Search Results

Search found 15132 results on 606 pages for 'home improvement'.

Page 100/606 | < Previous Page | 96 97 98 99 100 101 102 103 104 105 106 107  | Next Page >

  • Getting a `free()` error when deallocating with `delete` in the backtrace

    - by wonko
    I got the following error from gdb: *** glibc detected *** /.root0/autohome/u132/hsreekum/ipopt/ipopt/debug/Ipopt/examples/ex3/ex3: free(): invalid next size (fast): 0x0000000120052b60 *** Here's the backtrace: #0 0x000000555626b264 in raise () from /lib/libc.so.6 #1 0x000000555626cc6c in abort () from /lib/libc.so.6 #2 0x00000055562a7b9c in __libc_message () from /lib/libc.so.6 #3 0x00000055562aeabc in malloc_printerr () from /lib/libc.so.6 #4 0x00000055562b036c in free () from /lib/libc.so.6 #5 0x000000555561ddd0 in Ipopt::TNLPAdapter::~TNLPAdapter () from /home/ba01/u132/hsreekum/ipopt/ipopt/build/lib/libipopt.so.1 #6 0x00000055556a9910 in Ipopt::GradientScaling::~GradientScaling () from /home/ba01/u132/hsreekum/ipopt/ipopt/build/lib/libipopt.so.1 #7 0x00000055557241b8 in Ipopt::OrigIpoptNLP::~OrigIpoptNLP () from /home/ba01/u132/hsreekum/ipopt/ipopt/build/lib/libipopt.so.1 #8 0x00000055556ae7f0 in Ipopt::IpoptAlgorithm::~IpoptAlgorithm () from /home/ba01/u132/hsreekum/ipopt/ipopt/build/lib/libipopt.so.1 #9 0x0000005555602278 in Ipopt::IpoptApplication::~IpoptApplication () from /home/ba01/u132/hsreekum/ipopt/ipopt/build/lib/libipopt.so.1 #10 0x0000005555614428 in FreeIpoptProblem () from /home/ba01/u132/hsreekum/ipopt/ipopt/build/lib/libipopt.so.1 #11 0x0000000120001610 in main () at ex3.c:169` And here's the code for Ipopt::TNLPAdapter::~TNLPAdapter () TNLPAdapter::~TNLPAdapter() { delete [] full_x_; delete [] full_lambda_; delete [] full_g_; delete [] jac_g_; delete [] c_rhs_; delete [] jac_idx_map_; delete [] h_idx_map_; delete [] x_fixed_map_; delete [] findiff_jac_ia_; delete [] findiff_jac_ja_; delete [] findiff_jac_postriplet_; delete [] findiff_x_l_; delete [] findiff_x_u_; } My question is : why does free() throw an error when ~TNLPAdapter() uses delete[]? Also, I would like to step through ~TNLPAdapter() so I can see which deallocation causes the error. I believe the error occurs in the external library (IPOPT) but I have compiled it with debug flags on ; is this sufficient?

    Read the article

  • div content change only jquery Mobile

    - by user3659748
    I have that : <div data-role="page" id="Home"> <div data-role="header" > <h2 class="header">My app</h2> </div> <div data-role="content"> </div> <div data-role="footer" data-position="fixed"> <div data-role="navbar"> <ul> <li><a href="partials/home.html" data-icon="home" data-transition="slide">Home</a></li> <li><a href="partials/about.html" data-icon="info">About</a></li> </ul> </div> </div> </div> </body> I want when a users click on links le content slide on a div content of for exemple home.html who have just that : home that is possible or not ? Thanks :)

    Read the article

  • How to Assign a Static IP to an Ubuntu 10.04 Desktop Computer

    - by Mysticgeek
    If you have a home network with several computers, assigning them static IP addresses can make troubleshooting easier. Today we take a look at switching from DHCP to a static IP in Ubuntu. Assign a Static IP Using Static IPs prevents address conflicts between machines and can allow easier access to them. If you have a small home network and are satisfied with the machines getting their IP address automatically via DHCP, there won’t be anything gained by using static addresses. Using Static IPs isn’t necessarily for the average user, but if you’re a geek who wants to know the address assigned to each machine, it can allow for faster troubleshooting.  To change your Ubuntu machine to a Static IP go to System \ Preferences \ Network Connections. In our example, we’re on a wired system so click on the Wired tab, then select Auto eth0 and click on Edit. Select the IPv4 settings tab, change Method to Manual, click the Add button. Then type in the Static IP Address, Subnet Mask, DNS Servers, and Default Gateway. Then click Apply when you’re finished. Make sure to hit Enter after typing in the Default Gateway otherwise it will revert back to 0.0.0.0 You’ll need to enter in your admin password before the changes go into affect. To verify the changes have been made successfully launch a Terminal session and type in ifconfig at the command prompt, or follow these directions. You also might want to ping the address from another machine to make sure everything is communicating. If you want to assign a Static IP to your Windows machines, check out our article on how to assign a Static IP on Windows systems (make sure to browse the comments as our readers have some good suggestions).  Whether you have a small office or home network set up with a server and several machines, using a Static IP on each device can help you manage them easily. Again, it isn’t for everyone as it really depends on how your network is setup and the way you use it. Similar Articles Productive Geek Tips Change Ubuntu Desktop from DHCP to a Static IP AddressAllow Remote Control To Your Desktop On UbuntuAssign Custom Shortcut Keys on Ubuntu LinuxKeyboard Ninja: 21 Keyboard Shortcut ArticlesChange Ubuntu Server from DHCP to a Static IP Address TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips HippoRemote Pro 2.2 Xobni Plus for Outlook All My Movies 5.9 CloudBerry Online Backup 1.5 for Windows Home Server TubeSort: YouTube Playlist Organizer XPS file format & XPS Viewer Explained Microsoft Office Web Apps Guide Know if Someone Accessed Your Facebook Account Shop for Music with Windows Media Player 12 Access Free Documentaries at BBC Documentaries

    Read the article

  • Reasons to Use a VM For Development

    - by George Stocker
    Background: I work at a start-up company, where one team uses Virtual Machines to connect to a remote server to do their development, and another team (the team I'm on) uses local IIS/SQL Server 2005/Visual Studio installations to conduct work. Team VM is located about 1000 miles from Team Non-VM, and the servers the VMs run off of are located near Team VM (Latency, for those that are wondering, is about 50ms). A person high in the company is pushing for Team Non-VM to use virtual machines for programming, development, and testing. The latter point we agree on -- we want Virtual Machines to test configurations and various aspects of the web application in a 'clean' state. The Problem: What we don't agree on is having developers using RDP to connect to a desktop remotely that contains Visual Studio, SQL Server, and IIS to do the same development we could do locally on our laptops. I've tried the VM set-up, and besides the color issue, there is a latency issue that is rather noticeable, not to mention that since we're a start-up, a good number of employees work from home on occasion with our work laptops, and this move would cut off the laptops. They'd be turned in. Reasons to Use Remote VMs for Development (Not Testing!): Here are the stated reasons that this person wants us to use VMs: They work for TeamVM. They keep the source code "safe". If we want to work from home, we could just use our home PCs. Licenses (I don't know what the argument is, only that it's been used). Reasons not to use Remote VMs for Development: Here are the stated reasons why we don't want to use VMs: We like working from home. We get a lot done on our own time. We're not going to use our Home PCs to do work related stuff. The Latency is noticeable. Support for the VMs (if they go down, or if we need a new VM) takes a while. We don't have administrative privileges on the VM, and are unable to change settings as needed. What I'm looking for from the community is this: What reasons would you give for not using VMs for development? Keep in mind these are remote VMs -- this isn't a VM running on a local desktop. It's using the laptop (or a desktop) as a thin client for a remote VM. Also, on the other side of the coin: Is there something we're missing that makes VMs more palatable for development? Edit: I think 'safe' is used in term of corporate espionage, or more correctly if the Laptop gets stolen, the person who stole would have access to our source code. The former (as we've pointed out, is always going to be a possibility -- companies stop that with litigation, there isn't a technical solution (so far as I can see)). The latter point is ( though I don't know its usefulness in a corporate scenario) mitigated by Truecrypt'ing the entire volume.

    Read the article

  • Installing Yaws server on Ubuntu 12.04 (Using a cloud service)

    - by Lee Torres
    I'm trying to get a Yaws web server working on a cloud service (Amazon AWS). I've compilled and installed a local copy on the server. My problem is that I can't get Yaws to run while running on either port 8000 or port 80. I have the following configuration in yaws.conf: port = 8000 listen = 0.0.0.0 docroot = /home/ubuntu/yaws/www/test dir_listings = true This produces the following successful launch/result: Eshell V5.8.5 (abort with ^G) =INFO REPORT==== 16-Sep-2012::17:21:06 === Yaws: Using config file /home/ubuntu/yaws.conf =INFO REPORT==== 16-Sep-2012::17:21:06 === Ctlfile : /home/ubuntu/.yaws/yaws/default/CTL =INFO REPORT==== 16-Sep-2012::17:21:06 === Yaws: Listening to 0.0.0.0:8000 for <3> virtual servers: - http://domU-12-31-39-0B-1A-F6:8000 under /home/ubuntu/yaws/www/trial - =INFO REPORT==== 16-Sep-2012::17:21:06 === Yaws: Listening to 0.0.0.0:4443 for <1> virtual servers: - When I try to access the the url (http://ec2-72-44-47-235.compute-1.amazonaws.com), it never connects. I've tried using paping to check if port 80 or 8000 is open(http://code.google.com/p/paping/) and I get a "Host can not be resolved" error, so obviously something isn't working. I've also tried setting the yaws.conf so its at Port 80, appearing like this: port = 8000 listen = 0.0.0.0 docroot = /home/ubuntu/yaws/www/test dir_listings = true and I get the following error: =ERROR REPORT==== 16-Sep-2012::17:24:47 === Yaws: Failed to listen 0.0.0.0:80 : {error,eacces} =ERROR REPORT==== 16-Sep-2012::17:24:47 === Can't listen to socket: {error,eacces} =ERROR REPORT==== 16-Sep-2012::17:24:47 === Top proc died, terminate gserv =ERROR REPORT==== 16-Sep-2012::17:24:47 === Top proc died, terminate gserv =INFO REPORT==== 16-Sep-2012::17:24:47 === application: yaws exited: {shutdown,{yaws_app,start,[normal,[]]}} type: permanent {"Kernel pid terminated",application_controller," {application_start_failure,yaws,>>>>>>{shutdown,>{yaws_app,start,[normal,[]]}}}"} I've also opened up the port 80 using iptables. Running sudo iptables -L gives this output: Chain INPUT (policy ACCEPT) target prot opt source destination ACCEPT tcp -- ip-192-168-2-0.ec2.internal ip-192-168-2-16.ec2.internal tcp dpt:http ACCEPT tcp -- 0.0.0.0 anywhere tcp dpt:http ACCEPT all -- anywhere anywhere ctstate RELATED,ESTABLISHED ACCEPT tcp -- anywhere anywhere tcp dpt:http ACCEPT tcp -- anywhere anywhere tcp dpt:http Chain FORWARD (policy ACCEPT) target prot opt source destination Chain OUTPUT (policy ACCEPT) target prot opt source destination In addition, I've gone to the security group panel in the Amazon AWS configuration area, and add ports 80, 8000, and 8080 to ip source 0.0.0.0 Please note: if you try to access the URL of the virtual server now, it likely won't connect because I'm not running currently running the yaws daemon. I've tested it when I've run yaws either through yaws or yaws -i Thanks for the patience

    Read the article

  • How to access files on a drive from an older system, mounted in a new system?

    - by David Thomas
    I've recently built a new system, after a rather large physical injury was sustained by my previous system (a precarious balance, and gravity, were not a happy mix). Surprisingly the /home drive of that system appears to have more-or-less survived the trauma. However... I decided to use a fresh drive for / (and swap) partition(s), and another fresh drive for the new /home. Now that's working, I decided to install the old /home drive (that I had assumed until now would be entirely dead and without capacity for use) into the new system to recover the files and data (so far as is possible). At this point I've run into a snag: I have no idea how to go about this (with Windows it was relatively easy, the new drive would be the latest character of the alphabet, and go from there). With 'disk utility' (System - Administration - Disk Utitlity) I've worked out which drive it is (/dev/sda) but clicking on 'mount' produces an error: 1: helper failed with: mount: according to mtab, /dev/sdb1 is already mounted on / mount failed ...if it is mounted on / I can't see it. I'm also moderately confused by the disk (device /dev/sda) being referred to as /dev/sdb1. Any and all insights would be incredibly welcome (I've already voted for: Idea #9063: New internal hard drives default automount at Brainstorm). Edited in response to Roland's request for a screenshot of disk utility: Details (so far as I know them): 40GB disk is / and swap, 1.0 TB Samsung is /home 1.0 TB Hitachi is from the old system (and was the old /home drive). Output from sudo fdisk -l pasted below: Disk /dev/sda: 1000.2 GB, 1000204886016 bytes 255 heads, 63 sectors/track, 121601 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000bef00 Device Boot Start End Blocks Id System /dev/sda1 1 121601 976760001 83 Linux Disk /dev/sdb: 40.0 GB, 40018599936 bytes 255 heads, 63 sectors/track, 4865 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x00037652 Device Boot Start End Blocks Id System /dev/sdb1 * 1 4742 38084608 83 Linux /dev/sdb2 4742 4866 993281 5 Extended /dev/sdb5 4742 4866 993280 82 Linux swap / Solaris Disk /dev/sdc: 1000.2 GB, 1000204886016 bytes 255 heads, 63 sectors/track, 121601 cylinders Units = cylinders of 16065 * 512 = 8225280 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000e8d46 Device Boot Start End Blocks Id System /dev/sdc1 1 121602 976760832 83 Linux

    Read the article

  • How migrate my keyring (containing ssh passprases, nautilus remote filesystem, pgp passwords) and network manager connections?

    - by con-f-use
    I changed the disk on my laptop and installed Ubuntu on the new disk. Old disk had 12.04 upgraded to 12.10 on it. Now I want to copy my old keyring with WiFi passwords, ftp passwords for nautilus and ssh key passphrases. I have the whole data from the old disk available (is now a USB disk and I did not delete the old data yet or do anything with it - I could still put it in the laptop and boot from it like nothing happened). On the new disc that is now in my laptop, I have installed 12.10 with the same password, user-id and username as on the old disk. Then I copied a few important config files from the old disk (e.g. ~/.firefox/, ~/.mozilla, ~/.skype and so on, which all worked fine... except for the key ring: The old methods of just copying ~/.gconf/... and ~/.gnome2/keyrings won't work. Did I miss something? 1. Edit: I figure one needs to copy files not located in the users home directory as well. I copied the whole old /home/confus (which is my home directory) to the fresh install to no effect. That whole copy is now reverted to the fresh install's home directory, so my /home/confus is as it was the after fresh install. 2. Edit: The folder /etc/NetworkManager/system-connections seems to be the place for WiFi passwords. Could be that /usr/share/keyrings is important as well for ssh keys - that's the only sensible thing that a search came up with: find /usr/ -name "*keyring* 3. Edit: Still no ssh and ftp passwords from the keyring. What I did: Convert old hard drive to usb drive Put new drive in the laptop and installed fresh version of 12.10 there (same uid, username and passwort) Booted from old hdd via USB and copied its /etc/NetwrokManager/system-connections, ~/.gconf/ and ~/.gnome2/keyrings, ~/.ssh over to the new disk. Confirmed that all keys on the old install work Booted from new disk Result: No passphrase for ssh keys, no ftp passwords in keyring. At least the WiFi passwords are migrated. 4. Edit: Boutny! Ending soon... 5. Edit: Keyring's now in ./local/share/keyrings/. Also interesting .gnupg

    Read the article

  • Reasons to Use a VM For Development

    - by George Stocker
    Background: I work at a start-up company, where one team uses Virtual Machines to connect to a remote server to do their development, and another team (the team I'm on) uses local IIS/SQL Server 2005/Visual Studio installations to conduct work. Team VM is located about 1000 miles from Team Non-VM, and the servers the VMs run off of are located near Team VM (Latency, for those that are wondering, is about 50ms). A person high in the company is pushing for Team Non-VM to use virtual machines for programming, development, and testing. The latter point we agree on -- we want Virtual Machines to test configurations and various aspects of the web application in a 'clean' state. The Problem: What we don't agree on is having developers using RDP to connect to a desktop remotely that contains Visual Studio, SQL Server, and IIS to do the same development we could do locally on our laptops. I've tried the VM set-up, and besides the color issue, there is a latency issue that is rather noticeable, not to mention that since we're a start-up, a good number of employees work from home on occasion with our work laptops, and this move would cut off the laptops. They'd be turned in. Reasons to Use Remote VMs for Development (Not Testing!): Here are the stated reasons that this person wants us to use VMs: They work for TeamVM. They keep the source code "safe". If we want to work from home, we could just use our home PCs. Licenses (I don't know what the argument is, only that it's been used). Reasons not to use Remote VMs for Development: Here are the stated reasons why we don't want to use VMs: We like working from home. We get a lot done on our own time. We're not going to use our Home PCs to do work related stuff. The Latency is noticeable. Support for the VMs (if they go down, or if we need a new VM) takes a while. We don't have administrative privileges on the VM, and are unable to change settings as needed. What I'm looking for from the community is this: What reasons would you give for not using VMs for development? Keep in mind these are remote VMs -- this isn't a VM running on a local desktop. It's using the laptop (or a desktop) as a thin client for a remote VM. Also, on the other side of the coin: Is there something we're missing that makes VMs more palatable for development? Edit: I think 'safe' is used in term of corporate espionage, or more correctly if the Laptop gets stolen, the person who stole would have access to our source code. The former (as we've pointed out, is always going to be a possibility -- companies stop that with litigation, there isn't a technical solution (so far as I can see)). The latter point is ( though I don't know its usefulness in a corporate scenario) mitigated by Truecrypt'ing the entire volume.

    Read the article

  • Silverlight 4 Twitter Client &ndash; Part 5

    - by Max
    In this post, we will look at implementing the following in our twitter client - displaying the profile picture in the home page after logging in. So to accomplish this, we will need to do the following steps. 1) First of all, let us create another field in our Global variable static class to hold the profile image url. So just create a static string field in that. public static string profileImage { get; set; } 2) In the Login.xaml.cs file, before the line where we redirect to the Home page if the login was successful. Create another WebClient request to fetch details from this url - .xml">http://api.twitter.com/1/users/show/<TwitterUsername>.xml I am interested only in the “profile_image_url” node in this xml string returned. You can choose what ever field you need – the reference to the Twitter API Documentation is here. 3) This particular url does not require any authentication so no need of network credentials for this and also the useDefaultCredentials will be true. So this code would look like. WebRequest.RegisterPrefix("http://", System.Net.Browser.WebRequestCreator.ClientHttp); WebClient myService = new WebClient(); myService.AllowReadStreamBuffering = myService.UseDefaultCredentials = true; myService.DownloadStringCompleted += new DownloadStringCompletedEventHandler(TimelineRequestCompleted_User);) myService.DownloadStringAsync(new Uri("http://api.twitter.com/1/users/show/" + TwitterUsername.Text + ".xml")); 4) To parse the xml file returned by this and get the value of the “profile_image_url” node, the LINQ code will look something like XDocument xdoc; xdoc = XDocument.Parse(e.Result); var answer = (from status in xdoc.Descendants("user") select status.Element("profile_image_url").Value); GlobalVariable.profileImage = answer.First().ToString(); 5) After this, we can then redirect to Home page completing our login formalities. 6) In the home page, add a image tag and give it a name, something like <Image Name="image1" Stretch="Fill" Margin="29,29,0,0" Height="73" VerticalAlignment="Top" HorizontalAlignment="Left" Width="73" /> 7) In the OnNavigated to event in home page, we can set the image source url as below image1.Source = new BitmapImage(new Uri(GlobalVariable.profileImage, UriKind.Absolute)); Hope this helps. If you have any queries / suggestions, please feel free to comment below or contact me. Technorati Tags: Silverlight,LINQ,Twitter API,Twitter

    Read the article

  • Why does Celery work in Python shell, but not in my Django views? (import problem)

    - by TIMEX
    I installed Celery (latest stable version.) I have a directory called /home/myuser/fable/jobs. Inside this directory, I have a file called tasks.py: from celery.decorators import task from celery.task import Task class Submitter(Task): def run(self, post, **kwargs): return "Yes, it works!!!!!!" Inside this directory, I also have a file called celeryconfig.py: BROKER_HOST = "localhost" BROKER_PORT = 5672 BROKER_USER = "abc" BROKER_PASSWORD = "xyz" BROKER_VHOST = "fablemq" CELERY_RESULT_BACKEND = "amqp" CELERY_IMPORTS = ("tasks", ) In my /etc/profile, I have these set as my PYTHONPATH: PYTHONPATH=/home/myuser/fable:/home/myuser/fable/jobs So I run my Celery worker using the console ($ celeryd --loglevel=INFO), and I try it out. I open the Python console and import the tasks. Then, I run the Submitter. >>> import fable.jobs.tasks as tasks >>> s = tasks.Submitter() >>> s.delay("abc") <AsyncResult: d70d9732-fb07-4cca-82be-d7912124a987> Everything works, as you can see in my console [2011-01-09 17:30:05,766: INFO/MainProcess] Task tasks.Submitter[d70d9732-fb07-4cca-82be-d7912124a987] succeeded in 0.0398268699646s: But when I go into my Django's views.py and run the exact 3 lines of code as above, I get this: [2011-01-09 17:25:20,298: ERROR/MainProcess] Unknown task ignored: "Task of kind 'fable.jobs.tasks.Submitter' is not registered, please make sure it's imported.": {'retries': 0, 'task': 'fable.jobs.tasks.Submitter', 'args': ('abc',), 'expires': None, 'eta': None, 'kwargs': {}, 'id': 'eb5c65b4-f352-45c6-96f1-05d3a5329d53'} Traceback (most recent call last): File "/home/myuser/mysite-env/lib/python2.6/site-packages/celery/worker/listener.py", line 321, in receive_message eventer=self.event_dispatcher) File "/home/myuser/mysite-env/lib/python2.6/site-packages/celery/worker/job.py", line 299, in from_message eta=eta, expires=expires) File "/home/myuser/mysite-env/lib/python2.6/site-packages/celery/worker/job.py", line 243, in __init__ self.task = tasks[self.task_name] File "/home/myuser/mysite-env/lib/python2.6/site-packages/celery/registry.py", line 63, in __getitem__ raise self.NotRegistered(str(exc)) NotRegistered: "Task of kind 'fable.jobs.tasks.Submitter' is not registered, please make sure it's imported." It's weird, because the celeryd client does show that it's registered, when I launch it. [2011-01-09 17:38:27,446: WARNING/MainProcess] Configuration -> . broker -> amqp://GOGOme@localhost:5672/fablemq . queues -> . celery -> exchange:celery (direct) binding:celery . concurrency -> 1 . loader -> celery.loaders.default.Loader . logfile -> [stderr]@INFO . events -> OFF . beat -> OFF . tasks -> . tasks.Decayer . tasks.Submitter Can someone help?

    Read the article

  • angular-ui-router : breadcrumps ok but view ko

    - by anakin59490
    this is my app.router.js : agentRouter.config([ '$stateProvider', '$urlRouterProvider', function($stateProvider, $urlRouterProvider) { var root = { name: 'root', abstract: true, url: '', title: 'home', views: { 'header': { templateUrl: 'views/headers/header.app.html', controller: 'HeaderCtrl' }, 'body': { templateUrl: "views/root.html" }, 'footer': { templateUrl: 'views/footers/footer.app.html' } } }; var agent = { name: 'root.agent', url: '/agent', title: 'agent', views: { 'root.sidebar': { templateUrl: "views/main.sidebar.html" }, 'root.container': { templateUrl: "views/partials/agent/list.container.html" } } }; var detail = { name: 'root.agent.detail', url: '/detail/:id', title: 'agentDetail', // use for breadcrumb views: { 'root.sidebar': { templateUrl: "views/main.sidebar.html" }, 'root.container': { templateUrl: "views/partials/agent/list.chantier.html" } } }; /.../ $stateProvider.state(root); $stateProvider.state(agent); $stateProvider.state(detail); } ]); and this is my root.html : <!--Breadcrumb content--> <ul class="row breadcrumb"> <i class="glyphicon glyphicon-home" style=""></i> <li ng-repeat="state in $state.$current.path"> <a ng-href="#{{state.url.format($stateParams)}}"><span ng-bind="state.title"></span></a> <span ng-hide="$last" class=""></span> </li> </ul> <!--Sidebar content--> <div ui-view="root.sidebar">default root.sidebar</div> <!--Container content--> <div style="background-color: #f9f9f9" ui-view="root.container">default root.container</div> I can access to my "agent" page (a list of person) and my breadcrumb is right : home / agent but when i click on an item of the list i got always the same page but my breadcrumb is right : home / agent / agentDetail but in app.router.js if change detail like this : var detail = { name: 'root.detail', // référence initiale + detail (fils) url: '/agent/detail/:id', // réference utilisée dans les fichiers HTML, attention c'est la suite de l'url précédente!!! title: 'agentDetail', // référence utilisée pour le breadcump views: { 'root.sidebar': { templateUrl: "views/main.sidebar.html" }, 'root.container': { templateUrl: "views/partials/agent/list.chantier.html" } } }; i got the right page (list.chantier.xml) but the breadcrumb is false : home / agentDetail instead of home / agent / agentDetail I would like to got the right breadcrumb (home / agent / agentDetail) with the right page (list.chantier.html) when i click on an item of the agent list page (list.container.html) Thank you in advance for your help

    Read the article

  • Customize the SimpleMembership in ASP.NET MVC 4.0

    - by thangchung
    As we know, .NET 4.5 have come up to us, and come along with a lot of new interesting features as well. Visual Studio 2012 was also introduced some days ago. They made us feel very happy with cool improvement along with us. Performance when loading code editor is very good at the moment (immediate after click on the solution). I explore some of cool features at these days. Some of them like Json.NET integrated in ASP.NET MVC 4.0, improvement on asynchronous action, new lightweight theme on Visual Studio, supporting very good on mobile development, improvement on authentication… I reviewed them, and found out that in this version of .NET Microsoft was not only developed new feature that suggest from community but also focused on improvement performance of existing features or components. Besides that, they also opened source more projects, like Entity Framework, Reactive Extensions, ASP.NET Web Stack… At the moment, I feel Microsoft want to open source more and more their projects. Today, I am going to dive in deep on new SimpleMembership model. It is really good because in this security model, Microsoft actually focus on development needs. As we know, in the past, they introduce some of provider supplied for coding security like MembershipProvider, RoleProvider… I don’t need to talk but everyone that have ever used it know that they were actually hard to use, and not easy to maintain and unit testing. Why? Because every time you inherit it, you need to override all methods inside it. Some people try to abstract it by introduce more method with virtual keyword, and try to implement basic behavior, so in the subclass we only need to override the method that need for their business. But to me, it’s only the way to work around. ASP.NET team and Web Matrix knew about it, so they built the new features based on existing components on .NET framework. And one of component that comes to us is SimpleMembership and SimpleRole. They implemented the Façade pattern on the top of those, and called it is WebSecurity. In the web, we can call WebSecurity anywhere we want, and make a call to inside wrapper of it. I read a lot of them on web blog, on technical news, on MSDN as well. Matthew Osborn had an excellent article about it at his blog. Jon Galloway had an article like this at here. He analyzed why old membership provider not fixed well to ASP.NET MVC and how to get over it. Those are very good to me. It introduced to me about how to doing SimpleMembership on it, how to doing it on new ASP.NET MVC web application. But one thing, those didn’t tell me was how to doing it on existing security model (that mean we already had Users and Roles on legacy system, and how we can integrate it to this system), that’s a reason I will introduce it today. I have spent couples of hours to see what’s inside this, and try to make one example to clarify my concern. And it’s lucky that I can make it working well.The first thing, we need to create new ASP.NET MVC application on Visual Studio 2012. We need to choose Internet type for this web application. ASP.NET MVC actually creates all needs components for the basic membership and basic role. The cool feature is DoNetOpenAuth come along with it that means we can log-in using facebook, twitter or Windows Live if you want. But it’s only for LocalDb, so we need to change it to fix with existing database model on SQL Server. The next step we have to make SimpleMembership can understand which database we use and show it which column need to point to for the ID and UserName. I really like this feature because SimpleMembership on need to know about the ID and UserName, and they don’t care about rest of it. I assume that we have an existing database model like So we will point it in code like The codes for it, we put on InitializeSimpleMembershipAttribute like [AttributeUsage(AttributeTargets.Class | AttributeTargets.Method, AllowMultiple = false, Inherited = true)]     public sealed class InitializeSimpleMembershipAttribute : ActionFilterAttribute     {         private static SimpleMembershipInitializer _initializer;         private static object _initializerLock = new object();         private static bool _isInitialized;         public override void OnActionExecuting(ActionExecutingContext filterContext)         {             // Ensure ASP.NET Simple Membership is initialized only once per app start             LazyInitializer.EnsureInitialized(ref _initializer, ref _isInitialized, ref _initializerLock);         }         private class SimpleMembershipInitializer         {             public SimpleMembershipInitializer()             {                 try                 {                     WebSecurity.InitializeDatabaseConnection("DefaultDb", "User", "Id", "UserName", autoCreateTables: true);                 }                 catch (Exception ex)                 {                     throw new InvalidOperationException("The ASP.NET Simple Membership database could not be initialized. For more information, please see http://go.microsoft.com/fwlink/?LinkId=256588", ex);                 }             }         }     }And decorating it in the AccountController as below [Authorize]     [InitializeSimpleMembership]     public class AccountController : ControllerIn this case, assuming that we need to override the ValidateUser to point this to existing User database table, and validate it. We have to add one more class like public class CustomAdminMembershipProvider : SimpleMembershipProvider     {         // TODO: will do a better way         private const string SELECT_ALL_USER_SCRIPT = "select * from [dbo].[User]private where UserName = '{0}'";         private readonly IEncrypting _encryptor;         private readonly SimpleSecurityContext _simpleSecurityContext;         public CustomAdminMembershipProvider(SimpleSecurityContext simpleSecurityContext)             : this(new Encryptor(), new SimpleSecurityContext("DefaultDb"))         {         }         public CustomAdminMembershipProvider(IEncrypting encryptor, SimpleSecurityContext simpleSecurityContext)         {             _encryptor = encryptor;             _simpleSecurityContext = simpleSecurityContext;         }         public override bool ValidateUser(string username, string password)         {             if (string.IsNullOrEmpty(username))             {                 throw new ArgumentException("Argument cannot be null or empty", "username");             }             if (string.IsNullOrEmpty(password))             {                 throw new ArgumentException("Argument cannot be null or empty", "password");             }             var hash = _encryptor.Encode(password);             using (_simpleSecurityContext)             {                 var users =                     _simpleSecurityContext.Users.SqlQuery(                         string.Format(SELECT_ALL_USER_SCRIPT, username));                 if (users == null && !users.Any())                 {                     return false;                 }                 return users.FirstOrDefault().Password == hash;             }         }     }SimpleSecurityDataContext at here public class SimpleSecurityContext : DbContext     {         public DbSet<User> Users { get; set; }         public SimpleSecurityContext(string connStringName) :             base(connStringName)         {             this.Configuration.LazyLoadingEnabled = true;             this.Configuration.ProxyCreationEnabled = false;         }         protected override void OnModelCreating(DbModelBuilder modelBuilder)         {             base.OnModelCreating(modelBuilder);                          modelBuilder.Configurations.Add(new UserMapping());         }     }And Mapping for User as below public class UserMapping : EntityMappingBase<User>     {         public UserMapping()         {             this.Property(x => x.UserName);             this.Property(x => x.DisplayName);             this.Property(x => x.Password);             this.Property(x => x.Email);             this.ToTable("User");         }     }One important thing, you need to modify the web.config to point to our customize SimpleMembership <membership defaultProvider="AdminMemberProvider" userIsOnlineTimeWindow="15">       <providers>         <clear/>         <add name="AdminMemberProvider" type="CIK.News.Web.Infras.Security.CustomAdminMembershipProvider, CIK.News.Web.Infras" />       </providers>     </membership>     <roleManager enabled="false">       <providers>         <clear />         <add name="AdminRoleProvider" type="CIK.News.Web.Infras.Security.AdminRoleProvider, CIK.News.Web.Infras" />       </providers>     </roleManager>The good thing at here is we don’t need to modify the code on AccountController. We only need to modify on SimpleMembership and Simple Role (if need). Now build all solutions, run it. We should see a screen like thisIf I login to Twitter button at the bottom of this page, we will be transfer to twitter authentication pageYou have to waiting for a moment Afterwards it will transfer you back to your admin screenYou can find all source codes at my MSDN code. I will really happy if you guys feel free to put some comments as below. It will be helpful to improvement my code in the future. Thank for all your readings. 

    Read the article

  • ASP.NET MVC 3: Layouts and Sections with Razor

    - by ScottGu
    This is another in a series of posts I’m doing that cover some of the new ASP.NET MVC 3 features: Introducing Razor (July 2nd) New @model keyword in Razor (Oct 19th) Layouts with Razor (Oct 22nd) Server-Side Comments with Razor (Nov 12th) Razor’s @: and <text> syntax (Dec 15th) Implicit and Explicit code nuggets with Razor (Dec 16th) Layouts and Sections with Razor (Today) In today’s post I’m going to go into more details about how Layout pages work with Razor.  In particular, I’m going to cover how you can have multiple, non-contiguous, replaceable “sections” within a layout file – and enable views based on layouts to optionally “fill in” these different sections at runtime.  The Razor syntax for doing this is clean and concise. I’ll also show how you can dynamically check at runtime whether a particular layout section has been defined, and how you can provide alternate content (or even an alternate layout) in the event that a section isn’t specified within a view template.  This provides a powerful and easy way to customize the UI of your site and make it clean and DRY from an implementation perspective. What are Layouts? You typically want to maintain a consistent look and feel across all of the pages within your web-site/application.  ASP.NET 2.0 introduced the concept of “master pages” which helps enable this when using .aspx based pages or templates.  Razor also supports this concept with a feature called “layouts” – which allow you to define a common site template, and then inherit its look and feel across all the views/pages on your site. I previously discussed the basics of how layout files work with Razor in my ASP.NET MVC 3: Layouts with Razor blog post.  Today’s post will go deeper and discuss how you can define multiple, non-contiguous, replaceable regions within a layout file that you can then optionally “fill in” at runtime. Site Layout Scenario Let’s look at how we can implement a common site layout scenario with ASP.NET MVC 3 and Razor.  Specifically, we’ll implement some site UI where we have a common header and footer on all of our pages.  We’ll also add a “sidebar” section to the right of our common site layout.  On some pages we’ll customize the SideBar to contain content specific to the page it is included on: And on other pages (that do not have custom sidebar content) we will fall back and provide some “default content” to the sidebar: We’ll use ASP.NET MVC 3 and Razor to enable this customization in a nice, clean way.  Below are some step-by-step tutorial instructions on how to build the above site with ASP.NET MVC 3 and Razor. Part 1: Create a New Project with a Layout for the “Body” section We’ll begin by using the “File->New Project” menu command within Visual Studio to create a new ASP.NET MVC 3 Project.  We’ll create the new project using the “Empty” template option: This will create a new project that has no default controllers in it: Creating a HomeController We will then right-click on the “Controllers” folder of our newly created project and choose the “Add->Controller” context menu command.  This will bring up the “Add Controller” dialog: We’ll name the new controller we create “HomeController”.  When we click the “Add” button Visual Studio will add a HomeController class to our project with a default “Index” action method that returns a view: We won’t need to write any Controller logic to implement this sample – so we’ll leave the default code as-is.  Creating a View Template Our next step will be to implement the view template associated with the HomeController’s Index action method.  To implement the view template, we will right-click within the “HomeController.Index()” method and select the “Add View” command to create a view template for our home page: This will bring up the “Add View” dialog within Visual Studio.  We do not need to change any of the default settings within the above dialog (the name of the template was auto-populated to Index because we invoked the “Add View” context menu command within the Index method).  When we click the “Add” Button within the dialog, a Razor-based “Index.cshtml” view template will be added to the \Views\Home\ folder within our project.  Let’s add some simple default static content to it: Notice above how we don’t have an <html> or <body> section defined within our view template.  This is because we are going to rely on a layout template to supply these elements and use it to define the common site layout and structure for our site (ensuring that it is consistent across all pages and URLs within the site).  Customizing our Layout File Let’s open and customize the default “_Layout.cshtml” file that was automatically added to the \Views\Shared folder when we created our new project: The default layout file (shown above) is pretty basic and simply outputs a title (if specified in either the Controller or the View template) and adds links to a stylesheet and jQuery.  The call to “RenderBody()” indicates where the main body content of our Index.cshtml file will merged into the output sent back to the browser. Let’s modify the Layout template to add a common header, footer and sidebar to the site: We’ll then edit the “Site.css” file within the \Content folder of our project and add 4 CSS rules to it: And now when we run the project and browse to the home “/” URL of our project we’ll see a page like below: Notice how the content of the HomeController’s Index view template and the site’s Shared Layout template have been merged together into a single HTML response.  Below is what the HTML sent back from the server looks like: Part 2: Adding a “SideBar” Section Our site so far has a layout template that has only one “section” in it – what we call the main “body” section of the response.  Razor also supports the ability to add additional "named sections” to layout templates as well.  These sections can be defined anywhere in the layout file (including within the <head> section of the HTML), and allow you to output dynamic content to multiple, non-contiguous, regions of the final response. Defining the “SideBar” section in our Layout Let’s update our Layout template to define an additional “SideBar” section of content that will be rendered within the <div id=”sidebar”> region of our HTML.  We can do this by calling the RenderSection(string sectionName, bool required) helper method within our Layout.cshtml file like below:   The first parameter to the “RenderSection()” helper method specifies the name of the section we want to render at that location in the layout template.  The second parameter is optional, and allows us to define whether the section we are rendering is required or not.  If a section is “required”, then Razor will throw an error at runtime if that section is not implemented within a view template that is based on the layout file (which can make it easier to track down content errors).  If a section is not required, then its presence within a view template is optional, and the above RenderSection() code will render nothing at runtime if it isn’t defined. Now that we’ve made the above change to our layout file, let’s hit refresh in our browser and see what our Home page now looks like: Notice how we currently have no content within our SideBar <div> – that is because the Index.cshtml view template doesn’t implement our new “SideBar” section yet. Implementing the “SideBar” Section in our View Template Let’s change our home-page so that it has a SideBar section that outputs some custom content.  We can do that by opening up the Index.cshtml view template, and by adding a new “SiderBar” section to it.  We’ll do this using Razor’s @section SectionName { } syntax: We could have put our SideBar @section declaration anywhere within the view template.  I think it looks cleaner when defined at the top or bottom of the file – but that is simply personal preference.  You can include any content or code you want within @section declarations.  Notice above how I have a C# code nugget that outputs the current time at the bottom of the SideBar section.  I could have also written code that used ASP.NET MVC’s HTML/AJAX helper methods and/or accessed any strongly-typed model objects passed to the Index.cshtml view template. Now that we’ve made the above template changes, when we hit refresh in our browser again we’ll see that our SideBar content – that is specific to the Home Page of our site – is now included in the page response sent back from the server: The SideBar section content has been merged into the proper location of the HTML response : Part 3: Conditionally Detecting if a Layout Section Has Been Implemented Razor provides the ability for you to conditionally check (from within a layout file) whether a section has been defined within a view template, and enables you to output an alternative response in the event that the section has not been defined.  This provides a convenient way to specify default UI for optional layout sections.  Let’s modify our Layout file to take advantage of this capability.  Below we are conditionally checking whether the “SideBar” section has been defined without the view template being rendered (using the IsSectionDefined() method), and if so we render the section.  If the section has not been defined, then we now instead render some default content for the SideBar:  Note: You want to make sure you prefix calls to the RenderSection() helper method with a @ character – which will tell Razor to execute the HelperResult it returns and merge in the section content in the appropriate place of the output.  Notice how we wrote @RenderSection(“SideBar”) above instead of just RenderSection(“SideBar”).  Otherwise you’ll get an error. Above we are simply rendering an inline static string (<p>Default SideBar Content</p>) if the section is not defined.  A real-world site would more likely refactor this default content to be stored within a separate partial template (which we’d render using the Html.RenderPartial() helper method within the else block) or alternatively use the Html.Action() helper method within the else block to encapsulate both the logic and rendering of the default sidebar. When we hit refresh on our home-page, we will still see the same custom SideBar content we had before.  This is because we implemented the SideBar section within our Index.cshtml view template (and so our Layout rendered it): Let’s now implement a “/Home/About” URL for our site by adding a new “About” action method to our HomeController: The About() action method above simply renders a view back to the client when invoked.  We can implement the corresponding view template for this action by right-clicking within the “About()” method and using the “Add View” menu command (like before) to create a new About.cshtml view template.  We’ll implement the About.cshtml view template like below. Notice that we are not defining a “SideBar” section within it: When we browse the /Home/About URL we’ll see the content we supplied above in the main body section of our response, and the default SideBar content will rendered: The layout file determined at runtime that a custom SideBar section wasn’t present in the About.cshtml view template, and instead rendered the default sidebar content. One Last Tweak… Let’s suppose that at a later point we decide that instead of rendering default side-bar content, we just want to hide the side-bar entirely from pages that don’t have any custom sidebar content defined.  We could implement this change simply by making a small modification to our layout so that the sidebar content (and its surrounding HTML chrome) is only rendered if the SideBar section is defined.  The code to do this is below: Razor is flexible enough so that we can make changes like this and not have to modify any of our view templates (nor make change any Controller logic changes) to accommodate this.  We can instead make just this one modification to our Layout file and the rest happens cleanly.  This type of flexibility makes Razor incredibly powerful and productive. Summary Razor’s layout capability enables you to define a common site template, and then inherit its look and feel across all the views/pages on your site. Razor enables you to define multiple, non-contiguous, “sections” within layout templates that can be “filled-in” by view templates.  The @section {} syntax for doing this is clean and concise.  Razor also supports the ability to dynamically check at runtime whether a particular section has been defined, and to provide alternate content (or even an alternate layout) in the event that it isn’t specified.  This provides a powerful and easy way to customize the UI of your site - and make it clean and DRY from an implementation perspective. Hope this helps, Scott P.S. In addition to blogging, I am also now using Twitter for quick updates and to share links. Follow me at: twitter.com/scottgu

    Read the article

  • 17 new features in Visual Studio 2010

    - by vik20000in
    Visual studio 2010 has been released to RTM a few days back. This release of Visual studio 2010 comes with a big number of improvements on many fronts. In this post I will try and point out some of the major improvements in Visual Studio 2010. 1)      Visual studio IDE Improvement. Visual studio IDE has been rewritten in WPF. The look and feel of the studio has been improved for improved readability. Start page has been redesigned and template so that anyone can change the start page as they wish. 2)      Multiple Monitor - Support for Multiple Monitor was already there in Visual studio. But in this edition it has been improved as much that we can now place the document, design and code window outside the IDE in another monitor. 3)      ZOOM in Code Editor – Making the editors in WPF has made significant improvement for them. The best one that I like is the ZOOM feature. We can now zoom in the code editor with the help of the ctrl + Mouse scroll. The zoom feature does not work on the Design surface or windows with icon like solution view and toolbox. 4)      Box Selection - Another Important improvement in the Visual studio 2010 is the box selection. We can select a rectangular by holding down the Alt Key and selecting with mouse.  Now in the rectangular selection we can insert text, Paste same code in different line etc. This is helpful if you want to convert a number of variables from public to private etc… 5)      New Improved Search – One of the best productivity improvements in Visual studio 2010 is its new search as you type support. This has been done in the Navigate To window which can be brought up by pressing (Ctrl + ,). The navigate To windows also take help of the Camel casing and will be able to search with the help of camel casing when character is entered in upper case. For example we can search AOH for AddOrederHeader. 6)      Call Hierarchy – This feature is only available to the Visual C# and Visual C++ editor. The call hierarchy windows displays the calls made to and from (yes both to and from) a selected method property or a constructor. The call hierarchy also shows the implementation of interface and the overrides of virtual or abstract methods. This window is very helpful in understanding the code flow, and evaluating the effect of making changes. The best part is it is available at design time and not at runtime only like a debugger. 7)      Highlighting references – One of the very cool stuff in Visual Studio 2010 is the fact if you select a variable then all the use of that variable will be highlighted alongside. This should work for all the result of symbols returned by Find all reference. This also works for Name of class, objects variable, properties and methods. We can also use the Ctrl + Shift + Down Arrow or Up Arror to move through them. 8)      Generate from usage - The Generate from usage feature lets you use classes and members before you define them. You can generate a stub for any undefined class, constructor, method, property, field, or enum that you want to use but have not yet defined. You can generate new types and members without leaving your current location in code, This minimizes interruption to your workflow.9)      IntelliSense Suggestion Mode - IntelliSense now provides two alternatives for IntelliSense statement completion, completion mode and suggestion mode. Use suggestion mode for situations where classes and members are used before they are defined. In suggestion mode, when you type in the editor and then commit the entry, the text you typed is inserted into the code. When you commit an entry in completion mode, the editor shows the entry that is highlighted on the members list. When an IntelliSense window is open, you can press CTRL+ALT+SPACEBAR to toggle between completion mode and suggestion mode. 10)   Application Lifecycle Management – A client application for management of application lifecycle like version control, work item tracking, build automation, team portal etc is available for free (this is not available for express edition.). 11)   Start Page – The start page has been redesigned with WPF for new functionality and look. Tabbed areas are provided for content from different source including MSDN. Once you open some project the start page closes automatically. The list of recent project also lets you remove project from the list. And above all the start page is customizable enough to be changed as per individual requirement. 12)   Extension Manager – Visual Studio 2010 has provided good ways to be extended. We can also use MEF to extend most of the features of Visual Studio. The new extension manager now can go the visual studio gallery and install the extension without even opening any explorer. 13)   Code snippets – Visual studio 2010 for HTML, Jscript and Asp.net also. 14)   Improved Intelligence for JavaScript has been improved vastly (around 2-5 times). Intelligence now also shows the XML documentation comment on the go. 15)   Web Deployment – Web Deployment has been vastly improved. We can package and publish the web application in one click. Three major supported deployment scenarios are Web packages, one click deployment and Web configuration Transformation. 16)   SharePoint - Visual Studio 2010 also brings vastly improved development experience for SharePoint. We can create, edit, debug, package, deploy and activate SharePoint project from within Visual Studio. Deployment of Site is as easy as hitting F5. 17)   Azure – Visual Studio 2010 also comes with handy improvement for developing on windows Azure environment. Vikram

    Read the article

  • CentOS 5.4 NFS v4 client file permissions differ from original files & NFS Share file contents

    - by p4guru
    Having a strange problem with NFS share and file permissions on the 1 out of the 2 NFS clients, web1 has file permissions issues but web2 is fine. web1 and web2 are load balanced web servers. So questions are: how do I ensure NFS share file contents retain the same permissions for user/group as the original files on web1 server like they do on web2 server ? how do I reverse what I did on web1, i tried unmount command and said command not found ? Information: I'm using 3 dedicated server setup. All 3 servers CentOS 5.4 64bit based. servers are as follows: web1 - nfs client with file permissions issues web2 - nfs client file permissions are OKAY db1 - nfs share at /nfsroot web2 nfs client was setup by my web host, while web1 was setup by me. I did the following commands on web1 and it worked with updating db1 nfsroot share at /nfsroot/site_css with latest files on web1 but the file permissions don't stick even if i use tar with -p command to perserve file permissions ? cd /home/username/public_html/forums/script/ tar -zcp site_css/ > site_css.tar.gz mount -t nfs4 nfsshareipaddress:/site_css /home/username/public_html/forums/scripts/site_css/ -o rw,soft cd /home/username/public_html/forums/script/ tar -zxf site_css.tar.gz But checking on web1 file permissions no longer username user/group but owned by nobody ? but web2 file permissions correct ? This is only a problem for web1 while web2 is correct ? Looks like numeric ids aren't the same ? Not sure how to correct this ? web1 with incorrect user/group of nobody ls -alh /home/username/public_html/forums/scripts/site_css total 48K drwxrwxrwx 2 nobody nobody 4.0K Feb 22 02:37 ./ drwxr-xr-x 3 username username 4.0K Feb 22 02:43 ../ -rw-r--r-- 1 nobody nobody 1 Nov 30 2006 index.html -rw-r--r-- 1 nobody nobody 5.8K Feb 22 02:37 style-057c3df0-00011.css -rw-r--r-- 1 nobody nobody 5.8K Feb 22 02:37 style-95001864-00002.css -rw-r--r-- 1 nobody nobody 5.8K Feb 18 05:37 style-b1879ba7-00002.css -rw-r--r-- 1 nobody nobody 5.8K Feb 18 05:37 style-cc2f96c9-00011.css web1 numeric ids ls -n /home/username/public_html/forums/scripts/site_css total 48 drwxrwxrwx 2 99 99 4096 Feb 22 02:37 ./ drwxr-xr-x 3 503 500 4096 Feb 22 02:43 ../ -rw-r--r-- 1 99 99 1 Nov 30 2006 index.html -rw-r--r-- 1 99 99 5876 Feb 22 02:37 style-057c3df0-00011.css -rw-r--r-- 1 99 99 5877 Feb 22 02:37 style-95001864-00002.css -rw-r--r-- 1 99 99 5877 Feb 18 05:37 style-b1879ba7-00002.css -rw-r--r-- 1 99 99 5876 Feb 18 05:37 style-cc2f96c9-00011.css web2 correct username user/group permissions ls -alh /home/username/public_html/forums/scripts/site_css total 48K drwxrwxrwx 2 root root 4.0K Feb 22 02:37 ./ drwxr-xr-x 3 username username 4.0K Dec 2 14:51 ../ -rw-r--r-- 1 username username 1 Nov 30 2006 index.html -rw-r--r-- 1 username username 5.8K Feb 22 02:37 style-057c3df0-00011.css -rw-r--r-- 1 username username 5.8K Feb 22 02:37 style-95001864-00002.css -rw-r--r-- 1 username username 5.8K Feb 18 05:37 style-b1879ba7-00002.css -rw-r--r-- 1 username username 5.8K Feb 18 05:37 style-cc2f96c9-00011.css web2 numeric ids ls -n /home/username/public_html/forums/scripts/site_css total 48 drwxrwxrwx 2 503 500 4096 Feb 22 02:37 ./ drwxr-xr-x 3 503 500 4096 Dec 2 14:51 ../ -rw-r--r-- 1 503 500 1 Nov 30 2006 index.html -rw-r--r-- 1 503 500 5876 Feb 22 02:37 style-057c3df0-00011.css -rw-r--r-- 1 503 500 5877 Feb 22 02:37 style-95001864-00002.css -rw-r--r-- 1 503 500 5877 Feb 18 05:37 style-b1879ba7-00002.css -rw-r--r-- 1 503 500 5876 Feb 18 05:37 style-cc2f96c9-00011.css I checked db1 /nfsroot/site_css and user/group ownership was incorrect for newer files dated feb22 owned by root and not username ? on db1 originally incorrect root assigned user/group for new feb22 dated files ls -alh /nfsroot/site_css total 44K drwxrwxrwx 2 root root 4.0K Feb 22 02:37 . drwxr-xr-x 17 root root 4.0K Feb 17 12:06 .. -rw-r--r-- 1 root root 1 Nov 30 2006 index.html -rw-r--r-- 1 root root 5.8K Feb 22 02:37 style-057c3df0-00011.css -rw-r--r-- 1 root root 5.8K Feb 22 02:37 style-95001864-00002.css -rw------- 1 username nfs 5.8K Feb 18 05:37 style-b1879ba7-00002.css -rw------- 1 username nfs 5.8K Feb 18 05:37 style-cc2f96c9-00011.css Then I chmod them all on db1 and chown to set to right ownership on db1 so it looks like below on db1 once corrected the newer feb22 dated files ls -alh /nfsroot/site_css total 44K drwxrwxrwx 2 root root 4.0K Feb 22 02:37 . drwxr-xr-x 17 root root 4.0K Feb 17 12:06 .. -rw-r--r-- 1 username username 1 Nov 30 2006 index.html -rw-r--r-- 1 username username 5.8K Feb 22 02:37 style-057c3df0-00011.css -rw-r--r-- 1 username username 5.8K Feb 22 02:37 style-95001864-00002.css -rw-r--r-- 1 username username 5.8K Feb 18 05:37 style-b1879ba7-00002.css -rw-r--r-- 1 username username 5.8K Feb 18 05:37 style-cc2f96c9-00011.css but still web1 shows owned by nobody ? while web2 shows correct permissions ? web1 still with incorrect user/group of nobody not matching what web2 and db1 are set to ? ls -alh /home/username/public_html/forums/scripts/site_css total 48K drwxrwxrwx 2 nobody nobody 4.0K Feb 22 02:37 ./ drwxr-xr-x 3 username username 4.0K Feb 22 02:43 ../ -rw-r--r-- 1 nobody nobody 1 Nov 30 2006 index.html -rw-r--r-- 1 nobody nobody 5.8K Feb 22 02:37 style-057c3df0-00011.css -rw-r--r-- 1 nobody nobody 5.8K Feb 22 02:37 style-95001864-00002.css -rw-r--r-- 1 nobody nobody 5.8K Feb 18 05:37 style-b1879ba7-00002.css -rw-r--r-- 1 nobody nobody 5.8K Feb 18 05:37 style-cc2f96c9-00011.css Just so confusing so any help is very very much appreciated! thanks

    Read the article

  • Migrate from MySQL to PostgreSQL on Linux (Kubuntu)

    - by Dave Jarvis
    Storyline Trying to migrate a database from MySQL to PostgreSQL. All the documentation I have read covers, in great detail, how to migrate the structure. I have found very little documentation on migrating the data. The schema has 13 tables (which have been migrated successfully) and 9 GB of data. MySQL version: 5.1.x PostgreSQL version: 8.4.x I want to use the R programming language to analyze the data using SQL select statements; PostgreSQL has PL/R, but MySQL has nothing (as far as I can tell). A long time ago in a galaxy far, far away... Create the database location (/var has insufficient space; also dislike having the PostgreSQL version number everywhere -- upgrading would break scripts!): sudo mkdir -p /home/postgres/main sudo cp -Rp /var/lib/postgresql/8.4/main /home/postgres sudo chown -R postgres.postgres /home/postgres sudo chmod -R 700 /home/postgres sudo usermod -d /home/postgres/ postgres All good to here. Next, restart the server and configure the database using these installation instructions: sudo apt-get install postgresql pgadmin3 sudo /etc/init.d/postgresql-8.4 stop sudo vi /etc/postgresql/8.4/main/postgresql.conf Change data_directory to /home/postgres/main sudo /etc/init.d/postgresql-8.4 start sudo -u postgres psql postgres \password postgres sudo -u postgres createdb climate pgadmin3 Use pgadmin3 to configure the database and create a schema. A New Hope The episode began in a remote shell known as bash, with both databases running, and the installation of a command with a most unusual logo: SQL Fairy. perl Makefile.PL sudo make install sudo apt-get install perl-doc (strangely, it is not called perldoc) perldoc SQL::Translator::Manual Extract a PostgreSQL-friendly DDL and all the MySQL data: sqlt -f DBI --dsn dbi:mysql:climate --db-user user --db-password password -t PostgreSQL > climate-pg-ddl.sql mysqldump --skip-add-locks --complete-insert --no-create-db --no-create-info --quick --result-file="climate-my.sql" --databases climate --skip-comments -u root -p The Database Strikes Back Recreate the structure in PostgreSQL as follows: pgadmin3 (switch to it) Click the Execute arbitrary SQL queries icon Open climate-pg-ddl.sql Search for TABLE " replace with TABLE climate." (insert the schema name climate) Search for on " replace with on climate." (insert the schema name climate) Press F5 to execute This results in: Query returned successfully with no result in 122 ms. Replies of the Jedi At this point I am stumped. Where do I go from here (what are the steps) to convert climate-my.sql to climate-pg.sql so that they can be executed against PostgreSQL? How to I make sure the indexes are copied over correctly (to maintain referential integrity; I don't have constraints at the moment to ease the transition)? How do I ensure that adding new rows in PostgreSQL will start enumerating from the index of the last row inserted (and not conflict with an existing primary key from the sequence)? Resources A fair bit of information was needed to get this far: https://help.ubuntu.com/community/PostgreSQL http://articles.sitepoint.com/article/site-mysql-postgresql-1 http://wiki.postgresql.org/wiki/Converting_from_other_Databases_to_PostgreSQL#MySQL http://pgfoundry.org/frs/shownotes.php?release_id=810 http://sqlfairy.sourceforge.net/ Thank you!

    Read the article

  • Apache2 name based virtual host always redirect 301

    - by Francesco
    I've got a server (runnging Debian Squeeze) with Apache 2.2, there are 4 site running there. I'm using namebased virtulhosts because I've got a single IP. Initial configuration has been made with Webmin and probably something has been messed up.. firstdomain.com is my default domain and is working correctly, seconddomain.com is another site that is working. Now I want to add lastdomain.tk as a new site, so I've made this config file: root@webamp:/etc/apache2# cat sites-available/lastdomain.tk.conf <VirtualHost *:80> DocumentRoot /home/server/Condivisione/RAID/lastdomain.tk ServerName www.alazanes.tk ServerAlias alazanes.tk </VirtualHost> I've added it to enabled-sites and restarted apache. The problem is that if I go to lastdomain.tk (or www.lastdomain.tk) I'm redirected to firstdomain.com with a 301 redirect. Both lastdomain.tk and www.lastdomain.tk are A DNS records pointing to my IP address. Strange thing is that if a change DocumentRoot of lastdomain.tk to DocumentRoot /home/server/Condivisione/RAID/Sito_SecondDomain I correctly see seconddomain.com content without being redirected (lastdomain.tk is showed on address bar) These are the other configurations I'm using. root@webamp:/root# source /etc/apache2/envvars ; /usr/sbin/apache2 -S VirtualHost configuration: wildcard NameVirtualHosts and _default_ servers: *:443 webamp.firstdomain.com (/etc/apache2/sites-enabled/ssl.bbteam:1) *:80 is a NameVirtualHost default server firstdomain.com (/etc/apache2/sites-enabled/000-default:7) port 80 namevhost firstdomain.com (/etc/apache2/sites-enabled/000-default:7) port 80 namevhost www.lastdomain.tk (/etc/apache2/sites-enabled/lastdomain.tk.conf:1) ## other domains ## port 80 namevhost seconddomain.com (/etc/apache2/sites-enabled/seconddomain.com.conf:1) Syntax OK Content of default config file is root@webamp:/etc/apache2# cat sites-available/default <VirtualHost *:80> ServerAdmin [email protected] ServerName firstdomain.com ServerAlias www.firstdomain.com direct.firstdomain.com DocumentRoot /home/server/Condivisione/RAID/Sito_Web_Apache_su_80 ErrorLog /var/log/apache2/error.log LogLevel warn CustomLog /var/log/apache2/access.log combined </VirtualHost> content of second domain config file is root@webamp:/etc/apache2# cat sites-available/seconddomain.com.conf <VirtualHost *:80> DocumentRoot /home/server/Condivisione/RAID/Sito_SecondDomain ServerName seconddomain.com ServerAlias www.seconddomain.com direct.seconddomain.com #redirect 301 / http://www.seconddomain.com/ <Directory "/home/server/Condivisione/RAID/Sito_SecondDomain"> allow from all Options +Indexes </Directory> </VirtualHost> Probably a file permission problem? root@webamp:/root# ls -lh /home/server/Condivisione/RAID/ total 7.1M drwxrwxr-x 15 www-data server 4.0K Jun 5 13:29 Sito_SecondDomain drwxrwxrwx 23 server server 4.0K Jun 7 16:22 Sito_Web_Apache_su_80 drwxrwxr-x 17 www-data server 4.0K Jun 8 09:56 alazanes.tk Do someone have an idea of what is happening? Thanks, Francesco

    Read the article

  • Problems with apache svn server (403 Forbidden)

    - by mrlanrat
    Iv recently setup a SVN server on my papache webserver. I installed USVN http://www.usvn.fr/ to help manage the repositories from a web interface. When I create a repository and try to import code into it from netbeans i get the following error: org.tigris.subversion.javahl.ClientException: RA layer request failed Server sent unexpected return value (403 Forbidden) in response to PROPFIND request for '/svn/python1' I know i have the username and password correct (and I have tried different users) I have done some research and it seems that it is most likely an Apache svn error. Below is the config file for this virtualhost. <VirtualHost *:80> ServerName svn.domain.com ServerAlias www.svn.domain.com ServerAlias admin.svn.domain.com DocumentRoot /home/mrlanrat/domains/svn.domain.com/usvn/public ErrorLog /var/log/virtualmin/svn.domain.com_error_log CustomLog /var/log/virtualmin/svn.domain.com_access_log combined DirectoryIndex index.html index.htm index.php index.php4 index.php5 <Directory "/home/mrlanrat/domains/svn.domain.com/usvn"> Options +SymLinksIfOwnerMatch AllowOverride All Order allow,deny Allow from all </Directory> <Location /svn/> ErrorDocument 404 default DAV svn Require valid-user SVNParentPath /home/mrlanrat/domains/svn.domain.com/usvn/files/svn SVNListParentPath on AuthType Basic AuthName "USVN" AuthUserFile /home/mrlanrat/domains/svn.domain.com/usvn/files/htpasswd AuthzSVNAccessFile /home/mrlanrat/domains/svn.domain.com/usvn/files/authz </Location> </VirtualHost> Can anyone point out what I may have done wrong and how to fix it? I have tested with changing file permissions and changing the configuration with no luck. Thanks in advance!

    Read the article

  • Apache Simple Configuration Issue: per-user directory is accessing /~user instead of ~user

    - by Huckphin
    Hello. I am just getting Apache 2.2 running on Fedora 13 Beta 64-bit. I am running into issues setting my per-user directory. The goal is to make localhost/~user map to /home/~user/public_html. I think that I have the permissions right because I have 755 to /home/~user, and I have 755 to /home/~user/public_html/ and I have 777 for all contents inside of /home/~user/public_html/ recursively set. My mod_userdir configuration looks like this: <IfModule mod_userdir.c> # # UserDir is disabled by default since it can confirm the presence # of a username on the system (depending on home directory # permissions). # UserDir disabled root UserDir enabled huckphin # # To enable requests to /~user/ to serve the user's public_html # directory, remove the "UserDir disabled" line above, and uncomment # the following line instead: # UserDir public_html The error that I am seeing in the error log is this: [Sat May 15 09:54:29 2010] [error] [client 127.0.0.1] (13)Permission denied: access to /~huckphin/index.html denied When I login as the apache user, I know that /~huckphin does not exist, and this is not what I want. I want it to be accessing ~huckphin, not /~huckphin. What do I need to change on my configuration for this to work?

    Read the article

  • Key-Based SSH Permission denied (publickey) Ubuntu 12-04

    - by user125176
    I have configured sshd to accept key-based ssh logins with LogLevel on DEBUG, and uploaded my public key to ~/.ssh.authorized_keys, where permissions are set as: 700 ~/.ssh 600 ~/.ssh/authorized_keys From root, I can su - USERNAME. From the client I get Permission denied (publicly). From the server Here's how it is telling me that it "Could not open authorized keys '/home/USERNAME/.ssh/authorized_keys': Permission denied". Client protocol version 2.0; client software version OpenSSH_5.2 match: OpenSSH_5.2 pat OpenSSH* Enabling compatibility mode for protocol 2.0 Local version string SSH-2.0-OpenSSH_5.9p1 Debian-5ubuntu1 permanently_set_uid: 105/65534 [preauth] list_hostkey_types: ssh-rsa,ssh-dss,ecdsa-sha2-nistp256 [preauth] SSH2_MSG_KEXINIT sent [preauth] SSH2_MSG_KEXINIT received [preauth] kex: client->server aes128-ctr hmac-md5 none [preauth] kex: server->client aes128-ctr hmac-md5 none [preauth] SSH2_MSG_KEX_DH_GEX_REQUEST received [preauth] SSH2_MSG_KEX_DH_GEX_GROUP sent [preauth] expecting SSH2_MSG_KEX_DH_GEX_INIT [preauth] SSH2_MSG_KEX_DH_GEX_REPLY sent [preauth] SSH2_MSG_NEWKEYS sent [preauth] expecting SSH2_MSG_NEWKEYS [preauth] SSH2_MSG_NEWKEYS received [preauth] KEX done [preauth] userauth-request for user USERNAME service ssh-connection method none [preauth] attempt 0 failures 0 [preauth] PAM: initializing for "USERNAME" PAM: setting PAM_RHOST to "USERHOSTNAME" PAM: setting PAM_TTY to "ssh" userauth_send_banner: sent [preauth] userauth-request for user USERNAME service ssh-connection method publickey [preauth] attempt 1 failures 0 [preauth] test whether pkalg/pkblob are acceptable [preauth] Checking blacklist file /usr/share/ssh/blacklist.RSA-4096 Checking blacklist file /etc/ssh/blacklist.RSA-4096 temporarily_use_uid: 1001/1002 (e=0/0) trying public key file /home/USERNAME/.ssh/authorized_keys Could not open authorized keys '/home/USERNAME/.ssh/authorized_keys': Permission denied restore_uid: 0/0 temporarily_use_uid: 1001/1002 (e=0/0) trying public key file /home/USERNAME/.ssh/authorized_keys2 Could not open authorized keys '/home/USERNAME/.ssh/authorized_keys2': Permission denied restore_uid: 0/0 Failed publickey for USERNAME from IPADDRESS port 57523 ssh2 Connection closed by IPADDRESS [preauth] do_cleanup [preauth] monitor_read_log: child log fd closed do_cleanup PAM: cleanup

    Read the article

  • Error while compiling Cuda Accelerated Linpack hpl_2.0_FERMI

    - by ghostrustam
    I use Ubuntu 11.04 x86_64 CUDA 4.0 OpenMpi 1.4stable MKL When I compile, I get this error: ar r -L/home/limksadmin/hpl-2.0_FERMI_v13/lib/CUDA/libhpl.a HPL_dlacpy.o HPL_dlatcpy.o HPL_fprintf.o HPL_warn.o HPL_abort.o HPL_dlaprnt.o HPL_dlange.o HPL_dlamch.o ar: -L/home/limksadmin/hpl-2.0_FERMI_v13/lib/CUDA/libhpl.a: No such file or directory make[2]: *** [lib.grd] Error 9 make[2]: Leaving directory `/home/limksadmin/hpl-2.0_FERMI_v13/src/auxil/CUDA' make[1]: *** [build_src] Error 2 make[1]: Leaving directory `/home/limksadmin/hpl-2.0_FERMI_v13' make: *** [build] Error 2 Make.CUDA: LAdir = /opt/intel/mkl/lib/intel64 LAlib = -L $(TOPdir)/src/cuda -ldgemm -L/usr/local/cuda/lib64 -lcuda -lcudart -lcublas -L$(LAdir) -lmkl_intel_lp64 -lmkl_intel_thread -lmkl_core -liomp5 MPdir = /usr/local/mpi/openmpi MPinc = -I$(MPdir)/include MPlib = -L$(MPdir)/lib/libmpi.so CC = /usr/local/mpi/openmpi/bin/mpicc What could be the problem?

    Read the article

  • Procmail lock failures and errors while writing

    - by user58292
    I'm setting up a mail server on an embedded linux system. When sending mail to a local user I get the following error from procmail: procmail: Lock failure on "/home/mail/ktos/.mailspool.lock" procmail: Error while writing to "/home/mail/ktos/.mailspool" procmail: Error while writing to "/var/spool/mail/ktos" From root@waben Wed Dec 15 10:00:40 2010 Folder: **Bounced** 0 procmail: Lock failure on "/root/.mailspool.lock" procmail: Error while writing to "/root/.mailspool" From MAILER-DAEMON Wed Dec 15 10:00:41 2010 Subject: Returned mail: see transcript for details Folder: /var/spool/mail/root 1732 And the mail goes to /var/spool/mail/root. This is my /etc/procmailrc: PATH=/usr/bin:/usr/local/bin MAILDIR=$HOME/.mailspool DEFAULT=$HOME/.mailspool LOGFILE=/dev/pts/0 SHELL=/bin/sh What could be the problem? I'm still pretty green with all the sendmail and procmail stuff as I'm primarily a developer.

    Read the article

  • SFTP jail & Keeping file ownership the same / File owner per folder

    - by Dragonshadow
    I want to setup a jailed SFTP account for a subfolder of another user's home folder, but want the owner of everything in that subfolder to stay the same, including new files and folders uploaded and created by the sftp user, while still allowing access to the files and folders of that subfolder as if the SFTP user was the parent user. rawny bawb-sftp /home/rawny <- rawny owns this /home/rawny/sftp <- rawny owns this too, but bawb-sftp can upload to it, edit files, etc bawb-sftp uploads a file /home/rawny/sftp/lol.txt rawny should still own the file, as if he made it in the first place, even though bawb-sftp was the one that uploaded it. Basically I guess I'm asking for an sftp jail that acts as a highly limited passthrough/puppet for another user?

    Read the article

  • sudo: apache restarting a service on CentOS

    - by WaveyDavey
    I need my web app to restart the dansguardian service (on CentOS) so it needs to run '/sbin/service dansguardian restart' I have a shellscript in /home/topological called apacherestart.sh which does the following: #!/bin/sh id=`id` /sbin/service dansguardian restart r=$? return $r This runs ok (logger statement in script for testing output to syslog, so I know it's running) To make it run, I put this in /etc/sudoers: User_Alias APACHE=www # Cmnd alias specification Cmnd_Alias HTTPRESTART=/home/topological/apacherestart.sh,/sbin/e-smith/db,/etc/rc7.d/S91dansguardian # Defaults specification # User privilege specification root ALL=(ALL) ALL APACHE ALL=(ALL) NOPASSWD: HTTPRESTART So far so good. But the service does not restart. To test this I created a user david, and fudged the uid/gid in /etc/passwd to be the same as www: www:x:102:102:e-smith web server:/home/e-smith:/bin/false david:x:102:102:David:/home/e-smith/files/users/david:/bin/bash then logged in as david and tried to run the apacherestart.sh. The problem I get is: /etc/rc7.d/S91dansguardian: line 51: /sbin/e-smith/db: Permission denied even though S91dansguardian and db are in the sudoers command list. Any ideas?

    Read the article

  • Create nice animation on your ASP.NET Menu control using jQuery

    - by hajan
    In this blog post, I will show how you can apply some nice animation effects on your ASP.NET Menu control. ASP.NET Menu control offers many possibilities, but together with jQuery, you can make very rich, interactive menu accompanied with animations and effects. Lets start with an example: - Create new ASP.NET Web Application and give it a name - Open your Default.aspx page (or any other .aspx page where you will create the menu) - Our page ASPX code is: <form id="form1" runat="server"> <div id="menu">     <asp:Menu ID="Menu1" runat="server" Orientation="Horizontal" RenderingMode="List">                     <Items>             <asp:MenuItem NavigateUrl="~/Default.aspx" ImageUrl="~/Images/Home.png" Text="Home" Value="Home"  />             <asp:MenuItem NavigateUrl="~/About.aspx" ImageUrl="~/Images/Friends.png" Text="About Us" Value="AboutUs" />             <asp:MenuItem NavigateUrl="~/Products.aspx" ImageUrl="~/Images/Box.png" Text="Products" Value="Products" />             <asp:MenuItem NavigateUrl="~/Contact.aspx" ImageUrl="~/Images/Chat.png" Text="Contact Us" Value="ContactUs" />         </Items>     </asp:Menu> </div> </form> As you can see, we have ASP.NET Menu with Horizontal orientation and RenderMode=”List”. It has four Menu Items where for each I have specified NavigateUrl, ImageUrl, Text and Value properties. All images are in Images folder in the root directory of this web application. The images I’m using for this demo are from Free Web Icons. - Next, lets create CSS for the LI and A tags (place this code inside head tag) <style type="text/css">     li     {         border:1px solid black;         padding:20px 20px 20px 20px;         width:110px;         background-color:Gray;         color:White;         cursor:pointer;     }     a { color:White; font-family:Tahoma; } </style> This is nothing very important and you can change the style as you want. - Now, lets reference the jQuery core library directly from Microsoft CDN. <script type="text/javascript" src="http://ajax.aspnetcdn.com/ajax/jQuery/jquery-1.4.4.min.js"></script> - And we get to the most interesting part, applying the animations with jQuery Before we move on writing jQuery code, lets see what is the HTML code that our ASP.NET Menu control generates in the client browser.   <ul class="level1">     <li><a class="level1" href="Default.aspx"><img src="Images/Home.png" alt="" title="" class="icon" />Home</a></li>     <li><a class="level1" href="About.aspx"><img src="Images/Friends.png" alt="" title="" class="icon" />About Us</a></li>     <li><a class="level1" href="Products.aspx"><img src="Images/Box.png" alt="" title="" class="icon" />Products</a></li>     <li><a class="level1" href="Contact.aspx"><img src="Images/Chat.png" alt="" title="" class="icon" />Contact Us</a></li> </ul>   So, it generates unordered list which has class level1 and for each item creates li element with an anchor with image + menu text inside it. If we want to access the list element only from our menu (not other list element sin the page), we need to use the following jQuery selector: “ul.level1 li”, which will find all li elements which have parent element ul with class level1. Hence, the jQuery code is:   <script type="text/javascript">     $(function () {         $("ul.level1 li").hover(function () {             $(this).stop().animate({ opacity: 0.7, width: "170px" }, "slow");         }, function () {             $(this).stop().animate({ opacity: 1, width: "110px" }, "slow");         });     }); </script>   I’m using hover, so that the animation will occur once we go over the menu item. The two different functions are one for the over, the other for the out effect. The following line $(this).stop().animate({ opacity: 0.7, width: "170px" }, "slow");     does the real job. So, this will first stop any previous animations (if any) that are in progress and will animate the menu item by giving to it opacity of 0.7 and changing the width to 170px (the default width is 110px as in the defined CSS style for li tag). This happens on mouse over. The second function on mouse out reverts the opacity and width properties to the default ones. The last parameter “slow” is the speed of the animation. The end result is:   The complete ASPX code: <html xmlns="http://www.w3.org/1999/xhtml"> <head runat="server">     <title>ASP.NET Menu + jQuery</title>     <style type="text/css">         li         {             border:1px solid black;             padding:20px 20px 20px 20px;             width:110px;             background-color:Gray;             color:White;             cursor:pointer;         }         a { color:White; font-family:Tahoma; }     </style>     <script type="text/javascript" src="http://ajax.aspnetcdn.com/ajax/jQuery/jquery-1.4.4.min.js"></script>     <script type="text/javascript">         $(function () {             $("ul.level1 li").hover(function () {                 $(this).stop().animate({ opacity: 0.7, width: "170px" }, "slow");             }, function () {                 $(this).stop().animate({ opacity: 1, width: "110px" }, "slow");             });         });     </script> </head> <body>     <form id="form1" runat="server">     <div id="menu">         <asp:Menu ID="Menu1" runat="server" Orientation="Horizontal" RenderingMode="List">                         <Items>                 <asp:MenuItem NavigateUrl="~/Default.aspx" ImageUrl="~/Images/Home.png" Text="Home" Value="Home"  />                 <asp:MenuItem NavigateUrl="~/About.aspx" ImageUrl="~/Images/Friends.png" Text="About Us" Value="AboutUs" />                 <asp:MenuItem NavigateUrl="~/Products.aspx" ImageUrl="~/Images/Box.png" Text="Products" Value="Products" />                 <asp:MenuItem NavigateUrl="~/Contact.aspx" ImageUrl="~/Images/Chat.png" Text="Contact Us" Value="ContactUs" />             </Items>         </asp:Menu>     </div>     </form> </body> </html> Hope this was useful. Regards, Hajan

    Read the article

< Previous Page | 96 97 98 99 100 101 102 103 104 105 106 107  | Next Page >