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• php values of one array to key of another array

  - by mark

  I have 2 arrays $arr1 = Array ( [0] => 12 [1] => 4 [2] => 8 [3] => xx [4] => 1 [5] => 1year [6] => 7 ) $arr2 = Array ( [0] => 1 [1] => 2 [2] => 3 [3] => 4 [4] => 5 [5] => 6 [6] => 7 ) I want to create a new array with the values of a2 as keys in $arr1. My resultant array should be like this $arr3 = Array ( [1] => 12 [2] => 4 [3] => 8 [4] => xx [5] => 1 [6] => 1year [7] => 7 )

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• Selecting dictionary items by key efficiently in Python

  - by user248237

  suppose I have a dictionary whose keys are strings. How can I efficiently make a new dictionary from that which contains only the keys present in some list? for example: # a dictionary mapping strings to stuff mydict = {'quux': ..., 'bar': ..., 'foo': ...} # list of keys to be selected from mydict keys_to_select = ['foo', 'bar', ...] The way I came up with is: filtered_mydict = [mydict[k] for k in mydict.keys() \ if k in keys_to_select] but I think this is highly inefficient because: (1) it requires enumerating the keys with keys(), (2) it requires looking up k in keys_to_select each time. at least one of these can be avoided, I would think. any ideas? I can use scipy/numpy too if needed.

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• Class templating std::set key types

  - by TomFLuff

  I have a class to evaluate set algebra but wish to template it. At the minute it looks a bit like this set.h: template<typename T> class SetEvaluation { public: SetEvaluation<T>(); std::set<T> evaluate(std::string in_expression); } set.cpp template<typename T> std::set<T> SetEvaluation<T>::evaluate(std::string expression) { std::set<T> result; etc etc... } But i'm getting undefined reference errors when compiling. Is it possible to declare the return type as std::set<T> and then pass std::string as the class template param. There are no errors in the class but only when I try to instantiate SetEvaluation<std::string> Can anyone shed light on this problem? thanks

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• Create array items by specify a key that includes hierachy

  - by Relax

  Given original codes as: foreach($option as $name=>$value) $array[$name] = $value; and some $name as button[0][text], button[0][value], button[1][text], spider[0][name], ... How could i get results as $array[button][0][text] = $value ... $array[spider][0][name] = $value ? ...

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• limiting mysql results by range of a specific key INCLUDING DUPLICATES

  - by aVC

  I have a query SELECT p.*, m.*, (SELECT COUNT(*) FROM newPhotoonAlert n WHERE n.userIDfor='$id' AND n.threadID=p.threadID and n.seen='0') AS unReadCount FROM posts p JOIN myMembers m ON m.id = p.user_id LEFT JOIN following f ON (p.user_id = f.user_id AND f.follower_id='$id' AND f.request='0' AND f.status='1') JOIN myMembers searcher ON searcher.id = '$id' WHERE ((f.follower_id = searcher.id) OR m.id='$id') AND p.flagged <'5' ORDER BY p.threadID DESC,p.positionID It brings result as expected but I want to add Another CLAUSE to limit the results. Say a sample (minimal shown) set of data looks like this with the above query. threadID postID positionID url 564 1254 2 a.com 564 1245 1 a1.com 541 1215 3 b1.com 541 1212 2 b2.com 541 1210 1 b3.com 523 745 1 c1.com 435 689 2 d2.com 435 688 1 a4.com 256 345 1 s3.com 164 316 1 f1.com . . I want to get ROWS corresponding to 2 DISTINCT threadIDs starting from MAX, but I want to include duplicates as well. Something like AND p.threadID IN (Select just Two of all threadIDs currently selected, but include duplicate rows) So my result should be threadID postID positionID url 564 1254 2 a.com 564 1245 1 a1.com 541 1215 3 b1.com 541 1212 2 b2.com 541 1210 1 b3.com

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• Ruby 1.9 regex as a hash key

  - by Liutauras

  I am trying this example myhash = {/(\d+)/ => "hello"} with ruby 1.9.2p136 (2010-12-25) [i386-mingw32]. It doesn't work as expected (edit: as it turned out it shouldn't work as I was expecting): irb(main):004:0> myhash = {/(\d+)/ => "hello"} => {/(\d+)/=>"Hello"} irb(main):005:0> myhash[2222] => nil irb(main):006:0> myhash["2222"] => nil In Rubular which is on ruby1.8.7 the regex works. What am I missing?

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• Foreign-key-like merge in R

  - by skyl

  I'm merging a bunch of csv with 1 row per id/pk/seqn. > full = merge(demo, lab13am, by="seqn", all=TRUE) > full = merge(full, cdq, by="seqn", all=TRUE) > full = merge(full, mcq, by="seqn", all=TRUE) > full = merge(full, cfq, by="seqn", all=TRUE) > full = merge(full, diq, by="seqn", all=TRUE) > print(length(full$ridageyr)) [1] 9965 > print(summary(full$ridageyr)) Min. 1st Qu. Median Mean 3rd Qu. Max. 0.00 11.00 19.00 29.73 48.00 85.00 Everything is great. But, I have another file which has multiple rows per id like: "seqn","rxd030","rxd240b","nhcode","rxq250" 56,2,"","",NA,NA,"" 57,1,"ACETAMINOPHEN","01200",2 57,1,"BUDESONIDE","08800",1 58,1,"99999","",NA 57 has two rows. So, if I naively try to merge this file, I have a ton more rows and my data gets all skewed up. > full = merge(full, rxq, by="seqn", all=TRUE) > print(length(full$ridageyr)) [1] 15643 > print(summary(full$ridageyr)) Min. 1st Qu. Median Mean 3rd Qu. Max. 0.00 14.00 41.00 40.28 66.00 85.00 Is there a normal idiomatic way to deal with data like this? Suppose I want a way to make a simple model like MYSPECIAL_FACTOR <- somehow() glm(MYSPECIAL_FACTOR ~ full$ridageyr, family=binomial) where MYSPECIAL_FACTOR is, say, whether or not rxd240b == "ACETAMINOPHEN" for the observations which are unique by seqn. You can reproduce by running the first bit of this.

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• php array_filter without key preservation

  - by pistacchio

  Hi, if i filter an array with array_filter to eliminate null values, keys are preserved and this generated "holes" in the array. Eg: The filtered version of [0] => 'foo' [1] => null [2] => 'bar' is [0] => 'foo' [2] => 'bar' How can i get, instead [0] => 'foo' [1] => 'bar' ? Thanks

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• Multiple key presses doing different events in C#

  - by Nevik Eeirnb

  Hi, private void Form1_KeyDown(object sender, KeyEventArgs e) { if (e.KeyCode == Keys.W) player1.moveUp(); if (e.KeyCode == Keys.NumPad8) player2.moveUp(); } In the above code the moveUp methods basically just increment a value. I want it so both keys can be pressed (or held down)at the same time and both events will trigger. Thanks, Nevik

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• Access php multidimensional array key based on a variable string

  - by ggirtsou

  I have stored the XML path to items in a string like this: response->items->item. What I need to do is to access an array called $xml_array like this: $xml_array['response']['items']['item'] When I write it in the code it works. The thing is that I want it to be done on the fly. I use this to convert response->items->item to ['response']['items']['item']: $xml_path = 'response->items->item'; $explode_path = explode('->', $xml_path); $correct_string = false; foreach($explode_path as $path) { $correct_string .= '[\''.$path.'\']'; } the problem is that I can't access $xml_array by doing this: $xml_array[$correct_string] So I end up with this: $xml_tag = 'title'; $xml_path = 'response->items->item'; $correct_string = '$items = $xml2array'; $explode_path = explode('->', $xml_path); foreach($explode_path as $path) { $correct_string .= '[\''.$path.'\']'; } $correct_string .= ';'; eval($correct_string); foreach($items as $item) { echo $item[$xml_tag].'<br />'; } and access the $xml_array array through $items array. Is there any way I can do this and avoid using eval()? Thanks in advance!

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• sort list(of string()) using a variable index into string() as key - vb.net

  - by tullynyguy

  I have a List(of String()). I have written a custom comparer (implements IComparer(of string)) to do an alphanumeric sort. Is there a way to sort the List using a given index to determine which position in the String() to sort by? In other words one time I might sort by Index = 0 and another time by Index = 3. The length of all String() in the list is the same. For reference this question is similar to Sort List<String[]> except I am using VB.net and that question is hardwired to Index=0.

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• Delete data with foreign key in SQL Server table

  - by Andha

  I'm going to delete data in an SQL Server table (parent) which has a relationship with another table (child). I tried the basic Delete query. But it isn't working (and I know it won't). DELETE FROM table WHERE ... It returned following error The DELETE statement conflicted with the REFERENCE constraint ... I need to keep the table's schema. I know that I just need to add some words in the query, I've ever done this before, but I just couldn't recall it.

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• Can I legally publish my Fortran 90 wrappers to nVidias CUFFT library (from CUDA SDK)?

  - by Jakub Narebski

  From a legal standpoint (licensing issues), can I legally in agreement with license publish Fortran 90 wrappers (bindings) to CUFFT library from nVidia CUDA Toolkit, under some open source license (either CC0 i.e. public domain, or some kind of permissive license like BSD). nVidia provides only C bindings with their CUDA SDK. Header files contain the following text: /* * Copyright 1993-2011 NVIDIA Corporation. All rights reserved. * * NOTICE TO LICENSEE: * * This source code and/or documentation ("Licensed Deliverables") are * subject to NVIDIA intellectual property rights under U.S. and * international Copyright laws. * * These Licensed Deliverables contained herein is PROPRIETARY and * CONFIDENTIAL to NVIDIA and is being provided under the terms and * conditions of a form of NVIDIA software license agreement by and * between NVIDIA and Licensee ("License Agreement") or electronically * accepted by Licensee. Notwithstanding any terms or conditions to * the contrary in the License Agreement, reproduction or disclosure * of the Licensed Deliverables to any third party without the express * written consent of NVIDIA is prohibited. The License.txt file includes the following fragment Source Code: Developer shall have the right to modify and create derivative works with the Source Code. Developer shall own any derivative works ("Derivatives") it creates to the Source Code, provided that Developer uses the Materials in accordance with the terms and conditions of this Agreement. Developer may distribute the Derivatives, provided that all NVIDIA copyright notices and trademarks are propagated and used properly and the Derivatives include the following statement: "This software contains source code provided by NVIDIA Corporation."

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• Licensing a JavaScript library

  - by Kendall Frey

  I am developing a free, open-source (duh) JavaScript library, and wondering how to license it. I was considering the GNU GPL, but I heard that I must distribute the license with the software, and I'm not sure anymore. I would like the library to be available much like jQuery: In a free, downloadable script, preferably in either original or minified form. Am I mistaken about the GNU GPL license terms? jQuery is dual licensed under GNU GPL or MIT licenses. How does the GPL apply to single script files like that? Can I license my library with nothing more than a few sentences in the script file? Is there another license that better suits my needs? What would be nice is a license that allows you to put the URL in the source, for people to read if they want. I don't know that many do, unless I am mistaken. I am generally looking to release the library as free software like the GPL specifies, but don't want to have to force licensees to download the full license unless they wish to read it.

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• How can I decrease relevancy of Creative Commons footer text? (In Google Webmaster Tools)

  - by anonymous coward

  I know that I may just have to link the image to make this happen, but I figured it was worth asking, just in case there's some other semantic markup or tips I could use... I have a site that uses the textual Creative Commons blurb in the footer. The markup is like so: <div class="footer"> <!-- snip --> <!-- Creative Commons License --> <a rel="license" href="http://creativecommons.org/licenses/by-nc-sa/3.0/us/"><img alt="Creative Commons License" style="border-width:0" src="http://i.creativecommons.org/l/by-nc-sa/3.0/us/80x15.png" /></a><br />This work by <a xmlns:cc="http://creativecommons.org/ns#" href="http://www.xmemphisx.com/" property="cc:attributionName" rel="cc:attributionURL">xMEMPHISx.com</a> is licensed under a <a rel="license" href="http://creativecommons.org/licenses/by-nc-sa/3.0/us/">Creative Commons Attribution-Noncommercial-Share Alike 3.0 United States License</a>. <!-- /Creative Commons License --> </div> Within Google Webmaster Tools, the list of relevant keywords is heavily saturated with the text from that blurb. For instance, 50% of my top-ten most relevant keywords (including the site name): [site name] license [keyword] commons creative [keyword] alike [keyword] attribution [keyword] I have not done any extensive testing to find out rather or not this list even matters, and so far this doesn't impact performance in any way. The site is well designed for humans, and it is as findable as it needs to be at the moment. But, out of mostly curiosity: Do you have any tips for decreasing the relevancy of the text from the Creative Commons footer blurb?

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• Introducing the PeopleSoft Interaction Hub

  - by Matthew Haavisto

  The PeopleSoft Applications Portal has just been re-branded as the PeopleSoft Interaction Hub.  It's not just a name change, however.  As part of our ongoing efforts to deliver a richer user experience to PeopleSoft customers, Oracle/PeopleSoft is now offering an enhanced restricted use license (login required) of the PeopleSoft Interaction Hub free with PeopleTools.  This change extends the existing restricted use license to include the following additional capabilities: Dynamic Unified Navigation.  Enables customers to easily provide seamless, unified navigation among their entire PeopleSoft application portfolio. Site-wide branding.  Makes it easier to brand your ecosystem and provide a vivid, contemporary appearance for your applications. These additions augment the capabilities provided in the previous restricted use license, which remain available: creation and use of collaborative workspaces, and pre-built collaborative services for use in related content.  (See the license notes (login required)for a complete list of everything that is granted with the PeopleTools license.)PeopleSoft is moving to deliver a contemporary user experience for your applications users, and the this license change supports that direction.  In addition, the name change reflects our positioning of the PeopleSoft Interaction Hub as a primary means for unifying your PeopleSoft ecosystem, and providing a richer, web-site-based user experience rather than a pillared, application-based experience.See this white paper to get an idea of some of the capabilities that you can employ with the PeopleSoft Interaction Hub to enhance the PeopleSoft user experience.  In addition, this red paper provides valuable 'how-to' guidance.  In the near future we will be producing a best practices guide for deployment.  In the mean time, the most recent release/feature pack of the PIH automates the setup of unified navigation with a Workcenter specifically supporting Unified Navigation. This Workcenter guides administrators through the setup process, and streamlines things.So what should customers do if they still want to use the PeopleSoft Interaction Hub for traditional portal purposes?  Customers can employ the PIH's full capabilities such as multiple site deployment/management and content management, by buying the full, unrestricted license. We are continuing to enhance the product, and it remains part of Applications Unlimited, and we have some exciting features planned.

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• JPA @OneToMany and composite PK

  - by Fleuri F

  Good Morning, I am working on project using JPA. I need to use a @OneToMany mapping on a class that has three primary keys. You can find the errors and the classes after this. If anyone has an idea! Thanks in advance! FF javax.persistence.PersistenceException: No Persistence provider for EntityManager named JTA_pacePersistence: Provider named oracle.toplink.essentials.PersistenceProvider threw unexpected exception at create EntityManagerFactory: javax.persistence.PersistenceException javax.persistence.PersistenceException: Exception [TOPLINK-28018] (Oracle TopLink Essentials - 2.0.1 (Build b09d-fcs (12/06/2007))): oracle.toplink.essentials.exceptions.EntityManagerSetupException Exception Description: predeploy for PersistenceUnit [JTA_pacePersistence] failed. Internal Exception: Exception [TOPLINK-7220] (Oracle TopLink Essentials - 2.0.1 (Build b09d-fcs (12/06/2007))): oracle.toplink.essentials.exceptions.ValidationException Exception Description: The @JoinColumns on the annotated element [private java.util.Set isd.pacepersistence.common.Action.permissions] from the entity class [class isd.pacepersistence.common.Action] is incomplete. When the source entity class uses a composite primary key, a @JoinColumn must be specified for each join column using the @JoinColumns. Both the name and the referenceColumnName elements must be specified in each such @JoinColumn. at oracle.toplink.essentials.internal.ejb.cmp3.EntityManagerSetupImpl.predeploy(EntityManagerSetupImpl.java:643) at oracle.toplink.essentials.ejb.cmp3.EntityManagerFactoryProvider.createEntityManagerFactory(EntityManagerFactoryProvider.java:196) at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:110) at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:83) at isd.pacepersistence.common.DataMapper.(Unknown Source) at isd.pacepersistence.server.MainServlet.getDebugCase(Unknown Source) at isd.pacepersistence.server.MainServlet.doGet(Unknown Source) at javax.servlet.http.HttpServlet.service(HttpServlet.java:718) at javax.servlet.http.HttpServlet.service(HttpServlet.java:831) at org.apache.catalina.core.ApplicationFilterChain.servletService(ApplicationFilterChain.java:411) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:290) at org.apache.catalina.core.StandardContextValve.invokeInternal(StandardContextValve.java:271) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:202) There is the source code of my classes : Action : @Entity @Table(name="action") public class Action { @Id @GeneratedValue(strategy=GenerationType.IDENTITY) private int num; @ManyToOne(cascade= { CascadeType.PERSIST, CascadeType.MERGE, CascadeType.REFRESH }) @JoinColumn(name="domain_num") private Domain domain; private String name; private String description; @OneToMany @JoinTable(name="permission", joinColumns= { @JoinColumn(name="action_num", referencedColumnName="action_num", nullable=false, updatable=false) }, inverseJoinColumns= { @JoinColumn(name="num") }) private Set<Permission> permissions; public Action() { } Permission : @SuppressWarnings("serial") @Entity @Table(name="permission") public class Permission implements Serializable { @EmbeddedId private PermissionPK primaryKey; @ManyToOne @JoinColumn(name="action_num", insertable=false, updatable=false) private Action action; @ManyToOne @JoinColumn(name="entity_num", insertable=false, updatable=false) private isd.pacepersistence.common.Entity entity; @ManyToOne @JoinColumn(name="class_num", insertable=false, updatable=false) private Clazz clazz; private String kondition; public Permission() { } PermissionPK : @SuppressWarnings("serial") @Entity @Table(name="permission") public class Permission implements Serializable { @EmbeddedId private PermissionPK primaryKey; @ManyToOne @JoinColumn(name="action_num", insertable=false, updatable=false) private Action action; @ManyToOne @JoinColumn(name="entity_num", insertable=false, updatable=false) private isd.pacepersistence.common.Entity entity; @ManyToOne @JoinColumn(name="class_num", insertable=false, updatable=false) private Clazz clazz; private String kondition; public Permission() { }

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• JPA @ManyToOne and composite PK

  - by Fleuri F

  Good Morning, I am working on project using JPA. I need to use a @ManyToOne mapping on a class that has three primary keys. You can find the errors and the classes after this. If anyone has an idea! Thanks in advance! FF javax.persistence.PersistenceException: No Persistence provider for EntityManager named JTA_pacePersistence: Provider named oracle.toplink.essentials.PersistenceProvider threw unexpected exception at create EntityManagerFactory: javax.persistence.PersistenceException javax.persistence.PersistenceException: Exception [TOPLINK-28018] (Oracle TopLink Essentials - 2.0.1 (Build b09d-fcs (12/06/2007))): oracle.toplink.essentials.exceptions.EntityManagerSetupException Exception Description: predeploy for PersistenceUnit [JTA_pacePersistence] failed. Internal Exception: Exception [TOPLINK-7220] (Oracle TopLink Essentials - 2.0.1 (Build b09d-fcs (12/06/2007))): oracle.toplink.essentials.exceptions.ValidationException Exception Description: The @JoinColumns on the annotated element [private java.util.Set isd.pacepersistence.common.Action.permissions] from the entity class [class isd.pacepersistence.common.Action] is incomplete. When the source entity class uses a composite primary key, a @JoinColumn must be specified for each join column using the @JoinColumns. Both the name and the referenceColumnName elements must be specified in each such @JoinColumn. at oracle.toplink.essentials.internal.ejb.cmp3.EntityManagerSetupImpl.predeploy(EntityManagerSetupImpl.java:643) at oracle.toplink.essentials.ejb.cmp3.EntityManagerFactoryProvider.createEntityManagerFactory(EntityManagerFactoryProvider.java:196) at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:110) at javax.persistence.Persistence.createEntityManagerFactory(Persistence.java:83) at isd.pacepersistence.common.DataMapper.(Unknown Source) at isd.pacepersistence.server.MainServlet.getDebugCase(Unknown Source) at isd.pacepersistence.server.MainServlet.doGet(Unknown Source) at javax.servlet.http.HttpServlet.service(HttpServlet.java:718) at javax.servlet.http.HttpServlet.service(HttpServlet.java:831) at org.apache.catalina.core.ApplicationFilterChain.servletService(ApplicationFilterChain.java:411) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:290) at org.apache.catalina.core.StandardContextValve.invokeInternal(StandardContextValve.java:271) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:202) There is the source code of my classes : Action : @Entity @Table(name="action") public class Action { @Id @GeneratedValue(strategy=GenerationType.IDENTITY) private int num; @ManyToOne(cascade= { CascadeType.PERSIST, CascadeType.MERGE, CascadeType.REFRESH }) @JoinColumn(name="domain_num") private Domain domain; private String name; private String description; @OneToMany @JoinTable(name="permission", joinColumns= { @JoinColumn(name="action_num", referencedColumnName="action_num", nullable=false, updatable=false) }, inverseJoinColumns= { @JoinColumn(name="num") }) private Set<Permission> permissions; public Action() { } Permission : @SuppressWarnings("serial") @Entity @Table(name="permission") public class Permission implements Serializable { @EmbeddedId private PermissionPK primaryKey; @ManyToOne @JoinColumn(name="action_num", insertable=false, updatable=false) private Action action; @ManyToOne @JoinColumn(name="entity_num", insertable=false, updatable=false) private isd.pacepersistence.common.Entity entity; @ManyToOne @JoinColumn(name="class_num", insertable=false, updatable=false) private Clazz clazz; private String kondition; public Permission() { } PermissionPK : @SuppressWarnings("serial") @Entity @Table(name="permission") public class Permission implements Serializable { @EmbeddedId private PermissionPK primaryKey; @ManyToOne @JoinColumn(name="action_num", insertable=false, updatable=false) private Action action; @ManyToOne @JoinColumn(name="entity_num", insertable=false, updatable=false) private isd.pacepersistence.common.Entity entity; @ManyToOne @JoinColumn(name="class_num", insertable=false, updatable=false) private Clazz clazz; private String kondition; public Permission() { }

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• extract data from Plist to array and dictionary

  - by Boaz

  Hi I made a plist that looks like that: <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE plist PUBLIC "-//Apple//DTD PLIST 1.0//EN" "http://www.apple.com/DTDs/PropertyList 1.0.dtd"> <plist version="1.0"> <array> <array> <dict> <key>Company</key> <string>xxx</string> <key>Title</key> <string>VP Marketing</string> <key>Name</key> <string>Alon ddfr</string> </dict> <dict> <key>Name</key> <string>Adam Ben Shushan</string> <key>Title</key> <string>CEO</string> <key>Company</key> <string>Shushan ltd.</string> </dict> </array> <array> <dict> <key>Company</key> <string>xxx</string> <key>Title</key> <string>CTO</string> <key>Name</key> <string>Boaz frf</string> </dict> </array> </array> </plist> Now I want to extract the data like that (all the 'A' for key "Name" to one section and all the 'B' "Name" to other one): NSString *plistpath = [[NSBundle mainBundle] pathForResource:@"PeopleData" ofType:@"plist"]; NSMutableArray *attendees = [[NSMutableArray alloc] initWithContentsOfFile:plistpath]; listOfPeople = [[NSMutableArray alloc] init];//Add items NSDictionary *indexADict = [NSDictionary dictionaryWithObject:[[attendees objectAtIndex:0] objectForKey:@"Name"] forKey:@"Profiles"]; NSDictionary *indexBDict = [NSDictionary dictionaryWithObject:[[attendees objectAtIndex:1] objectForKey:@"Name"] forKey:@"Profiles"]; [listOfPeople addObject:indexADict]; [listOfPeople addObject:indexBDict]; This in order to view them in sectioned tableView. I know that the problem is here: NSDictionary *indexADict = [NSDictionary dictionaryWithObject:[[attendees objectAtIndex:0] objectForKey:@"Name"] forKey:@"Profiles"]; But I just can't figure how to do it right. Thanks.

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• List of Django model instance foreign keys losing consistency during state changes.

  - by Joshua

  I have model, Match, with two foreign keys: class Match(model.Model): winner = models.ForeignKey(Player) loser = models.ForeignKey(Player) When I loop over Match I find that each model instance uses a unique object for the foreign key. This ends up biting me because it introduces inconsistency, here is an example: >>> def print_elo(match_list): ... for match in match_list: ... print match.winner.id, match.winner.elo ... print match.loser.id, match.loser.elo ... >>> print_elo(teacher_match_list) 4 1192.0000000000 2 1192.0000000000 5 1208.0000000000 2 1192.0000000000 5 1208.0000000000 4 1192.0000000000 >>> teacher_match_list[0].winner.elo = 3000 >>> print_elo(teacher_match_list) 4 3000 # Object 4 2 1192.0000000000 5 1208.0000000000 2 1192.0000000000 5 1208.0000000000 4 1192.0000000000 # Object 4 >>> I solved this problem like so: def unify_refrences(match_list): """Makes each unique refrence to a model instance non-unique. In cases where multiple model instances are being used django creates a new object for each model instance, even if it that means creating the same instance twice. If one of these objects has its state changed any other object refrencing the same model instance will not be updated. This method ensure that state changes are seen. It makes sure that variables which hold objects pointing to the same model all hold the same object. Visually this means that a list of [var1, var2] whose internals look like so: var1 --> object1 --> model1 var2 --> object2 --> model1 Will result in the internals being changed so that: var1 --> object1 --> model1 var2 ------^ """ match_dict = {} for match in match_list: try: match.winner = match_dict[match.winner.id] except KeyError: match_dict[match.winner.id] = match.winner try: match.loser = match_dict[match.loser.id] except KeyError: match_dict[match.loser.id] = match.loser My question: Is there a way to solve the problem more elegantly through the use of QuerySets without needing to call save at any point? If not, I'd like to make the solution more generic: how can you get a list of the foreign keys on a model instance or do you have a better generic solution to my problem? Please correct me if you think I don't understand why this is happening.

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• Hibernate mapping to object that already exists

  - by teehoo

  I have two classes, ServiceType and ServiceRequest. Every ServiceRequest must specify what kind of ServiceType it is. All ServiceType's are predefined in the database, and ServiceRequest is created at runtime by the client. Here are my .hbm files: <hibernate-mapping> <class dynamic-insert="false" dynamic-update="false" mutable="true" name="xxx.model.entity.ServiceRequest" optimistic-lock="version" polymorphism="implicit" select-before-update="false"> <id column="USER_ID" name="id"> <generator class="native"/> </id> <property name="quantity"> <column name="quantity" not-null="true"/> </property> <many-to-one cascade="all" class="xxx.model.entity.ServiceType" column="service_type" name="serviceType" not-null="false" unique="false"/> </class> </hibernate-mapping> and <hibernate-mapping> <class dynamic-insert="false" dynamic-update="false" mutable="true" name="xxx.model.entity.ServiceType" optimistic-lock="version" polymorphism="implicit" select-before-update="false"> <id column="USER_ID" name="id"> <generator class="native"/> </id> <property name="description"> <column name="description" not-null="false"/> </property> <property name="cost"> <column name="cost" not-null="true"/> </property> <property name="enabled"> <column name="enabled" not-null="true"/> </property> </class> </hibernate-mapping> When I run this, I get com.mysql.jdbc.exceptions.MySQLIntegrityConstraintViolationException: Cannot add or update a child row: a foreign key constraint fails I think my problem is that when I create a new ServiceRequest object, ServiceType is one of its properties, and therefore when I'm saving ServiceRequest to the database, Hibernate attempts to insert the ServiceType object once again, and finds that it is already exists. If this is the case, how do I make it so that Hibernate points to the exists ServiceType instead of trying to insert it again?

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• Inheritance of jQuery's prototype partially fails

  - by user1065745

  I want to use Coffeescript to create an UIObject class. This class should inherit from jQuery, so that instances of UIObject can be used as if they where created with jQuery. class UIObject isObject: (val) -> typeof val is "object" constructor: (tag, attributes) -> @merge jQuery(tag, attributes), this @UIObjectProperties = {} merge: (source, destination) -> for key of source if destination[key] is undefined destination[key] = source[key] else if @isObject(source[key]) @merge(source[key], destination[key]) return It partially works. Consider the Foobar class below: class Foobar extends UIObject constructor: -> super("<h1/>", html: "Foobar") $("body").append(new Foobar) works fine. BUT: (new Foobar).appendTo("body") places the tag, but also raises RangeError: Maximum call stack size exceeded. Was it just a bad idea to inherit from jQuery? Or is there a solurion? For those who don't know CoffeeScript, the JavaScript source is: var Foobar, UIObject; var __hasProp = Object.prototype.hasOwnProperty, __extends = function(child, parent) { for (var key in parent) { if (__hasProp.call(parent, key)) child[key] = parent[key]; } function ctor() { this.constructor = child; } ctor.prototype = parent.prototype; child.prototype = new ctor; child.__super__ = parent.prototype; return child; }; UIObject = (function () { UIObject.prototype.isObject = function (val) { return typeof val === "object"; }; function UIObject(tag, attributes) { this.merge(jQuery(tag, attributes), this); this.UIObjectProperties = {}; } UIObject.prototype.merge = function (source, destination) { var key; for (key in source) { if (destination[key] === void 0) { destination[key] = source[key]; } else if (this.isObject(source[key])) { this.merge(source[key], destination[key]); } } }; return UIObject; })(); Foobar = (function () { __extends(Foobar, UIObject); function Foobar() { Foobar.__super__.constructor.call(this, "<h1/>", { html: "Foobar" }); } return Foobar; })();

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• How to wrtie a XML License Line(ended with a forward slash '/') in C#?

  - by Nano HE

  I want to write a XML file as below: <?xml version="1.0" encoding="UTF-8"?> <books xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <License licenseId="" licensePath="" /> Some piece of my code attached here // Create a new file in D:\\ and set the encoding to UTF-8 XmlTextWriter textWriter = new XmlTextWriter("D:\\books.xml", System.Text.Encoding.UTF8); // Format automatically textWriter.Formatting = Formatting.Indented; // Opens the document textWriter.WriteStartDocument(); // Write the namespace declaration. textWriter.WriteStartElement("books", null); // Write the genre attribute. textWriter.WriteAttributeString("xmlns", "xsd", null, "http://www.w3.org/2001/XMLSchema"); textWriter.WriteAttributeString("xmlns", "xsi", null, "http://www.w3.org/2001/XMLSchema-instance"); And now I need to write the License Line below in C# <License licenseId="" licensePath="" /> But I don't know how to move on for I found the Line ended with the forward slash / .Thank you.

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• How to wrtie a XML License Line in C#?

  - by Nano HE

  My want to write a XML file as this: <?xml version="1.0" encoding="UTF-8"?> <Equipment xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <License licenseId="" licensePath="" /> Some piece of my code attached here // Create a new file in D:\\ and set the encoding to UTF-8 XmlTextWriter textWriter = new XmlTextWriter("D:\\books.xml", System.Text.Encoding.UTF8); // Format automatically textWriter.Formatting = Formatting.Indented; // Opens the document textWriter.WriteStartDocument(); // Write the namespace declaration. textWriter.WriteStartElement("books", null); // Write the genre attribute. textWriter.WriteAttributeString("xmlns", "xsd", null, "http://www.w3.org/2001/XMLSchema"); textWriter.WriteAttributeString("xmlns", "xsi", null, "http://www.w3.org/2001/XMLSchema-instance"); And now I need to write the License Line below in C# <License licenseId="" licensePath="" /> But I don't know how to move on for I found the Line ended with the special / .Thank you.

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• Missed OpenWorld 2011 or JavaOne? See the Key Announcements Today

  - by Dain C. Hansen

  Learn more about Oracle OpenWorld and JavaOne Key Announcements through our six On Demand Webcasts or Podcasts. Your time is precious and you can't make time to watch all keynotes and sessions on demand. Want to get a concise overview on the Oracle OpenWorld and JavaOne key announcements? Presented by Oracle experts in EMEA, these six webcasts will help you decide which keynotes, general or solution sessions on Oracle OpenWorld and JavaOne could be of more interest to you. Six informative, on-demand sessions are available as podcasts and webcasts, on Oracle Hardware and Software, each taking just 15-20 minutes. Be updated in an hour on Oracle OpenWorld on… Oracle Exadata and Exalogic Engineered Systems with Oracle Applications Oracle Exalytics Business Intelligence Machine, the industry's first in-memory hardware and software system Oracle Big Data Appliance, the end-to-end solution for Big Data Oracle Enterprise Manager 12c, the industry's first solution to combine management of the full Oracle stack with complete enterprise cloud lifecycle management Oracle Fusion Applications, a complete suite with 100+ modules Oracle Public Cloud with subscription-based, self-service access to Oracle Fusion Applications, Oracle Fusion Middleware and Oracle Database Watch the Six JavaOne Key Announcement Webcasts anywhere you can access the Internet and learn more about: Plans for advancing the Java Platform, Standard Edition (Java SE) and an update on Java SE 8 Plans announced for the evolution Java Platform, Micro Edition Availability of JavaFX 2.0 The NetBeans IDE Availability for Windows, Mac, Linux and Oracle Solaris Latest developments in the evolution of Java Platform, Enterprise Edition (Java EE). Oracle Java Cloud Service. Follow other informative, on-demand sessions on Oracle Hardware and Software on topics like Cloud, Exadata, Exalogic, Exalytics, Big Data Appliance, Enterprise Manager 12c, Hardware - SuperCluster, Server - and Storage, Oracle Fusion Applications Register now!

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