Search Results

Search found 12096 results on 484 pages for 'to date'.

Page 102/484 | < Previous Page | 98 99 100 101 102 103 104 105 106 107 108 109  | Next Page >

  • Bypassing validation with machinist

    - by toofancy
    Hi, I am writing my specs on my model Thing which has a date field which should be after the date of creation, thus I use the *validate_timeliness* plugin like that validate_date :date, :after Time.now I want to be able to add some Things with an anterior date but validation fails. I want to bypass the validation when creating some Things with the machinist factory. Any clue ?

    Read the article

  • How best to convert CakePHP date picker form data to a PHP DateTime object?

    - by Daren Thomas
    I'm doing this in app/views/mymodel/add.ctp: <?php echo $form->input('Mymodel.mydatefield'); ?> And then, in app/controllers/mymodel_controller.php: function add() { # ... (if we have some submitted data) $datestring = $this->data['Mymodel']['mydatefield']['year'] . '-' . $this->data['Mymodel']['mydatefield']['month'] . '-' . $this->data['Mymodel']['mydatefield']['day']; $mydatefield = DateTime::createFromFormat('Y-m-d', $datestring); } There absolutly has to be a better way to do this - I just haven't found the CakePHP way yet... What I would like to do is: function add() { # ... (if we have some submitted data) $mydatefield = $this->data['Mymodel']['mydatefiled']; # obviously doesn't work }

    Read the article

  • SQL - fetch the row which has the Max value for a column

    - by Umang
    Table: UserId, Value, Date. I want to get the UserId, Value for the max(Date) for each UserId. That is, the Value for each UserId that has the latest date. Is there a way to do this simply in SQL? (Preferably Oracle) Thank in advance! [Update:] Apologies for any ambiguity: I need to get ALL the UserIds. But for each UserId, only that row where that user has the latest date.

    Read the article

  • Are jQuery's :first and :eq(0) selectors functionally equivalent?

    - by travis
    I'm not sure whether to use :first or :eq(0) in a selector. I'm pretty sure that they'll always return the same object, but is one speedier than the other? I'm sure someone here must have benchmarked these selectors before and I'm not really sure the best way to test if one is faster. Update: here's the bench I ran: /* start bench */ for (var count = 0; count < 5; count++) { var i = 0, limit = 10000; var start, end; start = new Date(); for (i = 0; i < limit; i++) { var $radeditor = $thisFrame.parents("div.RadEditor.Telerik:eq(0)"); } end = new Date(); alert("div.RadEditor.Telerik:eq(0) : " + (end-start)); var start = new Date(); for (i = 0; i < limit; i++) { var $radeditor = $thisFrame.parents("div.RadEditor.Telerik:first"); } end = new Date(); alert("div.RadEditor.Telerik:first : " + (end-start)); start = new Date(); for (i = 0; i < limit; i++) { var radeditor = $thisFrame.parents("div.RadEditor.Telerik")[0]; } end = new Date(); alert("(div.RadEditor.Telerik)[0] : " + (end-start)); start = new Date(); for (i = 0; i < limit; i++) { var $radeditor = $($thisFrame.parents("div.RadEditor.Telerik")[0]); } end = new Date(); alert("$((div.RadEditor.Telerik)[0]) : " + (end-start)); } /* end bench */ I assumed that the 3rd would be the fastest and the 4th would be the slowest, but here's the results that I came up with: FF3: :eq(0) :first [0] $([0]) trial1 5275 4360 4107 3910 trial2 5175 5231 3916 4134 trial3 5317 5589 4670 4350 trial4 5754 4829 3988 4610 trial5 4771 6019 4669 4803 Average 5258.4 5205.6 4270 4361.4 IE6: :eq(0) :first [0] $([0]) trial1 13796 15733 12202 14014 trial2 14186 13905 12749 11546 trial3 12249 14281 13421 12109 trial4 14984 15015 11718 13421 trial5 16015 13187 11578 10984 Average 14246 14424.2 12333.6 12414.8 I was correct about just returning the first native DOM object being the fastest ([0]), but I can't believe the wrapping that object in the jQuery function was faster that both :first and :eq(0)! Unless I'm doing it wrong.

    Read the article

  • Regex age verification

    - by KevinDeus
    Anyone have a good regex for Age verification? I have a date field where I am validating that what the user enters is a date. basically I wanted to figure out if that date is valid, and then further refine the date to be within x number of years Perhaps this may be too complicated to tack onto whatever I have too far, but I figured it wouldn't be. ^([1][012]|[0]?[1-9])[/-]([3][01]|[12]\d|[0]?[1-9])[/-](\d{4}|\d{2})$

    Read the article

  • Objective C: CoreData and aggregation

    - by Ralf
    Given a CoreData-Entity with an date (days) and an ammount called Transaction. Is it with CoreData possible (and how) to aggregate/group the 'table' (with all Transactions) by Date and calculate the sum of the day in a second column/attribute? (the SQL-Solution would be SELECT date, sum(ammount) FROM transaction GROUP BY date)

    Read the article

  • how to uppercase date and month first letter of ToLongDateString() result in es-mx Culture ?

    - by Oscar Cabrero
    currently i obtain the below result from the following C# line of code when in es-MX Culture Thread.CurrentThread.CurrentCulture = Thread.CurrentThread.CurrentUICulture = new CultureInfo("es-mx"); <span><%=DateTime.Now.ToLongDateString()%></span> miércoles, 22 de octubre de 2008 i would like to obtain the following Miércoles, 22 de Octubre de 2008 do i need to Build my own culture?

    Read the article

  • Check for repeating dates.

    - by kylex
    I am creating a calendar in PHP and in the database have a date, let's say 6-10-10. Sometimes I have repeating events, stored as weekly repeating, so if the date is 6-10-10, and I am repeating an event every two weeks from that day (including that day) what is the best way to find dates for every two weeks from 6-10-10? For example, let's say the date is 7-8-10, how can I check to see that date meets my criteria?

    Read the article

  • jqGrid local date manipulation; problem with row ids when deleting and adding new rows

    - by Sam
    I'm using jqGrid as a client side grid input, allowing the user to input multiple records before POSTing all the data back at once. I'm having a problem where if the user has added a few records (say 3 ) the id's for the records will be 1,2,3. if the user deletes record 2, you're left with 1 and 3 for the id of the records. When the user now adds a new records, jqGrid assigns that records the id 3 again since it just seems to count the total records and increments it by one for the new record. This causes problems when selecting rows as now the row id's are 1, 3 and 3. Does anyone know how to access the row ids of records as I could probably use the afterSubmit event and reassign the row id's increasing from 1. ( so after i delete row id 2, this will set the other row id's to 1 and 2) Any other suggestions to solve this problem? Thanks

    Read the article

  • Cross field validation in jsf h:datatable using p:calendar

    - by Matt Broekhuis
    I noticed this question was asked, but it has not been answered correctly. I have a datatable that has two columns start date and end date. Both contain primefaces p:calendar controls in them. I need to ensure that for each row that the date in column1 is not after the date in column2. I would like to tie this into the JSF validation framework, but I'm having trouble. i've tried marking the datatable rowStatePreserved="true" , this allows me to get the values, but something is still wrong as when it fails, all the values in the first row overwrite all the other values. What am I doing wrong, or should I be using a completely different strategy? xhtml code <h:form> <f:event type="postValidate" listener="#{bean.doCrossFieldValidation}"/> <p:dataTable id="eventDaysTable" value="#{course.courseSchedules}" var="_eventDay" styleClass="compactDataTable" > <p:column id="eventDayStartColumn"> <f:facet name="header"> Start </f:facet> <p:calendar id="startDate" required="true" value="#{_eventDay.startTime}" pattern="MM/dd/yyyy hh:mm a"/> </p:column> <p:column id="eventDayEndColumn"> <f:facet name="header"> End </f:facet> <p:calendar id="endDate" required="true" value="#{_eventDay.endTime}" pattern="MM/dd/yyyy hh:mm a"/> </p:column> </p:dataTable> </h:form> validationCode public void doCrossFieldValidation(ComponentSystemEvent cse) { UIData eventsDaysStable = (UIData) cse.getComponent().findComponent("eventDaysTable"); if (null != eventsDaysStable && eventsDaysStable.isRendered()) { Iterator<UIComponent> startDateCalendarIterator = eventsDaysStable.findComponent("eventDayStartColumn").getChildren().iterator(); Iterator<UIComponent> endDateCalendarIterator = eventsDaysStable.findComponent("eventDayEndColumn").getChildren().iterator(); while (startDateCalendarIterator.hasNext() && endDateCalendarIterator.hasNext()) { org.primefaces.component.calendar.Calendar startDateComponent = (org.primefaces.component.calendar.Calendar) startDateCalendarIterator.next(); org.primefaces.component.calendar.Calendar endDateComponent = (org.primefaces.component.calendar.Calendar) endDateCalendarIterator.next(); Date startDate = (Date) startDateComponent.getValue(); Date endDate = (Date) endDateComponent.getValue(); if (null != startDate && null != endDate && startDate.after(endDate)) { eventScheduleChronologyOk = false; startDateComponent.setValid(false); endDateComponent.setValid(false); } } if (!eventScheduleChronologyOk) { showErrorMessage(ProductManagementMessage.PRODUCT_SCHEDULE_OUT_OF_ORDER); } } }

    Read the article

  • Hibernate-Search: How to search dates?

    - by Aaron
    @Entity @Table(name = "USERS") public class User { @Id @GeneratedValue(strategy = GenerationType.AUTO) private long id; @Column(name = "USERNAME", nullable = false, length = 20) private String userName; @Column(name = "PASSWORD", nullable = false, length = 10) private String password; @Column(name = "Date", nullable = false ) private Date date; } How can I select the records which have the date between [now | now-x hours] [now | now-x days] [now | now-x months] [now | now-x years]

    Read the article

  • .ics Calendar File - Parsing Date Time - What is the time format?

    - by Josh
    I am coding in php, attempting to get the start\end dates and times for events. I am utilizing the following RegEx for parsing out the information: $pattern='/(?P<StartDate>[0-9]{8})T(?P<StartTime>[0-9]{6}) .+(?P<EndDate>[0-9]{8})T(?P<EndTime>[0-9]{6})/'; The sample event entry is here: BEGIN:VEVENT UID:34b09fd7-8e6e-4d56-86b0-445745b89d93 ORGANIZER;CN=*********:mailto:********* DTSTART;TZID="(GMT-06.00) Central Time (US & Canada)":20100413T130000 DTEND;TZID="(GMT-06.00) Central Time (US & Canada)":20100413T160000 STATUS:CONFIRMED CLASS:PRIVATE X-MICROSOFT-CDO-INTENDEDSTATUS:BUSY TRANSP:OPAQUE X-MICROSOFT-DISALLOW-COUNTER:TRUE DTSTAMP:20100414T140711Z SEQUENCE:0 END:VEVENT 20100413T130000 and 20100413T160000 are the start and end points. The dates are straight forward, however how do I interpret the time part? This event starts at one and ends at four.

    Read the article

  • Script to download file and rename according to date on Windows Vista machine?

    - by Dave
    Hi, I need to daily run a script that will download a file from a fixed location and save it on my computer with an appropriate filename-YYYYMMDD-HHSS.ext timestamp. I need a historical record of what that file was at that particular time. I can manually check and see what the changes were, so compairson not needed. (I was looking for an online service that would do this for me, but I think a locally running script on my machine would be good enough). Although i do have php on my machine, i would prefer if its a pure windows builtin solution, just in case i have to (likely) adapt it to someone else's system (non-techies). If someone has something like this and can contribute the code - help would be most appreciated!! D

    Read the article

  • A Digg-like rotating homepage of popular content, how to include date as a factor?

    - by Ferdy
    I am building an advanced image sharing web application. As you may expect, users can upload images and others can comments on it, vote on it, and favorite it. These events will determine the popularity of the image, which I capture in a "karma" field. Now I want to create a Digg-like homepage system, showing the most popular images. It's easy, since I already have the weighted Karma score. I just sort on that descendingly to show the 20 most valued images. The part that is missing is time. I do not want extremely popular images to always be on the homepage. I guess an easy solution is to restrict the result set to the last 24 hours. However, I'm also thinking that in order to keep the image rotation occur throughout the day, time can be some kind of variable where its offset has an influence on the image's sorting. Specific questions: Would you recommend the easy scenario (just sort for best images within 24 hours) or the more sophisticated one (use datetime offset as part of the sorting)? If you advise the latter, any help on the mathematical solution to this? Would it be best to run a scheduled service to mark images for the homepage, or would you advise a direct query (I'm using MySQL) As an extra note, the homepage should support paging and on a quiet day should include entries of days before in order to make sure it is always "filled" I'm not asking the community to build this algorithm, just looking for some advise :)

    Read the article

  • Adding a TimeSpan to a given DateTime

    - by Amokrane
    I just want to add 1 day to a DateTime. So I wrote: DateTime date = new DateTime(2010, 4, 29, 10, 25, 00); TimeSpan t = new TimeSpan(1, 0, 0, 0); date.Add(t); Console.WriteLine("A day after the day: " + date.ToString()); I tought the result would be: 2010 04 30- 10:25:00 but I'm still getting the initial date. What's wrong?

    Read the article

  • Keeping a database structure up to date in a project where code is on subversion?

    - by Bruno De Barros
    I have been working with Subversion for a while now, and it's been incredible for the management of my projects, and even to help managing the deployment to several different servers, but there is just the one thing that still annoys me. Whenever I make any changes to the database structure, I need to update every server manually, I have to keep track of any changes I made, and because some of my servers run branches of the project (modifications that are still being worked on, or were made for different purposes), it's a bit awkward. Until now, I've been using a "database.sql" file, which is a dump of the database structure for a specific revision. But it just seems like such a bad way to manage this. And I was wondering, how does everyone else manage their MySQL databases when they're working on a project and using Subversion?

    Read the article

  • How do I run jQuery form validation by class?

    - by joshcomley
    Hi there, I've been using the jQuery form validator, but I can't seem to figure out how to trigger it by class. Take this example: $("#myform").validate({ rules: { field: { required: true, date: true } } }); Where field it is expecting the name of the particular input. But, what if I have the following: <input class="date".... /> How can I tell the validator to validate all inputs with a "date" class as a date?

    Read the article

  • Specific query in Mysql

    - by Radhe
    I have two tables reports and holidays. reports: (username varchar(30),activity varchar(30),hours int(3),report_date date) holidays: (holiday_name varchar(30), holiday_date date) select * from reports gives +----------+-----------+---------+------------+ | username | activity | hours | date | +----------+-----------+---------+------------+ | prasoon | testing | 3 | 2009-01-01 | | prasoon | coding | 4 | 2009-01-03 | | prasoon | designing| 2 | 2009-01-04 | | prasoon | coding | 4 | 2009-01-06 | +----------+-----------+---------+------------+ select * from holidays gives +--------------+---------------+ | holiday_name | holiday_date | +--------------+---------------+ | Diwali | 2009-01-02 | | Holi | 2009-01-05 | +--------------+---------------+ Is there any way by which I can output the following? +-------------+-----------+---------+-------------------+ | date | activity | hours | holiday_name | +-------------+-----------+---------+-------------------+ | 2009-01-01 | testing | 3 | | | 2009-01-02 | | | Diwali | | 2009-01-03 | coding | 4 | | | 2009-01-04 | designing| 2 | | | 2009-01-05 | | | Holi | | 2009-01-06 | coding | 4 | | +-------------+-----------+---------+-------------------+

    Read the article

  • Blocking problem, C#, .net, Deserializing XML to object problem

    - by fernando
    Hi I have a blocking problem I have XML file under some url http://myserver/mywebApp/myXML.xml In the below code which I run in Console Application, bookcollection has null Books field :( <books> <book id="5352"> <date>1986-05-05</date> <title> Alice in chains </title> </book> <book id="4334"> <date>1986-05-05</date> <title> 1000 ways to heaven </title> </book> <book id="1111"> <date>1986-05-05</date> <title> Kitchen and me </title> </book> </books> XmlDocument doc = new XmlDocument(); doc.Load("http://myserver/mywebapp/myXML.xml"); BookCollection books = new BookCollection(); XmlNodeReader reader2 = new XmlNodeReader(doc.DocumentElement); XmlSerializer ser2 = new XmlSerializer(books.GetType()); object obj = ser2.Deserialize(reader2); BookCollection books2= (BookCollection)obj; using System; using System.Collections.Generic; using System.Linq; using System.Text; namespace ConsoleApplication1 { [Serializable()] public class Book { [System.Xml.Serialization.XmlAttribute("id")] public string id { get; set; } [System.Xml.Serialization.XmlElement("date")] public string date { get; set; } [System.Xml.Serialization.XmlElement("title")] public string title { get; set; } } } using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Xml.Serialization; namespace ConsoleApplication1 { [Serializable()] [System.Xml.Serialization.XmlRootAttribute("books", Namespace = "", IsNullable = false)] public class BookCollection { [XmlArray("books")] [XmlArrayItem("book", typeof(Book))] public Book[] Books { get; set; } } }

    Read the article

< Previous Page | 98 99 100 101 102 103 104 105 106 107 108 109  | Next Page >