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  • Why is file sharing over internet still working, despite all firewall exceptions for filesharing being disabled?

    - by Triynko
    Every exception in my windows server firewall that starts with "File and Printer Sharing" is disabled (ordered by name, so that includes domain, public (active), and private profiles). The Network and Sharing Center's options for everything except password protected sharing are off. Why would I still be able to access a network share on that server via an address like "\\my.server.com\" over the internet? The firewall is on for all profiles and blocking incoming connections by default. A "netstat -an" command on the server reveals the share connection is occurring over port 445 (SMB). I restarted the client to ensure it was actually re-establishing a new connection successfully. Is the "Password protected sharing: On" option in Network and Sharing Center bypassing the firewall restrictions, or adding some other exception somewhere that I'm missing? EDIT: "Custom" rules are not the problem. It's the "built-in" rules for Terminal Services that was the problem. Can you believe port 445 (File Sharing Port) has to be wide open to the internet to use Terminal Services Licensing?)

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  • Create text file named after a cell containing other cell data

    - by user143041
    I tried using the code below for the Excel program on my `Mac Mini using the OS X Version 10.7.2 and it keeps saying Error due to file name / path: (The Excel file I am creating is going to be a template with my formulas and macros installed which will be used over and over). Sub CreateFile() Do While Not IsEmpty(ActiveCell.Offset(0, 1)) MyFile = ActiveCell.Value & ".txt" fnum = FreeFile() Open MyFile For Output As fnum Print #fnum, ActiveCell.Offset(0, 1) & " " & ActiveCell.Offset(0, 2) Close #fnum ActiveCell.Offset(1, 0).Select Loop End Sub What Im trying to do: 1st Objective I would like to have the following data to be used to create a text file. A:A is what I need the name of the file to be. B:2 is the content I need in the text file. So, A2 - "repair-video-game-Glassboro-NJ-08028.txt" is the file name and B2 to be the content in the file. Next, A3 is the file name and B3 is the content for the file, etc. ONCE the content reads what is in cell A16 and B16 (length will vary), the file creation should stop, if not then I can delete the additional files created. This sheet will never change. Is there a way to establish the excel macro to always go to this sheet instead of have to select it with the mouse to identify the starting point? 2nd Objective I would like to have the following data to be used to create a text file. A:1 is what I need the name of the file to be. B:B is the content I want in the file. So, A2 - is the file name "geo-sitemap.xml" and B:B to be the content in the file (ignore the .xml file extension in the photo). ONCE the content cell reads what is in cell "B16" (length will vary), the file creation should stop, if not then I can adjust the cells that have need content (formulated content you see in the image is preset for 500 rows). This sheet will never change. Is there a way to establish the excel macro to always go to this sheet instead of have to select it with the mouse to identify the starting point? I can Provide the content in the cells that are filled in by excel formulas that are not not to be included in the .txt files. It is ok if it is not possible. I can delete the extra cells that are not populated (based on the data sheet). Please let me know if you need any more additional information or clarity and I will be happy to provide it.

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  • /etc/hosts file for a multi-homed, multi-domain machine?

    - by threecheeseopera
    I have a server (debian) with two network interfaces that I would like to host multiple services and domains on; it is not entirely clear to me how the hosts file should be set up. Example: eth0, bound to WAN interface 1.2.3.4: mail.example.com www.example.com eth0:1, bound to WAN interface 1.2.3.5: www.other-domain.com eth1, bound to LAN 192.168.1.123: some-clever-hostname What should my hosts file look like? (including localhost,localhost.localdomain, etc.) Should I use DNS for some of these entries? Which ones? Thanks!

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  • pscp: how to copy a file from a windows machine to a non-home location on another windows machine?

    - by help
    I want to copy a file from C:\temp on MachineA to C:\final on MachineB. I tried to use the following command, but it gave me an error (permission denied): C:\PROGRA~1\putty\pscp.exe -i C:\PROGRA~1\cwRsync\home\rcadmin\.ssh\id_rsa_private.ppk [email protected]:C:\final\test.txt C:\temp\test.txt It turned out I can only access C:\users\direcpc in my source computer. So if I put the file in C:\users\direcpc\text.txt, then it would work: C:\PROGRA~1\putty\pscp.exe -i C:\PROGRA~1\cwRsync\home\rcadmin\.ssh\id_rsa_private.ppk [email protected]:/test.txt C:\temp\test.txt But I want to access any location on my source computer instead of just my user home directory, is there a way to do this?

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  • How to remove file permissions from an external hard drive?

    - by user2540416
    My macbook recently died and I am currently trying to figure out how to copy my data. What I did was, I took out the hard drive, put it in an enclosure and plugged it in to my other laptop that runs linux. The problem is, I cannot copy files from the hard drive due to file permissions. I tried to access the hard drive as root. But I still cannot copy files. How do I remove file permissions from the harddrive?

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  • How can I open a file as read-only from Windows Explorer?

    - by Daniel Daranas
    Is there an easy way to open a file as read-only from Windows Explorer? My inmediate interest is in a Microsoft Access file. I am doing some sanity checks in old MS Access databases and I see that their date is automatically updated when I open them. I don't like this, since it will look like all the old files have been modified today. I am working with Windows XP. Update: As Yoda said, "Do, or do not. There is no try." In my case, it was "do not". I ended up copying the entire (big) folder tree to MyDocuments, and then opening all the databases from there.

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  • SQL SERVER – FIX: ERROR Msg 5169, Level 16: FILEGROWTH cannot be greater than MAXSIZE for file

    - by pinaldave
    I am writing this blog post right after I resolve this error for one of the system. Recently one of the my friend who is expert in infrastructure as well private cloud was working on SQL Server installation. Please note he is seriously expert in what he does but he has never worked SQL Server before and have absolutely no experience with its installation. He was modifying database file and keep on getting following error. As soon as he saw me he asked me where is the maxfile size setting so he can change. Let us quickly re-create the scenario he was facing. Error Message: Msg 5169, Level 16, State 1, Line 1 FILEGROWTH cannot be greater than MAXSIZE for file ‘NewDB’. Creating Scenario: CREATE DATABASE [NewDB] ON PRIMARY (NAME = N'NewDB', FILENAME = N'D:\NewDB.mdf' , SIZE = 4096KB, FILEGROWTH = 1024KB, MAXSIZE = 4096KB) LOG ON (NAME = N'NewDB_log', FILENAME = N'D:\NewDB_log.ldf', SIZE = 1024KB, FILEGROWTH = 10%) GO Now let us see what exact command was creating error for him. USE [master] GO ALTER DATABASE [NewDB] MODIFY FILE ( NAME = N'NewDB', FILEGROWTH = 1024MB ) GO Workaround / Fix / Solution: The reason for the error is very simple. He was trying to modify the filegrowth to much higher value than the maximum file size specified for the database. There are two way we can fix it. Method 1: Reduces the filegrowth to lower value than maxsize of file USE [master] GO ALTER DATABASE [NewDB] MODIFY FILE ( NAME = N'NewDB', FILEGROWTH = 1024KB ) GO Method 2: Increase maxsize of file so it is greater than new filegrowth USE [master] GO ALTER DATABASE [NewDB] MODIFY FILE ( NAME = N'NewDB', FILEGROWTH = 1024MB, MAXSIZE = 4096MB) GO I think this blog post will help everybody who is facing similar issues. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Error Messages, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • Changing the BizTalk message output file name

    - by Bill Osuch
    By default, BizTalk creates the filename of the message dropped to a send port as %MessageID%, which is the unique identifier (GUID) of the message. What if you want to create your own filename? To start, create a simple schema, and a basic orchestration that will receive the message and send it right back out, like this: If you deploy this and wire up the ports, you can drop an xml file into your receive port and have it come out at your send port named something like {7A63CAF8-317B-49D5-871F-9FD57910C3A0}.xml. Now, we'll create a new message with a custom filename. First, create a new orchestration variable called NewFileName, of the type System.String. Next, create a second message using the same schema as the message you're receiving in the Receive shape. Now, drag a Construct Message shape to the orchestration. In the shape's properties, set Messages Constructed to be the new message you just created. Double click the Message Assignment shape (inside the Construct shape...) and paste in the following code: Message_2 = Message_1;   NewFileName = Message_1(FILE.ReceivedFileName); NewFileName = NewFileName.Replace(".xml","_"); NewFileName = NewFileName + "output_" + System.DateTime.Now.Year.ToString() + "-" + System.DateTime.Now.Month.ToString();   Message_2(FILE.ReceivedFileName) = NewFileName; Here we make a copy of the received message, get it's original file name (ReceivedFileName), replace its extension with an underscore, and date-stamp it. Finally, add a Send shape and a Port to the surface, and configure them to send the message you just created. You should wind up with an orchestration like this: Deploy it, and create a new send port. It should be just about identical to the first send port, except this time the file name will be "%SourceFileName%.xml" (without the quotes of course). Fire up the application, drop in a test file, and you should now get both the xml file named with a GUID, and a second file named something along the lines of "MySchemaTestFile_output_2011-6.xml".

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  • FileOpenPicker/FileSavePicker doesn't allow *.* wildcard file associations

    - by mbrit
    On Twitter, Matthias Jauernig commented that the FileOpenPicker and FileSavePicker doesn't allow *.* wildcard file associations. I was relaxed about this and wrote back that it was related to sandboxing implying it was a "good thing", however as Matthias commented back, perhaps it's not.In Metro-style the sandboxing works that if something gives you a file (e.g. the picker, or a share operation), you can access it regardless of where on the system. If you find the file yourself, you have to declare the type.The reason why I think it's related to sandboxing is because if you work with files programmatically you have to be explicit about the file types. This is to stop malware that you think is only interested in - say .PDF files, scanning and uploading any .EML files that it can find on the machine. It follows then on the pickers that restriction would continue. It allow's the retail store team to validate that an app is likely to behave itself. If it's an app that works with images, locking down the picker so that it can only access image file types makes sense.However Matthias mentioned that he has an app that should allow files of any arbitrary file. That fits more into the "if the user selects it, it must be OK" camp than the "programmatic scanning" camp. So now I'm left wondering why the picker doesn't allow any type to be selected.I think then maybe the decision comes down to simplicity. A lot of the decisions in Metro-style design relate to ideas about "zero intimidation". Allow the user to select any file is too much like Old Windows, and not enough like Reimagined Windows. What happens in Matthias's app if the user selects Explorer.exe as the file he or she wants to work with? I guess it's fine if you expect your user to know what they're doing (Old Windows), but not so fine if you're expecting a three year old to work with it (Reimagined Windows).

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  • BizTalk 2009 - Error when Testing Map with Flat File Source Schema

    - by StuartBrierley
    I have recently been creating some flat file schemas using the BizTalk Server 2009 Flat File Schema Wizard.  I have then been mapping these flat file schemas to a "normal" xml schema format. I have not previsouly had any cause to map flat files and ran into some trouble when testing the first of these flat file maps; with an instance of the flat file as the source it threw an XSL transform error: Test Map.btm: error btm1050: XSL transform error: Unable to write output instance to the following <file:///C:\Documents and Settings\sbrierley\Local Settings\Temp\_MapData\Test Mapping\Test Map_output.xml>. Data at the root level is invalid. Line 1, position 1. Due to the complexity of the map in question I decided to created a small test map using the same source and destination schemas to see if I could pinpoint the problem.  Although the source message instance vaildated correctly against the flat file schema, when I then tested this simplified map I got the same error. After a time of fruitless head scratching and some serious google time I figured out what the problem was. Looking at the map properties I noticed that I had the test map input set to "XML" - for a flat file instance this should be set to "native".

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  • Form File Upload with other TextBox Inputs + Creating Custom Form Action attribute

    - by Jonathan Stowell
    Hi All, I am attempting to create a form where a user is able to enter your typical form values textboxes etc, but also upload a file as part of the form submission. This is my View code it can be seen that the File upload is identified by the MCF id: <% using (Html.BeginForm("Create", "Problem", FormMethod.Post, new { id = "ProblemForm", enctype = "multipart/form-data" })) {%> <p> <label for="StudentEmail">Student Email (*)</label> <br /> <%= Html.TextBox("StudentEmail", Model.Problem.StudentEmail, new { size = "30", maxlength=26 })%> <%= Html.ValidationMessage("StudentEmail", "*") %> </p> <p> <label for="Type">Communication Type (*)</label> <br /> <%= Html.DropDownList("Type") %> <%= Html.ValidationMessage("Type", "*") %> </p> <p> <label for="ProblemDateTime">Problem Date (*)</label> <br /> <%= Html.TextBox("ProblemDateTime", String.Format("{0:d}", Model.Problem.ProblemDateTime), new { maxlength = 10 })%> <%= Html.ValidationMessage("ProblemDateTime", "*") %> </p> <p> <label for="ProblemCategory">Problem Category (* OR Problem Outline)</label> <br /> <%= Html.DropDownList("ProblemCategory", null, "Please Select...")%> <%= Html.ValidationMessage("ProblemCategory", "*")%> </p> <p> <label for="ProblemOutline">Problem Outline (* OR Problem Category)</label> <br /> <%= Html.TextArea("ProblemOutline", Model.Problem.ProblemOutline, 6, 75, new { maxlength = 255 })%> <%= Html.ValidationMessage("ProblemOutline", "*") %> </p> <p> <label for="MCF">Mitigating Circumstance Form</label> <br /> <input id="MCF" type="file" /> <%= Html.ValidationMessage("MCF", "*") %> </p> <p> <label for="MCL">Mitigating Circumstance Level</label> <br /> <%= Html.DropDownList("MCL") %> <%= Html.ValidationMessage("MCL", "*") %> </p> <p> <label for="AbsentFrom">Date Absent From</label> <br /> <%= Html.TextBox("AbsentFrom", String.Format("{0:d}", Model.Problem.AbsentFrom), new { maxlength = 10 })%> <%= Html.ValidationMessage("AbsentFrom", "*") %> </p> <p> <label for="AbsentUntil">Date Absent Until</label> <br /> <%= Html.TextBox("AbsentUntil", String.Format("{0:d}", Model.Problem.AbsentUntil), new { maxlength = 10 })%> <%= Html.ValidationMessage("AbsentUntil", "*") %> </p> <p> <label for="AssessmentID">Assessment Extension</label> <br /> <%= Html.DropDownList("AssessmentID") %> <%= Html.ValidationMessage("AssessmentID", "*") %> <%= Html.TextBox("DateUntil", String.Format("{0:d}", Model.AssessmentExtension.DateUntil), new { maxlength = 16 })%> <%= Html.ValidationMessage("DateUntil", "*") %> </p> <p> <label for="Details">Assessment Extension Details</label> <br /> <%= Html.TextArea("Details", Model.AssessmentExtension.Details, 6, 75, new { maxlength = 255 })%> <%= Html.ValidationMessage("Details", "*") %> </p> <p> <label for="RequestedFollowUp">Requested Follow Up</label> <br /> <%= Html.TextBox("RequestedFollowUp", String.Format("{0:d}", Model.Problem.RequestedFollowUp), new { maxlength = 16 })%> <%= Html.ValidationMessage("RequestedFollowUp", "*") %> </p> <p> <label for="StaffEmail">Staff</label> <br /> <%= Html.ListBox("StaffEmail", Model.StaffEmail, new { @class = "multiselect" })%> <%= Html.ValidationMessage("StaffEmail", "*")%> </p> <p> <input class="button" type="submit" value="Create Problem" /> </p> This is my controller code: [AcceptVerbs(HttpVerbs.Post)] public ActionResult Create(Problem problem, AssessmentExtension assessmentExtension, Staff staffMember, HttpPostedFileBase file, string[] StaffEmail) { if (ModelState.IsValid) { try { Student student = studentRepository.GetStudent(problem.StudentEmail); Staff currentUserStaffMember = staffRepository.GetStaffWindowsLogon(User.Identity.Name); var fileName = Path.Combine(Request.MapPath("~/App_Data"), Path.GetFileName(file.FileName)); file.SaveAs(@"C:\Temp\" + fileName); if (problem.RequestedFollowUp.HasValue) { String meetingName = student.FirstName + " " + student.LastName + " " + "Mitigating Circumstance Meeting"; OutlookAppointment outlookAppointment = new OutlookAppointment(currentUserStaffMember.Email, meetingName, (DateTime)problem.RequestedFollowUp, (DateTime)problem.RequestedFollowUp.Value.AddMinutes(30)); } problemRepository.Add(problem); problemRepository.Save(); if (assessmentExtension.DateUntil != null) { assessmentExtension.ProblemID = problem.ProblemID; assessmentExtensionRepository.Add(assessmentExtension); assessmentExtensionRepository.Save(); } ProblemPrivacy problemPrivacy = new ProblemPrivacy(); problemPrivacy.ProblemID = problem.ProblemID; problemPrivacy.StaffEmail = currentUserStaffMember.Email; problemPrivacyRepository.Add(problemPrivacy); if (StaffEmail != null) { for (int i = 0; i < StaffEmail.Length; i++) { ProblemPrivacy probPrivacy = new ProblemPrivacy(); probPrivacy.ProblemID = problem.ProblemID; probPrivacy.StaffEmail = StaffEmail[i]; problemPrivacyRepository.Add(probPrivacy); } } problemPrivacyRepository.Save(); return RedirectToAction("Details", "Student", new { id = student.Email }); } catch { ModelState.AddRuleViolations(problem.GetRuleViolations()); } } return View(new ProblemFormViewModel(problem, assessmentExtension, staffMember)); } This form was working correctly before I had to switch to using a non-AJAX file upload, this was due to an issue with Flash when enabling Windows Authentication which I need to use. It appears that when I submit the form the file is not sent and I am unsure as to why? I have also been unsuccessful in finding an example online where a file upload is used in conjunction with other input types. Another query I have is that for Create, and Edit operations I have used a PartialView for my forms to make my application have higher code reuse. The form action is normally generated by just using: Html.BeginForm() And this populates the action depending on which Url is being used Edit or Create. However when populating HTML attributes you have to provide a action and controller value to pass HTML attributes. using (Html.BeginForm("Create", "Problem", FormMethod.Post, new { id = "ProblemForm", enctype = "multipart/form-data" })) Is it possible to somehow populate the action and controller value depending on the URL to maintain code reuse? Thinking about it whilst typing this I could set two values in the original controller action request view data and then just populate the value using the viewdata values? Any help on these two issues would be appreciated, I'm new to asp.net mvc :-) Thanks, Jon

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  • How to obtain position in file (byte-position) from java scanner?

    - by september2010
    How to obtain a position in file (byte-position) from the java scanner? Scanner scanner = new Scanner(new File("file")); scanner.useDelimiter("abc"); scanner.hasNext(); String result = scanner.next(); and now: how to get the position of result in file (in bytes)? Using scanner.match().start() is not the answer, because it gives the position within internal buffer.

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  • 500 error using lighttpd, fastcgi and PHP on file upload

    - by Dan
    I have a server running lighttpd with fastcgi, and it appears to be working correctly. However when I try to upload a file using a form, I get a 500 Internal server error, along with the following in the logs: 2012-03-23 18:25:09: (mod_fastcgi.c.2566) unexpected end-of-file (perhaps the fastcgi process died): pid: 2755 socket: unix:/tmp/php-fastcgi-1.socket-0 2012-03-23 18:25:09: (mod_fastcgi.c.3354) response not received, request sent: 50437 on socket: unix:/tmp/php-fastcgi-1.socket-0 for /index.php?url=brand/manager, closing connection I've been looking around for a long while now trying to find a solution to the issue, but nothing I'm trying is working. My current fastcgi conf looks as follows: server.modules += ( "mod_fastcgi" ) fastcgi.server = ( ".php" => (( "socket" => "/tmp/php-fastcgi-1.socket", "bin-path" => "/usr/bin/php-cgi", "allow-x-send-file" => "enable", "max-procs" => 1, "broken-scriptfilename" => "enable" )) ) If anyone could suggest if there is anything wrong in the configuration it would be greatly appreciated, or any suggestion as to what I might do? As I say, it is only happening when trying to upload a file (the file in question being only 45k). Thanks, Dan

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  • Python: shutil.rmtree fails on Windows with 'Access is denied'

    - by Sridhar Ratnakumar
    In Python, when running shutil.rmtree over a folder that contains a read-only file, the following exception is printed: File "C:\Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\Python26\lib\shutil.py", line 221, in rmtree onerror(os.remove, fullname, sys.exc_info()) File "C:\Python26\lib\shutil.py", line 219, in rmtree os.remove(fullname) WindowsError: [Error 5] Access is denied: 'build\\tcl\\tcl8.5\\msgs\\af.msg' Looking in File Properties dialog I noticed that af.msg file is set to be read-only. So the question is: what is the simplest workaround/fix to get around this problem - given that my intention is to do an equivalent of rm -rf build/ but on Windows? (without having to use third-party tools like unxutils or cygwin - as this code is targeted to be run on a bare Windows install with Python 2.6 w/ PyWin32 installed)

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  • Extract wav file from video file

    - by Nikos Steiakakis
    I am developing an application in which I need to extract the audio from a video. The audio needs to be extracted in .wav format but I do not have a problem with the video format. Any format will do, as long as I can extract the audio in a wav file. Currently I am using Windows Media Player COM control in a windows form to play the videos, but any other embedded player will do as well. Any suggestions on how to do this? Thanks

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  • Locking behaviour is different via network shares

    - by MattH
    I have been trying to lock a file so that other cloned services cannot access the file. I then read the file, and then move the file when finished. The Move is allowed by using FileShare.Delete. However in later testing, we found that this approach does not work if we are looking at a network share. I appreciate my approach may not have been the best, but my specific question is: Why does the below demo work against the local file, but not against the network file? The more specific you can be the better, as I've found very little information in my searches that indicates network shares behave differently to local disks. string sourceFile = @"C:\TestFile.txt"; string localPath = @"C:\MyLocalFolder\TestFile.txt"; string networkPath = @"\\MyMachine\MyNetworkFolder\TestFile.txt"; File.WriteAllText(sourceFile, "Test data"); if (!File.Exists(localPath)) File.Copy(sourceFile, localPath); foreach (string path in new string[] { localPath, networkPath }) { using (FileStream fsLock = File.Open(path, FileMode.Open, FileAccess.ReadWrite, (FileShare.Read | FileShare.Delete))) { string target = path + ".out"; File.Move(path, target); //This is the point of failure, when working with networkPath if (File.Exists(target)) File.Delete(target); } if (!File.Exists(path)) File.Copy(sourceFile, path); }

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  • shutil.rmtree fails on Windows with 'Access is denied'

    - by Sridhar Ratnakumar
    In Python, when running shutil.rmtree over a folder that contains a read-only file, the following exception is printed: File "C:\ActivePython32Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\ActivePython32Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\ActivePython32Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\ActivePython32Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\ActivePython32Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\ActivePython32Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\ActivePython32Python26\lib\shutil.py", line 216, in rmtree rmtree(fullname, ignore_errors, onerror) File "C:\ActivePython32Python26\lib\shutil.py", line 221, in rmtree onerror(os.remove, fullname, sys.exc_info()) File "C:\ActivePython32Python26\lib\shutil.py", line 219, in rmtree os.remove(fullname) WindowsError: [Error 5] Access is denied: 'build\\pyhg_trunk-win32-x86-hgtip27\\image\\feature-core\\INSTALLDIR\\tcl\\tcl8.5\\msgs\\af.msg' Looking in File Properties dialog I noticed that af.msg file is set to be read-only. So the question is: what is the simplest workaround/fix to get around this problem - given that my intention is to do an equivalent of rm -rf build/ but on Windows? (without having to use unxutils or cygwin)

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  • Carrier Wave not completing upload to Rackspace Cloud Files

    - by Zack Fernandes
    Hello, I have been attempting to get file uploads to Rackspace Cloud Files online all night, and finally tried the Carrierwave Plugin. Although the plugin worked right away, when I tried viewing the file uploaded (an image) it was broken. Upon further testing, I found out that files would upload to Cloud Files, however were just a fraction of their original size. I can't seem to figure out what's worng, and any help would be greatly appreciated. My code is as follows. models\attachment.rb class Attachment < ActiveRecord::Base attr_accessible :title, :user_id, :file, :remote_file_url, :file_cache, :remove_file belongs_to :user mount_uploader :file, AttachmentUploader end uploaders\attachment_uploader.rb class AttachmentUploader < CarrierWave::Uploader::Base storage :cloud_files def store_dir "#{model.user_id}-#{model.id}" end end

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  • S3 Backup Memory Usage in Python

    - by danpalmer
    I currently use WebFaction for my hosting with the basic package that gives us 80MB of RAM. This is more than adequate for our needs at the moment, apart from our backups. We do our own backups to S3 once a day. The backup process is this: dump the database, tar.gz all the files into one backup named with the correct date of the backup, upload to S3 using the python library provided by Amazon. Unfortunately, it appears (although I don't know this for certain) that either my code for reading the file or the S3 code is loading the entire file in to memory. As the file is approximately 320MB (for today's backup) it is using about 320MB just for the backup. This causes WebFaction to quit all our processes meaning the backup doesn't happen and our site goes down. So this is the question: Is there any way to not load the whole file in to memory, or are there any other python S3 libraries that are much better with RAM usage. Ideally it needs to be about 60MB at the most! If this can't be done, how can I split the file and upload separate parts? Thanks for your help. This is the section of code (in my backup script) that caused the processes to be quit: filedata = open(filename, 'rb').read() content_type = mimetypes.guess_type(filename)[0] if not content_type: content_type = 'text/plain' print 'Uploading to S3...' response = connection.put(BUCKET_NAME, 'daily/%s' % filename, S3.S3Object(filedata), {'x-amz-acl': 'public-read', 'Content-Type': content_type})

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  • Alert show when extension of FileUpLoads are not allowed

    - by Vy Clarks
    I have a asp FileUpload control in my aspx page. And the code behind to check file's extension and then insert them into database: private string Write(HttpPostedFile file, string table) { string fileNameMain = Path.GetFileName(file.FileName); // check for the valid file extension string fileExtension = Path.GetExtension(fileNameMain).ToLower(); if (fileExtension.Equals(".pdf") || fileExtension.Equals(".doc")) { ...insert fileupload into database } else { LabelError.Text = "Extension of files are not allowed."; return null; } } With the code above, it checks the extension and then show the message "Extension of files are not allowed." in a LabelError if the fileupload is not allowed. Now, I'm required to do the "check-extension" in the other way: at the moment the client click and choose FileUpload, an alert show "Extension of files are not allowed.". I need a way to make an alert show at the momment the FileUpload choosed in browser. Help!!!!

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