Search Results

Search found 3554 results on 143 pages for 'django modelforms'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 100/143 | < Previous Page | 96 97 98 99 100 101 102 103 104 105 106 107  | Next Page >

  • Creating a User Registration Page using MongoEngine

    - by Drew Watkins
    I am currently working an a webapp, using mongoengine and django, which will require users to create an account from a registration page. I know MongoEngine has an authentication backend, but does it also include a registration form, etc..., like django itself does? If not, are there any example projects which show how to implement this? The only open-source mongoengine project I've found is django-mumblr, but I can't find the examples I want in it. I'm not interested in alternative options, such as MongoKit or mango for handling authentication. I am just getting started with django and mongoDB, so please excuse my lack of knowledge. Thanks in advance for the help!

    Read the article

  • How do I use multiple settings file in Django with multiple sites on one server?

    - by William Bing Hua
    I have an ec2 instance running Ubuntu 14.04 and I want to host two sites from it. On my first site I have two settings file, production_settings.py and settings.py (for local development). I import the local settings into the production settings and override any settings with the production settings file. Since my production settings file is not the default settings.py name, I have to create an environment variable DJANGO_SETTINGS_MODULE='site1.production_settings' However because of this whenever I try to start my second site it says No module named site1.production_settings I am assuming that this is due to me setting the environment variable. Another problem is that I won't be able to use different settings file for different sites. How do I start use two different settings file for two different websites?

    Read the article

  • Django Problem - trying to access data entered into a form and feed it through a different page

    - by John Hoke
    OK, so let me give you an overview first. I have this site and in it there is a form section. When you access that section you can view or start a new project. Each project has 3-5 different forms. My problem is that I don't want viewers to have to go through all 3-5 pages to see the relevant information they need. Instead I want to give each project a main page where all the essential data entered into the forms is shown as non-editable data. I hope this makes sense. So I need to find a way to access all that data from the different forms for each project and to feed that data into the new page I'll be calling "Main". Each project will have a separate main page for itself. I'm pretty much clueless as to how I should do this, so any help at all would be appreciated. Thanks

    Read the article

  • How can I update only certain fields in a Django model form?

    - by J. Frankenstein
    I have a model form that I use to update a model. class Turtle(models.Model): name = models.CharField(max_length=50, blank=False) description = models.TextField(blank=True) class TurtleForm(forms.ModelForm): class Meta: model = Turtle Sometimes I don't need to update the entire model, but only want to update one of the fields. So when I POST the form only has information for the description. When I do that the model never saves because it thinks that the name is being blanked out while my intent is that the name not change and just be used from the model. turtle_form = TurtleForm(request.POST, instance=object) if turtle_form.is_valid(): turtle_form.save() Is there any way to make this happen? Thanks!

    Read the article

  • Installing OSQA on windows(Local system)

    - by Pankaj Khurana
    Hi I want to install osqa on windows local system for this i have downloaded bitnami-djangostack-1.1.1-2-windows-installer.exe which has in built django,python,mysql & apache. I have run a django example given on the django website. Its working fine. But i am confused how to install osqa. I have downloaded the source code available on osqa site and readed the installation instruction(requires django 1.1.1). But how to make it working? Please help me on this Thanks

    Read the article

  • Is there a better way to format this Python/Django code as valid PEP8?

    - by Ryan Detzel
    I have code written both ways and I see flaws in both of them. Is there another way to write this or is one approach more "correct" than the other? def functionOne(subscriber): try: results = MyModelObject.objects.filter( project__id=1, status=MyModelObject.STATUS.accepted, subscriber=subscriber).values_list( 'project_id', flat=True).order_by('-created_on') except: pass def functionOne(subscriber): try: results = MyModelObject.objects.filter( project__id=1, status=MyModelObject.STATUS.accepted, subscriber=subscriber) results = results.values_list('project_id', flat=True) results = results.order_by('-created_on') except: pass

    Read the article

  • Best practice: How to persist simple data without a database in django?

    - by Infinity
    I'm building a website that doesn't require a database because a REST API "is the database". (Except you don't want to be putting site-specific things in there, since the API is used by mostly mobile clients) However there's a few things that normally would be put in a database, for example the "jobs" page. You have master list view, and the detail views for each job, and it should be easy to add new job entries. (not necessarily via a CMS, but that would be awesome) e.g. example.com/careers/ and example.com/careers/77/ I could just hardcode this stuff in templates, but that's no DRY- you have to update the master template and the detail template every time. What do you guys think? Maybe a YAML file? Or any better ideas? Thx

    Read the article

  • How can I traverse a reverse generic relation in a Django template?

    - by user569139
    I have the following class that I am using to bookmark items: class BookmarkedItem(models.Model): is_bookmarked = models.BooleanField(default=False) user = models.ForeignKey(User) content_type = models.ForeignKey(ContentType) object_id = models.PositiveIntegerField() content_object = generic.GenericForeignKey() And I am defining a reverse generic relationship as follows: class Link(models.Model): url = models.URLField() bookmarks = generic.GenericRelation(BookmarkedItem) In one of my views I generate a queryset of all links and add this to a context: links = Link.objects.all() context = { 'links': links } return render_to_response('links.html', context) The problem I am having is how to traverse the generic relationship in my template. For each link I want to be able to check the is_bookmarked attribute and change the add/remove bookmark button according to whether the user already has it bookmarked or not. Is this possible to do in the template? Or do I have to do some additional filtering in the view and pass another queryset?

    Read the article

  • [Django] How do I filter the choices in a ModelForm that has a CharField with the choices attribute

    - by nubela
    I understand I am able to filter queryset of Foreignkey or Many2ManyFields, however, how do I do that for a simple CharField that is a Select Widget (Select Tag). For example: PRODUCT_STATUS = ( ("unapproved", "Unapproved"), ("approved", "Listed"), #("Backorder","Backorder"), #("oos","Out of Stock"), #("preorder","Preorder"), ("userdisabled", "User Disabled"), ("disapproved", "Disapproved by admin"), ) and the Field: o_status = models.CharField(max_length=100, choices=PRODUCT_STATUS, verbose_name="Product Status", default="approved") Suppose I wish to limit it to just "approved" and "userdisabled" instead showing the full array (which is what I want to show in the admin), how do I do it? Thanks!

    Read the article

  • what is the 'extra' mean in this django code..

    - by zjm1126
    TOPIC_COUNT_SQL = """ SELECT COUNT(*) FROM topics_topic WHERE topics_topic.object_id = maps_map.id AND topics_topic.content_type_id = %s """ MEMBER_COUNT_SQL = """ SELECT COUNT(*) FROM maps_map_members WHERE maps_map_members.map_id = maps_map.id """ maps = maps.extra(select=SortedDict([ ('member_count', MEMBER_COUNT_SQL), ('topic_count', TOPIC_COUNT_SQL), ]), select_params=(content_type.id,)) i don't know this mean, thanks

    Read the article

  • Django database - how to add this column in raw SQL.

    - by alex
    Suppose I have my models set up already. class books(models.Model): title = models.CharField... ISBN = models.Integer... What if I want to add this column to my table? user = models.ForeignKey(User, unique=True) How would I write the raw SQL in my database so that this column works?

    Read the article

  • Django - Problem with models/manager to organise a query...

    - by user296644
    Hi, I have an application to count the number of access to an object for each website in a same database. class SimpleHit(models.Model): """ Hit is the hit counter of a given object """ content_type = models.ForeignKey(ContentType) object_id = models.PositiveIntegerField() content_object = generic.GenericForeignKey('content_type', 'object_id') site = models.ForeignKey(Site) hits_total = models.PositiveIntegerField(default=0, blank=True) [...] class SimpleHitManager(models.Manager): def get_query_set(self): print self.model._meta.fields qset = super(SimpleHitManager, self).get_query_set() qset = qset.filter(hits__site=settings.SITE_ID) return qset class SimpleHitBase(models.Model): hits = generic.GenericRelation(SimpleHit) objects = SimpleHitManager() _hits = None def _db_get_hits(self, only=None): if self._hits == None: try: self._hits = self.hits.get(site=settings.SITE_ID) except SimpleHit.DoesNotExist: self._hits = SimpleHit() return self._hits @property def hits_total(self): return self._db_get_hits().hits_total [...] class Meta: abstract = True And I have a model like: class Model(SimpleHitBase): name = models.CharField(max_length=255) url = models.CharField(max_length=255) rss = models.CharField(max_length=255) creation = AutoNowAddDateTimeField() update = AutoNowDateTimeField() So, my problem is this one: when I call Model.objects.all(), I would like to have one request for the SQL (not two). In this case: one for Model in order to have information and one for the hits in order to have the counter (hits_total). This is because I cannot call directly hits.hits_total (due to SITE_ID?). I have tried select_related, but it seems to do not work... Question: - How can I add column automatically like (SELECT hits.hits_total, model.* FROM [...]) to the queryset? - Or use a functional select_related with my models? I want this model could be plugable on all other existing model. Thank you, Best regards.

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 96 97 98 99 100 101 102 103 104 105 106 107  | Next Page >