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  • Why do I get an extra newline in the middle of a UTF-8 character with XML::Parser?

    - by René Nyffenegger
    I encountered a problem dealing with UTF-8, XML and Perl. The following is the smallest piece of code and data in order to reproduce the problem. Here's an XML file that needs to be parsed: <?xml version="1.0" encoding="utf-8"?> <test> <words>???????????? ??????? ????????? ???? ???????????? ??????</words> <words>???????????? ??????? ????????? ???? ???????????? ??????</words> <words>???????????? ??????? ????????? ???? ???????????? ??????</words> [<words> .... </words> 148 times repeated] <words>???????????? ??????? ????????? ???? ???????????? ??????</words> <words>???????????? ??????? ????????? ???? ???????????? ??????</words> </test> The parsing is done with this perl script: use warnings; use strict; use XML::Parser; use Data::Dump; my $in_words = 0; my $xml_parser=new XML::Parser(Style=>'Stream'); $xml_parser->setHandlers ( Start => \&start_element, End => \&end_element, Char => \&character_data, Default => \&default); open OUT, '>out.txt'; binmode (OUT, ":utf8"); open XML, 'xml_test.xml' or die; $xml_parser->parse(*XML); close XML; close OUT; sub start_element { my($parseinst, $element, %attributes) = @_; if ($element eq 'words') { $in_words = 1; } else { $in_words = 0; } } sub end_element { my($parseinst, $element, %attributes) = @_; if ($element eq 'words') { $in_words = 0; } } sub default { # nothing to see here; } sub character_data { my($parseinst, $data) = @_; if ($in_words) { if ($in_words) { print OUT "$data\n"; } } } When the script is run, it produces the out.txt file. The problem is in this file on line 147. The 22th character (which in utf-8 consists of \xd6 \xb8) is split between the d6 and b8 with a new line. This should not happen. Now, I am interested if someone else has this problem or can reproduce it. And why I am getting this problem. I am running this script on Windows: C:\temp>perl -v This is perl, v5.10.0 built for MSWin32-x86-multi-thread (with 5 registered patches, see perl -V for more detail) Copyright 1987-2007, Larry Wall Binary build 1003 [285500] provided by ActiveState http://www.ActiveState.com Built May 13 2008 16:52:49

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  • DTD is prohibited in this XML document -- how to change permissions?

    - by frankadelic
    I am using a 3rd-party .NET component which requires an XML configuration file. I'm am using this in an ASP.NET application. I get an error when configure the XML with the following dtd: <!DOCTYPE prod-config SYSTEM "prod-config.dtd"> The error is as follows: For security reasons DTD is prohibited in this XML document. To enable DTD processing set the ProhibitDtd property on XmlReaderSettings to false and pass the settings into XmlReader.Create method. prod-config.dtd is sitting in the same directory as the XML config file. I don't have access to the component code to modify XmlReaderSettings, ProhibitDtd etc. Is there anotherway I can modify or tag the XML file to permit the DTD to be accessed? (FYI, the component is Oracle Coherence .NET client)

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  • View problem - how to show integer from activity in XML?

    - by Oliver Goossens
    Hi there, I started two days ago with android, gone through the hello android stuff and also started to read the Hello Android book, which is great. PROBLEM: I use in my app - VERY EASY APP- the XML output. So basically the main activity just tells the android to show the XML layout of main. But what if I have in the activity - code defined integer variable and I want this integer variable also be shown on the display? How do I PUSH the integer variable to the XML??? From main XML reference to other strings in XML is easy - @string/app_name ... but how do I use the integer variable from the activity? Please help Thank you Oliver

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  • What is the recommended toolchain for formatting XML DocBook?

    - by Jonathan Leffler
    I've seen Best tools for working with DocBook XML documents, but my question is slightly different. Which is the currently recommended formatting toolchain - as opposed to editing tool - for XML DocBook? In Eric Raymond's 'The Art of Unix Programming' from 2003 (an excellent book!), the suggestion is XML-FO (XML Formatting Objects), but I've since seen suggestions here that indicated that XML-FO is no longer under development (though I can no longer find that question on StackOverflow, so maybe it was erroneous). Assume I'm primarily interested in Unix/Linux (including MacOS X), but I wouldn't automatically ignore Windows-only solutions. Is Apache's FOP the best way to go? Are there any alternatives?

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  • How to get a non-XML output using JDOM XSLTransformer?

    - by Neil McF
    Hello, I have an XML file which I'd like to parse into a non-XML (text) file based on a XLST file. The code in both seem correct, and it works when testing manually, but I'm having a problem doing this programatically. I'm using JDOM's XSLTransformer class to apply the XSLT to the XML and it returns it in the format of a JDOM Document. The problem here is that I can't seem to access anything in the Document as it is not a proper XML file and I get a "java.lang.IllegalStateException: Root element not set" error. Is there a better way within Java to obtain a non-XML file as a result of XSLT?

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  • Why does IE prompt a security warning when viewing an XML file?

    - by Tav
    Opening an XML file in Internet explorer gives a security warning. IE has a nice collapsible tree view for viewing XML, but it's disabled by default and you get this scary error message about a potential security hole. http://www.leonmeijer.nl/archive/2008/04/27/106.aspx But why? How can simply viewing an XML file (not running any embedded macros in it or anything) possibly be a security hole? Sure, I get that running XSLT could potentially do some bad stuff, but we're not talking about executing anything. We're talking about viewing. Why can't IE simply display the XML file as text (plus with the collapsible tree viewer)? So why did they label this as a security hole? Can someone describe how simply viewing an XML document could be used as an attack document?

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  • How do I parse an XML file that's on a different web server?

    - by Tim
    I have a list of training dates saved into an XML file, and I have a little javascript file that parses all of the training dates and spits them out into a neatly formatted page. This solution was fine until we decided that we wanted another web-page on another sever to access the same XML file. Since I cannot use JavaScript to parse an XML file that's located on another server, I figured I'd just use an ASP script. However, when I run this following, I get a response that there are 0 nodes matching a value which should have several: <% Dim URL, objXML URL = "http://www.site.com/feed.xml" Set objXML = Server.CreateObject("MSXML2.DOMDocument.3.0") objXML.setProperty "ServerHTTPRequest", True objXML.async = False objXML.Load(URL) If objXML.parseError.errorCode <> 0 Then Response.Write(objXML.parseError.reason) Response.Write(objXML.parseError.errorCode) End If Response.Write(objXML.getElementsByTagName("era").length) %> My question is two-fold: Is there are a way I can use java-script to parse a remote XML file If not, why doesn't my code give me the proper response?

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  • Is there a way to avoid IE7 quirks mode while rendering XML + CSS?

    - by Steven Huwig
    I've got some DocBook documentation styled with a CSS xml-stylesheet declaration. It looks great in Firefox, but IE7 doesn't seem to understand the CSS child selectors (e.g. section > title { ... }). I think this is because IE is running in quirks mode to render this XML, and older versions of IE didn't support that CSS syntax at all. The pages I found on the web all seem to focus on HTML and XHTML doctypes and how IE will behave given various permutations of these values. I couldn't find any information about straight XML + CSS. Worse yet, it seems that random XML documents always end up in quirks mode, no matter what format or stylesheet directives they have. Is XML rendering in IE doomed to be IE5.5 compatible? Will I really have to rewrite my CSS?

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  • Is it possible to generate plain-old XML using Haml?

    - by lsdr
    I've been working on a piece of software where I need to generate a custom XML file to send back to a client application. The current solutions on Ruby/Rails world for generating XML files are slow, at best. Using builder or event Nokogiri, while have a nice syntax and are maintainable solutions, they consume too much time and processing. I definetly could go to ERB, which provides a good speed at the expense of building the whole XML by hand. HAML is a great tool, have a nice and straight-forward syntax and is fairly fast. But I'm struggling to build pure XML files using it. Which makes me wonder, is it possible at all? Does any one have some pointers to some code or docs showing how to do this, build a full, valid XML from HAML?

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  • How to append to an XML response an error attribute using Ruby on Rails 3?

    - by user502052
    I am trying to implement REST APIs, so in my RoR3 application I have XML responses. Before to pass to a consumer the XML, I wuold like to check if there are errors and, if so, send back a response with error messages. I read "Active Record Validations and Callbacks" guides on the RoR website, but it seems not work in my case. I extract from the database a resource doing @response = User.find_by_id(1) and I wuold like, if possible, to add error to it. Seeing some examples I have seen how to report errors in an XML file format.xml { render :xml => @response.errors } but how I can add append new errors to the @response? Maybe something like this: errors.add(:password, "is invalid")

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  • XML Processing on iPhone: What is the best option?

    - by gonso
    Hello Im building a new version of an iPhone application and Im wondering if I should review how my app communicates with the server. My iPhone client sends and receives XML over HTTP requests. To send the information I use ASIHTTPRequest framework. I "manually" build the XML request by appending strings. To parse the response Im using a NSXMLParser. My question is if I have better options to A) Create an XML string from a memory object. B) Create a memory object from the XML string. Is there anything like JAXB to marshal XML into object? Thanks Gonso

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  • How to Send and Receive XML request to another ASP classic page?

    - by SH
    I want to send an XML to another Asp Classic page on the same domain. i am using following code for sending XMl url = "http://localhost/api/xmlget.asp" information = "ColtTaylor100" Set xmlhttp = server.Createobject("MSXML2.ServerXMLHTTP") xmlhttp.Open "POST", url, false xmlhttp.setRequestHeader "Content-Type", "text/xml" xmlhttp.send information And i have setup xmlget.asp with following code to receive XML: Dim xmlDoc Dim userName set xmlDoc=Server.CreateObject("Microsoft.XMLDOM") xmlDoc.async="false" xmlDoc.load(Request) I run the code but do not see any reflection, how would i know? And if it is successful I want to know the xml and i dont know exact property to load from xmlDoc!

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  • Is there an existing tool for jsonp like fetching of xml in jquery?

    - by BearCode
    Hi, For a web service I'm developing I would like my embedded code (on the client's site) to fetch an xml file from my sever script which resides on my domain. As this is a cross-domain request I figured to use jsonp as it seems the de facto standard for such apis. However, for my application it would be easier for me to use xml instead of json. Now, I could of course convert my xml to json on the server and then back again to xml in the client's site javascript, but that seems unnecessarily cumbersome. What I really need is and xmlp solution, xml with padding. I tired googling but couldn't find a jquery plug-in that does that. Anyone knows a simple solution?

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  • AS3: How to get all XML-Nodes with a special attribute? (With sourch)

    - by insnet
    Hi there The Challenge: i d like to collect all nodes with the attribute "id". The Problem: The code doenst work with nested nodes. <?xml version="1.0" encoding="utf-8"?><contentmap><fonts id="fonts"> fonts/Arial.swf swf/library_main.swf private function onXMLLoader(event : Event) : void { _xml = _loader.getXML(event.target.url.url); var searchTerms : XMLList = _xml.*.(hasOwnProperty('@id')); if (searchTerms.length() 0 ) { _NodeArray = new Array(); _parseNode(searchTerms); } private function _parseNode(xml : XMLList) : void { for each (var node: XML in xml) { if(!node.hasSimpleContent()) { _parseNode(node.children()); } else { var nodeObject : Object = new Object(); nodeObject['value'] = node.text(); for each(var a:XML in node.@*) { var name : String = String(a.name()); nodeObject[name] = a.toXMLString(); } _NodeArray.push(nodeObject); } } }

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  • Running a WebLogic Portal (WLP) 10.3.4 Domain as a Windows Service

    - by user647124
    To start a WLP server as a Windows service it is simplest to make your own script based on the provided standard script located at WL_HOME\server\bin\installSvc.cmd. The standard script works fine for a plain WLS domain, but lacks some classpath and options necessary for WLP.Start by making a copy of the installSvc.cmd script and naming it something specific to your domain.Next, just under SETLOCAL you will find where WL_HOME is defined. Here you will add the definitions you would normally add in a script that later calls installSvc.cmd (as per the standard documentation). set DOMAIN_NAME=gnma_test_domainset USERDOMAIN_HOME=D:\my_test_domainset SERVER_NAME=AdminServerset WLS_USER=weblogicset WLS_PW=gnmaAdmin01set PRODUCTION_MODE=trueset MEM_ARGS=-Xms512m –Xmx512mset MW_HOME=C:\Oracle\Middleware Note: I had heard of people using this approach who had issues with the length of the command line. This may be due to their use of the default domain path. In the example above, I use a shorter path.At this point, edit the DOMAIN_HOME\bin\startWebLogic.cmd and set it to echo both the classpath and the options. Then start the domain and capture the output of those echoes, then shut the domain back down. Now REM out the existing CLASSPATH definition, then use the outputs you captured earlier to set the CLASSPATH and JAVA_OPTIONS like this: REM set CLASSPATH=%WEBLOGIC_CLASSPATH%;%CLASSPATH%; C:\Oracle\Middleware\wlportal_10.3\portal\lib\security\wsrp-security-providers.jarset CLASSPATH=%MW_HOME%\patch_wls1034\profiles\default\sys_manifest_classpath\weblogic_patch.jar;%MW_HOME%\patch_wlp1034\profiles\default\sys_manifest_classpath\weblogic_patch.jar;%MW_HOME%\patch_oepe1111\profiles\default\sys_manifest_classpath\weblogic_patch.jar;%MW_HOME%\patch_ocm1033\profiles\default\sys_manifest_classpath\weblogic_patch.jar;%MW_HOME%\JROCKI~1.1-3\lib\tools.jar;%WL_HOME%\server\lib\weblogic_sp.jar;%WL_HOME%\server\lib\weblogic.jar;%MW_HOME%\modules\features\weblogic.server.modules_10.3.4.0.jar;%WL_HOME%\server\lib\webservices.jar;%MW_HOME%\modules\ORGAPA~1.1/lib/ant-all.jar;%MW_HOME%\modules\NETSFA~1.0_1/lib/ant-contrib.jar;%WL_HOME%\common\derby\lib\derbyclient.jar;%WL_HOME%\server\lib\xqrl.jar;%WL_HOME%\server\lib\xquery.jar;%WL_HOME%\server\lib\binxml.jarset JAVA_OPTIONS= -Xverify:none -ea -da:com.bea... -da:javelin... -da:weblogic... -ea:com.bea.wli... -ea:com.bea.broker... -ea:com.bea.sbconsole... -Dplatform.home=%WL_HOME% -Dwls.home=%WL_HOME%\server -Dweblogic.home=%WL_HOME%\server -Dweblogic.wsee.bind.suppressDeployErrorMessage=true -Dweblogic.wsee.skip.async.response=true -Dweblogic.management.discover=true -Dwlw.iterativeDev=true -Dwlw.testConsole=true -Dwlw.logErrorsToConsole=true -Dweblogic.ext.dirs=%MW_HOME%\patch_wls1034\profiles\default\sysext_manifest_classpath;%MW_HOME%\patch_wlp1034\profiles\default\sysext_manifest_classpath;%MW_HOME%\patch_oepe1111\profiles\default\sysext_manifest_classpath;%MW_HOME%\patch_ocm1033\profiles\default\sysext_manifest_classpath;%MW_HOME%\wlportal_10.3\p13n\lib\system;%MW_HOME%\wlportal_10.3\light-portal\lib\system;%MW_HOME%\wlportal_10.3\portal\lib\system;%MW_HOME%\wlportal_10.3\info-mgmt\lib\system;%MW_HOME%\wlportal_10.3\analytics\lib\system;%MW_HOME%\wlportal_10.3\apps\lib\system;%MW_HOME%\wlportal_10.3\info-mgmt\deprecated\lib\system;%MW_HOME%\wlportal_10.3\content-mgmt\lib\system -Dweblogic.alternateTypesDirectory=%MW_HOME%\wlportal_10.3\portal\lib\securityAnd that's it. Looks really simple, but it took me quite some time to gather all the necessary pieces in order to make it work. Hopefully you find this before you went through half as much research.The example here uses a domain with only the Admin server and no managed servers. For a variety of reasons I only want the Admin server to be run as a service. The standard documentation along with the example above should allow you to expand this to include managed servers should you feel the need.

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  • Java XML Unmarshalling fails on ampersand (&amp;) using JAXB

    - by ryanprayogo
    I have the following XML: <?xml version="1.0" encoding="UTF-8"?> <details> ... <address1>Test&amp;Address</address1> ... </details> When I try to unmarshal it using JAXB, it throws the following exception: Caused by: org.xml.sax.SAXParseException: The reference to entity "Address" must end with the ';' delimiter. at org.apache.xerces.util.ErrorHandlerWrapper.createSAXParseException(Unknown Source) at org.apache.xerces.util.ErrorHandlerWrapper.fatalError(Unknown Source) at org.apache.xerces.impl.XMLErrorReporter.reportError(Unknown Source) at org.apache.xerces.impl.XMLErrorReporter.reportError(Unknown Source) at org.apache.xerces.impl.XMLScanner.reportFatalError(Unknown Source) at org.apache.xerces.impl.XMLDocumentFragmentScannerImpl.scanEntityReference(Unknown Source) at org.apache.xerces.impl.XMLDocumentFragmentScannerImpl$FragmentContentDispatcher.dispatch(Unknown Source) at org.apache.xerces.impl.XMLDocumentFragmentScannerImpl.scanDocument(Unknown Source) at org.apache.xerces.parsers.XML11Configuration.parse(Unknown Source) at org.apache.xerces.parsers.XML11Configuration.parse(Unknown Source) at org.apache.xerces.parsers.XMLParser.parse(Unknown Source) at org.apache.xerces.parsers.AbstractSAXParser.parse(Unknown Source) at org.apache.xerces.jaxp.SAXParserImpl$JAXPSAXParser.parse(Unknown Source) at com.sun.xml.bind.v2.runtime.unmarshaller.UnmarshallerImpl.unmarshal0(UnmarshallerImpl.java:194) But when I changed the &amp; in the XML to &apos;, it works. Looks like the problem is only with ampersand &amp; and I cannot understand why. The code to unmarshal is: JAXBContext context = JAXBContext.newInstance("some.package.name", this.getClass().getClassLoader()); Unmarshaller unmarshaller = context.createUnmarshaller(); obj = unmarshaller.unmarshal(new StringReader(xml)); Anyone have some insight?

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  • Is there a GUI that I can use to create XML documents based on my schema?

    - by David Conlisk
    Hi all, I want to create a simple graphical user interface to allow non-technical users to create an XML file without having to manually edit the XML source. Ideally I'd like a drag and drop interface, but failing that, anything really. The contents of the XML file are similar to an encoded flow chart of a binary tree, so maybe something like Visio, with a save as xml option? Here's a quick sample of the XML output that is required: <?xml version="1.0" encoding="utf-8"?> <steps> <step id="1" type="prompt"> <prompt> Welcome. </prompt> <next>1.1</next> </step> <step id="1.1" type="question"> <prompt> Do you have what you need? </prompt> <yes>1.2</yes> <no>1.1.1</no> </step> ... </steps> Are there any existing tools out there that you can recommend for this purpose? Ideally open-source or with a free personal license, but I'm interested in hearing about all options. Thanks, David

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  • What is the performance penalty of XML data type in SQL Server when compared to NVARCHAR(MAX)?

    - by Piotr Owsiak
    I have a DB that is going to keep log entries. One of the columns in the log table contains serialized (to XML) objects and a guy on my team proposed to go with XML data type rather than NVARCHAR(MAX). This table will have logs kept "forever" (archiving some very old entries may be considered in the future). I'm a little worried about the CPU overhead, but I'm even more worried that DB can grow faster (FoxyBOA from the referenced question got 70% bigger DB when using XML). I have read this question http://stackoverflow.com/questions/514827/microsoft-sql-server-2005-2008-xml-vs-text-varchar-data-type and it gave me some ideas but I am particulairly interrested in clarification on whether the DB size increases or decreases. Can you please share your insight/experiences in that matter. BTW. I don't currently have any need to depend on XML features within SQL Server (there's nearly zero advantage to me in the specific case). Ocasionally log entries will be extracted, but I prefer to handle the XML using .NET (either by writing a small client or using a function defined in a .NET assembly).

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  • How to parse large xml files on google app engine?

    - by Alon Carmel
    Hey, I have fairly large xml file 1mb in size that i host on s3. I need to parse that xml file into my app engine datastore entirely. I have written a simple DOM parser that works fine locally but online it reaches the 30sec error and stops. I tried lowering the xml parsing by downloading the xml file into a BLOB at first before the parser then parse the xml file from blob. problem is that blobs are limited to 1mb. so it fails. I have multiple inserts to the datastore which cause it to fail on 30 sec. i saw somewhere that they recommend using the Mapper class and save some exception where the process stopped but as i am a python n00b i cant figure out how to implement it on a DOM parser or an SAX one (please provide an example?) on how to use it. i'm pretty much doing a bad thing right now and i parse the xml using php outside the app engine and push the data via HTTP post to the app engine using a proprietary API which works fine but is stupid and makes me maintain two codes. can you please help me out?

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  • XSLT question, how to transform xml when I have xslt file stored, but object in mem?

    - by JL
    I have a function that takes 2 parameters : 1 = XML file, 2 = XSLT file, then performs a transformation and returns the resulting HTML. Here is the function: /// <summary> /// Will apply an XSLT style to any XML file and return the rendered HTML. /// </summary> /// <param name="xmlFileName"> /// The file name of the XML document. /// </param> /// <param name="xslFileName"> /// The file name of the XSL document. /// </param> /// <returns> /// The rendered HTML. /// </returns> public string TransformXml(string xmlFileName, string xslFileName) { var xtr = new XmlTextReader(xmlFileName) { WhitespaceHandling = WhitespaceHandling.None }; var xd = new XmlDocument(); xd.Load(xtr); var xslt = new System.Xml.Xsl.XslCompiledTransform(); xslt.Load(xslFileName); var stm = new MemoryStream(); xslt.Transform(xd, null, stm); stm.Position = 1; var sr = new StreamReader(stm); xtr.Close(); return sr.ReadToEnd(); } I want to change the function not to accept a file name, but rather a strongly typed object de-serialized (now in the form of a variable). Is this possible? So keep the xslt coming from a file, but the xml input should be a the serialized xml of the object I pass, and I want to do this without file system IO.

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  • Add namespace to XmlTextWriter using C#

    - by xml
    Hi, I have an serializeable class that his root is serizlized to XmlRootAttribute with namespace. I want to add additional namespace to this root elemt, how can i do it? adding XmlAttribute failed to compile. The code: [System.Xml.Serialization.XmlRootAttribute("Root", Namespace = "http://www.w3.org/2003/05/soap-envelope", IsNullable = false)] public class MyClass { [System.Xml.Serialization.XmlElement("...")] public ClassA A; [System.Xml.Serialization.XmlElement("..")] public ClassB b; } After the serialization i'm getting something like that: <Root xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns="http://www.w3.org/2003/05/soap-envelope"> <ClassA/> <ClassB/> </Envelope> I want to add to the rood additioanl namespace, e.g. i want the xml to be: <Root xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" **xmlns:tns="anotherXml"** xmlns="http://www.w3.org/2003/05/soap-envelope"> <ClassA/> <ClassB/> </Envelope> Any idea?

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