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  • Getting deadlocks in MySQL

    - by at
    We're very frustratingly getting deadlocks in MySQL. It isn't because of exceeding a lock timeout as the deadlocks happen instantly when they do happen. Here's the SQL code that is executing on 2 separate threads (with 2 separate connections from the connection pool) that produces a deadlock: UPDATE Sequences SET Counter = LAST_INSERT_ID(Counter + 1) WHERE Sequence IS NULL Sequences table has 2 columns: Sequence and Counter The LAST_INSERT_ID allows us to retrieve this updated counter value as per MySQL's recommendation. That works perfect for us, but we get these deadlocks! Why are we getting them and how can we avoid them?? Thanks so much for any help with this.

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  • MySQL text field issues

    - by chenger
    This is quite a noobish question, I have searched for a few hours now and I know this has to be simple. I am using XAMPP and I am trying to learn some more about using PHP and mySQL together. When I create the DB and the table for information to store, I tried insert info to the table and it stores it as a .dat file rather than text. I know this has to be with how I am setting up the table or the DB but I have gone through things and I think I am just skipping over something. * Apache/2.2.12 (Win32) DAV/2 mod_ssl/2.2.12 OpenSSL/0.9.8k mod_autoindex_color PHP/5.3.0 mod_perl/2.0.4 Perl/v5.10.0 * MySQL client version: 5.1.37 * PHP extension: mysqli that is the phpmyadmin info.

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  • mysql_close(): supplied argument is not a valid MySQL-Link resource

    - by maxedison
    I'm trying to get the hang of using custom session handlers to store session data in a MySQL database. However, I keep getting the following warning: mysql_close(): supplied argument is not a valid MySQL-Link resource Here's the code I'm using, which I got from here: function _open(){ global $_sess_db; $_sess_db = mysql_connect("localhost", "root", "******"); if ($_sess_db) { return mysql_select_db('style', $_sess_db); } return false; } function _close(){ global $_sess_db; return mysql_close($_sess_db); //error happens here } The full text of the error message ultimately points to the final "return mysql_close($_sess_db);" line. I can confirm that the mysql_connect info does in fact work, and I do have the rest of the session handler functions defined as well. And in case it helps, I get these errors immediately upon page load, without actually calling any of the session handler functions, and without having any current sessions open.

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  • mysql querying age from dob

    - by Confused
    My MySQL database has date of birth stored in the format yyyy-mm-dd, how do I query the database - without using php code - to show me results of people born within x years of now, and/or, who are y years of age? The table is called users, the colum is called dob. I've spent a while viewing the MySQL manual but I can't work out precisely how to form my query. So far I went for select * from users where dob... but I don't think that's the way to go.

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  • Way to store dates with missing days/months in mysql (php)

    - by Paul M
    I want to store dates in mysql so I set the table to be of type 'Date', which is fine but mysql requires that the full date is provided YYYY-MM-DD. However some of my data does not include day and some is missing the month. Now I could just use a varchar(10) field, but then its difficult to run date based queries on the data. Is there another date format which is not as strong and would allow me to use ?? or 00 where the day/month is not known?

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  • Get the Latest on MySQL Enterprise Edition

    - by monica.kumar
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mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;}.MsoChpDefault {mso-style-type:export-only; mso-default-props:yes; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:Calibri; mso-fareast-theme-font:minor-latin; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;}.MsoPapDefault {mso-style-type:export-only; margin-bottom:10.0pt; line-height:115%;}@page WordSection1 {size:8.5in 11.0in; margin:1.0in 1.0in 1.0in 1.0in; mso-header-margin:.5in; mso-footer-margin:.5in; mso-paper-source:0;}div.WordSection1 {page:WordSection1;} /* List Definitions */ @list l0 {mso-list-id:595597020; mso-list-type:hybrid; mso-list-template-ids:1001697690 67698689 67698691 67698693 67698689 67698691 67698693 67698689 67698691 67698693;}@list l0:level1 {mso-level-number-format:bullet; mso-level-text:?; mso-level-tab-stop:none; mso-level-number-position:left; text-indent:-.25in; font-family:Symbol;}ol {margin-bottom:0in;}ul {margin-bottom:0in;}--Oracle just announced MySQL 5.5 Enterprise Edition. MySQL Enterprise Edition is a comprehensive subscription that includes:- MySQL Database- MySQL Enterprise Backup- MySQL Enterprise Monitor- MySQL Workbench- Oracle Premier Support; 24x7, WorldwideNew in this release is the addition of MySQL Enterprise Backup and MySQL Workbench along with enhancements in MySQL Enterprise Monitor. Recent integration with MyOracle Support allows MySQL customers to access the same support infrastructure used for Oracle Database customers. Joint MySQL and Oracle customers can experience faster problem resolution by using a common technical support interface. Supporting multiple operating systems, including Linux and Windows, MySQL Enterprise Edition can enable customers to achieve up to 90 percent TCO savingsover Microsoft SQL Server. See what Booking.com is saying:“With more than 50 million unique monthly visitors, performance and uptime are our first priorities,” said Bert Lindner, Senior Systems Architect, Booking.com. “The MySQL Enterprise Monitor is an essential tool to monitor, tune and manage our many MySQL instances. It allows us to zoom in quickly on the right areas, so we can spend our time and resources where it matters.” Read the press release for detailson technology enhancements.

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  • MySQL - Installation

    - by Stuart Brierley
    In order to create a development environment for a project I am working on, I recently needed to install MySQL Server.  The first step was to download the msi. Running this presents you with the installer splash screen, detailing the version of MySQL that you are about to install - in this case MySQL Server 5.1. Next you can choose whether to install a Typical, Complete or Custom installation.  Although this is the first time I have installed MySQL and the Custom option states "Recommended for advanced users" I opted to carry out a Custom installation, specifically so that I could be sure of what features and components were installed. On the Custom Setup screen you can choose which components to install.  By default the Developer Components are not included, but I opted to include some of these elements. Next up is the ready to install screen and then the intsallation progress.   Following the completion of the installation you are shown a few screens with details of the MySQL Enterprise subscription option. Finally the installation is complete and you are offered the chance to configure and register MySQL. Next I will be looking at the configuration of MySQL Server 5.1.

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  • Script throwing unexpected operator when using mysqldump

    - by Astron
    A portion of a script I use to backup MySQL databases has stopped working correctly after upgrading a Debian box to 6.0 Squeeze. I have tested the backup code via CLI and it works fine. I believe it is in the selection of the databases before the backup occurs, possibly something to do with the $skipdb variable. If there is a better way to perform the function then I'm will to try something new. Any insight would be greatly appreciated. $ sudo ./script.sh [: 138: information_schema: unexpected operator [: 138: -1: unexpected operator [: 138: mysql: unexpected operator [: 138: -1: unexpected operator Using bash -x script here is one of the iterations: + for db in '$DBS' + skipdb=-1 + '[' test '!=' '' ']' + for i in '$IGGY' + '[' mysql == test ']' + : + '[' -1 == -1 ']' ++ /bin/date +%F + FILE=/backups/hostname.2011-03-20.mysql.mysql.tar.gz + '[' no = yes ']' + /usr/bin/mysqldump --single-transaction -u root -h localhost '-ppassword' mysql + /bin/tar -czvf /backups/hostname.2011-03-20.mysql.mysql.tar.gz mysql.sql mysql.sql + rm -f mysql.sql Here is the code. if [ $MYSQL_UP = "yes" ]; then echo "MySQL DUMP" >> /tmp/update.log echo "--------------------------------" >> /tmp/update.log DBS="$($MYSQL -u $MyUSER -h $MyHOST -p"$MyPASS" -Bse 'show databases')" for db in $DBS do skipdb=-1 if [ "$IGGY" != "" ] ; then for i in $IGGY do [ "$db" == "$i" ] && skipdb=1 || : done fi if [ "$skipdb" == "-1" ] ; then FILE="$DEST$HOST.`$DATE +"%F"`.$db.mysql.tar.gz" if [ $ENCRYPT = "yes" ]; then $MYSQLDUMP -u $MyUSER -h $MyHOST -p"$MyPASS" $db > $db.sql && $TAR -czvf - $db.sql | $OPENSSL enc -aes-256-cbc -salt -out $FILE.enc -k $ENC_PASS && rm -f $db.sql else $MYSQLDUMP --single-transaction -u $MyUSER -h $MyHOST -p"$MyPASS" $db > $db.sql && $TAR -czvf $FILE $db.sql && rm -f $db.sql fi fi done fi

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  • Need help to debug application using .Net and MySQL

    - by Tim Murphy
    What advice can you give me on how to track down a bug I have while inserting data into MySQL database with .Net? The error message is: MySql.Data.MySqlClient.MySqlException: Duplicate entry '26012' for key 'StockNumber_Number_UNIQUE' Reviewing of the log proves that StockNumber_Number of 26012 has not been inserted yet. Products in use. Visual Studio 2008. mysql.data.dll 6.0.4.0. Windows 7 Ultimate 64 bit and Windows 2003 32 bit. Custom built ORM framework (have source code). Importing data from Access 2003 database. The code works fine for 3000 - 5000 imports. The record being imported that causes the problem in a full run works fine if just importing by itself. I've also seen the error on other records if I sort the data to be imported a different way. Have tried import with and without transactions. Have logged the hell out of the system. The SQL command to create the table: CREATE TABLE `RareItems_RareItems` ( `RareItemKey` CHAR(36) NOT NULL PRIMARY KEY, `StockNumber_Text` VARCHAR(7) NOT NULL, `StockNumber_Number` INT NOT NULL AUTO_INCREMENT, UNIQUE INDEX `StockNumber_Number_UNIQUE` (`StockNumber_Number` ASC), `OurPercentage` NUMERIC , `SellPrice` NUMERIC(19, 2) , `Author` VARCHAR(250) , `CatchWord` VARCHAR(250) , `Title` TEXT , `Publisher` VARCHAR(250) , `InternalNote` VARCHAR(250) , `DateOfPublishing` VARCHAR(250) , `ExternalNote` LONGTEXT , `Description` LONGTEXT , `Scrap` LONGTEXT , `SuppressionKey` CHAR(36) NOT NULL, `TypeKey` CHAR(36) NOT NULL, `CatalogueStatusKey` CHAR(36) NOT NULL, `CatalogueRevisedDate` DATETIME , `CatalogueRevisedByKey` CHAR(36) NOT NULL, `CatalogueToBeRevisedByKey` CHAR(36) NOT NULL, `DontInsure` BIT NOT NULL, `ExtraCosts` NUMERIC(19, 2) , `IsWebReady` BIT NOT NULL, `LocationKey` CHAR(36) NOT NULL, `LanguageKey` CHAR(36) NOT NULL, `CatalogueDescription` VARCHAR(250) , `PlacePublished` VARCHAR(250) , `ToDo` LONGTEXT , `Headline` VARCHAR(250) , `DepartmentKey` CHAR(36) NOT NULL, `Temp1` INT , `Temp2` INT , `Temp3` VARCHAR(250) , `Temp4` VARCHAR(250) , `InternetStatusKey` CHAR(36) NOT NULL, `InternetStatusInfo` LONGTEXT , `PurchaseKey` CHAR(36) NOT NULL, `ConsignmentKey` CHAR(36) , `IsSold` BIT NOT NULL, `RowCreated` DATETIME NOT NULL, `RowModified` DATETIME NOT NULL ); The SQL command and parameters to insert the record: INSERT INTO `RareItems_RareItems` (`RareItemKey`, `StockNumber_Text`, `StockNumber_Number`, `OurPercentage`, `SellPrice`, `Author`, `CatchWord`, `Title`, `Publisher`, `InternalNote`, `DateOfPublishing`, `ExternalNote`, `Description`, `Scrap`, `SuppressionKey`, `TypeKey`, `CatalogueStatusKey`, `CatalogueRevisedDate`, `CatalogueRevisedByKey`, `CatalogueToBeRevisedByKey`, `DontInsure`, `ExtraCosts`, `IsWebReady`, `LocationKey`, `LanguageKey`, `CatalogueDescription`, `PlacePublished`, `ToDo`, `Headline`, `DepartmentKey`, `Temp1`, `Temp2`, `Temp3`, `Temp4`, `InternetStatusKey`, `InternetStatusInfo`, `PurchaseKey`, `ConsignmentKey`, `IsSold`, `RowCreated`, `RowModified`) VALUES (@RareItemKey, @StockNumber_Text, @StockNumber_Number, @OurPercentage, @SellPrice, @Author, @CatchWord, @Title, @Publisher, @InternalNote, @DateOfPublishing, @ExternalNote, @Description, @Scrap, @SuppressionKey, @TypeKey, @CatalogueStatusKey, @CatalogueRevisedDate, @CatalogueRevisedByKey, @CatalogueToBeRevisedByKey, @DontInsure, @ExtraCosts, @IsWebReady, @LocationKey, @LanguageKey, @CatalogueDescription, @PlacePublished, @ToDo, @Headline, @DepartmentKey, @Temp1, @Temp2, @Temp3, @Temp4, @InternetStatusKey, @InternetStatusInfo, @PurchaseKey, @ConsignmentKey, @IsSold, @RowCreated, @RowModified) @RareItemKey = 0b625bd6-776d-43d6-9405-e97159d172a6 @StockNumber_Text = 199305 @StockNumber_Number = 26012 @OurPercentage = 22.5 @SellPrice = 1250 @Author = SPARRMAN, Anders. @CatchWord = COOK: SECOND VOYAGE @Title = A Voyage Round the World with Captain James Cook in H.M.S. Resolution… Introduction and notes by Owen Rutter, wood engravings by Peter Barker-Mill. @Publisher = @InternalNote = @DateOfPublishing = 1944 @ExternalNote = The first English translation of Sparrman’s narrative, which had originally been published in Sweden in 1802-1818, and the only complete version of his account to appear in English. The eighteenth-century translation had appeared some time before the Swedish publication of the final sections of his account. Sparrman’s observant and well-written narrative of the second voyage contains much that appears nowhere else, emphasising naturally his interests in medicine, health, and natural history.&lt;br&gt;&lt;br&gt;One of 350 numbered copies: a handsomely produced and beautifully illustrated work. @Description = Small folio, wood-engravings in the text; original olive glazed cloth, top edges gilt, a very good copy. London, Golden Cockerel Press, 1944. @Scrap = @SuppressionKey = 00000000-0000-0000-0000-000000000000 @TypeKey = 93f58155-7471-46ad-84c5-262ab9dd37e8 @CatalogueStatusKey = 00000000-0000-0000-0000-000000000003 @CatalogueRevisedDate = @CatalogueRevisedByKey = c4f6fc06-956d-44c4-b393-0d5462cbffec @CatalogueToBeRevisedByKey = 00000000-0000-0000-0000-000000000000 @DontInsure = False @ExtraCosts = @IsWebReady = False @LocationKey = 00000000-0000-0000-0000-000000000000 @LanguageKey = 00000000-0000-0000-0000-000000000000 @CatalogueDescription = @PlacePublished = Golden Cockerel Press @ToDo = @Headline = @DepartmentKey = 529578a3-9189-40de-b656-eef9039d00b8 @Temp1 = @Temp2 = @Temp3 = @Temp4 = v @InternetStatusKey = 00000000-0000-0000-0000-000000000000 @InternetStatusInfo = @PurchaseKey = 00000000-0000-0000-0000-000000000000 @ConsignmentKey = @IsSold = True @RowCreated = 8/04/2010 8:49:16 PM @RowModified = 8/04/2010 8:49:16 PM Suggestions on what is causing the error and/or how to track down what is causing the problem?

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  • MySQL access classes in PHP

    - by Mike
    I have a connection class for MySQL that looks like this: class MySQLConnect { private $connection; private static $instances = 0; function __construct() { if(MySQLConnect::$instances == 0) { //Connect to MySQL server $this->connection = mysql_connect(MySQLConfig::HOST, MySQLConfig::USER, MySQLConfig::PASS) or die("Error: Unable to connect to the MySQL Server."); MySQLConnect::$instances = 1; } else { $msg = "Close the existing instance of the MySQLConnector class."; die($msg); } } public function singleQuery($query, $databasename) { mysql_select_db(MySQLConfig::DB, $this->connection) or die("Error: Could not select database " . MySQLConfig::DB . " from the server."); $result = mysql_query($query) or die('Query failed.'); return $result; } public function createResultSet($query, $databasename) { $rs = new MySQLResultSet($query, MySQLConfig::DB, $this->connection ) ; return $rs; } public function close() { MySQLConnect::$instances = 0; if(isset($this->connection) ) { mysql_close($this->connection) ; unset($this->connection) ; } } public function __destruct() { $this->close(); } } The MySQLResultSet class looks like this: class MySQLResultSet implements Iterator { private $query; private $databasename; private $connection; private $result; private $currentRow; private $key = 0; private $valid; public function __construct($query, $databasename, $connection) { $this->query = $query; //Select the database $selectedDatabase = mysql_select_db($databasename, $connection) or die("Error: Could not select database " . $this->dbname . " from the server."); $this->result = mysql_query($this->query) or die('Query failed.'); $this->rewind(); } public function getResult() { return $this->result; } // public function getRow() // { // return mysql_fetch_row($this->result); // } public function getNumberRows() { return mysql_num_rows($this->result); } //current() returns the current row public function current() { return $this->currentRow; } //key() returns the current index public function key() { return $this->key; } //next() moves forward one index public function next() { if($this->currentRow = mysql_fetch_array($this->result) ) { $this->valid = true; $this->key++; }else{ $this->valid = false; } } //rewind() moves to the starting index public function rewind() { $this->key = 0; if(mysql_num_rows($this->result) > 0) { if(mysql_data_seek($this->result, 0) ) { $this->valid = true; $this->key = 0; $this->currentRow = mysql_fetch_array($this->result); } } else { $this->valid = false; } } //valid returns 1 if the current position is a valid array index //and 0 if it is not valid public function valid() { return $this->valid; } } The following class is an example of how I am accessing the database: class ImageCount { public function getCount() { $mysqlConnector = new MySQLConnect(); $query = "SELECT * FROM images;"; $resultSet = $mysqlConnector->createResultSet($query, MySQLConfig::DB); $mysqlConnector->close(); return $resultSet->getNumberRows(); } } I use the ImageCount class like this: if(!ImageCount::getCount()) { //Do something } Question: Is this an okay way to access the database? Could anybody recommend an alternative method if it is bad? Thank-you.

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  • Has anyone ever successfully make index merge work for MySQL?

    - by user198729
    Setup: mysql> create table t(a integer unsigned,b integer unsigned); mysql> insert into t(a,b) values (1,2),(1,3),(2,4); mysql> create index i_t_a on t(a); mysql> create index i_t_b on t(b); mysql> explain select * from t where a=1 or b=4; +----+-------------+-------+------+---------------+------+---------+------+------+-------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+-------+------+---------------+------+---------+------+------+-------------+ | 1 | SIMPLE | t | ALL | i_t_a,i_t_b | NULL | NULL | NULL | 3 | Using where | +----+-------------+-------+------+---------------+------+---------+------+------+-------------+ Is there something I'm missing? Update mysql> explain select * from t where a=1 or b=4; +----+-------------+-------+------+---------------+------+---------+------+------+-------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+-------+------+---------------+------+---------+------+------+-------------+ | 1 | SIMPLE | t | ALL | i_t_a,i_t_b | NULL | NULL | NULL | 1863 | Using where | +----+-------------+-------+------+---------------+------+---------+------+------+-------------+ Version: mysql> select version(); +----------------------+ | version() | +----------------------+ | 5.1.36-community-log | +----------------------+ Has anyone ever successfully make index merge work for MySQL? I'll be glad to see successful stories here:)

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  • PHP & MySQL database storing the name Array problem.

    - by comma
    I'm new to PHP & MySQL and I keep getting the word Array stored in my MySQL tables fields $skill, $experience, $yearsI was wondering how can I fix this problem? And I know I need to add mysqli_real_escape_string which I left out to make code more easier to read Hopefully. Here is the PHP & MySQL code. if (isset($_POST['info_submitted'])) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT learned_skills.*, users_skills.* FROM learned_skills INNER JOIN users_skills ON learned_skills.id = users_skills.skill_id WHERE user_id='$user_id'"); if (!$dbc) { print mysqli_error($mysqli); return; } $user_id = '5'; $skill = $_POST['skill']; $experience = $_POST['experience']; $years = $_POST['years']; if (isset($_POST['skill'][0]) && trim($_POST['skill'][0])!=='') { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT learned_skills.*, users_skills.* FROM learned_skills INNER JOIN users_skills ON users_skills.skill_id = learned_skills.id WHERE users_skills.user_id='$user_id'"); if (mysqli_num_rows($dbc) == 0) { for ($s = 0; $s < count($skill); $s++){ for ($x = 0; $x < count($experience); $x++){ for ($g = 0; $g < count($years); $g++){ $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $query1 = mysqli_query($mysqli,"INSERT INTO learned_skills (skill, experience, years) VALUES ('" . $s . "', '" . $x . "', '" . $g . "')"); $id = mysqli_insert_id($mysqli); if ($query1 == TRUE) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $query2 = mysqli_query($mysqli,"INSERT INTO users_skills (skill_id, user_id) VALUES ('$id', '$user_id')"); } } } } } } } Here is the XHTML code. <li><label for="skill">Skill: </label><input type="text" name="skill[0]" id="skill[0]" /> <label for="experience">Experience: </label> <?php echo '<select id="experience[0]" name="experience[0]">' . "\n"; foreach($experience_options as $option) { if ($option == $experience) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> <label for="years">Years: </label> <?php echo '<select id="years[0]" name="years[0]">' . "\n"; foreach($grade_options as $option) { if ($option == $years) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> </li>

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  • SQL SELECT: "Give me all documents where all of the documents procedures are 'work in progress'"

    - by prestonmarshall
    This one really has me stumped. I have a documents table which hold info about the documents, and a procedures table, which is kind of like a revisions table for each document. What I need to do is write a select statement which gives me all of the documents where all of the procedures have the status "work_in_progress". Here's an example procedures table: document_id | status 1 | 'wip' 1 | 'wip' 1 | 'wip' 1 | 'approved' 2 | 'wip' 2 | 'wip' 2 | 'wip' Here, I would want my query to only return document id 2, because all of its statuses are work_in_progress. I DO NOT want document_id 1 since one of its statuses is 'approved'. I believe this is relational division I want, but I'm not sure where to start. This is MySQL 5.0 FYI.

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  • I need to calculate the date / time difference between one date time column

    - by Stringz
    Details. I have the notes table having the following columns. ID - INT(3) Date - DateTime Note - VARCHAR(100) Tile - Varchar(100) UserName - Varchar(100) Now this table will be having NOTES along with the Titles entered by UserName on the specified date / time. I need to calculate the DateTimeDifference between the TWO ROWS in the SAME COLUMN For example the above table has this peice of information in the table. 64, '2010-03-26 18:16:13', 'Action History', 'sending to Level 2.', 'Salman Khwaja' 65, '2010-03-26 18:19:48', 'Assigned By', 'This is note one for the assignment of RF.', 'Salman Khwaja' 66, '2010-03-27 19:19:48', 'Assigned By', 'This is note one for the assignment of CRF.', 'Salman Khwaja' Now I need to have the following resultset in query reports using MYSQL. TASK - TIME Taken ACTION History - 2010-03-26 18:16:13 Assigned By - 00:03:35 Assigned By - 25:00:00 More smarter approach would be TASK - TIME Taken ACTION History - 2010-03-26 18:16:13 Assigned By - 3 minutes 35 seconds Assigned By - 1 day, 1 hour. I would appreciate if one could give me the PLAIN QUERY along with PHP code to embed it too.

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  • How to merge two tables based on common column and sort the results by date

    - by techiepark
    Hello friends, I have two mysql tables and i want to merge the results of these two tables based on the common column rev_id. The merged results should be sorted by the date of two tables. Please help me. CREATE TABLE `reply` ( `id` int(3) NOT NULL auto_increment, `name` varchar(25) NOT NULL default '', `member_id` varchar(45) NOT NULL, `rev_id` int(3) NOT NULL default '0', `description` text, `post_date` timestamp NOT NULL default CURRENT_TIMESTAMP on update CURRENT_TIMESTAMP, `flag` char(2) NOT NULL default 'N', PRIMARY KEY (`id`), KEY `member_id` (`member_id`) ) ENGINE=MyISAM; CREATE TABLE `comment` ( `com_id` int(8) NOT NULL auto_increment, `rev_id` int(5) NOT NULL default '0', `member_id` varchar(50) NOT NULL, `comm_desc` text NOT NULL, `date_created` timestamp NOT NULL default CURRENT_TIMESTAMP on update CURRENT_TIMESTAMP, PRIMARY KEY (`com_id`), KEY `member_id` (`member_id`) ) ENGINE=MyISAM;

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  • free sql script to get a list of countries, provinces/states and their cities.

    - by reggie
    I am working on a registration page for a php website as mysql as the backend database. I need a sql script to insert the list of countries with their associated provinces and the provinces with their associated cities. I need all the countries, provinces and cities all over the world which are related to each other. I can get the individual list of countries, provinces and cities but there is no list that relates them together.. any help appreciated.. thanks in advance.

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  • PDO update with conditional?

    - by dmontain
    I have a PDO mysql that updates 3 fields. $update = $mypdo->prepare("UPDATE tablename SET field1=:field1, field2=:field2, field3=:field3 WHERE key=:key"); But I want field3 to be updated only when $update3 = true; Is this possible to accomplish with a single query? I could do it with 2 queries where I update field1 and field2 then check the boolean and update field3 if needed in a separate query. But hopefully there is a way to accomplish this in 1 query?

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  • select random value from each type

    - by Joseph Mastey
    I have two tables, rating: +-----------+-----------+-------------+----------+ | rating_id | entity_id | rating_code | position | +-----------+-----------+-------------+----------+ | 1 | 1 | Quality | 0 | | 2 | 1 | Value | 0 | | 3 | 1 | Price | 0 | +-----------+-----------+-------------+----------+ And rating_option +-----------+-----------+------+-------+----------+ | option_id | rating_id | code | value | position | +-----------+-----------+------+-------+----------+ | 1 | 1 | 1 | 1 | 1 | | 2 | 1 | 2 | 2 | 2 | | 3 | 1 | 3 | 3 | 3 | | 4 | 1 | 4 | 4 | 4 | | 5 | 1 | 5 | 5 | 5 | | 6 | 2 | 1 | 1 | 1 | | 7 | 2 | 2 | 2 | 2 | | 8 | 2 | 3 | 3 | 3 | | 9 | 2 | 4 | 4 | 4 | | 10 | 2 | 5 | 5 | 5 | | 11 | 3 | 1 | 1 | 1 | | 12 | 3 | 2 | 2 | 2 | | 13 | 3 | 3 | 3 | 3 | | 14 | 3 | 4 | 4 | 4 | | 15 | 3 | 5 | 5 | 5 | +-----------+-----------+------+-------+----------+ I need a SQL query (not application level, must stay in the database) which will select a set of ratings randomly. A sample result would look like this, but would pick a random value for each rating_id on subsequent calls: +-----------+-----------+------+-------+----------+ | option_id | rating_id | code | value | position | +-----------+-----------+------+-------+----------+ | 1 | 1 | 1 | 1 | 1 | | 8 | 2 | 3 | 3 | 3 | | 15 | 3 | 5 | 5 | 5 | +-----------+-----------+------+-------+----------+ I'm totally stuck on the random part, and grouping by rating_id has been a crap shoot so far. Any MySQL ninjas want to take a stab? Thanks, Joe

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  • Is it possible to call a procedure within an SQL statement?

    - by darren
    Hi everyone I thought I would use a stored routine to clean up some of my more complex SQL statements. From what I've read, it seems impossible to use a stored procedure within an sql statement, and a stored function only returns a single value when what I need is a result set. I am using mySQL v5.0 SELECT p.`id`, gi.`id` FROM `sport`.`players` AS p JOIN `sport`.`gameinstances` AS gi ON p.`id` = gi.`playerid` WHERE (p.`playerid` IN (CALL findPlayers`("Canada", "2002"))) AND (gi.`instanceid` NOT IN (CALL findGameInstances`("Canada", "2002"))); For example, the procedures 'findPlayers' and 'findGameInstances' are are stored routines that execute some SQL and return a result set. I would prefer not to include their code directly within the statement above.

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  • Identifying which value of a multi-row inserts fails foreign key constraint

    - by Jonathan
    I have a multi-row insert that looks something like: insert into table VALUES (1, 2, 3), (4, 5, 6), (7, 8, 9); Assume the first attribute (1, 4, 7) is a foreign key to another table and assume that this referenced table does not have the value '4'. A MySQLExeption is thrown with error code 1452. EXCEPTION: Cannot add or update a child row: a foreign key constraint fails (dbName/tableName, CONSTRAINT id FOREIGN KEY (customer_id) REFERENCES referencedTable (customer_id)) Is there a way to identify which value caused the error? I would love to give my user an error message that said something like: Error: '4' does not exist in the referenced table. I am using the .NET mysql connector to execute the insert. Thanks- Jonathan

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  • PDO update query with conditional?

    - by dmontain
    I have a PDO mysql that updates 3 fields. $update = $mypdo->prepare("UPDATE tablename SET field1=:field1, field2=:field2, field3=:field3 WHERE key=:key"); But I want field3 to be updated only when $update3 = true; (meaning that the update of field3 is controlled by a conditional statement) Is this possible to accomplish with a single query? I could do it with 2 queries where I update field1 and field2 then check the boolean and update field3 if needed in a separate query. //run this query to update only fields 1 and 2 $update_part1 = $mypdo->prepare("UPDATE tablename SET field1=:field1, field2=:field2 WHERE key=:key"); //if field3 should be update, run a separate query to update it separately if ($update3){ $update_part2 = $mypdo->prepare("UPDATE tablename SET field3=:field3 WHERE key=:key"); } But hopefully there is a way to accomplish this in 1 query?

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  • Force 'Replace Into' to use a certain index

    - by Bobby
    I have a MySQL (5.0) table with 3 rows which are considered a combined Unique Index: CREATE TABLE `test`.`table_a` ( `Id` int(11) NOT NULL AUTO_INCREMENT, `field1` varchar(5) COLLATE latin1_swedish_ci NOT NULL DEFAULT '', `field2` varchar(5) COLLATE latin1_swedish_ci NOT NULL DEFAULT '', `field3` varchar(5) COLLATE latin1_swedish_ci NOT NULL DEFAULT '', PRIMARY KEY (`Id`), INDEX `IdxUnqiue` (`field1`(5),`field2`(5),`field3`(5)) ) ENGINE=MyISAM; This table should be filled with a REPLACE INTO query: REPLACE INTO table_a ( Field1, Field2, Field3 ) VALUES ( "Test1", "Test2", "Test3" ) The behavior I'd like to see is that this query always overrides the previous inserted row, because IdxUnique is...ahm, triggered. But unfortunately, there's still the primary index which seems to kick in and always inserts a new row. What I get: Query was executed 3 times: +---Id---+---Field1---+---Field2---+---Field3---+ | 1 | Test1 | Test2 | Test2 | | 2 | Test1 | Test2 | Test2 | | 3 | Test1 | Test2 | Test2 | +--------+------------+------------+------------+ What I want: Query was executed 3 times: +---Id---+---Field1---+---Field2---+---Field3---+ | 3 | Test1 | Test2 | Test2 | +--------+------------+------------+------------+ So, can I tell REPLACE INTO to use just a certain Index or to consider one 'more inportant' then another?

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