OS and want to connect (in PHP) to local DB2 Instance. Do I need DB2 Connect product to call any program on i5/OS? If I can use ODBC Driver, can somebody - please - give me an url to some place where I can download it (OpenSource?) ? Another question: Is there any PDO_ODBC or ODBC adapter for Zend Framework's Zend_Db?

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  • How to know that a php project is using Zend framework?

    - by Wing C. Chen
    I am writing a piece of small software to go through the folders and files of all the php projects that are passed in and detect if any of them is actually also a Zend project. Is there any particular file that I can immediately read and tell that the current project is a Zend project? or is there any convenient way to tell?

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  • SQL SERVER – Example of Performance Tuning for Advanced Users with DB Optimizer

    - by Pinal Dave
    Performance tuning is such a subject that everyone wants to master it. In beginning everybody is at a novice level and spend lots of time learning how to master the art of performance tuning. However, as we progress further the tuning of the system keeps on getting very difficult. I have understood in my early career there should be no need of ego in the technology field. There are always better solutions and better ideas out there and we should not resist them. Instead of resisting the change and new wave I personally adopt it. Here is a similar example, as I personally progress to the master level of performance tuning, I face that it is getting harder to come up with optimal solutions. In such scenarios I rely on various tools to teach me how I can do things better. Once I learn about tools, I am often able to come up with better solutions when I face the similar situation next time. A few days ago I had received a query where the user wanted to tune it further to get the maximum out of the performance. I have re-written the similar query with the help of AdventureWorks sample database. SELECT * FROM HumanResources.Employee e INNER JOIN HumanResources.EmployeeDepartmentHistory edh ON e.BusinessEntityID = edh.BusinessEntityID INNER JOIN HumanResources.Shift s ON edh.ShiftID = s.ShiftID; User had similar query to above query was used in very critical report and wanted to get best out of the query. When I looked at the query – here were my initial thoughts Use only column in the select statements as much as you want in the application Let us look at the query pattern and data workload and find out the optimal index for it Before I give further solutions I was told by the user that they need all the columns from all the tables and creating index was not allowed in their system. He can only re-write queries or use hints to further tune this query. Now I was in the constraint box – I believe * was not a great idea but if they wanted all the columns, I believe we can’t do much besides using *. Additionally, if I cannot create a further index, I must come up with some creative way to write this query. I personally do not like to use hints in my application but there are cases when hints work out magically and gives optimal solutions. Finally, I decided to use Embarcadero’s DB Optimizer. It is a fantastic tool and very helpful when it is about performance tuning. I have previously explained how it works over here. First open DBOptimizer and open Tuning Job from File >> New >> Tuning Job. Once you open DBOptimizer Tuning Job follow the various steps indicates in the following diagram. Essentially we will take our original script and will paste that into Step 1: New SQL Text and right after that we will enable Step 2 for Generating Various cases, Step 3 for Detailed Analysis and Step 4 for Executing each generated case. Finally we will click on Analysis in Step 5 which will generate the report detailed analysis in the result pan. The detailed pan looks like. It generates various cases of T-SQL based on the original query. It applies various hints and available hints to the query and generate various execution plans of the query and displays them in the resultant. You can clearly notice that original query had a cost of 0.0841 and logical reads about 607 pages. Whereas various options which are just following it has different execution cost as well logical read. There are few cases where we have higher logical read and there are few cases where as we have very low logical read. If we pay attention the very next row to original query have Merge_Join_Query in description and have lowest execution cost value of 0.044 and have lowest Logical Reads of 29. This row contains the query which is the most optimal re-write of the original query. Let us double click over it. Here is the query: SELECT * FROM HumanResources.Employee e INNER JOIN HumanResources.EmployeeDepartmentHistory edh ON e.BusinessEntityID = edh.BusinessEntityID INNER JOIN HumanResources.Shift s ON edh.ShiftID = s.ShiftID OPTION (MERGE JOIN) If you notice above query have additional hint of Merge Join. With the help of this Merge Join query hint this query is now performing much better than before. The entire process takes less than 60 seconds. Please note that it the join hint Merge Join was optimal for this query but it is not necessary that the same hint will be helpful in all the queries. Additionally, if the workload or data pattern changes the query hint of merge join may be no more optimal join. In that case, we will have to redo the entire exercise once again. This is the reason I do not like to use hints in my queries and I discourage all of my users to use the same. However, if you look at this example, this is a great case where hints are optimizing the performance of the query. It is humanly not possible to test out various query hints and index options with the query to figure out which is the most optimal solution. Sometimes, we need to depend on the efficiency tools like DB Optimizer to guide us the way and select the best option from the suggestion provided. Let me know what you think of this article as well your experience with DB Optimizer. Please leave a comment. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Joins, SQL Optimization, SQL Performance, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • Static content not displayed with Zend FW

    - by shin
    I am trying to display a static content with Zend framework. When I go to http://square.localhost/content/services, I get an error message. Could anyone tell me how to fix this please? Thanks in advance. application.ini .... .... resources.layout.layoutPath = APPLICATION_PATH "/layouts" resources.layout.layout = "master" resources.router.routes.home.route = /home resources.router.routes.home.defaults.module = default resources.router.routes.home.defaults.controller = index resources.router.routes.home.defaults.action = index resources.router.routes.static-content.route = /content/:page resources.router.routes.static-content.defaults.module = default resources.router.routes.static-content.defaults.controller = static-content resources.router.routes.static-content.defaults.action = display application/modules/default/controllers/StaticContentController.php class StaticContentController extends Zend_Controller_Action { public function init() { } // display static views public function displayAction() { $page = $this->getRequest()->getParam('page'); if (file_exists($this->view->getScriptPath(null) . "/" . $this->getRequest()->getControllerName() . "/$page." . $this->viewSuffix)) { $this->render($page); } else { throw new Zend_Controller_Action_Exception('Page not found', 404); } } } application/modules/default/views/scripts/static-content/services.phtml some html ... ... Error message An error occurred Page not found Exception information: Message: Page not found Stack trace: #0 /var/www/square/library/Zend/Controller/Action.php(513): StaticContentController->displayAction() #1 /var/www/square/library/Zend/Controller/Dispatcher/Standard.php(295): Zend_Controller_Action->dispatch('displayAction') #2 /var/www/square/library/Zend/Controller/Front.php(954): Zend_Controller_Dispatcher_Standard->dispatch(Object(Zend_Controller_Request_Http), Object(Zend_Controller_Response_Http)) #3 /var/www/square/library/Zend/Application/Bootstrap/Bootstrap.php(97): Zend_Controller_Front->dispatch() #4 /var/www/square/library/Zend/Application.php(366): Zend_Application_Bootstrap_Bootstrap->run() #5 /var/www/square/public/index.php(26): Zend_Application->run() #6 {main} Request Parameters: array ( 'page' => 'services', 'module' => 'default', 'controller' => 'static-content', 'action' => 'display', )

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  • Problem connecting to MySQL with zend

    - by wheresrhys
    I've set up a virtual host on my local machine (windows xp with xampp installed), have installed zend there and am now trying to connect to the MySQLdatabase. I get the following error message: Message: SQLSTATE[HY000] [2003] Can't connect to MySQL server on ''myhost.com'' (10060) All the tips I've found via google haven't helped. I use kaspersky antivirus and have added port 3306 to the allowed list for MySQL and Apache. I've also pinged myhost.com:3306 and get a response (with ip address 67.63.50.51), though localhost:3306 and 127.0.0.1:3306 aren't found. I've checked that other apps can still access MySQL if the virtual host is pointed at them instead and my non zend apps do work. I guess I have to do something further to the port, or maybe force the app to use a different port, but am not sure how to do either. Any help appreciated.

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  • Problem connecting to MySQL with zend

    - by wheresrhys
    I've set up a virtual host on my local machine (windows xp with xampp installed), have installed zend there and am now trying to connect to the MySQLdatabase. I get the following error message: Message: SQLSTATE[HY000] [2003] Can't connect to MySQL server on ''myhost.com'' (10060) All the tips I've found via google haven't helped. I use kaspersky antivirus and have added port 3306 to the allowed list for MySQL and Apache. I've also pinged myhost.com:3306 and get a response (with ip address 67.63.50.51), though localhost:3306 and 127.0.0.1:3306 aren't found. I've checked that other apps can still access MySQL if the virtual host is pointed at them instead and my non zend apps do work. I guess I have to do something further to the port, or maybe force the app to use a different port, but am not sure how to do either. Any help appreciated.

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  • phpmyadmin throws a blank page after installing Zend CE server

    - by infotoknowledge
    I installed LAMP on Ubuntu 12.0.4 LTE. Then I installed phpmyadmin. Everything was good. I used phpadmin to do lots of DB administration.... Then I installed Zend CE server. Now, phpmyadmin throws a blank page. No login screen. So, I reinstalled my VPS in the same sequence again. No luck. Same behavior. This time, I installed Apache, Mysql, PHP and Zend server in that order. Then I installed phpmyadmin....Unfortunately, still blank page on phpmyadmin. Any help?...Thanks in advance.

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  • Display subform after validate main form

    - by bahamut100
    Hi, I want to display a new form after the validation of a form. I use Zend_Form_SubForm to do it (I Try to Zend_Form too), but this new form is not displaying. Why ?? This is the code in question : if ($this->_request->isPost()) { $formData = $this->_request->getPost(); if ($form->isValid($formData)) { $subForm = new Zend_Form_SubForm(); $subForm ->setAction('') ->setMethod('post'); $nom=new Zend_Form_Element_Text('nom'); $submit = new Zend_Form_Element_Submit('submit'); $submit->setLabel('OK'); $subForm->addElements(array($nom,$submit)); } else { $form->populate($formData); } }

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  • zend_form ViewScript decorator / passing arguments

    - by timpone
    I have a form that is extend from Zend_Form. I am placing the form into a ViewScript decorator like this: $this->setDecorators(array(array('ViewScript', array('viewScript' => 'game/forms/game-management.phtml')))); I'd like to pass in a variable to this ViewScript but am not sure how this could be done. Since the partial renders out as a Zend_View (allowing $this-app_store_icon for rendering), it seems like there should be a way to pass variables to be rendered. I tried the following but to no avail. $this->setDecorators(array(array('ViewScript', array('viewScript' => 'game/forms/game-management.phtml'),array('app_store_picon'=>$current_app_store_picon)))); Any help on how to get this done would be appreciated. thanks

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  • Setting the inner html text of a < span > element using Zend_Form_Decorators

    - by Mallika Iyer
    I'm trying to set the inner html of the < span tag here , so it looks like: Group this is what i have so far: $form->addDisplayGroup( array( ................ ), 'maingroup1', array( 'legend'=>'', 'disableDefaultDecorators'=> true, 'decorators'=> array('FormElements', array('FieldSet',array('class'=>'dashed-outline2')), array(array('SpanTag' => 'HtmlTag'), array('tag'=>'span','class' => 'group',)), array('HtmlTag',array('tag'=>'div','id'=>'group1','class'=>'group','openOnly'=> true)) ) ) ); Is there a setter / property that I can use to set the inner text of the < span element using Zend_form_decorators? Thanks.

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  • How to add CSS classes to Zend_Form_Element_Select option

    - by Jah Selassie
    Hi, I'm trying to add a CSS class to a Zend_Form_Element_Select option, but I just can't find a way to do it. The desired output would be something like this: <select name="hey" id="hey"> <option value="value1" style="parent">label1</option> <option value="value2" style="sibling">sublabel1</option> <option value="value3" style="sibling">sublabel2</option> <option value="value4" style="parent">label2</option> <option value="value5" style="sibling">sublabel3</option> <option value="value6" style="sibling">sublabel4</option> </select> But I'm getting this: <select name="hey" id="hey"> <option value="value1">label1</option> <option value="value2">sublabel1</option> <option value="value3">sublabel2</option> <option value="value4">label2</option> <option value="value5">sublabel3</option> <option value="value6">sublabel4</option> </select> I can't seem to pass a CSS class attribute to any of the options in the select element although I can style the select element itselft. My code: $sel = new Zend_Form_Element_Select('hey'); $sel->setRequired(true)->setLabel('Select an Option:'); $sel->addMultiOption('value1', 'label1', array('class' => 'parent')) ->addMultiOption('value2', 'sublabel1', array('class' => 'sibling')) (etc...); After researching a bit I found out that Element_Select doesn't have a method for adding CSS styles to the options in the select box, only for the select itself. So, how can I add them? Should I extend the form_element_select? Or would a custom decorator suffice? Can anyone give me a hint? I'm baffled with this. Thanks in advance!

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  • management users with Zend_Auth and Zend_Session

    - by user1400
    I want to Zend_Auth and Zend_Session to save user sessions and logins information whats the easy and best way for implements following items: 1-Disallow multiple concurrent logins for the specific user 2-List all of all user currently logged in 3-Admin could logout of specific user or destroy specific session Is there any special ZF or PHP API or library that can do the above? thanks

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  • How can I append a description to a Zend_Form_Element?

    - by Mallika Iyer
    I have the following Zend_Form_Element: $imginstructions = "Some description"; $img = $this->createElement('select','img'); $img->setAttrib('class', 'image-select'); $imgdecorator = $img->getDecorator('Description'); $imgdecorator->setOption('escape', false); $img->setLabel('Image:') ->setRequired(true) ->addMultiOptions($images) ->setValue('') ->setDescription($imginstructions) ->addErrorMessage('You must select an image'); $img->size = 5; $this->addElement($img); The description should appear next to the select box. The problem is : When an error is thrown, the html rendered changes so the description shows up below the select box, instead of beside it. HTML rendered before error is thrown: <dd id="img-element"> <select size="5" class="image-select" id="img" name="img" style="display: none;"> ...........options.............. </select> <p class="description">Some Description</p></dd> HTML rendered after error is thrown: <dd id="img-element"> <select size="5" class="image-select" id="img" name="img" style="display: none;"> ...........options.............. </select> <ul class="errors"><li>You must select an image</li></ul> <p class="description">Some Description</p></dd> Is there a way to force the error message to be appended as the last element in the DOM tree for the dd element? Something like: <dd id="img-element"> <select size="5" class="image-select" id="img" name="img" style="display: none;"> ...........options.............. </select> <p class="description">Some Description</p> <ul class="errors"><li>You must select an image</li></ul></dd> so the 'ul' is at the end of the dd DOM tree. Thanks, I appreciate your taking the time to respond to this question!

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  • Some question about Zend_Auth and Zend_Session

    - by user1400
    I want to Zend_Auth and Zend_Session to save user sessions and logins information whats the easy and best way for implements following items: 1-Disallow multiple concurrent logins for the specific user 2-List all of all user currently logged in 3-Admin could logout of specific user or destroy specific session Is there any special ZF or PHP API or library that can do the above? thanks

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  • What's the simplest way to create a Zend_Form tabular display with each row having a radio button?

    - by RenderIn
    I've seen simple examples of rendering a Zend_Form using decorators, but I'm not sure they are able to handle the issue I'm facing very well. I query the database and get an array of user objects. I want to display these users as a form, with a radio button next to each of them and a submit button at the bottom of the page. Here's roughly what the form will look like: [user id] [email] [full name] ( ) 1 [email protected] Test user 1 (*) 2 [email protected] Test user 2 [SUBMIT] Is this something achievable in a reasonably straightforward way or do I need to use the ViewScript partial?

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  • row specific class

    - by stimpie
    How do I create a Zend_Db_Table which returns a different class for each row.? Example UserTable has id,name and type Type contains class names (admin,client,etc...) The classes admin, client are all subclasses of user If I call fetch I need to get a admin or client object depending on the corresponding value in the db.

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  • Inject filter into Zend_View

    - by chelmertz
    Hi! I wish to set some properties in MyFilter with constructor injection but it seems impossible with Zend_View::addFilter(string $filter_class_name) since it loads a new instance upon usage. MyFilter implements Zend_Filter_Interface. Can I somehow inject an instance of a filter to an instance of Zend_View?

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