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  • find: missing argument to -exec

    - by Abs
    Hello all, I was helped out today with a command, but it doesn't seem to be working. This is the command: find /home/me/download/ -type f -name "*.rm" -exec ffmpeg -i {} -sameq {}.mp3 && rm {}\; The shell returns find: missing argument to `-exec' What I am basically trying to do is go through a directory recursively (if it has other directories) and run the ffmpeg command on the .rm file types and convert them to .mp3 file types. Once this is done, remove the .rm file that has just been converted. I appreciate any help on this.

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  • Detecting when a process has finished (but not exited)

    - by Egwor
    I have a program that's run in unix (that I have no control over) that when finished prints 'Completed successfully' but does not exit. I want to automatically detect when the process finishes (by checking the output of the command), so that I can kill the process and so that I can proceed do other activities. The complexity comes because I want to be able to run multiples of these scripts concurrently. (One activity I need to do requires the script to be called with various inputs, but each time the script runs it takes a while to return, and so I want to do them in parallel) Has anyone done something similar to this? I could redirect the stderr and stdout output of the command to a temporary file which has a random file name, then tail the file and pipe to grep for the end conditions (I.e. the certain log lines). The problem is, surely tail -f would keep running, and so it would never exit. Should I poll? If so, what's the best approach?

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  • Change -- to . for all files in a directory

    - by Larry
    Hello, I need to rename all the files in a directory. Some examples of the source filenames are: alpha--sometext.381928 comp--moretext.7294058 The resultant files would be renamed as: alpha.sometext.381928 comp.moretext.7294058 The number of characters before and after the -- is not consistant. The script needs to work on current installations of Ubuntu and FreeBSD. These are lean LAMP servers so only the necessary packages have been installed. Thanks

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  • List content of tar file or a directory only down to some level

    - by Tim
    I wonder how to list content of tar file only down to some level? I understand "tar tvf mytar.tar" will list all files, but sometimes I wish I can just see directories down to some level. Similarly for command "ls" how to control the level of subdirectories that will be displayed? By default, it will only show the direct subdirectories, but not further. Thanks and regards

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  • Linux: Find all symlinks of a given 'original' file? (reverse 'readlink')

    - by sdaau
    Hi all, Consider the following command line snippet: $ cd /tmp/ $ mkdir dirA $ mkdir dirB $ echo "the contents of the 'original' file" > orig.file $ ls -la orig.file -rw-r--r-- 1 $USER $USER 36 2010-12-26 00:57 orig.file # create symlinks in dirA and dirB that point to /tmp/orig.file: $ ln -s $(pwd)/orig.file $(pwd)/dirA/ $ ln -s $(pwd)/orig.file $(pwd)/dirB/lorig.file $ ls -la dirA/ dirB/ dirA/: total 44 drwxr-xr-x 2 $USER $USER 4096 2010-12-26 00:57 . drwxrwxrwt 20 root root 36864 2010-12-26 00:57 .. lrwxrwxrwx 1 $USER $USER 14 2010-12-26 00:57 orig.file -> /tmp/orig.file dirB/: total 44 drwxr-xr-x 2 $USER $USER 4096 2010-12-26 00:58 . drwxrwxrwt 20 root root 36864 2010-12-26 00:57 .. lrwxrwxrwx 1 $USER $USER 14 2010-12-26 00:58 lorig.file -> /tmp/orig.file At this point, I can use readling to see what is the 'original' (well, I guess the usual term here is either 'target' or 'source', but those in my mind can be opposite concepts as well, so I'll just call it 'original') file of the symlinks, i.e. $ readlink -f dirA/orig.file /tmp/orig.file $ readlink -f dirB/lorig.file /tmp/orig.file ... However, what I'd like to know is - is there a command I could run on the 'original' file, and find all the symlinks that point to it? In other words, something like (pseudo): $ getsymlinks /tmp/orig.file /tmp/dirA/orig.file /tmp/dirB/lorig.file Thanks in advance for any comments, Cheers!

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  • How to run command in the background and notify me via email when done

    - by Abs
    Hello all, I have the following command which will take ages to run (couple of hours). I would like to make it a background process and for it to send me an email when its done. For the cherry on the top, any errors it encountered should write to a text file when an error has occurred? find . -type f -name "*.rm" -exec ./rm2mp3.sh \{} \; -exec rm \{} \; How can I do this with my above command?

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  • Problem with cyrillic symbols in console

    - by woto
    Hi everyone, sorry for bad English. It's Ruby code. s = "???????" `touch #{s}` `cat #{s}` `cat < #{s}` Can anybody tell why it's code fails? With sh: cannot open ???????: No such file But thic code works fine s = "????????" `touch #{s}` `cat #{s}` `cat < #{s}` Problem is only when Russian symbol '?' in the word and with symobol '<' woto@woto-work:/tmp$ locale LANG=ru_RU.UTF-8 LC_CTYPE="ru_RU.UTF-8" LC_NUMERIC="ru_RU.UTF-8" LC_TIME="ru_RU.UTF-8" LC_COLLATE="ru_RU.UTF-8" LC_MONETARY="ru_RU.UTF-8" LC_MESSAGES="ru_RU.UTF-8" LC_PAPER="ru_RU.UTF-8" LC_NAME="ru_RU.UTF-8" LC_ADDRESS="ru_RU.UTF-8" LC_TELEPHONE="ru_RU.UTF-8" LC_MEASUREMENT="ru_RU.UTF-8" LC_IDENTIFICATION="ru_RU.UTF-8" LC_ALL= woto@woto-work:/tmp$ ruby -v ruby 1.8.7 (2010-01-10 patchlevel 249) [x86_64-linux] woto@woto-work:/tmp$ uname -a Linux woto-work 2.6.32-26-generic #48-Ubuntu SMP Wed Nov 24 10:14:11 UTC 2010 x86_64 GNU/Linux woto@woto-work:/tmp$ lsb_release -a No LSB modules are available. Distributor ID: Ubuntu Description: Ubuntu 10.04.1 LTS Release: 10.04 Codename: lucid

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  • Curl: How to insert value to a cookie?

    - by Crazy_Bash
    Ho to insert cookies value in curl? from firebug "request headers" i can see in the following "Cookie: PHPSESSID=gg792c2ktu6sch6n8q0udd94o0; was=1; uncheck2=1; uncheck3=1; uncheck4=1; uncheck5=0; hd=1; uncheck1=1" I have tried the following: curl http://site.com/ -s -L -b cookie.c -c cookie.c -d "was=1; uncheck2=1; uncheck3=1; uncheck4=1; uncheck5=0; hd=1; uncheck1=1" > comic and the only thing i see in cookie.c is PHPSESSID=gg792c2ktu6sch6n8q0udd94o0; was=1;

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  • How to perform an action when a remote (Http) file changed?

    - by ZeissS
    Hi, I want to create a script that checks an URL and perform an action (download + unzip) when the "Last-Modified" header of the remote file changed. I thought about fetching the header with curl but then I have to store it somewhere for each file and perform a date comparison. Does anyone have a different idea using (mostly) standard unix tools? thanks

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  • Linux How to print all the files with the same prefix after searching for them?

    - by Alyx
    I need to search through a directory which contains many sub directories, each which contain files. The files read as follows question1234_01, where 1234 are random digits and the suffix _01 is the number of messages that contain the prefix, meaning they are apart of the same continuing thread. find . -name 'quest*' | cut -d_ -f1 | awk '{print $1}' | uniq -c | sort -n example output: 1 quest1234 10 quest1523 This searches for all the files then sorts them in order. What I want to do is print all the files which end up having the most occurrences, in my example the one with 10 matches. So it should only output quest1523_01 - 11

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  • Make Tar + gzip ignore directory paths

    - by norm
    Anybody know if it is possible that when making a tar + gzip through 'tar c ...' command if the relative paths will be ignored upon expanding. e.g. tar cvf test.tgz foo ../../files/bar and then expanding the test.tgz with: tar xvf test.tgz gives a dir containing: foo files/bar i want the dir to contain the files foo bar is this possible?

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  • Improved technique to store a filename in a variable?

    - by SDGuero
    Greetings, I need to store the filename of a log into a variable so my script can perform some checks on the daily log files. These logs always have a different name because they have a timestamp in the name. Currently I'm using a hodge podged method that pipes an ls command to sed, sort, cut, and tail in order to get the name out. CRON_LOG=$(ls -1 $LOGS_DIR/fetch_cron_{true,false}_$CRON_DATE*.log 2> /dev/null | sed 's/^[^0-9][^0-9]*\([0-9][0-9]*\).*/\1 &/' | sort -n | cut -d ' ' -f2- | tail -1 ) UPDATE: $CRON_DATE is supplied as an argument to the script. It is the date (to the day) that the log was created on. Sometimes multiple logs will exist for the same day so I want this to get the most recent one. A typical filename is fetch_cron_false_031810090452.log I'm pretty sure I kluged this together from some stuff I found google a few months ago. it works now but I'm not really happy with the technique. I have some ideas about how to do this better but I have had great success on this site before and thought it might be best to refer to the stackoverflow gods first. All answers are greatly appreciated. Thanks, Ryan

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  • Find and replace date within a file

    - by user1629011
    My apologies if my title is not descriptive enough, I believe the following will be. I have 3 files which are just plain text, within each file, is a date Date: 2012-08-31 for example I would like to get a command/script to find this and update to the current date, but the date will be ever changing and may not be known going in (without viewing the contents of the file Knowing what the date is, its simple enough with sed, but how can I do this knowing the syntax of the line I want to modify, but not the specific values. ("Date: " at least is unchanging)

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  • Is it possible to get a graphical representation of gprof results?

    - by Werner
    Hi, I am interested in getting the profiling of some number crunching program. I compiled it with -g and -pg options and linked it and got it gmon.out. After reading the info (plain text) it looks a bit ugly. I wonder if there are some open source tools for getting a graphical representation of the 10 functions where the program spends the most of the time as well as a flux diagram. Thanks

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  • Getting input in system() function (Mac)

    - by Alex
    #include <iostream> using namespace std; int main() { short int enterVal; cout << "enter a number to say: " << endl; cin >> enterVal; system("say "%d"") << enterVal; return 0; } Is what I am currently trying. I want the user to enter a number and the system() function says it basically. The code above has an error which says " 'd' was not declared in this scope ". Thanks in advance.

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  • replace new lines with comas in shell

    - by mpapis
    I want to replace new lines in text with coma or space but do not change the last new line. I know of this question: How to replace new lines with tab characters - but it does produce an tab on end instead of new line. So far I have come with: awk 'NR>1{printf","} {printf $1} END{printf"\n"}' Is there an easier way to do this? This is not an assignment, I am just curious want to level up my scripting.

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  • How to get line count from variable (from MYSQL query)?

    - by Mint
    My problematic code: testMYSQL=`mysql -u $mysqlUser -p$mysqlPass -h $mysqlHost --skip-column-names --batch -D $mysqlDB -e "SELECT $select FROM $mysqlTable WHERE nameTXT='test';"` $testMYSQL now contains: test test test Then I do: TEST=$(echo $testMYSQL | wc -l) echo "$TEST" I would of thought that would work, but it doesn't, it returns 1 But if I put this into $testMYSQL: "test\ntest\ntest" it will say 3… Whats going on here? does MYSQL not use new lines? PS, I know I can use a for loop to loop though the lines then count up the lines that way, but I was hoping for a simpler solution like wc

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  • php/ssh2 script does not display the stdout to $stream

    - by kamal
    The following php script works for simple linux commands, like ps -ef , but when i use ./dstat -t -a , it seems to hang and i dont get the prompt back on my local machine. Kep in mind that all commands are executed over ssh on a remote host: <?php $target = time() . '_' . 'txt'; if($ssh = ssh2_connect('10.1.0.174', 22)) { if(ssh2_auth_password($ssh, 'root', 'kmoon77')) { //$stream = ssh2_exec($ssh, 'whoami'); $sCommand = 'dstat -a'; //$sCommand = 'ps -ef'; $stream = ssh2_exec($ssh, $sCommand); //$stream = ssh2_exec($ssh, 'pwd'); stream_set_blocking($stream, true); $data = ''; while($buffer = fread($stream, 4096)) { $data .= $buffer; } //fclose($stream); echo $data; // user } } ?>

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  • Removing a text block from a file : sed ?

    - by user555338
    Hi, Following an attack, I need to remove 4 lines of text added to .htaccess files in my site, and was thinking SED would be the way to go, but cannot see how in spire of many attempts. The added lines are RewriteEngine On RewriteCond %{HTTP_REFERER} ^http:// RewriteCond %{HTTP_REFERER} !%{HTTP_HOST} RewriteRule . http://targeturlhere.net/%{REMOTE_ADDR} I managed to create the script to remove added htaccess files containing those lines only, but for existing htaccess files in which that was appended I have to edit the file and cannot delete it. I cannot just remove line by line nor use "RewriteEngine On" as the start marker, as this instruction "RewriteEngine On" is sometimes legitimate elsewhere in the file. In most cases those lines are the last, but I guess in other files they could be in the middle, so I was trying to remove exactly that block - and have a script I could reuse in a similar case. (Edit: my 4 lines are below one another, no blank line in between but the editor here seems to either show no breakline, or one adding a blank line) Any hint or tip ? Thanks.

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