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  • PHP readdir(): 3 is not a valid Directory resource

    - by Jordan
    <?php function convert(){ //enable error reporting for debugging error_reporting(E_ALL | E_STRICT); //convert pdf's to html using payroll.sh script and //pdftohtml command line tool $program = "payroll.sh"; $toexec="sh /var/www/html/tmp/" . $program . " 2>&1"; $exec=shell_exec($toexec); //display message from payroll.sh //echo $exec; //echo ('<br/>'); } function process(){ $dir = '/var/www/html/tmp/converted'; //echo ('one'); if (is_dir($dir)) { //echo ('two'); if ($dh = opendir($dir)) { //echo ('three'); while (($file = readdir($dh)) !== false) { //echo ('four'); if ($file != "." && $file != ".."){ echo 'opening file: '; echo $file; echo ("<br/>"); $fp = fopen('/var/www/html/tmp/converted/' . $file, 'r+'); $count = 0; //while file is not at the EOF marker while (!feof($fp)) { $line = fgets($fp); if($count==21) { $employeeID = substr($line,71,4); echo 'employee ID: '; echo $employeeID; echo ('<br/>'); //echo ('six'); $count++; } else if($count==30) { $employeeDate = substr($line,71,10); echo 'employee Date: '; echo $employeeDate; echo ('<br/>'); //echo ('seven'); $count++; } else { //echo ('eight'); //echo ('<br/>'); $count++; } } fclose($fp); closedir($dh); } } } } } convert(); process(); ?> I am setting up a php script that will take a paystub in pdf format, convert it to html, then import it into Drupal after getting the date and employee ID. The code only seems to process the first file in the directory then it gives me this: opening file: dd00000112_28_2010142011-1.html employee ID: 9871 employee Date: 12/31/2010 Warning: readdir(): 3 is not a valid Directory resource in /var/www/html/pay.mistequaygroup.com/payroll.php on line 29 The '3' in the error really confuses me, and google is not helping much. Could it be the 3rd iteration of the loop? The only files in the directory reddir() is scanning are the .html files waiting to be processed. Any ideas? Also, how does my code look? I'm fairly new to doing any real programming and I don't get too much input around work.

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  • parse this directory path without losing slash

    - by PPTim
    hi, I have a wxPython application. I am taking in a directory path from a textbox using GetValue(). I notice that while trying to parse in the directory path "C:\Documents and Settings\UserName\Desktop\InputFile.xls", python sees the string as 'C:\\Documents and Settings\UserName\\Desktop\\InputFile.xls' (missing a slash between "Settings" and "UserName). Why is it that only that slash is not correctly escaped? Once the string has been changed to 'C:\Documents and Settings\UserName\Desktop\InputFile.xls', is there a type conversion or function that can does this properly? Thanks.

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  • BASH Script to cd to directory with spaces in pathname

    - by Rails Newbie
    Argggg. I've been struggling with this stupid problem for days and I can't find an answer. I'm using BASH on Mac OS X and I'd like to create a simple executable script file that would change to another directory when it's run. However, the path to that directory has spaces in it. How the heck do you do this? This is what I have... Name of file: cdcode File contents: cd ~/My Code Now granted, this isn't a long pathname, but my actual pathname is five directories deep and four of those directories have spaces in the path. BTW, I've tried cd "~/My Code" and cd "~/My\ Code" and neither of these worked. If you can help, THANKS! This is driving me crazy!!

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  • Create Directory, 'cd' to it and download a file pipeline in Perl

    - by neversaint
    I have a file that looks like this: ftp://url1/files1.tar.gz dir1 ftp://url2/files2.txt dir2 .... many more... What I want to do are these steps: Create directory based on column 2 Unix 'cd' to that directory Download file with 'wget' based on column1 But how come this approach of mine doesn't work while(<>) { chomp; my ($url,$dir) = split(/\t/,$_); system("mkdir $dir"); system("cd $dir"); # Fail here system("wget $url"); # here too } What's the right way to do it?

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  • Eclipse buildpath automatically taking all JARs of a internal directory

    - by Niko
    How do I configure my project buildpath to have a set of .jar files located in the same directory automatically included in the buildpath ? Meaning that adding a new .jar file to this directory (and refreshing the project) updates the buildpath ? Rem : I am not working in a Webapp but in a standalone Java app. I know that it is possible in a Dynamic Web Project to have all the .jars located in WEB-INF/lib to be included in the build path. Is it possible to do kind of the same include but in standalone app ? I am using Eclipse 3.4

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  • Moving directory after compilation of R

    - by CravingSpirit
    I compiled R in /tmp/R-3.0.0 and then moved it to /home/user/opt/R-3.0.0, then I got an error when executing R: /home/kaiyin/opt/R-3.0.0/bin/R: line 236: /tmp/R-3.0.0/etc/ldpaths: No such file or directory ERROR: R_HOME ('/tmp/R-3.0.0') not found If I export R_HOME='/home/kaiyin/opt/R-3.0.0', it still gives almost the same error: WARNING: ignoring environment value of R_HOME /home/kaiyin/opt/R-3.0.0/bin/R: line 236: /tmp/R-3.0.0/etc/ldpaths: No such file or directory ERROR: R_HOME ('/tmp/R-3.0.0') not found Is there a way to solve this, or do I have to recompile it?

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  • Viewing directory containing MIME encoded email messages

    - by Mark
    I have an application which generates and sends MIME encoded messages (javax.mail.internet.MimeMessage) through an SMTP server. As part of the development process only, I'd like to be able to view these messages rather than send them (I know the sending works just fine, but there are restrictions on the domains within the dev environment which makes it a little difficult) I thought the easiest way would be to save the text for each message to a directory, then point "an app" at the directory and check them over. So the question is, what would be a good app to use? Is it as simple as configuring Outlook or another email client to do it? Thanks

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  • Java import from other directory

    - by heldopslippers
    Hi People! I am building a Enterprise Service Bus (ESB) with Java. I won't get into details But I have to build multiple servers who make use of the same classes. I have the following directory structure: /server1 -Main.java /server2 -Main.java /com -Database.java I want to import from the Main.java class for example the Database.class. But of course the following statements won't work: import com.Database; I am working with the javac compiler in the command line (so not eclipse stuff or whatever. just TextMate and the command line). And I found a (pretty stupid) solution by creating a symbolic link in the servers to the com directory. But that is not really an ideal solution. Does anybody have a better one?? THANXS in advanced!! :D

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  • Error becuase Virtual directory not being configured as an application in IIS

    - by Cipher
    Hi, I was trying to install a CMS in a folder in my website. After the installation on trying to run, it shows this error: Error 14 It is an error to use a section registered as allowDefinition='MachineToApplication' beyond application level. This error can be caused by a virtual directory not being configured as an application in IIS. E:\Users\Sarin\Documents\Visual Studio 2010\WebSites\WebAssist\blog\web.config 61 I added the webiste as a Virtual Directory and also converted that to application. On trying to browse this application, the following error occurs as shown in the screenshot: http://i.imgur.com/jcRJe.jpg How to make this work?

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  • git - is there a way to get only required files in the working directory

    - by spoonboy
    I'm new to git and trying to use it with a project that has many (several hundreds) sources. The problem I have is that git is extracting all the project's sources to my working directory when doing checkout. This makes a lot of mess as I have to jump between the files and can unintentionally change/corrupt files that I wasn't even planning to change. I would prefer to extract only sources that I'm going to modify and then work with them. So, is there a way to tell git that I only going to work with specific sources, and so, that only these sources would be extracted to the working directory? Note, that this is not a partial checkout or something like this. I'm ok to checkout the whole branch. It's more about organising a working folder. Thanks.

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  • Write file in sub-directory in Android

    - by Davide Vosti
    I'm trying to save a file in a subdirectory in Android 1.5. I can successfully create a directory using _context.GetFileStreamPath("foo").mkdir(); (_context is the Activity where I start the execution of saving the file) but then if I try to create a file in foo/ by _context.GetFileStreamPath("foo/bar.txt"); I get a exception saying I can't have directory separator in a file name ("/"). I'm missing something of working with files in Android... I thought I could use the standard Java classes but they don't seem to work... I searched the Android documentation but I couldn't fine example and google is not helping me too... I'm asking the wrong question (to google)... Can you help me out with this? Thank you!

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  • Python read files in directory and concatenate

    - by JJ Beck
    I want to write a Python script that searches all folders in the current directory, looks for all .txt files, and creates a file that is a concatenation of all those files (in any order) in the current directory. If folders have subfolders, it should not search those subfolders. An example is main_folder folder_1 sub_folder file1.txt file2.txt folder_2 file3.txt The script is placed inside main_folder. It should create a file that is a concatenation of file2.txt and file3.txt (in any order) inside main_folder. My question is: How can I tell Python to traverse through the folders, look for .txt files, without going into the subfolders?

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  • C# directory to "play with"

    - by Adam S
    Simple question here. I have a C# program which needs to stores some files onto the hard drive, but I don't need them to be anywhere useful to the end-user, only somewhere that the program can read/write from. Is there a directory that I can reference programmatically to be my "filespace playground" - that is, that I can read/write freely to and from? EDIT: Also, if I use a temp directory, how long are the files guaranteed to be there? I don't want the them to disappear while my program is still running!

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  • Why can't I view a directory in Linux?

    - by Thread7
    I am setting up a Linux web server running apache. I uploaded and untared my web sites files. The files in the main directory are all visible when I am SSH'd into the system. However, I am blocked from all subdirectories. If I write: # cd images Then I get the error: -bash: cd: images: Permission denied I am signed in as ec2-user. I untarred the stuff as ec2-user and I doubt there was any permissions in the tar file since I created the archive on a Windows system. The weird thing is that I am the owner of this directory. Here is a snippet of the command: ls -l drw-rw-r-- 19 ec2-user ec2-user 4096 May 4 04:09 images When I do "sudo su" and then type the command cd images everything is fine. Why do I get "Permission denied" as ec2-user if I am the owner and have rw permission?

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  • Rsync module path needs to be a home directory

    - by Malfist
    I'm trying to use rsync to backup windows servers to an rsync server. I'm having problems with rsync on the linux side though, it doesn't like symlinks. Currently I'm trying to use the module path of ~/backup, but rsync says that the chroot failed. I looked up what to do and saw that I needed to add the option use chroot = no and munge symlinks = no. That fixed the @ERROR: chroot failed but now it's telling me @ERROR: chdir failed and the log files say that there is no ~/backup directory. I know the user I'm authenticating with has a backup folder in his directory. How can I fix this? For reference I'm using a .NET port of rsync called NetSync and tunneling it over a port forwarded SSH connection generated with granados.

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  • No such file or directory python in linux only (coming from windows)

    - by user1804633
    I have the same exact directory structure within a folder in Windows & in Linux (Debian) - where the script is along the static + dataoutput folders How come the following code works fine in Windows, but gives a no such file or directory path error in linux? @app.route('/_getdataoutputfilelisting') def getdataoutputfilelisting(): listoffilesindataouput = getfiles('static/dataoutput') return jsonify(listoffiles = listoffilesindataouput) def getfiles(dirpath): a = [s for s in os.listdir(dirpath) if os.path.isfile(os.path.join(dirpath, s))] a.sort(key=lambda s: os.path.getmtime(os.path.join(dirpath, s))) a.reverse() return a Is there a way to make it universal such that it works in both OSs? Thanks

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  • Unable to execute file in the temporary directory

    - by Bixal
    I am using Windows 8.1 Pro 64-bit. I see this error, almost everytime I launch an executable file (to install it) but not for all of them. I don't see the error when I use Run as Administrator. I looked around, and found a solution: I needed to give permissions to the current user for the temp file as shown in the picture below: The problem here is solved temporarily, but it goes back to give me the same problem after restarting the PC. What can I do to prevent such a thing? I don't really want to use the built in Administrator account all the time. Update: The problem is caused by the cracked version of Adobe Acrobat. And the root cause is the cracked amtlib.dll Read more here: http://www.sabernova.com/2013/12/cracked-adobe-acrobat-xi-will-revert.html#axzz2r8VSzZi9

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  • Active Directory Group Policy: Script Errors

    - by ToreTrygg
    Hello all. Anyone having issues with AD group policy script errors when enabling VMware Fusion's "Sharing" feature? I've run into this problem in version 2.0 and 3.0. I have a logon script applied on an AD OU. It works fine on all Windows client workstations and in VMware Fusion only when the "Sharing" feature is NOT enabled. Any ideas would be much appreciated. Thanks.

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