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  • Showing solution path in VS2008 window name

    - by Garry Shutler
    Is there a way to display the path of the solution in the Visual Studio window's name? By default it displays (SolutionName) - Microsoft Visual Studio, I would like it to instead show something like (SolutionName) - (PathToSolution) - Microsoft Visual Studio. The reason behind this is I can have multiple versions of a project checked out at a time (staging and trunk for example) and I'd like a quick way of checking without going through prompts etc.

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  • Exception: Need to specify class name in environment or system property: java.naming.factory.initial

    - by DanDan
    When i run a JMS related application, i am encountering the following exception error. javax.naming.NoInitialContextException: Need to specify class name in environment or system property, or as an applet parameter, or in an application resource file: java.naming.factory.initial We are using Sun Application Server 9.1 Any idea what are we missing? I already tried adding the following but result still the same Properties env = new Properties(); env.put("java.naming.factory.initial","com.sun.jndi.cosnaming.CNCtxFactory"); Context ctx = new InitialContext(env);

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  • Ensuring the contacts in a Distribution List are displayed with both name and email address

    - by hawbsl
    How can I ensure the contacts I add to an Outlook distribution list are displayed with both name and email address? These contacts may not exist in any other address book, just the distribution list. Currently they show up just as an email address (in both columns). Here's roughly the VBA we're using: Do Until RS.EOF //here's where we want to inject RS!FirstName, RS!Surname etc objRecipients.Add RS!Email objRecipients.Resolve RS.MoveNext Loop Set objDistList = contactsFolder.Items.Add("IPM.DistList") objDistList.DLName = "Whatever" objDistList.AddMembers objRecipients objDistList.Save etc

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  • Scala: getting the name of the class the trait is mixed in

    - by Alexey Romanov
    Given an instance of a class, we can obviously return its name: trait MixedInClassDiscovery { val className = this.getClass.getName } class AClass extends MixedInClassDiscovery { ... this.className // returns "AClass" ... } But this way uses reflection, once for every instance of AClass. Can the same be done once for every class, instead? One solution which comes to mind is to mix it into companion objects instead of classes themselves.

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  • "incomplete universal character name" with stringWithUTF8String

    - by Nasser
    hi, when i try to convert form utf-8 string to NSString like so: NSString *s = [NSString stringWithUTF8String:"\U0627\U0644\U0641\U0631\U0646"]; NSLog(@"%@", s); i get the compile error: incomplete universal character name note that it sometime just works fine: NSString *UAE = [NSString stringWithUTF8String:"\U0627\U0644\U0641\U0631\U0646"]; NSLog(@"%@", UAE); and the output: ???????? so why is that happening? please help.

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  • Class Name in Windows Forms

    - by oliverikawood
    Hi, I wonder about dynamically changing of class name in .NET application. For example WindowsForms10.SysTreeView32.app.0.19fd5c7. The last string "19fd5c7" would change, but I don't know what makes it changing. Is it the version, the GUI modification, environment, OS or what? Thanks.

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  • check if a url has anything after the domain name

    - by raklos
    im using asp.net c#. I want to check if the current url has anything after the domain name. e.g for the if the current url www.example.com/ or www.example.com i want to set a bool to true. if it has anything after i want to set it to false. e.g. www.example.com/stuff should return false.

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  • How to "ping" a domain name?

    - by Jene
    Hi, In Code i want to validate a domain name. For example : " DomainName.com". How can i do that in C#. I worked on MSDN Solution. (Second Solution). But "PingCompletedCallback" is not getting executed. Thanx

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  • 'Scanner' does not name a type error in g++

    - by Max
    Hi. I'm trying to compile code in g++ and I get the following errors: In file included from scanner.hpp:8, from scanner.cpp:5: parser.hpp:14: error: ‘Scanner’ does not name a type parser.hpp:15: error: ‘Token’ does not name a type Here's my g++ command: g++ parser.cpp scanner.cpp -Wall Here's parser.hpp: #ifndef PARSER_HPP #define PARSER_HPP #include <string> #include <map> #include "scanner.hpp" using std::string; class Parser { // Member Variables private: Scanner lex; // Lexical analyzer Token look; // tracks the current lookahead token // Member Functions <some function declarations> }; #endif and here's scanner.hpp: #ifndef SCANNER_HPP #define SCANNER_HPP #include <iostream> #include <cctype> #include <string> #include <map> #include "parser.hpp" using std::string; using std::map; enum { // reserved words BOOL, ELSE, IF, TRUE, WHILE, DO, FALSE, INT, VOID, // punctuation and operators LPAREN, RPAREN, LBRACK, RBRACK, LBRACE, RBRACE, SEMI, COMMA, PLUS, MINUS, TIMES, DIV, MOD, AND, OR, NOT, IS, ADDR, EQ, NE, LT, GT, LE, GE, // symbolic constants NUM, ID, ENDFILE, ERROR }; class Token { public: int tag; int value; string lexeme; Token() {tag = 0;} Token(int t) {tag = t;} }; class Num : public Token { public: Num(int v) {tag = NUM; value = v;} }; class Word : public Token { public: Word() {tag = 0; lexeme = "default";} Word(int t, string l) {tag = t; lexeme = l;} }; class Scanner { private: int line; // which line the compiler is currently on int depth; // how deep in the parse tree the compiler is map<string,Word> words; // list of reserved words and used identifiers // Member Functions public: Scanner(); Token scan(); string printTag(int); friend class Parser; }; #endif anyone see the problem? I feel like I'm missing something incredibly obvious.

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  • Get full name of an artifact in Maven

    - by Maurits Rijk
    I need to know the complete filename of a specific artifact in Maven. I looked at versions-maven-plugin but it seems to change the pom itself. Is there another way to reach my goal? I want to store the complete artifact name in a property so I can pick it up in Java code.

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  • How do I set a property in python using its string name

    - by dave
    Hey, here's a dumb question: how can I set an object property given its name in a string. I have a dictionary being passed to me and I wish to transfer its values into namesake properties using code like this: for entry in src_dict: if entry.startswith('can_'): tgt_obj[entry] = src_dict_profile[entry] I'm still a bit of a noob with Python so would appreciate some help. - dave.

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  • How to return string name of calling method?

    - by keruilin
    Right now my code works as such: def method_a self.method_b ==> 'method_b' end def method_b puts self.name_of_calling_method end def name_of_calling_method if /`(.*)'/.match(caller.first) return $1 else return nil end end Instead of method_b printing 'method_b', how can I print the name of the calling method - 'method_a'?

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  • How to parse the file name and rename in Matlab

    - by Paul
    I am reading a .xls file and then procesing it inside and rewriting it in the end of my program. I was wondering if someone can help me to parse the dates as my input file name is like file_1_2010_03_03.csv and i want my outputfile to be newfile_2010_03_03.xls is there a way to incorporate in matlab program so i do not have to manually write the command xlswrite('newfile_2010_03_03.xls', M); everytime and change the dates as i input files with diff dates like file_2_2010_03_04.csv. Thanks

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  • Display Phone number with network name

    - by user360530
    Hi Guys I have an idea, can u tel me what the procedure to do this? In my incoming calls r outgng cal it should display the phone number as wel as with network name For eg: 9876543210,Airtel like that How to do that i am new to android. So anybody help me. whats the way to develop it? Send me reply soon its very urgent

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  • Use the keyword class as a variable name in C++

    - by Leif Andersen
    I am having trouble writing C++ code that uses a header file designed for a C file. In particular, the header file used a variable name called class: int BPY_class_validate(const char *class_type, PyObject *class, PyObject *base_class, BPY_class_attr_check* class_attrs, PyObject **py_class_attrs); This works in C as class isn't taken as a keyword, but in C++, class is. So is there anyway I can #include this header file into a c++ file, or am I out of luck? Thank you.

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  • R: getting a function name as a string

    - by HamiltonUlmer
    Say I have a bunch of functions, each with something likeMyFunction.1, etc. I want to pass these functions into another function, which prints out a small report. Ideally I'd like to be able to label sections of a report by which function is being used to generate the results. So are there any nice ways of getting the name of a predefined function as a string?

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