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  • Create rails record from two ids

    - by Michael Luby
    The functionality I'm trying to build allows Users to Visit a Restaurant. I have Users, Locations, and Restaurants models. Locations have many Restaurants. I've created a Visits model with user_id and restaurant_id attributes, and a visits_controller with create and destroy methods. Thing is, I can't create an actual Visit record. Any thoughts on how I can accomplish this? Or am I going about it the wrong way. Here's the code: Model: class Visit < ActiveRecord::Base attr_accessible :restaurant_id, :user_id belongs_to :user belongs_to :restaurant end View: <% @restaurants.each do |restaurant| %> <%= link_to 'Visit', location_restaurant_visits_path(current_user.id, restaurant.id), method: :create %> <% @visit = Visit.find_by_user_id_and_restaurant_id(current_user.id, restaurant.id) %> <%= @visit != nil ? "true" : "false" %> <% end %> Controller: class VisitsController < ApplicationController before_filter :find_restaurant before_filter :find_user def create @visit = Visit.create(params[:user_id => @user.id, :restaurant_id => @restaurant.id]) respond_to do |format| if @visit.save format.html { redirect_to location_restaurants_path(@location), notice: 'Visit created.' } format.json { render json: @visit, status: :created, location: @visit } else format.html { render action: "new" } format.json { render json: @visit.errors, status: :unprocessable_entity } end end end def destroy @visit = Visit.find(params[:user_id => @user.id, :restaurant_id => @restaurant.id]) @restaurant.destroy respond_to do |format| format.html { redirect_to location_restaurants_path(@restaurant.location_id), notice: 'Unvisited.' } format.json { head :no_content } end end private def find_restaurant @restaurant = Restaurant.find(params[:restaurant_id]) end def find_user @user = current_user end end

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  • Unable to change two things about a single row in mysql with php

    - by user1624005
    Here's the code: $id = intval($_POST['id']); $score = "'" . $_POST['score'] . "'"; $shares = "'" . $_POST['shares'] . "'"; $conn = new PDO('mysql:host=localhost;dbname=news', 'root', ''); $stmt = $conn->prepare("UPDATE news SET 'shares' = :shares, 'score' = :score WHERE id = :id"); $stmt -> execute(array( 'shares' => $shares, 'score' => $score, 'id' => $id )); And it doesn't work. I am unsure as to how I would see the error that I assume mysql is giving somewhere, and I've tried everything I could think of. Using double quotes and adding the variables into the statement right away. Adding single quotes to shares and score. How am I supposed to be doing this?

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  • Normalization two types of customers into one table

    - by JDewzy
    I am trying to model a sales situation where you can sell to a person or to a business with a contact person. I cannot figure out the proper way to do this. It seems like 2 tables would be incorrect. But how do I model a Customer table that can be a business or a person? Would I just have a boolean for "business" and an additional "business_name" field that would default to Null. But then I have to do an if/then on the columns and that seems like poor design. Any advice, direction, or links is appreciated.

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  • match two data.frame

    - by Elb
    I have a situation like this: DF1 COL1 COL2 COL3 ... a b c b d b f e a g m f DF2 COL a b c d e f g h i l m n o I would like to match each column of DF1 with the only one column of DF2 and score how many occurrence of DF2 are in each column of DF1. How this can be done? Thanks in advance, E.

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  • How can I use UML to model a relationship between two classes, where one has functions exposed as friend to the other?

    - by user1796528
    I have a two classes: ------------ --------------- X Y ------------ --------------- relation ------------ ------------------ --------------- A() C() B() D() E() ------------ --------------- I want to inherit just these two functions from X class, where they are defined with the friend access modifier. My class will be: --------------- Y --------------- --------------- C() A() D() --------------- Y class uses some functions of X class namely A and D. How can I model this relationship in a UML class diagram?

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  • How to find collision detection side between two objects?

    - by user2362369
    I am using box2D and I have two objects, one is bouncy ball and the other one is block. I'd like to find which side of the block is collided with, so I can only make the ball bounce when it hits the top. I tried to implement many things like fixture data and by detecting position, using manifold but not get the accurate result. I also tried to calculate distance between two object but all went wrong.

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  • Why is my NTP controlled computer clock two minutes ahead?

    - by Martin Liversage
    The clock in my computer is configured to be synchronized using NTP. To verify this I have tried two NTP clients using various NTP servers. My computer and the NTP clients are in complete agreement about the current time even across a wide range of NTP servers. I also have a GPS and my national phone company provides an accurate clock available by calling a specific phone number. Both my GPS and the phone company agrees on the current time. However, my computer is almost precisely two minutes (or 1 minute and 59 seconds) ahead of what I believe to be the "real" current time where I live. Why is my computer two minutes ahead? I realize that synchronizing clocks using the internet may not be entirely accurate as there is latency, but two minutes is a very long time on the internet. Is NTP really two minutes ahead? I'm running Windows 7 and live in the time zone UTC+1, but I don't think that is important in understanding my problem.

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  • A GFX card with two DVI and one HDMI with audio?

    - by TomaszRykala
    I haven't upgraded my PC for a while nor kept up to date with pc hardware since 2007, but have recently come up with a requirement and I am wondering if I can solve it! Are there any graphics cards out there that have two DVIs and one HDMI output, with the HDMI supporting sound over it? Basically, I've got a two PC monitor setup, and both monitors are connected to the two DVI's of my GTX9800+. I want to upgrade my card to say, GTX 460, but can't find if there is such with two DVIs (for my monitors) and one HDMI with audio (for my TV). So I am wondering, if such solution possible at all? I noticed that there are some cards out there with two DVI's and one mini-HDMI, but they all say 'HDMI Output Yes x 1 (via DVI to HDMI adaptor x 1 )', which probably means that because of the DVI element, the audio won't work. Is this true? Such card is an exmaple: http://uk.asus.com/Graphics_Cards/NVIDIA_Series/ENGTX460_DirectCU2DI1GD5/#specifications Many thanks for your help!

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  • Ubuntu networking issue: two specific machines cannot browse web while connected to network at the same time.

    - by jensendarren
    I have setup a secure wireless network which works very well except for two laptops running Ubuntu 10.10 that can't access the Internet via a browser at the same time. They can both ping sites, wget sites, use skype but when using a browser the page never loads (in Firefox the status bar just sits there saying "Connecting" until it times out.) Here is what we have tried so far (nothing has fixed this issue): OpenDNS Restart networking services Using wired connection rather than wireless Removing all other nodes from the network except the two machines that have this issue Swapped out the router Factory reset the router Reformatted one of the machines and re-installed Ubuntu 10.10 Other things that we have checked: The two machines can connect simultaneously without any issues to other wireless networks in different locations (say in an Internet Cafe or another office) The two machines have unique IP addresses The two machines have unique MAC addresses The two machines can communicate on the network using Skype, wget, ping etc We are not using a proxy on either machine FYI: I have attached output from wireshark. For the test we turned both machines on and pointed them both to the same website. The content loaded on one and not the other. Here is the output from wireshark- (speedyshare.com/files/26228631/machine_output_1 && speedyshare.com/files/26228649/machine2). As you can see the first one worked, the second one didn't. I don't fully understand the output and would appreciate if someone could shed some light on what might be causing this and how we can fix it! Many thanks! Darren

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  • Two graphical entities, smooth blending between them (e.g. asphalt and grass)

    - by Gabriel Conrad
    Supposedly in a scenario there are, among other things, a tarmac strip and a meadow. The tarmac has an asphalt texture and its model is a triangle strip long that might bifurcate at some point into other tinier strips, and suppose that the meadow is covered with grass. What can be done to make the two graphical entities seem less cut out from a photo and just pasted one on top of the other at the edges? To better understand the problem, picture a strip of asphalt and a plane covered with grass. The grass texture should also "enter" the tarmac strip a little bit at the edges (i.e. feathering effect). My ideas involve two approaches: put two textures on the tarmac entity, but that involves a serious restriction in how the strip is modeled and its texture coordinates are mapped or try and apply a post-processing filter that mimics a bloom effect where "grass" is used instead of light. This could be a terrible failure to achieve correct results. So, is there a better or at least a more obvious way that's widely used in the game dev industry?

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  • How do I cluster strings based on a relation between two strings?

    - by Tom Wijsman
    If you don't know WEKA, you can try a theoretical answer. I don't need literal code/examples... I have a huge data set of strings in which I want to cluster the strings to find the most related ones, these could as well be seen as duplicate. I already have a set of couples of string for which I know that they are duplicate to each other, so, now I want to do some data mining on those two sets. The result I'm looking for is a system that would return me the possible most relevant couples of strings for which we don't know yet that they are duplicates, I believe that I need clustering for this, which type? Note that I want to base myself on word occurrence comparison, not on interpretation or meaning. Here is an example of two string of which we know they are duplicate (in our vision on them): The weather is really cold and it is raining. It is raining and the weather is really cold. Now, the following strings also exist (most to least relevant, ignoring stop words): Is the weather really that cold today? Rainy days are awful. I see the sunshine outside. The software would return the following two strings as most relevant, which aren't known to be duplicate: The weather is really cold and it is raining. Is the weather really that cold today? Then, I would mark that as duplicate or not duplicate and it would present me with another couple. How do I go to implement this in the most efficient way that I can apply to a large data set?

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  • [Rails3] How to do multiple many to many relationships between the same two tables.

    - by Kurt
    Hi. I have a model of a club where I want to model the two entities Meeting and Member. There are actually two many-to-many relationships between these entities though, as for any meeting a Member can either be a Speaker or a Guest. Now I am an OO thinker, so would normally just create the two classes and each one would just have two arrays of the other inside, but rails is making me think a bit more data centric here, so I realise I need to break these M2M relationships up with join tables Speakers and Guests which I have done, but now I am having trouble describing the relationships in the models. The two join table models both have "belongs_to :meeting" and "belongs_to :member" and I think that should be sufficient. I am not however sure about the Meeting and Member models though. Each one has "has_many :guests" and "has_many: speakers" but I am not sure if I also want to go: has_many :members, :through = :guests has_many :members, :through = :speakers But I suspect that this is like declaring two "members" that will clash. I also thought about: has_many :guests, :through = :guests has_many :speakers, :through = :speakers Does that make sense? How would ActiveRecord know that they are in fact Members? I have found heaps of examples of polymorphic m2m relationships and m2m relationships where 1 table references itself, but no good examples to help me mode this situation where two separate tables have two different m2m relationships. Anyone got any tips?

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  • Recovering data from failed Raid configuration with 4 drives and two raid sets (Asus P6T / Intel ICH10r)

    - by user56365
    I've added the complete detailed version for my question below for those who can help, but want to quickly summarize my question first. I setup two Raid arrays using (4) WD Raptors, a striped set for the OS and 1+0 set for crucial data. After booting once out of the 50 times a cable fell out, the drive wasn't recognized in the array anymore. After trying to fix it, another drive did the same. I now have two drives remaining, luckily with the parity information. I know the striped set is gone, but I need the data on the other set. Can anyone recommend anything to recover the data, or fix the two drives that doesn't allow the raid controller to recognize the drives, even though they are listed on the utility screen as still apart of the configuration but that they are not found? More Details I recently upgraded to a ASUS P6T motherboard with an Intel ICH10R raid controller and changed my previous 4 drive raid array from strictly a Raid 1+0 set to a Raid 0 for the OS/Page/Scratch drive and a Raid 1+0 set for crucial data. I never had problems after upgrading with my configuration, even when a drive died and was replaced. I managed to rebuild the array fine. Unfortunately this time around, a cable came unattached and I booted my system up until the raid status screen with the degraded error. This shouldn't have been a problem, but after I attached the drive it was no longer recognized as a member in the array. Both drives actually show up as a non-member disk. I've spent a very, very long time online trying to find information or support and haven't had much luck. After spending time trying to scan the drive for errors, damaged partition info, etc.. another drive in the set decided it didn't want to be recognized as a part of the array. At this point, I have two out of the four drives still functioning, but the Raid 1+0 array went from degraded to failed and I must find a way to retrieve that data. I think the two drives still in the array have the parity information because they show up as OS (110GB),BACKUP(80GB) and OS:1(110GB),BACKUP(80GB) under windows data management. The other two are simply 74gb Raw unallocated Is it possible recover the data using those two drive only, and which tool would I use? Could it be a simple partition table or any other error that is repairable with hard drive utilities out there? I know the Raid 0 set is done for, but I would assume because the correct drives failed in a 1+0 config to save the data I can retrieve it some how.

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  • Why do I need two Instances in Windows Azure?

    - by BuckWoody
    Windows Azure as a Platform as a Service (PaaS) means that there are various components you can use in it to solve a problem: Compute “Roles” - Computers running an OS and optionally IIS - you can have more than one "Instance" of a given Role Storage - Blobs, Tables and Queues for Storage Other Services - Things like the Service Bus, Azure Connection Services, SQL Azure and Caching It’s important to understand that some of these services are Stateless and others maintain State. Stateless means (at least in this case) that a system might disappear from one physical location and appear elsewhere. You can think of this as a cashier at the front of a store. If you’re in line, a cashier might take his break, and another person might replace him. As long as the order proceeds, you as the customer aren’t really affected except for the few seconds it takes to change them out. The cashier function in this example is stateless. The Compute Role Instances in Windows Azure are Stateless. To upgrade hardware, because of a fault or many other reasons, a Compute Role's Instance might stop on one physical server, and another will pick it up. This is done through the controlling fabric that Windows Azure uses to manage the systems. It’s important to note that storage in Azure does maintain State. Your data will not simply disappear - it is maintained - in fact, it’s maintained three times in a single datacenter and all those copies are replicated to another for safety. Going back to our example, storage is similar to the cash register itself. Even though a cashier leaves, the record of your payment is maintained. So if a Compute Role Instance can disappear and re-appear, the things running on that first Instance would stop working. If you wrote your code in a Stateless way, then another Role Instance simply re-starts that transaction and keeps working, just like the other cashier in the example. But if you only have one Instance of a Role, then when the Role Instance is re-started, or when you need to upgrade your own code, you can face downtime, since there’s only one. That means you should deploy at least two of each Role Instance not only for scale to handle load, but so that the first “cashier” has someone to replace them when they disappear. It’s not just a good idea - to gain the Service Level Agreement (SLA) for our uptime in Azure it’s a requirement. We point this out right in the Management Portal when you deploy the application: (Click to enlarge) When you deploy a Role Instance you can also set the “Upgrade Domain”. Placing Roles on separate Upgrade Domains means that you have a continuous service whenever you upgrade (more on upgrades in another post) - the process looks like this for two Roles. This example covers the scenario for upgrade, so you have four roles total - One Web and one Worker running the "older" code, and one of each running the new code. In all those Roles you want at least two instances, and this example shows that you're covered for High Availability and upgrade paths: The take-away is this - always plan for forward-facing Roles to have at least two copies. For Worker Roles that do background processing, there are ways to architect around this number, but it does affect the SLA if you have only one.

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  • How to manage two video cards on a laptop that runs Ubuntu 10.10?

    - by Marc-François Cochaux-Laberge
    I have a laptop with two video cards. One ATI and on integrated Intel. On Windows, I can choose which video card I want to use. For example, I use the Intel card for normal use and for gaming, I switch to my ATI card for better performance, but a shorter battery life. In Ubuntu 10.10, only the Intel driver is installed, the ATI driver for my card doesn't work at all and there's heat coming out of my computer all the time, like when I'm playing video games on Windows. I think both cards are active, but only the Intel one is usefull. How can I solve this by making sure Ubuntu is aware of the two video cards and by disabling my ATI. Or may be I am all wrong about this?

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  • Google is not treating two Austrailian schools as separate sites when both are subdomains of qld.edu.au

    - by LuckySpoon
    My question relates to two websites, each of which is a "Calvary Christian College", however in two totally different locations and unrelated to each other entirely (except by name, and domain). All schools in the state are issued a .qld.edu.au, in this case calvary.qld.edu.au and calvarycc.qld.edu.au. Now what's interesting is that these domains are crossing each other in sitelinks for searches such as "calvary christian college townsville" (if you check the sitelinks 2/6 are to a different domain). I've put a demotion in for this ages ago (we control calvary.qld.edu.au), however we're seeing no change on the results page. I have been able to get the owners of calvarycc.qld.edu.au to submit demotions for our domain, which should go in sometime this week. What can we do to tell Google that these websites are not interchangeable, despite both appearing as "subdomains" of qld.edu.au. We can possibly open channels of communication with the administrators of qld.edu.au but will need to tell them what we need to change, and at this point I'm out of ideas.

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  • AdWords test with two different agencies - can I track their results without them being aware of each other

    - by Drew
    Currently going through a process of testing two AdWords ppc providers at the same time from two separate AdWords accounts. However they will require access to my GA account for linking and ecommerce tracking. Which means that they will be able to see each others results. I dont want this; Is it possible to set up GA so that; Company A only sees Adwords results associated to their AdWords management via GA Company B only sees Adwords results associated to their AdWords management via GA And each company never sees the other company's Adwords results? 100 positive karma points to anyone who can shed some light on this. Cheers.

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  • How to manage two video cards on a laptop (ATI and Intel)?

    - by Marc-François Cochaux-Laberge
    I have a laptop with two video cards. One ATI and on integrated Intel. On Windows, I can choose which video card I want to use. For example, I use the Intel card for normal use and for gaming, I switch to my ATI card for better performance, but a shorter battery life. In Ubuntu 10.10, only the Intel driver is installed, the ATI driver for my card doesn't work at all and there's heat coming out of my computer all the time, like when I'm playing video games on Windows. I think both cards are active, but only the Intel one is usefull. How can I solve this by making sure Ubuntu is aware of the two video cards and by disabling my ATI. Or may be I am all wrong about this?

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  • Is there a better way to have a two column website with header and footer, equal height columns and stretchy column widths? [closed]

    - by Seamus
    I wrote a website a while ago that is a little messy in how it does things. I used this CSS template and this equal height columns trick. I have not one but two container divs and I can't remember what they're doing. So I'm thinking of re structuring the thing from scratch, and possibly making use of the more "semantic" html5 tags like <nav> and so on at the same time. The question is: is there a better way to achieve a site structure with these properties: 2 equal height main columns (with widths as percentages of the available real estate, not explicitly stated) both a header and footer element that stretch the whole width of the total of the two main columns That allows the use of semantic html5 tags instead of meaningless divs

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  • Are two database trips reasonable for a login system?

    - by Randolph Potter
    I am designing a login system for a project, and have an issue about it requiring two trips to the database when a user logs in. User types in username and password Database is polled and password hash is retrieved for comparative purposes (first trip) Code tests hash against entered password (and salt), and if verified, resets the session ID New session ID and username are sent back to the database to write a row to the login table, and generate a login ID for that session. EDIT: I am using a random salt. Does this design make sense? Am I missing something? Is my concern about two trips unfounded? Comments and suggestions are welcome.

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  • How to detect and collide two elastic line segments?

    - by Tautrimas
    There are 4 moving physical nodes in 3D space. They are paired with two elastic line segments / strings (1 <- 2; 3 <- 4). Part I: How to detect the collision of two segments? Part II: On the moment of collision, fifth node is created at the intersection point and here you have the force-based graph. 5-th node (bend point) can slide among the strings as in a real world. Given the new coordinates of 4 nodes, how to calculate the position of the 5-th node on the next frame? I assume string force on the nodes to be F = -k * x where x is the string length. All I came up to is that the force between 5 and 1 equals 5 and 2 (the same with 3 and 4). What are the other properties?.

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