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  • Weird IIS with Windows Authentication + IE problem

    - by Paulius Maruška
    I have a website running on IIS and using Windows Authentication. All users that are configured to get access to the site are form a AD domain (not local users). In the properties of a Website, I have set to use the AD domain as the realm. Now, when using Firefox, Safari or Chrome - Everything is fine. When the user tries to open the site, he get's the login box. he enters simply "username" and "password" (let's pretend that it's an actual login and password :P) and he get's into the site. When using IE, however, things get nasty. When the user tries to open the site - he get's the login box. User enters the "username" and "password" again, but those get rejected! And when the second time login box pops up - it has the username filled in as "web-server-domain-name\username" which is wrong, because web-server-domain-name is not the domain where all users reside (it's "ad-domain"). I've spent days trying to figure out what's going on... Note, that if I manually enter "ad-domain\username" - I get accepted into the site without problems. So, my guess is that IE sends wrong username if domain is not specified. Anyway, IE is the only browser that triggers this behavior! Is it possible to do a server-side fix? Maybe it's possible to somehow auto-map the users to AD users? If it's not solvable server-side - is there a client-side fix for this? Thank you. PS: I'm more of a programmer than a sys-admin, so configuring servers isn't the strong side of mine... :P UPDATE: @Evan: Yes, "Digest authentication for Windows domain servers" is also enabled. @Eric: IIS version is 6.0. The authentication methods enabled are: Integrated and digest - all other methods are disabled. As for the security log. I looked at it, when doing "username" and "password" login in Chrome/Firefox and when doing "ad-domain\username" and "password" login from IE - the generated log messages are the same (I see no difference, anyway). When entering "username" and "password" I don't see any errors in the security (or any other) log, so can't tell what method it's trying to use. UPDATE 2: As suggested by Eric in the comments - I played around with Fiddler... While playing with it, I noticed, that when "username" and "password" is entered in FF and IE - the "Authorization" header value (encrypted) sent by IE is longer (almost two times) than one sent by FF. I tried to disable Windows Integrated authentication and only leave the Digest enabled - that fixed the problem (meaning, IE used the right realm just like other browsers), but that caused bazillion other problems with my site, because with Digest - user impersonation on the server doesn't work (that causes problems, when connecting to database etc). Any ideas?

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  • Postfix + SASLAUTHD + MySQL authentication problems

    - by Or W
    I've been trying to sort this out for the past 6 hours or so, this is the error message I'm facing (Running CentOS x64): /var/log/maillog: Jun 22 20:42:49 ptroa postfix/smtpd[10130]: warning: SASL authentication failure: Password verification failed Jun 22 20:42:49 ptroa postfix/smtpd[10130]: warning: bzq-79-177-192-133.red.bezeqint.net[79.177.192.133]: SASL PLAIN authentication failed: authentication failure Jun 22 20:42:49 ptroa postfix/smtpd[10130]: warning: bzq-79-177-192-133.red.bezeqint.net[79.177.192.133]: SASL LOGIN authentication failed: authentication failure /var/log/messages: Jun 22 20:15:38 ptroa saslauthd[9401]: do_auth : auth failure: [user=myuser] [service=smtp] [realm=domain.com] [mech=pam] [reason=PAM auth error] I have dovecot installed as well and I'm able to receive emails via the MySQL authentication. The problem is when I'm trying to use SMTP to send out emails. Some config files: /etc/postfix/main.cf: # See /usr/share/postfix/main.cf.dist for a commented, more complete version # Debian specific: Specifying a file name will cause the first # line of that file to be used as the name. The Debian default # is /etc/mailname. myorigin = /etc/mailname smtpd_banner = Server Message biff = no # appending .domain is the MUA's job. append_dot_mydomain = no # Uncomment the next line to generate "delayed mail" warnings #delay_warning_time = 4h readme_directory = /usr/share/doc/postfix # TLS parameters smtpd_tls_cert_file = /etc/postfix/smtpd.cert smtpd_tls_key_file = /etc/postfix/smtpd.key smtpd_use_tls = yes smtpd_tls_session_cache_database = btree:${data_directory}/smtpd_scache smtp_tls_session_cache_database = btree:${data_directory}/smtp_scache # See /usr/share/doc/postfix/TLS_README.gz in the postfix-doc package for # information on enabling SSL in the smtp client. myhostname = domain.com alias_maps = hash:/etc/aliases alias_database = hash:/etc/aliases myorigin = /etc/mailname mydestination = relayhost = mynetworks = 127.0.0.0/8 [::ffff:127.0.0.0]/104 [::1]/128 mailbox_size_limit = 0 recipient_delimiter = + inet_interfaces = all html_directory = /usr/share/doc/postfix/html message_size_limit = 30720000 virtual_alias_domains = virtual_alias_maps = proxy:mysql:/etc/postfix/mysql-virtual_forwardings.cf, mysql:/etc/postfix/mysql-virtual_email2email.cf virtual_mailbox_domains = proxy:mysql:/etc/postfix/mysql-virtual_domains.cf virtual_mailbox_maps = proxy:mysql:/etc/postfix/mysql-virtual_mailboxes.cf virtual_mailbox_base = /home/vmail virtual_uid_maps = static:5000 virtual_gid_maps = static:5000 smtpd_sasl_auth_enable = yes broken_sasl_auth_clients = yes smtpd_sasl_authenticated_header = yes smtpd_recipient_restrictions = permit_mynetworks, permit_sasl_authenticated, reject_unauth_destination virtual_create_maildirsize = yes virtual_maildir_extended = yes proxy_read_maps = $local_recipient_maps $mydestination $virtual_alias_maps $virtual_alias_domains $virtual_mailbox_maps $virtual_mailbox_domains $relay_recipient_maps $relay_domains $canonical_maps $sender_canonical_maps $recipient_cano$ virtual_transport = dovecot dovecot_destination_recipient_limit = 1 /etc/default/saslauthd: START=yes DESC="SASL Authentication Daemon" NAME="saslauthd" MECHANISMS="pam" MECH_OPTIONS="" THREADS=5 OPTIONS="-c -m /var/spool/postfix/var/run/saslauthd -r" /etc/pam.d/smtp: #%PAM-1.0 #auth include password-auth #account include password-auth auth required pam_mysql.so user=mail_admin passwd=password host=127.0.0.1 db=mail table=users usercolumn=email passwdcolumn=password crypt=1 verbose=1 account sufficient pam_mysql.so user=mail_admin passwd=password host=127.0.0.1 db=mail table=users usercolumn=email passwdcolumn=password crypt=1 verbose=1

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  • IE7 textbox onfocus problem

    - by Craig
    Because IE won't do document.getElementById(ID).setAttribute('type','password') I've re-engineered the way the password field woirks on this site: http://devdae.dialanexchange.com/Default.aspx so it works in accordance with this idea: http://www.folksonomy.org/2009/01/12/changing-input-type-from-text-to-password-in-internet-explorer-hack/ It works fine in IE8 and FF3. It breaks in IE7 just as you click into the password field. I'm now tearing my hair out. Can anyone give me a clue what's wrong as IE7's diagnosis is just "Object expected, code 0"?

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  • How do I run a sudo command in Emacs?

    - by Inaimathi
    I tried using shell-command, but it just does something like this: Sudo password: incorrect, try again. Sudo password: incorrect, try again. Sudo password: incorrect, try again. Failed three attempts. without actually asking for a password. I don't want to have to start up Emacs using sudo emacs, but I guess that's an option if nothing else will work.

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  • jQuery + Dialog Form Validation

    - by Panther24
    Hi, I have a jQuery Dialog form and on submit I'm trying to validate the fields. I'm using http://docs.jquery.com/Plugins/Validation to validate. In this I'm facing an issue, the validate function is not being called. I'm posting some snippet of my code $("#register-dialog-form").dialog({ autoOpen: false, height: 350, width: 450, modal: true, buttons: { 'Register': function() { $("#registerFrm").validate({ rules: { accountid: "required", name: { required: true, minlength: 5 }, username: { required: true, minlength: 5 }, password: { required: true, minlength: 5 } }, messages: { firstname: "Please enter your firstname", accountid: "Please enter the lastname", name: "Please enter a user friendly name", username: { required: "Please enter a username", minlength: jQuery.format("Enter at least {0} characters") }, password: { required: "Please provide a password", minlength: jQuery.format("Password must be at least {0} characters long") } } }); //****************** //TODO: Need to submit my form here //****************** $(this).dialog('close'); }, Cancel: function() { $(this).dialog('close'); } }, close: function() { //$('registerFrm').clearForm(); } }); Can someone please tell me what I'm doing wrong here. I've also tried to put the validation into $(document).ready(function() {}, but with no success. Here is the html code <div id="register-dialog-form" title="Register Account - Master" align="center" style="display: none"> <s:form name="registerFrm" id="registerFrm" action="registermaster" method="POST"> <table width="90%" border="0" class="ui-widget"> <tr> <td> <s:textfield label="Account Id" name="accountid" id="accountid" cssClass="text ui-widget-content ui-corner-all" /> </td> </tr> <tr> <td> <s:textfield label="Name" name="name" id="name" cssClass="text ui-widget-content ui-corner-all" /> </td> </tr> <tr> <td> <s:textfield label="Username" name="username" id="username" cssClass="text ui-widget-content ui-corner-all" /> </td> </tr> <tr> <td> <s:password label="Password" name="password" id="password" cssClass="text ui-widget-content ui-corner-all" /> </td> </tr> </table> </s:form> </div><!--End of RegisterAcc form-->

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  • VB.Net Split A Group Of Text

    - by Ben
    I am looking to split up multiple lines of text to single them out, for example: Url/Host:ftp://server.com/1 Login:Admin1 Password:Password1 Url/Host:ftp://server.com/2 Login:Admin2 Password:Password2 Url/Host:ftp://server.com/3 Login:Admin3 Password:Password3 How can I split each section into a different textbox, so that section one would be put into TextBox1.Text on its own: Url/Host:ftp://server.com/1 Login:Admin1 Password:Password1 Thanks in advance :)!

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  • How can I get an Active Directory data code from System.DirectoryServices[.Protocols]?

    - by Alex Waddell
    When using .Protocols, I can run the following pseudocode to authenticate to an AD: try { LdapConnection c = new LdapConnection("User", "Password"); c.Bind(); } catch (LdapException le) { Debug.WriteLine(le.ResultCode); } This code will allow me to get the "Invalid Credentials" error string, and the AD code "49", but I need to get the additional data errors similar to an LDAP Java client : [LDAP: error code 49 - 80090308: LdapErr: DSID-0C09030F, comment: AcceptSecurityContext error, data **525**, vece ] 525 – user not found 52e – invalid credentials (bad password) 530 – logon time restriction 532 – password expired 533 – account disabled 701 – account expired 773 – user must reset password

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  • A problem in my windows boot menu

    - by user210332
    Hi, One i had kept a supervisor password to my windows boot screen, but now i forgot that password, Now i am unable to access the boot menu since its asking the password, all menu options are disabled. Is it possible to remove that password and can i get the boot menu default settings back? Processor: Intel Pentium dual core (2) OS : XP Thanks in Advance,

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  • Why does MS SQL Mgmt Studio Express keep forgetting my passwords?

    - by Ryan
    I have about had it with this tool, I check the save password box at the login dialogue but it just doesn't work. Sometimes it will for a few days, and then the password will just be gone. Nearly every time I load this thing up I have to track down the password again and type it in. Is there some password rule in the database that would be causing this? This is driving me absolutely crazy.

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  • How to pass parameters for OPENDATASOURCE

    - by Rapunzo
    I can connect to a linked server with this: SELECT testNo, soruTuruId, soruNo, cevap , degerlendirenTcNo, degerlendirilenTcNo FROM OPENDATASOURCE('SQLOLEDB', 'Data Source=192.168.150.42;User ID=readerUser;Password=1').akreditasyon.dbo.tblPerfCevap But I have to pass the password as parameter. and I try like this: SET @connectionString = 'Data Source=192.168.150.42;User ID=readerUser;Password='+@pw SELECT testNo, soruTuruId, soruNo, cevap , degerlendirenTcNo, degerlendirilenTcNo FROM OPENDATASOURCE('SQLOLEDB', @connectionString ).akreditasyon.dbo.tblPerfCevap and SELECT testNo, soruTuruId, soruNo, cevap , degerlendirenTcNo, degerlendirilenTcNo FROM OPENDATASOURCE('SQLOLEDB', 'Data Source=192.168.150.42;User ID=readerUser;Password='+@pw ).akreditasyon.dbo.tblPerfCevap but didnt work:S does anyone have an idea?

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  • Java MessageDigest result does not stay constant

    - by user344146
    I've got this function for encrypting passwords in Java, but somehow when I call MessageDigest, it returns a different result every time even though I call it with the same password. I wonder if I am initializing it wrong somehow. public String encrypt (String password) { MessageDigest md = MessageDigest.getInstance("SHA-1"); md.reset(); md.update(password.getBytes(Charset.forName("utf-8")),0,password.length()); String res = md.digest().toString(); }

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  • Page not redirecting properly(php)

    - by user225269
    I want to do the login page this way so that I won't be having trouble posting the username in the userpage. But everytime I try to access login.php. I get an error in firefox, that the page is not redirecting properly. What do I do? This works when I separate them into two. Into something like, login.php and verifylogin.php as the form action. But if I do it like this, I get redirection errors: <?php $host="localhost"; $username="root"; $password="nitoryolai123$%^"; $db_name="school"; $tbl_name="users"; mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $uname = mysql_real_escape_string($_POST['username']); $pword = mysql_real_escape_string($_POST['password']); $SQL = "SELECT * FROM users WHERE username = '$uname' AND password = '$pword'"; $result = mysql_query($SQL); $num_rows = mysql_num_rows($result); if ($result) { if ($num_rows > 0) { session_start(); $_SESSION['login'] = "1"; header ("Location: userpage.php"); } else { session_start(); $_SESSION['login'] = ""; header ("Location: login.php"); } } else { $errorMessage = "Error logging on"; } ?> <tr> <form name="form1" method="post" action="login.php"> <td> <table> <tr> <td><strong><font size="2">Login User</strong></td> </tr> <tr> <td width="30" height="35"><font size="2">Username:</td> <td width="30"><input name="username" type="text" id="username" maxlength="17"></td> </tr> <tr> <td width="30" height="35" ><font size="2">Password:</td> <td width="30"><input name="password" type="password" id="password" maxlength="17"></td> </tr> <td><td align="right" width="30"><input type="submit" name="Submit" value="Submit" /></td> <td><input type="reset" name="Reset" value="Reset"></td></td> </tr> </form> please help, thanks.

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  • Random TCP Resets

    - by allenwei
    We got randomly TCP "reset" error when we send request to remote server. Log from remote server Cisco TCP Connection Terminated,Nov 05 14:43:39 EST: %ASA-session-6-302014: Teardown TCP connection 640068283 for Outside:xxxx to xxxx duration 0:00:00 bytes 4160 TCP Reset-O One my local machine I saw when I use netstat 100703 connections reset due to unexpected data 324186 connections reset due to early user close I also use tcpdump to see what's wrong with it, I saw xxxx.https: Flags [R.], seq 290, ack 1369, win 136, options [nop,nop,TS val 2871790533 ecr 1897173283], length 0 The problem just happened today, we didn't change anything on our server. Anyone know what's wrong with it? Is it related to code we wrote send out request or related to linux configuration?

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  • .htaccess authentication from a php script to prevent a browser dialog box

    - by digitalbart
    Using php I authenticate a user, then behind the scenes,they are then again authenticated a second time with a single .htaccess username & password. This would be the same for all users, but I would not want them to have to enter a username and password again and they would now be allowed to enter the password protected directory. I prefer not to use http://username@password:somedomain.com. Any thoughts?

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  • ProxyPass or intercept web requests .NET

    - by JerryO
    I have got a .NET winform application that uses a Web Mapping Service that is password protected. Unfortunately I cannot attach a username and password to requests, ( the request are generated from a GIS mapcontrol) I can think of two ways around it Intercept all web requests from my .NET app and add a username/password Set up an Apache webserver and use proxypass to pass along my request adding a username/password Does anyone know how to do either of these?

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  • Error in create back up in mysql through java program

    - by Arivu2020
    Runtime.getRuntime().exec("C:\mysql\bin\mysqldump -u root -pmypassword Databasename -r C:/backup.sql"); I am using this code to create back up from my sql. but It creates the empty file in the path.Because it is waiting in the command prompt to get the password. How can i give password to it Using command prompt directly when i press enter after typing, it asks password.After giving password,It creates the backup.Give me any solution for this Thanks in advance

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  • SQL SERVER – Capturing Wait Types and Wait Stats Information at Interval – Wait Type – Day 5 of 28

    - by pinaldave
    Earlier, I have tried to cover some important points about wait stats in detail. Here are some points that we had covered earlier. DMV related to wait stats reset when we reset SQL Server services DMV related to wait stats reset when we manually reset the wait types However, at times, there is a need of making this data persistent so that we can take a look at them later on. Sometimes, performance tuning experts do some modifications to the server and try to measure the wait stats at that point of time and after some duration. I use the following method to measure the wait stats over the time. -- Create Table CREATE TABLE [MyWaitStatTable]( [wait_type] [nvarchar](60) NOT NULL, [waiting_tasks_count] [bigint] NOT NULL, [wait_time_ms] [bigint] NOT NULL, [max_wait_time_ms] [bigint] NOT NULL, [signal_wait_time_ms] [bigint] NOT NULL, [CurrentDateTime] DATETIME NOT NULL, [Flag] INT ) GO -- Populate Table at Time 1 INSERT INTO MyWaitStatTable ([wait_type],[waiting_tasks_count],[wait_time_ms],[max_wait_time_ms],[signal_wait_time_ms], [CurrentDateTime],[Flag]) SELECT [wait_type],[waiting_tasks_count],[wait_time_ms],[max_wait_time_ms],[signal_wait_time_ms], GETDATE(), 1 FROM sys.dm_os_wait_stats GO ----- Desired Delay (for one hour) WAITFOR DELAY '01:00:00' -- Populate Table at Time 2 INSERT INTO MyWaitStatTable ([wait_type],[waiting_tasks_count],[wait_time_ms],[max_wait_time_ms],[signal_wait_time_ms], [CurrentDateTime],[Flag]) SELECT [wait_type],[waiting_tasks_count],[wait_time_ms],[max_wait_time_ms],[signal_wait_time_ms], GETDATE(), 2 FROM sys.dm_os_wait_stats GO -- Check the difference between Time 1 and Time 2 SELECT T1.wait_type, T1.wait_time_ms Original_WaitTime, T2.wait_time_ms LaterWaitTime, (T2.wait_time_ms - T1.wait_time_ms) DiffenceWaitTime FROM MyWaitStatTable T1 INNER JOIN MyWaitStatTable T2 ON T1.wait_type = T2.wait_type WHERE T2.wait_time_ms > T1.wait_time_ms AND T1.Flag = 1 AND T2.Flag = 2 ORDER BY DiffenceWaitTime DESC GO -- Clean up DROP TABLE MyWaitStatTable GO If you notice the script, I have used an additional column called flag. I use it to find out when I have captured the wait stats and then use it in my SELECT query to SELECT wait stats related to that time group. Many times, I select more than 5 or 6 different set of wait stats and I find this method very convenient to find the difference between wait stats. In a future blog post, we will talk about specific wait stats. Read all the post in the Wait Types and Queue series. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, PostADay, SQL, SQL Authority, SQL DMV, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, SQL Wait Stats, SQL Wait Types, T SQL, Technology

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  • Setting up RADIUS + LDAP for WPA2 on Ubuntu

    - by Morten Siebuhr
    I'm setting up a wireless network for ~150 users. In short, I'm looking for a guide to set RADIUS server to authenticate WPA2 against a LDAP. On Ubuntu. I got a working LDAP, but as it is not in production use, it can very easily be adapted to whatever changes this project may require. I've been looking at FreeRADIUS, but any RADIUS server will do. We got a separate physical network just for WiFi, so not too many worries about security on that front. Our AP's are HP's low end enterprise stuff - they seem to support whatever you can think of. All Ubuntu Server, baby! And the bad news: I now somebody less knowledgeable than me will eventually take over administration, so the setup has to be as "trivial" as possible. So far, our setup is based only on software from the Ubuntu repositories, with exception of our LDAP administration web application and a few small special scripts. So no "fetch package X, untar, ./configure"-things if avoidable. UPDATE 2009-08-18: While I found several useful resources, there is one serious obstacle: Ignoring EAP-Type/tls because we do not have OpenSSL support. Ignoring EAP-Type/ttls because we do not have OpenSSL support. Ignoring EAP-Type/peap because we do not have OpenSSL support. Basically the Ubuntu version of FreeRADIUS does not support SSL (bug 183840), which makes all the secure EAP-types useless. Bummer. But some useful documentation for anybody interested: http://vuksan.com/linux/dot1x/802-1x-LDAP.html http://tldp.org/HOWTO/html_single/8021X-HOWTO/#confradius UPDATE 2009-08-19: I ended up compiling my own FreeRADIUS package yesterday evening - there's a really good recipe at http://www.linuxinsight.com/building-debian-freeradius-package-with-eap-tls-ttls-peap-support.html (See the comments to the post for updated instructions). I got a certificate from http://CACert.org (you should probably get a "real" cert if possible) Then I followed the instructions at http://vuksan.com/linux/dot1x/802-1x-LDAP.html. This links to http://tldp.org/HOWTO/html_single/8021X-HOWTO/, which is a very worthwhile read if you want to know how WiFi security works. UPDATE 2009-08-27: After following the above guide, I've managed to get FreeRADIUS to talk to LDAP: I've created a test user in LDAP, with the password mr2Yx36M - this gives an LDAP entry roughly of: uid: testuser sambaLMPassword: CF3D6F8A92967E0FE72C57EF50F76A05 sambaNTPassword: DA44187ECA97B7C14A22F29F52BEBD90 userPassword: {SSHA}Z0SwaKO5tuGxgxtceRDjiDGFy6bRL6ja When using radtest, I can connect fine: > radtest testuser "mr2Yx36N" sbhr.dk 0 radius-private-password Sending Access-Request of id 215 to 130.225.235.6 port 1812 User-Name = "msiebuhr" User-Password = "mr2Yx36N" NAS-IP-Address = 127.0.1.1 NAS-Port = 0 rad_recv: Access-Accept packet from host 130.225.235.6 port 1812, id=215, length=20 > But when I try through the AP, it doesn't fly - while it does confirm that it figures out the NT and LM passwords: ... rlm_ldap: sambaNTPassword -> NT-Password == 0x4441343431383745434139374237433134413232463239463532424542443930 rlm_ldap: sambaLMPassword -> LM-Password == 0x4346334436463841393239363745304645373243353745463530463736413035 [ldap] looking for reply items in directory... WARNING: No "known good" password was found in LDAP. Are you sure that the user is configured correctly? [ldap] user testuser authorized to use remote access rlm_ldap: ldap_release_conn: Release Id: 0 ++[ldap] returns ok ++[expiration] returns noop ++[logintime] returns noop [pap] Normalizing NT-Password from hex encoding [pap] Normalizing LM-Password from hex encoding ... It is clear that the NT and LM passwords differ from the above, yet the message [ldap] user testuser authorized to use remote access - and the user is later rejected...

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  • How could I stop ssh offering a wrong key?

    - by Alvaro Maceda
    (This is a problem with ssh, not gitolite) I've configured gitolite on my home server (ubuntu 12.04 server, open-ssh). I want an special identityfile to administer the repositories, so I need to access throught ssh to my own host ussing two different identity keys. This is the content of my .ssh/config file: Host gitadmin.gammu.com User git IdentityFile /home/alvaro/.ssh/id_gitolite_mantra Host git.gammu.com User git IdentityFile /home/alvaro/.ssh/id_alvaro_mantra This is the content of my hosts file: # Git 127.0.0.1 gitadmin.gammu.com 127.0.0.1 git.gammu.com So I should be able to communicate with gitolite this way to access with the "normal" account: $ssh git.gammu.com and this way to access with the administrative account: $ssh gitadmin.gammu.com When I try to access with the normal account, all is ok: alvaro@mantra:~/.ssh$ ssh git.gammu.com PTY allocation request failed on channel 0 hello alvaro, this is gitolite 2.2-1 (Debian) running on git 1.7.9.5 the gitolite config gives you the following access: @R_ @W_ testing Connection to git.gammu.com closed. When I do the same with the administrative account: alvaro@mantra:~$ ssh gitadmin.gammu.com PTY allocation request failed on channel 0 hello alvaro, this is gitolite 2.2-1 (Debian) running on git 1.7.9.5 the gitolite config gives you the following access: @R_ @W_ testing Connection to gitadmin.gammu.com closed. It should show the administrative repository. If I launch ssh with verbose option: ssh -vvv gitadmin.gammu.com ... debug1: SSH2_MSG_SERVICE_REQUEST sent debug2: service_accept: ssh-userauth debug1: SSH2_MSG_SERVICE_ACCEPT received debug2: key: /home/alvaro/.ssh/id_alvaro_mantra (0x7f7cb6c0fbc0) debug2: key: /home/alvaro/.ssh/id_gitolite_mantra (0x7f7cb6c044d0) debug1: Authentications that can continue: publickey,password debug3: start over, passed a different list publickey,password debug3: preferred gssapi-keyex,gssapi-with-mic,publickey,keyboard-interactive,password debug3: authmethod_lookup publickey debug3: remaining preferred: keyboard-interactive,password debug3: authmethod_is_enabled publickey debug1: Next authentication method: publickey debug1: Offering RSA public key: /home/alvaro/.ssh/id_alvaro_mantra debug3: send_pubkey_test debug2: we sent a publickey packet, wait for reply debug1: Server accepts key: pkalg ssh-rsa blen 279 ... It's offering the key id_alvaro_mantra, and it should'nt!! The same happens when I specify the key with the -i option: ssh -i /home/alvaro/.ssh/id_gitolite_mantra -vvv gitadmin.gammu.com ... debug1: SSH2_MSG_SERVICE_REQUEST sent debug2: service_accept: ssh-userauth debug1: SSH2_MSG_SERVICE_ACCEPT received debug2: key: /home/alvaro/.ssh/id_alvaro_mantra (0x7fa365237f90) debug2: key: /home/alvaro/.ssh/id_gitolite_mantra (0x7fa365230550) debug2: key: /home/alvaro/.ssh/id_gitolite_mantra (0x7fa365231050) debug1: Authentications that can continue: publickey,password debug3: start over, passed a different list publickey,password debug3: preferred gssapi-keyex,gssapi-with-mic,publickey,keyboard-interactive,password debug3: authmethod_lookup publickey debug3: remaining preferred: keyboard-interactive,password debug3: authmethod_is_enabled publickey debug1: Next authentication method: publickey debug1: Offering RSA public key: /home/alvaro/.ssh/id_alvaro_mantra debug3: send_pubkey_test debug2: we sent a publickey packet, wait for reply debug1: Server accepts key: pkalg ssh-rsa blen 279 debug2: input_userauth_pk_ok: fp 36:b1:43:36:af:4f:00:e5:e1:39:50:7e:07:80:14:26 debug3: sign_and_send_pubkey: RSA 36:b1:43:36:af:4f:00:e5:e1:39:50:7e:07:80:14:26 debug1: Authentication succeeded (publickey). ... What the hell is happening??? I'm missing something, but I can't find what. These are the contents of my home dir: -rw-rw-r-- 1 alvaro alvaro 395 nov 14 18:00 authorized_keys -rw-rw-r-- 1 alvaro alvaro 326 nov 21 10:21 config -rw------- 1 alvaro alvaro 137 nov 20 20:26 environment -rw------- 1 alvaro alvaro 1766 nov 20 21:41 id_alvaromaceda.es -rw-r--r-- 1 alvaro alvaro 404 nov 20 21:41 id_alvaromaceda.es.pub -rw------- 1 alvaro alvaro 1766 nov 14 17:59 id_alvaro_mantra -rw-r--r-- 1 alvaro alvaro 395 nov 14 17:59 id_alvaro_mantra.pub -rw------- 1 alvaro alvaro 771 nov 14 18:03 id_developer_mantra -rw------- 1 alvaro alvaro 1679 nov 20 12:37 id_dos_pruebasgit -rw-r--r-- 1 alvaro alvaro 395 nov 20 12:37 id_dos_pruebasgit.pub -rw------- 1 alvaro alvaro 1679 nov 20 12:46 id_gitolite_mantra -rw-r--r-- 1 alvaro alvaro 397 nov 20 12:46 id_gitolite_mantra.pub -rw------- 1 alvaro alvaro 1675 nov 20 21:44 id_gitpruebas.es -rw-r--r-- 1 alvaro alvaro 408 nov 20 21:44 id_gitpruebas.es.pub -rw------- 1 alvaro alvaro 1679 nov 20 12:34 id_uno_pruebasgit -rw-r--r-- 1 alvaro alvaro 395 nov 20 12:34 id_uno_pruebasgit.pub -rw-r--r-- 1 alvaro alvaro 2434 nov 21 10:11 known_hosts There are a bunch of other keys which aren't offered... why id_alvaro_mantra is offered and not the other keys? I can't understand. I need some help, don't know where to look....

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  • Jquery append input for 2 different input-sections

    - by Email
    Hi i use the following simple jquery script to append input. Source http://muiomuio.com/web-design/add-remove-items-with-jquery <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>Add and Remove - jQuery tutorial</title> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js" type="text/javascript"></script> <script type="text/javascript"> $(function() { var i = $('input').size() + 1; $('a.add').click(function() { $('<p><input type="text" value="input ' + i + '" name="input_field'+ i +'" /></p>').animate({ opacity: "show" }, "slow").appendTo('#inputs'); i++; }); $('a.remove').click(function() { if(i > 2) { $('input:last').animate({opacity:"hide"}, "slow").remove(); i--; } }); $('a.reset').click(function() { while(i > 2) { $('input:last').remove(); i--; } }); }); </script> </head> <body> <h1>Add / remove text fields from webform</h1> <a href="#" class="add"><img src="add.png" width="24" height="24" alt="add" title="add input" /></a> <a href="#" class="remove"><img src="remove.png" width="24" height="24" alt="remove input" /></a> <a href="#" class="reset"><img src="reset.png" width="24" height="24" alt="reset" /></a> <div id="inputs"> <p> <input type="text" value="input 1" name="input_field1"> </p> </div> </div> </body> </html> I know want to add more input fields so i add this html <div id="outputs"> <p> <input type="text" value="output 1" name="output_field1"> </p> how can i achieve that the var i = $('input').size() + 1; will be individually for every input section? EDITED: the full script is the following. copy and paste will get you a full clone of mine. Problem still exists <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>Add and Remove - jQuery tutorial</title> <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js" type="text/javascript"></script> <script type="text/javascript"> $(function() { var i = $('input').size() + 1; $('a.add').click(function() { $('<p><input type="text" value="input ' + i + '" name="input_field'+ i +'" /></p>').animate({ opacity: "show" }, "slow").appendTo('#inputs'); i++; }); $('a.remove').click(function() { if(i > 2) { $('input:last').animate({opacity:"hide"}, "slow").remove(); i--; } }); $('a.reset').click(function() { while(i > 2) { $('input:last').remove(); i--; } }); $('a.add_o').click(function() { $('<p><input type="text" value="output ' + i + '" name="input_field'+ i +'" /></p>').animate({ opacity: "show" }, "slow").appendTo('#outputs'); i++; }); $('a.remove_o').click(function() { if(i > 2) { $('input:last').animate({opacity:"hide"}, "slow").remove(); i--; } }); $('a.reset_o').click(function() { while(i > 2) { $('input:last').remove(); i--; } }); }); </script> <style rel="stylesheet" type="text/css"> h1 { font-family:"Trebuchet MS", Arial, Helvetica, sans-serif;} .hide {visibility:hidden;} img {border:none;} input { width:500px; height:20px; padding:10px; background:#f7f7f7; border:1px solid #f0f0f0; color:#333; font-size:20px; text-align:center; line-height:120px; margin:0; -moz-border-radius:5px; -webkit-border-radius:5px; } #inputs { width:520px; padding:0px 20px; border:1px solid #f0f0f0; -moz-border-radius:20px; -webkit-border-radius:20px; } </style> </head> <body> <h1>Add / remove text fields from webform</h1> <a href="#" class="add"><img src="http://muiomuio.com/tutorials/jquery/add-remove/add.png" width="24" height="24" alt="add" title="add input" /></a> <a href="#" class="remove"><img src="http://muiomuio.com/tutorials/jquery/add-remove/remove.png" width="24" height="24" alt="remove input" /></a> <a href="#" class="reset"><img src="http://muiomuio.com/tutorials/jquery/add-remove/reset.png" width="24" height="24" alt="reset" /></a> <div id="inputs"> <p> <input type="text" value="input 1" name="input_field1"> </p> </div> <a href="#" class="add_o"><img src="http://muiomuio.com/tutorials/jquery/add-remove/add.png" width="24" height="24" alt="add" title="add input" /></a> <a href="#" class="remove_o"><img src="http://muiomuio.com/tutorials/jquery/add-remove/remove.png" width="24" height="24" alt="remove input" /></a> <a href="#" class="reset_o"><img src="http://muiomuio.com/tutorials/jquery/add-remove/reset.png" width="24" height="24" alt="reset" /></a> <div id="outputs"> <p> <input type="text" value="output 1" name="output_field1"> </p> </div> </body> </html>

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  • SSH service will not start on fresh Cygwin 1.7.15 install

    - by Coder6841
    OS: Windows 7 x64 Cygwin: 1.7.15-1 OpenSSH: 6.0p1-1 I'm attempting to install an SSH server on Windows 7. The tutorial that I'm following to do this is here: http://www.howtogeek.com/howto/41560/how-to-get-ssh-command-line-access-to-windows-7-using-cygwin/ The issue is that upon executing the net start sshd command I get the following output:The CYGWIN sshd service is starting. The CYGWIN sshd service could not be started. The service did not report an error. More help is available by typing NET HELPMSG 3534. Here is the full output of the setup: AdminUser@ThisComputer ~ $ ssh-host-config *** Info: Generating /etc/ssh_host_key *** Info: Generating /etc/ssh_host_rsa_key *** Info: Generating /etc/ssh_host_dsa_key *** Info: Generating /etc/ssh_host_ecdsa_key *** Info: Creating default /etc/ssh_config file *** Info: Creating default /etc/sshd_config file *** Info: Privilege separation is set to yes by default since OpenSSH 3.3. *** Info: However, this requires a non-privileged account called 'sshd'. *** Info: For more info on privilege separation read /usr/share/doc/openssh/README.privsep. *** Query: Should privilege separation be used? (yes/no) yes *** Info: Note that creating a new user requires that the current account have *** Info: Administrator privileges. Should this script attempt to create a *** Query: new local account 'sshd'? (yes/no) yes *** Info: Updating /etc/sshd_config file *** Query: Do you want to install sshd as a service? *** Query: (Say "no" if it is already installed as a service) (yes/no) yes *** Query: Enter the value of CYGWIN for the daemon: [] *** Info: On Windows Server 2003, Windows Vista, and above, the *** Info: SYSTEM account cannot setuid to other users -- a capability *** Info: sshd requires. You need to have or to create a privileged *** Info: account. This script will help you do so. *** Info: You appear to be running Windows XP 64bit, Windows 2003 Server, *** Info: or later. On these systems, it's not possible to use the LocalSystem *** Info: account for services that can change the user id without an *** Info: explicit password (such as passwordless logins [e.g. public key *** Info: authentication] via sshd). *** Info: If you want to enable that functionality, it's required to create *** Info: a new account with special privileges (unless a similar account *** Info: already exists). This account is then used to run these special *** Info: servers. *** Info: Note that creating a new user requires that the current account *** Info: have Administrator privileges itself. *** Info: No privileged account could be found. *** Info: This script plans to use 'cyg_server'. *** Info: 'cyg_server' will only be used by registered services. *** Query: Do you want to use a different name? (yes/no) no *** Query: Create new privileged user account 'cyg_server'? (yes/no) yes *** Info: Please enter a password for new user cyg_server. Please be sure *** Info: that this password matches the password rules given on your system. *** Info: Entering no password will exit the configuration. *** Query: Please enter the password: *** Query: Reenter: *** Info: User 'cyg_server' has been created with password '[CENSORED]'. *** Info: If you change the password, please remember also to change the *** Info: password for the installed services which use (or will soon use) *** Info: the 'cyg_server' account. *** Info: Also keep in mind that the user 'cyg_server' needs read permissions *** Info: on all users' relevant files for the services running as 'cyg_server'. *** Info: In particular, for the sshd server all users' .ssh/authorized_keys *** Info: files must have appropriate permissions to allow public key *** Info: authentication. (Re-)running ssh-user-config for each user will set *** Info: these permissions correctly. [Similar restrictions apply, for *** Info: instance, for .rhosts files if the rshd server is running, etc]. *** Info: The sshd service has been installed under the 'cyg_server' *** Info: account. To start the service now, call `net start sshd' or *** Info: `cygrunsrv -S sshd'. Otherwise, it will start automatically *** Info: after the next reboot. *** Info: Host configuration finished. Have fun! AdminUser@ThisComputer ~ $ net start sshd The CYGWIN sshd service is starting. The CYGWIN sshd service could not be started. The service did not report an error. More help is available by typing NET HELPMSG 3534. Note that on the line *** Query: Enter the value of CYGWIN for the daemon: [] I haven't entered anything. Tutorials often say to use ntsec or ntsec tty here but those options are removed from the latest version of OpenSSH. I've tried using them anyway and the result is the same. The file /var/log/sshd.log is empty. If I try just running the command /usr/sbin/sshd I get the output /var/empty must be owned by root and not group or world-writable.. The /var/empty directory has the following permissions: drwxr-xr-x+ 1 cyg_server root 0 May 29 15:28 empty. Google searches on this error did not turn up any working fixes. One person seems to have solved it by using the command chown SYSTEM /var/empty but that did not fix it in my case.

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  • (PHP) User is being forced to RE-LOGIN after trying to do something on an admin page

    - by hatorade
    I have created an admin panel for a client in PHP, which requires a login. Here is the code at the top of the admin page requiring the user to be logged in: admin.php <?php session_start(); require("_lib/session_functions.php"); require("_lib/db.php"); db_connect(); //if the user has not logged in if(!isLoggedIn()) { header('Location: login_form.php'); die(); } ?> Obviously, the if statement is what catches them and forces them to log in. Here is the code on the resulting login page: login_form.php <form name="login" action="login.php" method="post"> Username: <input type="text" name="username" /> Password: <input type="password" name="password" /> <input type="submit" value="Login" /> </form> Which posts info to this controller page: login.php <?php session_start(); //must call session_start before using any $_SESSION variables include '_lib/session_functions.php'; $username = $_POST['username']; $password = $_POST['password']; include '_lib/db.php'; db_connect(); // Connect to the DB $username = mysql_real_escape_string($username); $query = "SELECT password, salt FROM users WHERE username = '$username';"; $result = mysql_query($query); if(mysql_num_rows($result) < 1) //no such user exists { header('Location: login_form.php?login=fail'); die(); } $userData = mysql_fetch_array($result, MYSQL_ASSOC); db_disconnect(); $hash = hash('sha256', $password . $userData['salt']); if($hash != $userData['password']) //incorrect password { header('Location: login_form.php?login=fail'); die(); } else { validateUser(); //sets the session data for this user } header('Location: admin.php'); ?> and the session functions page that provides login functions contains this: session_functions.php <?php function validateUser() { session_regenerate_id (); //this is a security measure $_SESSION['valid'] = 1; $_SESSION['userid'] = $username; } function isLoggedIn() { if($_SESSION['valid']) return true; return false; } function logout() { $_SESSION = array(); //destroy all of the session variables if (ini_get("session.use_cookies")) { $params = session_get_cookie_params(); setcookie(session_name(), '', time() - 42000, $params["path"], $params["domain"], $params["secure"], $params["httponly"] ); } session_destroy(); } ?> I grabbed the sessions_functions.php code of an online tutorial, so it could be suspicious. Any ideas why the user logs in to the admin panel, tries to do something, is forced to re-login, and THEN is allowed to do stuff like normal in the admin panel?

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  • Html LogIn form not functioning

    - by Tony C
    Ok, I have a login form that looks like this: <form id="loginForm" name="loginForm" method="post" action="login-exec.php"> <table width="300" border="0" align="center" cellpadding="2" cellspacing="0"> <tr> <td width="112"><b>Login</b></td> <td width="188"><input name="login" type="text" class="textfield" id="login" /></td> </tr> <tr> <td><b>Password</b></td> <td><input name="password" type="password" class="textfield" id="password" /></td> </tr> <tr> <td>&nbsp;</td> <td><input type="submit" name="Submit" value="Login" /></td> </tr> </table> </form> Now, This form is on a page in a directory called members. When i put it on a page in the home directory and change the action to "members/login-exec.php" When I try to logIn it just refreshes the page, but the name of the page in the browser changes to the actions taking place in the form. Any ideas on making this work guys? EDIT, heres the login-exec.php code: <?php //Start session session_start(); //Include database connection details require_once('config.php'); //Array to store validation errors $errmsg_arr = array(); //Validation error flag $errflag = false; //Connect to mysql server $link = mysql_connect(DB_HOST, DB_USER, DB_PASSWORD); if(!$link) { die('Failed to connect to server: ' . mysql_error()); } //Select database $db = mysql_select_db(DB_DATABASE); if(!$db) { die("Unable to select database"); } //Function to sanitize values received from the form. Prevents SQL injection function clean($str) { $str = @trim($str); if(get_magic_quotes_gpc()) { $str = stripslashes($str); } return mysql_real_escape_string($str); } //Sanitize the POST values $login = clean($_POST['login']); $password = clean($_POST['password']); //Input Validations if($login == '') { $errmsg_arr[] = 'Login ID missing'; $errflag = true; } if($password == '') { $errmsg_arr[] = 'Password missing'; $errflag = true; } //If there are input validations, redirect back to the login form if($errflag) { $_SESSION['ERRMSG_ARR'] = $errmsg_arr; session_write_close(); header("location: login-form.php"); exit(); } //Create query $qry="SELECT * FROM members WHERE login='$login' AND passwd='".md5($_POST['password'])."'"; $result=mysql_query($qry); //Check whether the query was successful or not if($result) { if(mysql_num_rows($result) == 1) { //Login Successful session_regenerate_id(); $member = mysql_fetch_assoc($result); $_SESSION['SESS_MEMBER_ID'] = $member['member_id']; $_SESSION['SESS_FIRST_NAME'] = $member['firstname']; $_SESSION['SESS_LAST_NAME'] = $member['lastname']; session_write_close(); header("location: members.php"); exit(); }else { //Login failed header("location: login-failed.php"); exit(); } }else { die("Query failed"); } ?>

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  • I'm trying to pass a string from my first ViewController to my second ViewController but it returns NULL

    - by Dashony
    In my first view controller I have 3 input fields each of them take the user input into and saves it into a string such as: address, username and password as NSUserDefaults. This part works fine. In my second view controller I'm trying to take the 3 strings from first controller (address, username and password) create a html link based on the 3 strings. I've tried many ways to access the 3 strings with no luck, the result I get is NULL. Here is my code: //.h file - first view controller with the 3 input fields CamSetup.h #import <UIKit/UIKit.h> @interface CamSetup : UIViewController <UITextFieldDelegate> { NSString * address; NSString * username; NSString * password; IBOutlet UITextField * addressField; IBOutlet UITextField * usernameField; IBOutlet UITextField * passwordField; } -(IBAction) saveAddress: (id) sender; -(IBAction) saveUsername: (id) sender; -(IBAction) savePassword: (id) sender; @property(nonatomic, retain) UITextField *addressField; @property(nonatomic, retain) UITextField *usernameField; @property(nonatomic, retain) UITextField *passwordField; @property(nonatomic, retain) NSString *address; @property(nonatomic, retain) NSString *username; @property(nonatomic, retain) NSString *password; @end //.m file - first view controller CamSetup.m #import "CamSetup.h" @interface CamSetup () @end @implementation CamSetup @synthesize addressField, usernameField, passwordField, address, username, password; -(IBAction) saveAddress: (id) sender { address = [[NSString alloc] initWithFormat:addressField.text]; [addressField setText:address]; NSUserDefaults *stringDefaultAddress = [NSUserDefaults standardUserDefaults]; [stringDefaultAddress setObject:address forKey:@"stringKey1"]; NSLog(@"String [%@]", address); } -(IBAction) saveUsername: (id) sender { username = [[NSString alloc] initWithFormat:usernameField.text]; [usernameField setText:username]; NSUserDefaults *stringDefaultUsername = [NSUserDefaults standardUserDefaults]; [stringDefaultUsername setObject:username forKey:@"stringKey2"]; NSLog(@"String [%@]", username); } -(IBAction) savePassword: (id) sender { password = [[NSString alloc] initWithFormat:passwordField.text]; [passwordField setText:password]; NSUserDefaults *stringDefaultPassword = [NSUserDefaults standardUserDefaults]; [stringDefaultPassword setObject:password forKey:@"stringKey3"]; NSLog(@"String [%@]", password); } - (void)viewDidLoad { [addressField setText:[[NSUserDefaults standardUserDefaults] objectForKey:@"stringKey1"]]; [usernameField setText:[[NSUserDefaults standardUserDefaults] objectForKey:@"stringKey2"]]; [passwordField setText:[[NSUserDefaults standardUserDefaults] objectForKey:@"stringKey3"]]; [super viewDidLoad]; } @end //.h second view controller LiveView.h #import <UIKit/UIKit.h> #import "CamSetup.h" @interface LiveView : UIViewController { NSString *theAddress; NSString *theUsername; NSString *thePassword; CamSetup *camsetup; //here is an instance of the first class } @property (nonatomic, retain) NSString *theAddress; @property (nonatomic, retain) NSString *theUsername; @property (nonatomic, retain) NSString *thePassword; @end //.m second view LiveView.m file #import "LiveView.h" @interface LiveView () @end @implementation LiveView @synthesize theAddress, theUsername, thePassword; - (void)viewDidLoad { [super viewDidLoad]; theUsername = camsetup.username; //this is probably not right? NSLog(@"String [%@]", theUsername); //resut here is NULL NSLog(@"String [%@]", camsetup.username); //and here NULL as well } @end

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  • Why can't I reinstall MySQL?

    - by Johannes Nielsen
    I've been looking all around the Internet for an answer but didn't find anything. I hope you can help me now. I have a server with MySQL. From one day to another, MySQL didn't let me enter with my root password anymore (accsess denied for user 'root'@'localhost' using password: 'YES'). So I tried two ways to reset the password: No.1: I typed: shell> /etc/init.d/mysqld stop To stop MySQL. Then I restarted it skipping the grant-tables: shell> mysqld_safe --skip-grant-tables So I was able to log in as root and change the password using: mysql> UPDATE mysql.user SET Password = PASSWORD('MyNewPassword') WHERE User = 'root'; FLUSH PRIVILEGES; I restarted MySQL and tried to log in as root with my new password - didn't work. So I tried the solution that's described here: http://dev.mysql.com/doc/refman/5.0/en/resetting-permissions.html (I don't want to post it here because this post is already pretty long). Didn't work either. Actually it made it worse, because since that day, every time I try to start MySQL, it doesn't even ask me for my password, but I get: shell> ERROR 2002 (HY000): Can't connect to local MySQL server through socket '/var/run/mysqld/mysqld.sock' (111) Well, I've looked up what it means and found that my mysqld.sock is missing. I tried to create it using touch but MySQL can't start with that socket. Now I'm trying to reinstall MySQL but everytime I type in shell> apt-get --purge remove mysql-server mysql-common mysql-client In that or any other order or every one of those three alone, I get: shell> Reading package lists... Done shell> Building dependency tree shell> Reading state information... Done shell> Package mysql-client is not installed, so not removed shell> Package mysql-server is not installed, so not removed shell> You might want to run 'apt-get -f install' to correct these: shell> The following packages have unmet dependencies: shell> libmysqlclient18 : Depends: mysql-common (>= 5.5.28-0ubuntu0.12.04.2) but it is not going to be installed shell> libmysqlclient18:i386 : Depends: mysql-common:i386 (>= 5.5.28-0ubuntu0.12.04.2) shell> mysql-client-5.5 : Depends: mysql-common (>= 5.5.28-0ubuntu0.12.04.2) but it is not going to be installed shell> mysql-server-5.5 : PreDepends: mysql-common (>= 5.5.28-0ubuntu0.12.04.2) but it is not going to be installed shell> psa-firewall : Depends: plesk-core (>= 11.0.9) but it is not installable shell> Depends: mysql-server but it is not going to be installed shell> psa-spamassassin : Depends: plesk-core (>= 11.0.9) but it is not installable shell> psa-vpn : Depends: plesk-core (>= 11.0.9) but it is not installable shell> Depends: plesk-base (>= 11.0.9) but it is not installable shell> Depends: mysql-server but it is not going to be installed shell> E: Unmet dependencies. Try 'apt-get -f install' with no packages (or specify a solution). So I said to my self "let's just remove those files with depenencies, too" (that psa-stuff since plesk is virtual and can't be uninstalled)... Guess what happened: shell> Reading package lists... Done shell> Building dependency tree shell> Reading state information... Done shell> Package mysql-client is not installed, so not removed shell> Package mysql-server is not installed, so not removed shell> You might want to run 'apt-get -f install' to correct these: shell> The following packages have unmet dependencies: shell> libmysqlclient18 : Depends: mysql-common (>= 5.5.28-0ubuntu0.12.04.2) but it is not going to be installed shell> libmysqlclient18:i386 : Depends: mysql-common:i386 (>= 5.5.28-0ubuntu0.12.04.2) shell> mysql-client-5.5 : Depends: mysql-common (>= 5.5.28-0ubuntu0.12.04.2) but it is not going to be installed shell> mysql-server-5.5 : PreDepends: mysql-common (>= 5.5.28-0ubuntu0.12.04.2) but it is not going to be installed shell> E: Unmet dependencies. Try 'apt-get -f install' with no packages (or specify a solution). Of course I tried apt-get -f install, too many times even. What am I doing wrong? No matter, which other packages I include into apt-get --purge remove, I always get new dependencies. Do I have to delete every MySQL-related directory and file manually? Hope there's someone out there who can help me! Cheers! EDIT: After trying apt-get purge mysql-server mysql-common mysql-client libmysqlclient18 libmysqlclient18:i386 mysql-client-5.5 mysql-server-5.5 psa-firewall psa-spamassassin psa-vpn Reading package lists... Done Building dependency tree Reading state information... Done Package mysql-client is not installed, so not removed Package mysql-server is not installed, so not removed You might want to run 'apt-get -f install' to correct these: The following packages have unmet dependencies: libdbd-mysql-perl : Depends: libmysqlclient18 (>= 5.5.13-1) but it is not going to be installed libmyodbc : Depends: libmysqlclient18 (>= 5.5.13-1) but it is not going to be installed libqt4-sql-mysql:i386 : Depends: libmysqlclient18:i386 (>= 5.5.13-1) but it is not going to be installed php5-mysql : Depends: libmysqlclient18 (>= 5.5.13-1) but it is not going to be installed ruby-mysql : Depends: libmysqlclient18 (>= 5.5.13-1) but it is not going to be installed E: Unmet dependencies. Try 'apt-get -f install' with no packages (or specify a solution). So I tried to remove all these and got: Building dependency tree Reading state information... Done Package mysql-client is not installed, so not removed Package mysql-server is not installed, so not removed You might want to run 'apt-get -f install' to correct these:qlclient18:i386 mysql The following packages have unmet dependencies: libmysql-ruby1.8 : Depends: ruby-mysql but it is not going to be installed E: Unmet dependencies. Try 'apt-get -f install' with no packages (or specify a solution). And actually I think removing that file, too solved my problem :-S Next time I'll try everything before asking :D Thank you Eric for keeping me couraged to just go on removing :D

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