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  • Addind link with existin href.

    - by Dom
    Hello gurus, Im trying to create link inside my list tag that will have href inherited from link that already exists in this list tag. Don't know how much sense does it makes, but i have this: <ul> <li><a href="page1.html">Support</a></li> <li><a href="page2.html">Products</a></li> <li><a href="page3.html">Management</a></li> <li><a href="page4.html">Others</a></li> </ul> and I need soothing like this: <ul> <li> <a href="page1.html">Support</a> <div class="slideLink"><a href="page1.html">Click Here</a></div> </li> <li> <a href="page2.html">Products</a> <div class="slideLink"><a href="page2.html">Click Here</a></div> </li> <li> <a href="page3.html">Management</a> <div class="slideLink"><a href="page3.html">Click Here</a></div> </li> <li> <a href="page4.html">Others</a> <div class="slideLink"><a href="page4.html">Click Here</a></div> </li> </ul> So far I have managed to add div with class and link within it with "click here" text, but i don't have a clue how to grab link href and add it to my new link. $('ul li a').each(function(){ $(this).after("<div class='slideLink'><a href=" + Link + ">Read more</div>"); }); Thank you for your help in advance. Best Regards Dom

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  • Prolog - generate correct bracketing

    - by Henrik Bak
    I'd like to get some help in the following exam problem, i have no idea how to do this: Input: a list of numbers, eg.: [1,2,3,4] Output: every possible correct bracketing. Eg.: (in case of input [1,2,3,4]): ((1 2) (3 4)) ((1 (2 3)) 4) (1 ((2 3) 4)) (1 (2 (3 4))) (((1 2) 3) 4) Bracketing here is like a method with two arguments, for example multiplication - then the output is the possible multiplication orders. Please help, i'm stuck with this one. Any help is appreciated, thanks!

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  • Take the intersection of an arbitrary number of lists in python

    - by thepandaatemyface
    Suppose I have a list of lists of elements which are all the same (i'll use ints in this example) [range(100)[::4], range(100)[::3], range(100)[::2], range(100)[::1]] What would be a nice and/or efficient way to take the intersection of these lists (so you would get every element that is in each of the lists)? For the example that would be: [0, 12, 24, 36, 48, 60, 72, 84, 96]

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  • embed youtube custom playlist name

    - by John Stockton
    I found a nice article: http://911-need-code-help.blogspot.com/2012/07/youtube-iframe-embeds-video-playlist-and-html5.html I am using the last option (Custom Playlist). But how to edit the embed code: <iframe width="560" height="315" src="http://www.youtube.com/embed/T0Jqdjbed40?playlist=SyoA4LXQco4,6l6PPvUhR4c" frameborder="0" allowfullscreen></iframe> in order to show my playlist name above thumbinails? i tried to add listname="name", name="name", list="name" but it don't work

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  • Java - PriorityQueue vs sorted LinkedList

    - by msr
    Hello, Which implementation is less "heavy": PriorityQueue or a sorted LinkedList (using a Comparator)? I want to have all the items sorted. The insertion will be very frequent and ocasionally I will have to run all the list to make some operations. Thank you!

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  • When to use LinkedList<> over ArrayList<>?

    - by sdellysse
    I've always been one to simply use List<String> names = new ArrayList<String>(); I use the interface as the type name for portability, so that when I ask questions such as these I can rework my code. When should LinkedList should be used over ArrayList and vice-versa?

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  • Generate a sequence of Fibonacci number in Scala

    - by qin
    def fibSeq(n: Int): List[Int] = { var ret = scala.collection.mutable.ListBuffer[Int](1, 2) while (ret(ret.length - 1) < n) { val temp = ret(ret.length - 1) + ret(ret.length - 2) if (temp >= n) { return ret.toList } ret += temp } ret.toList } So the above is my code to generate a Fibonacci sequence using Scala to a value n. I am wondering if there is a more elegant way to do this in Scala?

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  • LinkedList insert tied to inserted object

    - by wrongusername
    I have code that looks like this: public class Polynomial { List<Term> term = new LinkedList<Term>(); and it seems that whenever I do something like term.add(anotherTerm), with anotherTerm being... another Term object, it seems anotherTerm is referencing the same thing as what I've just inserted into term so that whenever I try to change anotherTerm, term.get(2) (let's say) get's changed too. How can I prevent this from happening?

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  • Data structure for an ordered set with many defined subsets; retrieve subsets in same order

    - by Aaron
    I'm looking for an efficient way of storing an ordered list/set of items where: The order of items in the master set changes rapidly (subsets maintain the master set's order) Many subsets can be defined and retrieved The number of members in the master set grow rapidly Members are added to and removed from subsets frequently Must allow for somewhat efficient merging of any number of subsets Performance would ideally be biased toward retrieval of the first N items of any subset (or merged subset), and storage would be in-memory (and maybe eventually persistent on disk)

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  • How to test an iPhone application update?

    - by sfkaos
    I already have an iPhone application (version 1.0) available in the App Store and am ready to submit a newer version (version 1.1). How do I test the new upgrade to make sure that the current sqlite database and property list files on the earlier version do not get deleted/overwritten etc? The new version assumes the old data in both the sqlite database and property lists remain. Or better yet, is there a resource I can use to walk me through what to watch for when developing an application update?

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  • Is it alright to call len() in a loop's conditional statement?

    - by DormoTheNord
    In C, it is considered bad practice to call strlen like this: for ( i = 0; strlen ( str ) != foo; i++ ) { // stuff } The reason, of course, is that it is inefficient since it "counts" the characters in a string multiple times. However, in Python, I see code like this quite often: for i in range ( 0, len ( list ) ): # stuff Is this bad practice? Should I store the result of len() in a variable and use that?

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  • How to extract List<int> from Dictionary<int, string>?

    - by DaveDev
    I have a method that takes a List<int>, which is a list of IDs. The source of my data is a Dictionary<int, string> where the integers are what I want a list of. Is there a better way to get this than the following code? var list = new List<int>(); foreach (var kvp in myDictionary) { list.Add(pair.Key); } ExecuteMyMethod(list);

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  • List<T> and IEnumerable difference

    - by Jonas Elfström
    While implementing this generic merge sort, as a kind of Code Kata, I stumbled on a difference between IEnumerable and List that I need help to figure out. Here's the MergeSort public class MergeSort<T> { public IEnumerable<T> Sort(IEnumerable<T> arr) { if (arr.Count() <= 1) return arr; int middle = arr.Count() / 2; var left = arr.Take(middle).ToList(); var right = arr.Skip(middle).ToList(); return Merge(Sort(left), Sort(right)); } private static IEnumerable<T> Merge(IEnumerable<T> left, IEnumerable<T> right) { var arrSorted = new List<T>(); while (left.Count() > 0 && right.Count() > 0) { if (Comparer<T>.Default.Compare(left.First(), right.First()) < 0) { arrSorted.Add(left.First()); left=left.Skip(1); } else { arrSorted.Add(right.First()); right=right.Skip(1); } } return arrSorted.Concat(left).Concat(right); } } If I remove the .ToList() on the left and right variables it fails to sort correctly. Do you see why? Example var ints = new List<int> { 5, 8, 2, 1, 7 }; var mergeSortInt = new MergeSort<int>(); var sortedInts = mergeSortInt.Sort(ints); With .ToList() [0]: 1 [1]: 2 [2]: 5 [3]: 7 [4]: 8 Without .ToList() [0]: 1 [1]: 2 [2]: 5 [3]: 7 [4]: 2 Edit It was my stupid test that got me. I tested it like this: var sortedInts = mergeSortInt.Sort(ints); ints.Sort(); if (Enumerable.SequenceEqual(ints, sortedInts)) Console.WriteLine("ints sorts ok"); just changing the first row to var sortedInts = mergeSortInt.Sort(ints).ToList(); removes the problem (and the lazy evaluation). EDIT 2010-12-29 I thought I would figure out just how the lazy evaluation messes things up here but I just don't get it. Remove the .ToList() in the Sort method above like this var left = arr.Take(middle); var right = arr.Skip(middle); then try this var ints = new List<int> { 5, 8, 2 }; var mergeSortInt = new MergeSort<int>(); var sortedInts = mergeSortInt.Sort(ints); ints.Sort(); if (Enumerable.SequenceEqual(ints, sortedInts)) Console.WriteLine("ints sorts ok"); When debugging You can see that before ints.Sort() a sortedInts.ToList() returns [0]: 2 [1]: 5 [2]: 8 but after ints.Sort() it returns [0]: 2 [1]: 5 [2]: 5 What is really happening here?

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  • Python: Improving long cumulative sum

    - by Bo102010
    I have a program that operates on a large set of experimental data. The data is stored as a list of objects that are instances of a class with the following attributes: time_point - the time of the sample cluster - the name of the cluster of nodes from which the sample was taken code - the name of the node from which the sample was taken qty1 = the value of the sample for the first quantity qty2 = the value of the sample for the second quantity I need to derive some values from the data set, grouped in three ways - once for the sample as a whole, once for each cluster of nodes, and once for each node. The values I need to derive depend on the (time sorted) cumulative sums of qty1 and qty2: the maximum value of the element-wise sum of the cumulative sums of qty1 and qty2, the time point at which that maximum value occurred, and the values of qty1 and qty2 at that time point. I came up with the following solution: dataset.sort(key=operator.attrgetter('time_point')) # For the whole set sys_qty1 = 0 sys_qty2 = 0 sys_combo = 0 sys_max = 0 # For the cluster grouping cluster_qty1 = defaultdict(int) cluster_qty2 = defaultdict(int) cluster_combo = defaultdict(int) cluster_max = defaultdict(int) cluster_peak = defaultdict(int) # For the node grouping node_qty1 = defaultdict(int) node_qty2 = defaultdict(int) node_combo = defaultdict(int) node_max = defaultdict(int) node_peak = defaultdict(int) for t in dataset: # For the whole system ###################################################### sys_qty1 += t.qty1 sys_qty2 += t.qty2 sys_combo = sys_qty1 + sys_qty2 if sys_combo > sys_max: sys_max = sys_combo # The Peak class is to record the time point and the cumulative quantities system_peak = Peak(time_point=t.time_point, qty1=sys_qty1, qty2=sys_qty2) # For the cluster grouping ################################################## cluster_qty1[t.cluster] += t.qty1 cluster_qty2[t.cluster] += t.qty2 cluster_combo[t.cluster] = cluster_qty1[t.cluster] + cluster_qty2[t.cluster] if cluster_combo[t.cluster] > cluster_max[t.cluster]: cluster_max[t.cluster] = cluster_combo[t.cluster] cluster_peak[t.cluster] = Peak(time_point=t.time_point, qty1=cluster_qty1[t.cluster], qty2=cluster_qty2[t.cluster]) # For the node grouping ##################################################### node_qty1[t.node] += t.qty1 node_qty2[t.node] += t.qty2 node_combo[t.node] = node_qty1[t.node] + node_qty2[t.node] if node_combo[t.node] > node_max[t.node]: node_max[t.node] = node_combo[t.node] node_peak[t.node] = Peak(time_point=t.time_point, qty1=node_qty1[t.node], qty2=node_qty2[t.node]) This produces the correct output, but I'm wondering if it can be made more readable/Pythonic, and/or faster/more scalable. The above is attractive in that it only loops through the (large) dataset once, but unattractive in that I've essentially copied/pasted three copies of the same algorithm. To avoid the copy/paste issues of the above, I tried this also: def find_peaks(level, dataset): def grouping(object, attr_name): if attr_name == 'system': return attr_name else: return object.__dict__[attrname] cuml_qty1 = defaultdict(int) cuml_qty2 = defaultdict(int) cuml_combo = defaultdict(int) level_max = defaultdict(int) level_peak = defaultdict(int) for t in dataset: cuml_qty1[grouping(t, level)] += t.qty1 cuml_qty2[grouping(t, level)] += t.qty2 cuml_combo[grouping(t, level)] = (cuml_qty1[grouping(t, level)] + cuml_qty2[grouping(t, level)]) if cuml_combo[grouping(t, level)] > level_max[grouping(t, level)]: level_max[grouping(t, level)] = cuml_combo[grouping(t, level)] level_peak[grouping(t, level)] = Peak(time_point=t.time_point, qty1=node_qty1[grouping(t, level)], qty2=node_qty2[grouping(t, level)]) return level_peak system_peak = find_peaks('system', dataset) cluster_peak = find_peaks('cluster', dataset) node_peak = find_peaks('node', dataset) For the (non-grouped) system-level calculations, I also came up with this, which is pretty: dataset.sort(key=operator.attrgetter('time_point')) def cuml_sum(seq): rseq = [] t = 0 for i in seq: t += i rseq.append(t) return rseq time_get = operator.attrgetter('time_point') q1_get = operator.attrgetter('qty1') q2_get = operator.attrgetter('qty2') timeline = [time_get(t) for t in dataset] cuml_qty1 = cuml_sum([q1_get(t) for t in dataset]) cuml_qty2 = cuml_sum([q2_get(t) for t in dataset]) cuml_combo = [q1 + q2 for q1, q2 in zip(cuml_qty1, cuml_qty2)] combo_max = max(cuml_combo) time_max = timeline.index(combo_max) q1_at_max = cuml_qty1.index(time_max) q2_at_max = cuml_qty2.index(time_max) However, despite this version's cool use of list comprehensions and zip(), it loops through the dataset three times just for the system-level calculations, and I can't think of a good way to do the cluster-level and node-level calaculations without doing something slow like: timeline = defaultdict(int) cuml_qty1 = defaultdict(int) #...etc. for c in cluster_list: timeline[c] = [time_get(t) for t in dataset if t.cluster == c] cuml_qty1[c] = [q1_get(t) for t in dataset if t.cluster == c] #...etc. Does anyone here at Stack Overflow have suggestions for improvements? The first snippet above runs well for my initial dataset (on the order of a million records), but later datasets will have more records and clusters/nodes, so scalability is a concern. This is my first non-trivial use of Python, and I want to make sure I'm taking proper advantage of the language (this is replacing a very convoluted set of SQL queries, and earlier versions of the Python version were essentially very ineffecient straight transalations of what that did). I don't normally do much programming, so I may be missing something elementary. Many thanks!

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  • Problem with jQuery plugin TinySort

    - by Volmar
    I'm trying to sort a list with the help of jQuery and the TinySort-plugin, and it works good but one thing is not working as i want. My Code is: <!doctype html> <html> <head> <meta charset="UTF-8" /> <title>TinySort problem</title> <script type="text/javascript" src="http://so.volmar.se/www/js/jquery.js"></script> <script type="text/javascript" src="http://so.volmar.se/www/js/jquery.tinysort.min.js"></script> <script type="text/javascript"> function pktsort(way){ if($("div#paket>ul>li.sortdiv>a#s_abc").text() == "A-S"){ $("div#paket>ul>li.sortdiv>a#s_abc").text("S-A"); $("div#paket ul li.sortable").tsort("",{place:"org",returns:true,order:"desc"}); }else{ $("div#paket>ul>li.sortdiv>a#s_abc").text("A-S"); $("div#paket ul li.sortable").tsort("",{place:"org",returns:true,order:"asc"}); } } </script> </head> <body> <div id="paket" title="Paket"> <ul class="rounded"> <li class="sortdiv">Sort: <a href="#" onclick="pktsort();" class="active_sort" id="s_abc">A-S</a></li> <li class="sortable">Almost Famous</li> <li class="sortable">Children of Men</li> <li class="sortable">Coeurs</li> <li class="sortable">Colossal Youth</li> <li class="sortable">Demonlover</li> <li class="sortable">Femme Fatale</li> <li class="sortable">I'm Not There</li> <li class="sortable">In the City of Sylvia</li> <li class="sortable">Into the Wild</li> <li class="sortable">Je rentre à la maison</li> <li class="sortable">King Kong</li> <li class="sortable">Little Miss Sunshine</li> <li class="sortable">Man on Wire</li> <li class="sortable">Milk</li> <li class="sortable">Monsters Inc.</li> <li class="sortable">My Winnipeg</li> <li class="sortable">Ne touchez pas la hache</li> <li class="sortable">Nói albinói</li> <li class="sortable">Regular Lovers</li> <li class="sortable">Shaun of the Dead</li> <li class="sortable">Silent Light</li> <li class="addmore"><b>This text is not supposed to move</b></li> </ul> </div> </body> </html> you can try it out at: http://www.volmar.se/list-prob.html MY PROBLEM IS: I don't want the <li class="addmore"> to move above all the <li class="sortable">-elements when i press the sort-link. i wan't it to always be in the bottom. you can find documentation of the TinySort plugin here. i've tried loads of combinations with place and returns propertys but i just can't get it right.

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  • Recursively created linked lists with a class, C++

    - by Jon Brant
    I'm using C++ to recursively make a hexagonal grid (using a multiply linked list style). I've got it set up to create neighboring tiles easily, but because I'm doing it recursively, I can only really create all 6 neighbors for a given tile. Obviously, this is causing duplicate tiles to be created and I'm trying to get rid of them in some way. Because I'm using a class, checking for null pointers doesn't seem to work. It's either failing to convert from my Tile class to and int, or somehow converting it but not doing it properly. I'm explicitly setting all pointers to NULL upon creation, and when I check to see if it still is, it says it's not even though I never touched it since initialization. Is there a specific way I'm supposed to do this? I can't even traverse the grid without NULLs of some kind Here's some of my relevant code. Yes, I know it's embarassing. Tile class header: class Tile { public: Tile(void); Tile(char *Filename); ~Tile(void); void show(void); bool LoadGLTextures(); void makeDisplayList(); void BindTexture(); void setFilename(char *newName); char Filename[100]; GLuint texture[2]; GLuint displayList; Tile *neighbor[6]; float xPos, yPos,zPos; };` Tile Initialization: Tile::Tile(void) { xPos=0.0f; yPos=0.0f; zPos=0.0f; glEnable(GL_DEPTH_TEST); strcpy(Filename, strcpy(Filename, "Data/BlueTile.bmp")); if(!BuildTexture(Filename, texture[0]))MessageBox(NULL,"Texture failed to load!","Crap!",MB_OK|MB_ICONASTERISK); for(int x=0;x<6;x++) { neighbor[x]=NULL; } } Creation of neighboring tiles: void MakeNeighbors(Tile *InputTile, int stacks) { for(int x=0;x<6;x++) { InputTile->neighbor[x]=new Tile();InputTile->neighbor[x]->xPos=0.0f;InputTile->neighbor[x]->yPos=0.0f;InputTile->zPos=float(stacks); } if(stacks) { for(int x=0;x<6;x++)MakeNeighbors(InputTile->neighbor[x],stacks-1); } } And finally, traversing the grid: void TraverseGrid(Tile *inputTile) { Tile *temp; for(int x=0;x<6;x++) if(inputTile->neighbor[x]) { temp=inputTile->neighbor[x]; temp->xPos=0.0f; TraverseGrid(temp); //MessageBox(NULL,"Not Null!","SHUTDOWN ERROR",MB_OK | MB_ICONINFORMATION); } } The key line is "if(inputTile-neighbor[x])" and whether I make it "if(inputTile-neighbor[x]==NULL)" or whatever I do, it just isn't handling it properly. Oh and I'm also aware that I haven't set up the list fully. It's only one direction now.

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  • Sencha Touch 2 - Can't get list to display // or load a store? [UPDATED X2]

    - by Jordan
    I have been trying to get a list to display for quite a while now. I have tried all sorts of tips from various people without success. Now I am running into a new problem. I have taken the exact code from an example and I can't seem to get it to work either. First of all, here is the code. Station.js Ext.define('Syl.model.Station', { extend: 'Ext.data.Model', config: { fields: [ { name: 'id', type: 'string' }, { name: 'stop', type: 'string' } ] } }); Stations.js Ext.define('Syl.store.Stations', { extend : 'Ext.data.Store', requires: ['Syl.model.Station'], id: 'stations', xtype: 'stations', config : { model : 'Syl.model.Station', //storeId: 'stationsStore', autoLoad : true, //sorters: 'stop', /* proxy: { type: 'ajax', url: 'stations.json' }*/ data: [ { "id": "129", "stop": "NY Station" }, { "id": "13", "stop": "Newark Station" } ] } }); MyService.js Ext.define('Syl.view.MyService', { extend: 'Ext.Panel', xtype: 'stationsformPage', requires: [ 'Syl.store.Stations', 'Ext.form.FieldSet', 'Ext.field.Password', 'Ext.SegmentedButton', 'Ext.List' ], config: { fullscreen: true, layout: 'vbox', //iconCls: 'settings', //title: 'My Service', items: [ { docked: 'top', xtype: 'toolbar', title: 'My Service' }, { [OLDER CODE BEGIN] xtype: 'list', title: 'Stations', //store: 'Stations', store: stationStore, //UPDATED styleHtmlContent: true, itemTpl: '<div><strong>{stop}</strong> {id}</div>' [OLDER CODE END] [UPDATE X2 CODE BEGIN] xtype: 'container', layout: 'fit', flex: 10, items: [{ xtype: 'list', title: 'Stations', width: '100%', height: '100%', store: stationStore, styleHtmlContent: true, itemTpl: '<div><strong>{stop}</strong> {id}</div>' }] [UPDATE X2 CODE END] }, ] } }); app.js (edited down to the basics) var stationStore; //UPDATED Ext.application({ name: 'Syl', views: ['MyService'], store: ['Stations'], model: ['Station'], launch: function() { stationStore = Ext.create('Syl.store.Stations');//UPDATED var mainPanel = Ext.Viewport.add(Ext.create('Syl.view.MyService')); }, }); Okay, now when I run this in the browser, I get this error: "[WARN][Ext.dataview.List#applyStore] The specified Store cannot be found". The app runs but there is no list. I can't understand how this code could work for the people who gave the example and not me. Could it be a difference in the Sencha Touch version? I am using 2.0.1.1. To add to this, I have been having problems in general with lists not displaying. I had originally tried a stripped down list without even having a store. I tried to just set the data property in the list's config. I didn't get this error, but I also didn't get a list to display. That is why I thought I would try someone else's code. I figured if I could at least get a working list up and running, I could manipulate it into doing what I want. Any help would be greatly appreciated. Thanks. [UPDATED] Okay, so I did some more hunting and someone told me I needed to have an instance of my store to load into the list, not the store definition. So I updated the code as you can see and the error went away. The problem is that I still don't get a list. I have no errors at all, but I can't see a list. Am I not loading the data correctly? Or am I not putting the list in the view correctly? [UPDATED X2] Okay, so I learned that the list should be in a container and that I should give it a width and a height. I'm not totally sure on this being correct, but I do now have a list that I can drag up and down. The problem is there is still nothing in it. Anyone have a clue why?

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  • Android: List View Selected item -1

    - by Josemalive
    Hi, Im getting a -1 value when i try to get the selected item position on my listview that is already populated. list.setOnItemClickListener ( new AdapterView.OnItemClickListener() { public void onItemClick(AdapterView adapterView, View view,int arg2, long arg3) { int selectedPosition = adapterView.getSelectedItemPosition(); ShowAlert(String.valueOf(selectedPosition)); } } ); To fill my list view i use the following code: SimpleAdapter mSchedule = new SimpleAdapter( this, mylist, R.layout.listviewtest, new String[] {"test1", "test2", "test3"}, new int[] {R.id.TextView_websitename, R.id.TextView_keywords, R.id.TextView_backlink}); Any idea? Thanks in advance. Best Regards. Jose.

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