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  • Sharing two SSL wildcard certificates in memory in nginx

    - by hvtilborg
    I have an nginx server running with two IP addresses, say 1.2.3.4 and 4.3.2.1. Besides there are two wildcard SSL certificates for *.example.net (i.e. wc1, pointing to 1.2.3.4) and *.sub.example.net (i.e. wc2, pointing to 4.3.2.1). The nginx docs mention that you can share a wildcard certificate between server instances like this: ssl_certificate wc1.crt; ssl_certificate_key wc1.key; server { listen 1.2.3.4:443; server_name www.example.net; ssl on; ... } server { listen 1.2.3.4:443; server_name test.example.net; ssl on; ... } However, I was wondering whether this same construct is possible to use with the second wildcard certificate too. Both domains have around 500 subdomains. Do they not get mixed up, since the ssl_certificate construct is now global?

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  • What is consuming memory?

    - by Milan Babuškov
    Feel free to change the question title. I have a VPS with standard LAMP stack and a busy website. Operating system is CentOS 5.5. Virtualization is done with VMWare. My server gets real slow about every 6 hours. Logging into it I see that 1.6GB of RAM is consumed. However, listing the active processes does not explain the problem. Can anyone make any sense of this? "free" shows this: total used free shared buffers cached Mem: 2059456 2049280 10176 0 14780 380968 -/+ buffers/cache: 1653532 405924 Swap: 2096472 96 2096376 While this is output of "ps": [root@vmi29 /]# ps aux USER PID %CPU %MEM VSZ RSS TTY STAT START TIME COMMAND root 1 0.0 0.0 10348 688 ? Rs Jun05 0:01 init [3] root 2 0.0 0.0 0 0 ? S< Jun05 0:00 [migration/0] root 3 0.0 0.0 0 0 ? SN Jun05 0:00 [ksoftirqd/0] root 4 0.0 0.0 0 0 ? S< Jun05 0:00 [migration/1] root 5 0.0 0.0 0 0 ? SN Jun05 0:00 [ksoftirqd/1] root 6 0.0 0.0 0 0 ? S< Jun05 0:00 [migration/2] root 7 0.0 0.0 0 0 ? SN Jun05 0:00 [ksoftirqd/2] root 8 0.0 0.0 0 0 ? S< Jun05 0:00 [migration/3] root 9 0.0 0.0 0 0 ? SN Jun05 0:00 [ksoftirqd/3] root 10 0.0 0.0 0 0 ? S< Jun05 0:06 [events/0] root 11 0.0 0.0 0 0 ? S< Jun05 0:00 [events/1] root 12 0.0 0.0 0 0 ? S< Jun05 0:00 [events/2] root 13 0.0 0.0 0 0 ? S< Jun05 0:00 [events/3] root 14 0.0 0.0 0 0 ? S< Jun05 0:00 [khelper] root 31 0.0 0.0 0 0 ? S< Jun05 0:00 [kthread] root 38 0.0 0.0 0 0 ? S< Jun05 0:00 [kblockd/0] root 39 0.0 0.0 0 0 ? S< Jun05 0:00 [kblockd/1] root 40 0.0 0.0 0 0 ? S< Jun05 0:00 [kblockd/2] root 41 0.0 0.0 0 0 ? S< Jun05 0:00 [kblockd/3] root 42 0.0 0.0 0 0 ? S< Jun05 0:00 [kacpid] root 204 0.0 0.0 0 0 ? S< Jun05 0:00 [cqueue/0] root 205 0.0 0.0 0 0 ? S< Jun05 0:00 [cqueue/1] root 206 0.0 0.0 0 0 ? S< Jun05 0:00 [cqueue/2] root 207 0.0 0.0 0 0 ? S< Jun05 0:00 [cqueue/3] root 210 0.0 0.0 0 0 ? S< Jun05 0:00 [khubd] root 212 0.0 0.0 0 0 ? S< Jun05 0:00 [kseriod] root 302 0.0 0.0 0 0 ? S Jun05 0:00 [khungtaskd] root 303 0.0 0.0 0 0 ? S Jun05 0:00 [pdflush] root 304 0.0 0.0 0 0 ? S Jun05 0:01 [pdflush] root 305 0.0 0.0 0 0 ? S< Jun05 0:05 [kswapd0] root 306 0.0 0.0 0 0 ? S< Jun05 0:00 [aio/0] root 307 0.0 0.0 0 0 ? S< Jun05 0:00 [aio/1] root 308 0.0 0.0 0 0 ? S< Jun05 0:00 [aio/2] root 309 0.0 0.0 0 0 ? S< Jun05 0:00 [aio/3] root 515 0.0 0.0 0 0 ? S< Jun05 0:00 [kpsmoused] root 582 0.0 0.0 0 0 ? S< Jun05 0:00 [mpt_poll_0] root 583 0.0 0.0 0 0 ? S< Jun05 0:00 [mpt/0] root 584 0.0 0.0 0 0 ? S< Jun05 0:00 [scsi_eh_0] root 590 0.0 0.0 0 0 ? S< Jun05 0:00 [ata/0] root 591 0.0 0.0 0 0 ? S< Jun05 0:00 [ata/1] root 592 0.0 0.0 0 0 ? S< Jun05 0:00 [ata/2] root 593 0.0 0.0 0 0 ? S< Jun05 0:00 [ata/3] root 594 0.0 0.0 0 0 ? S< Jun05 0:00 [ata_aux] root 610 0.0 0.0 0 0 ? S< Jun05 0:00 [kstriped] root 631 0.0 0.0 0 0 ? S< Jun05 0:05 [kjournald] root 656 0.0 0.0 0 0 ? S< Jun05 0:00 [kauditd] root 689 0.0 0.0 13364 928 ? S<s Jun05 0:00 /sbin/udevd -d root 2123 0.0 0.0 0 0 ? S< Jun05 0:00 [kmpathd/0] root 2124 0.0 0.0 0 0 ? S< Jun05 0:00 [kmpathd/1] root 2126 0.0 0.0 0 0 ? S< Jun05 0:00 [kmpathd/2] root 2127 0.0 0.0 0 0 ? S< Jun05 0:00 [kmpathd/3] root 2128 0.0 0.0 0 0 ? S< Jun05 0:00 [kmpath_handlerd] root 2203 0.0 0.0 0 0 ? S< Jun05 0:00 [kjournald] root 2613 0.0 0.0 5908 648 ? Ss Jun05 0:00 syslogd -m 0 root 2617 0.0 0.0 3804 424 ? Ss Jun05 0:00 klogd -x root 2707 0.0 0.0 10760 372 ? Ss Jun05 0:02 irqbalance apache 2910 0.5 0.6 213964 12912 ? S 00:22 0:07 /usr/sbin/httpd dbus 3011 0.0 0.0 21256 904 ? Ss Jun05 0:00 dbus-daemon --system root 3025 0.0 0.0 3800 576 ? Ss Jun05 0:00 /usr/sbin/acpid 68 3038 0.0 0.2 31152 4336 ? Ss Jun05 0:01 hald root 3039 0.0 0.0 21692 1176 ? S Jun05 0:00 hald-runner 68 3046 0.0 0.0 12324 856 ? S Jun05 0:00 hald-addon-acpi: listening on acpid socket /var/run/acpid.s 68 3052 0.0 0.0 12324 856 ? S Jun05 0:00 hald-addon-keyboard: listening on /dev/input/event0 root 3105 0.0 0.0 62624 1212 ? Ss Jun05 0:00 /usr/sbin/sshd root 3264 0.0 0.0 74820 1156 ? Ss Jun05 0:00 crond root 3292 0.0 0.0 18416 472 ? S Jun05 0:00 /usr/sbin/smartd -q never root 3300 0.0 0.0 3792 480 tty2 Ss+ Jun05 0:00 /sbin/mingetty tty2 root 3301 0.0 0.0 3792 480 tty3 Ss+ Jun05 0:00 /sbin/mingetty tty3 root 3302 0.0 0.0 3792 484 tty4 Ss+ Jun05 0:00 /sbin/mingetty tty4 root 3304 0.0 0.0 3792 480 tty5 Ss+ Jun05 0:00 /sbin/mingetty tty5 root 3306 0.0 0.0 3792 480 tty6 Ss+ Jun05 0:00 /sbin/mingetty tty6 apache 5158 0.4 0.5 211896 11848 ? S 00:28 0:04 /usr/sbin/httpd apache 5519 0.4 0.5 211896 11992 ? S 00:29 0:03 /usr/sbin/httpd root 5649 0.0 0.0 63848 1184 pts/0 S Jun05 0:00 /bin/sh /usr/bin/mysqld_safe --datadir=/var/lib/mysql --soc mysql 5696 2.1 1.9 411060 40392 pts/0 Rl Jun05 2:01 /usr/libexec/mysqld --basedir=/usr --datadir=/var/lib/mysql apache 5943 0.4 0.5 211896 12000 ? S 00:30 0:03 /usr/sbin/httpd apache 5976 0.6 0.5 211896 11792 ? S 00:30 0:04 /usr/sbin/httpd apache 6073 0.4 0.5 211896 11208 ? S 00:31 0:03 /usr/sbin/httpd apache 6122 0.4 0.5 211896 11848 ? S 00:31 0:03 /usr/sbin/httpd apache 6128 0.3 0.5 211896 11940 ? S 00:31 0:02 /usr/sbin/httpd apache 6159 0.5 0.5 211896 11872 ? S 00:31 0:04 /usr/sbin/httpd apache 6636 0.4 0.6 213960 13444 ? S 00:32 0:02 /usr/sbin/httpd apache 6787 0.3 0.5 211884 11308 ? S 00:33 0:02 /usr/sbin/httpd apache 6796 0.4 0.5 211884 12024 ? S 00:33 0:02 /usr/sbin/httpd apache 6801 0.3 0.5 211896 11920 ? S 00:33 0:01 /usr/sbin/httpd apache 6804 0.4 0.5 211884 11848 ? S 00:33 0:02 /usr/sbin/httpd apache 6825 0.4 0.5 211896 11972 ? S 00:33 0:02 /usr/sbin/httpd apache 6866 0.3 0.5 210860 11044 ? S 00:33 0:01 /usr/sbin/httpd apache 6870 0.2 0.5 211896 11108 ? S 00:33 0:01 /usr/sbin/httpd apache 6872 0.3 0.5 211896 11900 ? S 00:33 0:01 /usr/sbin/httpd apache 6993 0.3 0.5 211896 11836 ? S 00:33 0:02 /usr/sbin/httpd apache 6994 0.3 0.5 211896 11792 ? S 00:33 0:01 /usr/sbin/httpd apache 7136 0.2 0.5 211896 11432 ? S 00:34 0:01 /usr/sbin/httpd apache 7143 0.2 0.5 210860 11052 ? S 00:34 0:01 /usr/sbin/httpd apache 7145 0.2 0.5 211896 11136 ? S 00:34 0:01 /usr/sbin/httpd apache 7266 0.2 0.6 213952 12748 ? S 00:34 0:01 /usr/sbin/httpd apache 7299 0.2 0.5 211884 11276 ? S 00:34 0:01 /usr/sbin/httpd apache 7311 0.2 0.5 211884 11300 ? S 00:34 0:01 /usr/sbin/httpd apache 7313 0.3 0.5 211884 11876 ? S 00:34 0:01 /usr/sbin/httpd apache 7345 0.2 0.5 210872 11100 ? S 00:34 0:01 /usr/sbin/httpd apache 7349 0.2 0.5 210860 11008 ? S 00:34 0:01 /usr/sbin/httpd apache 7350 0.2 0.5 211896 11832 ? S 00:34 0:01 /usr/sbin/httpd apache 7351 0.1 0.5 211884 11072 ? S 00:34 0:00 /usr/sbin/httpd apache 7352 0.2 0.5 210872 11096 ? S 00:34 0:01 /usr/sbin/httpd apache 7449 0.1 0.5 210860 11020 ? S 00:35 0:00 /usr/sbin/httpd root 7490 0.3 0.0 0 0 ? S Jun05 3:11 [vmmemctl] root 7597 0.0 0.0 72656 1260 ? Ss Jun05 0:06 /usr/lib/vmware-tools/sbin64/vmware-guestd --background /va apache 7720 0.1 0.5 210860 10748 ? S 00:36 0:00 /usr/sbin/httpd apache 7726 0.1 0.4 209836 9304 ? R 00:36 0:00 /usr/sbin/httpd apache 7727 0.1 0.5 210860 10916 ? S 00:36 0:00 /usr/sbin/httpd apache 7731 0.1 0.5 210860 10780 ? S 00:36 0:00 /usr/sbin/httpd apache 7732 0.3 0.5 210860 10916 ? S 00:36 0:01 /usr/sbin/httpd apache 7733 0.1 0.5 210872 11000 ? S 00:36 0:00 /usr/sbin/httpd apache 7735 0.1 0.5 211884 11048 ? S 00:36 0:00 /usr/sbin/httpd apache 7761 0.1 0.5 210860 10552 ? S 00:36 0:00 /usr/sbin/httpd apache 7776 0.1 0.4 209836 8648 ? R 00:37 0:00 /usr/sbin/httpd apache 7790 0.2 0.3 208812 7724 ? R 00:40 0:00 /usr/sbin/httpd apache 7800 0.2 0.3 208812 8088 ? R 00:40 0:00 /usr/sbin/httpd root 7801 0.0 0.0 3792 484 tty1 Ss+ 00:41 0:00 /sbin/mingetty tty1 apache 7820 0.2 0.3 208812 7552 ? R 00:41 0:00 /usr/sbin/httpd apache 7834 0.2 0.3 207788 6756 ? R 00:42 0:00 /usr/sbin/httpd apache 7864 0.2 0.2 207788 6148 ? R 00:42 0:00 /usr/sbin/httpd apache 7872 0.3 0.2 207788 5856 ? R 00:43 0:00 /usr/sbin/httpd apache 7874 2.5 0.3 207788 6336 ? R 00:43 0:00 /usr/sbin/httpd root 7875 0.3 0.0 63844 1056 ? S 00:43 0:00 sh -c lsb_release -sd 2>/dev/null root 7879 1.6 0.0 65604 964 pts/0 R+ 00:43 0:00 ps aux root 16316 0.0 0.1 90128 3272 ? Ss Jun05 0:00 sshd: milanb [priv] milanb 16358 0.0 0.0 90128 1752 ? S Jun05 0:00 sshd: milanb@pts/0 milanb 16360 0.0 0.0 66076 1480 pts/0 Ss Jun05 0:00 -bash root 16875 0.0 0.0 101068 1324 pts/0 S Jun05 0:00 su - root 16877 0.0 0.0 66184 1692 pts/0 S Jun05 0:00 -bash root 24373 0.0 0.3 206764 7348 ? Rs Jun05 0:01 /usr/sbin/httpd

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  • HIGH CPU USAGE + low memory usage

    - by hadi
    as you can see in below , there are high cpu usage by httpd request. please help me to decrease them. thanks. 28577 apache 15 0 99676 53m 3488 S 21 0.2 1:13.67 httpd 28568 apache 15 0 99676 53m 3496 S 19 0.2 1:14.92 httpd 28608 apache 15 0 99676 53m 3428 R 19 0.2 0:28.28 httpd 28615 apache 15 0 99676 53m 3436 R 19 0.2 0:25.33 httpd 28616 apache 15 0 99676 53m 3440 S 19 0.2 0:25.83 httpd 28619 apache 15 0 99676 53m 3436 R 19 0.2 0:26.12 httpd 28635 apache 15 0 97.9m 54m 3416 S 19 0.2 0:24.86 httpd 28558 apache 15 0 97.9m 54m 3432 R 17 0.2 1:40.75 httpd 28560 apache 15 0 97.9m 54m 3496 R 17 0.2 1:40.02 httpd 28621 apache 15 0 97.9m 54m 3420 S 17 0.2 0:25.61 httpd 28641 apache 16 0 97.9m 54m 3428 R 17 0.2 0:21.52 httpd 28642 apache 15 0 99756 53m 3424 R 15 0.2 0:21.46 httpd 28643 apache 15 0 99676 53m 3424 S 15 0.2 0:21.59 httpd 28594 apache 15 0 99756 53m 3428 R 13 0.2 0:44.41 httpd 28618 apache 15 0 99676 53m 3420 S 13 0.2 0:26.15 httpd 28654 apache 15 0 99676 53m 3472 S 13 0.2 0:04.27 httpd 28575 apache 15 0 99756 53m 3436 R 11 0.2 1:14.02 httpd 28576 apache 15 0 99676 53m 3496 S 11 0.2 1:16.79 httpd 28634 apache 15 0 99676 53m 3436 S 11 0.2 0:25.36 httpd 28653 apache 15 0 99676 53m 3424 S 11 0.2 0:04.35 httpd 28574 apache 15 0 99676 53m 3440 S 10 0.2 1:13.05 httpd 28592 apache 15 0 99676 53m 3492 R 10 0.2 0:45.78 httpd 28595 apache 15 0 99676 53m 3432 R 10 0.2 0:47.02 httpd 28617 apache 16 0 99676 53m 3436 S 10 0.2 0:25.32 httpd 28620 apache 15 0 99676 53m 3432 S 10 0.2 0:25.35 httpd 28597 apache 15 0 99676 53m 3428 S 8 0.2 0:43.56 httpd 11345 mysql 15 0 2927m 198m 4472 R 4 0.6 1624:43 mysqld 1 root 15 0 2036 648 552 S 0 0.0 0:16.97 init 2 root RT 0 0 0 0 S 0 0.0 0:48.50 migration/0 3 root 34 19 0 0 0 S 0 0.0 0:26.72 ksoftirqd/0 4 root RT 0 0 0 0 S 0 0.0 0:00.00 watchdog/0 5 root RT 0 0 0 0 S 0 0.0 0:04.98 migration/1 6 root 34 19 0 0 0 R 0 0.0 0:27.51 ksoftirqd/1 7 root RT 0 0 0 0 S 0 0.0 0:00.00 watchdog/1 8 root RT 0 0 0 0 S 0 0.0 0:15.42 migration/2 9 root 34 19 0 0 0 S 0 0.0 0:26.50 ksoftirqd/2 10 root RT 0 0 0 0 S 0 0.0 0:00.00 watchdog/2

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  • How to confirm memcache memory increase?

    - by Peter Johansson
    Alright, I have downloaded /etc/sysconfig/memcache And edited the file that contained "PORT="11211" USER="memcached" MAXCONN="1024" CACHESIZE="64" OPTIONS="" to 1000 cachesize. I uploaded the file back to the server. Now I know there is a way to check if the changes took effect, but I cant remember how. I tried "memcached-tool 127.0.0.1:11211 stats" but it didnt show me the RAM size. Any help would be appreciated.

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  • JVM memory initializazion error after windows update

    - by gianni
    We have three Windows Server 2003 with 2 GB RAM. Server1 tomcat 5.5.25 jvm version SUN 1.6.0_11-b03 Server2 tomcat 5.5.25 jvm version SUN 1.6.0_14-b08 Server3 tomcat 6.0.18 jvm version SUN 1.6.0_14-b08 For the three servers JVM parameters are: -XX:MaxPermSize=256m -Dcatalina.base=C:\Programmi\Apache Group\apache-tomcat-5.5.25 -Dcatalina.home=C:\Programmi\Apache Group\apache-tomcat-5.5.25 -Djava.endorsed.dirs=C:\Programmi\Apache Group\apache-tomcat-5.5.25\common\endorsed -Djava.io.tmpdir=C:\Programmi\Apache Group\apache-tomcat-5.5.25\temp vfprintf -Xms512m -Xmx1024m For some months everithing worked fine. Last friday we installed some windows updates. After the reboot tomcat doesnt start with error: Error occurred during initialization of VM Could not reserve enough space for object heap We reduced the parameter -Xmx1024m to -Xmx768m and now tomcat starts. But we need greater max heap size What happened to our servers ? Thanks in advance.

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  • how to solve out of memory error in java in amazon ec2 server

    - by sathishkumar
    can anyone explain about this error message? we are using IBM jre to run java application Its occupying more space on the server. JVMDUMP006I Processing dump event "systhrow", detail "java/lang/OutOfMemoryError" - please wait. JVMDUMP006I Processing dump event "systhrow", detail "java/lang/OutOfMemoryError" - please wait. JVMDUMP032I JVM requested Heap dump using '/home/sathish/jetty6/heapdump.20110417.114115.18926.0001.phd' in response to an event JVMDUMP010I Heap dump written to /home/sathish/jetty6/heapdump.20110417.114115.18926.0001.phd JVMDUMP032I JVM requested Heap dump using '/home/sathish/jetty6/heapdump.20110417.114115.18926.0002.phd' in response to an event JVMDUMP010I Heap dump written to /home/sathish/jetty6/heapdump.20110417.114115.18926.0002.phd JVMDUMP032I JVM requested Heap dump using '/home/sathish/jetty6/heapdump.20110417.114115.18926.0003.phd' in response to an event JVMDUMP010I Heap dump written to /home/sathish/jetty6/heapdump.20110417.114115.18926.0003.phd JVMDUMP032I JVM requested Java dump using '/home/sathish/jetty6/javacore.20110417.114115.18926.0004.txt' in response to an event JVMDUMP010I Java dump written to /home/sathish/jetty6/javacore.20110417.114115.18926.0004.txt

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  • Support-Tool (SDK): Capture system information (Registry, Memory, etc.), Make a screenshoot, send an

    - by Robert
    I have the task to find or develop a support tool which has some very common (?) features: Send the following data as a email or to ticket system, after clicking a button like "get system summary" or "create ticket" Screen shoot System Summary Registry Log-Files Question(s): Are their any tools which have a similar functionality already (to buy or for inspiration). I their some kind of commercial or open source framework or tool set, which I can use as starting point or to customize?

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  • Ubuntu won't boot from USB memory stick

    - by mackenir
    I used the instructions on this webpage to create a bootable USB drive for running Ubuntu 9.10. Unfortunately it doesn't work on my EeePC. Even with 'Removable Dev.' selected in the BIOS as the first boot device, the PC just boots into Windows 7. How do I troubleshoot this problem? The drive is readable and looks like this: Directory of E:\ 28/10/2009 21:14 <DIR> .disk 28/10/2009 21:14 222 README.diskdefines 28/10/2009 21:14 143 autorun.inf 28/10/2009 21:14 <DIR> casper 28/10/2009 21:14 <DIR> dists 28/10/2009 21:14 <DIR> install 28/10/2009 21:14 <DIR> syslinux 28/10/2009 21:14 4,098 md5sum.txt 28/10/2009 21:14 <DIR> pics 28/10/2009 21:14 <DIR> pool 28/10/2009 21:14 <DIR> preseed 28/10/2009 21:14 0 ubuntu 26/10/2009 16:16 1,468,640 wubi.exe 25/02/2010 00:28 2,147,483,648 casper-rw 8 Dir(s) 5,290,307,584 bytes free

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  • Bootable SD card still has small memory, even after formating

    - by Inazuma
    I have an SD card which I used to run my RaspberryPi. I wanted to update the copy of raspbian on it, so I formated the card using the software from www.sdcard.com. I followed all the instructions correctly, however the size of my SD card didn't go back to it's default. It is a 4gb SD card, which after it's spell in the RaspberryPi had shrunken to 52mb, which I understand is normal. After formatting, the size rose to 3.69gb. This means that there is not enough space to install a new OS, so how can I make my SD card 4gb again? Any help would be much appreciated!

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  • Is there an eSATA memory stick / thumb drive?

    - by jasondavis
    The new PC I just finished building has eSATA support. I use a USB stick/thumb drive all the time on my PC for stuff, is there an equivalent available anywhere for eSATA? Please list one product per post, and provide a link to the manufacturer's product page. Also see the USB-3 version of this question.

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  • e2fsck extremely slow, although enough memory exists

    - by kaefert
    I've got this external USB-Disk: kaefert@blechmobil:~$ lsusb -s 2:3 Bus 002 Device 003: ID 0bc2:3320 Seagate RSS LLC As can be seen in this dmesg output, there is some problem that prevents that disk from beeing mounted: kaefert@blechmobil:~$ dmesg ... [ 113.084079] usb 2-1: new high-speed USB device number 3 using ehci_hcd [ 113.217783] usb 2-1: New USB device found, idVendor=0bc2, idProduct=3320 [ 113.217787] usb 2-1: New USB device strings: Mfr=2, Product=3, SerialNumber=1 [ 113.217790] usb 2-1: Product: Expansion Desk [ 113.217792] usb 2-1: Manufacturer: Seagate [ 113.217794] usb 2-1: SerialNumber: NA4J4N6K [ 113.435404] usbcore: registered new interface driver uas [ 113.455315] Initializing USB Mass Storage driver... [ 113.468051] scsi5 : usb-storage 2-1:1.0 [ 113.468180] usbcore: registered new interface driver usb-storage [ 113.468182] USB Mass Storage support registered. [ 114.473105] scsi 5:0:0:0: Direct-Access Seagate Expansion Desk 070B PQ: 0 ANSI: 6 [ 114.474342] sd 5:0:0:0: [sdb] 732566645 4096-byte logical blocks: (3.00 TB/2.72 TiB) [ 114.475089] sd 5:0:0:0: [sdb] Write Protect is off [ 114.475092] sd 5:0:0:0: [sdb] Mode Sense: 43 00 00 00 [ 114.475959] sd 5:0:0:0: [sdb] Write cache: enabled, read cache: enabled, doesn't support DPO or FUA [ 114.477093] sd 5:0:0:0: [sdb] 732566645 4096-byte logical blocks: (3.00 TB/2.72 TiB) [ 114.501649] sdb: sdb1 [ 114.502717] sd 5:0:0:0: [sdb] 732566645 4096-byte logical blocks: (3.00 TB/2.72 TiB) [ 114.504354] sd 5:0:0:0: [sdb] Attached SCSI disk [ 116.804408] EXT4-fs (sdb1): ext4_check_descriptors: Checksum for group 3976 failed (47397!=61519) [ 116.804413] EXT4-fs (sdb1): group descriptors corrupted! ... So I went and fired up my favorite partition manager - gparted, and told it to verify and repair the partition sdb1. This made gparted call e2fsck (version 1.42.4 (12-Jun-2012)) e2fsck -f -y -v /dev/sdb1 Although gparted called e2fsck with the "-v" option, sadly it doesn't show me the output of my e2fsck process (bugreport https://bugzilla.gnome.org/show_bug.cgi?id=467925 ) I started this whole thing on Sunday (2012-11-04_2200) evening, so about 48 hours ago, this is what htop says about it now (2012-11-06-1900): PID USER PRI NI VIRT RES SHR S CPU% MEM% TIME+ Command 3704 root 39 19 1560M 1166M 768 R 98.0 19.5 42h56:43 e2fsck -f -y -v /dev/sdb1 Now I found a few posts on the internet that discuss e2fsck running slow, for example: http://gparted-forum.surf4.info/viewtopic.php?id=13613 where they write that its a good idea to see if the disk is just that slow because maybe its damaged, and I think these outputs tell me that this is not the case in my case: kaefert@blechmobil:~$ sudo hdparm -tT /dev/sdb /dev/sdb: Timing cached reads: 3562 MB in 2.00 seconds = 1783.29 MB/sec Timing buffered disk reads: 82 MB in 3.01 seconds = 27.26 MB/sec kaefert@blechmobil:~$ sudo hdparm /dev/sdb /dev/sdb: multcount = 0 (off) readonly = 0 (off) readahead = 256 (on) geometry = 364801/255/63, sectors = 5860533160, start = 0 However, although I can read quickly from that disk, this disk speed doesn't seem to be used by e2fsck, considering tools like gkrellm or iotop or this: kaefert@blechmobil:~$ iostat -x Linux 3.2.0-2-amd64 (blechmobil) 2012-11-06 _x86_64_ (2 CPU) avg-cpu: %user %nice %system %iowait %steal %idle 14,24 47,81 14,63 0,95 0,00 22,37 Device: rrqm/s wrqm/s r/s w/s rkB/s wkB/s avgrq-sz avgqu-sz await r_await w_await svctm %util sda 0,59 8,29 2,42 5,14 43,17 160,17 53,75 0,30 39,80 8,72 54,42 3,95 2,99 sdb 137,54 5,48 9,23 0,20 587,07 22,73 129,35 0,07 7,70 7,51 16,18 2,17 2,04 Now I researched a little bit on how to find out what e2fsck is doing with all that processor time, and I found the tool strace, which gives me this: kaefert@blechmobil:~$ sudo strace -p3704 lseek(4, 41026998272, SEEK_SET) = 41026998272 write(4, "\212\354K[_\361\3nl\212\245\352\255jR\303\354\312Yv\334p\253r\217\265\3567\325\257\3766"..., 4096) = 4096 lseek(4, 48404766720, SEEK_SET) = 48404766720 read(4, "\7t\260\366\346\337\304\210\33\267j\35\377'\31f\372\252\ffU\317.y\211\360\36\240c\30`\34"..., 4096) = 4096 lseek(4, 41027002368, SEEK_SET) = 41027002368 write(4, "\232]7Ws\321\352\t\1@[+5\263\334\276{\343zZx\352\21\316`1\271[\202\350R`"..., 4096) = 4096 lseek(4, 48404770816, SEEK_SET) = 48404770816 read(4, "\17\362r\230\327\25\346//\210H\v\311\3237\323K\304\306\361a\223\311\324\272?\213\tq \370\24"..., 4096) = 4096 lseek(4, 41027006464, SEEK_SET) = 41027006464 write(4, "\367yy>x\216?=\324Z\305\351\376&\25\244\210\271\22\306}\276\237\370(\214\205G\262\360\257#"..., 4096) = 4096 lseek(4, 48404774912, SEEK_SET) = 48404774912 read(4, "\365\25\0\21|T\0\21}3t_\272\373\222k\r\177\303\1\201\261\221$\261B\232\3142\21U\316"..., 4096) = 4096 ^CProcess 3704 detached around 16 of these lines every second, so 4 read and 4 write operations every second, which I don't consider to be a lot.. And finally, my question: Will this process ever finish? If those numbers from fseek (48404774912) represent bytes, that would be something like 45 gigabytes, with this beeing a 3 terrabyte disk, which would give me 134 days to go, if the speed stays constant, and e2fsck scans the disk like this completly and only once. Do you have some advice for me? I have most of the data on that disk elsewhere, but I've put a lot of hours into sorting and merging it to this disk, so I would prefer to getting this disk up and running again, without formatting it anew. I don't think that the hardware is damaged since the disk is only a few months and since I can't see any I/O errors in the dmesg output. UPDATE: I just looked at the strace output again (2012-11-06_2300), now it looks like this: lseek(4, 1419860611072, SEEK_SET) = 1419860611072 read(4, "3#\f\2447\335\0\22A\355\374\276j\204'\207|\217V|\23\245[\7VP\251\242\276\207\317:"..., 4096) = 4096 lseek(4, 43018145792, SEEK_SET) = 43018145792 write(4, "]\206\231\342Y\204-2I\362\242\344\6R\205\361\324\177\265\317C\334V\324\260\334\275t=\10F."..., 4096) = 4096 lseek(4, 1419860615168, SEEK_SET) = 1419860615168 read(4, "\262\305\314Y\367\37x\326\245\226\226\320N\333$s\34\204\311\222\7\315\236\336\300TK\337\264\236\211n"..., 4096) = 4096 lseek(4, 43018149888, SEEK_SET) = 43018149888 write(4, "\271\224m\311\224\25!I\376\16;\377\0\223H\25Yd\201Y\342\r\203\271\24eG<\202{\373V"..., 4096) = 4096 lseek(4, 1419860619264, SEEK_SET) = 1419860619264 read(4, ";d\360\177\n\346\253\210\222|\250\352T\335M\33\260\320\261\7g\222P\344H?t\240\20\2548\310"..., 4096) = 4096 lseek(4, 43018153984, SEEK_SET) = 43018153984 write(4, "\360\252j\317\310\251G\227\335{\214`\341\267\31Y\202\360\v\374\307oq\3063\217Z\223\313\36D\211"..., 4096) = 4096 So the numbers in the lseek lines before the reads, like 1419860619264 are already a lot bigger, standing for 1.29 terabytes if those numbers are bytes, so it doesn't seem to be a linear progress on a big scale, maybe there are only some areas that need work, that have big gaps in between them. UPDATE2: Okey, big disappointment, the numbers are back to very small again (2012-11-07_0720) lseek(4, 52174548992, SEEK_SET) = 52174548992 read(4, "\374\312\22\\\325\215\213\23\0357U\222\246\370v^f(\312|f\212\362\343\375\373\342\4\204mU6"..., 4096) = 4096 lseek(4, 46603526144, SEEK_SET) = 46603526144 write(4, "\370\261\223\227\23?\4\4\217\264\320_Am\246CQ\313^\203U\253\274\204\277\2564n\227\177\267\343"..., 4096) = 4096 so either e2fsck goes over the data multiple times, or it just hops back and forth multiple times. Or my assumption that those numbers are bytes is wrong. UPDATE3: Since it's mentioned here http://forums.fedoraforum.org/showthread.php?t=282125&page=2 that you can testisk while e2fsck is running, i tried that, though not with a lot of success. When asking testdisk to display the data of my partition, this is what I get: TestDisk 6.13, Data Recovery Utility, November 2011 Christophe GRENIER <[email protected]> http://www.cgsecurity.org 1 P Linux 0 4 5 45600 40 8 732566272 Can't open filesystem. Filesystem seems damaged. And this is what strace currently gives me (2012-11-07_1030) lseek(4, 212460343296, SEEK_SET) = 212460343296 read(4, "\315Mb\265v\377Gn \24\f\205EHh\2349~\330\273\203\3375\206\10\r3=W\210\372\352"..., 4096) = 4096 lseek(4, 47347830784, SEEK_SET) = 47347830784 write(4, "]\204\223\300I\357\4\26\33+\243\312G\230\250\371*m2U\t_\215\265J \252\342Pm\360D"..., 4096) = 4096 (times are in CET)

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  • e2fsck extremly slow, although enough memory exists

    - by kaefert
    I've got this external USB-Disk: kaefert@blechmobil:~$ lsusb -s 2:3 Bus 002 Device 003: ID 0bc2:3320 Seagate RSS LLC As can be seen in this dmesg output, there are some problems that prevents that disk from beeing mounted: kaefert@blechmobil:~$ dmesg | grep sdb [ 114.474342] sd 5:0:0:0: [sdb] 732566645 4096-byte logical blocks: (3.00 TB/2.72 TiB) [ 114.475089] sd 5:0:0:0: [sdb] Write Protect is off [ 114.475092] sd 5:0:0:0: [sdb] Mode Sense: 43 00 00 00 [ 114.475959] sd 5:0:0:0: [sdb] Write cache: enabled, read cache: enabled, doesn't support DPO or FUA [ 114.477093] sd 5:0:0:0: [sdb] 732566645 4096-byte logical blocks: (3.00 TB/2.72 TiB) [ 114.501649] sdb: sdb1 [ 114.502717] sd 5:0:0:0: [sdb] 732566645 4096-byte logical blocks: (3.00 TB/2.72 TiB) [ 114.504354] sd 5:0:0:0: [sdb] Attached SCSI disk [ 116.804408] EXT4-fs (sdb1): ext4_check_descriptors: Checksum for group 3976 failed (47397!=61519) [ 116.804413] EXT4-fs (sdb1): group descriptors corrupted! So I went and fired up my favorite partition manager - gparted, and told it to verify and repair the partition sdb1. This made gparted call e2fsck (version 1.42.4 (12-Jun-2012)) e2fsck -f -y -v /dev/sdb1 Although gparted called e2fsck with the "-v" option, sadly it doesn't show me the output of my e2fsck process (bugreport https://bugzilla.gnome.org/show_bug.cgi?id=467925 ) I started this whole thing on Sunday (2012-11-04_2200) evening, so about 48 hours ago, this is what htop says about it now (2012-11-06-1900): PID USER PRI NI VIRT RES SHR S CPU% MEM% TIME+ Command 3704 root 39 19 1560M 1166M 768 R 98.0 19.5 42h56:43 e2fsck -f -y -v /dev/sdb1 Now I found a few posts on the internet that discuss e2fsck running slow, for example: http://gparted-forum.surf4.info/viewtopic.php?id=13613 where they write that its a good idea to see if the disk is just that slow because maybe its damaged, and I think these outputs tell me that this is not the case in my case: kaefert@blechmobil:~$ sudo hdparm -tT /dev/sdb /dev/sdb: Timing cached reads: 3562 MB in 2.00 seconds = 1783.29 MB/sec Timing buffered disk reads: 82 MB in 3.01 seconds = 27.26 MB/sec kaefert@blechmobil:~$ sudo hdparm /dev/sdb /dev/sdb: multcount = 0 (off) readonly = 0 (off) readahead = 256 (on) geometry = 364801/255/63, sectors = 5860533160, start = 0 However, although I can read quickly from that disk, this disk speed doesn't seem to be used by e2fsck, considering tools like gkrellm or iotop or this: kaefert@blechmobil:~$ iostat -x Linux 3.2.0-2-amd64 (blechmobil) 2012-11-06 _x86_64_ (2 CPU) avg-cpu: %user %nice %system %iowait %steal %idle 14,24 47,81 14,63 0,95 0,00 22,37 Device: rrqm/s wrqm/s r/s w/s rkB/s wkB/s avgrq-sz avgqu-sz await r_await w_await svctm %util sda 0,59 8,29 2,42 5,14 43,17 160,17 53,75 0,30 39,80 8,72 54,42 3,95 2,99 sdb 137,54 5,48 9,23 0,20 587,07 22,73 129,35 0,07 7,70 7,51 16,18 2,17 2,04 Now I researched a little bit on how to find out what e2fsck is doing with all that processor time, and I found the tool strace, which gives me this: kaefert@blechmobil:~$ sudo strace -p3704 lseek(4, 41026998272, SEEK_SET) = 41026998272 write(4, "\212\354K[_\361\3nl\212\245\352\255jR\303\354\312Yv\334p\253r\217\265\3567\325\257\3766"..., 4096) = 4096 lseek(4, 48404766720, SEEK_SET) = 48404766720 read(4, "\7t\260\366\346\337\304\210\33\267j\35\377'\31f\372\252\ffU\317.y\211\360\36\240c\30`\34"..., 4096) = 4096 lseek(4, 41027002368, SEEK_SET) = 41027002368 write(4, "\232]7Ws\321\352\t\1@[+5\263\334\276{\343zZx\352\21\316`1\271[\202\350R`"..., 4096) = 4096 lseek(4, 48404770816, SEEK_SET) = 48404770816 read(4, "\17\362r\230\327\25\346//\210H\v\311\3237\323K\304\306\361a\223\311\324\272?\213\tq \370\24"..., 4096) = 4096 lseek(4, 41027006464, SEEK_SET) = 41027006464 write(4, "\367yy>x\216?=\324Z\305\351\376&\25\244\210\271\22\306}\276\237\370(\214\205G\262\360\257#"..., 4096) = 4096 lseek(4, 48404774912, SEEK_SET) = 48404774912 read(4, "\365\25\0\21|T\0\21}3t_\272\373\222k\r\177\303\1\201\261\221$\261B\232\3142\21U\316"..., 4096) = 4096 ^CProcess 3704 detached around 16 of these lines every second, so 4 read and 4 write operations every second, which I don't consider to be a lot.. And finally, my question: Will this process ever finish? If those numbers from fseek (48404774912) represent bytes, that would be something like 45 gigabytes, with this beeing a 3 terrabyte disk, which would give me 134 days to go, if the speed stays constant, and he scans the disk like this completly and only once. Do you have some advice for me? I have most of the data on that disk elsewhere, but I've put a lot of hours into sorting and merging it to this disk, so I would prefer to getting this disk up and running again, without formatting it anew. I don't think that the hardware is damaged since the disk is only a few months and since I can't see any I/O errors in the dmesg output. UPDATE: I just looked at the strace output again (2012-11-06_2300), now it looks like this: lseek(4, 1419860611072, SEEK_SET) = 1419860611072 read(4, "3#\f\2447\335\0\22A\355\374\276j\204'\207|\217V|\23\245[\7VP\251\242\276\207\317:"..., 4096) = 4096 lseek(4, 43018145792, SEEK_SET) = 43018145792 write(4, "]\206\231\342Y\204-2I\362\242\344\6R\205\361\324\177\265\317C\334V\324\260\334\275t=\10F."..., 4096) = 4096 lseek(4, 1419860615168, SEEK_SET) = 1419860615168 read(4, "\262\305\314Y\367\37x\326\245\226\226\320N\333$s\34\204\311\222\7\315\236\336\300TK\337\264\236\211n"..., 4096) = 4096 lseek(4, 43018149888, SEEK_SET) = 43018149888 write(4, "\271\224m\311\224\25!I\376\16;\377\0\223H\25Yd\201Y\342\r\203\271\24eG<\202{\373V"..., 4096) = 4096 lseek(4, 1419860619264, SEEK_SET) = 1419860619264 read(4, ";d\360\177\n\346\253\210\222|\250\352T\335M\33\260\320\261\7g\222P\344H?t\240\20\2548\310"..., 4096) = 4096 lseek(4, 43018153984, SEEK_SET) = 43018153984 write(4, "\360\252j\317\310\251G\227\335{\214`\341\267\31Y\202\360\v\374\307oq\3063\217Z\223\313\36D\211"..., 4096) = 4096 So this number of the lseeks before the reads, like 1419860619264 are already a lot bigger, standing for 1.29 terabytes if the numbers are bytes, so it doesn't seem to be a linear progress on a big scale, maybe there are only some areas that need work, that have big gaps in between them. (times are in CET)

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  • SQLS Timeouts - High Reads in Profiler

    - by lb01
    I've audited a SQLS2008 server with Profiler for one day.. the overhead didn't seem to trouble this new client my company has. They are using a legacy VB6 application as a front-end. They're experiencing timeouts once SQLS RAM usage is high. The server is currently running x64 sqls2008 on a VM with nearly 9 GB of RAM. SQL Server's 'max server memory option' is currently set to 6GB. I've put the results of the trace in a table and queried them using this query. SELECT TextData, ApplicationName, Reads FROM [TraceWednesday] WHERE textdata is not null and EventClass = 12 GROUP BY TextData, ApplicationName, Reads ORDER BY Reads DESC As I expected, some values are very high. Top Reads, in pages. 2504188 1965910 1445636 1252433 1239108 1210153 1088580 1072725 Am I correct in thinking that the top one (2504188 pages) is 20033504 KB, which then is roughly ~20'000 MB, 20GB? These queries are often executed and can take quite some time to run. Eventually RAM is used up because of the cache fattening, and timeouts occur once SQL cannot 'splash' pages in the buffer pool as much. Costs go up. Am I correct in my understanding? I've read that I should tune the associated T-SQL and create appropriate indices. Obviously cutting down the I/O would make SQL Server use less RAM. OR, maybe it might just slow down the process of chewing up the whole RAM. If a lot less pages are read, maybe it'll all run much better even when usage is high? (less time swapping, etc.) Currently, our only option is to restart SQL once a week when RAM usage is high, suddenly the timeouts disappear. SQL breathes again. I'm sure lots of DBAs have been in this situation.. I'm asking before I start digging out all of the bad T-SQL and put indices here and there, is there is something else I can do? Any advice except from what I know (not much yet..) Much appreciated. Leo.

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  • Linux: find out what process is using all the RAM?

    - by Timur
    Before actually asking, just to be clear: yes, I know about disk cache, and no, it is not my case :) Sorry, for this preamble :) I'm using CentOS 5. Every application in the system is swapping heavily, and the system is very slow. When I do free -m, here is what I got: total used free shared buffers cached Mem: 3952 3929 22 0 1 18 -/+ buffers/cache: 3909 42 Swap: 16383 46 16337 So, I actually have only 42 Mb to use! As far as I understand, -/+ buffers/cache actually doesn't count the disk cache, so I indeed only have 42 Mb, right? I thought, I might be wrong, so I tried to switch off the disk caching and it had no effect - the picture remained the same. So, I decided to find out who is using all my RAM, and I used top for that. But, apparently, it reports that no process is using my RAM. The only process in my top is MySQL, but it is using 0.1% of RAM and 400Mb of swap. Same picture when I try to run other services or applications - all go in swap, top shows that MEM is not used (0.1% maximum for any process). top - 15:09:00 up 2:09, 2 users, load average: 0.02, 0.16, 0.11 Tasks: 112 total, 1 running, 111 sleeping, 0 stopped, 0 zombie Cpu(s): 0.0%us, 0.0%sy, 0.0%ni,100.0%id, 0.0%wa, 0.0%hi, 0.0%si, 0.0%st Mem: 4046868k total, 4001368k used, 45500k free, 748k buffers Swap: 16777208k total, 68840k used, 16708368k free, 16632k cached PID USER PR NI VIRT RES SHR S %CPU %MEM TIME+ SWAP COMMAND 3214 ntp 15 0 23412 5044 3916 S 0.0 0.1 0:00.00 17m ntpd 2319 root 5 -10 12648 4460 3184 S 0.0 0.1 0:00.00 8188 iscsid 2168 root RT 0 22120 3692 2848 S 0.0 0.1 0:00.00 17m multipathd 5113 mysql 18 0 474m 2356 856 S 0.0 0.1 0:00.11 472m mysqld 4106 root 34 19 251m 1944 1360 S 0.0 0.0 0:00.11 249m yum-updatesd 4109 root 15 0 90152 1904 1772 S 0.0 0.0 0:00.18 86m sshd 5175 root 15 0 90156 1896 1772 S 0.0 0.0 0:00.02 86m sshd Restart doesn't help, and, by they way is very slow, which I wouldn't normally expect on this machine (4 cores, 4Gb RAM, RAID1). So, with that - I'm pretty sure that this is not a disk cache, who is using the RAM, because normally it should have been reduced and let other processes to use RAM, rather then go to swap. So, finally, the question is - if someone has any ideas how to find out what process is actually using the memory so heavily?

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  • SQLS Timeouts - High Reads in Profiler

    - by lb01
    Hi I've audited a SQLS2008 server with Profiler for one day.. the overhead didn't seem to trouble this new client my company has. They are using a legacy VB6 application as a front-end. They're experiencing timeouts once SQLS RAM usage is high. The server is currently running x64 sqls2008 on a VM with nearly 9 GB of RAM. SQL Server's 'max server memory option' is currently set to 6GB. I've put the results of the trace in a table and queried them using this query. SELECT TextData, ApplicationName, Reads FROM [TraceWednesday] WHERE textdata is not null and EventClass = 12 GROUP BY TextData, ApplicationName, Reads ORDER BY Reads DESC As I expected, some values are very high. Top Reads, in pages. 2504188 1965910 1445636 1252433 1239108 1210153 1088580 1072725 Am I correct in thinking that the top one (2504188 pages) is 20033504 KB, which then is roughly ~20'000 MB, 20GB? These queries are often executed and can take quite some time to run. Eventually RAM is used up because of the cache fattening, and timeouts occur once SQL cannot 'splash' pages in the buffer pool as much. Costs go up. Am I correct in my understanding? I've read that I should tune the associated T-SQL and create appropriate indices. Obviously cutting down the I/O would make SQL Server use less RAM. OR, maybe it might just slow down the process of chewing up the whole RAM. If a lot less pages are read, maybe it'll all run much better even when usage is high? (less time swapping, etc.) Currently, our only option is to restart SQL once a week when RAM usage is high, suddenly the timeouts disappear. SQL breathes again. I'm sure lots of DBAs have been in this situation.. I'm asking before I start digging out all of the bad T-SQL and put indices here and there, is there is something else I can do? Any advice except from what I know (not much yet..) Much appreciated. Leo.

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  • The instruction at “0x7c910a19” referenced memory at “oxffffffff”. The memory could not be “read”

    - by ClareBear
    Hello guys/girls I have a small issue, I receive the following error before the .vbs terminates. I don't know why this error is thrown. Below is the process of the .vbs file: Call ImportTransactions() Call UpdateTransactions() Function ImportTransactions() Dim objConnection, objCommand, objRecordset, strOracle Dim strSQL, objRecordsetInsert Set objConnection = CreateObject("ADODB.Connection") objConnection.Open "DSN=*****;UID=*****;PWD==*****;" Set objCommand = CreateObject("ADODB.Command") Set objRecordset = CreateObject("ADODB.Recordset") strOracle = "SELECT query here from Oracle database" objCommand.CommandText = strOracle objCommand.CommandType = 1 objCommand.CommandTimeout = 0 Set objCommand.ActiveConnection = objConnection objRecordset.cursorType = 0 objRecordset.cursorlocation = 3 objRecordset.Open objCommand, , 1, 3 If objRecordset.EOF = False Then Do Until objRecordset.EOF = True strSQL = "INSERT query here into SQL database" strSQL = Query(strSQL) Call RunSQL(strSQL, objRecordsetInsert, False, conTimeOut, conServer, conDatabase, conUsername, conPassword) objRecordset.MoveNext Loop End If objRecordset.Close() Set objRecordset = Nothing Set objRecordsetInsert = Nothing End Function Function UpdateTransactions() Dim strSQLUpdateVAT, strSQLUpdateCodes Dim objRecordsetVAT, objRecordsetUpdateCodes strSQLUpdateVAT = "UPDATE query here SET [value:costing output] = ([value:costing output] * -1)" Call RunSQL(strSQLUpdateVAT, objRecordsetVAT, False, conTimeOut, conServer, conDatabase, conUsername, conPassword) strSQLUpdateCodes = "UPDATE query here SET [value:costing output] = ([value:costing output] * -1) different WHERE clause" Call RunSQL(strSQLUpdateCodes, objRecordsetUpdateCodes, False, conTimeOut, conServer, conDatabase, conUsername, conPassword) Set objRecordsetVAT = Nothing Set objRecordsetUpdateCodes = Nothing End Function It does both the import and update and seems to throw this error after. If I comment out the ImportTransactions it doesnt throw a error, however I have produced similar code for another vbs file and this does not throw any errors Thanks in advance for any help, Clare

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  • In Ruby, how to I read memory values from an external process?

    - by grg-n-sox
    So all I simply want to do is make a Ruby program that reads some values from known memory address in another process's virtual memory. Through my research and basic knowledge of hex editing a running process's x86 assembly in memory, I have found the base address and offsets for the values in memory I want. I do not want to change them; I just want to read them. I asked a developer of a memory editor how to approach this abstract of language and assuming a Windows platform. He told me the Win32API calls for OpenProcess, CreateProcess, ReadProcessMemory, and WriteProcessMemory were the way to go using either C or C++. I think that the way to go would be just using the Win32API class and mapping two instances of it; One for either OpenProcess or CreateProcess, depending on if the user already has th process running or not, and another instance will be mapped to ReadProcessMemory. I probably still need to find the function for getting the list of running processes so I know which running process is the one I want if it is running already. This would take some work to put all together, but I am figuring it wouldn't be too bad to code up. It is just a new area of programming for me since I have never worked this low level from a high level language (well, higher level than C anyways). I am just wondering of the ways to approach this. I could just use a bunch or Win32API calls, but that means having to deal with a bunch of string and array pack and unpacking that is system dependant I want to eventually make this work cross-platform since the process I am reading from is produced from an executable that has multiple platform builds, (I know the memory address changes from system to system. The idea is to have a flat file that contains all memory mappings so the Ruby program can just match the current platform environment to the matching memory mapping.) but from the looks of things I'll just have to make a class that wraps whatever is the current platform's system shared library memory related function calls. For all I know, there could already exist a Ruby gem that takes care of all of this for me that I am just not finding. I could also possibly try editing the executables for each build to make it so whenever the memory values I want to read from are written to by the process, it also writes a copy of the new value to a space in shared memory that I somehow have Ruby make an instance of a class that is a pointer under the hood to that shared memory address and somehow signal to the Ruby program that the value was updated and should be reloaded. Basically a interrupt based system would be nice, but since the purpose of reading these values is just to send to a scoreboard broadcasted from a central server, I could just stick to a polling based system that sends updates at fixed time intervals. I also could just abandon Ruby altogether and go for C or C++ but I do not know those nearly as well. I actually know more x86 than C++ and I only know C as far as system independent ANSI C and have never dealt with shared system libraries before. So is there a gem or lesser known module available that has already done this? If not, then any additional information as to how to accomplish this would be nice. I guess, long story short, how do I do all this? Thanks in advance, Grg PS: Also a confirmation that those Win32API calls should be aimed at the kernel32.dll library would be nice.

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  • .NET 3.5SP1 64-bit memory model vs. 32-bit memory model

    - by James Dunne
    As I understand it, the .NET memory model on a 32-bit machine guarantees 32-bit word writes and reads to be atomic operations but does not provide this guarantee on 64-bit words. I have written a quick tool to demonstrate this effect on a Windows XP 32-bit OS and am getting results consistent with that memory model description. However, I have taken this same tool's executable and run it on a Windows 7 Enterprise 64-bit OS and am getting wildly different results. Both the machines are identical specs just with different OSes installed. I would have expected that the .NET memory model would guarantee writes and reads to BOTH 32-bit and 64-bit words to be atomic on a 64-bit OS. I find results completely contrary to BOTH assumptions. 32-bit reads and writes are not demonstrated to be atomic on this OS. Can someone explain to me why this fails on a 64-bit OS? Tool code: using System; using System.Threading; namespace ConsoleApplication1 { class Program { static void Main(string[] args) { var th = new Thread(new ThreadStart(RunThread)); var th2 = new Thread(new ThreadStart(RunThread)); int lastRecordedInt = 0; long lastRecordedLong = 0L; th.Start(); th2.Start(); while (!done) { int newIntValue = intValue; long newLongValue = longValue; if (lastRecordedInt > newIntValue) Console.WriteLine("BING(int)! {0} > {1}, {2}", lastRecordedInt, newIntValue, (lastRecordedInt - newIntValue)); if (lastRecordedLong > newLongValue) Console.WriteLine("BING(long)! {0} > {1}, {2}", lastRecordedLong, newLongValue, (lastRecordedLong - newLongValue)); lastRecordedInt = newIntValue; lastRecordedLong = newLongValue; } th.Join(); th2.Join(); Console.WriteLine("{0} =? {2}, {1} =? {3}", intValue, longValue, Int32.MaxValue / 2, (long)Int32.MaxValue + (Int32.MaxValue / 2)); } private static long longValue = Int32.MaxValue; private static int intValue; private static bool done = false; static void RunThread() { for (int i = 0; i < Int32.MaxValue / 4; ++i) { ++longValue; ++intValue; } done = true; } } } Results on Windows XP 32-bit: Windows XP 32-bit Intel Core2 Duo P8700 @ 2.53GHz BING(long)! 2161093208 > 2161092246, 962 BING(long)! 2162448397 > 2161273312, 1175085 BING(long)! 2270110050 > 2270109040, 1010 BING(long)! 2270115061 > 2270110059, 5002 BING(long)! 2558052223 > 2557528157, 524066 BING(long)! 2571660540 > 2571659563, 977 BING(long)! 2646433569 > 2646432557, 1012 BING(long)! 2660841714 > 2660840732, 982 BING(long)! 2661795522 > 2660841715, 953807 BING(long)! 2712855281 > 2712854239, 1042 BING(long)! 2737627472 > 2735210929, 2416543 1025780885 =? 1073741823, 3168207035 =? 3221225470 Notice how BING(int) is never written and demonstrates that 32-bit reads/writes are atomic on this 32-bit OS. Results on Windows 7 Enterprise 64-bit: Windows 7 Enterprise 64-bit Intel Core2 Duo P8700 @ 2.53GHz BING(long)! 2208482159 > 2208121217, 360942 BING(int)! 280292777 > 279704627, 588150 BING(int)! 308158865 > 308131694, 27171 BING(long)! 2549116628 > 2548884894, 231734 BING(int)! 534815527 > 534708027, 107500 BING(int)! 545113548 > 544270063, 843485 BING(long)! 2710030799 > 2709941968, 88831 BING(int)! 668662394 > 667539649, 1122745 1006355562 =? 1073741823, 3154727581 =? 3221225470 Notice that BING(long) AND BING(int) are both displayed! Why are the 32-bit operations failing, let alone the 64-bit ones?

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  • OBI already has a caching mechanism in presentation layer and BI server layer. How is the new in-memory caching better for performance?

    - by Varun
    Question: OBI already has a caching mechanism in presentation layer and BI server layer. How is the new in-memory caching better for performance? Answer: OBI Caching only speeds up what has been seen before. An In-memory data structure generated by the summary advisor is optimized to provide maximum value by accounting for the expected broad usage and drilldowns. It is possible to adapt the in-memory data to seasonality by running the summary advisor on specific workloads. Moreover, the in-memory data is created in an analytic database providing maximum performance for the large amount of memory available.

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  • How can I determine which GPU card is running at PCI Express 2.0 x16 & which is using x8?

    - by M. Tibbits
    Is there a way to determine the speed of the PCI Express connection to a specific card? I have three cards plugged in: two Nvidia GTX 480's (one at x16 & and one at x8) one Nvidia GTX 460 running at x8 Is there some way, either by a function call in C or an option to lspci that I can determine the bus speed of the graphics cards? When I only use one of the cards for my CUDA program, I'd like to use the one which is running at x16. Thanks! Note: lspci -vvv dumps out For the two GTX 480s. I don't see any differences that pertain to bus speed. 03:00.0 VGA compatible controller: nVidia Corporation Device 06c0 (rev a3) Subsystem: eVga.com. Corp. Device 1480 Control: I/O- Mem+ BusMaster+ SpecCycle- MemWINV- VGASnoop- ParErr- Stepping- SERR- FastB2B- DisINTx- Status: Cap+ 66MHz- UDF- FastB2B- ParErr- DEVSEL=fast >TAbort- <TAbort- <MAbort- >SERR- <PERR- INTx- Latency: 0 Interrupt: pin A routed to IRQ 16 Region 0: Memory at d4000000 (32-bit, non-prefetchable) [size=32M] Region 1: Memory at b0000000 (64-bit, prefetchable) [size=128M] Region 3: Memory at bc000000 (64-bit, prefetchable) [size=64M] Region 5: I/O ports at df00 [disabled] [size=128] [virtual] Expansion ROM at b8000000 [disabled] [size=512K] Capabilities: <access denied> Kernel driver in use: nvidia Kernel modules: nvidia, nvidiafb, nouveau 03:00.1 Audio device: nVidia Corporation Device 0be5 (rev a1) Subsystem: eVga.com. Corp. Device 1480 Control: I/O- Mem- BusMaster- SpecCycle- MemWINV- VGASnoop- ParErr- Stepping- SERR- FastB2B- DisINTx- Status: Cap+ 66MHz- UDF- FastB2B- ParErr- DEVSEL=fast >TAbort- <TAbort- <MAbort- >SERR- <PERR- INTx- Interrupt: pin B routed to IRQ 5 Region 0: [virtual] Memory at d7ffc000 (32-bit, non-prefetchable) [disabled] [size=16K] Capabilities: <access denied> 04:00.0 VGA compatible controller: nVidia Corporation Device 06c0 (rev a3) Subsystem: eVga.com. Corp. Device 1480 Control: I/O+ Mem+ BusMaster+ SpecCycle- MemWINV- VGASnoop- ParErr- Stepping- SERR- FastB2B- DisINTx- Status: Cap+ 66MHz- UDF- FastB2B- ParErr- DEVSEL=fast >TAbort- <TAbort- <MAbort- >SERR- <PERR- INTx- Latency: 0 Interrupt: pin A routed to IRQ 16 Region 0: Memory at dc000000 (32-bit, non-prefetchable) [size=32M] Region 1: Memory at c0000000 (64-bit, prefetchable) [size=128M] Region 3: Memory at cc000000 (64-bit, prefetchable) [size=64M] Region 5: I/O ports at cf00 [size=128] [virtual] Expansion ROM at c8000000 [disabled] [size=512K] Capabilities: <access denied> Kernel driver in use: nvidia Kernel modules: nvidia, nvidiafb, nouveau 04:00.1 Audio device: nVidia Corporation Device 0be5 (rev a1) Subsystem: eVga.com. Corp. Device 1480 Control: I/O- Mem+ BusMaster+ SpecCycle- MemWINV- VGASnoop- ParErr- Stepping- SERR- FastB2B- DisINTx- Status: Cap+ 66MHz- UDF- FastB2B- ParErr- DEVSEL=fast >TAbort- <TAbort- <MAbort- >SERR- <PERR- INTx- Latency: 0, Cache Line Size: 64 bytes Interrupt: pin B routed to IRQ 5 Region 0: Memory at dfffc000 (32-bit, non-prefetchable) [size=16K] Capabilities: <access denied> And the only differences I see relate specifically to the memory mapping: myComputer:~> diff card1 card2 3c3 < Control: I/O- Mem+ BusMaster+ SpecCycle- MemWINV- VGASnoop- ParErr- Stepping- SERR- FastB2B- DisINTx- --- > Control: I/O+ Mem+ BusMaster+ SpecCycle- MemWINV- VGASnoop- ParErr- Stepping- SERR- FastB2B- DisINTx- 7,11c7,11 < Region 0: Memory at d4000000 (32-bit, non-prefetchable) [size=32M] < Region 1: Memory at b0000000 (64-bit, prefetchable) [size=128M] < Region 3: Memory at bc000000 (64-bit, prefetchable) [size=64M] < Region 5: I/O ports at df00 [disabled] [size=128] < [virtual] Expansion ROM at b8000000 [disabled] [size=512K] --- > Region 0: Memory at dc000000 (32-bit, non-prefetchable) [size=32M] > Region 1: Memory at c0000000 (64-bit, prefetchable) [size=128M] > Region 3: Memory at cc000000 (64-bit, prefetchable) [size=64M] > Region 5: I/O ports at cf00 [size=128] > [virtual] Expansion ROM at c8000000 [disabled] [size=512K] 18c18 < Control: I/O- Mem- BusMaster- SpecCycle- MemWINV- VGASnoop- ParErr- Stepping- SERR- FastB2B- DisINTx- --- > Control: I/O- Mem+ BusMaster+ SpecCycle- MemWINV- VGASnoop- ParErr- Stepping- SERR- FastB2B- DisINTx- 19a20 > Latency: 0, Cache Line Size: 64 bytes 21c22 < Region 0: [virtual] Memory at d7ffc000 (32-bit, non-prefetchable) [disabled] [size=16K] --- > Region 0: Memory at dfffc000 (32-bit, non-prefetchable) [size=16K]

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  • Caching by in-memory dictionaries. Are we doing it all wrong?

    - by user73983
    This approach is pretty much the accepted way to do anything in our company. A simple example : when a piece of data for a customer is requested from a service, we fetch all the data for that customer(relevant part to the service) and save it in a in-memory dictionary then serve it from there on following requests(we run singleton services). Any update goes to DB, then updates the in memory dictionary. It seems all simple and harmless but as we implement more complicated business rules the cache gets out of sync and we have to deal with hard to find bugs. Sometimes we defer writing to database, keeping new data in cache till then. There are cases when we store millions of rows in memory because the table has many relations to other tables and we need to show aggregate data quickly. All this cache handling is a big part of our codebase and I sense this is not the right way to do it. All of this juggling adds too much noise to the code and it makes it hard to understand the actual business logic. However I don't think we can serve data in a reasonable amount of time if we have to hit the database every time. I am unhappy about the current situation but I don't have a better alternative. My only solution would be to use NHibernate 2nd level cache but I have nearly no experience with it. I know many campanies use Redis or MemCached heavily to gain performance but I have no idea how I would integrate them into our system. I also don't know if they can perform better than in-memory data structures and queries. Are there any alternative approaches that I should look into?

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  • General monitoring for SQL Server Analysis Services using Performance Monitor

    - by Testas
    A recent customer engagement required a setup of a monitoring solution for SSAS, due to the time restrictions placed upon this, native Windows Performance Monitor (Perfmon) and SQL Server Profiler Monitoring Tools was used as using a third party tool would have meant the customer providing an additional monitoring server that was not available.I wanted to outline the performance monitoring counters that was used to monitor the system on which SSAS was running. Due to the slow query performance that was occurring during certain scenarios, perfmon was used to establish if any pressure was being placed on the Disk, CPU or Memory subsystem when concurrent connections access the same query, and Profiler to pinpoint how the query was being managed within SSAS, profiler I will leave for another blogThis guide is not designed to provide a definitive list of what should be used when monitoring SSAS, different situations may require the addition or removal of counters as presented by the situation. However I hope that it serves as a good basis for starting your monitoring of SSAS. I would also like to acknowledge Chris Webb’s awesome chapters from “Expert Cube Development” that also helped shape my monitoring strategy:http://cwebbbi.spaces.live.com/blog/cns!7B84B0F2C239489A!6657.entrySimulating ConnectionsTo simulate the additional connections to the SSAS server whilst monitoring, I used ascmd to simulate multiple connections to the typical and worse performing queries that were identified by the customer. A similar sript can be downloaded from codeplex at http://www.codeplex.com/SQLSrvAnalysisSrvcs.     File name: ASCMD_StressTestingScripts.zip. Performance MonitorWithin performance monitor,  a counter log was created that contained the list of counters below. The important point to note when running the counter log is that the RUN AS property within the counter log properties should be changed to an account that has rights to the SSAS instance when monitoring MSAS counters. Failure to do so means that the counter log runs under the system account, no errors or warning are given while running the counter log, and it is not until you need to view the MSAS counters that they will not be displayed if run under the default account that has no right to SSAS. If your connection simulation takes hours, this could prove quite frustrating if not done beforehand JThe counters used……  Object Counter Instance Justification System Processor Queue legnth N/A Indicates how many threads are waiting for execution against the processor. If this counter is consistently higher than around 5 when processor utilization approaches 100%, then this is a good indication that there is more work (active threads) available (ready for execution) than the machine's processors are able to handle. System Context Switches/sec N/A Measures how frequently the processor has to switch from user- to kernel-mode to handle a request from a thread running in user mode. The heavier the workload running on your machine, the higher this counter will generally be, but over long term the value of this counter should remain fairly constant. If this counter suddenly starts increasing however, it may be an indicating of a malfunctioning device, especially if the Processor\Interrupts/sec\(_Total) counter on your machine shows a similar unexplained increase Process % Processor Time sqlservr Definately should be used if Processor\% Processor Time\(_Total) is maxing at 100% to assess the effect of the SQL Server process on the processor Process % Processor Time msmdsrv Definately should be used if Processor\% Processor Time\(_Total) is maxing at 100% to assess the effect of the SQL Server process on the processor Process Working Set sqlservr If the Memory\Available bytes counter is decreaing this counter can be run to indicate if the process is consuming larger and larger amounts of RAM. Process(instance)\Working Set measures the size of the working set for each process, which indicates the number of allocated pages the process can address without generating a page fault. Process Working Set msmdsrv If the Memory\Available bytes counter is decreaing this counter can be run to indicate if the process is consuming larger and larger amounts of RAM. Process(instance)\Working Set measures the size of the working set for each process, which indicates the number of allocated pages the process can address without generating a page fault. Processor % Processor Time _Total and individual cores measures the total utilization of your processor by all running processes. If multi-proc then be mindful only an average is provided Processor % Privileged Time _Total To see how the OS is handling basic IO requests. If kernel mode utilization is high, your machine is likely underpowered as it's too busy handling basic OS housekeeping functions to be able to effectively run other applications. Processor % User Time _Total To see how the applications is interacting from a processor perspective, a high percentage utilisation determine that the server is dealing with too many apps and may require increasing thje hardware or scaling out Processor Interrupts/sec _Total  The average rate, in incidents per second, at which the processor received and serviced hardware interrupts. Shoulr be consistant over time but a sudden unexplained increase could indicate a device malfunction which can be confirmed using the System\Context Switches/sec counter Memory Pages/sec N/A Indicates the rate at which pages are read from or written to disk to resolve hard page faults. This counter is a primary indicator of the kinds of faults that cause system-wide delays, this is the primary counter to watch for indication of possible insufficient RAM to meet your server's needs. A good idea here is to configure a perfmon alert that triggers when the number of pages per second exceeds 50 per paging disk on your system. May also want to see the configuration of the page file on the Server Memory Available Mbytes N/A is the amount of physical memory, in bytes, available to processes running on the computer. if this counter is greater than 10% of the actual RAM in your machine then you probably have more than enough RAM. monitor it regularly to see if any downward trend develops, and set an alert to trigger if it drops below 2% of the installed RAM. Physical Disk Disk Transfers/sec for each physical disk If it goes above 10 disk I/Os per second then you've got poor response time for your disk. Physical Disk Idle Time _total If Disk Transfers/sec is above  25 disk I/Os per second use this counter. which measures the percent time that your hard disk is idle during the measurement interval, and if you see this counter fall below 20% then you've likely got read/write requests queuing up for your disk which is unable to service these requests in a timely fashion. Physical Disk Disk queue legnth For the OLAP and SQL physical disk A value that is consistently less than 2 means that the disk system is handling the IO requests against the physical disk Network Interface Bytes Total/sec For the NIC Should be monitored over a period of time to see if there is anb increase/decrease in network utilisation Network Interface Current Bandwidth For the NIC is an estimate of the current bandwidth of the network interface in bits per second (BPS). MSAS 2005: Memory Memory Limit High KB N/A Shows (as a percentage) the high memory limit configured for SSAS in C:\Program Files\Microsoft SQL Server\MSAS10.MSSQLSERVER\OLAP\Config\msmdsrv.ini MSAS 2005: Memory Memory Limit Low KB N/A Shows (as a percentage) the low memory limit configured for SSAS in C:\Program Files\Microsoft SQL Server\MSAS10.MSSQLSERVER\OLAP\Config\msmdsrv.ini MSAS 2005: Memory Memory Usage KB N/A Displays the memory usage of the server process. MSAS 2005: Memory File Store KB N/A Displays the amount of memory that is reserved for the Cache. Note if total memory limit in the msmdsrv.ini is set to 0, no memory is reserved for the cache MSAS 2005: Storage Engine Query Queries from Cache Direct / sec N/A Displays the rate of queries answered from the cache directly MSAS 2005: Storage Engine Query Queries from Cache Filtered / Sec N/A Displays the Rate of queries answered by filtering existing cache entry. MSAS 2005: Storage Engine Query Queries from File / Sec N/A Displays the Rate of queries answered from files. MSAS 2005: Storage Engine Query Average time /query N/A Displays the average time of a query MSAS 2005: Connection Current connections N/A Displays the number of connections against the SSAS instance MSAS 2005: Connection Requests / sec N/A Displays the rate of query requests per second MSAS 2005: Locks Current Lock Waits N/A Displays thhe number of connections waiting on a lock MSAS 2005: Threads Query Pool job queue Length N/A The number of queries in the job queue MSAS 2005:Proc Aggregations Temp file bytes written/sec N/A Shows the number of bytes of data processed in a temporary file MSAS 2005:Proc Aggregations Temp file rows written/sec N/A Shows the number of bytes of data processed in a temporary file 

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