Search Results

Search found 22947 results on 918 pages for 'xml schema collection'.

Page 100/918 | < Previous Page | 96 97 98 99 100 101 102 103 104 105 106 107  | Next Page >

  • parsed xml file: skip creation if blank?

    - by GoodGets
    This could be a HappyMapper specific question, but I don't think so. In my app, users can upload their blog subscriptions (via an OPML file), which I parse and add to their profile. The only problem is during the parsing, or more specifically the creation of each subscription, I can't figure out how to skip over entries that are just "labels". Since OPML files allow you to label your blogs, or organize them into folders, this is my problem. The actual blog subscriptions and their labels both have "outline" tags. <outline text="Rails" > <outline title="Katz Got Your Tongue?" text="Katz Got Your Tongue?" htmlUrl="http://yehudakatz.com" type="rss" xmlUrl="http://feeds.feedburner.com/KatzGotYourTongue" /> After parsing, I create each feed via a method call inside of the HappyMapper module def create_feed Feed.new( :feed_htmlUrl => self.htmlUrl, :feed_title => self.title, ... But how do I prevent it from creating new "feeds" for those outline tags that are just tags? (i.e. those that don't have an htmlUrl?)

    Read the article

  • Getting XQuery [modify()]: Top-level attribute nodes are not supported error while modifying xml

    - by sam
    DECLARE @mycur CURSOR DECLARE @id int DECLARE @ParentNodeName varchar(max) DECLARE @NodeName varchar(max) DECLARE @NodeText varchar(max) SET @mycur = CURSOR FOR SELECT * FROM @temp OPEN @mycur FETCH NEXT FROM @mycur INTO @id,@ParentNodeName,@NodeName,@NodeText WHILE @@FETCH_STATUS = 0 BEGIN PRINT @id -- sample statements PRINT @ParentNodeName PRINT @NodeName SET @x.modify (' insert attribute status {sql:variable("@status")} as first into (/@ParentNodeName/@NodeName/child::*[position()=sql:variable("@status")])[1] ') FETCH NEXT FROM @mycur INTO @id,@ParentNodeName,@NodeName,@NodeText END DEALLOCATE @mycur Any idea why I am getting this error as query works fine if I manually insert path

    Read the article

  • Sending Illegal XML Characters in Soap Request

    - by SK
    I am trying to send special (&, ' (single quote)) characters in the Soap Request. I am using axis 1.4. The webservice client is in weblogic server and the webservice server is an ibm mainframe (COBOL program). The request data from the client contains special character (& symbol) which is converted to &amp; I tried to enclose it with CDATA as <![CDATA[Some Name & Some Data ]]> which got converted to &lt;![CDATA[Some Name &amp; Some Data]]&gt; The webservice client is generated from wsdl, so I couldn't use CDATA api to construct the request. I am able to set it as string value, and it is getting converted. Any help on this would be greatly appreciated. Please let me know if you need any more information on this.

    Read the article

  • @ in AndroidManifest.xml file

    - by C.W.Holeman II
    From the O'Reilly book "Android Application Development " by Rick Rogers, John Lombardo, Zigurd Mednieks & Blake Meike: page 23: <TextView android:layout_width="fill_parent" android:layout_height="wrap_content" android:text="@string/hello" /> page 44: <application android:icon="@drawable/icon2"> What is the meaning of the "@" in each of the above fragments?

    Read the article

  • How to unencode escaped XML with xQuery

    - by mbrevoort
    I have a variable in xQuery of type xs:string with the value of an encoded HTML snippet (the content of a twitter tweet). It looks like this: Headlines-Today &#8226; AP sources: &lt;b&gt;Obama&lt;/b&gt; pick for Justice post withdraws : News - Rest Of World - &lt;a href=&quot;http://shar.es/mqMAG&quot;&gt;http://shar.es/mqMAG&lt;/a&gt; When I try to write this out in an HTML block, I need the string to be unescaped so that the HTML snippet will be interpreted by the browser. Instead the string is getting written out as is and the browser is rendering it as just text (so you see <a href="blah.... ). Here's how I'm writing out this string: {$entry/atom:content/text()} How can I have the escaped characters unencoded so it writes < rather tha &lt; ? I've tried to do a replacelike this but it always replaces the &lt; with &lt; ! fn:replace($s, "&lt;", "<")

    Read the article

  • Simple XML variable returns "0"

    - by Warren Haskins
    Ok, so im working with tumblr's API and im using SimpleXMLElement with php and ive run into a problem. Basically, when I call on a variable it just prints a zero. for instance : <?php echo $data->posts->post[0]->photo-url[5]; ?> This just breaks the page, and when I leave out the [5] it just prints zero I want to echo the photo-url with the number [5] but I cant get my head around this and its killing me. I just dont understand why it wont work. Heres a sample of the simpleXMLElement print-out : SimpleXMLElement Object ( [@attributes] = Array ( [version] = 1.0 ) [posts] => SimpleXMLElement Object ( [@attributes] => Array ( [type] => photo ) [post] => Array ( [0] => SimpleXMLElement Object ( [@attributes] => Array ( [id] => 574166180 [url] => http://young-n-reckless.tumblr.com/post/574166180 [url-with-slug] => http://young-n-reckless.tumblr.com/post/574166180 [type] => photo [date-gmt] => 2010-05-05 19:52:46 GMT [date] => Wed, 05 May 2010 15:52:46 [unix-timestamp] => 1273089166 [format] => html [reblog-key] => vc9EfT7d [slug] => [tumblelog] => young-n-reckless [bookmarklet] => true ) [tumblelog] => SimpleXMLElement Object ( [@attributes] => Array ( [title] => Young & Reckless [name] => young-n-reckless [url] => http://young-n-reckless.tumblr.com/ [timezone] => US/Eastern [avatar-url-16] => http://24.media.tumblr.com/avatar_424f776dd55c_16.png [avatar-url-24] => http://24.media.tumblr.com/avatar_424f776dd55c_24.png [avatar-url-30] => http://24.media.tumblr.com/avatar_424f776dd55c_30.png [avatar-url-40] => http://25.media.tumblr.com/avatar_424f776dd55c_40.png [avatar-url-48] => http://24.media.tumblr.com/avatar_424f776dd55c_48.png [avatar-url-64] => http://26.media.tumblr.com/avatar_424f776dd55c_64.png [avatar-url-96] => http://25.media.tumblr.com/avatar_424f776dd55c_96.png [avatar-url-128] => http://24.media.tumblr.com/avatar_424f776dd55c_128.png [avatar-url-512] => http://29.media.tumblr.com/avatar_424f776dd55c_512.png ) ) [photo-link-url] => http://www.flickr.com/photos/katiemabey/3429588812/ [photo-url] => Array ( [0] => http://30.media.tumblr.com/tumblr_l1w1qd7Zcg1qatgoto1_500.jpg [1] => http://30.media.tumblr.com/tumblr_l1w1qd7Zcg1qatgoto1_500.jpg [2] => http://25.media.tumblr.com/tumblr_l1w1qd7Zcg1qatgoto1_400.jpg [3] => http://28.media.tumblr.com/tumblr_l1w1qd7Zcg1qatgoto1_250.jpg [4] => http://30.media.tumblr.com/tumblr_l1w1qd7Zcg1qatgoto1_100.jpg [5] => http://30.media.tumblr.com/tumblr_l1w1qd7Zcg1qatgoto1_75sq.jpg ) ) Any help would be greatly appreciated, and thanks in advance. Warren

    Read the article

  • Union with LINQ to XML

    - by Ryan Riley
    I need to union two sets of XElements into a single, unique set of elements. Using the .Union() extension method, I just get a "union all" instead of a union. Am I missing something? var elements = xDocument.Descendants(w + "sdt") .Union(otherDocument.Descendants(w + "sdt") .Select(sdt => new XElement( sdt.Element(w + "sdtPr") .Element(w + "tag") .Attribute(w + "val").Value, GetTextFromContentControl(sdt).Trim()) ) );

    Read the article

  • XML String into a DataGridView (C#)

    - by Justin Daniels
    I am currently working with a webservice to pull a report about users in a remote support system. After pulling my report and receiving the result, I am given the following string back by the method: <report><header><field id="0">Source</field><field id="1">Session ID</field><field id="2">Date</field><field id="3">Name</field><field id="24">Technician Name</field><field id="25">Technician ID</field></header><data><row><field id="0">Email</field><field id="1">55037806</field><field id="2">4/13/2010 2:28:06 AM</field><field id="3">Bill Gates</field><field id="24">John</field><field id="25">1821852</field></row><row><field id="0">Telephone</field><field id="1">55034548</field><field id="2">4/13/2010 12:59:44 AM</field><field id="3">Steve Jobs</field><field id="24">John</field><field id="25">1821852</field></row></data></report> After receiving this string, I need to take it and display the actual data in a datagridview. I've tried putting it into an XMLDocument then reading that, but it seems to keep failing. Just interested in another set of eyes :) Application is written in C# in VS2010.

    Read the article

  • Using two namespaces when defining a new xml file (XDocument, XElement, XAttribute)

    - by Manchuwook
    XNamespace xnRD = "http://schemas.microsoft.com/SQLServer/reporting/reportdesigner"; XNamespace xnNS = "http://schemas.microsoft.com/sqlserver/reporting/2008/01/reportdefinition"; XAttribute xaRD = new XAttribute(XNamespace.Xmlns + "rd", xnRD); XAttribute xaNS = new XAttribute("xmlns", xnNS); XElement x = new XElement("Report", xaRD, xaNS, new XElement("DataSources"), new XElement("DataSets"), new XElement("Body"), new XElement("Width"), new XElement("Page"), new XElement("ReportID", xaRD), new XElement("ReportUnitType", xaRD) ); XDocument doc = new XDocument(new XDeclaration("1.0", "utf-8", "yes")); doc.Add(x); Console.WriteLine(doc.ToString()); Results in runtime error: {"The prefix '' cannot be redefined from '' to 'http://schemas.microsoft.com/sqlserver/reporting/2008/01/reportdefinition' within the same start element tag."} What I am trying to do is just make the DataSources and DataSets write out to the Debug.Console to build ObjectDataSources since VS2010 neglected to add them for ASPX. EDIT: new XElement(xaRD + "ReportID"), new XElement(xaRD + "ReportUnitType") Changed and got : Additional information: The ':' character, hexadecimal value 0x3A, cannot be included in a name. Instead

    Read the article

  • replace xml element

    - by snorlaks
    Hello, Im doing something like that: var results = from d in myDocument.Elements().Descendants("myName") select d; foreach (var result in results){ if (sth...){ result.replace(myXElement); } } The problem is that when I replace an element I cant iterate to the next element cause there is null reference. (var result in results). Is there any other way to replace that element with another one and still be able to iterate through that document ? thanks for help

    Read the article

  • C# LINQ XML Query with duplicate element names that have attributes

    - by ncain187
    <Party id="Party_1"> <PartyTypeCode tc="1">Person</PartyTypeCode> <FullName>John Doe</FullName> <GovtID>123456789</GovtID> <GovtIDTC tc="1">Social Security Number US</GovtIDTC> <ResidenceState tc="35">New Jersey</ResidenceState> <Person> <FirstName>Frank</FirstName> <MiddleName>Roberts</MiddleName> <LastName>Madison</LastName> <Prefix>Dr.</Prefix> <Suffix>III</Suffix> <Gender tc="1">Male</Gender> <BirthDate>1974-01-01</BirthDate> <Age>35</Age> <Citizenship tc="1">United States of America</Citizenship> </Person> <Address> <AddressTypeCode tc="26">Bill Mailing</AddressTypeCode> <Line1>2400 Meadow Lane</Line1> <Line2></Line2> <Line3></Line3> <Line4></Line4> <City>Somerset</City> <AddressStateTC tc="35">New Jersey</AddressStateTC> <Zip>07457</Zip> <AddressCountryTC tc="1">United States of America</AddressCountryTC> </Address> </Party> <!-- *********************** --> <!-- Insured Information --> <!-- *********************** --> <Party id="Party_2"> <PartyTypeCode tc="1">Person</PartyTypeCode> <FullName>Dollie Robert Madison</FullName> <GovtID>123956239</GovtID> <GovtIDTC tc="1">Social Security Number US</GovtIDTC> <Person> <FirstName>Dollie</FirstName> <MiddleName>R</MiddleName> <LastName>Madison</LastName> <Suffix>III</Suffix> <Gender tc="2">Female</Gender> <BirthDate>1996-10-12</BirthDate> <Citizenship tc="1">United States of America</Citizenship> </Person> <!-- Insured Address --> <Address> <AddressTypeCode tc="26">Bill Mailing</AddressTypeCode> <Line1>2400 Meadow Lane</Line1> <City>Somerset</City> <AddressStateTC tc="35">New Jersey</AddressStateTC> <Zip>07457</Zip> <AddressCountryTC tc="1">United States of America</AddressCountryTC> </Address> <Risk> <!-- Disability Begin Effective Date --> <DisabilityEffectiveStartDate>2006-01-01</DisabilityEffectiveStartDate> <!-- Disability End Effective Date --> <DisabilityEffectiveStopDate>2008-01-01</DisabilityEffectiveStopDate> </Risk> </Party> <!-- ******************************* --> <!-- Company Information --> <!-- ****************************** --> <Party id="Party_3"> <PartyTypeCode tc="2">Organization</PartyTypeCode> <Organization> <DTCCMemberCode>1234</DTCCMemberCode> </Organization> <Carrier> <CarrierCode>105</CarrierCode> </Carrier> </Party> Here is my code which doesn't work because party 3 doesn't contain FullName, I know that partyelements contains 3 parties if I only return the name attribute. Is there a way to loop through each tag seperate? var partyElements = from party in xmlDoc.Descendants("Party") select new { Name = party.Attribute("id").Value, PartyTypeCode = party.Element("PartyTypeCode").Value, FullName = party.Element("FullName").Value, GovtID = party.Element("GovtID").Value, };

    Read the article

  • YAML, JSON, or XML to store items in a document database

    - by Zubair
    I am creating a document database and I have to decide on a structure for the records which will be represented as strings. The database has to be able to be read from and written to using as many languages as possible using stable libraries in an efficient way. What are the relavant issues I have to consider, and what would you suggest is the ideal format?

    Read the article

  • XML/XHTML replace content?

    - by Daveo
    I have a XHTML string I want to replace tags in for example <span tag="x">FOO</span> <span tag="y"> <b>bar</b> some random text <span>another span</span> </span> I want to be able to find tag="x" and replace FOO with my own content and find tag=y and replace all the inner content with by own content. What is the best way to do this? I am thinking regex is definitely out of the question. Can XPATH do this or is that just for searching can it do manipulation?

    Read the article

  • xml regular expression/regex OR operator

    - by Naz Haque
    Hi am trying to use a regeX to read through my document to identify currency types whether they're $,£ or a €. The regex I've created doesn't seem to work, somebody please advise me what it should be. I'd really appreciate the help: The regEX I've created ("\$|£|€]")is in a simpleType within my XSD file used for validating a document. The code is show after the colon, please note to display on stackoverflow I've had to remove the open/close tags (<): xs:simpleType name="currencyType" xs:restriction base="utf8-string" xs:length value="1" / xs:pattern value="[\$|£|€]"/ /xs:restriction /xs:simpleType

    Read the article

  • Dynamic Data Manipulation using XSLT from XML

    - by Imrul
    I am not working with XSLT not too long. I read that variable of XSLT can't be updated on the fly, so how can i do the following task. I want to sum up Purchase & Sales and put them into a variable, and make some decision according to these values. (For example, if Purchase is greater then sales then do something if not, do something else) <rows> <row> <col attr2="Purchase" >100.00</col> <col attr2="Sales" >100.00</col> </row> <row > <col attr2="Purchase" >19.16</col> <col attr2="Sales" >12.94</col> </row> <row > <col attr2="Purchase" >0.67</col> <col attr2="Sales" >2.74</col> </row> <row > <col attr2="Purchase" >71.95</col> <col attr2="Sales" >61.54</col> </row> <row > <col attr2="Purchase" >3.62</col> <col attr2="Sales" >14.72</col> </row> <row > <col attr2="Purchase">8.80</col> <col attr2="Sales">1.22</col> </row> <row > <col attr2="Purchase" >-4.28</col> <col attr2="Sales" >6.53</col> </row> </rows> if anyone knows, please help me.

    Read the article

  • I need a simple command line program to transform XML using XSLT

    - by fuzzy lollipop
    I am on OSX Snow Leopard (10.6.2) I can install anything I need to. I would preferably like a Python or Java solution. I have searched on Google and found lots of information on writing my own program to do this, but this is a just a quick and dirty experiment so I don't want to invest a lot of time on writing a bunch of code to do this, I am sure someone else has done this already.

    Read the article

  • Problems with creating XML with DOMDocument in PHP

    - by maralbjo
    The below code is fetched from php.net (http://docs.php.net/manual/en/domdocument.savexml.php). My problem is - it doesn't work. My only output from this is: "Saving all the document: Saving only the title part:". What am I missing here? $doc = new DOMDocument('1.0'); // we want a nice output $doc-formatOutput = true; $root = $doc-createElement('book'); $root = $doc-appendChild($root); $title = $doc-createElement('title'); $title = $root-appendChild($title); $text = $doc-createTextNode('This is the title'); $text = $title-appendChild($text); echo "Saving all the document:\n"; echo $doc-saveXML() . "\n"; echo "Saving only the title part:\n"; echo $doc-saveXML($title);

    Read the article

  • Jquery-ajax parse xml and set radiobutton

    - by haltman
    hi everybody, I've a form with some radio button like this: <input type="radio" name="leva" value="a"><input type="radio" name="leva" value="b"> with ajax post method I receive value of the radio. The question is how can I set correct radio value to checked? thanks in advance ciao h.

    Read the article

  • Regarding XML Parsing

    - by Anjan
    I am using IXMLDOMNodeListPtr , IXMLDOMNodePtr , IXMLDOMElementPtr and IXMLDOMDocPtr. I am having little confusion over here i.e. Should i have to call Release() on these pointers before they go out of scope. Thanks.

    Read the article

  • Modify xml element name in SQL Server

    - by sesame
    I want to change element name with following statement: SET @myDoc.modify('replace value of (/CustomerInfo)[1] with "Customer"') from <CustomerInfo>     <ID1</ID> </CustomerInfo> to <Customer>     <ID1</ID> </Customer> But failed. So how can i change it just in sql ?

    Read the article

< Previous Page | 96 97 98 99 100 101 102 103 104 105 106 107  | Next Page >